I need help ASAP with this pyramid scale factor question!

Answer:

you saved $3.20

Step-by-step explanation:

16 x 20/100

16 x 0.2

= 3.20

so 16-3.20= 12.80

final price is 12.80

Answer:

13.5w + 5.4.

Step-by-step explanation:

Using the distributive property, we would write it out like
-6(0.6w-3w-0.9)-0.9w = -3.6w + 18w + 5.4 - 0.9w
Then we would combine like terms by adding the coefficients of the w terms:
-3.6w + 18w - 0.9w = 13.5w
Lastly we can add the constant terms.
13.5w + 5.4 = 13.5w + 5.4

Answer:

The answer is the third graph or c

Step-by-step explanation:

I just did the test and the other guy is correct to.

Answer:

If you are on edg 2021 then it is the graph with the line going down from 0 to the bottom left square of the graph

Step-by-step explanation:

So it is the first graph.

Answer:

daddy chill

Step-by-step explanation:

what does te guy say?

If points d and f are on side ab and points e and g are on side ac then line segments de and fg are parallel

What are parallel lines?

Parallel lines are those lines that do not meet at any point. If we draw a triangle ABC and plot points d and f are marked on side ab and points e and g are marked on side ac then the line segment fg is parallel to de because both the line segments are drawn from the points which are on the sides opposite to each other. We have assumed a simple triangle because no description is given for the triangle

Hence the line segment fg is parallel to de if drawn points d and f marked on ab and points e and g are marked on ac.

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The simplification of the expression 6 + (5 + x) is 11 + x

6 + (5 + x)

Based on the associative property

= (6 + 5) + x

Add 6 and 5

= 11 + x

Associative property states that the rearranging of parenthesis in an expression will not change the result.

Commutative property on the other hand states that the numbers on which we operate can be interchanged or moved from their position without making any difference to the result.

Ultimately, the results of 6 + (5 + x) is 11 + x

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The coefficient of determination, R^2, represents the proportion of the total variation in the dependent variable (sale price, y) that can be explained by the independent variable (gross living area, GLA, x) in a linear regression model.

In this case, the given value of R^2 is 0.77 (or 77%). This means that approximately 77% of the total variation in the sale prices of the properties in the sample can be attributed to the linear relationship between the gross living area and the sale price.

Interpreting this value:

- The value of 0.77 indicates a relatively high coefficient of determination. It suggests that the model is able to explain a significant portion of the variability in sale prices based on the variation in the gross living area.

- The higher the R^2 value, the more accurately the model can predict the sale prices based on the gross living area.

- In this case, the linear regression model with the gross living area as the independent variable accounts for 77% of the observed variation in sale prices.

It is important to note that the coefficient of determination, R^2, does not indicate causality but rather the strength of the linear relationship and the proportion of the variability explained by the model.

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Answer:

12.955

Step-by-step explanation:

you know they made errors because between all the numbers, the whole number is 12 and the rest are 0, which means that the whole number part cannot be less than 12. While for the decimal part the largest number of decimal places is 3, and that what your final answer has to have. I hope this helped :)

Answer:

x=3 one solution

Step-by-step explanation:

2x minus 6=-2x+6

2x+2x=6+6

4x=12

divide by 4

x=3

so it has one solution

Answer:

The first quadrant

Step-by-step explanation:

If the figure in the second quadrant is reflected over the y-axis, then the reflected figure will appear in the first quadrant.

Given that:

A figure is in the second quadrant.

Then, it is reflected over the y-axis.

After the reflection of a figure, the resulting figure or the reflected image will be the mirror image of the figure.

Since the reflection is over the y-axis, the figure will be reflected through the right of the original figure.

So, the reflected figure will appear on the first quadrant.

In another way, the coordinates of a point on the second quadrant will be (-x, y).

After reflection over the y-axis, the x-coordinate will become negative.

So, the coordinate will be (x, y), which is in the first quadrant.

Hence, the reflected figure will be in the first quadrant.

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Step-by-step explanation:

so 2.3 + 5.7 is 8.0 is the answer

The expected value for the given binomial distribution is approximately 0.91648.

