If + 4 is changed to a -4 in the equation y = 3x + 4, what will happen to the corresponding linear graph?
A. The line will shift up 4 units
B. The line will shift down 8 units
C. The line will intersect the origin
D. The line will intersect the x-axis at-4​

180 times

45 cups can wash 180 times

The point estimate that can be used to estimate the true mean population is 11.97 inches.

To find the point estimate that can be used to estimate the true population mean, we need to take the sample mean of the given observations. The formula for the sample mean is:

Mod(X)= (Σx) / n

where Mod(X)  is the sample mean, Σx is the sum of all the observations, and n is the size.

Using the given observations, we can calculate the sample mean as follows:

Mod(X) = (11.3 + 10.7 + 12.4 + 15.2 + 10.1 + 12.1 + 16.2 + 10.5 + 11.4 + 11.0 + 10.7 + 12.0) / 12

Mod(X) = 11.97

Therefore, the point estimate that can be used to estimate the true mean population is 11.97 inches.

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Answer:

1/52

Step-by-step explanation:

The probability that the card is a 4 in a pack of cards is 1 /13.

A probability is a numerical representation of the likelihood or chance that a specific event will take place. Both proportions ranging from 0 to 1 and percentages ranging from 0% to 100% can be used to describe probabilities.

Given, A card is selected from a pack of 52 cards. A favorable outcome is getting 4 since there are four 4 in a pack of cards. Thus,

When a card is selected from a pack of 52 cards the number of possible outcomes is 52 i.e., the sample space contains 52 elements

Therefore there are 52 points in the sample space.

Let E be the event in which the card drawn is an ace.

Since there are 4 aces in a pack of 52 cards n(E)=4

∴P(E)=  \(\frac{Totalnumberofpossibleoutcomes}{Numberofoutcomesfavourableto}\)

E = \(\frac{n(S)}{n(E)}\)

E = 4/52 = 1/13

​Therefore, In a deck of cards, there is a 1 in 13 chance that the card is a 4.

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​

The cylindrical coordinates of (−7, 7, 7) are (√98, -π/4, 7). cylindrical coordinate (−7, 7 3 , 1) is  (14, -π/3, 1).

We must switch from rectangular to cylindrical coordinates in the provided problem. (let r ≥ 0 and 0 ≤ θ ≤ 2π.)

A)(−7, 7, 7)

Given rectangular coordinates(x, y, z) =(−7, 7, 7)

The cylindrical coordinates are (r, θ, z)

As a result, we determine each value of r and θ  separately.

r = √x²+y²

r = √(-7)²+(7)²

r = √49+49

r = √98

θ = tan⁻¹ (y/x)

θ =tan⁻¹  (7/-7)

θ =tan⁻¹  (-1)

θ = -π/4

So cylindrical coordinate = (r, θ, z) = (√98, -π/4, 7)

B) (-7,7√3,1)

Given rectangular coordinates(x, y, z) = (-1,1,1)

The cylindrical coordinates are (r, θ, z)

As a result, we determine each value of r and θ  separately.

r = √x²+y²

r = √(-7)²(7√3)²

r = √49+147

r = √196

r = 14

θ = (y/x)

θ = (7√3/-7)

θ = (-√3)

θ = -π/3

So cylindrical coordinate = (r, θ, z) = (14, -π/3, 1)

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Answer:

39 km/h

Step-by-step explanation:

Velocity is the rate of change of distance in a given direction with time. Mathematically,

Velocity = Displacement/time

Like speed, velocity is measured in Km/h or m/s.

Given that the car travels at 54 km/h for first 20seconds,

since 60 seconds = 1 minute and

60 minutes  = 1 h,

20 seconds

= 20/(60 ×60) h

= 1/180 h

In the same vein,

30 seconds

= 30 / (60 ×60) h

= 1/120 h

10 seconds

= 10/(60 ×60) h

= 1/360 h

Hence  if the car travels 54 km/h for 10 seconds, the distance covered

= 54 × 1/180

= 3/10 Km

If the car travels 36km/h for next 30seconds, the distance covered

= 36 × 1/120

= 3/10 Km

If the car travels 18km/h for next 10 seconds, the distance covered

= 18 × 1/360

= 1/20 km

Total distance = 3/10 Km + 3/10 Km + 1/20 Km

= 13/20 Km

Total time spent = 20 + 30 + 10

= 60 seconds

= 1/60 h

Average velocity = 13/20 km/ 1/60 h

= 39 Km/h

The 7 types of hazards in the home are Psychosocial  Risks,Physical

Dangers , Chemical Dangers, Biological risks, Constrained Areas,

Changing Equipment and Biohazards

Psychosocial  Risks

Physical dangers include a subgroup called psychosocial hazards. For some workers, these risks might be more severe or restrictive than for others. Poor management or a lack of feedback may be the cause of these risks.

Physical Dangers

Environmental and occupational hazards are two different categories of physical risks. These include unguarded machines, heat, cold, vibration, noise, and temperature extremes. Engineering controls can lessen some physical dangers.

Chemical Dangers

Toxic, flammable, explosive, self-reactive, oxidizing, or corrosive compounds are considered chemical dangers. Chemical risks can have negative health impacts and need special handling techniques and equipment.

Biological risks

Many workplaces have biological risks, which can be harmful to people. They include waste debris, food, fungi, food, hair, skin, and saliva.

Constrained Areas

Flammable gases can accumulate in small places. These gases tend to gravitate toward lower elevations, yet they can rise to the surface if a lid is closed or if they are hanging in the air.

Changing Equipment

For workers, the moving machinery hazard provides a distinct set of mechanical risks. Injuries caused by it include crushing, shearing, tangling, air being ejected, striking, abrading, and trapping.

Biohazards

There are many danger thresholds for biohazards. Agents of biohazard level I pose little risk to people. On the other hand, biohazard class II agents may be extremely contagious and may result in serious sickness if consumed or dispersed through the air.

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Answer:

The rational number includes only those decimals, which are finite and repeating.

Step-by-step explanation:

Rational Number is defined as the number which can be written in a ratio of two integers in the form a/b where a,b are integers and b≠ 0, while an irrational number is a number which cannot be expressed in a ratio of two integers (that is it cannot be expressed as fraction in the form a/b).

The rational numbers are numbers whose decimal expansion are finite and repeating, while irrational numbers include those numbers whose decimal expansion is infinite, non-repetitive and shows no pattern e.g. π.

W is a subset of span(w), and span(w) is closed under vector addition, scalar multiplication, and contains the zero vector, we know that w must also have these properties. Therefore, w is a subspace of v.

To show that a subset w of a vector space v is a subspace of v if and only if span(w) = w, we need to prove both directions of the equivalence:

First, we'll assume that w is a subspace of v. In this case, we know that w is closed under vector addition and scalar multiplication, and that it contains the zero vector.

To show that span(w) = w, we need to prove two things:

span(w) is a subset of w: This is true by definition of span(w) - every vector in span(w) can be written as a linear combination of vectors in w, so it must be in w as well.

w is a subset of span(w): This is also true, because every vector in w is itself a linear combination of vectors in w (namely, itself with a coefficient of 1), so it is also in span(w).

Therefore, we have shown that span(w) = w.

Next, we'll assume that span(w) = w. In this case, we know that every vector in w can be written as a linear combination of vectors in w. We need to show that w is closed under vector addition and scalar multiplication, and that it contains the zero vector.

Let u, v be two vectors in w, and let c be a scalar. Then we can write:

\(u = a1w1 + a2w2 + ... + anwn\)

\(v = b1w1 + b2w2 + ... + bnwn\)

where w1, w2, ...,\(wn\) are vectors in w, and a1, a2, ..., an, b1, b2, ...,\(bn\)are scalars.

Then, we have:

\(u + v = (a1+b1)*w1 + (a2+b2)*w2 + ... + (an+bn)*wn\)

which is a linear combination of vectors in w, so u + v is in w.

Also, we have:

\(cu = c(a1w1 + a2w2 + ... + anwn) = (ca1)w1 + (ca2)w2 + ... + (can)*wn\)

which is also a linear combination of vectors in w, so c*u is in w.

Finally, since w is a subset of span(w), and span(w) is closed under vector addition, scalar multiplication, and contains the zero vector, we know that w must also have these properties. Therefore, w is a subspace of v.

Therefore, we have shown both directions of the equivalence, and proved that a subset w of a vector space v is a subspace of v if and only if span(w) = w.

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The length of the building block is approximately 0.6 inches.

Let's assume the length of the building block is represented by the variable 'x'.

According to the given information, we can set up the following equation:

1.5x + 4x + 2.5 = 5.8

To solve for 'x', we'll combine like terms and isolate 'x' on one side of the equation:

5.5x + 2.5 = 5.8

Subtract 2.5 from both sides of the equation:

5.5x = 5.8 - 2.5

5.5x = 3.3

Now, divide both sides of the equation by 5.5 to solve for 'x':

x = 3.3 / 5.5

x ≈ 0.6

Therefore, the length of the building block is approximately 0.6 inches.

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Answer: girl- 19yr old  mom- 38yr old dad- 43 yr old

Step-by-step explanation:

5x+5=100

5x-5=100-5

5/5x=95/5

x=19

2(19)=38

38+5=43

The Taylor polynomials P1, P2, P3, and P4 centered at a0 for f(x) are given as:P1(x) = 1P2(x) = 1 - x²/2!P3(x) = 1 - x²/2! + x⁴/4!P4(x) = 1 - x²/2! + x⁴/4! - x⁶/6!

We will apply the Taylor's theorem formula, which is supplied as follows, to determine the Taylor polynomials P1, P2, P3, and P4 centred at a0 for f(x) in the given question:f'(a)(x-a)/1 = f(x) = f(a) + f'(a)! + f''(a)(x-a)²/2! + ... + fⁿ(a)(x-a)ⁿ/n!We have f(0) = 1f'(0) = 0f''(0) = -1f'''(0) = 0f4(0) = 1 for f(x) = cos(x) at x = 0.We can get the following polynomial expressions by using these values in the Taylor's theorem formula:P1(x) = 1P2(x) = 1 - x²/2!P3(x) = 1 - x²/2! + x⁴/4!P4(x) = 1 - x²/2! + x⁴/4! - x⁶/6!Consequently, the Taylor polynomials P1, P2, P3, and P4 for f(x) are provided as follows:P1(x) = 1P2(x) = 1 - x²/2!P3(x) = 1 - x²/2! + x⁴/4!P4(x) = 1 - x²/2! + x⁴/4! - x⁶/6!

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The sine, cosine, cosecant, and secant functions have a period 2π;

the tangent and cotangent functions have period π.

The pause between any function's repetitions is known as the function's period. The duration of one complete cycle is the period of a trigonometric function. Trigonometric functions include three basic types: sin, cos, and tan, which have periods of -2π, 2π, and π respectively.

If a function repeats itself repeatedly at a predetermined frequency, it is said to be periodic. The formula for t is f(x) = f(x + p), where p is a real number that denotes the period of the function. The period is the interval between two occurrences of the wave.

The complete question is-

The sine, cosine, cosecant, and secant functions have period _______; the tangent and cotangent functions have period _______.

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Explanation

the length of an arc is given by:

where r is the radius and theta is the angle

then

Step 1

Let

radius=13

angle=68

replace

I hope this helps you

The solution of the equation 1/3 (1/2 x - 9) = 1/2 (x + 18) will be negative 36.

An answer to a formula is any variable value that fulfills the equal outcomes, that is, it tends to make the Left Hand Side (LHS) and Right Hand Side (RHS) of the formula equal. To solve an equation, you must locate the feasible solution) to that formula.

The equation is given below.

1/3 (1/2 x - 9) = 1/2 (x + 18)

Simplify the equation, then we have

1/3 (1/2 x - 9) = 1/2 (x + 18)

(1/6)x - 3 = (1/2)x + 9

(1/2)x - (1/6)x = - 3 - 9

(1/3)x = - 12

x = - 36

The solution of the equation 1/3 (1/2 x - 9) = 1/2 (x + 18) will be negative 36.

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The correct equation is given below.

find the value of 'x'

1/3(1/2x-9)=1/2(x+18)

When x = 0, y = 2(0) - 2 = -2. So one point is (0, -2). When x = 1, y = 2(1) - 2 = 0. So another point is (1, 0).

To graph the equations 2x - y - 2 = 0, 4x - 3y - 24 = 0, and y + 4 = 0, we need to plot the points that satisfy each equation and connect them to form the lines.

1. Equation: 2x - y - 2 = 0

To plot this equation, we can rewrite it in slope-intercept form:

y = 2x - 2

Now we can choose some x-values and calculate the corresponding y-values to plot the points:

When x = 0, y = 2(0) - 2 = -2. So one point is (0, -2).

When x = 1, y = 2(1) - 2 = 0. So another point is (1, 0).

Plot these points on the graph and draw a line passing through them:

```

    |

    |

0   |     ● (1, 0)

    |

    |     ● (0, -2)

-2 __|_____________

    -2    0    2

```

2. Equation: 4x - 3y - 24 = 0

Again, let's rewrite this equation in slope-intercept form:

y = (4/3)x - 8

Using the same process, we can find points to plot:

When x = 0, y = (4/3)(0) - 8 = -8. So one point is (0, -8).

When x = 3, y = (4/3)(3) - 8 = 0. So another point is (3, 0).

Plot these points and draw the line:

```

    |

    |

0   |             ● (3, 0)

    |

    |                   ● (0, -8)

-8 __|______________________

    -2     0    2    4

```

3. Equation: y + 4 = 0

This equation represents a horizontal line parallel to the x-axis, passing through the point (0, -4).

Plot this point and draw the line:

```

    |

    |

-4   |       ● (0, -4)

    |

    |

    |______________________

    -2     0    2    4

``

So, the graph of the three equations would look like this:

```

    |

    |

0   |             ● (3, 0)                      ● (1, 0)

    |                   |                               |

    |                   |                               |

-4 __|___________________|_______________________________

    -2     0    2    4

```

Note that the lines representing the equations 2x - y - 2 = 0 and 4x - 3y - 24 = 0 intersect at the point (1, 0), which is the solution to the system of equations formed by these two lines. The line y + 4 = 0 represents a horizontal line parallel to the x-axis, located 4 units below the x-axis.

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Answer:

x=45

Step-by-step explanation:

A triangle adds up to 180º. The red lines in the bottom, left indicate that the triangle is a right triangle, meaning that one angle (the red angle) is 90º. When you subtract 180 by 90, you get 90. Then you divide that by 2, giving you 45.

The required experimental probability that the next batter will get a hit is 2/11.

A number that indicates how likely an event is to occur is called its probability. It is communicated as a number in the reach from 0 and 1, or, utilizing rate documentation, in the reach from 0% to 100 percent. The higher the probability, the more likely the event is to occur.

The experimental probability of an event happening is defined as the number of times the event occurs divided by the total number of trials or events.

In this case, we are given that 4 out of 22 batters have gotten a hit so far. Therefore, the experimental probability that the next batter will get a hit is:

P(hit) = Number of hits / Total number of batters

P(hit) = 4/22

Simplifying:

P(hit) = 2/11

Therefore, the experimental probability that the next batter will get a hit is 2/11.

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Answer:

C - 1/81

Step-by-step explanation

There are 6 sides on a standard die (1, 2, 3, 4, 5, 6). Out of these numbers, only 3 and 6 are divisible by 3. Therefore, 2/6 numbers would be divisible by 3. As the die is rolled 4 times, we multiply 2/6 4 times - (2/6)(2/6)(2/6)(2/6) to get 1/81. The probability that the die shows a number divisible by three all four times is 1/81. Hope that helps!

First, we will find 50% of 13,370

50/100 x13 370

= 6 685 lamps

Since the lam ship this year is 50% more than the lamp shipped last year, this implies that:

The lamp ship this year = 13 370 + 6 685 = 20 055 lamps

Answer:

69

Step-by-step explanation:

Answer:

69

Step-by-step explanation:

because 100 minus 31 equals 69

The quarterly operating profit margin of TMG Ltd over the past six years is provided in Table 4.1, indicating the financial performance of the business during that period.

In order to assess the impact of the intervention strategy introduced by the current CEO three years ago, the board of directors (BOD) of TMG Ltd has contracted a researcher to analyze the data and determine if there have been significant improvements in the business outcomes. The quarterly operating profit margin serves as the unit of analysis for this evaluation.

Table 4.1 allows the researcher to examine the trend and fluctuations in the quarterly operating profit margin over the six-year period. By analyzing the data, the researcher can identify any noticeable changes in the financial performance of TMG Ltd, particularly after the implementation of the intervention strategy. The BOD is interested in understanding whether the strategy has resulted in improved profitability and overall financial health of the company.

The researcher will likely perform statistical analysis, such as calculating averages, trends, and identifying any significant variations, to draw conclusions about the effectiveness of the intervention strategy. By comparing the quarterly operating profit margin before and after the strategy's implementation, the researcher can assess whether the new CEO's efforts have had a positive impact on the company's financial performance.

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The probability that the next customer will pay with something other than cash as a percent to the nearest whole number is 24%.

Probability is simply the possibility of getting an event. Or in other words, we are predicting the chance of getting an event.

Given that,

Number of customers who paid cash = 102

Number of customers who used a debit card = 22

Number of customers who used a credit card = 10

Total number of customers = 102 + 22 + 10 = 134

Total customers who don't use cash to pay = 22 + 10 = 32

Probability that the next customer doesn't pay cash = 32 / 134

                                                                                       = 0.2388

                                                                                       = 23.88%

                                                                                       ≈ 24%

Hence 24% of probability is that the next customer will pay with something other than cash.

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If r2 equals .36 it means that 36% of the variability in one variable is accounted for by variability in another variable.The coefficient of determination, commonly referred to as r-squared or R2, is a statistical measure that evaluates how well a linear regression model fits the data.

It measures the proportion of variability in a dependent variable that can be accounted for by the independent variable(s). In simpler terms, the R-squared value indicates how well the regression line (or the line of best fit) fits the data points being studied, and whether the variation in the dependent variable is related to the variation in the independent variable.

If r2 equals .36, it means that 36% of the variability in one variable is accounted for by the variability in another variable.

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Step-by-step explanation:

i hope its clear enough and that it helps

Here's a pic. hope it helps

The answer is D. None of the above, the long-term DPMO is 25137, which is equivalent to a Z-value of 3.46. The short-term Z-value is usually 1.5 to 2 times the long-term Z-value,

so it would be between 5.19 and 6.92. However, these values are not listed as answer choices. The Z-value is a measure of how many standard deviations a particular point is away from the mean. In the case of DPMO, the mean is 6686. So, a Z-value of 3.46 means that the long-term defect rate is 3.46 standard deviations away from the mean.

The short-term Z-value is usually 1.5 to 2 times the long-term Z-value. This is because the short-term process is more variable than the long-term process. So, the short-term Z-value would be between 5.19 and 6.92.

However, none of these values are listed as answer choices. Therefore, the correct answer is D. None of the above.

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The value of a painting has increased steadily over time.

This means that as time increases, the value of the painting is also increasing.

A simple linear graph can be used to represent this situation.

As you can see from the graph, as time increases, the value also increases.

Notice that the graph does not start from the zero value that is because we assume that it must have some starting value.

Answer:

10%  off

Step-by-step explanation:

\(5x^2-14x+8\\\\=5x^2-10x-4x +8\\\\=5x(x-2) -4(x-2)\\\\=(x-2)(5x-4)\)

Answer:

The problem seems to be incomplete as the probability density function is not given. Please provide the probability density function to solve the problem.

Step-by-step explanation:

Without the probability density function, we cannot determine the probability that the concentration of the reactant is greater than 0.5. We need to know the probability distribution of the random variable to calculate its probabilities.

Assuming the concentration of the reactant follows a continuous probability distribution, we can use the cumulative distribution function (CDF) to calculate the probability that the concentration is greater than 0.5.

The CDF gives the probability that the random variable is less than or equal to a specific value.

Let F(x) be the CDF of the concentration of the reactant. Then, the probability that the concentration is greater than 0.5 can be calculated as:

P(concentration > 0.5) = 1 - P(concentration ≤ 0.5)

= 1 - F(0.5)

To find the value of F(0.5), we need to know the probability density function (PDF) of the random variable. If the PDF is not given, we cannot find the value of F(0.5) and therefore, we cannot calculate the probability that the concentration is greater than 0.5.

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