Answer:
Step-by-step explanation:
2/14 * 1/23 = 1/91
i don't understand how to do this.. can someone help, please
The possible values for angles 1, 2, and 3 given that lines a and b are parallel lines include the following:
m∠1 = 60°.m∠2 = 120°.m∠3 = 60°.What are parallel lines?In Mathematics and Geometry, parallel lines are two (2) lines that are always the same (equal) distance apart and never meet or intersect.
Note: Assuming angle 1 is equal to 60 degrees.
In Mathematics and Geometry, the vertical angles theorem states that two (2) opposite vertical angles that are formed whenever two (2) lines intersect each other are always congruent, which simply means being equal to each other:
m∠1 ≅ m∠3 = 60°.
Based on the linear pair postulate, the measure of angle 2 can be determined as follows;
m∠1 + m∠2 = 180°
60° + m∠2 = 180°
m∠2 = 180° - 60°
m∠2 = 120°
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A shipping box is 36 inches by 24 inches by 18 inches
how many cubic feet can it hold
Answer:
To find the volume of the shipping box in cubic feet, we need to convert the dimensions from inches to feet and then calculate the volume.
Given:
Length = 36 inches
Width = 24 inches
Height = 18 inches
Converting the dimensions to feet:
Length = 36 inches / 12 inches/foot = 3 feet
Width = 24 inches / 12 inches/foot = 2 feet
Height = 18 inches / 12 inches/foot = 1.5 feet
Now, we can calculate the volume of the box by multiplying the length, width, and height:
Volume = Length * Width * Height
Volume = 3 feet * 2 feet * 1.5 feet
Volume = 9 cubic feet
Therefore, the shipping box can hold 9 cubic feet.
Step-by-step explanation:
First convert the units because it's asking for the cubic feet but they give us the measurements in inches.
To convert inches to feet we divide the number by 12.
36 ÷ 12 = 3
24 ÷ 12 = 2
18 ÷ 12 = 1.5
Now to find the volume, we multiply it all together.
3 × 2 × 1.5 = 9
It can hold 9 cubic feet.
Hope this helped!
Saeed wants to have his birthday at an amusement park with a few of his friends but he can't spend no more then $80. The amusement park charge6a flat admission fee of $35 for a private party and 6.50 per person for food and drinks
Write an inequality that represents the total cost of seeds birthday for n people given his budget
Answer:
T=35X6.50
Step-by-step explanation:
I need help with my homwork, and understanding how to solve it
Problem:
Answer:
Sorry, I cant read whole problem. Edit your question and ill fix my answer
Step-by-step explanation:
4. Find the equation of the line that has a slope of 3 and goes through the point (3,4).
equation= y-y¹=m(x-x¹)
= y-4= 3(x-3)
y-4= 3x-9
y= 3x-9+4
y=3x-5
URGENT!! ILL GIVE BRAINLIEST! AND 100 POINTS
Fill in the banks if you had this question before!!
An equation for the total cars and trucks for dealership A is: x + y = 164.
An equation for the total cars and trucks for dealership B is: 2x + 0.5y = 229.
The number of cars that dealership A sold is: 98 cars.
The number of trucks that dealership B sold is: 66 trucks.
How to write a system of equations to model this situation?In order to write a system of linear equations to describe this situation, we would assign variables to the number of cars sold and number of trucks sold, and then translate the word problem into an algebraic equation as follows:
Let the variable x represent the number of cars sold.Let the variable y represent the number of trucks sold.Since the first dealership sold a total of 164 cars and trucks, a linear equation to model this situation is given by;
x + y = 164.
Additionally, the second dealership sold twice as many cars and half as many trucks as the first dealership, with a total of 229 cars and trucks;
2x + 0.5y = 229.
By solving the systems of linear equations simultaneously, we have:
2x + 0.5(164 - x) = 229
1.5x + 82 = 229
x = 98 cars.
For the y-value, we have;
2(98) + 0.5y = 229
0.5y = 229 - 196
y = 33/0.5
y = 66 trucks.
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Find the LCM of A= 3^2 x 5^4 x 7 and B= 3^4 x 5^3 x 7 x11
The LCM of A = 3² × 5⁴ × 7 and B = 3⁴ × 5³ × 7 × 11 is 3898125 using Prime factorization.
Given are two numbers which are showed in the prime factorized form.
A = 3² × 5⁴ × 7
B = 3⁴ × 5³ × 7 × 11
Prime factorization is the factorization of a number in terms of prime numbers.
