Light photons always travel at a constant speed (the speed of light) regardless of their energy, while the velocity of electrons is not constant and can vary with their energy.
Light photons and energetic electrons do not have constant velocities independent of energy. Light photons, which are particles of electromagnetic radiation, travel at a constant speed in a vacuum, which is approximately 299,792 kilometers per second (or about 186,282 miles per second) in a vacuum, denoted as the speed of light (c). This speed is a fundamental constant of nature and remains constant regardless of the energy of the photons. In other words, all photons, regardless of their energy, travel at the same speed in a vacuum.
On the other hand, energetic electrons do not have a constant velocity independent of their energy. According to classical physics, the velocity of an electron can vary depending on its energy. In classical mechanics, the kinetic energy of an object is related to its velocity. However, in the microscopic world of quantum mechanics, the behavior of particles such as electrons is described differently.
In quantum mechanics, the concept of particle velocity becomes less straightforward. Instead of velocity, quantum particles are described by wavefunctions, which represent the probability distribution of finding the particle at a certain location. The wavefunction of an electron evolves over time according to the Schrödinger equation, and it does not directly correspond to a well-defined classical velocity.
However, in certain situations, such as in electron beams or particle accelerators, electrons can be accelerated to high energies. In these cases, the energy of the electrons is related to their speed, but it is not a constant relationship. As the energy of the electrons increases, their speed can also increase, but it is not independent of their energy.
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calculate the speed of a bowling ball that travels 4 meters in 2 seconds
Answer:
2 m/s
Explanation:
Just divide the distance and time. 4/2= 2 m/s
hewo pweese help
A runner accelerates at 3 m/s/s for total of 6 seconds. How far will she have run during this time?
Answer: 18 m/s/s
Explanation:
3 times 6 equals 18 and 3 seconds every second makes this equation
which will have longer shadow: ben whose height is 5 feet tall and 2 inches or his brother mike who is 6 feet and 2 inches when they both stand under the sun around 10am? i need help asap and anyone get my answer now i will give branliest
Answer: I believe his brother, Mike, who is 6'2, will have the longer shadow.
ocean acidification impacts corals in what major way?
The graph shows the solubility of several different compounds in water. According to the graph, which compound can form a saturated solution when 160g is dissolved at a temperature of 55°C?
A. NaClO3
B. KBr
C. KNO3
D. NaCl
What is the minimum runway length that will serve? hint: you can solve this problem using ratios without having any additional information. express your answer in miles.
There are many factors that determine if an aircraft can operate from a given airport. Of course the availability of certain services, such as fuel, access to air stairs and maintenance are all necessary. But before considering anything else, one must determine if the plane can physically land at an airport, and equally as important, take off.
What is the minimum runway length that will serve?
Looking at aerial views of runways can lead some to the assumption that they are all uniform, big and appropriate for any plane to land. This couldn’t be further from the truth.
A given aircraft type has its own individual set of requirements in regards to these dimensions. The classic 150’ wide runway that can handle a wide-body plane for a large group charter flight isn’t a guarantee at every airport. Knowing the width of available runways is important for a variety of reasons including runway illusion and crosswind condition.
Runways also have different approach categories based on width, and have universal threshold markings that indicate the actual width.
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What is the acceleration of a 65 kg object pushed with a force of 500 newtons?
Answer:
7.69 m/s²Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
\(a = \frac{f}{m} \\ \)
f is the force
m is the mass
From the question we have
\(a = \frac{500}{65} = 7.692307... \\ \)
We have the final answer as
7.69 m/s²Hope this helps you
a 5.20-kg howler monkey is swinging due east on a vine. it overtakes and grabs onto a 6.20-kg monkey also moving east on a second vine. the first monkey is moving at 10.2 m/s at the instant it grabs the second, which is moving at 7.20 m/s.
The relative velocity of the two monkeys is 8.568m/s.it overtakes and grabs onto a 6.20-kg monkey also moving east on a second vine. the first monkey is moving at 10.2 m/s at the instant it grabs the second.
