if you hear that the net forces on an object is zero, what is the only conclusion you can make without seeing the object?

The bandwidth available for this circuit is 9.1 kHz.

The bandwidth of a circuit is the range of frequencies that it can handle or transmit effectively. It is determined by the difference between the highest and lowest frequencies. In this case, the highest frequency is 10 kHz and the lowest frequency is 900 Hz.

To calculate the bandwidth, subtract the lowest frequency from the highest frequency:

Bandwidth = Highest Frequency - Lowest Frequency

         = 10 kHz - 900 Hz

Before performing the subtraction, it is necessary to convert the frequencies to a consistent unit. Since 1 kHz is equal to 1000 Hz, the conversion is as follows:

10 kHz = 10,000 Hz

Now we can calculate the bandwidth:

Bandwidth = 10,000 Hz - 900 Hz

         = 9,100 Hz

         = 9.1 kHz

Therefore, the available bandwidth for this circuit is 9.1 kHz. It indicates that the circuit can effectively handle frequencies within this range, allowing for the transmission or processing of signals within the specified frequency band.

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Given that a sample contains 2.4 × 10^24 atoms of argon, we need to find the number of moles of argon present in the sample. The conversion factor is provided as 1 mole = 6.022 × 10^23 atoms. We can use this conversion factor to convert the number of atoms to moles.

Steps to find the number of moles of argon:Given,Number of atoms of argon = 2.4 × 10^24 atomsConversion factor: 1 mole = 6.022 × 10^23 atomsWe can use the above conversion factor to convert the number of atoms to moles as shown below:1 mole of Ar has 6.022 × 10^23 atoms of argon. Thus, the total number of moles of Ar in the sample containing 2.4 × 10^24 atoms of argon is calculated as follows:Number of moles of argon = (2.4 × 10^24 atoms of argon) / (6.022 × 10^23 atoms/mole) = 3.986 moles (approx)Thus, there are approximately 3.986 moles of argon in a sample containing 2.4 × 10^24 atoms of argon.An alternative method to solve the problem is to use the relationship between the number of moles and the mass of argon.Sample refers to the amount of argon given to us, and the mass of argon is not provided. Therefore, we cannot use the second method to solve this problem. The conversion factor is also given as 1 mole = 6.022 × 10^23 atoms. The final answer should be expressed to three significant figures, since the given quantity 2.4 × 10^24 has three significant figures.The number of moles of argon in a sample containing 2.4 × 10^24 atoms of argon is 3.986 moles (approx).

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Answer:

m₀ = 96 g

Explanation:

First, we will calculate the no. of half-lives passed:

\(n = \frac{T}{T_{1/2}}\)

where,

n = no. of half-lives passed = ?

T = Total time elapsed = 32 h

\(T_{1/2}\) = Half-Life = 8 h

Therefore,

\(n = \frac{32\ h}{8\ h}\\\\n = 4\)

Now, for the initial amount of element:

\(m = \frac{m_o}{2^n}\\\\m_o = m(2^n)\)

where,

m₀ = initial amount of element = ?

m = current amount of element = 6 g

Therefore,

\(m_o = (6\ g)(2^4)\)

m₀ = (6 g)(16)

m₀ = 96 g

Differentials are the components of a car that transfer engine torque to the axles allowing the wheels on the same axle to turn at different speeds.

There are two differentials in a car. The first one is located on the rare wheels and the second one is located on the front wheels.

The purpose of differentials is to allow the wheels to turn at different speeds required when the car is making a turn. The differentials send the torque from the transmission to the drive wheels.

During the turn, the differentials allow the front and rare wheels to turn at different speeds.

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Answer:

In a electric circuit. Wire, cell,switch,bulb are used

Explanation:

one wire is directly connected with battery from cell or battery to bulb and another wire is connected to battery to switch from bulb. switch is used to disconnect and connect wire easily.

Cystic fibrosis is a recessive genetic disorder caused by a mutation in the CFTR gene. It affects the lungs, pancreas, and other organs, causing difficulties in breathing and digestive problems.

Hemophilia is an X-linked recessive genetic disorder that affects blood clotting due to mutations in clotting factor genes. Hemophilia A is caused by a mutation in the F8 gene while hemophilia B is caused by a mutation in the F9 gene.

Duchenne muscular dystrophy is an X-linked recessive genetic disorder caused by mutations in the DMD gene, which codes for a protein called dystrophin. It affects muscle function and leads to muscle weakness and wasting.