In order to find the LCM of these two numbers, we have to first match the common primes and write down vertically when possible and then bring down the primes in each column.
A = 3² × 5³ × 5 × 7
B = 3² × 3² × 5³ × 7 × 11
Bring down the primes in each column.
LCM = 3² × 3² × 5³ × 5 × 7 × 11
= 3898125
Hence the LCM is 3898125.
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Which equations are true and can be used to find some multiples of 7? Check all that apply.
O 7x 0 = 7
O 7x1=7
O 7*4= 27
O 7x 10 = 70
O 7 x 12 = 84
Answer:
7 × 1 = 7 7 × 10 = 70 7 × 12 = 84
Step-by-step explanation:
Question 8 of 10
Which descriptions from the list below accurately describe the relationship
between ABC and DEF? Check all that apply.
Answer:
C. Same shape
D. Similar
Step-by-step explanation:
All three angles in ∆ABC are congruent to all three corresponding angles in ∆DEF. However, the three corresponding sides of both ∆s are not the same but they are proportional to each other.
This implies that, both triangles are similar.
Similar triangles have the same shape but different size.
Thus, ∆ABC and ∆DEF can be referred to as being similar and also having the same shape.
Is this correct?? So, basically, it asking for a decimal equivalent to 920.35
What equation results from completing the square and then factoring?
x2 + 16x = 41
Answer:
D. (x+8)^2=105 A P E X
Step-by-step explanation:
A population of deer inside a park has a carrying capacity of 200 and a growth rate of 3%. If the initial population is 80 deer, what is the population of deer at any given time?
Answer:
The population of deer at any given time = 200(e^0.03t) ÷ (1.5 + (e^0.03t))
Step-by-step explanation:
This is an example of logistic equation on population growth
carrying capacity, k = 200
Rate, r = 3% = 0.03
Initial Population, P1 = 80
P(t) =?
P(t) = (P1 (k)(e^rt)) ÷ (k- P1 + P1(e^rt))
P(t) = (80 (200)(e^0.03t)) ÷ (200 - 80 + 80(e^0.03t))
= (16000(e^0.03t)) ÷ (120 + 80(e^0.03t))
= 200(e^0.03t) ÷ (1.5 + (e^0.03t))
A boat is heading towards a lighthouse, whose beacon-light is 104 feet above the water. From point A, the boat’s crew measures the angle of elevation to the beacon 7°, before they draw closer. They measure the angle of elevation a second time from point B at some later time to be 24° Find the distance from point A to point B. Round your answer to the nearest tenth of a foot if necessary.
The distance form the point A to point B is equal to 618.76 feet according to the trigonometric laws.
Given that beacon-light is 104 feet above the water.
Also ∠A = 7° and ∠B = 24° with respect to the ground and the light house.
Sketch part from the above information attached below.
Let's say that the lighthouse is "O".
According to the trigonometric laws:
Tan ∝ = opposite side / adjacent side
Now, we need to find accordingly.
⇒ Tan 7°=104/AO
A0 = 104/Tan 7°
AO ≈ 852.46
Similarly,
Tan 24°= 104/BO
BO = 104/ tan 24°
BO ≈ 233.7
Now, we need to find the distance from point A to point B.
AB = AO-BO
AB = 852.46-233.7
AB = 618.76 feet
Therefore, the distance from point A to point B is 618.76 feet.
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Factor the expression completely
54a⁶b²+ 9ab²
To factor the expression 54a⁶b²+ 9ab², you can use the fact that a common factor of 54a⁶b² and 9ab² is ab².
Thus, you can rewrite the expression as:
ab²(54a⁶ + 9)
You can then factor the expression inside the parentheses using the fact that 3 is a common factor of both 54 and 9:
ab²(3 * 18a⁶ + 3 * 3)
This can be simplified as:
ab²(6a⁶ + 9)
This expression is completely factored and cannot be further simplified. Therefore, the completely factored form of the expression is:
ab²(6a⁶ + 9)
I don’t know how to do these
The area, A, of the regular polygons found their side lengths, s and the length of their apothem, are;
4. A ≈ 2144.5 cm²
6. A = 12080 in²
8. A ≈ 1168.5 m²
What is a regular polygon?A regular polygon is a polygon that have sides of the same length and that the sides are symmetric about a common central point.
The area of a regular polygon is given by the formula;
\( \displaystyle{A = \frac{n \times s\times a}{2} }\)
Therefore, we have;
4. The area of a regular pentagon is given by the formula;
\(\displaystyle{A = \frac{5 \times s\times a}{2} }\)
Where;
a = 24.3 cm, s = 35.3 cm, we have;
\(\displaystyle{A = \frac{5 \times 35.3 \times 24.3}{2} \approx 2144.5}\)
The area of the pentagon is therefore; A ≈ 2144.5 cm²6. The area of a regular octagon is given by the formula;
\(\displaystyle{A = \frac{8 \cdot s\cdot a}{2} }\)
Where;
a = 60.4 in,
s = 50 in
Which gives;
\(\displaystyle{A = \frac{8 \times 50\times 60.4}{2} = 12080 }\)
The area of the octagon is A = 12080 in²8. The area of a regular decagon is given by the formula;
\(\displaystyle{A = \frac{10 \times s\times a}{2} }\)
Where;
a = 19 m
s = 12.3 m
Which gives;
\(\displaystyle{A = \frac{10 \times 12.3\times 19}{2} = 1168.5}\)
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What is the slope of the line containing (-2,5) and (4,-4)?A.3/2B.-3/2C. -2D. 2
Answer:
B.-3/2
Step-by-step explanation:
To find the slope, we need to take two points from a line. I am going to call them:
(x1,y1) and (x2,y2).
The slope is:
\(a=\frac{y2-y1}{x2-x1}\)In this question:
(x1,y1) = (-2,5)
(x2,y2) = (4, -4)
So
\(a=\frac{y2-y1}{x2-x1}=\frac{-4-5}{4-(-2)}=\frac{-9}{4+2}=-\frac{9}{6}=-\frac{3}{2}\)So the correct answer is:
B.-3/2
Five occupancy in a city is an indication of the economic health of the region in which it is located. A random sample of offices in two cities was selected, and the number of vacancies was recorded. Construcr a 95% confidence interval to estimate the difference in vacancy rates between these two cities. What conclusions can be made?
Occupancy by City
City 1 City 2
x1 = 22 x2 = 12
n1 = 155 n2 = 135
A. Since the confidence interval does include zero, there is no evidence that the vacancy rates are different between the two cities.
B. Since the confidence interval does not include zero, there is no evidence that the vacancy rates are different between the two cities.
C. Since the confidence interval does not include zero, there is evidence that the vacancy rates are different between the two cities.
D. Since the confidence interval does include zero, there is evidence that the vacancy rates are different between the two cities.
Answer:
Step-by-step explanation:
Confidence interval for the difference in the two proportions is written as
Difference in sample proportions ± margin of error
Sample proportion, p= x/n
Where x = number of success
n = number of samples
For city 1,
x = 22
n1 = 155
p1 = 22/155 = 0.14
For city 2,
x = 12
n2 = 135
p2 = 12/135 = 0.09
Margin of error = z√[p1(1 - p1)/n1 + p2(1 - p2)/n2]
To determine the z score, we subtract the confidence level from 100% to get α
α = 1 - 0.95 = 0.05
α/2 = 0.05/2 = 0.025
This is the area in each tail. Since we want the area in the middle, it becomes
1 - 0.025 = 0.975
The z score corresponding to the area on the z table is 1.96. Thus, confidence level of 95% is 1.96
Margin of error = 1.96 × √[0.14(1 - 0.14)/155 + 0.09(1 - 0.09)/135]
= 1.96 × √0.00138344086
= 0.073
Confidence interval = 0.12 - 0.09 ± 0.073
= 0.03 ± 0.073
C. Since the confidence interval does not include zero, there is evidence that the vacancy rates are different between the two cities.
Answer:
Option A
Step-by-step explanation:
90% CI for p₁ - p₂
\(x_1=22,n_1=155\\x_2=12,n_2=135\)
\(\hat p=\frac{22}{155} =0.141935 \approx 0.142\\\\\hat p_2=\frac{12}{135}=0.088889\approx 0.089\)
\((\hat p_1-\hat p_2)=(0.142-0.0889)=0.0531\)
\(SE_{(\hat p_1-\hat p_2)}=\sqrt{\frac{\hat p_1 (1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2} } \\\\=\sqrt{\frac{0.142(1-0.142)}{155} +\frac{0.00889(1-0.00889)}{135} } \\\\=\sqrt{\frac{0.142(0.858)}{155} +\frac{0.00889(0.9111)}{135} } \\\\=\sqrt{\frac{0.1218}{155} +\frac{0.0080997}{135} } \\\\=0.037224\\\\\approx0.037\)
\(Z_{\alpha /2}=Z_{0.05}=1.645 (\texttt {from z table})\\\\\texttt {Margin of Error}=Z_{\alpha /2}SE_{p_1-p_2}=1.65\times0.0372=0.061234\\\\\texttt {CI is given by}:(\hat p_1- \hat p_2) \pm Z_{\alpha /2}SE_{p_1-p_2}\\\\\texttt {lower limit}=0.0531-1.645\times0.0372=-0.008187\approx-0.008\\\\\texttt {Upper limit}=0.053+1.645\times0.0372=0.114281\approx0.114\)
90% CI for p₁ - p₂ : (-0.008 , 0.114)
Therefore, Since the confidence interval does include zero, there is no evidence that the vacancy rates are different between the two cities.
