if we were to use electrons instead of x-rays, at what speed must the electrons be moving to see first order constructive inference at 20°? the mass of an electron is 9.1×10−31 kg
Answers
If electrons were used in place of x-rays, first-order constructive inference at 20° would require an electron speed of 1.07 x 10⁹ m/s. One electron weighs 9.1×10−31 kg.
To determine the speed of electrons required to observe first-order constructive interference at 20 degrees, we can use Bragg's law:
n λ = 2dsinθ
where n is the order of diffraction, λ is the wavelength, d is the spacing between atomic planes in the crystal, and θ is the angle of incidence.
Assuming the spacing between atomic planes is d = 0.2 nm and the angle of incidence is θ = 20 degrees, we can rearrange the equation to solve for the wavelength:
λ = 2dsinθ / n = 2 x 0.2 nm x sin(20) / 1 = 0.068 nm
The de Broglie wavelength of an electron can be calculated using:
λ = h / p
where h is Planck's constant and p is the momentum of the electron. Rearranging this equation, we can solve for the momentum:
p = h / λ = 6.626 x 10⁻³⁴ J s / 0.068 nm = 9.74 x 10⁻²⁰ kg m/s
Finally, we can use the momentum and the mass of the electron to calculate the velocity:
v = p / m = (9.74 x 10⁻²⁰ kg m/s) / (9.1 x 10⁻³¹ kg) = 1.07 x 10⁹ m/s
Therefore, the electrons would need to be moving at a speed of approximately 1.07 x 10⁹ m/s to observe first-order constructive interference at 20 degrees.
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Related Questions
1. I get so much energy when I eat candy! What type of energy is this statement referring to?
O mechanical
O kinetic
O potential
O chemical
Answers
The answer is chemical
At temperature T 0, substance X in its A form (A can be liquid, solid or vapor) has same chemical potential with its B form (B can be liquid, solid, or vapor). At this temperature, the standard molar entropy of A is S
m(A)=65 J K −1mol −1, and the standard molar entropy of B is S m (B)= 43 J K −1mol −1. When the temperature is increased by 1 K, which form is thermodynamically more stable?
Answers
At temperature T₀, substance X in its A form has the same chemical potential with its B form. When the temperature is increased by 1 K, the form A is thermodynamically more stable.
When the temperature is increased by 1 K, the thermodynamically stable form is the one with the lowest Gibbs energy. The Gibbs energy change of transition from A to B is given by ΔG = ΔH - TΔS, where ΔH is the enthalpy change and ΔS is the entropy change of transition. If substance X in its A form has the same chemical potential with its B form at temperature T₀, it means that at this temperature ΔG = 0.
So, we have ΔH - T₀ΔS = 0.
From this equation, we can calculate the enthalpy change of transition as:
ΔH = T₀ΔS = T₀ (S m(A) - S m(B)) = T₀ (65 - 43) J K⁻¹ mol⁻¹ = 1320 J mol⁻¹.
The positive value of ΔH means that the transition from A to B is endothermic. When the temperature is increased by 1 K, the term TΔS becomes larger, so ΔG will be negative, meaning that B is less stable than A. Therefore, A is thermodynamically more stable.
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A subway car moves at a constant speed of 10 m/s over a period of 10 s. What is the instantaneous speed halfway through this motion
Answers
Answer: 10 m/s
We're told the speed is constant, so it's not changing throughout the time period given to us. So throughout the entire interval, the speed is 10 m/s.
What is the density of ocean water if 308.19g fills a 300mL container?
Answers
Answer:
Density = 1027.3 [kg/m3]
Explanation:
To solve this problem we must use the concept of density which is defined as the relationship between mass and volume, which can be determined by the following equation.
density = m/v
m = mass = 308.19 [gramm] = 0.30819 [kg]
v = volume = 300 [mL] = 0.3 [Lt] = 0.0003 [m3]
density = (0.30819/0.0003)
density = 1027.3 [kg/m3]
Chemical bonds form when (A)atoms share a nucleus. (B)atoms share protons. (C)atoms share neutrons. (D)atoms share electrons.