Huntington's disease is an autosomal dominant genetic disorder caused by a mutation in the HTT gene. It affects brain function, leading to psychiatric symptoms and movement problems.

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Cystic fibrosis -  autosomal recessive pattern, Hemophilia -  X-linked recessive pattern, Duchenne muscular dystrophy -  X-linked recessive pattern and Huntington's disease - autosomal dominant pattern.

Gene alterations that are essentially present in every cell in the body cause many hereditary diseases. These illnesses thus frequently impact many bodily systems, and the majority cannot be treated. To treat or manage some of the accompanying symptoms, there might be methods available.

Genetic disorders connected to mutations in genes on the X chromosome are referred to as having X-linked recessive inheritance. Because he contains just one X chromosome, a male who carries this mutation will be affected. A female who carries a gene mutation in one X chromosome but has a normal gene on the other X chromosome usually has no symptoms.

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The main evidence for the presence of invisible matter in our galaxy is gravitational lensing and the motion of stars within galaxies.

Gravitational lensing is the bending of light by the gravitational pull of massive objects, which can reveal the presence of invisible matter. Astronomers have observed gravitational lensing effects in our galaxy and other galaxies, indicating the existence of dark matter. The motion of stars within galaxies also provides evidence for the presence of invisible matter.

The speed at which stars move within galaxies suggests that there is more mass present than can be accounted for by visible matter alone. This additional mass is believed to be dark matter, which does not emit, absorb, or reflect light, making it invisible to telescopes. Further research and observations are needed to better understand the nature of dark matter and its role in the universe.

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Answer:

please help

Explanation:

The answers are physically and mathematically reasonable, since both have the same order of magnitude of the external forces shown in the figure.

Let be a system at equilibrium, which mathematically is represented by the following formulas:

\(\Sigma F = 0\) (1)

\(\Sigma M = 0\) (2)

We construct equations around points A and B by Newton's Laws and D'Alembert Principle:

\(\Sigma M = F_{B}\cdot (1\,m)-(3000\,kgf)\cdot (2\,m)-(10000\,kgf)\cdot (6\,m) = 0\) (3)

\(\Sigma M = -F_{A,x}\cdot (1\,m) - (3000\,kgf)\cdot (2\,m)-(10000\,kgf)\cdot (6\,m) = 0\) (4)

\(\Sigma F_{x} = F_{A,x} + F_{B} = 0\) (5)

\(\Sigma F_{y} = F_{A,y} -3000\,kgf-10000\,kgf = 0\) (6)

The solution of the entire system is: \(F_{A,x} = -66000\,kgf\), \(F_{B} = 66000\,kgf\) and \(F_{A,y} = 13000\,kgf\).

The magnitude of the force acting on the crane at point A is determined by the Pythagorean theorem:

\(F_{A} = \sqrt{(-66000\,kgf)^{2}+(13000\,kgf)^{2}}\)

\(F_{A} \approx 67268.120\,kgf\)

The force acting on the crane at point A has a magnitude of approximately 67268.128 kilograms-force. \(\blacksquare\)

The force acting on the crane at point B has a magnitude of approximately 66000 kilograms-force. \(\blacksquare\)

The answers of parts (a) and (b) have an order of magnitude of \(10^{3}\), the same order of magnitude of the external forces shown in the figure. Hence, those answers are physically and mathematically reasonable.

Figure is missing. The statement is incomplete. Complete statement is presented below:

A 3000 kilograms-force is supporting a 10000 kilograms-force crate. The crane pivots about point A and is at rest pressed against a support at B.

(a) FInd the force acting on the crane at point A.

(b) Find the force acting on the crane at point B.

(c) Use order of magnitude sense-making to determine the reasonableness of your answers to parts (a) and (b). Hint: consider how the lever arm to the crate  is much different than that to other points.

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This expression will give us the phase difference, β, in radians. λ = 630 nm = 630 x 10^-9 m, w = 3.6 μm = 3.6 x 10^-6 m, y = -79 mm = -79 x 10^-3 m, l = 1.7 m, β = (2π / (630 x 10^-9 m)) * (3.6 x 10^-6 m) * (-79 x 10^-3 m) / (1.7 m)

To calculate the phase difference, β, between rays passing through the top and bottom of the slit, we can use the small angle approximation and consider the geometry of the setup.

