If the price for a meal is $15 and there is a $3 dollar tip, what percentage of the total is the tip?

m = slope of the line

b = y-intercept of the line

b = y-intercept of line

m = slope of line

Hope this helps! Have a nice day! God bless and stay safe.

The art teacher can make a maximum of 24 identical kits using all the crayons and drawing paper for proper distribution.

To determine the largest number of identical kits the art teacher can make using all the crayons and drawing paper, we need to find the greatest common divisor (GCD) of the quantities.

The GCD represents the largest number that can divide all the quantities without leaving a remainder.

The GCD of the quantities of crayons can be found by considering the prime factorization:

72 = 2³ × 3²

48 = 2⁴ × 3

48 = 2⁴ × 3

48 = 2⁴ × 3

The GCD of the crayons is 2³ × 3 , which is 24.

Now, we need to find the GCD of the quantity of drawing paper:

120 = 2³ × 3 × 5

The GCD of the drawing paper is also 2³ × 3 , which is 24.

Since the GCD of both the crayons and drawing paper is 24, the art teacher can make a maximum of 24 identical kits using all the crayons and drawing paper.

Each kit would contain an equal distribution of crayons and drawing paper.

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Answer:

The amount of fabric needed to create one quilting square is 8 inches.

Answer:

The amount of fabric needed to create one quilting square is 8 inches.

Step-by-step explanation:

Part a; compounded semiannually (n = 2); CI =  $6,390.

Part b: compounded quarterly ( n = 4) ; CI =  $6,425

Part c: compounded monthly (n = 12): CI =  $6,450

Part d: compounded continuously; CI =  $6,467.

The compound interest is calumniated by formula.

A = P(1 + r/100n)∧nt

In which,

A  = amount after compounding

P = principal amount  ($20,000 )

n = number of time principal amount compounded in a year.

t = total time in years (7 years)

r= rate of interest (4%)

Part a; compounded semiannually (n = 2)

A = P(1 + r/100n)∧nt

A = 20,000(1 + 4/200)∧(2x7)

A = 26390

CI = A - P

CI =  26,390 -  20,000

CI =  $6,390.

Part b: compounded quarterly ( n = 4)

A = 20,000(1 + 4/400)∧(4x7)

A = 26425

CI = A - P

CI =  26,425 -  20,000

CI =  $6,425

Part c: compounded monthly (n = 12)

A = 20,000(1 + 4/1200)∧(12x7)

A = 26450

CI = A - P

CI =  26,450-  20,000

CI =  $6,450

Part d: compounded continuously.

P = P₀e∧rt

P = (20,000)(2.72)∧(0.04 x 7)

P = 20,000 x 1.32

P = 26,467

CI =  26,467 - 20, 000

CI =  $6,467.

Thus, the for compounded continuously is $6,467.

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The values of f(x) for the given x - values rounded to 4 decimal places are 0.0078, 0.0078, 0.0020, 0.0020, 0.0019 and 0.0013 respectively

Given the function :

Substitute the given value of x to obtain the corresponding f(x) values :

x = -0.6

f(x) = (tanπ(-0.6))/7(-0.6) = 0.0078358

x = -0.51

f(x) = (tanπ(-0.51))/7(-0.51) = 0.0078350

x = -0.501

f(x) = (tanπ(-0.501))/7(-0.501) = 0.001967

x = -0.5

f(x) = (tanπ(-0.5))/7(-0.5) = 0.001959

x = -0.4999

f(x) = (tanπ(-0.4999))/7(-0.4999) = 0.001958

x = 0.499

f(x) = (tanπ(-0.499))/7(-0.499) = 0.001951

x = -0.49

f(x) = (tanπ(-0.49))/7(-0.49) = 0.00188

x = -0.4

f(x) = (tanπ(-0.4))/7(-0.4) = 0.00125

Therefore, values which complete the table are 0.0078, 0.0078, 0.0020, 0.0020, 0.0019 and 0.0013

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Answer:

2 * 2 * 5 * 5

Step-by-step explanation:

100 = 2 * 50

       = 2 * 2 * 25

       = 2 * 2 * 5 * 5

The equation of pressure is given by:

\(p = \frac{f}{s} \)

where p is the pressure.

f is the applied force.

s is the surface area to which the force is applied.

I will start off by calculating the surface area of the table top given by:

\(s = l \times w = 1.8 \times 1.2 = 2.16\)

s=2.16 m²

We know that f=400 N, that is given.