The relative velocity of an object to another item is its speed in respect to that object. It is a measurement of the relative speed of two moving objects. Because it clarifies how objects move and interact with one another, relative velocity is significant in physics.
Given;
mass of first monkey = 5.2 kg
mass of second monkey = 6.2 kg
speed of first monkey = 10.2 m/s
speed of second monkey = 7.20 m/s
by conservation of momentum
initial momentum = final momentum
5.2 * 10.2 + 6.2 * 7.2 = (5.2 + 6.2) * v
v = 8.568 m/s
their common speed = 8.568 m/s
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A 15-kg disk is sliding along a rough horizontal surface fs = 0.25 and x = 0.20, respectively. At time t=0 it is sliding with a linear velocity 9 m/s and zero angular velocity. Determine the distance travelled before it starts rolling.
The question asks to determine the distance traveled by a 15-kg disk on a rough horizontal surface before it starts rolling. The coefficient of friction (fs) is given as 0.25 and the distance (x) is given as 0.20. The disk starts with a linear velocity of 9 m/s and zero angular velocity.
In order to determine the distance traveled before the disk starts rolling, we need to consider the conditions for rolling motion to occur. When the disk is sliding, the frictional force acts in the opposite direction to the motion. The disk will start rolling when the frictional force reaches its maximum value, which is equal to the product of the coefficient of static friction (fs) and the normal force.
Since the disk is initially sliding with a linear velocity, the frictional force will gradually slow it down until it reaches zero linear velocity. At this point, the frictional force will reach its maximum value, causing the disk to start rolling. The distance traveled before this happens can be determined by calculating the work done by the frictional force. The work done is given by the product of the frictional force and the distance traveled, which is equal to the initial kinetic energy of the disk. By using the given values and equations related to work and kinetic energy, we can calculate the distance traveled before the disk starts rolling.
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A 0100 kg hamster enters its exercise wheel, which has an inner diameter of 231 cm, and begins to run at t=0, accelerating at a constant rate. After t=0.800 seconds, the wheel is turning with a rotational frequency of 100 Hz. What is the tangential acceleration of the inner surface of the wheel between t= 0 and 1=0.800 s? ___ m/s2
Therefore, the tangential acceleration of the inner surface of the wheel between t=0 and t=0.800 s is approximately \(906.5 m/s^2.\)
What is rotational frequency?The rotational frequency f is defined as the number of revolutions per second, which means that the wheel makes 100 revolutions in one second.
The angular velocity ω is the change in angle per unit time, so we can find it by multiplying the rotational frequency by 2π (the number of radians in one revolution):
ω = 2πf = 2π(100 Hz) = 200π radians/second
Now we can use the time interval and the angular velocity to find the angle through which the wheel has turned.
The time interval is Δt = 0.800 s, so the angle through which the wheel has turned is:
θ = ωΔt = (200π radians/second)(0.800 s) = 160π radians
The circumference of the inner surface of the wheel is C = πd, where d is the diameter of the wheel.
C = π(231 cm) = 725.4 cm
The tangential acceleration a_t is the acceleration of a point on the rim of the wheel, perpendicular to the radius.
We can use the formula for tangential acceleration:
a_t = rα
where r is the radius of the wheel and α is the angular acceleration.
We can find the radius of the wheel by dividing the diameter by 2:
r = d/2 = 231 cm/2 = 115.5 cm
Now we can find the angular acceleration by using the formula:
α = Δω/Δt
where Δω is the change in angular velocity and Δt is the time interval.