Let's assume that the central maximum of the diffraction pattern falls at y = 0 on the screen. We are interested in calculating the phase difference at a point y = -79 mm above the central maximum.

Using the small angle approximation, we can assume that the angle θ formed by the rays passing through the top and bottom of the slit is small. This allows us to use the approximation sin(θ) ≈ θ.

The phase difference between the two rays is given by:

β = (2π / λ) * w * sin(θ)

In our case, sin(θ) ≈ θ, and we can express θ in terms of y, l, and the distance from the central maximum to the point of interest:

θ = y / l

Substituting this into the equation for β, we have:

β = (2π / λ) * w * (y / l)

Now we can plug in the given values:

λ = 630 nm = 630 x 10^-9 m

w = 3.6 μm = 3.6 x 10^-6 m

y = -79 mm = -79 x 10^-3 m

l = 1.7 m

β = (2π / (630 x 10^-9 m)) * (3.6 x 10^-6 m) * (-79 x 10^-3 m) / (1.7 m)

Evaluating this expression will give us the phase difference, β, in radians.

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11.The time at 75° East longitude would be 1 hour and 20 minutes behind. 12.The time at 135° degrees East longitude would be 4 hours ahead. and 13. the time in Lima, Peru (15° South latitude, 75° West longitude) would also be 9:30 AM.

At 2:00 AM at 90° East longitude, the time at 75° East longitude would be 1 hour and 20 minutes behind. This is because for every 15 degrees of longitude, there is a time difference of approximately 1 hour. Since the two longitudes in question have a difference of 15 degrees, we can divide this by 15 to calculate the time difference.

If it is 8:00 PM at 15° East longitude, the time at 135° East longitude would be 4 hours ahead. Similarly, for every 15 degrees of longitude, there is an approximate time difference of 1 hour. Since the two longitudes in question have a difference of 120 degrees, we can divide this by 15 to calculate the time difference.

There is a 7-hour difference** between 105° West longitude and the Prime Meridian (0° longitude). The Prime Meridian, passing through Greenwich, England, serves as the reference point for determining time zones. As one moves westward from the Prime Meridian, each 15 degrees of longitude corresponds to a time difference of approximately 1 hour. Therefore, the time at 105° West longitude would be 7 hours behind the time at the Prime Meridian.

If it is 9:30 AM in New York (41° North latitude, 75° West longitude), the time in Lima, Peru (15° South latitude, 75° West longitude) would also be 9:30 AM. The latitude does not affect the time difference between the two locations. However, since both locations have the same longitude (75° West), they would experience the same local time. The time difference between different latitudes is primarily significant for determining time zones rather than the actual time within a specific time zone.

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The statement that is wrong concerning the two tails of a comet is "they are perpendicular to each other." Two tails of a comet can't be perpendicular to each other.

Comets are celestial bodies that circle around the sun, originating from the Kuiper Belt and Oort Cloud. Comets are believed to be made up of ice, rock, and dust, and they can range in size from a few meters to tens of kilometers in diameter. Comets typically consist of two tails: a gas or plasma tail and a dust tail. Two tails of a comet. The two tails of a comet are made up of gas, plasma, and dust. They all point in opposite directions from the comet's nucleus, or core, as it travels through space. The dust tail of a comet is more massive than its ion tail, which is made up of electrically charged particles that are affected by the sun's magnetic field. Both tails of a comet are not perpendicular to each other because they are pointing in opposite directions. A gas tail may be tens or hundreds of thousands of kilometers long. It consists of highly volatile molecules such as water and carbon dioxide that have been energized by the sun's ultraviolet radiation. As they lose energy, the molecules release the energy in the form of light, which is what makes the gas tail visible. A dust tail, on the other hand, consists of tiny grains of rock and dust that have been kicked off the surface of the comet. It's typically much shorter than the gas tail, but it can be much brighter.

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The final pressure of the gas is p2 = 2.085 * 10^5 pa.

Boyle's law is a gas law that states that the pressure exerted by a gas (of a given mass at a constant temperature) is inversely proportional to the volume it occupies. That is, if the temperature and quantity of gas are constant, the pressure and volume of the gas are inversely proportional.

