If the spring constant is 30 N/m and x
has a value of 0.5 m as shown in the
attached diagram, what is m equal to?
Answers
Hooke's Law gives the relationship between applied forces m·g, 2·m·g and extensions of an elastic material x, 2·x based on its elasticity.
The value of the mass, m is approximately 1.53 kg.Reason:
Given parameter;
Spring constant = 30 N/m
Value of the extension, x = 0.5 m
Extension of the spring by mass, m = x
Extension of the spring by mass, 2·m = 2·x
Required:
To find the value of mass m.
Solution:
The measures of weight and extension from the diagram are;
\(\begin{array}{|l|cl|}\mathbf{Extension}&&\mathbf{Weight \ (Force), \, F}\\0&&0\\x&&m \cdot g\\2 \cdot x&&2 \cdot m \cdot g\end{array}\right]\)
The rate of change of the extension with the applied force are;
\(Between \ second \ and \ frirst\ row, \ \dfrac{\Delta F}{\Delta x} =\dfrac{m \cdot g}{x}\)
\(Between \ third \ row \ and \ second \ row, \ \dfrac{\Delta F}{\Delta x} = \dfrac{2 \cdot m \cdot g - m \cdot g}{2 \cdot x - x} = \dfrac{m \cdot g}{x}\)
Therefore;
The rate of change of the extension with the applied force, \(\dfrac{\Delta F}{\Delta x}\), is a
constant equal to m·g, and the spring obeys Hooke's law.
According to Hooke's law, force applied to the spring, F = -K·xWhere;
F = The spring force
Therefore;
The force applied by the weight of the mass, m·g = -F∴ m·g = -(-k·x) = 30 N/m × 0.5 m
Where;
g = Acceleration due to gravity = 9.81 m/s²
\(m = \dfrac{30 \, N/m \times 0.5 \, m }{9.81 \, m/s^2} \approx 1.53 \, kg\)The mass, m ≈ 1.53 kg
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Related Questions
Choose the appropriate descriptor for the term square centimeter .
A. mass
B. length
C. volume
D. area
Answers
it takes the elevator in a skyscraper 4.0 s to reach its cruising speed of loms. a bu kg passenger gets aboard on the eround floor. what is the passenger's weight a. before the elevator startsm o v i n g ! b. while the elevator is speeding up? c. after the elevator reaches itscruising speed?
Answers
The passenger's weight remains the same throughout the elevator's motion. The weight is determined by the gravitational force acting on the passenger, which is unaffected by the elevator's motion.
let's consider the three scenarios:
a. Before the elevator starts moving: The passenger's weight is determined by the gravitational force acting on them. Therefore, the weight of the passenger is the same as their mass multiplied by the acceleration due to gravity (9.8 m/s^2).
b. While the elevator is speeding up: During this phase, the passenger experiences an additional acceleration due to the elevator's upward motion. The passenger's apparent weight increases, resulting from the combination of the gravitational force and the upward acceleration of the elevator. The total force acting on the passenger is the sum of their actual weight (mg) and the upward force due to acceleration (ma), where m is the mass of the passenger and a is the elevator's acceleration.
c. After the elevator reaches its cruising speed: Once the elevator reaches its cruising speed, it travels at a constant velocity, and the passenger experiences a steady state without any acceleration. At this point, the passenger's weight returns to their actual weight, determined solely by the gravitational force.
Therefore, the passenger's weight is the same before the elevator starts moving (a) and after it reaches its cruising speed (c), while it increases during the period when the elevator is speeding up (b) due to the combined effects of gravitational force and upward acceleration.
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Which apgar score indicates a moderately depressed newborn that requires stimulation and oxygen?
Answers
An Apgar score of 4 to 6 indicates a moderately depressed newborn that requires stimulation and oxygen.
The Apgar score is a quick assessment conducted one minute and five minutes after birth to evaluate the newborn's overall well-being and to determine if any immediate medical intervention is required.
The Apgar score is a scoring system used to assess a newborn's appearance, pulse, grimace, activity, and respiration.
Each category is assigned a score of 0 to 2, with a total score ranging from 0 to 10. A score of 4 to 6 indicates moderate depression in the newborn. In this range, the baby may require stimulation, such as rubbing the back or feet, and supplemental oxygen to help improve their condition and initiate normal breathing.
The healthcare provider will closely monitor the baby's progress and provide appropriate care based on their specific needs.
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What is the weight of a 328N emperor penguin?
Answers
Answer:
Weight = 3217.68
Explanation:
N times Gravity = weight
Gravity= 9.81
The weight of the emperor penguin whose mass is 328 Kg on is 3214.4 Newtons.
What is Weight ?
Weight is the force exerted by the earth on an object at the surface of the earth. Mathematically -
W = m x g
where -
[m] is the mass of object
[g] is acceleration due to gravity
Given is the mass of an emperor penguin as 328 Kg.
We can write -
Mass [m] = 328 kg
Acceleration due to gravity [g] = 9.8 m/s²
Therefore, the weight of the emperor penguin will be
W[P] = m x g = 328 x 9.8 = 3214.4 Newtons
Hence, the weight of the emperor penguin whose mass is 328 Kg on is 3214.4 Newtons
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is there any machine that is 100% efficient? why?why not
Answers
Answer:
No, it's not there.
Explanation:
For a machine to be 100% efficient, it has to be with an output which is equal to its input. But machines have an out put less than an input, hence efficiency below 100%.
A 1.5 kg ball is kicked with an initial velocity of 26 m/s at an angle of 30 degrees above the horizontal. How far did the ball go before returning to the ground? Answer in meters.
Answers
The maximum height travelled by the ball before returning to the ground is 8.62 m.
What is the maximum height travelled by the ball?
The maximum height travelled by the ball before returning to the ground is calculated by applying the following kinematic equation as shown below.
H = (u²sin²θ) / 2g
where;
u is the initial velocity of the ballθ is the angle of projection of the ballg is acceleration due to gravityH = (26² (sin 30)²) / (2 x 9.8)
H = 8.62 m
Thus, the maximum height travelled by a projectile depends on the initial velocity and angle of projection.
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During a collision with another car, the occupants of a minivan initially travelling at 4.0 m/s come to a complete stop in 0.5 s. What was the acceleration of the occupants of the minivan?
a) 8.0 m/s2
b) –8.0 m/s2
c) 2.0 m/s2
d) –2.0 m/s2
Answers
Answer: b) - 8.0 \(m/s^{2}\)
Explanation: Acceleration is a vector indicating a rate an object's velocity changes over time:
a = \(\frac{v}{t}\)
and its SI unit is \(m/s^{2}\)
For the minivan to stop, it takes a period of 0.5s:
a = \(\frac{4.0}{0.5}\)
a = 8.0 \(m/s^{2}\)
As a vector, acceleration has magnitude (8\(m/s^{2}\)) and direction. Since it is stopping, the minivan has a direction opposite to the other car, which means acceleration is negative. So: a = \(- 8.0 m/s^{2}\).
a boat travels 12.0 m while it reduces its velocity from 9.5 m/s to 5.5 m/s. what is the magnitude of the boat’s acceleration while it travels the 12.0 m?
Answers
Answer:
-2.5 \(m/s^2\)
Explanation:
We can use the kinematics equation below to find the boat's acceleration.
\(V_{f} ^{2}= V_{i} ^{2}+2ax\)
Lets solve for \(a\).
Subtract \(V_i^2\) from both sides of the equation.
\(2ax=V_{f} ^{2}- V_{i} ^{2}\)
Divide each term in \(2ax=V_{f} ^{2}- V_{i} ^{2}\) by \(2x\).