We know the initial angular velocity (zero), so we can find the change in angular velocity by subtracting the initial angular velocity from the final angular velocity:
Δω = ω - ω_0 = 200π radians/second - 0 radians/second = 200π radians/second
So the angular acceleration is:
α = Δω/Δt = (200π radians/second)/(0.800 s) = 250π \(radians/second^2\)
Finally, we can find the tangential acceleration by multiplying the radius by the angular acceleration:
a_t = rα = (115.5 cm)(250π radians/\(second^2\)) = 28875π \(cm/second^2\)
a_t = 288.75π \(m/s^2\)
Using a calculator, we get:
a_t ≈ 906.5 \(m/s^2\) (rounded to one decimal place)
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on a hot summer day, you notice that a bag of chips left in your vehicle has inflated. why did this happen? a as temperature increases, gas molecules lose kinetic energy and the volume of gas increases inside the bag of chips b as temperature increases, gas molecules gain kinetic energy and the volume of gas increases inside the bag of chips c as temperature increases, gas molecules gain kinetic energy and the volume of gas decreases inside the bag of chips
The correct answer is B:
as temperature increases, gas molecules gain kinetic energy and the volume of gas increases inside the bag of chips. This is because as the temperature rises, the molecules inside the bag of chips start moving faster and bumping into each other more frequently, causing the air molecules to expand and take up more space. This results in an increase in the volume of gas inside the bag, causing it to inflate To monitor the change, a global fleet of about 4,000 devices called Argo floats is collecting temperature data from the ocean’s upper 2,000 meters As temperatures have been warming, mangroves have been spreading.
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Please write in complete sentences.
How does density affect refraction?
Diamonds are a very dense material. Predict what would happen to the light ray if you projected it from the air through a diamond.
Answer:
The density of a material affects the speed that a wave will be transmitted through it. In general, the denser the transparent material, the more slowly light travels through it.
PLEASE HELP ME THIS IS VERY IMPORTANT!!!!!!!!!!!!! 20 points and I will give brainlyest
The diagram below shows a portion of the rock cycle.
Diagram of the rock cycle including 4 boxes labeled A, B, C, and D. There is an arrow labeled burial cementation extending from underwater sediment to box A. There is an arrow labeled deep burial, heating and pressure extending from underwater sediment to box B. There is an arrow labeled melting connecting box B to box D. There is an arrow labeled slow crystallization connecting box D to box C.
At what location in the diagram is granite most likely formed? (4 points)
Group of answer choices
Location A
Location B
Location C
Location D
Answer: I believe it’s location D. Or whichever is the location of slow crystallization.
Explanation: Slow crystallization of magma forms granite. Hope this helps. :)
Answer:
D
Explanation:
You kick a soccer ball with a speed of 31 m/s at an angle of 50 degrees. How long does it take the ball to reach the top of its trajectory?
Answer:
Reaches max height at t = 2.42s.
Explanation:
I've assumed we are neglecting air resistance. If not let me know and I'll update.
We want to examine the behaviour of the ball in the y-direction. In the absence of air resistance the only force acting on the ball is gravity, which produces an acceleration in the negative y direction.
a daring ranch hand sitting on a tree limb wishes to drop vertically onto a horse galloping under the tree. the constant speed of the horse is 15.0 m/s, and the distance from the limb to the level of the saddle is 3.20 m.
The ranch hand should drop from the tree limb and time their drop to take approximately 0.81 seconds. This will allow them to fall vertically onto the horse's saddle.
Let's consider the situation from the perspective of an observer on the ground. The horse is moving with a constant speed of 15.0 m/s. Meanwhile, the ranch hand is stationary on the tree limb.
The ranch hand needs to drop vertically onto the horse. Since the ranch hand and the horse are in motion relative to the observer on the ground, the vertical distance between them will decrease as the ranch hand drops.
The distance from the limb to the saddle is given as 3.20 m. To successfully drop onto the horse, the ranch hand needs to time their drop such that the vertical distance they fall is equal to 3.20 m when they reach the level of the saddle.
We can calculate the time it takes for the ranch hand to fall using the formula: distance = (1/2) * acceleration * time^2. In this case, the distance is 3.20 m and the acceleration is the acceleration due to gravity, which is approximately 9.8 m/s^2.
Plugging in these values into the formula, we get:
3.20 = (1/2) * 9.8 * time^2
Simplifying the equation, we find:
time^2 = (2 * 3.20) / 9.8
time^2 = 0.653
Taking the square root of both sides, we find:
time = 0.81 s
Therefore, the ranch hand should drop from the tree limb and time their drop to take approximately 0.81 seconds. This will allow them to fall vertically onto the horse's saddle.
