If there is a source voltage of 12 volts with a 2.5 volt drop over the LED, and an intended current of 100 mA, what size resistor should be used?

The interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

To determine the interval between the first and second echo, we need to consider the time it takes for sound to travel from the student to the first cliff, and then from the first cliff to the second cliff, and finally back to the student.

Let's break down the distances and calculate the time for each part of the journey:

Distance from the student to the first cliff: 330 meters

Time taken: t₁ = distance / speed = 330 m / 330 m/s = 1 second

Distance from the first cliff to the second cliff: 990 meters

Time taken: t₂ = distance / speed = 990 m / 330 m/s = 3 seconds

Distance from the second cliff back to the student: 990 meters

Time taken: t₃ = distance / speed = 990 m / 330 m/s = 3 seconds

Now, we can calculate the total interval between the first and second echo by adding up the individual times:

Interval between first and second echo = t₁ + t₂ + t₃ = 1 s + 3 s + 3 s = 7 seconds

Therefore, the interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

It's important to note that this calculation assumes a straight path for the sound waves and neglects factors such as air temperature and wind that can affect the speed of sound. Additionally, it assumes perfect reflection of sound waves off the cliffs, which may not be the case in real-world scenarios.

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Note the complete questions is:

A student stands 330m from a tall cliff which is 990m from another tall cliff. If the speed of sound between the cliffs is 330m/s.What is the interval between the first and second echo?

The distance traveled by the car before coming to a complete stop is 156.25 m

The given parameter:

initial velocity of the car, u = 25 m/s

acceleration of the car, a = - 2 m/s²

The distance traveled by the car before coming to a complete stop is calculated as;

\(v^2 = u^2 + 2as\\\\2as = v^2 - u^2\\\\s = \frac{v^2-u^2}{2a} \\\\when \ the \ car \ stops \ the \ final \ velocity \ v = 0\\\\s = \frac{-u^2}{2a} \\\\s = \frac{- (25)^2}{2(-2)} = 156.25 \ m\)

Thus, the distance traveled by the car before coming to a complete stop is 156.25 m

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We have that the car's travel before coming to a complete stop is

S=156.3m

From the question we are told that

A car is coasting with a velocity of 25 m/s

decelerate the car at a rate of -2 m/s2.

Generally the Newtons equation for the  distance is mathematically given as

\(S=\frac{v^2}{2a}\)

Therefore

S=\frac{25^2}{2*2}

S=156.3m

Therefore

the car's travel before coming to a complete stop is

S=156.3m

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Science reevaluates a theory when new evidence is found that contradicts it and lots of evidence to support its claims, while hypothesis and theory need evidence to support them.

A scientific theory is a well-sustained body of evidence that is supported by many predictive outcomes.

Conversely, a hypothesis is a plausible explanation that needs to be tested by using the scientific method.

In conclusion, science reevaluates a theory when new evidence is found that contradicts it (question 1) and lots of evidence to support its claims (question 2), hypothesis and theory need evidence to support them (question 3).

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Answer:

To sum up the confusion its

1) D) Science Reevaluates the validity of the theory
2) D) Theories are well established with lots of evidence to support their claims.
3) A) Both a hypothesis and a theory need evidence to support them.

Explanation:

I took the test and it's what the last guy tried to say even if it was all jumbled up...

Answer:

the Indian Ocean on 26 December 2004. This event claimed 227,898 dead and missing from 14 countries. The difference in mortality rates between these tsunamis reflects, in part, the benefits of understanding how tsunami waves are generated and move, and educating citizens to make scientifically

sound and potentially life-saving decisions.

A tsunami is a series of rapidly propagating, shallow-water ocean waves that develops when a submarine earthquake, landslide, or volcanic eruption displaces a large volume of water. Powerful earthquakes, with magnitudes of 9 or greater, caused both the 2004 and 2011 tsunamis. The earthquakes resulted from the movement of large tectonic plates. The 11 March 2011 earthquake occurred at 32 km (20

mi.) deep in Earth’s crust about 130 km (81 mi.) east of the city of Sendai. This location is on the boundary between two tectonic plates—the Pacific plate to the east and North American plate to the west. This

boundary fractured, releasing energy that was transmitted through the rocks and elevated portions of the

ocean floor. This drastic movement transmitted energy to the overlying ocean water, which generated

tsunami waves that radiated outward. The waves washed over the nearby coastlines and were felt around

the globe within hours (Figure 1.1).  

Explanation:

Answer:

I believe Geosphere (lithosphere) and Hydrosphere

Explanation:

I hope it's right if not please notify me.

The value of R₂, given that the total resistance in a circuit with two parallel resistor is 2 ohms, is 3 ohms

The formula to obtain the total resistance in a parallel connection for two resistors is given as folllow:

Rₜ = (R₁ × R₂) / (R₁ + R₂)

With the above formula, we can obtain the value of R₂. Details below:

Rₜ = (R₁ × R₂) / (R₁ + R₂)

2 = (6 × R₂) / (6 + R₂)

2 = 6R₂ / (6 + R₂)

Cross multiply

2 × (6 + R₂) = 6R₂

Clear bracket

12 + 2R₂ = 6R₂

Collect like terms

12 = 6R₂ - 2R₂

12 = 4R₂

Divide both sides by 4

R₂ = 12 / 4

R₂ = 3 ohms

Thus, we can conclude that the value of R₂ is 3 ohms

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Answer:

hope this helpes!!

Explanation:

plz mark brainliest

The nuclear equation for the alpha decay of astatine-213 is shown below:

²¹³₈₅At ⇒   ²⁰⁹₈₃X +  ⁴₂He

²¹³₈₅At ⇒   ²⁰⁹₈₃Bi +  ⁴₂He

This is derived by calculating a and b of the new element.

²¹³₈₅At ⇒   ᵇₐX +  ⁴₂He

213 = b + 4

213-4 = b

209 =b

b= 209

85= a+2

85-2 = a

83=a

a=83

The alpha decay of Astatine-213 forms the element known as Bismuth.

Astatine has an atomic number of 85. Alpha decay involves an element

being split into a new element and a Helium ion.

The atomic mass is usually decreased by 4 and the atomic number is usually

decreased by 2 which gives rise to  the element Bismuth which is denoted by

²⁰⁹₈₃Bi

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Option A) 3.9 km is the correct answer. the magnitude of Rhea's displacement vector is approximately 3.92 km.

In order to find out the magnitude of Rhea's displacement vector, we have to add up all of the displacement vectors.

Then we can use the Pythagorean theorem to calculate the magnitude of the resultant vector.

Since Rhea is first driving north for 2.4 km and then west for 3.1 km, we can represent her displacement vectors as follows: Δx = 0 km and Δy = 2.4 km for the first vector, and Δx = -3.1 km and Δy = 0 km for the second vector.

We can then add these vectors together by adding their components: Δx = 0 km + (-3.1 km) = -3.1 km and Δy = 2.4 km + 0 km = 2.4 km.

This gives us a resultant vector of -3.1 km east and 2.4 km north.

Using the Pythagorean theorem, we can find the magnitude of this vector: \(\sqrt{(\(-3.1 km)^{2} + (2.4 km)^{2} ) } = \sqrt{(9.61 + 5.76) km^{2} } = \sqrt{15.37 km^{2} } \approx 3.92 km.\)

Therefore, the magnitude of Rhea's displacement vector is approximately 3.92 km.

Therefore, option A) 3.9 km is the correct answer.

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ANSWER AND EXPLAINATION:
To calculate the impulse imparted on the baseball, we can use the impulse-momentum principle, which states that the impulse experienced by an object is equal to the change in momentum of the object. Mathematically, it can be expressed as:

Impulse = Change in momentum

The momentum of an object is given by the product of its mass and velocity:

Momentum = mass × velocity

In this case, the baseball has an initial mass of 0.14 kg and an initial velocity of 32 m/s. After being struck by the bat, it travels in the opposite direction at a velocity of 49 m/s.

Therefore, the change in momentum is given by:

Change in momentum = (mass × final velocity) - (mass × initial velocity)

Change in momentum = mass × (final velocity - initial velocity)

Change in momentum = 0.14 kg × (49 m/s - (-32 m/s))

Change in momentum = 0.14 kg × (49 m/s + 32 m/s)

Change in momentum = 0.14 kg × 81 m/s

Change in momentum = 11.34 kg·m/s

So, the impulse imparted on the baseball is 11.34 kg·m/s.

To solve this problem, we need to use Newton's second law to find the net force acting on the two boxes. The net force is equal to the mass of the two boxes times the acceleration. Since the boxes are moving at a constant speed, the acceleration is zero, and the net force is also zero. This means that the sum of all the forces acting on the two boxes must be zero.The force you exert on the boxes is the force of tension in the rope, and this force is equal in magnitude and opposite in direction to the force of friction on the lower box. The magnitude of the friction force on the lower box is equal to the coefficient of kinetic friction times the normal force acting on the lower box.The normal force is the force exerted by the ramp on the lower box, and it is equal in magnitude to the weight of the lower box. The weight of the lower box is equal to the mass of the lower box times the acceleration due to gravity.The magnitude of the friction force on the upper box is equal to the coefficient of static friction times the normal force acting on the upper box. The normal force acting on the upper box is equal in magnitude to the weight of the upper box.Now that we have all the forces, we can use Newton's second law to solve for the force you need to exert. The equation is:F_tension - F_friction_lower = 0

F_tension = F_friction_lowerF_friction_lower = u_k * N_lower

F_tension = u_k * m_lower * gWhere:F_tension is the force you need to exertF_friction_lower is the force of friction on the lower boxu_k is the coefficient of kinetic friction between the ramp and the lower boxN_lower is the normal force acting on the lower boxm_lower is the mass of the lower boxg is the acceleration due to gravitySubstituting the given values, we get:F_tension = (0.444) * (m_lower) * (9.8 m/s^2)The force you need to exert is therefore:F_tension = (0.444) * (m_lower) * (9.8 m/s^2)The magnitude of the friction force on the upper box is:F_friction_upper = u_s * N_upperWhere:F_friction_upper is the force of friction on the upper boxu_s is the coefficient of static friction between the two boxesN_upper is the normal force acting on the upper boxSubstituting the given values, we get:F_friction_upper = (0.800) * (m_upper) * (9.8 m/s^2)The direction of the friction force on the upper box is opposite to the direction of motion of the upper box.

Answer:

It will be cut in half

Explanation:

The diffraction of a slit is given by the formula

a sin θ = m where

a = width of the slit,

λ = wavelength and

m = integer that determines the order of diffraction.

Next we divide both sides by a, we have

sin θ = m λ / a

Also, recall that

a’ = 2 a

Then we substitute in the previous equation

2asin θ' = m λ, if divide by 2a, we have

sin θ' = (m λ / 2a).

Now again, from the first equation, we said that sin θ = m λ / a, so we substitute

sin θ ’= sin θ / 2

Then we use trigonometry to find the width, we say

tan θ = y / L

Since the angle is small, we then have

tan θ = sin θ / cos θ

tan θ = sin θ, this then means that

sin θ = y / L

we will then substitute

y’ / L = y/L 1/2

y' = y / 2

this means that when the slit width is doubled the pattern width will then be halved

To calculate the torque required to create an angular acceleration, we can use the formula:

Torque = Moment of Inertia × Angular Acceleration

The moment of inertia of a disk can be calculated using the formula:

Moment of Inertia = (1/2) × Mass × Radius^2

Given:

Mass = 15,000 kg

Radius = 6.14 m

Angular Acceleration = 0.0500 rad/s^2

First, calculate the moment of inertia:

Moment of Inertia = (1/2) × Mass × Radius^2

Moment of Inertia = (1/2) × 15,000 kg × (6.14 m)^2

Next, calculate the torque:

Torque = Moment of Inertia × Angular Acceleration

Torque = Moment of Inertia × 0.0500 rad/s^2

Now, let's plug in the values and calculate:

Moment of Inertia = (1/2) × 15,000 kg × (6.14 m)^2

Moment of Inertia ≈ 283,594.13 kg·m^2

Torque = 283,594.13 kg·m^2 × 0.0500 rad/s^2

Torque ≈ 14,179.71 N·m

Rounding to three significant figures, the torque required to create an angular acceleration of 0.0500 rad/s^2 is approximately 14,180 N·m.

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Here are two examples of work done to store potential energy i.e. Lifting a weight, and stretching a spring.

1. Lifting a weight: When you lift a weight against the force of gravity, you are doing work to store potential energy in the weight. As you lift the weight, you are increasing its height above the ground, which increases its potential energy. The work you do to lift the weight is equal to the increase in potential energy of the weight.

2. Stretching a spring: When you stretch a spring, you are doing work to store potential energy in the spring. As you stretch the spring, you are increasing its length, which causes the spring to store potential energy. The work done you do to stretch the spring is equal to the potential energy stored in the spring.

In both of these examples, work is done to store potential energy in an object by changing its position or shape. This stored potential energy can be released later to do work on other objects, such as when a weight is dropped or a spring is released.

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The kinetic energy of a body determines it's level of impact on the object in which it comes in contact with. Hence, the much larger kinetic energy exhibited by a wrecking ball compared to a yo-yo means that is has a much larger impact on a building than a yo-yo.

The kinetic energy of a body is a factor of it's velocity and mass as they are directly proportional.

The wrecking ball has a very large mass which is thousands of times larger than that of a yo-yo. Also, the velocity at which a wrecking ball is launched is higher than the velocity of a yo-yo.

This means that the kinetic energy of a wrecking ball is much higher than that of yo-yo. Hence, having much greater impact on a building compared to a yo-yo.

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Answer:

128

Explanation:

Answer:

54 degrees

Explanation:

Answer:

a

   \(v  =  5.39 \  m/s\)

b

Horizontal component

     \(v_x  =  5.00 \  m/s\)

vertical component

     \(v_y  =  - 2.0 \  m/s\)

c

     \(t =  0.921 \  s\)

d

\(d = 4.605 \  m \)

Explanation:

Generally from the question we can deduce that he initial velocity of the cork, as seen by an observer on the ground in terms of the x  unit vector is  

     \(v_x  =  5.00 \  m/s\) due to the fact that the cork is moving horizontally

Generally from the question we can deduce that the vertical and horizontal  components of the initial velocity is  

       \(v_y  =  - 2.0 \  m/s\) due to the fact that the balloon is moving downward which is the negative which will also cause the cork to move vertically with the balloon speed

Generally the  initial velocity (magnitude and direction) of the cork, as seen by an observer on the ground is mathematically represented as

       \(v  =  \sqrt{ v^2 _x  + v^2 _y  }\)

       \(v  =  \sqrt{ 5^2  + (-2)^2 _y  }\)

        \(v  =  5.39 \  m/s\)

Generally the  initial direction of motion as seen by the same observer is mathematically represented as

    \(\theta =  tan^{-1}[\frac{2}{5} ]\)

    \(\theta  =  21.80^o\)

Generally the time taken by the cork in the air before landing is mathematically represented as

       \(D  =  ut  + \frac{1}{2} g t^2\)

So  D =  6 \  m from the question

     g =  9.8 \  m/s^2

     u  =  \(v_y\) =  2 m/s  this because we are considering the  vertical motion

So

     \(6  =   2 t  + \frac{1}{2} *  9.8*  t^2\)

       \(6  =   2 t  + 4.9  t^2\)

Solving using quadratic formula w have that

      \(t =  0.921 \  s\)

Generally the distance of the cork from the balloon is mathematically represented as

     \(d = v_x  *  t\)

    \(d = 5  * 0.921 \)

      \(d = 4.605 \  m \)

Answer:2.23 m/s

Explanation:

Given

Mass of person and vehicle is \(m=1600\ kg\)

Total work done is \(W_t=6000\ J\)

Friction consumes one-third of the energy

The remaining two-third is consumed to increase the kinetic energy

\(\Rightarrow \dfrac{2}{3}\times 6000=\dfrac{1}{2}\times 1600\times v^2\\\\\Rightarrow 4000\times 2=1600\times v^2\\\\\Rightarrow v=\sqrt{5}\ \approx 2.23\ m/s\)

1200 joule is work done on the stone by friction

mass=20 kg

v=2 m/s

d= 30 m

work done= Fd

work done=20×2×30

work done=1200 joule

An external force must exert at least a fraction of its force in the direction of the displacement when it moves an object over a distance. Physics refers to this as work done. Work may be estimated if the force acting along the path is constant by multiplying the length of the path by the component of the force acting along the path. To quantitatively express this concept, the work W is equal to the force f times the distance h, or W = mgh. If the force is applied at an angle to the displacement, the work is W = mas.

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Answer:

vfyugpuvfhvjvfhuvihfiurj

Explanation:

vfehgwfljhgiurnjfkfjhk

Answer:

Explanation:

F = GMm/d²

F = 6.67259 x 10⁻¹¹(2.39)(0.016) / 0.0681²

F = 5.5019685...x 10⁻¹⁰ N

round as appropriate, probably no more than 3 significant figures.

Value of G seems low, but well within the 3 significant figures of the other numerals. I typically see G = 6.674 x 10⁻¹¹

When the thistle funnel is moved upwards towards the surface of the liquids, the height (h) decrease.

What happens when the thistle funnel is moved upward?

An important principle outlined by Pascal's law states that any fluid (in this instance, liquids) experiences equal transmission of force in every direction within it. Hence, there is an intimate relationship between the height of a liquid column and its pressure.

Raising a thistle funnel reduces this height causing loss of weight from above this point thus decreasing its pressure.

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See complete question in the attached image.

Answer:

The tension in the light rope must be equal to the weight of the bucket

Explanation:

Given that,

Constant velocity of bucket and direction of bucket in downward

We need to find the tension in the rope

Using given data,

When a bucket  moves downward with a constant velocity then the net force does not applied on the bucket.

So, The weight of the bucket will be equal to the tension in the light rope

In mathematically,

\(T=mg\)

Where, T = tension

m = mass of bucket

g = acceleration due to gravity

Hence, The tension in the light rope must be equal to the weight of the bucket.

Answer:

refraction is the change in direction of a wave passing from one medium to another or from a gradual change in the medium.

Answer:

average speed = 50km/hr

average velocity =0

Explanation:

the average speed equals to average of these two speeds as the distance covered in both the cases are same.

average speed = (40+60)/2= 50km/hr

as the train returns to the same point the displacement is zero,

hence the average velocity is zero.

The average speed of the train is 50 km/hr.

The average velocity of the train is zero.

Speed of the train when it travels from the first station, v₁ = 40 km/hr

Speed of the train when it returns to the first station, v₂ = 60 km/hr

The expression for the average speed of the train is given by,

Average speed = (v₁ + v₂)/2

Average speed = (40 + 60)/2

Average speed = 100/2

Average speed = 50 km/hr

Since, the train travels from the first station, reaches the second station and then it again returns back to the first station, the total displacement covered by the train will become zero.

s = 0

Therefore, the average velocity of the train is also zero.

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So, the number with the greatest number of significant figures is:

0.009514. [Option B]

Answer:

75 cm/second.

Explanation:

Formula:

Walking speed = stride length / time per step

Walking speed = 90cm/time per step

                         = 90cm/1.2 seconds (a common estimate time per step)

                         = 75cm/second.

Answer:

they all kinda fit together like a puzzle also because they can tell now that the continates are moving so, they can asume that they have always been moving

Answer:

deformation : elastic deformation is reversed when the force is removed. inelastic deformation is not fully reversed when the force is removed – there is a permanent change in shape.

Explanation:

tysm