To calculate the expected value for a binomial distribution, you need to multiply each possible value by its corresponding probability and then sum them up. Let's calculate the expected value using the provided probabilities: Successes Probability

0 1024/3125

1 256/625

2 128/625

3 32/625

4 4/625

5 1/3125

Expected Value (μ) = (0 * (1024/3125)) + (1 * (256/625)) + (2 * (128/625)) + (3 * (32/625)) + (4 * (4/625)) + (5 * (1/3125)). Expected Value (μ) = 0 + 0.4096 + 0.32768 + 0.1536 + 0.0256 + 0.00032. Expected Value (μ) = 0.91648. Therefore, the expected value for the given binomial distribution is approximately 0.91648.

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a. (0,0), (5,0), (3.75, 3.75), (3.5,4.5), (0,8);

b. x = 3.5, y = 4.5, OFV = 59.5;

c. s1 = 0, s2 = 2, s3 = 0.

a. The extreme points of the feasible region are the vertices of the polygon formed by the intersection of the constraint lines. In this case, the extreme points are (0,0), (5,0), (3.75, 3.75), (3.5,4.5), and (0,8).

b. To find the optimal solution and the objective function value, we evaluate the objective function at each extreme point and choose the point that maximizes the objective function. In this case, the point (3.5, 4.5) maximizes the objective function with a value of 59.5. Therefore, the optimal solution is x = 3.5 and y = 4.5, and the objective function value is 59.5.

c. The slack variables represent the surplus or slack in each constraint. We calculate the slack variables by subtracting the actual value of the left-hand side of each constraint from the right-hand side. In this case, the values of the slack variables are s1 = 0 (indicating no slack in the first constraint), s2 = 2 (indicating a surplus of 2 in the second constraint), and s3 = 0 (indicating no slack in the third constraint).

Therefore, the correct option is:

a. (0,0), (5,0), (3.75, 3.75), (3.5,4.5), (0,8);

b. x = 3.5, y = 4.5, OFV = 59.5;

c. s1 = 0, s2 = 2, s3 = 0.

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The reduced cost matrix for travelling salesperson problem in the given instance is shown below. The Travelling Salesperson Problem (TSP) is a classical combinatorial optimization issue that belongs to the category of NP-Hard problems.

This problem can be resolved using a branch and bound algorithm or by using dynamic programming.The reduced cost matrix for the given travelling salesperson problem instance The computation of the reduced cost matrix for travelling salesperson problem involves two steps: Identify the smallest element of each row and subtract the value from all the values in the row.

Identify the smallest element of each column and subtract the value from all the values in the column.In the given instance, the smallest element of each row is highlighted in bold. Therefore, after performing Step 1 the matrix becomes the matrix becomes Hence, the reduced cost matrix for the travelling salesperson problem is obtained.

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The control chart limits (3 sigma) for the fertilizer-bag-filling machine can be computed using Table $6.1.

To compute the control chart limits (3 sigma) using Table $6.1 for the fertilizer-bag-filling machine, follow these steps:

Determine the sample size: In this problem, each sample consists of 7 observations.

Calculate the average range (R): For each sample, calculate the range by subtracting the smallest observation from the largest observation. Then, calculate the average range across all 35 samples.

Find the appropriate value from Table $6.1: Locate the row in Table $6.1 corresponding to the sample size (7) and find the factor associated with 3 sigma. This factor represents the number of standard deviations for the control limits.

Compute the control limits: Multiply the average range (R) by the factor obtained from Table $6.1 to determine the width of the control limits. Then, subtract this width from the overall average of the process data to obtain the lower control limit, and add the width to the overall average to obtain the upper control limit.

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Answer:

22

Step-by-step explanation:

6 divided 6 equals 1 and 1 times 22 equals 22

Brainliest ?