In conclusion, the daring ranch hand can successfully drop onto the horse by timing their drop to take approximately 0.81 seconds. This will ensure that they fall vertically onto the horse's saddle as the horse gallops under the tree.
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A student performed an investigation into the refraction of light in a transparent material.
The results are shown below:
The angle of refraction of the refracted ray through the material shown is 32o .
Use this information to calculate the critical angle of the transparent material
The critical angle of the transparent material is 35.3 degrees.
What is the critical angle?The critical angle is the angle of incidence at which the angle of refraction is 90 degrees. In this case, the angle of refraction is 32 degrees. Therefore, the critical angle is calculated as follows:
sin(critical angle) = sin(90 degrees) / sin(angle of refraction)
sin(critical angle) = 1 / sin(32 degrees)
sin(critical angle) = 0.574
critical angle = arcsin(0.574)
critical angle = 35.3 degrees
Therefore, the critical angle of the transparent material is 35.3 degrees.
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determine the current (in ma) through the led in the circuit below if the forward biased voltage of the led is 2 v?
The current flowing through the LED is also 10 mA. To determine the current (in mA) through the LED in the circuit given below.
Assuming that the forward biased voltage of the LED is 2V, the following procedure is followed: To calculate the current flowing through the LED in the given circuit, the following formula is used: Ohm's Law: V = IR where V is the voltage applied to the circuit, I is the current flowing through the circuit, and R is the resistance of the circuit. Now, in the given circuit, the total voltage applied to the circuit is 12V. Therefore, the voltage across the resistor (R) is V = 12 - 2 = 10V. So, we know that the voltage across the resistor is 10V and the value of the resistor is 1000 ohms.
Therefore, the current through the resistor is: I = V/R = 10/1000 = 0.01 A = 10 mA. Now, this current will also be the current flowing through the LED as the LED is in series with the resistor. Therefore, the answer is 10 mA.
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4 pleasee i have to submit in 10 minutes
Answer:
True
Explanation:
A train is traveling N at 45 m/s. After 10s, it is traveling at 90 m/s. What is it's acceleration?
Answer:
The train's acceleration is 4.5 m/s²
Explanation:
The train's speed increased by 45 m/s after 10 seconds, which means that it's speed increased by 4.5 m/s each second, or rather 4.5m/s²
Once a metamorphic rock, always a metamorphic rock. Rocks cannot change from one type of a rock to another.
true or false?
Answer:
False
Explanation:
Metamorphic rock can melt into magma or weathers down (erosion) into sediments.
what produces magnetic fields
Answer:
B is the answer
Explanation:
Magnetic fields are produced by moving electric charges and the intrinsic magnetic moments of elementary particles associated with a fundamental quantum property, their spin.
Balance is the body's ability to maintain ____________ and stability.
Answer:
Equilibrium or coordination
Explanation:
The body's equilibrium is it's way to maintain balance, and perfect distribution of weight. When no force is acting to make a body move in a line, the body is in translational equilibrium; when no force is acting to make the body turn, the body is in rotational equilibrium.
Answer: Control
Explanation:
I did it on FLVS Flex
In order to attain orbit around earth, the ATLAS-V rocket must accelerate up to a
speed of about 7700m/s in about 11 minutes.
a) What average acceleration is required to accomplish this?
b) If the mass of the rocket + fuel is 3.05x105 kg, what is the applied force of the engine?
A shopping cart is pushed and released,
and eventually it slows to a stop. If the velocity of the 28-kg cart
after release is 3.5 m/s and it travels a distance of 6 meters before
stopping, determine the magnitude of the friction on the cart.
The magnitude of the friction on the cart is 28,56 N
To measure the deceleration of a car, without the value of the time of the movement, the Torricelli equation is used, which consists of:
\({\displaystyle {v_{f}}^{2}={v_{o}}^{2}+2a\Delta s}\)
Where is final velocity, is initial velocity, is acceleration, and is displacement.