\(\frac{2ax}{2x} =\frac{V_{f} ^{2}}{x} +\frac{- V_{i} ^{2}}{2x}\)
Simplify the left side.
Cancel the common factor of 2.
\(\frac{ax}{x} =\frac{V_{f} ^{2}}{x} +\frac{- V_{i} ^{2}}{2x}\)
Cancel the common factor of x.
\(a=\frac{V_{f} ^{2}}{x} +\frac{- V_{i} ^{2}}{2x}\)
Simplify the right side.
Move the negative in front of the fraction.
\(a=\frac{V_{f} ^{2}}{2x} -\frac{ V_{i} ^{2}}{2x}\)
Now we have an equation for \(a\).
We are given
\(V_f=5.5\\V_i=9.5\\x=12\)
Substituting our numbers into the equation gives us
\(a=\frac{5.5^{2}}{2*12} -\frac{ 9.5 ^{2}}{2*12}\)
\(a=\frac{30.25}{2*12} -\frac{90.25}{2*12}\)
\(a=\frac{30.25}{24} -\frac{90.25}{24}\)
\(a=-2.5\)
what is the SI unit of a force
Answers
Answer:
The So unit of force is the newton,symbol N. the base units relevant to force.
Answer
the SI unit of force is newton
which of the following describes the magnitude of the momentum of the object in the first two straight-line segments shown in the graph as the object moves from point h to point j ?
Answers
The magnitude of the momentum in the first two straight-line segments of the graph remains the same throughout the object's motion from point h to point j.
The magnitude of the momentum of the object in the first two straight-line segments shown in the graph as it moves from point h to point j can be described as **constant**.
In the initial segments of the motion, the graph shows a straight-line portion, indicating that the object's momentum remains constant. This means that the object maintains a consistent magnitude of momentum during this time interval. The momentum of an object is the product of its mass and velocity, and if the velocity remains constant, the momentum will also remain constant. Therefore, the magnitude of the momentum in the first two straight-line segments of the graph remains the same throughout the object's motion from point h to point j.
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what is one weird thing that happens at absolute zero?
Answers
Answer:
Atoms cannot move.
Explanation:
A student designs an experiment to demonstrate the conservation of gravitational potential and kinetic energy. She drops a wooden block from rest through a photogate 2 m below. If energy is conserved, how fast should the block be traveling when it passes through the photogate?
A.
2.0 m/s
B.
6.3 m/s
C.
9.8 m/s
D.
19.6 m/s
Answers
Answer:
6.3 m/s
Explanation:
A student drops a wooden block from rest through a photogate 2 m below. Since there is a conservation of the gravitational potential energy and the kinetic energy, the final speed of the block is B. 6.3 m/s.
Gravitational potential energy and kinetic energyGravitational potential energy: is the potential energy a massive object has in relation to another massive object due to gravity.Kinetic energy: is a form of energy that an object or a particle has by reason of its motion.A wooden block is dropped from rest. If energy is conserved, the initial gravitational potential energy (U₁) will be equal to the final kinetic energy (K₂).
U₁ = K₂
m × g × h₁ = 1/2 × m × v₂²
where,
m is the mass of the object.g is the gravity.h₁ is the initial height.v₂ is the final speed.m × g × h₁ = 1/2 × m × v₂²
g × h₁ = 1/2 × v₂²
v₂ = √(2 × g × h₁)
v₂ = √(2 × (9.8 m/s²) × 2 m) = 6.3 m/s
A student drops a wooden block from rest through a photogate 2 m below. Since there is a conservation of the gravitational potential energy and the kinetic energy, the final speed of the block is B. 6.3 m/s.
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An ionized oxygen molecule (O2+) at point a has a charge +e and moves at 2.00 x 10^3 m/s in the positive x-direction. A constant electric force in the negative x-direction slows the molecule to a stop a point B, a distance of 0.750 mm past A on the x-axis. Calculate (a) the x-component of the electric field and (b) the potential difference between points A and B.