Find the measure of BC
Using central angle theorem,
The measure of the arc BC = 110°.
Define central angle?An angle with its vertex in the middle of the circle it creates with its two radii is said to be central.
Here in the question,
As per the central angle theorem:
(2x -30) ° + x° = 180°
⇒ 2x - 30 + x = 180
⇒ 3x - 30 = 180
Adding 30 on both sides:
⇒ 3x = 180 + 30
⇒ 3x = 210
Dividing both sides by 3.
⇒ x = 70°
Now BC = 2x-30
= 2 × 70 -30
= 140 - 30
= 110°
Therefore, the measure of BC = 110°.
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ASAP BRAINLIEST !! Luis is given the fraction 4/5. He is told to create an equivalent fraction with a numerator of 32. Explain the steps you’d use to solve for the missing denominator. Answer in 2-3 sentences.
Answer: answer 40.
Step-by-step explanation:
Note : lets make x the missing denominator.
I would take the 4/5 and set it equals to 32/x
we then cross multiply
where it would be 4 * x = 32 * 5
it would then be 4x = 160
we would then divide 160 by 4
x = 160/ 4
and x would be 40
.... therefore the missing denominator is 40.
Answer:
Your fraction would be 32/40
Step-by-step explanation:
For it to be equivalent it has to be equal to 4/5. what i did was divided 32 by for and got 8. I then multiplied 4/5 and 8/8 and the answer was 32/40. I multiplied by 8/8 because for it to be equivalent i have to do the same thing to both the numerator and denominator.
I really hope this helps as much as it can
Have an amazing rest of the day or night : )
I will be glad to help if you have any more questions
The wheel on a scooter completes 124 revolutions and travels 22.4 meters. What is the diameter of the wheel in mm? Use 3.14 for pi and round to the nearest whole millimeter.
If wheel on a scooter completes 124 revolutions and travels 22.4 meters then diameter of the wheel is 57 mm
Each revolution of the wheel covers a distance equal to the circumference of the wheel.
The diameter of the wheel "d".
The distance covered in 124 revolutions is:
distance = 124 x circumference
= 124 x pi x d
= 124 x 3.14 x d
We know that this distance is equal to 22.4 meters, so we can set up an equation:
124 x 3.14 x d = 22.4
Simplifying and solving for d:
d = 22.4 / (124 x 3.14)
d = 0.057 meters
As we know that 1 meter is equal to thousand millimeters so multiply by 1000 to get in millimeters
d = 57 millimeters
Therefore, the diameter of the wheel is approximately 57 mm.
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Question 14 (1 point)
Chris sells computer equipment for his company. He receives a base pay of $300
plus commission on his sales. He receives 10% for the first $5000 in sales and 15%
anything over $5000.
Last week, he sold $17000 in computer equipment. Find his gross pay.
Round to the nearest whole dollar.
For your answer, do NOT include symbols, commas, words, etc.
HELP PLS
Chris' gross pay for the week after selling computer equipment worth $17,000 is $2,600.
How is the gross pay determined?The gross pay is the addition of the base pay and the sales commission.
The sales commission is graduated and computed as follows:
Chris' base pay = $300
Sales Commissions:
First $5,000 = 10%
Above $5,000 = 15%
Last week's sales = $17,000
10% Commission = $500 ($5,000 x 10%)
15% Commission = $1,800 ($17,000 - $5,000 x 15%)
Total Commission = $2,300
Gross pay = Base Pay + Commission
= $2,600 ($300 + $2,300)
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please help need this done by tomorrow [PHOTO]
Answer:
15
Step-by-step explanation:
8x-3+4x+3=180
12x=180
x=180/12
x=15
Step-by-step explanation:
The Straight angle is an angle equal to 180 degrees.
So (8x - 3) + (4x + 3) = 180
8x - 3 + 4x + 3 = 180
12x = 180
x = 15
please give me a brainliest answer
Alex Meir recently won a lottery and has the option of receiving one of the following three prizes: (1) $90,000 cash immediately, (2) $35,000 cash immediately and a six-period annuity of $9,400 beginning one year from today, or (3) a six-period annuity of $17,700 beginning one year from today. (FV of $1, PV of $1, FVA of $1, PVA of $1, FVAD of $1 and PVAD of $1) (Use appropriate factor(s) from the tables provided.)
1. Assuming an interest rate of 5%, determine the present value for the above options. Which option should Alex choose?
2. The Weimer Corporation wants to accumulate a sum of money to repay certain debts due on December 31, 2030. Weimer will make annual deposits of $180,000 into a special bank account at the end of each of 10 years beginning December 31, 2021. Assuming that the bank account pays 6% interest compounded annually, what will be the fund balance after the last payment is made on December 31, 2030?
Based on the annuities calculated, he should choose option 1.
How to calculate the annuities?Present value = $35,000 + (Annuity amount * Present value of an ordinary annuity of $1)
= $35,000 + ($9,400 * (5%,6))
= $35,000 + ($9,400 * 5.07569)
= $35,000 + 47,711
= $82,711
Present value = (Annuity amount * Present value of an ordinary annuity of $1)
= $17,700 * (5%,6)
= $17,700 * 5.07569
= $89,840
Alex should choose Option 1
Future value annuity = Annuity amount * Future value of an ordinary annuity of $1
= $180,000 * (6%,10)
= $180,000 * 13.1808
= $2,372,544
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Suppose you have an experiment where you toss a fair coin three times You then count the number of heads observed over those three tosses Use this experiment to address each of the following questions Round solutions to three decimal places if necessary a. State the random variable
b. Construct a probability distribution table for the number of heads obtained over three tosses Enter the x values from smallest to largest
c. Determine the shape of the probability distribution of x The probability distribution of is d Find the mean number of heads for this distribution fl.____
The mean of a discrete probability distribution is also notated by Select an answer Which of the following is the correct interpretation of the mean Select an answer e Find the standard deviation for the number of heads for this distribution
f Find the probability of obtaining one or more heads over three tosses of a coin P one or more heads
The probability distribution of X is Binomial with parameter n = 3 , p = 0.5
How to solve thisa) X : The random variable denotes the number of heads observed over those three tosses.
b) n = number of tosses = 3 , p = probability of head = 0.5 ( as the coin is unbiased)
x P[X=x] = p(x) = (3)0.53\n
0 0.125
1 0.375
2 0.375
3 0.125
Total 1.0
c) The probability distribution of X is Binomial with parameter n = 3 , p = 0.5
d) We know mean of Binomial(n , p ) = np = 3 x 0.5 = 1.5
e) We know sd of Binomial np = \(\sqrt{np(1-P)} = \sqrt{3 * 0.5 * 0.5} = 0.867\)
f) P[Two or more heads] = P[ X= 2]+P[X=3]
= 0.375+0.125
=0.5
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4-member curling team is randomly chosen from 6 grade 11 students and 8 grade 12 students. What is the probability that the team has at least 2 grade 11 students?
Answer:
0.5944 = 59.44% probability that the team has at least 2 grade 11 students
Step-by-step explanation:
The students are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.
Hypergeometric distribution:
The probability of x successes is given by the following formula:
\(P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}\)
In which:
x is the number of successes.
N is the size of the population.
n is the size of the sample.
k is the total number of desired outcomes.
Combinations formula:
\(C_{n,x}\) is the number of different combinations of x objects from a set of n elements, given by the following formula.
\(C_{n,x} = \frac{n!}{x!(n-x)!}\)
We have that:
6 + 8 = 14 students, which means that \(N = 14\)
6 grade 11 students means that \(k = 6\)
Teams of 4 members means that \(n = 4\)
What is the probability that the team has at least 2 grade 11 students?
This is:
\(P(X \geq 2) = 1 - P(X < 2)\)
In which
\(P(X < 2) = P(X = 0) + P(X = 1)\)
So
\(P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}\)
\(P(X = 0) = h(0,14,4,6) = \frac{C_{6,0}*C_{8,4}}{C_{14,4}} = 0.0699\)
\(P(X = 1) = h(1,14,4,6) = \frac{C_{6,1}*C_{8,3}}{C_{14,4}} = 0.3357\)
Then
\(P(X < 2) = P(X = 0) + P(X = 1) = 0.0699 + 0.3357 = 0.4056\)
\(P(X \geq 2) = 1 - P(X < 2) = 1 - 0.4056 = 0.5944\)
0.5944 = 59.44% probability that the team has at least 2 grade 11 students
Find the local maximum and local minimum
Answer:
Maximum= (-2,15)
Minimum= (2,-15)
Let BC=CD=12cm, and the length of arc BD=15cm. Find the area, in square centimeters, of sector BCD.
Answer:
option b : 90 sq. cm
Step-by-step explanation:
1) Area of circle with radius = 12cm
Area = π r^2
= 3.14 * (12) (12)
= 3.14 * 144
= approx 452.4
2) Circumference of circle with radius = 12cm
Circumference = 2πr
= 2 * 3.14 * 12
= approx 75 .4
3) Arc length = 15cm ......(given)
\( \frac{area \: of \: sector}{total \: area} = \frac{arc \: length}{circumference} \)
\( \frac{area \: of \: sector}{452.4} = \frac{15}{75.4} \)
\(area \: of \: sector \: = \frac{15 \times 452.4}{75.4} \)
\( = \frac{6786}{75.4} \)
\( = 90 {cm}^{2} \)
How could Brent use a rectangle to model the factors of x2 – 7x + 6?
He could draw a diagram of a rectangle with dimensions x – 3 and x – 4 and then show the area is equivalent to the sum of x2, –3x, –4x, and half of 12.
He could draw a diagram of a rectangle with dimensions x + 7 and x – 1 and then show the area is equivalent to the sum of x2, 7x, –x, and 6.
He could draw a diagram of a rectangle with dimensions x – 1 and x – 6 and then show the area is equivalent to the sum of x2, –x, –6x, and 6.
He could draw a diagram of a rectangle with dimensions x – 4 and x + 3 and then show the area is equivalent to the sum of x2, –4x, 3x, and half of –12.
The true statement is (c) that He could draw a diagram of a rectangle with dimensions x – 1 and x – 6 and then show the area is equivalent to the sum of x^2, –x, –6x, and 6.
What is factorization?factorization is the method of breaking a number into smaller numbers that multiplied together will give that original form.
The expression is given as:
\(x^{2} -7x + 6\)
Expand;
\(x^{2} -6x - x +6\)
Factorize;
x(x-1) - 6 (x- 1)
Factor out x - 6
(x - 6) (x- 1)
This means that the factors of \(x^{2} -7x + 6\) are x - 1 and x - 6
Hence, the true statement is (c) that He could draw a diagram of a rectangle with dimensions x – 1 and x – 6 and then show the area is equivalent to the sum of x^2, –x, –6x, and 6.
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Answer: Answer is C
Step-by-step explanation:
What conversion factor between cubic inches and cubic yards
Answer:
The conversation factor is 16.387604
identify the parametric equations that represent the same path as the following parametric equations. show your work
x=3+ cos theta
y= 2 sin theta
A. x=3+cos 2 theta
y=2sin 2theta
B.x=cos theta
y=3+2sin theta
C. x=3+2 cos theta
y= 4 sin theta
D. x=2 sin theta
y= 3+cos theta
I know it’s A but i’m not sure how to do the work :(
The parametric equation that represents the same path as the given parametric equation is Option A.
What is a parametric equation?A parametric equation is an equation where the value of x variable given in terms of theta is also expressed in y variable in terms of the same parameter theta.
Given that:
x=3+ cos thetay= 2 sin thetawhere;
theta = parameterThe pair of (x and y) are called parametric equations.
At any given theta (θ), we can substitute it into the equation to determine the value of x and y.
Now, the cartesian form of the parametric equation will help us to determine if the parametric equation are represented in the same path.
The cartesian form is the equation with just x and y whereby the parameter is eliminated.
So, from the given equation;
x = 3 + cos θ
y = 2 sin θ
cos θ = x - 3
sin θ = y/2
We know from trigonometry identity that:
sin²θ + cos²θ = 1we can eliminate the parameter by saying:
(y/2)² + (x-3)² = 1From the given options, Option A represents the same path as the given parametric equation.
This is because:
x = 3 + cos 2 θ
y = 2sin 2 θ
cos 2θ = 3 - x
sin2θ = y/2
Eliminating the parameter, we have:
(y/2)² + (x-3)² = 1Learn more about parametric equations here:
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