I want to know if I’m doing this correctly, and if not, then what would be the best process to do solve it?

Answer:

A) 1.76U×10⁻³N

B) 2.716×10⁻³N

C) 264.5⁰

Explanation:

See detailed workings for (a), (b), (c) attached.

Answer:

B) Mass is a measurement of force

Explanation:

Mass is not a measurement of force, mass is a measurement of the amount of matter in an object.

The buoyant force on the cannon stays the same as long as it is fully under water because the buoyant force is determined by the volume of fluid that the cannon displaces and not by the weight or mass of the cannon itself.

Archimedes' Principle states that the buoyant force on an object in a fluid is equal to the weight of the fluid that the object displaces. This means that as long as the cannon remains fully submerged in the water and does not change its volume, the amount of water it displaces and thus the buoyant force on the cannon will also remain the same.

In other words, the buoyant force is dependent on the fluid's density and the volume of the object, not its weight. So, as long as the volume of the cannon and the density of the fluid surrounding it remain constant, the buoyant force will also stay constant.

The buoyant force on the cannon will stay the same as long as it is fully under water.

The buoyant force on an object is equal to the weight of the fluid displaced by the object. The buoyant force is always directed upwards, and it opposes the force of gravity. As long as the cannon is fully under water, the amount of water displaced by the cannon will stay the same. This means that the buoyant force on the cannon will also stay the same.

The buoyant force on an object depends on the density of the fluid, the volume of the object, and the acceleration due to gravity. The density of water is constant, so the buoyant force on the cannon will only change if the volume of the cannon changes or if the acceleration due to gravity changes.

Neither of these factors change. The volume of the cannon does not change as it is being recovered from the shipwreck. The acceleration due to gravity also does not change, as it is the same on Earth's surface as it is underwater.

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Answer:

The value of g is  \(g =76.2 m/s^2\)

Explanation:

From the question we are told that

     The mass of the weight is \(m = 1.30 kg\)

      The spring  constant  \(k = 1.73 g/m = 1.73 *10^{-3} \ kg/m\)

       The second harmonic frequency is \(f = 100 \ Hz\)

       The number of oscillation is \(N = 200\)

        The time taken is  \(t = 315 \ s\)

Generally the frequency is  mathematically represented as

           \(f = \frac{v}{\lambda}\)

At second harmonic frequency the length of the string vibrating is equal to  the wavelength of the wave generated

         \(l = \lambda\)

Noe from the question the vibrating string is just half of the length of the main string so

Let assume the length of the main string is  \(L\)

So      \(l = \frac{L}{2}\)

The velocity of the vibrating string is mathematically represented as

             \(v = \sqrt{\frac{T}{\mu} }\)

Where T is the tension on the string which can be mathematically represented as

             \(T = mg\)

So  

           \(v = \sqrt{\frac{mg}{k} }\)

Then

          \(f = \frac{v}{\frac{L}{2} }\)

=>       \(v = \frac{fL }{2}\)

=>      \(\sqrt{\frac{mg}{k} } = \frac{fL}{2}\)

=>        \(g = \frac{f^2 L^2 \mu}{4m}\)

substituting values

             \(g = \frac{(100) * (1.73 *10^{-3} )}{(4 * 1.30)} L^2\)

              \(g = 3.326 m^{-1} s^{-2} L^2\)

Generally the period of oscillation is mathematically represented as

       \(T_p = 2 \pi \sqrt{\frac{L}{g} }\)

=>   \(L = \frac{T^2 g}{4 \pi ^2}\)

   The period can be mathematically evaluated as

                \(T_p = \frac{t}{N}\)

 substituting values

             \(T_p = \frac{315}{200}\)

             \(T_p = 1.575 \ s\)

Therefore

          \(L = \frac{1.575^2 * g }{4 \pi ^2}\)

           \(L = 0.0628 ^2 g\)

so

      \(g = 3.326 m^{-1} s^{-2} L^2\)

substituting for L

        \(g = 3.326 ((0.0628) g)^2\)

=>    \(g = \frac{1}{(3.326)* (0.0628)^2}\)

       \(g =76.2 m/s^2\)

Answer:

4500 N

Explanation:

Bc f is equal to mass times acceleration and the acceleration is 60

If a 75 kg student drives a 650 kg car, then the car starts from rest and accelerates to 60 m/s in 8 seconds, then the applied force on the car would be 5437.5 Newtons.

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

The mathematical expression for Newton's second law is as follows

F = m × a

As given in problem an If a 75 kg student drives a 650 kg car, the car starts from rest and accelerates to 60 m/s in 8 seconds.

The acceleration of the car = 60 / 8

                                             = 7.5 m / s²

The force applied on the car = 725 × 7.5

                                                = 5437.5 Newtons

Thus,  the applied force on the car would be 5437.5 Newtons.

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The displacement of the dog is 15.3 meters at a bearing of 339.4 degrees (or about 20.6 degrees west of due north).

Displacement is a vector quantity that measures the change in position of an object from its initial position to its final position. It is the straight-line distance and direction between these two points.

To calculate the displacement, we need to find the straight-line distance and direction between the starting point A and the final point where the dog ends up.

The dog first moves 15m toward the east. This means that its position changes in the x-direction by 15m. We can represent this as a vector:

d1 = 15i

where i is the unit vector in the x-direction.

Next, the dog turns 90 degrees south and moves 3m. This means that its position changes in the y-direction by -3m (since south is in the negative y-direction). We can represent this as another vector:

d2 = -3j

where j is the unit vector in the y-direction.

To find the displacement, we can add these two vectors:

d = d1 + d2

= 15i - 3j

The magnitude of this vector is:

|d| = sqrt(15^2 + (-3)^2)

= sqrt(234)

≈ 15.3

So the dog's displacement is approximately 15.3 meters. To find the direction, we can calculate the angle that this vector makes with the positive x-axis:

theta = arctan(-3/15)

≈ -0.197

Since the angle is negative, we know that the vector points in the fourth quadrant. To express the direction as a compass bearing, we can add 360 degrees to the angle and convert to degrees:

theta_degrees = (-0.197 + 2*pi) * 180/pi

≈ 339.4

Hence, the dog's displacement is approximately 15.3 meters at a bearing of 339.4 degrees (or about 20.6 degrees west of due north).

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The process through which UV light bleaches pigments, textiles, or other things is known as photo deterioration. UV radiation is used to disinfect surfaces, destroy microorganisms, and remove stains from clothing.

It is a chemical procedure that causes the fabric's molecules to disintegrate and release the natural oils by the application of ultraviolet light. By dissolving the fabric's molecules, releasing natural oils, and eradicating bacteria, it kills germs when applied to clothing. A colorant's lightfastness—a radiation that specifies how resistant it is to fading when exposed to light—can be described as a dye or pigment. Dyes and pigments are employed, for instance, in the production of paints and printing inks as well as the dying of fabrics, polymers, and other materials. Colorant molecules go through several chemical steps throughout the fading.

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Photo degradation is the process by which UV light bleaches textiles, pigments, and other materials. Surfaces are cleaned with UV radiation, which also eliminates bacteria and gets stains out of clothes.

By using UV light, a chemical process forces the fabric's molecules to break down and release its natural oils. When applied to garments, it kills germs by dissolving the fabric's molecules, releasing natural oils, and eliminating bacteria. An indicator of a colorant's lightfastness, also known as a dye or pigment, is how resistant it is to fading when exposed to light. For example, dyes and pigments are used to colour fabrics, polymers, and other materials in addition to producing paints and printing inks.

The majority of UVC rays are absorbed by the atmosphere's nitrogen, oxygen, and ozone, and the remainder are scattered, preventing them from reaching the earth's surface.

Skin lesions are brought on by UVC. During the fading process, colorant molecules go through a number of chemical processes.

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The calculated value of speed of sound be 400 m/s.

An echo is a sound produced when sound waves are reflected off of a surface and returned to the listener. It is the sound that has been reflected, and it reaches the listener after the original sound has passed.

Given parameters:

The student's  distance to the wall is = 300 m.

The time delay between clap an echo is 1.5 seconds.

In this time, sound waves goes to the wall and hits back to the student's ear.

So, total distance covered by the sound wave: d= 2 × 300 m = 600 m.

Hence,  the speed of sound be - 600 m/1.5s = 400 m/s.

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Hi there!

We can use the following kinematic equation:

\(v_f^2 = v_i^2 + 2ad\)

vf = final velocity (? m/s)
vi = intial velocity (0 m/s)

a = acceleration (5 m/s²)

d = displacement (8 m)

Plug in the givens and solve.

\(v_f^2 = 0 + 2(5)(8)\\\\v_f = \sqrt{80} = \boxed{8.944 \frac{m}{s}}\)

In Tesla squared meters, the magnitude of the change in the magnetic flux. (ΔΦ= 2.3468T⋅m²).

The magnetic flux through the loop is given by;

Φ = B A cosθ

where B is magnetic field strength, A is area of the loop, and θ is angle between the normal to the loop and the direction of the magnetic field. Since the magnetic field is perpendicular to the plane of the loop, θ = 0 and cosθ = 1.

The magnitude of the change in the magnetic flux is given by;

ΔΦ = Φ₂ - Φ₁

where Φ₁ is the initial magnetic flux through the loop when the magnetic field strength is B₁ = 0.65 T, and Φ₂ is the final magnetic flux through the loop when the magnetic field strength is B₂ = 4.5 T.

The initial magnetic flux through the loop is;

Φ₁ = B₁ A cosθ = 0.65 × πr² × 1 = 0.1126 T⋅m²

The final magnetic flux through the loop is;

Φ₂ = B₂ A cosθ = 4.5 × πr² × 1 = 2.4594 T⋅m²

Therefore, the magnitude of the change in the magnetic flux is;

ΔΦ = Φ₂ - Φ₁ = 2.4594 - 0.1126 = 2.3468 T⋅m²

Therefore, ΔΦ = 2.3468 T⋅m².

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Option d (T₁ > T₂ > T₃) correctly describes the tension in the three rope system.    

Let's evaluate each tension.

Case T₃.

\( T_{3} - W_{3} = 0 \)

For the system to be in equilibrium, the algebraic sum of the tension force (T) and the weight (W) must be equal to zero. The minus sign of W is because it is in the opposite direction of T.          

\( T_{3} = W_{3} \)          

Since W₃ = mg, where m is for mass and g is for the acceleration due to gravity, we have:                

\( T_{3} = W_{3} = mg \)  (1)                                                                                                     Case T₂.

\( T_{2} - (T_{3} + W_{2}) = 0 \)    

\( T_{2} = T_{3} + W_{2} \)   (2)

By entering W₂ = 2mg and equation (1) into eq (2) we have:

\( T_{2} = T_{3} + W_{2} = mg + 2mg = 3mg \)

Case T₁.

\( T_{1} - (T_{2} + W_{1}) = 0 \)  

\( T_{1} = T_{2} + W_{1} \)    (3)

Knowing that W₁ = 3mg and T₂ = 3mg, eq (3) is:

\( T_{1} = 3mg + 3mg = 6mg \)        

Therefore, the correct option is d: T₁ > T₂ > T₃.

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I hope it helps you!

Correct answer: D. \(T_{1} > T_{2} > T_{3}\)

First, we must construct the Equations of Equilibrium for each mass based on Newton's Laws of Motion, then we solve the resulting system for every Tension force:

Mass m:

\(\Sigma F = T_{3}-m\cdot g = 0\) (1)

Mass 2m:

\(\Sigma F = T_{2}-2\cdot m \cdot g -T_{3} = 0\) (2)

Mass 3m:

\(\Sigma F = T_{1}-3\cdot m\cdot g - T_{2} = 0\) (3)

The solution of this system is: \(T_{3} = m\cdot g\), \(T_{2} = 3\cdot m\cdot g\) and \(T_{1} = 6\cdot m\cdot g\), which means that \(T_{1} > T_{2} > T_{3}\). (Correct answer: D.)

Heat will flow from the metal to the water until both are at a temperature somewhere between 20°C and 300°C because of thermal equilibrium.

When there is no temperature differential between the system and its surroundings, a system is said to be in thermal equilibrium.

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Answer:

F=w=ma                                                                                                                                                       OR by using equations of motions                                                                               vf=vi-at                    : a=vf-vi/t                                                              eq 1                         s=vit+1/2at squre                                                                                 eq 2                     2as=vf squre - vi squre                                                                        eq 3                                                                                                                                                                                  

Explanation:

where m is the mass of falling body , f is the weight is the force acting down ward , vf is the final velocity, vi is the inetial velocity , t is the time and s is the distance covered by a body.

Explanation:

the rate at which something occurs or is repeated over a particular period of time or in a given sample

Answer:

Frequency is the number of occurrences of a repeating event per unit of time. It is also referred to as temporal frequency, which emphasizes the contrast to spatial frequency and angular frequency. Frequency is measured in units of hertz (Hz) which is equal to one occurrence of a repeating event per second.

Hope this helps :D

The energy of a body which is associated with the height of body above the ground is known as gravitational potential energy. Therefore, option (3) is correct.

Mathematical expression of the gravitational potential energy is,

Here, U is the potential energy, m is the mass, g is the acceleration due to gravity and h is the height of body above the ground.

Explanation:

s=d/t

d=s×t

d=8×16.4

d=131.2

distance is 131.2m.

The larger the value of heat of fusion or heat of vaporization to intermolecular forces.

The stronger the intermolecular forces, the higher the heat of fusion., and the higher the heat of vaporization.  The heat of fusion is used for the evaluation of the freezing point .when a solvent dissolves a solute.

The heat of fusion has intent chemists and physicists because it proposes that a substance can absorb or release energy without swap temperatures. Indeed, when one mole of ice at 0°C absorbs 6020 Joules of heat, liquid water will also have a temperature of 0°C.

So we can conclude that The heat of fusion of any material is the critical reckoning of the heat.

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The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:

τ = r * F * sin(θ)

where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.

Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:

τ_M = r_M * F_M * sin(θ)

where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.

Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:

τ_M = τ_stick

r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)

Substituting the given values:

30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)

Solving for F_M:

F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)

F_M = 0.0264 kg * 9.8 m/s^2

F_M = 0.25872 N

Finally, we can convert the force into mass using the formula:

F = m * g

0.25872 N = M * 9.8 m/s^2

M = 0.0264 kg

Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

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The correct statement is Molecular collisions transfer thermal energy between the system and its surroundings. Thus, option D is correct.

The energy moves between a system of reacting substances and the surroundings by the collision of molecules. The transfer of heat or thermal energy between the system and its surroundings by the process of Conduction. Conduction is the process of transmitting the heat to the neighboring atoms or collisions by the process of collisions.

The conduction takes place more steadily in solids and liquids where the molecules are closer together. When the molecules are collided with the nearby molecules, the potential energy is converted into kinetic energy and hence the heat energy is transferred between the system and its surroundings.

Hence, Molecular collisions transfer thermal energy between the system and its surroundings. Thus, the correct option is D.

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Answer:

25 meter per second square

Answer:

\(F = ma = 0.1 \times a \\ a = \frac{5}{0.1} \\ a = 50 \: m. {s}^{ - 2} \)

The magnitude of the force and the impulse applied to the car are  85714 N and  30000 N-s respectively.

The definition of force in physics is: The push or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

The magnitude of the force applied to the car = change in momentum/time interval

= (1200 kg × 25 m/s - 1200 kg×0)/0.35 second

= 85714 N.

The impulse applied to the car = change in momentum

= (1200 kg × 25 m/s - 1200 kg×0)

= 30000 N-s.

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Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.

Frequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).

Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.

Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.

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Answer:

Its D

Explanation:

edgen 2 0 2 1

Answer:

D.) To get the reader to understand the two types of signals

Explanation:

Edge, 2022.

(See the attachment below.)

Good luck on the quiz!

<3

Over the first 16.4 m, the person performs

W = (60.0 N) (16.4 m) = 984 J

of work.

Over the remaining 6.88 m, they perform a varying amount of work according to

F(x) ≈ 60.0 N + (-8.72 N/m) x

where x is in meters. (-8.72 is the slope of the line segment connecting the points (0, 60.0) and (6.88, 0).) The work done over this interval can be obtained by integrating F(x) over the interval [0, 6.88 m] :

W = ∫₀⁶˙⁸⁸ F(x) dx ≈ 206.4 J

(Alternatively, you can plot F(x) and see that it's a triangle with base 6.88 m and height 60.0 N, so the work done is the same, 1/2 (6.88 m) (60.0 N) = 206.4 J.)

So the total work performed by the person on the box is

984 J + 206.4 J = 1190.4 J ≈ 1190 J

Answer:

c

Explanation:

Answer:

the answer to your question is c

Explanation:

Answer:

D

Explanation:

If the distance is reduced by factor of 2, lets say the distance was 10cm

reducing by a factor of 2 will leave the distance at 5cm

so the electric force increases by a factor of 2