Answers
Answer:
d) atoms share electrons
Explanation:
Atoms with relatively similar electronegativities share electrons between them and are connected by covalent bond. Atoms with large differences in the electronicnegativity transfer electron's to form ions. The ions are then attracted to each other.
Answer:
D.
Explanation:
edge
A wagon, initially traveling at a constant 8.5 m/s, starts going down a hill that creates an
acceleration of 4.1 m/s2. How far downhill has the wagon gone after 2.7 s ?
Answers
Answer:
Explanation:
Given parameters:
Initial velocity = 8.5m/s
Acceleration = 4.1m/s²
Time = 2.7s
Unknown:
Distance downhill traveled = ?
Solution:
To solve this problem, we have to adopt the right motion equation;
S = ut + \(\frac{1}{2}\)at²
where s = distance
u = initial velocity
a = acceleration
t = time taken
Insert the parameters and solve;
S = (8.5 x 2.7) + (\(\frac{1}{2}\) x 4.1 x 2.7²)
S = 22.95 + 14.95
S = 37.9m
When you sit in a chair, your body exerts a downward force on the chair. What
is the reaction force?
A. The floor pushes up on the chair.
B. The chair pushes down on the floor.
C. Earth's gravity pulls up on the chain
D. The chair pushes up on your body.
Answers
Answer:
ITS D !!!
Explanation:
IN ME WE TRUST
When you sit on the chair, your body will exert a downward force and in reaction, the chair pushes up on your body. Hence, option D is correct.
What is a Reaction Force?A building experiences a reaction force when it rests against another object. Calculating the reaction forces at the supports as a result of the forces operating on the beam is a necessary step in the analysis of a beam structure. The reaction forces can be calculated using a free body diagram of the entire beam.
Corrosion can be caused by reaction forces. For instance, due to the system's increased stiffness, reaction forces increase when bearing clearances are reduced from 350 mm to 150 mm.
According to the question, when the body will exert a downward force that is mg due to gravity, the chair will make a normal reaction force which will be equal to the force applied by the body on the chair.
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What is the relationship between an object’s mass and the amount of inertia that it has?.
Answers
An infant's pulse rate is measured to be 135 +/- 6 beats/min. What is the percent uncertainty in this measurement? O 4.44% O 4.4% O 4% 0.04%
Answers
The percent uncertainty in the measurement of an infant's pulse rate, which is recorded as 135 +/- 6 beats/min, is 4.4%.
The percent uncertainty is calculated by dividing the range of the measurement (in this case, 6 beats/min) by the average value of the measurement (in this case, 135 beats/min), and then multiplying by 100 to express it as a percentage. In this case, the range is 6 beats/min and the average value is 135 beats/min. Dividing 6 by 135 gives 0.0444, and multiplying by 100 gives 4.44%. Therefore, the percent uncertainty in this measurement is 4.4%.
This measurement indicates that the pulse rate of the infant can vary within a range of +/- 6 beats/min from the average value of 135 beats/min. The percent uncertainty provides a measure of the relative variability or precision of the measurement. A lower percent uncertainty would indicate a more precise measurement with less variability, while a higher percent uncertainty would indicate a less precise measurement with greater variability. In this case, a percent uncertainty of 4.4% suggests a reasonably precise measurement of the infant's pulse rate.
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Using the fft function in MATLAB, plot the magnitude spectrum versus frequency for the signal g(t)=exp(−10t)u(t) for 0≤t≤1 with Δt=0.01. Determine the number of points in the signal. Use 450 zeros for precede and trail and determine the period T. B. Separately, plot the continuous magnitude transform given by: G(f)= 10+j2πf
1
[1−e −(10+j2πf)
] Utilize the same separation in frequencies. C. Using the fft function in MATLAB, plot the magnitude spectrum versus frequency for the signal: g(t)=sinc(πt). Assume Δt=0.01, and use 450 zeros for precede and trail and determine the period T.
Answers
The magnitude spectrum versus frequency for the signal g(t) = exp(-10t)u(t) and the continuous magnitude transform, and to determine the number of points in the signal and the period, the provided MATLAB code can be used.
A. To plot the magnitude spectrum versus frequency for the signal g(t) = exp(-10t)u(t) for 0 ≤ t ≤ 1 with Δt = 0.01 and determine the number of points in the signal:
```matlab
% Define parameters
delta_t = 0.01; % Sampling interval
t = 0:delta_t:1; % Time vector
g = exp(-10*t).*(t >= 0); % Signal definition
% Pad with zeros
N_zeros = 450;
g_padded = [zeros(1, N_zeros), g, zeros(1, N_zeros)];
% Compute the Fourier Transform
G = fft(g_padded);
% Compute the magnitude spectrum
G_mag = abs(G);
% Determine the number of points in the signal
num_points = length(g_padded);
% Determine the period
T = num_points * delta_t;
% Determine the frequency vector
Fs = 1/delta_t; % Sampling frequency
f = (-Fs/2 : Fs/num_points : Fs/2 - Fs/num_points);
% Plot the magnitude spectrum versus frequency
plot(f, G_mag);
xlabel('Frequency');
ylabel('Magnitude Spectrum');
title('Magnitude Spectrum versus Frequency');
```
B. To plot the continuous magnitude transform given by G(f) = (10 + j2πf) / (1 - e^(-(10 + j2πf))) and utilize the same frequency separation:
```matlab
% Define frequency range
f = -Fs/2 : Fs/num_points : Fs/2 - Fs/num_points;
% Evaluate the expression for G(f)
G_continuous = (10 + 1j * 2 * pi * f) ./ (1 - exp(-(10 + 1j * 2 * pi * f)));
% Plot the continuous magnitude transform
plot(f, abs(G_continuous));
xlabel('Frequency');
ylabel('Magnitude');
title('Continuous Magnitude Transform');
```
C. To plot the magnitude spectrum versus frequency for the signal g(t) = sinc(πt) assuming Δt = 0.01 and determine the period T:
```matlab
% Define parameters
delta_t = 0.01; % Sampling interval
t = -1:delta_t:1; % Time vector
g = sinc(pi*t); % Signal definition
% Pad with zeros
N_zeros = 450;
g_padded = [zeros(1, N_zeros), g, zeros(1, N_zeros)];
% Compute the Fourier Transform
G = fft(g_padded);
% Compute the magnitude spectrum
G_mag = abs(G);
% Determine the number of points in the signal
num_points = length(g_padded);
% Determine the period
T = num_points * delta_t;
% Determine the frequency vector
Fs = 1/delta_t; % Sampling frequency
f = (-Fs/2 : Fs/num_points : Fs/2 - Fs/num_points);
% Plot the magnitude spectrum versus frequency
plot(f, G_mag);
xlabel('Frequency');
ylabel('Magnitude Spectrum');
title('Magnitude Spectrum versus Frequency');
```
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1. A 60-Hz, single-phase source with V = 277 ∠0o volts is applied to a circuit element. (a) Determine the instantaneous source voltage. Also determine the phasor and instantaneouscurrents entering the positive terminal if the circuit element is (b) a 30-resistor, (c) a 15-mH inductor, (d) a capacitor with 100mF.
Answers
(a) The instantaneous source voltage can be determined by using the given magnitude and phase angle. Since the phase angle is 0°, the instantaneous source voltage can be written as:
V(t) = 277 * cos(2π * 60 * t)
(b) For a 30-Ω resistor, the current entering the positive terminal is the same as the source current. Since the voltage and resistance are given, we can use Ohm's law to determine the current:
I(t) = V(t) / R = (277 * cos(2π * 60 * t)) / 30
(c) For a 15-mH inductor, the phasor current can be determined using the formula:
I = V / jωL
where j is the imaginary unit (√(-1)), ω is the angular frequency (2π * frequency), and L is the inductance. In this case, ω = 2π * 60 and L = 15 * 10^(-3):
I = (277 ∠0°) / (j * 2π * 60 * 15 * 10^(-3))
To find the instantaneous current, we can take the real part of the phasor current and then convert it to the time-domain using cosine function:
I(t) = Re(I * e^(jωt))
(d) For a capacitor with 100 mF, the phasor current can be determined using the formula:
I = jωCV
where C is the capacitance. In this case, ω = 2π * 60 and C = 100 * 10^(-3):
I = (j * 2π * 60 * 100 * 10^(-3)) * 277 ∠0°
To find the instantaneous current, we can take the imaginary part of the phasor current and then convert it to the time-domain using sine function:
I(t) = Im(I * e^(jωt))
Jane spent 3 hours exploring a mountain with a dirt bike First, she rode 72 miles uphill After she reached the peak she rode for 21 miles along the summit While going uphill, she went 5 mph slower than when she was the summit What was her rate along the summit?
Answers
Jane's rate along the summit was 25 mph.
Let's assume that Jane's rate along the summit is represented by the variable "x" in miles per hour. We know that she rode 72 miles uphill at a rate that was 5 mph slower than her rate along the summit. Therefore, her rate uphill would be (x - 5) mph.
To find her average rate for the entire journey, we can calculate the total time taken for each segment and divide it by the total distance covered.
Time taken to ride uphill = Distance / Rate
Time taken to ride uphill = 72 miles / (x - 5) mph
Time taken to ride along the summit = Distance / Rate
Time taken to ride along the summit = 21 miles / x mph
Since the total time taken for the entire journey is 3 hours, we can write the equation:
Time taken to ride uphill + Time taken to ride along the summit = Total time
72 / (x - 5) + 21 / x = 3
By solving this equation, we find that x = 25 mph. Therefore, Jane's rate along the summit was 25 mph.
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someone pls help me this is due today!!!
Answers
Answer:
a. 6 A
b. 3 V
Explanation:
a. By using Kirchoff's Junction Rule, which states that the current flowing into a junction must equal the current flowing out of it. As you can see in the first 3-way split, the current splits into 3A, 2A, and 1A. This means that when the 3 wires rejoin, the current must have a magnitude equal to the total of the current flowing in all 3 branches, which would equate to 3+2+1 = 6 A.
b. Voltage differences across branches of a parallel circuit are identical. This means that we can treat the 3 resistors as one, and say that the voltage drop across that whole area is 3 V. Since that is the only voltage drop in the circuit, the battery's voltage drop must also be 3 V to equate to it. This is explained by Kirchoff's Loop Rule.
A car of mass 800 kg travels over a hill of height h. By travelling to the top of the hill, the car gains 40000 J of gravitational potential energy. The gravitational field strength g is 10 N /kg
Answers
\( \sf\huge{\underline{\underline{\overbrace{Answer}}}} \)
The height of the hill is 5m.
Explanation:
Given :-⠀
Mass of the car (m) = 800kg
Height of the hill (h) = ?
Gravitational field strength (g) = 10N/kg
Potential energy (P.E.) = 40,000J
⠀
To find :-⠀
The height of the hill
⠀
Solution :-⠀
▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃
⠀⠀⠀ ⠀⠀■ NoteThe gravitational potential energy is the energy acquired by the object when the mass of the object is under the gravitational pull of the earth. It is directly proportional to mass and height of the object. If the mass or the height of the object increases the potential energy also increases.
⠀
⠀⠀⠀⠀⠀□ ExampleIf we keep a book on the table and if we push the book from the table. This will result in the falling of the book on ground due to gravitational pull of the earth of it's mass and height.
▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃
⠀
⠀
While formula to find potential energy is
⠀
\( \tt{\Large {P.E. = mg}}h\)
But we need to find 'h'
so the formula for 'h' will be
⠀
\( \bold{\Large {h = \frac{P.E. }{mg} }}\)
▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃
⠀
⠀
Now substituting the required values.
⠀
\( \sf \hookrightarrow h = \frac{40000}{800 \times 10} \\ \\ \\ \sf \hookrightarrow h = \frac{40 \cancel 0 \cancel 0 \cancel 0}{8 \cancel 0 \cancel 0 \times \cancel{10}} \\ \\ \\ \sf \hookrightarrow h = \frac{ \cancel{ 40} \: \:{ \small{5}}}{ \cancel 8} \\ \\ \\ \boxed {\hookrightarrow h = 5m}\)
HELP PLS .. The half-life of potassium-44 is 22 minutes. It decays into calcium-44. After
66 minutes, what fraction of the original amount of potassium-44 in a sample
will still be potassium?
Answers
Answer:
B. 1/8
Explanation:
did the test !!
Answer: 1/8
Explanation:
Just took the test
the destroyactor function must be used to destroy a particle system. choose one • 1 point true false
Answers
True, the destroyactor function must be used to destroy a particle system.
The destroyactor function is a method that is used to remove an actor or object from a scene in programming. In the context of particle systems, when you want to remove a particle system from your scene, you need to use the destroyactor function. This function will effectively destroy the particle system and remove it from memory, freeing up resources.
It is important to properly destroy particle systems when they are no longer needed to prevent memory leaks and optimize performance. Therefore, the statement that the destroyactor function must be used to destroy a particle system is true.
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Drag each label to the correct location on the table. Sort the sentences based on whether they describe radio waves, visible light waves, or both. They have colors. They can travel in a vacuum. They have energy. They’re used to learn about dust and gas clouds. They’re used to find the temperature of stars. They’re invisible.
Answers
Based on the given sentences, let's sort them into the correct categories: radio waves, visible light waves, or both.
Radio waves:
- They're used to learn about dust and gas clouds.
Visible light waves:
- They have colors.
- They're used to find the temperature of stars.
Both radio waves and visible light waves:
- They can travel in a vacuum.
- They have energy.
- They're invisible.
Sorted table:
| Radio Waves | Visible Light Waves | Both |
|----------------------|----------------------|----------------------|
| They're used to learn about dust and gas clouds. | They have colors. | They can travel in a vacuum. |
| - | They're used to find the temperature of stars. | They have energy. |
| - | - | They're invisible. |
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Does the size of the magnetic field change with the size of the magnet?
Answers
Answer:
Not all of the time, it can also depend on the strength of the magnet.
Explanation:
say you have a small very strong magnet, that might work just as well as a large but week magnet.
Please Help!
In all organisms, cells are the most basic units of structure and function. The structure of an organism is affected by the way its cells are shaped and organized. Many of the functions that an organism needs to carry out to stay alive happen inside its cells. A cell is the smallest unit that can get and use energy, remove waste, and carry out other processes necessary for life.
The micrographs below show cells from two different organisms: an onion plant, which is multicellular, and a diatom, which is unicellular.
Answers
Answer:
Essential processes happen in a cell: Onion plant and Diatom
A cell is its basic unit of structure: Onion plant and Diatom
Made up of one cell: Diatom
Made up of many cells: Onion plant
When a sample of Radium-226 decays, the energy released is 7.81 ×10^-13 J.What is the mass defectA. 8.68×10^-30 kgB. 2.60×10^-21 kgC. 3.84 × 10^20 kgD. 1.15×10^29 kg
Answers
The mass defect and the energy released in radioactive decay are related by the following equation:
\(E=mc^2\)Where:
\(\begin{gathered} E=\text{ Energy} \\ m=\text{ mass} \\ c=\text{ speed of light} \end{gathered}\)We solve for the mass by dividing both sides by the square of the velocity of light:
\(\frac{E}{c^2}=m\)The speed of light is a constant and is equal to:
\(c=3\times10^8\frac{m}{s}\)Now we replace the given values:
\(\frac{7.81\times10^{-13}J}{(3\times10^8\frac{m}{s})^2}=m\)Now we solve the square in the denominator:
\(\frac{7.81\times10^{-13}J}{9\times10^{16}\frac{m}{s}}=m\)Now we solve the operations and we get:
\(8.68\times10^{-30}\operatorname{kg}=m\)Therefore, the mass defect is option A.
You decide to "go green" and use an exercise bike to power your home appliances. Assume that your exercise bike is rigged to generate electrical power with 60% efficiency. In other words, only 6/10 of the power you develop
can be used to store electrical energy for later use. Consider your 3500-Watt central AC unit. You need to run this unit for 4 hours each day during the summer. If you can develop a sustained power of 300 Watts on your exercise bike, how long would you have to work out just to keep the AC
running on a summer day?
Answers
The amount of time required to generate energy on the exercise bike is almost impractical, and other sources of energy should be considered.
Let's start with calculating the amount of energy that the AC unit consumes in a day.
Power = Voltage x Current
The power consumption of the AC unit is 3500 Watts.
Time = Power / Voltage x Current (Ohm's Law)
Assuming that your home uses 120 volts AC, the amount of current needed is as follows:
Current = Power / Voltage
= 3500 W / 120 V
= 29.16 A.
The time required to operate the AC unit for four hours per day is:
Time = Power / Voltage x Current
= 3500 W x 4 hr / 120 V x 29.16 A
= 12 hours.
Now, if you can generate a consistent power of 300 watts on the exercise bike, the amount of time you'd need to work out each day to keep the AC unit running for four hours would be:
Time required for the exercise bike = Time for AC Unit x (Power required by AC unit / Power generated by exercise bike)
Time required for the exercise bike = 4 hours x (3500 W / 300 W)
Time required for the exercise bike = 46.7 hours.
Using an exercise bike to generate electricity is a great idea, but it would be difficult to generate enough energy to keep large home appliances running, such as a central AC unit.
In this case, the amount of time required to generate energy on the exercise bike is almost impractical, and other sources of energy should be considered.
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A patient has a decreased urine output, fluid volume excess, and electrolyte disturbances. Which phase of acute renal failure is the patient experiencing? Intrarenal Postrenal Oliguric O Recovery
Answers
The phase of acute renal failure that the patient is experiencing, who has a decreased urine output, fluid volume excess, and electrolyte disturbances, is the oliguric phase of acute renal failure.
What is oliguria?Oliguria is defined as a low urine volume, generally less than 400 mL per day in an adult. It's generally a symptom of a kidney issue. Oliguria is caused by an underlying condition that impairs urine production or flow. The phase of acute renal failure when a patient's urine output is significantly decreased, typically less than 400 ml in 24 hours, is known as the oliguric phase.
Acute renal failure can be caused by a variety of factors, including dehydration, reduced blood flow to the kidneys, urinary tract blockages, and infections, among others. This phase lasts between one and three weeks and is characterized by increased nitrogenous waste accumulation, fluid volume excess, and electrolyte disturbances.
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2. A wave on a rope has a wavelength of 2.0 m and a frequency of 2.0 Hz. What is the speed of the
wave?
step# 1
step#2
step#3
Answers
Answer:
4 m/s or 4 meters per second.
Explanation:
In order to calculate the speed of wave, you multiply the wavelength in meters and the frequency of the Wave in Hertz. 2 times 2 equals 4. The wave speed is always in m/s considering that the wavelength is also in meters.
* Question Completion Status: Moving to another question will save this response. Question 29 Which one of the following statements is not true? (choose all apply) O UV radiation is a type of ionizing
Answers
One statement that is not true is that UV radiation is a type of electromagnetic radiation. It is also a type of ionizing radiation. UV radiation is actually a form of non-ionizing radiation.
UV radiation, or ultraviolet radiation, is a type of electromagnetic radiation that falls between visible light and X-rays on the electromagnetic spectrum. It is often categorized into three types: UVA, UVB, and UVC. Unlike ionizing radiation, such as X-rays and gamma rays, which have enough energy to remove tightly bound electrons from atoms or molecules, UV radiation lacks the necessary energy to ionize atoms or molecules. Instead, it primarily interacts with the outermost electrons of atoms or molecules, leading to chemical reactions and causing biological effects.