Now, substitute the values in the formula:
\(0^{2} = (3.5)^{2} + 2a6\)
\(0 = 12.25 + 12a\)
\(a = -\frac{12.25}{12}\)
\(a = -1.02\)
Finally, the value of the acceleration found is multiplied by the mass of the object, thus measuring the friction force:
\(F = 28\times-1.02\)
\(F = -28.56 N\)
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A spring gun with a spring constant of 250N/m is compressed 5. Ocm. How fast
will a 0. 025kg dart move when it leaves the gun?
0. 13 m/s
0. 50 m/s
1. 5 m/s
5. 0 m/s
The dart will move at velocity approximately 5.0 m/s when it leaves the gun.
To calculate the speed of the dart, we can use the conservation of energy principle. When the spring is compressed, it has potential energy, which is converted into the kinetic energy of the dart when it is released. The potential energy of the compressed spring can be calculated using the formula: PE = 0.5 * k * x^2, where PE is the potential energy, k is the spring constant (250 N/m), and x is the compression distance (0.05 m).
PE = 0.5 * 250 * (0.05)^2 = 0.3125 J (joules)
Now, we can use the kinetic energy formula to find the speed of the dart: KE = 0.5 * m * v^2, where KE is the kinetic energy, m is the mass of the dart (0.025 kg), and v is the speed. We can rearrange this formula to solve for v:
v = sqrt((2 * KE) / m)
Plugging in the values, we get:
v = sqrt((2 * 0.3125) / 0.025) ≈ 5.0 m/s
Therefore, the speed of the dart when it leaves the gun is approximately 5.0 m/s.
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why does damp soil help excess electrons move
Explanation:
Because where there is water, energy is conducted, and moves the electrons.They also move excess electrons because pure water is a poor conductorOkay, so I have a project and we have to create a brochure to promote a planet and try to get people to visit. We also have to create a catchy slogan
I dunno if this is a good site to ask on, but I NEED HELP CREATING A SLOGAN FOR NEPTUNE. PLEAASE HELP :(
Explanation:
the tune of neptune is better thatbany other tune
hope it helps
The figure shows a U-Shaped conducting rail that is oriented vertically in a horizontal magnetic field. The rail has no electric resistance and does not move. A slide wire with mass m and resistance R can slide up and down without friction while maintaining electrical contact with the rail. The slide wire is released from rest.
a) Show that the slide wire reaches a terminal speed (Vterm) and find and expression for Vterm
b) Determine the value for Vterm if l=20cm m=10g R=10 ohms B=0.50T
c) What is the direction of the current that flows in the slide wire?
The gravitational force (Fg) is the force of attraction between two objects with mass due to gravity.
The correct answers are:
a) We get the expression for the terminal speed:
\(Vterm = (mgR) / (LB)\)
b) Vterm = 4.9 m/s
c) In this case, the current will flow in a direction that opposes the motion of the slide wire, which means it will be flowing upward.
The gravitational force is a fundamental force of nature that attracts objects with mass toward each other. It is the force responsible for the Earth's gravitational pull, keeping objects on the surface and causing objects to fall when released.
a) To determine the terminal speed (Vterm) of the slide wire, we can analyze the forces acting on it. There are two main forces involved: the gravitational force (mg) and the electromagnetic force (ILB), where I is the current flowing through the wire, L is the length of the wire, and B is the magnetic field strength.
At terminal speed, the electromagnetic force will balance the gravitational force, so we have:
\(ILB = mg\)
Solving for I, we get:
\(I = mg / (LB)\)
The current I can also be expressed as the rate of change of charge with time, I = dQ/dt, where Q is the charge passing through the wire.
Since the slide wire is sliding without friction, the potential difference (V) across the wire is constant, and we can write:
\(V = IR\)
Taking the time derivative of both sides, we get:
\(dV/dt = R * dI/dt\)
But dI/dt is the rate of change of charge passing through the wire, which is equal to I/t, where t is the time taken for the charge to pass through the wire.