\(p = \frac{400 \: n}{2.16 \: m {}^{2} } \)

Plug this on your calculator (excluding the units lol)

\(p = 185.185 \frac{n}{m {}^{2} } \)

\(p = 185 \frac{n}{m {}^{2} } \)

Addison spent 17 hours on the app and Charli spent 21 hours on the app

Answer:

Step-by-step explanation:

Angles can be either straight, right, acute or obtuse.

An angle is a fraction of a circle where the whole circle is 360°.

Two angles whose measures together are 180° are called supplementary

two right angles are supplementary since 90° + 90° = 180°.

Answered by NONE other than the ONE & ONLY #QUEEN herself aka #DRIPPQUEENMO!!!

HOPE THIS HELPED!!!!

Angles are classified by what degree/position they’re in. So lets say you got a straight line, now imagine you laying the line on a flat surface. Like a pencil? It’s straight and does not bend. That’s 180 degrees. That would be called a straight angle. It kinda makes sense does it? Now a acute angle is when you bend the line till it has little space! That would be called a “acute” angle. Like cute things are small? Imagine that! And a 360 degree angle is when you just fully turn the line around until it gets back to its original spot! Your just making a whole circle till you get back to your original position. Hope this helps! <3

a) B', complement of B =  {a, b, d, f, h}

b) AN B', A intersection B' =  {b, h}

c) (A/B), or A - B = {a, b, h}

d) BU (CNA)​, B union (C intersection A) = {a, b, c, d, e, g, h}

a) The complement of B, denoted B', consists of all elements in U that are not in B. Thus, we have:

B' = {a, b, d, f, h}

b) A intersection B' consists of all elements that are in A but not in B. From the given sets, we have:

B' = {a, b, d, f, h}

A = {a, b, c, e, h}

Thus, A intersection B' = {b, h}

c) A/B, also denoted A - B, consists of all elements in A that are not in B. From the given sets, we have:

A = {a, b, c, e, h}

B = {c, e, g}

Thus, A/B = {a, b, h}

d) CNA is the union of C and A. From the given sets, we have:

A = {a, b, c, e, h}

C = {a, c, d, g, e}

Thus, A union C = {a, b, c, d, e, g, h}.

Finally, BU(A union C) is the union of B with A union C. From the given sets, we have:

B = {c, e, g}

A union C = {a, b, c, d, e, g, h}

Thus, BU(A union C) = {a, b, c, d, e, g, h}

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Answer:

1.63

Step-by-step explanation:

Answer:

2 2/3 hours or 2 hours and 4o minutes

Step-by-step explanation:

set up a proportion

\(\frac{time}{distance}\) = \(\frac{time}{distance}\)

\(\frac{\frac{4}{5} }{\frac{3}{10} }\) = \(\frac{h}{1}\)cross multiply and solve for h

\(\frac{3}{10}\) h = \(\frac{4}{5}\)  Multiply both sides by \(\frac{10}{3}\)

\((\frac{10}{3})\)\(\frac{3}{10}\) h = \((\frac{10}{3})\)\(\frac{4}{5}\)  Multiply and then divide the top and bottom by 5

h = \(\frac{8}{3}\) o r2 \(\frac{2}{3}\)

a. The answer is: The fewest number of multibase blocks required to represent 20 longs in base seven is 2 flats.

b. The answer is: The fewest number of multibase blocks required to represent 10 longs in base three is 3 flats and 1 unit.

a. To represent 20 longs in base seven, we need to find the fewest number of multibase blocks required.

In base seven, we have the following conversions:

1 long = 1 unit

1 flat = 10 units

1 block = 10 flats

To represent 20 longs, we can use 2 flats (each flat representing 10 units) and 0 units since there are no remaining units.

So, the fewest number of multibase blocks required would be 2 flats.

Therefore, the answer is: The fewest number of multibase blocks required to represent 20 longs in base seven is 2 flats.

b. To represent 10 longs in base three, we need to find the fewest number of multibase blocks required.

In base three, we have the following conversions:

1 long = 1 unit

1 flat = 3 units

1 block = 3 flats

To represent 10 longs, we can use 3 flats (each flat representing 3 units) and 1 unit since there is one remaining unit.

So, the fewest number of multibase blocks required would be 3 flats and 1 unit.

Therefore, the answer is: The fewest number of multibase blocks required to represent 10 longs in base three is 3 flats and 1 unit.

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9514 1404 393

Answer:

Step-by-step explanation:

Assuming the events are independent, the numbers of ways are multiplied in order to find the total number of possible ways a combination of events can happen.

1. 3×4 = 12

2. 1×5 = 5

3. 4×6×2 = 48

4. 2×9×5 = 90

Number of raisins in the bag is 160 raisins

Given that;

Ratio of peanuts to raisins = 5:4

Bag of the snack mix contains = 200 peanuts

Find:

Number of raisins in the bag

Computation:

Number of raisins in the bag = 4[200/5]

Number of raisins in the bag = 4[40]

Number of raisins in the bag = 160 raisins

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Answer:

211.1

Step-by-step explanation:

3 isn't greater than or equal to 5 so it will not round up to 2 so your answer will be 211.1

Answer:

211.1

Step-by-step explanation:

Rounded to the nearest 10th

Answer:

A = 2184 cm²

Step-by-step explanation:

the area (A) of the figure is calculated as

A = \(\frac{1}{2}\) h(b₁ + b₂)

where h is the perpendicular height between the bases b₁ and b₂

here h = 42 , b₁ = 52 , b₂ = 52 , then

A = \(\frac{1}{2}\) × 42 × (52 + 52) = 21 × 104 = 2184 cm²

Answer:

A = 2184 cm2

Step-by-step explanation:

Area of a parallelogram:

\(A = b*h\)

\(b=52,h=42\)

\(A=(42)(52)=2184cm^{2}\)

Hope this helps.

Answer:

074°

Step-by-step explanation:

the bearing of Y from X is the measure of the angle from the north line (N) at X in a clockwise direction to Y , that is ∠ NXY

∠ NXY = 180° - 106° = 74°

the 3- figure bearing of Y from X is 074°

The probability distribution for x is:

x P(x)

0 0.214

1 0.571

2 0.214

Since there are 8 cameras in the box, the total number of ways to choose 2 cameras from the box is given by the combination formula:

C(8,2) = 8!/(2!×(8-2)!) = 28

So there are 28 possible ways to choose a sample of 2 cameras.

Now, let's calculate the probability of each possible value of x:

When x = 0, both cameras in the sample are non-defective. The number of ways to choose 2 non-defective cameras from the 4 non-defective cameras in the box is given by the combination formula:

C(4,2) = 4!/(2!×(4-2)!) = 6

So the probability of x = 0 is:

P(x=0) = (number of ways to choose 2 non-defective cameras)/(total number of ways to choose 2 cameras)

= 6/28

= 0.214

When x = 1, one camera in the sample is defective and the other is non-defective. The number of ways to choose 1 defective camera from the 4 defective cameras in the box and 1 non-defective camera from the 4 non-defective cameras in the box is given by the product of the corresponding combinations:

C(4,1) × C(4,1) = 4×4 = 16

So the probability of x = 1 is:

P(x=1) = (number of ways to choose 1 defective camera and 1 non-defective camera)/(total number of ways to choose 2 cameras)

= 16/28

= 0.571

When x = 2, both cameras in the sample are defective. The number of ways to choose 2 defective cameras from the 4 defective cameras in the box is given by the combination formula:

C(4,2) = 4!/(2!×(4-2)!) = 6

So the probability of x = 2 is:

P(x=2) = (number of ways to choose 2 defective cameras)/(total number of ways to choose 2 cameras)

= 6/28

= 0.214

Therefore, the probability distribution for x is:

x P(x)

0 0.214

1 0.571

2 0.214

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3/5 or 60% of the grass died because the sprinkler could only water 1/5 of the yard.

Let's start by breaking down the information given:

- Three-fourths of the yard is covered with grass.

- One-fourth of the yard is used as a garden.

- The sprinkler could only water 1/5 of the yard.

To find out how much of the grass died, we need to determine the portion of the grass that was not watered by the sprinkler.

Let's assume the total area of the yard is represented by the value 1. Therefore, we can calculate the area of the grass as 3/4 of the total yard, which is (3/4) * 1 = 3/4.

The sprinkler can only water 1/5 of the yard, so the portion of the grass that was watered is (1/5) * (3/4) = 3/20.

To find the portion of the grass that died, we subtract the watered portion from the total grass area:

Portion of grass that died = (3/4) - (3/20) = 15/20 - 3/20 = 12/20.

Simplifying, we get:

Portion of grass that died = 3/5.

Therefore, 3/5 or 60% of the grass died because the sprinkler could only water 1/5 of the yard.

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Answer:

(2, 1) is a solution to this system of linear inequalities.