UV radiation is commonly associated with sunlight and has various effects on living organisms and materials. It can cause sunburn, premature aging of the skin, and an increased risk of skin cancer. Exposure to excessive UV radiation can also damage the eyes and impair the immune system. It is important to protect oneself from excessive UV exposure by wearing sunscreen, protective clothing, and sunglasses.
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What is the constraint forces
Answers
Answer:
(1) Support
(2) Tension
(3) Reaction
The constraint forces are forces that occur in pairs such that the net force (effect) is zero
The details of the constraint forces are;
(1) The support force at the top of the swing acting upwards
(2) The tension in the swing rope acting upwards
(3) The (normal) reaction between the legs of the swing frame and the ground
Explanation:
The normal reaction is the force equal in magnitude and opposite in direction to the total weight force the swing and the person on the swing posses due to gravitational attraction which prevents the downward or sideways motion of the entire swing
An airplane flies with a constant speed of 800 km/h. How long will it take to travel a distance of 1300 kilometers?
Answers
Answer:
an hour and 30 minutes i believe.
Explanation:
Answer:
a hours and 30 mins
Explanation:
Why does hot air move upwards and cold air move downwards?
a) Because hot air is heavier than cold air. B) Because hot air is lighter than cold air. C) Because hot air is denser than cold air. D) Because hot air has less heat than cold air
Answers
Answer:
(B) hot air is lighter than cold air
P V = N R T ideal gas equation
If T (temperature) is smaller then N (number of moles) must be larger if other quantities remain constant,
A transverse harmonic wave travels on a rope according to the following expression:
y(x,t) = 0.14sin(2.1x + 17.7t)
The mass density of the rope is μ = 0.104 kg/m. x and y are measured in meters and t in seconds.
a. What is the amplitude of the wave?
b. What is the frequency of oscillation of the wave?
Answers
a. The amplitude of the wave is 0.14 meters.
b. The frequency of oscillation of the wave is 17.7 Hz.
In the given expression, the amplitude of the wave is determined by the coefficient in front of the sine function, which is 0.14. The amplitude represents the maximum displacement of the wave from its equilibrium position.
The frequency of oscillation of the wave is determined by the coefficient of t in the argument of the sine function, which is 17.7. The frequency represents the number of complete oscillations of the wave that occur per unit time, in this case, per second (Hz).
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Is steam gas? If not what is?
Answers
Answer:
steam is a gas
Explanation:
Answer: Steam is an invisible gas, unlike water vapor, which appears as a mist or fog.
Explanation:
suppose the voltage to be measured in a certain experiment is always positive, and never exceeds 2.5 v. how many of the 16 bits (not to be confused with bins) of the a/d converter are effectively utilized?
Answers
Only 8 bits of the 16 bits of Analog to Digital Converter (ADC) will be effectively utilized. This is because only the positive voltage signals will be measured, and the negative signals will not be effective.
When measuring voltage in an experiment, suppose the voltage to be measured is still positive and never exceeds 2.5 V. As a result, only half of the total 16 bits in the ADC are effectively utilized. This is because when the signal never goes negative, only positive values can be measured. As a result, we can use only the positive portion of the A/D converter's dynamic range, and only half of the bits will suffice.
ADC stands for Analog to Digital Converter. An ADC is used to transform a voltage or current signal into a binary code that can be used in digital computer processing. An ADC has a fixed number of bits that it uses to represent the analog signal. The number of bits that are used to represent the analog signal is known as the resolution of the ADC.
Suppose a 16-bit ADC is used, which can represent the analog voltage with a resolution of 2^16, which equals 65,536 discrete levels. The voltage range that can be measured is divided into these 65,536 levels. For a 16-bit ADC, the voltage range is usually from -5 volts to +5 volts. However, if the voltage signal to be measured is always positive, only half of the ADC's dynamic range is needed.
As a result, only half of the ADC's bits are utilized, i.e., only the positive portion of the dynamic range is used. As a result, we will only use the first 8 bits of the ADC, as they can represent up to 256 levels of the voltage signal. The remaining 8 bits will not be used because the voltage signal to be measured is always positive. Therefore, only 8 bits of the ADC are effectively used in this experiment.
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