If 6 electrons are available to fill five empty 6d atomic orbitals, how will the electrons be distributed in the five orbitals?



one electron in each orbital


two electrons in 3 orbitals and none in the other 2


two electrons in one orbital and one electron in the other four


six electrons cannot fill five empty 6d atomic orbitals

1) We have that one mole of Platinum is 195,084 g/mol

2) The Avogadro number is 6,022x1023.

The molar mass in grams of "one mole" of each substance is:

Fe: 55.845 g/mol

\(Cl_2\): 70.906 g/mol

\(FeCl_3\): 162.204 g/mol

To calculate the molar mass in grams of "one mole" of each substance, we need to determine the atomic masses of the elements involved in the equation.

The atomic mass of iron (Fe) is 55.845 g/mol.

For chlorine (\(Cl_2\)), we need to consider that the molar mass of \(Cl_2\) is twice the atomic mass of chlorine because the formula shows that two chlorine atoms combine to form one molecule of \(Cl_2\). The atomic mass of chlorine is 35.453 g/mol, so the molar mass of \(Cl_2\) is 2 * 35.453 g/mol = 70.906 g/mol.

The formula for iron(III) chloride (\(FeCl_3\)) indicates that one mole of \(FeCl_3\)contains one mole of iron and three moles of chlorine. Therefore, we can calculate the molar mass of \(FeCl_3\)by summing the atomic masses of iron and chlorine:

Molar mass of \(FeCl_3\)= (1 * atomic mass of Fe) + (3 * atomic mass of Cl)

Substituting the values, we have:

Molar mass of \(FeCl_3\) = (1 * 55.845 g/mol) + (3 * 35.453 g/mol)

= 55.845 g/mol + 106.359 g/mol

= 162.204 g/mol

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Answer:

Bathtub

Explanation:

Even though the water in a filled bathtub may be at the same temperature as water in a glass, the water in the bathtub has more thermal energy because it contains a greater number of water molecules.

Answer:

The mass of sucrose in grams required to make  7% weight volume in 100 mL solution of water is 7g

Explanation:

The percentage weight of a solution is mostly referred to as percentage weight per volume (% w/v). The formula for this is

% w/v = g of solute/100 mL of solvent

sucrose is the solute here while water is the solvent. The mass (in grams) of the solute is the unknown

7% = g of solute/100 mL of water

where 7% equals/the same with 7/100;

7/100 = g of solute/100 mL of water

g of solute = 7 × 100/100

g of solute = 7 g

The mass of sucrose in grams required to make  7% weight volume in 100 mL solution of water is 7g

A helium-filled balloon has a volume of 4.50 L at a barometric pressure of 747.3 mmHg. Given the balloon’s volume is neither increasing nor decreasing, the pressure of the helium inside the balloon is 747.3 mmHg.

A helium-filled balloon has a volume of 4.50 L when the temperature is 22.5 degrees C and the barometric pressure is 747.3 mmHg.

Barometric pressure is the measurement of air pressure in the atmosphere, specifically the measurement of the weight exerted by air molecules at a given point on Earth.

The pressure of the helium gas is the force that the gas exerts on the container boundaries, in this case, the balloon.

We know that the balloon’s volume is neither increasing nor decreasing. This means that the barometric pressure and the pressure of the helium gas are at equilibrium. That is, the pressure of the gas is 747.3 mmHg as well.

A helium-filled balloon has a volume of 4.50 L at a barometric pressure of 747.3 mmHg. Given the balloon’s volume is neither increasing nor decreasing, the pressure of the helium inside the balloon is 747.3 mmHg.

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Answer: Topical Anesthesia.

Explanation:

Topical anesthetics are used to treat ailments including small burns, insect bites, poison ivy, poison oak, poison sumac, and minor cuts and scratches that cause discomfort and irritation.

The nerve terminals in the skin are numbed by topical anesthesia. They don't render patients unconscious like general anesthetics used during surgery do. The majority of topical anesthetics are accessible over-the-counter, but your doctor may have specific recommendations for their usage and dosage given your particular medical condition.

Answer:

The atomic size decreases with an increase in atomic number when we move from left to right.

Explanation: Hope it helps you:))))))

                      Have a great day.

Answer:

A. P₂ / P₁ = 2

B. P₂ / P₁ = 1.1

Explanation:

A. Determination of the ratio P₂/P₁

Volume = constant

Initial temperature (T₁) = 46 K

Final temperature (T₂) = 92 K

Final pressure /Initial pressure (P₂/P₁) =?