Answers
The x-component of the electric field is -8.84 x 10^3 N/C and the potential difference between points A and B is 6.63 V.
The ionized oxygen molecule moves from point A to point B due to the electric force. The electric force is equal to the product of the charge and the electric field. The work done by the electric force is equal to the change in kinetic energy of the molecule.
(a) To find the x-component of the electric field, we can use the equation for work done by the electric force:
W = Fx * d = q * Ex * d
Where W is the work done, Fx is the x-component of the electric force, d is the distance, q is the charge, and Ex is the x-component of the electric field. We can rearrange the equation to solve for Ex:
Ex = W / (q * d)
We know that the work done is equal to the change in kinetic energy:
W = ΔKE = (1/2) * m * v^2 - (1/2) * m * u^2
Where m is the mass, v is the final velocity, and u is the initial velocity. The final velocity is zero, so the equation simplifies to:
W = -(1/2) * m * u^2
Plugging this into the equation for Ex, we get:
Ex = -(1/2) * m * u^2 / (q * d)
Plugging in the given values:
Ex = -(1/2) * (5.31 x 10^-26 kg) * (2.00 x 10^3 m/s)^2 / ((1.60 x 10^-19 C) * (0.750 x 10^-3 m))
Ex = -8.84 x 10^3 N/C
(b) To find the potential difference between points A and B, we can use the equation:
ΔV = -Ex * d
Plugging in the values for Ex and d:
ΔV = -(-8.84 x 10^3 N/C) * (0.750 x 10^-3 m)
ΔV = 6.63 V
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Help needed!
A force of 6.36 N acts on a(n) 4.9 kg object for 20.4 s. What is the objects change in momentum?
What is the change in velocity?
WU
Answers
Change in the momentum of the object with mass 4.9 kg on which force of 6.36 N acts for 20.4 s is 31.164kgm/s and change in velocity is 6.36m/s
As we know Force acting on any object is
F = m.a...........(1)
where m ⇒ mass
and a ⇒ acceleration
Also \(a=\frac{v}{t}\)..........(2)
where v ⇒ velocity
t ⇒ time
so equation (1) can be written as:
\(F=\frac{m.v}{t}\)..........(3)
Change in Momentum is equal to
p=m.v.......(4)
where m ⇒ mass
v ⇒ velocity
Now as per the question:
Force, F = 6.36 N
Mass, m = 4.9 kg
Time, t = 20.4s
putting the values in equation (3),
we get \(6.36=\frac{4.9*v}{20.4}\)
by solving this we get a value of v=6.36m/s
putting the values in equation (4)
we get, Change in momentum
\(p=4.9*6.36\\p=31.164kg m/s\)
so the change in velocity is 6.36m/s and change in momentum is 31.164kgm/s
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atoms in a thin, hot gas (such as a neon advertising sign), according to kirchhoff's laws, emit light at
Answers
Atoms in a thin, hot gas (such as a neon advertising sign) emit light at particular wavelengths, which is called spectral lines. When a thin, hot gas is examined using a spectroscope, the spectral lines are produced. In other words, these spectral lines are unique to the element that emits them.
According to Kirchhoff's laws, atoms in a thin, hot gas (such as a neon advertising sign) emit light at particular wavelengths, which is called spectral lines.
When a thin, hot gas is examined using a spectroscope, the spectral lines are produced. In summary, Kirchhoff's laws state that the spectral lines of a hot gas are unique to the element that emits them. These spectral lines can be used to identify the element present in the gas.
Atoms in a thin, hot gas (such as a neon advertising sign) emit light at particular wavelengths, which is called spectral lines. When a thin, hot gas is examined using a spectroscope, the spectral lines are produced. In other words, these spectral lines are unique to the element that emits them.
These spectral lines can be used to identify the element present in the gas. According to Kirchhoff's laws, when an electric current is passed through a thin gas in a discharge tube, the atoms in the gas absorb energy from the electric current and emit light.