Answer:

6.998 rounded to 7.00

Step-by-step explanation:

Answer:

3-y/3

The slope is -2/5

Step-by-step explanation:

Answer:

not exactly sure what is being asked butttt i think it's 90

Step-by-step explanation:

Answer:

The solution of the system of equation is x = 3, and y = 24

Step-by-step explanation:

The given system of equations are;

y = 8·x...(1)

y = 10·x -6...(2)

Solving the above system of linear equations using the comparison method, we first make one of the variables the subject of both equations

However, the given already have 'y' as subject, therefore, by comparison, we have;

y = y...(3)

8·x = 10·x - 6...(4)

From equation (4) given in the variable 'x', above, we have;

8·x = 10·x - 6

8·x - 8·x + 6 = 10·x - 6 + 6 - 8·x (the underlined items become zero)

∴ 6 = 10·x - 8·x = 2·x

6 = 2·x

∴ 2·x = 6

x = 6/2 = 3

x = 3

From equation (2), y = 8·x, we get;

y = 8·x

x = 3

∴ y = 8 × 3 = 24

y = 24

The values of 'x' and 'y' in the given system of equation is x = 3, y = 24.

Answer:

10/15-9/15=1/15

Step-by-step explanation:

2/3=10/15

3/5=9/15

10/15-9/15=1/15

Answer:

x= 3 + y/3

Step-by-step explanation:

The compound interest formula is:

Where

P is principal

r is rate of interest

n is number of compounding

t is number of years

Putting the given information, we have:

Interest amount is:

15,439.60 - 13,500 = $1939.60 (in a year/12 months)

In 10 months:

Justin would owe $1616.33 after 10 months.

The particular solution satisfying the initial conditions is y(t) = (1/2)*cos(2t) - (1/8)*sin(2t) + (1/4)t - 1/2 and the graph has been plotted.

The given differential equation is y′′ + 4y = (t − ) − (t − 2). To solve this equation, we will first find the general solution to the homogeneous part, y′′ + 4y = 0, and then find a particular solution to the non-homogeneous part, (t − ) − (t − 2).

The characteristic equation for the homogeneous part is obtained by assuming the solution is of the form. Substituting this into the equation, we get r² + 4 = 0. Solving this quadratic equation, we find two complex roots: r = ±2i. Therefore, the general solution to the homogeneous part is y_h(t) = c₁cos(2t) + c₂sin(2t), where c₁ and c₂ are arbitrary constants.

To find a particular solution to the non-homogeneous part, we will use the method of undetermined coefficients. Since the non-homogeneous part contains terms (t − ) and (t − 2), we assume a particular solution of the form y_p(t) = At + B, where A and B are constants to be determined.

Taking the derivatives, we have y′_p(t) = A and y′′_p(t) = 0. Substituting these into the differential equation, we get 0 + 4(At + B) = (t − ) − (t − 2). Equating the coefficients of the like terms on both sides, we get 4A = 1 and 4B = -2.

Solving these equations, we find A = 1/4 and B = -1/2. Thus, the particular solution is y_p(t) = (1/4)t - 1/2.

The general solution to the original differential equation is given by the sum of the homogeneous and particular solutions: y(t) = y_h(t) + y_p(t).

y(t) = c₁cos(2t) + c₂sin(2t) + (1/4)t - 1/2.

We are given the initial conditions y(0) = 0 and y′(0) = 0.

Substituting these values into the general solution, we get:

y(0) = c₁cos(0) + c₂sin(0) + (1/4)*0 - 1/2 = 0.

This equation simplifies to c₁ - 1/2 = 0, which gives c₁ = 1/2.

Differentiating the general solution with respect to t, we get:

y′(t) = -2c₁sin(2t) + 2c₂cos(2t) + 1/4.

Substituting t = 0 and y′(0) = 0 into the above equation, we have:

y′(0) = -2c₁sin(0) + 2c₂cos(0) + 1/4 = 0.

This equation simplifies to 2c₂ + 1/4 = 0, which gives c₂ = -1/8.

Therefore, the particular solution satisfying the initial conditions is:

y(t) = (1/2)*cos(2t) - (1/8)*sin(2t) + (1/4)t - 1/2.

The graph will show how the solution varies with the input value t. It will illustrate the oscillatory nature of the cosine and sine functions, along with the linear term (1/4)t, which represents a gradual increase. The initial condition y(0) = 0 ensures that the graph passes through the origin, and y′(0) = 0 implies the absence of an initial velocity.

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0.13% of the test-takers Scored better than the trainee who scored 77.