P₁/T₁ = P₂/T₂

P₁/46 = P₂/92

Cross multiply

46 × P₂ = P₁ × 92

Divide both side by P₁

46 × P₂ / P₁ = 92

Divide both side by 46

P₂ / P₁ = 92 / 46

P₂ / P₁ = 2

B. Determination of the ratio P₂/P₁

Volume = constant

Initial temperature (T₁) = 35.4 °C = 35.4 + 273 = 308.4 K

Final temperature (T₂) = 69.0 °C = 69 + 273 = 342 K

Final pressure /Initial pressure (P₂/P₁) =?

P₁/T₁ = P₂/T₂

P₁/308.4 = P₂/342

Cross multiply

308.4 × P₂ = P₁ × 342

Divide both side by P₁

308.4 × P₂ / P₁ = 342

Divide both side by 308.4

P₂ / P₁ = 342 / 308.4

P₂ / P₁ = 1.1

Electric charges flow through connection wires to constitutes electric current which supplie the generator.

An electric generator are used to generate electricity, they converts mechanical energy to form electricity.

Electric charges are available in the wire will winds through an external electric circuit to generate electricity.

Electric charges flow through this wires to constitutes electric current which supplies the generator.

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Answer:

D. Electrons: Negative.

Explanation:

Hello, happy to help you today!

In this case, by considering the Bohr's atomic model in which atom is composed by a nuclei containing both protons and neutrons which are positively and neutrally charged respectively and surrounding electrons assembled in orbits or levels of energy which are negatively charged in order to provide a balance to the atom, the correct statement is: D. Electrons: Negative. Also consider the Bohr's model on the attached picture.

My best regards to you!

A. Strong electrolyte The phrase "strong electrolyte" refers to an ionic compound's ability to function as an electrolyte when dissolved in water. This results in a high ion concentration and strong electrical conductivity.

Strong electrolytes can dissolve in aqueous solution, but weak electrolytes can not entirely dissociate into the solvent. The electrolyte's molecules and ions are both present in the solution. Strong electrolytes ionise entirely in water while weak electrolytes only partially do so.

An electrolyte that dissolves almost entirely in water is said to be a strong electrolyte. The powerful electrolyte hydrogen chloride  is an illustration. An electrolyte that doesn't entirely dissolve in water is said to be weak.

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unnilquadium

hope it helps

Answer:

unnilquadium 104

Explanation:

un - 1

nil - 0

quadium - 4

Answer:

59.8 g of PbSO₄.

Explanation:

The balanced equation for the reaction is given below:

Pb + PbO₂ + 2H₂SO₄ —> 2PbSO₄ + 2H₂O

Next, we shall determine the mass of PbO₂ that reacted and the mass of PbSO₄ produced from the balanced equation. This can be obtained as follow:

Molar mass of PbO₂ = 207 + (16×2)

= 207 + 32

= 239 g/mol

Mass of PbO₂ from the balanced equation = 1 × 239 = 239 g

Molar mass of PbSO₄ = 207 + 32 + (16×4)

= 207 + 32 + 64

= 303 g/mol

Mass of PbSO₄ from the balanced equation = 2 × 303 = 606 g

SUMMARY:

From the balanced equation above,

239 g of PbO₂ reacted to produce 606 g of PbSO₄.

Finally, we shall determine the mass of PbSO₄ that will be produced by the reaction of 23.6 g of PbO₂. This can be obtained as follow:

From the balanced equation above,

239 g of PbO₂ reacted to produce 606 g of PbSO₄.

Therefore, 23.6 g of PbO₂ will react to produce = (23.6 × 606) / 239 = 59.8 g of PbSO₄.

Thus, 59.8 g of PbSO₄ were obtained from the reaction.

The volume of gas when the pressure is 45 psi is 2,833.33mL.

The volume of a substance can be calculated using Boyle's law equation as follows:

P₁V₁ = P₂V₂

Where;

According to this question, a tank of carbondioxide has a pressure of 850 psi and a volume of 150 mL. The volume can be calculated as follows:

850 × 150 = 45 × V

V = 127,500 ÷ 45

V = 2,833.33mL

Therefore, 2,833.33mL is the volume of the gas.

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Answer:

pH = 4.45

Explanation:

We need to find the pH of \(3.5\times 10^{-5}\ M\) solution of HCl. We know that, pH of a solution is given by :

\(pH=-log[H]^+\)

Put all the values,

\(pH=-log[3.5\times 10^{-5}]\\\\pH=4.45\)

So, the pH of the solution of HCl is 4.45.

Answer:

C2H4(g) + 3O2(g) ----> 2CO2 + 2H2O(l)

Mg(s) + 2HCL(l) ----> MgCl2(aq) + H2(g)

The value of the equilibrium constant Kc or Kp for ((ab)²)/((a₂)(b²))

The equilibrium constant expression for the given chemical reaction is:

Kc = [(ab)²] / [(a₂)(b²)]

where Kc is the equilibrium constant.

Let's assume that the gases have partial pressures of p(ab), p(a2), and p(b). Then, the equilibrium constant expression can be written as:

Kp = [(p(ab))²] / [(p(a₂))(p(b²))]

Now, we can use the ideal gas law to relate the partial pressures to the number of moles of each gas:

p(ab) = (n(ab) * RT) / V

p(a2) = (n(a2) * RT) / V

p(b) = (n(b) * RT) / V

where n is the number of moles, R is the gas constant, T is the temperature in Kelvin, and V is the volume.

Substituting these expressions into the equilibrium constant expression, we get:

Kp = [(n(ab) * RT / V)²] / [(n(a₂) * RT / V) * (n(b) * RT / V)²]

Simplifying, we get:

Kp = (n(ab)² / n(a₂) * n(b)²) * (RT / V)²

We can rewrite the expression in terms of the number of moles of the reactants and products, as:

Kp = ([ab]² / [a₂] * [b]²) * (RT / P)²

where [ab], [a₂], and [b] are the molar concentrations of the reactants and products, and P is the total pressure of the gases.

Therefore, the value of the equilibrium constant Kc or Kp for ((ab)²)/((a₂)(b²)) can be calculated using the above expression. However, the specific numerical value of Kc or Kp will depend on the temperature and pressure conditions of the reaction.

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Answer:

Of course I breathe air.

Explanation:

I'm not a fish.

Answer:

\(ummmmmmm \: yes \: \)

a. The percentage relative uncertainty is 1.1 %

b. The absoulte uncertainty is ± 1.9

Since 91.3 (+-1.0) mM * (40.3 (+-0.2) mL) / (21.1 (+-0.2) mL) is in the form

R = A × B/C, the relative uncertainty is given by

ΔR/R = √[(ΔA/A)² + (ΔB/B)² + (ΔC/C)²] where

Substituting the values of the variables into the equation, we have

ΔR/R = √[(ΔA/A)² + (ΔB/B)² + (ΔC/C)²]

ΔR/R = √[(0.2 mM/91.3 mM)² + (0.2 mL/40.3 mL)² + (0.2 mL/21.1 mL)²]

ΔR/R = √[(0.002191)² + (0.004963)² + (0.009479)²]

ΔR/R = √[0.00000480 + 0.00002463 + 0.00008985]

ΔR/R = √0.00011928

ΔR/R = ± 0.0109

ΔR/R ≅ ±0.011

So, the percentage relative uncertainty % ΔR/R = ΔR/R × 100 %

= 0.011 × 100 %

= 1.1 %

So, the percentage relative uncertainty is 1.1 %

Since R = A × B/C where

So, R = A × B/C

= 91.3 mM × 40.3 mL/21.1 mL

= 3679.39 mMmL/21.1 mL

= 174.38 mM

≅ 174.4 mM

Now, the absoulte uncertainty in R, ΔR = ΔR/R × R

= ±0.011 × 174.4 mM

= ± 1.92

≅ ± 1.9

So, the absoulte uncertainty is ± 1.9

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There will be 0.4589 mL of ethyl acetate left in the space after evaporation.

The conversion of a liquid substance into a gas is known as evaporation. As a result of the liquid absorbing energy from its surroundings, molecules begin to travel faster and faster until they finally become a vapour and escape into the environment. Usually, the energy is absorbed as heat, but it can also be in the form of light or electricity.

No, the ethyl acetate won't all evaporate. The amount of ethyl acetate that will stay in the space after evaporation can be determined using the ideal gas law. As per the ideal gas law, PV = nRT

P is the overall system pressure, V is the room's volume, n is the amount of ethyl acetate in moles, R is the ideal gas constant, and T is the temperature.

To solve for n, the quantity of moles of ethyl acetate, we can rearrange the equation as follows: n = PV/RT

When the values are plugged in, we get:

n = (94.9 torr)(7.25 m x 2.75 m x 2.75 m)/(8.314 J/K mol)(298 K)

\(n = 4.666 \times 10^{-3} mol\)

The molar mass of ethyl acetate (88.11 g/mol) can then be used to compute the mass of ethyl acetate:

Mass = \(n \times M = (4.666 x 10^{-3} mol)(88.11 g/mol)\) = 0.4125 g

Using the density of ethyl acetate (0.901 g/mL), it is possible to determine the volume of the liquid that is still present:

Volume = mass/density = (0.4125 g)/(0.901 g/mL) = 0.4589 mL

As a result, there will be 0.4589 mL of ethyl acetate left in the space after evaporation.

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Answer:

It's important for scientists to know the properties of matter because all things are made up of matter. Each type of matter has different physical characteristics and scientists need to know and understand these characteristics to make calculations. ... The main phases of matter are solid, liquid, and gas

Explanation:

^^

Answer:

Option C. Keq = [SO2]² [O2] /[SO3]²

Explanation:

The equilibrium constant keq for a reaction is simply the ratio of the concentration of the products raised to their coefficient to the concentration of the reactants raised to their coefficient.

Now, let us determine the equilibrium constant for the reaction given in the question.

This is illustrated below:

2SO3(g) <==> 2SO2(g) + O2(g)

Reactant => SO3

Product => SO2, O2

Keq = concentration of products /concentration of reactants

Keq = [SO2]² [O2] /[SO3]²

40 quarters would need to be lined up in a row to reach a length of 1 meter.

To determine how many quarters would have to be lined up in a row to reach a length of 1 meter, we need to convert the given length of a quarter into meters and then divide the total length by the length of a single quarter.

1 meter is equal to 100 centimeters (since there are 100 centimeters in a meter).

Each quarter has a length of 2.5 centimeters.

To find out how many quarters are needed to reach 1 meter, we divide 100 centimeters by 2.5 centimeters:

100 cm ÷ 2.5 cm = 40

Therefore, you would need 40 quarters lined up in a row to reach a length of 1 meter.

Here's a step-by-step breakdown of the calculation:

Convert 1 meter to centimeters: 1 meter x 100 cm/m = 100 cm.

Determine the number of quarters needed: 100 cm ÷ 2.5 cm = 40 quarters.

Therefore, 40 quarters would need to be lined up in a row to reach a length of 1 meter.

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Answer:

The answer is "\(41.23 \ L\ N_2\)"

Explanation:

\(2 NO_3^{-} + 10 e^{-} + 12 H^{+} \longrightarrow N_2 + 6 H_2O\\\\= \frac{( 215 \ g \ NO_3^{-})}{(62.0049 \frac{\ g NO_3^{-}}{mol})} \times \frac{(1 \ mol \ N_2}{ 2 \ mol \ NO_3^{-})}\\\\\)

\(=3.46746789 \times 0.5\\\\= 1.733 \ mol \ N_2 \\\\\to V = \frac{nRT}{P} \\\\= (1.733 \ mol) \times (0.08205746 \frac{L\ atm}{Kmol}) \times \frac{ (17 + 273) K}{(1.00 atm)}\\\\= 41.23\)

The volume of CO2 is 206.27 L

The ideal gas equation is used to determine the volume, pressure, temperature, or number of moles. It can be mathematically expressed as:

PV = nRT

From the given information:

The equation for the reaction can be expressed as:

\(\mathbf{2NO_3^-_{(aq)} + 5CO_{(g)} + 2H^+_{(aq)} \to N_2{(g)} + 5CO_2_{(g)} + H_2O_{(l)}}\)

The number of moles of CO2 from the reaction is;

\(\mathbf{= \dfrac{215 \ g}{62.0049} \times \dfrac{5 \ mol \ of \ CO_2}{2 \ mol \ of \ NO_3^-} }\)

\(\mathbf{= 8.669 \ moles \ of \ CO_2 }\)

From ideal gas, by making the volume the subject of the, we have:

The volume of CO₂ \(\mathbf{V= \dfrac{nRT}{P}}\)

\(\mathbf{V= \dfrac{8.669 \ moles \times 0.08205 L atm/ kmol \times 290\ K}{1 \ atm }}\)

\(\mathbf{V= 206.27 \ L \ of \ CO_2 \ gas}\)

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Answer:

It is b to use a telescope

Answer:

B

Explanation: