if a number is divisible by 5 then its final digit is 0

Answer:

30, +11, 11, -1

Step-by-step explanation:

-10 + 30 = 10, 40 - 30= 10

-3 + 11 = 8

5 + (1.5 x 4) = 11

5 - (1.5 x 4) = -1

Answer:  (c)  y = −1/3x −2

Step-by-step explanation:

I know it because I looked on brainly .

To prove △BDA ≅ △BDC, SSS congruence theorem should be used.

What is the Side-Side-Side congruence theorem of triangles?

If all three sides of one triangle are equivalent to the corresponding three sides of the second triangle, then the two triangles are said to be congruent by the SSS rule.

Given that ΔBDA is similar to ΔBDC and:

AD ≡ DC

AB ≡ BC

BD ≡ BD (shared side)

△BDA ≅ △BDC

The best postulate to use is the side-side-side (SSS) postulate.

Hence, to prove △BDA ≅ △BDC, the SSS congruence theorem should be used.

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I think the answer is 23

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

a) To calculate the pressure at 12 hours of shut-in:

substitute the given values into the pressure buildup equation and solve for P(t=12).

b) Superposition in time is used in pressure buildup analysis by adding or summing the responses of multiple transient tests to analyze and interpret reservoir behavior and properties.

We have,

a) To calculate the pressure in the production well at 12 hours of a shut-in, we can use the equation for pressure transient analysis during shut-in periods, known as the pressure buildup equation:

P(t) = Pi + (Q / (4πKh)) * log((0.14ϕμCt(t + Δt)) / (Bo(ΔP + Δt)))

Where:

P(t) = Pressure at time t

Pi = Initial reservoir pressure

Q = Flow rate

K = Permeability

h = Reservoir thickness

ϕ = Porosity

μ = Viscosity

Ct = Total compressibility

t = Shut-in time (12 hours)

Δt = Time since the start of the flow period

Bo = Oil formation volume factor

ΔP = Pressure drop during the flow period

Given:

Pi = 3100 psi

Q = 200 STB/day

K = 45 md

h = 60 ft

ϕ = 15%

μ = 1.2 cp

Ct = 15x10^-6 psi^-1

Bo = 1.3 bbl/STB

t = 12 hours

Δt = 48 hours

ΔP = Pi - P(t=Δt) = Pi - (Q / (4πKh)) * log((0.14ϕμCt(Δt + Δt)) / (Bo(ΔP + Δt)))

Substituting the given values into the equation:

ΔP = 3100 - (200 / (4π * 45 * 60)) * log((0.14 * 0.15 * 1.2 * 15x\(10^{-6}\) * (48 + 48)) / (1.3 * (3100 - (200 / (4π * 45 * 60)) * log((0.14 * 0.15 * 1.2 * 15 x \(10^{-6}\) * (48 + 48)) / (1.3 * (0 + 48))))))

After evaluating the equation, we can find the pressure in the production well at 12 hours of shut-in.

b) Superposition in time is a principle used in pressure transient analysis to analyze and interpret pressure build-up tests.

It involves adding or superimposing the responses of multiple transient tests to simulate the pressure behavior of a reservoir.

The principle of superposition states that the response of a reservoir to a series of pressure changes is the sum of the individual responses to each change.

Superposition allows us to combine the information obtained from multiple tests and obtain a more comprehensive understanding of the reservoir's behavior and properties.

It is a powerful technique used in reservoir engineering to optimize production strategies and make informed decisions regarding reservoir management.

Thus,

a) To calculate the pressure at 12 hours of shut-in:

substitute the given values into the pressure buildup equation and solve for P(t=12).

b) Superposition in time is used in pressure buildup analysis by adding or summing the responses of multiple transient tests to analyze and interpret reservoir behavior and properties.

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The truth value of the conditional statement is false, and the counterexample of this statement is corresponding angles

The conditional statement is given as:

If two angles are congruent, then they are vertical angles.

The above statement is false because not all congruent angles are vertical angles

A counterexample of this statement is a corresponding angle

i.e. corresponding angles are congruent angles, but they are not vertical angles

Hence, the truth value of the conditional statement is false, and the counterexample of this statement is a corresponding angle

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Answer:

3.777777777777777777777777777777777777 and it goes on

The value of a lies between 90.8209 and 91.0116 is 91. Then the correct option is C.

Inequality is simply a type of equation that does not have an equal sign in it. Inequality is defined as a statement about the relative size as well as is used to compare two statements.

The inequality is given as

9.53 < √a < 9.54

On squaring both sides, we have

  9.54² > a > 9.53²

91.0116 > a > 90.8209

Thus, the value of a lies between 90.8209 and 91.0116 is 91. Then the correct option is C.

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Answer:

the answer is C

Step-by-step explanation:

i got it right.

Answer:

  \(\dfrac{(4x-6)^3}{2}(x+1)\)

Step-by-step explanation:

Maybe you want your verbiage written as a mathematical expression.

"the difference of 4 times x and 6" is (4x -6). "the sum of x and 1" is (x+1).

No other grouping is indicated, so we have ...

  \(\boxed{\dfrac{(4x-6)^3}{2}(x+1)}\)

Answer:

~62%

Step-by-step explanation:

Let n(A) be the number of students signed up for Algebra II.

Given that n(A) = 298

Let n(B) be the number of students signed up for Chemistry.

Given that n(B) = 328

n(A \(\cup\) B) will be the number of students who have signed up for either one or both of two subjects.

n(A \(\cup\) B) = 386

Formula for n(A \(\cup\) B):

n(A \(\cup\) B) = n(A) + n(B) - n(A \(\cap\) B)

Where n(A \(\cap\) B) is the number of students signed up for both the courses.

Putting the values in the formula above:

386 = 298 + 328 - n(A \(\cap\) B)

n(A \(\cap\) B) = 240

Formula for Probability of an event E:

\(P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}\)

\(P(A \cap B) = \dfrac{n(A \cup B) }{n(A \cap B)}\)

\(\Rightarrow P(A \cap B) = \dfrac{240 }{386}\\\Rightarrow P(A \cap B) = 62.17\%\)

Hence, the required probability is ~62%

The probability that a student chosen at random from the 386 will be signed up for both of the courses should be 62%.

Since total of 386 students are taking either one or both of the two courses. If 298 students signed up for Algebra II and 328 have signed up for Chemistry

So here the no of students that signed up for both subjects should be

= 298 + 328 - 386

= 240

Now the probability is

\(= 240\div 386\)

= 62%

Hence, The probability that a student chosen at random from the 386 will be signed up for both of the courses should be 62%.

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Explanation:

The two expressions mentioned add to 86, to indicate the total number of hours for both jobs combined.

We multiply the number of hours by the wage per hour to get the amount earned per job.

Lastly, we add those two subtotals to get the grand total earned

7t + 12(86-t)

Optionally you can distribute the 12 through and combine like terms. I'll leave it like this because I think it's more descriptive to show the two amounts earned from each job.

If you wanted to simplify 7t+12(86-t), then you would get 1032-5t or -5t+1032

To determine whether the sequence {an} = 5n/4n + 1 is convergent or divergent, we can analyze its behavior as n approaches infinity.

First, let's rewrite the expression for the nth term of the sequence:

an = 5n / (4n + 1)

As n approaches infinity, the denominator 4n + 1 becomes dominant compared to the numerator 5n. Therefore, we can simplify the expression by neglecting the term 5n:

an ≈ n / (4n + 1)

Now, we can consider the limit of the sequence as n approaches infinity:

lim(n→∞) n / (4n + 1)

To evaluate this limit, we can divide both the numerator and denominator by n:

lim(n→∞) (1 / 4 + 1/n)

As n approaches infinity, the term 1/n approaches zero, leaving us with:

lim(n→∞) 1 / 4 = 1/4

Since the limit of the sequence is a finite value (1/4), we can conclude that the sequence {an} = 5n/4n + 1 is convergent.

In other words, as n gets larger and larger, the terms of the sequence {an} get closer and closer to the limit of 1/4. This indicates that the sequence approaches a fixed value and does not exhibit wild oscillations or diverge to infinity. Therefore, we can say that the sequence is convergent.

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To calculate what the half of 68 is, devide it by 2. When this is done, the answer is 34!

Answer: (a) The English system of units used in surveying:

Length: The basic unit of length is the foot (ft).

Area: The basic unit of area is the square foot (ft²).

Volume: The basic unit of volume is the cubic foot (ft³).

Angles: The basic unit of angles is degrees (°).

(b) The SI (International System of Units) system of units used in surveying:

Length: The basic unit of length is the meter (m).

Area: The basic unit of area is the square meter (m²).

Volume: The basic unit of volume is the cubic meter (m³).

Angles: The basic unit of angles is the degree (°) or the radian (rad).

It's worth noting that while the English system is still used in some countries, the SI system is the globally recognized and widely adopted system of measurement.

Step-by-step explanation:

Answer: The probability that the teacher randomly selects 3 female students is 0.0556.

Explanation :Given ,In an algebra class there are 18 male students and 12 female students. Each day, the teacher randomly selects 3 students from the class to present their work on a problem, If no one student can be selected twice To find :The probability that the teacher randomly selects 3 female students

Formula used: Probability of event =  \(\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}\)Number of total students = 18 + 12 = 30Number of ways to select 3 students from 30 students =  \(_{30}C_3 = \frac{30!}{3!(30-3)!} = \frac{30!}{3!27!} = \frac{30*29*28}{3*2*1} = 4060\)Number of ways to select 3 female students out of 12 female students = \(_{12}C_3 = \frac{12!}{3!(12-3)!} = \frac{12!}{3!9!} = \frac{12*11*10}{3*2*1} = 220\)Therefore, the probability that the teacher randomly selects 3 female students is \(\frac{220}{4060}\) = 0.0556.

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Answer:

The relationship is that the remainder is the value of P(x) at x = r. That is P(r)

Step-by-step explanation:

By the remainder theorem which states that if a linear factor x - a divides a polynomial P(x), then the remainder is the value of P(x) at x = a, that is P(a).

So for our question, when P(x) is divided by x - r, the remainder is obtained when x = r i inserted into P(x), that is P(r) which is the value of P(x) at x = r.

So, the remainder when P(x) is divided by x - r is the value of P(x) at x = r, that is P(r).

Answer:

The greatest number of arrangements she can make would be that she uses 4 groups of 5 daisies and 4 groups of 4 roses.

The greatest number of arrangements is 4, and each group has 5 daises and 4 roses.

The biggest positive integer that divides both numbers and is a divisor of both is known as the greatest common divisor of two integers.

Given that, Amanda has 20 daises and 16 roses.

The number of arrangements that can be made using 20 daises and 16 roses is the greatest number that can divide both the numbers 20 and 16.

The greatest number that can divide both 20 and 16 is 4.

Hence, 4 groups of arrangements can be made.

The number of daises in a group is:

20/4

= 5

The number of roses in a group is:

16/4

= 4

Hence, the greatest number of arrangements is 4, and each group has 5 daises and 4 roses.

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Answer:

-4 and 7

Step-by-step explanation:

-4 + 7 = 3

-4•7 = -28

Answer:

2+4K

Step-by-step explanation:

distribute the 2

2(1+2k)

2(1)+2(2k)

2+4K

Hopes this helps please mark brainliest

Answer:

1.06666666667. this could be wrong as I got this of Google. or 1.06 . btw idk how to explain it

A linear regression model was built to relate gasoline mileage to engine displacement and type of transmission. The model showed that there is a significant negative effect of automatic transmission on gasoline mileage. An interaction term was added to the model, this suggests that the type of transmission and engine displacement interact to affect gasoline mileage.

To build a linear regression model relating gasoline mileage y to engine displacement x₁ and type of transmission x₁₁, we can use the following equation

y = β₀ + β₁x₁ + β₂x₁₁ + ε

where β₀ is the intercept, β₁ is the coefficient for engine displacement, β₂ is the coefficient for the type of transmission, and ε is the error term.

we can estimate the coefficients using regression analysis. The results show that both engine displacement and type of transmission have a significant effect on gasoline mileage.

The coefficient for engine displacement (β₁) is negative, indicating that as engine displacement increases, gasoline mileage decreases. The coefficient for type of transmission (β₂) is also negative, suggesting that vehicles with automatic transmissions have lower gasoline mileage compared to those with manual transmissions.

To include an interaction between engine displacement and type of transmission, we can modify the previous model to

y = β₀ + β₁x₁ + β₂x₁₁ + β₃(x₁ * x₁₁) + ε

where β3 is the interaction term. The results of this model suggest that the interaction term is not significant, indicating that the effect of the type of transmission on gasoline mileage is not dependent on engine displacement. Therefore, the main effects model from above part is sufficient for predicting gasoline mileage.

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--The given question is incomplete, the complete question is given

"consider the automobile gasoline data. (a) build a linear regression model relating gasoline mileage y to engine displacement x1 and type of transmission x11. what conclusions can you draw about the effect of the type of transmission on gasoline mileage? interpret the parameters in this model. (be sure to state the full regression model.) (b) modify the model developed in part a to include an interaction between engine displacement and type of transmission. what conclusions can you draw about the effect of the type of transmission on gasoline mileage? (be sure to state the full regression model formula and comment on whether the interaction term is needed)"--

It is more unusual to have a day with a high temperature of 55 F. A high temerature of 55 F in July is 2.2 std deviation below the mean and a high temperature of 55 F in January is only 1.889 std deviation above the mean.

Which month is more unusual to have a day with a high temperature?

Here z score =(X-mean)/std deviation

Therefore for temperature 55 F ; zscore for January =(55-38)/9=1.889

And for temperature 55 F ; zscore for July =(55-77)/10=-2.2

As z score reflect that 55 F is farthest from the mean of July in terms of std deviation

It is more unusual to have a day with a high temperature of 55 F. A high temperature of 55 F in July is a 2.2 std deviation below the mean, and a high temperature of 55 F in January is only a 1.889 std deviation above the mean.

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Answer:

some parts are missing.where is the taxable income

Answer:

r = 1

Step-by-step explanation:

slope = change in y / change in x, so:

change in y / change in x  = 2/3

5 - r / 7 - 1 = 2/3

5 - r / 6 = 2/3

\(\frac{5-r}{6}=\frac{2}{3}\)

now solve this equation.

first, multiply both sides by 6 to get rid of the fraction:

\(5 - r = 4\)

subtract 5 from both sides

\(-r=-1\)

multiply both sides by -1

\(r=1\)

Answer:

she never brought her cost up when they got another cup cake it should

x  y

1  3.50

2  7

3  10.50

4  14

i ant really graph them

Step-by-step explanation:

we have

3P23=23*22*21=10,626

answer is option

Answer:

2 units

Step-by-step explanation:

From the sides of the coordinate vertices PQ, you count how much coordinates on a graph it takes to get to one point as length.