To determine the percentage of test-takers who scored better than a trainee who scored 77, we can use the standard deviation and the concept of z-scores in a normal distribution.

Given that the distribution of scores is mound-shaped and symmetric, we can assume that the scores follow a normal distribution.

First, we need to calculate the z-score for the trainee who scored 77. The z-score measures how many standard deviations a particular value is from the mean. It is calculated using the formula:

z = (x - μ) / σ

Where:

- x is the individual score (77 in this case)

- μ is the mean (83 in this case)

- σ is the standard deviation (2 in this case)

Plugging in the values, we get:

z = (77 - 83) / 2 = -3

The z-score of -3 indicates that the trainee who scored 77 is 3 standard deviations below the mean.

To find the percentage of test-takers who scored better, we need to find the area under the normal curve to the right of the z-score -3. We can look up this value in a standard normal distribution table or use statistical software.

Using a standard normal distribution table, we find that the area to the right of -3 is approximately 0.0013.

To find the percentage, we multiply this area by 100:

Percentage = 0.0013 * 100 = 0.13%

Therefore, approximately 0.13% of the test-takers scored better than the trainee who scored 77.

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From the given equation, we are to solve for b.

Hence the answer of b is -108.

Sherie can ensure that the frame's corners will be right angles by using the Pythagorean theorem to measure the diagonals of the frame. If the diagonals are equal in length, then the corners will be right angles.

To explain the process in detail, Sherie can follow these steps:

1. Start by laying out the stretcher bars in the shape of a rectangle, with two bars parallel to each other forming the longer sides and the other two bars parallel to each other forming the shorter sides.

2. Take a ruler and measure 12 inches along one of the longer sides, and mark that point.

3. From the marked point, measure 9 inches along one of the shorter sides, and mark that point as well. This creates a right angle.

4. Now, measure the distance between the two marked points. This will be the length of one of the diagonals of the frame.

5. Next, measure the distance between the other two corners of the frame. This will be the length of the other diagonal of the frame.

6. Finally, compare the lengths of the two diagonals. If they are equal, then the corners of the frame will be right angles.

By using the Pythagorean theorem (a^2 + b^2 = c^2), where 'a' and 'b' are the lengths of the sides of the rectangle, and 'c' is the length of the diagonal, Sherie can ensure that the frame's corners are right angles.

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the correct choice is: The critical point x=-6/7 corresponds to a local maximum.

To find the critical points of the function f(x) = x^2 - 8x^2 - 12x, we need to find where its derivative is equal to zero or undefined. So, let's find the derivative of f(x) first:

f'(x) = 2x - 16x - 12

Next, we set f'(x) equal to zero and solve for x:

2x - 16x - 12 = 0

-14x - 12 = 0

x = -6/7

So, the critical point is x = -6/7.

To determine whether this critical point corresponds to a local maximum, local minimum, or neither, we need to use the Second Derivative Test. For this, we need to find the second derivative of f(x):

f''(x) = 2 - 16

f''(x) = -14

Plugging in x = -6/7, we have:

f''(-6/7) = -14

Since the second derivative is negative at x = -6/7, the function has a local maximum at x = -6/7.

Therefore, the correct choice is: The critical point x=-6/7 corresponds to a local maximum.
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Answer:

2(29+14)

Step-by-step explanation:

Given function:

Find the GCF of 58+28:

Rewrite:

Therefore, using GCF, the new expression would be 2(29+14)..

The expression 58 + 28 can be factorized as 2 (29 + 14).

GCF which is the abbreviated form for Greatest Common Factor of two numbers, as the name implies, is the greatest common factor of both the numbers.

GCF of two numbers can be found using prime factorization.

Given the expression 58 + 28.

To find the GCF of two numbers, list the prime factors of these two numbers.

58 = 2 × 29

28 = 2 × 14 = 2 × 2 × 7

The only common factor is 2.

So the greatest common factor is 2.

58 + 28 = (2 × 29) + (2 × 14)

Taking the common factor of 2 outside the brackets,

58 + 28 = 2 (29 + 14)

Hence the expression 58 + 28 can be factorized as 2 (29 + 14) using the greatest common factor.

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