Boyle's Law states that a change in the volume occupied by a gas (at a constant amount and temperature) leads to a change in the pressure exerted by the gas. The following mathematical formulation of this law is possible:

P1V1 = P2V2

Given,

Initial Volume, v1 = 500 cm3

Final Volume, v2 = 240 cm3

Initial Pressure, p1 = 1.0 * 10^5 pa

Final Pressure, p2

We know that,

p1 v1 = p2 v2

1.0 * 10^5 * 500 = p2 * 240

p2 = 2.085 * 10^5 pa

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Answer:

5kg

Explanation:

p = mv

m = p/v

m = 35/7

m = 5kg

Answer:

5 kilograms

Explanation:

Mass can be found using the following formula.

\(m=\frac{p}{v}\)

where p is the momentum and v is the velocity.

The object has a momentum of 35 kg m/s and a velocity of 7 m/s. Therefore,

p= 35 kg m/s

v= 7 m/s

Substitute these values into the formula.

\(m= \frac{35 kg- m/s}{ 7 m/s}\)

Divide 35 kg m/s  by 7 m/s. (35/7=5)

The m/s in the numerator and denominator cancel each other out.

\(m= 5 kg\)

The mass of the object is 5 kilograms.

Answer:

Gold is metallic, with a yellow color when in a mass, but when finely divided it may be black, ruby, or purple. It is the most malleable and ductile metal; 1 ounce (28 g) of gold can be beaten out to 300 square feet. It is a soft metal and is usually alloyed to give it more strength.

Formula  --

Molecular Weight (lb/m o l)  28.96

Critical Temp. (°F)  N/A

Critical Pressure (p s i a)  N/A

Boiling Point (°F)  -317.8

Melting Point (°F)  N/A

Psat  70°F (p s i a)  (note 1)

Explanation:

Both are dangerous on their own, but as they float through the air in Southern California's sunny climate, the sun bakes them into a new molecule called ozone, better known as smog.

Smog development and infiltration over Los Angeles. haze and air pollution in the entire community.

Burning sulfur-containing fossil fuels, particularly coal, causes sulfurous smog, also referred to as "London smog," which is characterized by a high concentration of sulfur oxides in the atmosphere.

The two primary substances in automotive exhaust are nitrogen oxides, which are created in scorching internal combustion engines, and hydrocarbons, which are derived from gasoline.

Therefore, Both are dangerous on their own, but as they float through the air in Southern California's sunny climate, the sun bakes them into a new molecule called ozone, better known as smog.

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21joule  heat is generated in 3.50 s .

The rate of heat transfer over time is measured by the heat current. The SI unit for heat current, or joule per second, or watt, refers to it as a rate of heat energy through time (W). Through conduction, heat moves through material things, with heated particles transferring their energy to nearby particles.

Where I is current, R is resistance, and t is time, the equation Q=I2Rt describes the amount of heat produced in a circuit.

H = I^2Rt

H = 2.00^2 × 1.50 × 3.50

H = 21joule .

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Answer:

The value is \(t = 5.124 \ s\)

Explanation:

From the question we are told that

   The height of the tree is \(s = 20 \ m\)

    The angle the ball leaves is  \(\theta = 45^o\)

    The initial velocity  is  \(u = 30.0 \ m/s\)

Generally the vertical of the ball's initial velocity is mathematically evaluated as

      \(u_y = u * sin (45)\)

=>   \(u_y =- 30 * sin (45)\)

=>   \(u_y = -21.21 \ m/s\)

Here  \(u_y\) is negative because it is in the direction of the negative y-axis

Generally from kinematic equation we have

      \(s = u_yt + \frac{1}{2} g t^2\)

=>   \(20= -21.21 t +4.9 t^2\)

=>   \(4.9 t^2 -21.21 t- 20= 0\)

Solving using quadratic formula we have that

        \(t = 5.124 \ s\)

Calcium Bromide, commonly known as calcium dibromide, is an ionic compound since the second element is a nonmetal, resulting in an ionic compound. It is referred to as a hydrated salt.

A chemical compound is a material made up of several similar molecules that include atoms from more than one chemical element and are kept together by chemical bonds. A molecule made up of only one element's atoms is hence not a compound.

A solution is a form of homogenous combination made of two or more components in chemistry. A solute in such a combination is a material that has been dissolved in another substance known as a solvent.

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Answer:

hydrogen bonding between H atoms.

Explanation:

A light-year is a unit of distance, specifically the distance that light travels in one year.

Light travels at a speed of approximately 299,792 kilometers per second (or about 186,282 miles per second) in a vacuum. Therefore, to determine which planet is 20 light-years away from Earth, we need to identify a planet located at a distance of approximately 20 times this speed of light.

As of my knowledge cutoff in September 2021, no known exoplanets have been directly observed and confirmed to be located exactly 20 light-years away from Earth. However, there are numerous exoplanets that have been discovered within a range of distances from Earth.

Some notable exoplanets discovered within approximately 20 light-years of Earth include:

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The photon's wavelength emitted during the transition from n = 2 to n = 3 is approximately 256 nm. The photon's wavelength emitted during the transition from n = 1 to n = 3 is about 160 nm. The width of the box is approximately 0.622 nm.

The energy levels of a particle in a one-dimensional box:

Eₙ = (n² ×h²) / (8 × m × L²)

where:

Eₙ: energy level of the particle

n: quantum number of the energy level

h: Planck's constant

m: mass of the particle

L: width of the box.

Transition from n = 2 to n = 3:

Let's assume the wavelength of the photon emitted during this transition is λ.

ΔE = E₃ - E₂

ΔE = ((3² × h²) / (8 ×m × L²)) - ((2² × h²) / (8 × m × L²))

ΔE = (h² / (8× m × L²)) ×(9 - 4)

ΔE = (h²/ (8 × m × L²)) × 5

The energy difference is proportional to the frequency of the emitted photon:

ΔE = h × c / λ

where c is the speed of light.

We can equate the two expressions for ΔE:

(h² / (8 × m × L²)) × 5 = h × c / λ

λ = (8 × m × L² ×c) / (5 × h)

Plugging in the given values:

m = mass of the electron = 9.11 x 10⁻³¹ kg

L = width of the box (to be determined)

c = speed of light = 3 x 10⁸ m/s

λ = (8 ×(9.11 x 10⁻³¹ kg) × L² × (3 x 10⁸ m/s)) / (5 ×(6.626 x 10⁻³⁴ J·s))

Solving for L

L² = (5 × (6.626 x 10⁻³⁴J·s) × λ) / (8 ×(9.11 x 10⁻³¹kg) × (3 x 10⁸ m/s))

L² = 0.00047765 m²

L ≈ 0.021847 m

The wavelength of the photon is given by:

λ = (8 × (9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (5 × (6.626 x 10⁻³⁴J·s))

λ ≈ 256 nm

Transition from n = 1 to n = 3:

Following the same steps,

ΔE = E₃ - E₁

ΔE = ((3² × h²) / (8 ×m ×L²)) - ((1² × h²) / (8 × m × L²))

ΔE = (h² / (m × L²))

Using ΔE = h × c / λ:

(h² / (m × L²)) = h ×c / λ

Simplifying and solving for λ:

λ = (m × L² × c) / h

Plugging in the given values:

λ = ((9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (6.626 x 10⁻³⁴ J·s)

λ ≈ 160 nm

Width of the box (L):

From the above equations,

L² = (5 × (6.626 x 10⁻³⁴J·s) × (426 nm)) / (8 × (9.11 x 10⁻³¹ kg) × (3 x 10⁸ m/s))

L ≈ 0.000622 m or 160 nm

Therefore, the answers are 256 nm, 160 nm, and 0.622 nm respectively.

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The wavelength of the photon released during the change from n = 2 to n = 3 is roughly 256 nm. About 160 nm is the wavelength of the photon that is released when n = 1 changes to n = 3. The box has a width of about 0.622 nm.

Given values:

m = mass of the electron = 9.11 x 10⁻³¹ kg

L = width of the box (to be determined)

c = speed of light = 3 x 10⁸ m/s

The energy levels of a particle in a one-dimensional box:

Eₙ = (n² ×h²) / (8 × m × L²)

where:

Eₙ: energy level of the particle

n: quantum number of the energy level

h: Planck's constant

m: mass of the particle

L: width of the box.

Transition from n = 2 to n = 3:

The wavelength of the photon emitted during this transition is λ.

ΔE = E₃ - E₂

ΔE = ((3² × h²) / (8 ×m × L²)) - ((2² × h²) / (8 × m × L²))

ΔE = (h²/ (8 × m × L²)) × 5

The frequency of the photon that was released directly correlates with the energy difference:

ΔE = h × c / λ

,c is the speed of light.

Evaluating the two expressions for ΔE:

(h² / (8 × m × L²)) × 5 = h × c / λ

λ = (8 × m × L² ×c) / (5 × h)

λ = (8 ×(9.11 x 10⁻³¹ kg) × L² × (3 x 10⁸ m/s)) / (5 ×(6.626 x 10⁻³⁴ J·s))

Solving for L

L² = (5 × (6.626 x 10⁻³⁴J·s) × λ) / (8 ×(9.11 x 10⁻³¹kg) × (3 x 10⁸ m/s))

L ≈ 0.021847 m

The wavelength of the photon is given by:

λ = (8 × (9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (5 × (6.626 x 10⁻³⁴J·s))

λ ≈ 256 nm

Transition from n = 1 to n = 3:

ΔE = E₃ - E₁

ΔE = ((3² × h²) / (8 ×m ×L²)) - ((1² × h²) / (8 × m × L²))

ΔE = (h² / (m × L²))

Using ΔE = h × c / λ:

(h² / (m × L²)) = h ×c / λ

Solving for λ:

λ = (m × L² × c) / h

λ = ((9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (6.626 x 10⁻³⁴ J·s)

λ ≈ 160 nm

Width of the box (L):

From the above equations,

L² = (5 × (6.626 x 10⁻³⁴J·s) × (426 nm)) / (8 × (9.11 x 10⁻³¹ kg) × (3 x 10⁸ m/s))

L ≈ 0.000622 m or 160 nm

Thus, the answers are 256 nm, 160 nm, and 0.622 nm respectively.

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Answer:

zero work is done by the worker

Answer:

600 kg

Explanation:

Answer: 5.0025 * 10^-8 N

Explanation:

\(F = \frac{Gm_1m_2}{r^{2} }\)

F = gravitational force

G (is a constant) = 6.67×\(10^{-11}\) N(m/kg)^2

m1 = mass of first object = 500 kg

m2 = mass of second object = 600 kg

r = distance between them = 20 M

\(6.67*10^{-11}N(m/kg)^2* \frac{500 kg*600 kg}{(20m)^2}\\6.67*10^{-11}N*\frac{m^2}{kg^2} * \frac{300000kg^2}{400m^2}\\6.67*10^{-11} N * 750\\5002.5 * 10^{-11} N \\5.0025 * 10^{-8} N\)

Yes, you can produce a net impulse on an automobile if you sit inside and push on the dashboard. When you push on the dashboard, you are applying a force on the car, which causes it to accelerate in the direction of your push.

The change in the car's velocity due to this force is what we call impulse. Therefore, by pushing on the dashboard, you are producing a net impulse on the automobile.
Hi! I'm happy to help with your question. In order to produce a net impulse on an automobile, an external force must be applied for a certain amount of time. Impulse is the product of force and time (Impulse = Force × Time).

When you sit inside the car and push on the dashboard, you are applying an internal force within the car. Since there is no external force being applied to the car, there is no net impulse produced on the automobile. The force you apply on the dashboard will be balanced by an equal and opposite force exerted by the dashboard on you, according to Newton's third law of motion. This means that the forces will cancel each other out, resulting in no net impulse on the car.

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Answer:

4.5 because just do the math and its 4.5

The kinetic energy of the train is for the given mass and speed is 9.832 MJ.

The given parameters;

The kinetic energy of the train is calculated as follows;

K.E = ¹/₂mv²

where;

The kinetic energy is calculated as;

\(K.E = \frac{1}{2} \times (2.1\times 10^6) \times 3.06^2\\\\K.E = 9.832 \times 10^6 J\\\\K.E = 9.832 \ MJ\)

Thus, the kinetic energy of the train is for the given mass and speed is 9.832 MJ.

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A neutral stimulus will turn into a conditioned stimulus (CS) and cause a conditioned response (CR) that is comparable to the initial unconditioned response if it is combined with an unconditioned stimulus (US) that has already caused an unconditioned response (UR).

A neutral stimulus is one that first merely directs attention and doesn't elicit any specific responses. When coupled with an unconditioned stimulus in classical conditioning, the neutral stimulus becomes a conditioned stimulus. The neutral stimulus will also elicit a response, known as a conditioned response, with repeated presentations of both the neutral stimulus and the unconditioned stimulus.

So, CR i.e., conditioned response is after learning while NS i.e.,  Neutral Stimulus is before learning.

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https://brainly.com/question/20573834

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The flow of electricity in a certain path is the circuit.

Answer:

it will hit 80

Explanation:

because evey sec

is 10