The Probability that no person is next to their partner is 104/105.
Probability of an event E represented by P(E) can be defined as (The number of favorable outcomes )/(Total number of outcomes).
Permutations is defined as arrangement of elements/objects in a particular way.
According to the question ,
8 people can be arranged in 8! ways = 40320ways
First let us find the probability that person is next to their partner.
4 couples can be arranged in 4! ways
and the couple itself can be arranged in 2! ways
Since there are 4 couples ,
Number of arrangement = \(4!(2!)^{4}\)
=24x16
=384 ways
Probability that person is next to their partner = \(\frac{384}{40320} =\frac{1}{105}\)
and the probability that no person is next to their partner is \(1-\frac{1}{105} =\frac{104}{105}\).
Therefore , the probability that no person is next to their partner is \(\frac{104}{105}\).
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what is the value of x? (3x-14)°=180° [4(x-9)]°=180°
Answer:
3x-14=180
3x=194
x= 64 2/3
4(x-9)=180
4x-36=180
4x=216
x=54
Hope This Helps!!!
Step-by-step explanation:
(3x-14)°=180°
3x-14=180
3x=180+14
3x=194
x=64.6
[4(x-9)]°=180°
4x-36=180
4x=180+36
4x=216
x=54
deshawn places a continuous stream of $2,000 per year into a savings account which has a continuously compounding interest rate of 1.3%. what will be the value of this continuous stream after 18 years? round your answer to the nearest integer. do not include a dollar sign or commas in your an
The value of this continuous stream of compound interest after 18 years will be \(\$2526\).
The interest that we earn even on interest is termed as compound interest .
We know that formulae for compound interest when compounded annually will be \(A = P(1 + \dfrac{r}{n})^{nt}\)
Where A is the amount,
P is the principal.
r is the interest rate,
t is the time (in years).
On putting the values in the formulae , we get:
\(A = 2000 ( 1 +\dfrac{1.3}{100})^{18}\)
On simplifying, we get:
A = \(2000\times1.263\)
A = \(2526.24\)
Rounding to the nearest integer, we get:
A =\(\$2526\)
Therefore, the value of the continuous stream after 18 years will be \(\$2526.\)
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QUESTION 11
Which classification best represents a triangle with side lengths 48 in., 56 in., and 83 in.?
O A. acute, because 832> 48² +56²
O B. acute, because 832 < 48² +56²
OC. obtuse, because 832> 48² +56²
O D. obtuse, because 832 < 482 +56²
h
The triangle with side lengths of 48 in., 56 in., and 83 in. is obtuse, because 832> 48² +56²
What is triangle?A triangle is a polygon with three edges and three vertices. It is one of the basic shapes in geometry. A triangle with vertices A, B, and C is denoted \triangle ABC. In Euclidean geometry, any three points, when non-collinear, determine a unique triangle and simultaneously, a unique plane.
here, we have,
The side lengths of the triangles are 48 in., 56 in., and 83 in
The smallest side lengths are: 48 in., 56 in
The sum of the squares of these side lengths is
48^2+ 56^2
For the triangle to be obtuse, then the following must be true
83^2> 48² +56²
Evaluate the exponents
6889> 5440
The above inequality is true.
Hence, the triangle is obtuse, because 83^2> 48² +56²
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During a workout, a person repeatedly lifts a 16-lb barbell through a distance of 1.1 ft .How many "reps" of this lift are required to work off 150 C?
The lifter would need to perform approximately 27 reps of lifting a 16-lb barbell through a distance of 1.1 ft to work off 150 C.
To answer this question, we need to know the amount of work done in each rep of the lift. Work is defined as force multiplied by distance, so the work done in lifting the 16-lb barbell through a distance of 1.1 ft is:
Work = Force x Distance
Work = 16 lb x 1.1 ft
Work = 17.6 ft-lb
Now we can calculate the number of reps required to work off 150 C. One calorie is equivalent to 4.184 joules of energy, so 150 C is equal to:
150 C x 4.184 J/C = 627.6 J
We can convert this to foot-pounds of work by dividing by the conversion factor of 1.3558:
627.6 J / 1.3558 ft-lb/J = 463.3 ft-lb
To work off 463.3 ft-lb of energy, the lifter would need to perform:
463.3 ft-lb / 17.6 ft-lb/rep = 26.3 reps (rounded up to the nearest whole number)
Therefore, the lifter would need to perform approximately 27 reps of lifting a 16-lb barbell through a distance of 1.1 ft to work off 150 C.
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The seventh grade class supplied bags of snacks and beverages for the school dance. They supplied 50 more beverages than bags of snacks. The dance was supplied with a total of 400 items. How many of each were supplied.
a) Define the variable(s)
b) Write a system of equations for the situation.
Answer:
a) let 's' = number of bags of snacks
b) let 's+50' = number of bags of beverages
s + s+50 = 400
Step-by-step explanation:
a) let 's' = number of bags of snacks
b) let 's+50' = number of bags of beverages
s + s+50 = 400
solve:
2s + 50 = 400
2s = 350
snacks = 175
beverages = 175+50 or 225
total = 400
find the euler equation that represents the relationship between current-period consumption and future-period consumption in the optimum.
The Euler equation represents the relationship between current-period consumption and future-period consumption in the optimum. It is derived from intertemporal optimization in economics.
In the context of consumption, the Euler equation can be expressed as:
u'(Ct) = β * u'(Ct+1)
where:
- u'(Ct) represents the marginal utility of consumption in the current period,
- Ct represents current-period consumption,
- β is the discount factor representing the individual's time preference,
- u'(Ct+1) represents the marginal utility of consumption in the future period.
This equation states that the marginal utility of consumption in the current period is equal to the discounted marginal utility of consumption in the future period. It implies that individuals make consumption decisions by considering the trade-off between present and future utility.
Note: The Euler equation assumes a constant discount factor and a utility function that is differentiable and strictly concave.
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An analysis of regression measures only the variance in ____ because it is the value we want to predict.
Answer:
Y is the awnser
Step-by-step explanation:
what is the range of Dan’s car? It’s highway EPA rating is 40mpg and the tank holds 12 gallons
The range at which Dan's car can go is 3.33 miles
What is range of a car?A car's range is the distance it can travel with the current amount of fuel in the tank.
The vehicle calculates the range based on the amount of fuel, how the accelerator and brakes are used, and how quickly the car is travelling.
The range of a car can be measured in the unit of distance.
Therefore the range of a car can be calculated as;
R = distance per gallon/ number of gallon.
Dan's car is 40mpg and has 12 gallons in it's tank.
Therefore it's range = 40/12
= 3.33miles.
therefore the range of Dan's car is 3.33miles
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a poster of area 15360 cm215360 cm2 has blank margins of 10 cm10 cm wide on the top and bottom and 6 cm6 cm wide on the sides. find the dimensions that maximize the printed area. (use decimal notation. give your answers as whole or exact numbers.)
The dimensions that maximize the area are, 96cm and 84cm.
What is area?
The measurement that expresses the size of a region on a plane or curved surface is called area. Surface area refers to the area of an open surface or the boundary of a three-dimensional object, whereas the area of a plane region or plane area refers to the area of a form or planar lamina.
Let the height of poster be h and breadth be b,
bh = 15630cm square........(1)
Height of the printed area=h-10-10 = h - 20
(decrement of 10 from top and bottom)
the breadth of the printed area b-6-6 = b-12
(decrement of 9 from both sides)
for maximum printed area:
A=(h-20)(b-12) should be maximum
\(A = (h - 20)(\frac{15360 }{h}-12)\)
From equation (1)
\(A = 15360-12h-\frac{307200}{h} +240\)
A = 15600 - 12h - (307200/h)
differentiate with respect to h (it should be=0)
\(\frac{dA}{dh}= 0-12 + \frac{307200}{h^2}\)
\(12 = \frac{307200}{h} \\h = 160 cm\)
from equation (1),
\(bh = 15630cm^2\\b = 96cm\)
dimension of printed area,
= h - 20
= 160 - 20
= 140 cm
= b - 12
= 96 - 12
= 84 cm
Therefore, the dimensions that maximize the area are, 96cm and 84cm.
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If h(x) = 2x and g(x) = 3x2 + 1, what is h(g(x))?
Answer:
h(g(x))=h(3x^2+1)=2(3x^2+1)=6x^2+2
If the area of a triangle is 72 square inches and the height is 6 inches, what is the length of the base
Answer: 24 inches.
Step-by-step explanation:
We can use the formula for the area of a triangle to solve for the length of the base:
A = (1/2)bh
where:
A = the area of the triangle (in this case, 72 square inches)
b = the length of the base (what we're trying to find)
h = the height of the triangle (in this case, 6 inches)
Plugging in the values we know, we get:
72 = (1/2)b(6)
72 = 3b
b = 24
Therefore, the length of the base of the triangle is 24 inches.
Chase has been playing a game where he can create towns and help his empire expand. Each town he has allows him to create 1.13 times as
many villagers. The game gave Chase 4 villagers to start with. Help Chase expand his empire by solving for how many villagers he can create
with 17 towns. Then explain to Chase how to create an equation to predict the number of villagers for any number of towns. Show your work
and use complete sentences. (10 points)
Answer:
about 23 villagers
Step-by-step explanation:
17 x 1.13 =19.21 + 4 =23.21
chase would have to use the equation
(n x 1.13)+4
with n being the number of towns
A peach orchard owner wants to maximize the amount of peaches produced by his orchard.
He cannot simply plant as many trees as he can, since planting more trees will decrease the amount of fruit that each tree produces (the yield of each tree).
He has found that the per-tree yield can be described by the equation
Y = 1200 - 15 x.
Here Y is the yield per tree and x is the number of trees planted per acre.
For example, if there were 10 trees planted per acre, each tree would produce 1200 - 15 * 10 = 1050 peaches.
Find the number of trees per acre that should be planted in order to produce the maximum crop and the resulting total yield.
Number of trees per acre : trees per acre
Total yield : peaches per acre
To maximize the amount of peaches produced by the orchard, the peach orchard owner should plant a certain number of trees per acre. The per-tree yield is given by the equation Y = 1200 - 15x, where Y represents the yield per tree and x represents the number of trees planted per acre.
To find the number of trees per acre that maximizes the crop yield, we need to determine the value of x that corresponds to the vertex of the equation. The vertex of a downward-opening parabola, represented by the given equation, occurs at the x-coordinate given by x = -b / (2a).
In this case, the coefficient of x is -15 and the constant term is 0, so b = 0 and a = -15. Substituting these values into the formula, we get x = -0 / (2 * -15) = 0.
While the mathematical calculation suggests that planting zero trees per acre would maximize the yield, this result is not practical. Therefore, the closest feasible value greater than zero would be 1 tree per acre.
For 1 tree per acre, substituting x = 1 into the equation, we find that each tree would produce a yield of Y = 1200 - 15 * 1 = 1185 peaches. Consequently, the resulting total yield would be 1185 peaches per acre.
Number of trees per acre: 1 tree per acre
Total yield: 1185 peaches per acre
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If 7 times the 7th term of an AP is equal to 11 times its 11th term, then its 18th term will be
7
18
11
0
Answer:
please mark me brainlist
Step-by-step explanation:
Consider the hypotheses shown below. Given that x
ˉ
=119,σ=27,n=46,α=0.10, complete parts a through c below. H 0
:μ=128
H A
⩽μ
=128
a. State the decision rule in terms of tho criteal value(s) of the test statistic: Reject the null hypothesis it the calculated value of the tost statistic, is otherwise, do not roject the null hypothesis. (Round to two decimal places as needed. Use a comma to separate answers as needed.) b. Stase the calculated value of the tost statistic. Tho best stasistic is (Round to toro decimal paces as needod.) c. State the conclusion. Beceuse the test statiski the null hypothesis and conclude the pepulation moan equal to 120 .
a. Decision rule: Reject the null hypothesis if the calculated z-value is less than or equal to -1.28. b. Calculated z-value: -1.8892. c. Conclusion: Reject the null hypothesis, indicating evidence that the population mean is less than 128.
To complete parts (a) through (c), we need to perform a hypothesis test for the given hypotheses
H0: μ = 128 (null hypothesis)
HA: μ ≤ 128 (alternative hypothesis)
Given: X= 119 (sample mean)
σ = 27 (population standard deviation)
n = 46 (sample size)
α = 0.10 (significance level)
a. The decision rule is to reject the null hypothesis if the calculated value of the test statistic is less than or equal to the critical value(s) of the test statistic. Since the alternative hypothesis is one-sided (μ ≤ 128), we will use a one-sample z-test and compare the calculated z-value with the critical z-value.
To find the critical z-value, we need to determine the z-value corresponding to the significance level α = 0.10. Looking up the critical value in the standard normal distribution table, we find that the critical z-value is -1.28 (rounded to two decimal places).
b. The calculated value of the test statistic, in this case, is the z-value. We can calculate the z-value using the formula
z = (X - μ) / (σ / √n)
Substituting the given values:
z = (119 - 128) / (27 / √46) ≈ -1.8892 (rounded to two decimal places)
c. The conclusion is based on comparing the calculated value of the test statistic with the critical value. Since the calculated z-value of -1.8892 is less than the critical z-value of -1.28, we have enough evidence to reject the null hypothesis. Therefore, we conclude that the population mean is less than 128.
The conclusion statement in part (c) is inconsistent with the given alternative hypothesis and should be revised accordingly.
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a fire department in a rural county reports that its response time to fires is approximately normally distributed with a mean of 22 minutes and a standard deviation of 6.9 minutes. assume that this claim is true.one percent of response times take at least how many minutes?
If this claim is true then one percent of response times take at least \(38.077\) minutes.
In the given question,
A fire department in a rural county reports that its response time to fires is approximately normally distributed with a mean of 22 minutes and a standard deviation of 6.9 minutes.
We have to assuming that the claim is true and finding that one percent of response times take at least how many minutes.
From the question,
Mean \(\mu=22\) minutes
Standard deviation \(\sigma=6.9\) minutes.
Since the given percentage is \(1\%\) and percentage means division of \(100\) so we can write \(1\%=1/100=0.01\)
So the one percent of response times take at least how many minutes is
\(P(x\geq a)=0.01\)
\(P(x\geq \frac{a-\mu}{\sigma})=0.01\)
As we know the all values. SO putting the values in the formula
\(P(x\geq \frac{a-22}{6.9})=0.01\dots\dots\)Equation 1
From the z table
\(P(z\geq 2.33)=0.01\dots\dots\)Equation 2
Now from Equation 1 and Equation 2
\(\frac{a-22}{6.9}=2.33\)
Multiply by \(6.9\) on both side
\(\frac{a-22}{6.9}\times6.9=2.33\times6.9\)
Simplifying
\(a-22=2.33\times6.9\)
\(a-22=16.077\)
Add \(22\) on both side
\(a-22+22=16.077+22\)
\(a=38.077\)
Hence, if this claim is true then one percent of response times take at least \(38.077\) minutes.
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Make your angle measures correct to the nearest degree and side measures to 1 decimal place
The measure of angle Z is 34°, side length of YZ is 34.1, and the side length of XZ is 41.1. The correct option is the third option ∠Z = 34°, YZ = 34.1, XZ = 41.1
Calculating measures of angles and side measures of a triangleFrom the question, we are to determine the angles measures of and the side measures of the given triangle XYZ
From the given information,
∠Y = 90°
XY = 23
∠X = 56°
First, we will determine the measure of angle Z
m ∠X + m ∠Y + m ∠Z = 180° (Sum of angles in triangle)
56° + 90° + m ∠Z = 180°
m ∠Z = 180° - 56° - 90°
m ∠Z = 34°
Now, since the measure of one of the angles is 90°, ΔXYZ is a right triangle.
Thus,
From SOH CAH TOA, we can write that
tan X = |YZ| / |XY|
∴ tan 56° = |YZ| / 23
|YZ| = 23 × tan 56°
|YZ| = 34.0989
|YZ| ≈ 34.1
Also,
cos X = |XY| / |XZ|
cos 56° = 23 / |XZ|
|XZ| = 23 ÷ cos 56°
|XZ| = 41.1307
|XZ| ≈ 41.1
Hence, ∠Z = 34°, |YZ| = 34.1, and |XZ| = 41.1
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the distance between the school and the library is 3 miles. About how many yards apart are the school and the library
Answer:
5280
Step-by-step explanation:
Take the amount of miles, multiply it by 1760, and you should get the approximate amount of yards.
Evaluate.
4⋅(4+(2^6⋅2^−3) )
A. 48
B. 24
C. 12
D. 2
Answer:
4+(64x1/8)=4+8=12
\(4 \times (4 + ( {2}^{6} \times {2}^{ - 3})) = \)
\(4 \times (4 + ( {2}^{6 - 3})) = \)
\(4 \times (4 + ( {2}^{3} )) = \)
\(4 \times (4 + (8)) = \)
\(4 \times (4 + 8) = \)
\(4 \times (12) = 48\)
_________________________________
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The correct answer is (( A )) .
♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️
Can someone pls help me
9514 1404 393
Answer:
y > 1/2x + 2
Step-by-step explanation:
The points shown on the line are separated by a "rise" of 1 unit vertically, and a "run" of 2 units horizontally. Its slope is rise/run = 1/2.
The line crosses the y-axis at y=2, so the y-intercept is 2.
The boundary line is then ...
y = mx + b . . . . . . . where the slope is m and the y-intercept is b
y = 1/2x + 2 . . . . . . the equation of the boundary line
__
The line is dashed, and the shaded area is above the line, where y-values are greater than the y-value on the line. Then the y-values on the line are NOT included in the solution set. The inequality is ...
y > 1/2x + 2
Natalie just rented an apartment for $900 a month for the first year. She was told that the rent will increase by $50 each year. About how much will her rent be in the 7th year
Answer:
The correct answer is $75,900.
Step-by-step explanation:
Sophia went shopping for a new camera. The listed price of the camera was $26, but the price with tax came to $27.30. Find the percent sales tax.
The percent sales tax of the camera that has a price with tax of $27.30 is 5 %.
What is percent of sales tax ?Percent Sales tax is an amount of money, calculated as a percentage, that is added to the cost of a product or service when purchased by a consumer at a retail location.
To calculate the percent of sales tax, we use the formula below.
Formula:
T(%) = 100(P-P')/P'........... Equation 1Where:
T(%) = Percent of sales taxP = Price of the camera with taxP' = Price of the camera without taxSubstitute these values into equation 1
T(%) = 100(27.30-26)/26T(%) = 100×0.05T(%) = 5 %Hence, the percent sales tax is 5 %.
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Hurry Please! Which of the following shows the extraneous solution to the logarithmic equation?
Image shown!
Answer:
the third circle.
Step-by-step explanation:
Terry buys an orange for 47p. He pays with a £1 coin. How much change does he get?
Answer:
if it works like the dollar 53p
Answer:
53p
Step-by-step explanation:
£1 = 100p
=> Change = 100p - 47p = 53p
2+5t+3a-2t-4m+7-8m-2 pls help
How do you write -1.7 as a fraction?
Answer:
-17/10 as a simplified fraction or -1 7/10 as a normal fraction
Step-by-step explanation:
Hi there! Your answer is going to be 1 7/10.
Step-by-step explanation: You have to remove the negative sign, then convert the positive decimal number to a positive fraction. Apply the negative sign to the fraction answer. Rewrite the decimal number as a fraction with 1 in the denominator. Multiply to remove 1 decimal places. Here, you multiply top and bottom by 10^1 = 10 1.7/1×10/10=17/10.
Hope this helps! Have a good day!
What is 4(1 + 9x) ?
Answer:
36x+4
Step-by-step explanation:
4*1+4*9x
A cattle farmer wants to save for his daughter's college tuition. He will have to pay P50,000 at the end of every year for the next four years that his daughter attends college. He has 8 years until his daughter starts college to save up for her tuition. Using a 7\% interest rate compounded annually, what is the amount the farmer would have to save every year for the 8 years?
Calculating this expression will give us the amount the farmer needs to save annually over the 8-year period.
Given:
Payment required at the end of each year: P50,000
Number of years until the daughter starts college: 8
Interest rate: 7% (compounded annually)
We can calculate the annual savings using the formula for the present value of an ordinary annuity:
P = \dfrac{PMT \times (1 - (1 + r)^{-n}{r}
Where:
P = Present value (amount to be saved annually)
PMT = Payment amount (P50,000)
r = Interest rate per period (7% or 0.07)
n = Number of periods (8)
Let's substitute the given values into the formula:
\[ P = \dfrac{50,000 \times (1 - (1 + 0.07)^{-8}{0.07} \]
Calculating this expression will give us the amount the farmer needs to save annually over the 8-year period.
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(4) Let ge ge c' be D. If there does not then Over D. no g'(x²) = 0 g function (5) If ACB and A is (6) Let f and I be I be twice. If f and 9 functions. If then function f(g(0) (7) Suppose 9 is increasing over D = [s₁ t] differentiable for all XED. a strictly concave function over exist a so that exists for the maximum couvex then B is convex. are continuously differentiable Strictly increasing, is increasing. Then Then g is
In the given set of statements, various conditions and properties related to functions and sets are mentioned.
The statements discuss concepts such as derivatives, concavity, convexity, and increasing functions. The relationships between functions and sets are explored, including the conditions for a function to be strictly concave or convex, the properties of strictly increasing functions, and the impact of differentiability on the existence of maximum values.
(4) The statement mentions the function g and its derivative g'. It states that if g'(x²) = 0, then g is a constant function over D, where D is a set.
(5) The statement introduces three points A, B, and C, and states that if ACB is true, then A is a midpoint between B and C.
(6) This statement introduces two functions f and g. It states that if f is twice differentiable and f and its derivative f' have the same sign, then g is an increasing function.
(7) This statement discusses a function g and its properties. It states that if g is strictly concave over D, a closed interval [s₁, t], and g is differentiable for all x in D, then there exists a point a in D such that g(a) is the maximum value of g over D. Additionally, if g is continuously differentiable and strictly increasing, then the set B is convex.
The statements touch upon concepts related to functions, derivatives, concavity, convexity, and increasing functions. They present various conditions and relationships between functions and sets, exploring properties such as differentiability, monotonicity, and the existence of maximum values.
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A water tank at Camp Newton holds 1200 gallons of water at time t = 0. During the time interval Osts 18 hours, water is pumped into the tank at the rate
W(t) = 95Vt sin^2 (t/6) gallons per hour During the same time interval water is removed from the tank at the rate R(t) = 275 sin^2 (1/3) gallons per hour a. Is the amount of water in the tank increasing at time t = 15? Why or why not?
b. To the nearest whole number, how many gallons of water are in the tank at time t = 18? c. At what time t, for 0 st 18, is the amount of water in the tank at an absolute minimum? Show the work that leads to your conclusion d. For t > 18, no water is pumped into the tank, but water continues to be removed at the rate R(C) until the tank becomes empty. Write, but do not solve, an equation involving an integral expression that can be used to find the value of k.
(a)The amount of water in the tank is increasing.
(b)Evaluate \(\int\limits^{18}_0(W(t) - R(t)) dt\) to get the number of gallons of water in the tank at t = 18.
(c)Solve part (b) to get the absolute minimum from the critical points.
(d)The equation can be set up as \(\int\limits^k_{18}-R(t) dt = 1200\) and solve this equation to find the value of k.
What is the absolute value of a number?
The absolute value of a number is its distance from zero on the number line. It represents the magnitude or size of a real number without considering its sign.
To solve the given problems, we need to integrate the given rates of water flow to determine the amount of water in the tank at various times. Let's go through each part step by step:
a)To determine if the amount of water in the tank is increasing at time t = 15, we need to compare the rate of water being pumped in with the rate of water being removed.
At t = 15, the rate of water being pumped in is given by \(W(t) = 95Vt sin^2(\frac{t}{6})\) gallons per hour. The rate of water being removed is \(R(t) = 275 sin^2(\frac{1}{3})\) gallons per hour.
Evaluate both rates at t = 15 and compare them. If the rate of water being pumped in is greater than the rate of water being removed, then the amount of water in the tank is increasing. Otherwise, it is decreasing.
b) To find the number of gallons of water in the tank at time t = 18, we need to integrate the net rate of water flow from t = 0 to t = 18. The net rate of water flow is given by the difference between the rate of water being pumped in and the rate of water being removed. So the integral to find the total amount of water in the tank at t = 18 is:
\(\int\limits^{18}_0(W(t) - R(t)) dt\)
Evaluate this integral to get the number of gallons of water in the tank at t = 18.
c)To find the time t when the amount of water in the tank is at an absolute minimum, we need to find the minimum of the function that represents the total amount of water in the tank. The total amount of water in the tank is obtained by integrating the net rate of water flow over the interval [0, 18] as mentioned in part b. Find the critical points and determine the absolute minimum from those points.
d. For t > 18, no water is pumped into the tank, but water continues to be removed at the rate R(t) until the tank becomes empty. To find the value of k, we need to set up an equation involving an integral expression that represents the remaining water in the tank after time t = 18. This equation will represent the condition for the tank to become empty.
The equation can be set up as:
\(\int\limits^k_{18}-R(t) dt = 1200\)
Here, k represents the time at which the tank becomes empty, and the integral represents the cumulative removal of water from t = 18 to t = k. Solve this equation to find the value of k.
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