Step-by-step explanation:

To find the solution to this system of linear inequalities, you need to find the values of x and y that satisfy all of the given inequalities.

The first inequality, x < 5, means that x must be less than 5. The second inequality, y ≤ x, means that y must be less than or equal to x. The third inequality, y ≥ -3, means that y must be greater than or equal to -3.

The graph of this system of linear inequalities would be a region on the coordinate plane that represents all of the points that satisfy all of the inequalities. The solution to this system of linear inequalities would be the set of all points within this region.

So, to find the solution to this system of linear inequalities, you need to find the values of x and y that satisfy all of the given inequalities. For example, the point (2, 1) satisfies all of the given inequalities, because 2 < 5, 1 ≤ 2, and 1 ≥ -3. Therefore, (2, 1) is a solution to this system of linear inequalities.

Answer: (4,4)

Step-by-step explanation: All coordinate points that exist within the shaded region satisfy all of the inequalities. The point (4,4) is within the shaded region.

The radius of a circle with the same vertex as a center is 12 units

To get the radius of the circle, we need to determine the diameter of the circle first:

According to SOH CAH TOA:

\(sin\theta = \frac{opp}{hyp} \\sin60 = \frac{12\sqrt{3}}{hyp} \\hyp =\frac{12\sqrt{3}}{sin60} \\hyp =\frac{2\times12\sqrt{3}}{\sqrt3}} \\hyp = 24 = diameter\)

Determine the radius of the circle

Radius = dismeter/2

Radius = 24/2

Radius = 12

Hence the radius of a circle with the same vertex as a center is 12 units

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Answer:

y = 12

Step-by-step explanation:

Consider the triangles in the diagram. Triangle QRS (the smaller one on the left) and Triangle PRO (the whole shape)

These two triangles are similar. It helps to write them separately. See image.

You can use a proportion (two ratios equal to each other) to solve this.

There are two good ways to set up an equation.

EITHER:

bottomLeg/sideLeg=bottomLeg/sideLeg

OR

smallbottom/bigbottom=smallside/bigside

see image.

Either way you set it up the answer comes out the same. Pretty much all the work is the same after you crossmultiply.

Solve 9/y = 12/16

OR 9/12 = y/16

see image.

Answer:

D and E

Step-by-step explanation: Math

Answer:

d and e

Step-by-step explanation:

419.56-75.68=343.88

199.75+143.712=343.462

Answer:

I think that's 11,8

Step-by-step explanation:

Hope its right

Answer:

Step-by-step explanation:

\(\frac{25}{100} \times 56=\frac{1}{4} \times 56=\frac{56}{4}=14\)

Racer scored 14 points.

Answer:

$7.74

Step-by-step explanation:

The school buys 350 books. These books, in total, costed the school $1137.50. The school wants to make a profit of $1500.

For the school to make a profit on its purchase, it needs to earn $1500 more than the price that they paid for the books.

This means that we can add these values together to get the minimum amount that the school needs to earn

\(1137.50+1500=2637.50\)

Now that we have the minimum value, we can divide this by 350 in order to find the minimum price for each individual book.

\(\frac{2637.50}{350} =7.7357=7.74\)

This means that the school needs to sell these books for at least $7.74

(... This fictional school is selling the books for more than double the price they paid for them...)

The missing value 'x' in the two-way relative frequency table is 0.36.

To convert the two-way table to a two-way relative frequency table, we need to calculate the relative frequencies for each category. Relative frequency is calculated by dividing the frequency of a particular category by the total count in that row or column.

Let's denote the missing value as 'x'. To find the value of 'x', we need to ensure that the sum of the relative frequencies in each row and each column adds up to 1.

First, let's calculate the relative frequencies for each category:

Likes hockey: The total count in this row is 12 + 18 = 30.

Relative frequency of "Likes hockey" = 12/30 = 0.4

Relative frequency of "Doesn't like hockey" = 18/30 = 0.6

Likes baseball: The total count in this column is 12 + 14 = 26.

Relative frequency of "Likes baseball" = 12/26 ≈ 0.4615

Relative frequency of "Doesn't like baseball" = 14/26 ≈ 0.5385

To ensure that the relative frequencies add up to 1, we can set up the following equations:

0.4 + x = 1 (sum of relative frequencies in the "Likes hockey" row)

0.4615 + 0.5385 + x = 1 (sum of relative frequencies in the "Likes baseball" column)

Simplifying the equations, we have:

x = 0.6 (1 - 0.4) = 0.6 * 0.6 = 0.36

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