The light is then separated into its component colors using a prism. A bright line spectrum is generated when the prism disperses the light into its component colors. The bright line spectrum corresponds to the energy absorbed and emitted by the atoms of the gas. Therefore, the bright line spectrum can be used to identify the elements present in the gas.
Kirchhoff's laws describe how elements produce a bright line spectrum, which can be used to identify elements present in a gas. When a thin, hot gas is examined using a spectroscope, the spectral lines are produced. The spectral lines are unique to the element that emits them.
The spectral lines can be used to identify the element present in the gas. When an electric current is passed through a thin gas in a discharge tube, the atoms in the gas absorb energy from the electric current and emit light. The light is then separated into its component colors using a prism.
The bright line spectrum is generated when the prism disperses the light into its component colors. The bright line spectrum corresponds to the energy absorbed and emitted by the atoms of the gas. The bright line spectrum can be used to identify the elements present in the gas.
In conclusion, Kirchhoff's laws state that the spectral lines of a hot gas are unique to the element that emits them. These spectral lines can be used to identify the element present in the gas. A bright line spectrum is produced when the light from a hot gas is separated into its component colors using a prism. The bright line spectrum corresponds to the energy absorbed and emitted by the atoms of the gas. Therefore, the bright line spectrum can be used to identify the elements present in the gas.
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the lungs are ___________ to the heart
Answers
Answer:
The lungs are lateral to the heart.
Explanation:
Answer:
lateral
Explanation:
can you get velocity from speed
Answers
Answer:
yes
Explanation:
velocity is vector though but speed is scalar
velocity requires direction
so velocity is literally speed with direction
Suppose an adult blue whale is stranded on a beach. The whale, which lies parallel to the shore, is 15 m from water deep enough for it to swim away in. A group of people line up along the side of the whale to push it back into the ocean. If the whale’s weight is 1. 5 × 10 6 N, and the force of friction that must be overcome by the people is 0. 25 times the whale’s weight, how much work must the people do on the whale in order to return it to the ocean?
Answers
Answer:
W = F x work done by force F thru distance X
F = w + .25 w = 1.25 w where w is the weight of the whale
x = 15 m distance the whale must be pushed
W = 1.25 w * x
W = 1.25 * 1.5E6 N * 15 m = 18.75E6 N * 15 m = 2.81E7 joules
Work done people on the whale in order to return it to the ocean is 5.625 ×10⁶ Joule.
What is friction?The resistance provided by surfaces in touch as they move past one another is known as friction. To walk without slipping, traction is provided by friction. In most situations, friction is advantageous. They do, however, give a strong amount of opposition to the move.
Given parameter:
Weight of the whale, W = 1.5×10⁶ N.
The people push it back a distance, d = 15 m.
Coefficient of friction on the surface, μ = 0.25.
The work done by the people on the whale in order to return it to the ocean is equal to work done against the friction. As, No work is done against gravitation on moving a object on the surface of earth,
Frictional force acting on the whale,
F= μ× normal reaction
= μ× weight of the whale
= 0.25 × 1.5× 10⁶ N.
= 3.75 ×10⁵ N.
Hence, work done by the people = F.d = 3.75 ×10⁵ × 15 Joule
= 5.625 ×10⁶ Joule.
Hence, people have to do 5.625 ×10⁶ Joule work.
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Question 12 of 20
How does decreasing the length of a wire affect a circuit?
A. It reduces the resistance caused by the wire.
B. It reduces the voltage carried by the wire.
O C. It increases the resistance caused by the wire.
D. It increases the current passing through the wire.
Answers
If we decrease the length of the wire in a circuit, It reduces the resistance.
What is resistance?Resistance is the opposition offered to the flow of current by a circuit element. The factors that affect resistance include;
Length of the wireCross sectional area of the wireHence, if we decrease the length of the wire in a circuit, It reduces the resistance caused by the wire since the resistance depends on the length of the wire.