Substituting the expression for I from earlier, we have:
\(dV/dt = (R / t) * (mg / (LB))\)
Since the left side represents the time derivative of the potential difference, it is the rate of change of voltage with time, which is equal to the current (I).
Therefore, we can write:
\(I = (R / t) * (mg / (LB))\)
Rearranging the equation, we find:
\(Vterm / t = (mgR) / (LB)\)
Simplifying further, we get the expression for the terminal speed:
\(Vterm = (mgR) / (LB)\)
b) Substituting the given values: l = 20 cm = 0.20 m, m = 10 g = 0.01 kg, R = 10 ohms, B = 0.50 T, into the expression for Vterm:
Vterm = (0.01 kg * 9.8 m/s² * 10 ohms) / (0.20 m * 0.50 T)
Vterm = 4.9 m/s
c) The direction of the current that flows in the slide wire can be determined using the right-hand rule. If we extend our right hand with the thumb pointing in the direction of the magnetic field (B) and curl the fingers around the wire, the direction of the current will be in the direction that the palm faces. In this case, the current will flow in a direction that opposes the motion of the slide wire, which means it will be flowing upward.
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What are waveform conversion circuits? 2. Where are waveform conversion circuits typically used
Waveform conversion circuits, also known as signal conversion circuits, are electronic circuits designed to convert one form of an electrical waveform into another form. Waveform conversion circuits find application in a wide range of fields where the modification, conditioning, or transformation of electrical waveforms is necessary to achieve specific objectives.
These circuits modify the characteristics of an input signal to achieve a desired output waveform. The conversion can involve changing the amplitude, frequency, phase, or shape of the waveform.
Waveform conversion circuits are used in various applications where it is necessary to transform signals to match specific requirements. Here are some common areas where waveform conversion circuits are typically used:
Audio Processing: In audio applications, waveform conversion circuits are used to modify audio signals for various purposes. This includes amplifying, filtering, equalizing, or modulating audio waveforms to enhance sound quality, remove noise, or achieve specific audio effects.
Power Electronics: Waveform conversion circuits are extensively employed in power electronics systems for converting and conditioning electrical power. These circuits are used in devices such as inverters, converters, rectifiers, and voltage regulators to transform power waveforms, adjust voltage or current levels, and ensure efficient power transfer.
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STRAIGHTNESS ON CYLINDERS AND CONES a. What lines are straight with respect to the surface of a cylinder or a cone? Why? Why not? b. Examine: - Can geodesics intersect themselves on cylinders and cones? - Can there be more than one geodesic joining two points on cylinders and cones? - What happens on cones with varying cone angles, including cone angles greater than 360∘ ? These are discussed starting in the next section.
(a) No lines are straight with respect to the surface of a cylinder or a cone. This is because cylinders and cones have curved surfaces, and a straight line is defined as the shortest distance between two points, which can only be achieved in a flat plane.
(b) Geodesics on cylinders and cones do not intersect themselves. However, there can be more than one geodesic joining two points on cylinders and cones, depending on the specific configuration and parameters of the shape.
On cones with varying cone angles, including cone angles greater than 360 degrees, the behavior of geodesics may change, leading to different paths and properties.
(a) The surfaces of cylinders and cones are curved, and their geometry differs from that of a flat plane. A straight line is defined as the shortest distance between two points in Euclidean geometry, and it exists only in a flat plane.
On the curved surface of a cylinder or a cone, any line drawn will follow the curvature of the shape and cannot remain straight throughout.
(b) Geodesics are the curves that represent the shortest distance between two points on a surface. On cylinders and cones, geodesics do not intersect themselves because they are the paths of minimum length. However, there can be more than one geodesic joining two points on cylinders and cones.
The presence of multiple geodesics depends on the shape and the specific points chosen. The curvature and orientation of the surface play a role in determining the geodesics.
When considering cones with varying cone angles, including cone angles greater than 360 degrees, the behavior of geodesics may change. Different cone angles result in different curvatures and shapes. This can affect the paths of geodesics and potentially lead to unique properties.
Exploring the behavior of geodesics on cones with varying cone angles provides insights into the relationship between curvature and path characteristics.
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