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Answer: A
Explanation:
What is the momentum of a 0.5 kg football thrown -5 m/s to the left?
Answers
Answer: -2.5 kg/m/s
Explanation: Momentum is equal to mass times velocity, so you do 0.5 kg times -5 m/s, and you get -2.5 kg/m/s.
As a block falls through the air by 40m it does work equal to-1800. Determine the mass ofthe block
Answers
Answer:
don't
Explanation:
The mass of the block is 4.5 kg that falls by 40m and work done is -1800J.
What is work done?The work done is defined as the product of the displacement of an object and the component of the applied force which is in the direction of the object's displacement.
w=f × s
-1800=f×40
f=45 N
by Newton's 2nd law
F=ma
45=m×(10)
m=45÷10=4.5 kg
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A gas occupies 500mL at a temperature of 20 degrees Celsius. What is the volume at 150 degrees Celsius?
Answers
Answer: 3750 ML
Explanation:
what happens to the body when one organ is not working properly
Answers
Answer: Organ failure is when a major organ stops working. Major organs all have important jobs to keep the body alive. Each organ counts on the other ones to keep the body working. If one of these organs stops working, the patient will not be able to survive without the help of very strong medicines and/or machines.
Explanation:
Answer:
Organ failure is when a major organ stops working. Major organs all have important jobs to keep the body alive. Each organ counts on the other ones to keep the body working. ... If one of these organs stops working, the patient will not be able to survive without the help of very strong medicines and/or machines.
Explanation:
Please help with this question
Answers
Answer:
for your first question it is the first answer that is there for your second question it is the second answer that is there
Which theory explains that cussing in front of your grandparents or hugging a stranger would be okay to you based on social context?
Group of answer choices
Social cognitive theory
social trait theory
Social science theory
social concrete theory
Answers
a waddling armadillo of mass 500kg moves at 5 m/s. how much kinetic energy does it have?
Answers
Answer:
K=6.250 J
Explanation:
m=500kg
v=m/s
Kinetic energy= ½mv²=½(500×25) J= 6.250 J
A baby mouse 1. 2 cm high is standing 4. 0 cm from a converging mirror having a focal length of 30 cm
Answers
The problem involves the image formation of a small object by a converging mirror.
According to the mirror equation, 1/f = 1/di + 1/do, where f is the focal length of the mirror, do is the object distance, and di is the image distance. In this case, the object is a baby mouse that is 1.2 cm high and located 4.0 cm away from the mirror. The mirror is a converging mirror with a focal length of 30 cm. To determine the image distance, we can use the mirror equation as follows: 1/30 = 1/di + 1/4. Solving for di, we get: di = 3.75 cm. This means that the image of the baby mouse is formed 3.75 cm behind the mirror. The size of the image can be determined using the magnification equation, M = -di/do, where M is the magnification. Substituting the values, we get: M = -(3.75 cm)/(4.0 cm) = -0.9375. The negative sign indicates that the image is inverted compared to the object. The magnification also tells us that the image is smaller than the object, with a height of: hi = Mho = (-0.9375)(1.2 cm) = -1.125 cm. Again, the negative sign indicates that the image is inverted. The absolute value of the height tells us that the image is smaller than the object, with a height of 1.125 cm.
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The scientist changed the temperature each time he cooked an egg. The temperature change is the...
manipulated/independent variable
responding/dependent variable
Answers
Answer: Independent variable
Explanation: i think
What does the object below model?
O A. The heart
O B. The skeletal system
C. The brain
O D. The lungs
Answers
Answer: c
Explanation: it is c because i used my brain to answer it
Answer: The Brain
Explanation:
Its the brain
Water is to a river as ____________ is to a wire
Answers
Answer:current
Explanation:water flows down a river. Current flows down a wire (in the drude model, at least)
Answer:
electricity
Explanation: