how to stop a deep cut from bleeding
Answers
To stop a deep cut from bleeding, apply pressure on, gauze or cloth while elevating Clean the wound.
When a serious cut won't stop bleeding, what should you do?Seek medical attention if the cut bleeds profusely or does not stop bleeding after 10 to 15 minutes of pressure. You might require stitches. After the bleeding has stopped, thoroughly clean the wound with cool water. You can either pour water from a cup over the area or hold the wound under running water.Put pressure on. Apply direct pressure to the wound with a clean piece of gauze or cloth while elevating. Elevate the affected limb above heart level if the cut is on your arms or legs to help the blood flow.Clean the wound. Apply pressure until the cut stops bleeding, then release it. Put on a bandage.To learn more about bleeding refer to:
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Related Questions
What's is the range 124 136 234 229 150
116 110 159 275 105
175 158 185 162 125
215 167 126 137 116
Answers
Answer:
the range is from 105 to 234
Step-by-step explanation:
Name the minor arc and find it’s measure. Then name the major arc and find it’s measure.
Answers
The minor arc in the given diagram as required to be determined is; arc TU and it's measure is; 116°.
The major arc in the given diagram as required to be determined is; arc TVU and it's measure is; 244°.
What are the measures of the minor and major arcs in the diagram?It follows from the task content that the minor and major arcs are to be named and their measures determined as required.
The minor arc in a circle is usually subtended by an angle less than 180° while the major arc is subtended by an angle greater than 180°.
Ultimately, the minor arc is; arc TU and it's measure is; 116° while the major arc is; arc TVU and it's measure is; 244°.
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A factory uses a special kind of lubricant to maintain its four milling machines. The weekly lubricant usage for each machine can be approximated with a normal distribution. This distribution has a mean of 30 gallons and a standard deviation of 11.5 gallons, and it can be considered as an independent random variable (zero covariance, zero correlation) from machine to machine. Suppose at the beginning of the week, the factory has a total of 150 gallons of lubricant in stock. The factory will not receive any replenishment of lubricant from its supplier until the end of the week.Assume that the total lubricant usage (four machines combined) also follows a normal distribution.
Required:
What is the probability that the factory will run out of lubricant before the next replenishment arrives?
Answers
Answer:
0.0968 = 9.68% probability that the factory will run out of lubricant before the next replenishment arrives
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean \(\mu\) and standard deviation \(\sigma\), the zscore of a measure X is given by:
\(Z = \frac{X - \mu}{\sigma}\)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
This distribution has a mean of 30 gallons and a standard deviation of 11.5 gallons
Since there are four machines, we have that:
\(\mu = 30*4 = 120\)
\(\sigma = 11.5\sqrt{4} = 11.5*2 = 23\)
What is the probability that the factory will run out of lubricant before the next replenishment arrives?
More than 150 gallons, so this is 1 subtracted by the pvalue of Z when X = 50.
\(Z = \frac{X - \mu}{\sigma}\)
\(Z = \frac{150 - 120}{23}\)
\(Z = 1.3\)
\(Z = 1.3\) has a pvalue of 0.9032
1 - 0.9032 = 0.0968
0.0968 = 9.68% probability that the factory will run out of lubricant before the next replenishment arrives
c⋅bc4−(7−a) When a=4, b=8, and c = 5
Answers
By plugging in the values given into \(c * \frac{bc}{4} - (7 - a)\) and using BODMAS rule, the algebraic expression can be evaluated as 47
\(\mathbf{c * \frac{bc}{4} - (7 - a) = 47}\)
Given the algebraic expression, \(c * \frac{bc}{4} - (7 - a)\), to evaluate the expression if a = 4, b = 8, and c = 5, plug in the values into the equation as shown below:
\(5 * \frac{(8)(5)}{4} - (7 - 4)\\\)
Solve the bracket\(5 * \frac{40}{4} - (3)\\\\5*10 - 3\)
Applying the BODMAS rule, multiply before you subtract
= 50 - 3
= 47
Therefore, by plugging in the values given into \(c * \frac{bc}{4} - (7 - a)\) and using BODMAS rule, the expression can be evaluated as 47
\(\mathbf{c * \frac{bc}{4} - (7 - a) = 47}\)
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Find the exact surface area of a sphere with a diameter of 13cm
Answers
Answer:
A = 530.929158457
Answer:
Area = 706.8583471
Explanation:
The used law to measure the surface area of the sphere is
\(area \: = 4\pi \: {r}^{2} \)
Where (r) is the radius. The radius is half the diameter, so it will be half 13 which is equal to 7.5. By using this law:
\(4\pi \: {7.5}^{2} = 706.8583471\)
If you like my explanation please give me 5 stars.The rate constant for first-order degradation of a N2O2 in a solution (1.0 mg/ml) at 40°C
is 0.00351 hr-1, activation energy is 2000 cal/mol, and R = 1.987 cal/mol/degree.
Calculate
a. The rate constant for first-order degradation of N2O2 at room temperature (25°C).
Answers
The 0.0035 hr⁻¹ first-order degradation rate constant in the 40 °C, 1.0 mg/ml solution, where R = 1.987 cal/mol/degree and 2,000 cal/mol activation energy indicates;
a. The rate constant for first-order degradation of N₂O₂ at room temperature is approximately 4.12595 × 10⁻² hr⁻¹
What is a first-order reaction?A first order reaction is one that has a rate that varies linearly with the concentration of one reactant
The given parameters are;
Temperature of the solution = 40°C
T₁ = 40 °C + 273.15 = 313.15 K
The rate constant, K₁ = 0.00351 hr⁻¹
Concentration of the solution = 1.0 mg/ml
Activation energy, Eₐ = 2000 Cal/mol
R = 1.987 cal/mol/degree
The formula by which the rate constant can be found is presented as follows;
\(log\dfrac{k_2}{k_1} =\dfrac{E_a}{2.303\times R} \times \dfrac{T_2-T_1}{T_1\cdot T_2}\)
a. Room temperature = 25 °C
T₂ = 25 °C + 273.15 = 298.15 K
Therefore;
\(log\dfrac{k_2}{0.00351} =\dfrac{2000}{2.303\times 1.987} \times \dfrac{313.15-298.15}{313.15 \times 298.15}\)
\(k_2=0.00351 \times 10^{\left(\dfrac{2000}{2.303\times 1.987} \times \dfrac{313.15-298.15}{313.15 \times 298.15}\right)} \approx 4.12595\times 10^{-2}\)
The rate constant for first-order degradation of N₂O₂ at room temperature is k₂ ≈ 4.12595 × 10⁻² hr⁻¹Learn more about the rate constant for first-order degradation here:
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(-1,1,5)
9
8
7-
6
5
4
3₂
-3-2-1₁
(1,5)
(0,3)
Which exponential function is represented by the graph?
Of(x)=2(3¹)
Of(x)=3(3)
Of(x)=3(2)
O f(x) = 2(2¹)
Answers
The value of the equation that defines the function is f(x) = 3(5/3)ˣ
Finding an equation defining the functionFrom the question, we have the following parameters that can be used in our computation:
(0, 3) and (1, 5)
An exponential function is represented s
y = abˣ
Where,
a = y when x = 0
So, we have
y = 3bˣ
Using the other point, we have
3b = 5
This gives
b = 5/3
So, we have
f(x) = 3(5/3)ˣ
Hence, the equation defining f is f(x) = 3(5/3)ˣ
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Solve this question Find AC
Answers
Answer:
26
Step-by-step explanation:
isosceles traingle:
AB=BC
7x-13=x+29
x=7
AC= 3x+5
AC= 3(7)+5
AC= 26
Team Arrow shoots an arrow from the top of a 1600-foot building on Earth-51. The arrow reaches a maximum height of 1840 feet after 4 seconds.Write an equation for the height of the arrow, h, in feet as a function of the number of seconds, t, since the arrow was shot.Round to 3 decimal places as needed. After how many seconds will the arrow reach the ground?Round to 3 decimal places as needed.
Answers
We will have the following:
***First:
\(h=h_0+v_0\cdot t+\frac{1}{2}g\cdot t^2\)Now, we will determine the value for the speed:
\(1840=1600+v_0\cdot(4)+\frac{1}{2}(-32.17)\cdot(4)^2\Rightarrow240=4v_0-\frac{25736}{25}\)\(\Rightarrow\frac{31736}{25}=4v_0\Rightarrow v_0=\frac{7934}{25}\Rightarrow v_0=137.36\)So, the equation for the height of the arrow (h) in feet as a function of the number of seconds t is:
\(h=1600+317.36t+\frac{1}{2}gt^2\)Here "g" is the gravitational pull of earth.
***Second:
We will determine how much time it would take for the arrow to hit the ground as follows:
\(0=1600+317.36t+\frac{1}{2}(-32.17)t^2\Rightarrow-\frac{3217}{200}t^2+317.36t+1600=0\)\(\Rightarrow t=\frac{-(317.36)\pm\sqrt[]{(317.36)^2-4(-\frac{3217}{200})(1600)}}{2(-\frac{3217}{200})}\Rightarrow\begin{cases}t\approx-4.163 \\ t\approx23.893\end{cases}\)So, afeter 23.893 seconds the arrow would hit the ground.
What’s the domain and range of the function graphed
Answers
Answer:where graph
Step-by-step explanation:
In the diagram, JK || GI. If the ratio of HJ to JG is 3 to 1, then what is the ratio of HK to KI?
Answers
The expression JK||GI implies line JK and GI are parallel lines
The ratio of HK : KI is 3 : 1
What is a ratio?A ratio is used to show the relationship between two related quantities
How to determine the ratio?The given parameter is:
HJ : JG = 3 : 1
Given that JK||GI , then it means that:
HJ : JG = HK : KI
This gives
HK : KI = 3 : 1
Hence, the ratio of HK : KI is 3 : 1
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A diet is being prepared for WTAMU dorms. The varied diet is to be made of three foods: A, B and C. Food A costs $2.25 per pound and contains 500 calories. Food B costs $ 2 per pound and contains 700 calories. Food C costs $ 3 per pound and contains 600 calories No more than 0.75 pounds of food C can be used per resident. No less than 2 pounds of food B should be used per resident. The objective is to feed the students at the least cost, but the diet must have at least 1800 calories.
If we define the decision variables as A: pounds of food A, B: pounds of food B, and C pounds of food C, the object function is to minimize Blank 1. In addition to non-negative constraints, other constraints are Blank 2,Blank 3, and Blank 4.
(1. No need to use multiplication sign. For example, just write 10A not 10*A. For greater(less) than sign, just write it as >= (<=).
2. Also please leave no space in equation. For example, write A<=100, not A <= 100.
3. Please write decimal number for example as 0.32 not .32 when applicable. )
Answers
This problem is designed to minimize the cost of feeding students in the dorms while providing a minimum of 1800 calories. The objective function is to minimize the cost of the diet, which is calculated by multiplying the pounds of each food by its cost and adding them together. The constraints of the problem are that A must be greater than or equal to 0, B must be greater than or equal to 2, and C must be less than or equal to 0.75.
1. 2.25A + 2B + 3C
2. A >= 0
3. B >= 2
4. C <= 0.75
The objective of this problem is to minimize the cost of feeding students in the dorms, while the diet must contain a minimum of 1800 calories. To achieve this, three decision variables were defined: A, B, and C, which represent the pounds of food A, B, and C respectively. The objective function is to minimize the cost of the diet, which is calculated by multiplying the pounds of each food by its cost, and adding them together. There are three constraints in the problem: A must be greater than or equal to 0, B must be greater than or equal to 2, and C must be less than or equal to 0.75. These constraints ensure that the diet contains the desired amount of each food and that the total calories meet the minimum requirements.
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someone help me please
Answers
Step-by-step explanation:
Hi,
You will have to move the pre-image 15 units to the right. You're also going to have to flip the image horizontally (kind of like flipping it across the x-axis) and after that, you're going to have to flip it so that it's facing the left side.
1) 15 units right
2) Flip-up
3) Flip to the left
Hope this helps :)
$14.95 to the nearest whole number
Answers
Answer:
umm IS it not $15
Step-by-step explanation:
Answer:1500
Step-by-step explanation: ok
6) What time will it be 17 hours and 53 minutes before 4:37 a.m.? Military time
Answers
Answer:
17:53=5:53pm
Step-by-step explanation:
How many }2 /3 cups servings are in a 4 cup container of food?
Answers
Answer 83
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
4 / \(\frac{2}{3}\) = 6
7X+2=5X+12 how do i show my work for this??
Answers
Answer:
Subtract 2 from each side=7X+2-2=5X+12-2
simplify=7X=5X+10
subtract 5x=7X-5X=5X+10-5X
simplify=2x=10
divide both sides by 2=2x/2=10/2
simplify=x=5
use symbolab for setbystep symbolab.com
A survey asks a random sample of 2500 adults in California if they support an increase in the state sales tax from 7.50% to 7.75%, with the additional revenue going to education. Let Y denote the number in the sample that say they support the increase. Suppose that 30% of all adults in California support the increase. The mean of Y is:_______
Answers
Answer:
\(E(Y) = 750\)
Step-by-step explanation:
Given
Sample Size = 2500
Percentage = 30%
Required
Calculate Mean of Y
Mean or Expected Value is calculated as thus;
\(E(Y) = np\)
Where E(Y) represents the mean
n represents the sample size (or population)
p represents the success probability
\(n = 2500 ; p = 30%\)%
\(p = \frac{30}{100} = 0.3\)
So,
\(E(Y) = 2500 * 0.3\)
\(E(Y) = 750\)
Hence, the mean value of Y is 750
Compute the following using a calculator.
csc(203∘)
Round your answer to the nearest thousandth, and only include the numerical value in your answer - do not write cscθ= in your response.
Answers
Using a calculator, the value of csc (203°) is -1.086
How to compute csc (203°) using a calculator?Trigonometry is a branch of mathematics dealing with the relationship between the ratios of the sides of a right-angled triangle with its angles.
Since csc (203°) = 1/[sin (203°)]
Press 1/ [sin (203°)] and then the equal to button on your calculator. We have:
1/[sin (203°)] = -1.086
Note: If you calculator have "cosec" or "csc" button, you can simply press cosec (203°) or csc (203°) to get the answer.
Thus, the value of csc (203°) is -1.086
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For questions 3-4, use the graph of the polynomial function to find the factorization of the polynomial. Assume there is no constant term. 3
Answers
3. The factored polynomial is p(x) = (x - 1)(x - 5)
4. The factored polynomial is p(x) = (x + 3)²
What is a polynomial?A polynomial is a mathematical expression in which the power of the unknown is greater than or equal to 2.
3. To factorize the polynomial using the graph, we see that the polynomial cuts the x - axis at x = 1 and x = 5.
This implies that its factors are (x - 1) and (x - 5)
So, the factored polynomial is p(x) = (x - 1)(x - 5)
4. To factorize the polynomial using the graph, we see that the polynomial touches the x - axis at only one point x = -3. So,it has repeated roots
This implies that its factors are (x - (-3)) = (x + 3) twice
So, the factored polynomial is p(x) = (x + 3)²
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explain why 4 x 3/5 =12 ×1/5 draw a picture
Answers
\( \rightarrow4 \times \frac{3}{5} = 12 \times \frac{1}{5} \\ \)
\( \rightarrow \frac{12}{5} = \frac{12}{5} \\ \)
\( \rightarrow \: lhs \: = \: rhs\)
Hence , 4 x 3/5 =12 ×1/5
Let's see
We know
a/b×c/d=ac/bdSo
4×3/5=12/5Hence verified
When a new machine is functioning properly, only 3% of the items produced are defective.
Assume that we will randomly select two parts produced on the machine and that we are
interested in the number of defective parts found.
a. Describe the conditions under which this situation would be a binomial experiment.
b. Draw a tree diagram similar to Figure 5.3 showing this problem as a two-trial experiment.
c. How many experimental outcomes result in exactly one defect being found?
d. Compute the probabilities associated with finding no defects, exactly one defect, and
two defects.
Answers
a. This situation would be a binomial experiment if the following conditions are met:
The trials are independent: The selection of one part does not affect the selection of the other.
Each trial has two possible outcomes: In this case, defective or non-defective.
The probability of success (finding a defective part) remains constant for each trial: In this case, the probability is 3% or 0.03.
The number of trials is fixed: We are selecting two parts, so the number of trials is predetermined.
b. Here is a tree diagram representing the two-trial experiment:
D ND
/ \ / \
D ND D ND
The branches represent the two trials, with D representing a defective part and ND representing a non-defective part.
c. To find the number of experimental outcomes resulting in exactly one defect, we can observe that there are two outcomes that meet this criterion: D-ND and ND-D. Both represent one defective part and one non-defective part.
d. The probabilities associated with finding no defects, exactly one defect, and two defects can be calculated as follows:
Probability of finding no defects: (1 - probability of finding a defective part) * (1 - probability of finding a defective part) = (1 - 0.03) * (1 - 0.03) = 0.97 * 0.97 = 0.9409.
Probability of finding exactly one defect: (probability of finding a defective part) * (probability of finding a non-defective part) + (probability of finding a non-defective part) * (probability of finding a defective part) = 0.03 * 0.97 + 0.97 * 0.03 = 0.0582.
Probability of finding two defects: (probability of finding a defective part) * (probability of finding a defective part) = 0.03 * 0.03 = 0.0009.
Therefore, the probabilities associated with finding no defects, exactly one defect, and two defects are approximately 0.9409, 0.0582, and 0.0009, respectively.
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what is the median of numbers 20,35,28,15,22,36,26
Answers
The median of the given data set is 26.
What is the median?In statistics and probability theory, the median is the value separating the higher half from the lower half of a data sample, a population, or a probability distribution. For a data set, it may be thought of as "the middle" value.
Given the data set, we need to find the median.
So, let's arrange the numbers from smallest to largest in order to find the median.
\(\sf 15,20,22,26,28,35,36.\)
\(\text{Median}=\sf 26\)
Therefore, the median of the data set is 26.
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solve by substitution: 12=4x and y=8x
Answers
x=3
y=24
Whats the prime factorization of 9. Use exponents when appropriate and order the factors from least to greatest (for example, 2235).
Answers
Answer:
9 = 3 x 3
Explanation:
A bag contains 30 blue beads, 10 red beads, and 35 yellow beads.Julia pulls a bead out of the bag at random, puts it aside and then pulls another bead out of the bag at randorWhat is the probability that Julia will pull two red beads out of the bag?O 4/225O 3/185O 2/12502/111Previous
Answers
EXPLANATION
Let's see the facts:
Bag contains:
30 blue beads
10 red beads
35 yellow beads
A bead is randomly pulled out from the bag
The Probability equation is given by the following expression:
\(\text{Probability}=\frac{Number\text{ of favourable outcomes}}{\text{Total number of outcomes}}\)The content in the bag = 30 blue beads + 10 red beads + 35 yellow beads = 75 total beads
To pull a bead from the bag= 75 ways
To pull two red beads out of the bag = 10 ways
So, P(Red and Red) without replacement = 10/75 * 9/74 = 3/185
So, the answer is 3/185
Find the value of x. Polygon angle sums
Answers
Answer:
x = 50
Step-by-step explanation:
In a polygon, the angles add up to 360°:
x + 10 + 2x + 3x + x = 360
7x + 10 = 360
7x = 350
x = 50
Answer:
x = 50
Step-by-step explanation:
There are 4 angles, making it a Quadrilateral. A Quadrilateral has a ∑m∠ of 360°.
Set each angle equal to 360°:
2x + 3x + x + x + 10 = 360
Simplify. Combine like terms:
(2x + 3x + x + x) + 10 = 360
7x + 10 = 360
Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.
PEMDAS =
Parenthesis
Exponents
Roots
Multiplication
Division
Addition
Subtraction
First, subtract 10 from both sides:
7x + 10 (-10) = 360 (-10)
7x = 360 - 10
7x = 350
Next, divide 7 from both sides:
(7x)/7 = (350)/7
x = 350/7
x = 50
50 is your value for x.
~
Please help me asap with both I’ll mark you brainly
Answers
1. The scholar made a mistake in the last step
where he said x=3.5
\(0.5x = 7 \\ \frac{0.5x}{0.5} = \frac{7}{0.5} \\ x = 14\)
SCHOLA DIVIDED 7 BY 2 INSTEAD OF DIVIDING BY 0.5
2.TO CHECK IF 3 as a solution satisfies the equation I will first look in what the LHS is equal to by plugging in 3 in the place of n. SO THAT n=3 SATISFIES THE EQUATION LHS=RHS
\(lhs = - \frac{1}{2} (2(3) - 8) + 3 \\ lhs = - \frac{1}{2} (6 - 8) + 3 \\ lhs = - \frac{ 1}{2} ( - 2) + 3 \\ lhs = 1 + 3 \\ lhs = 4\)
Now I will check what The RHS IS EQUAL TO BY ALSO PLUGGING IN 3 IN THE PLACE OF n
\(rhs = \frac{1}{4} (8(3) - 4) - 1 \\ rhs = \frac{1}{4} (24 - 4) -1 \\ rhs = \frac{1}{4} (20) - 1 \\ rhs = 5 - 41\\ rhs = 4\)
FROM WHAT I FOUND LHS=RHS THIS MEANS THAT n=3 SATISFIES THE EQUATION BECAUSE IT IS BALANCED. WHAT IS ON THE LEFT HAND SIDE IS EQUAL WITH WHAT IS ON THE RIGHT HAND SIDE.
I HOPE THIS HELPS.
Calculate the equivalent ratio 1.25 : 3.75 : 7.5
Answers
The equivalent ratio of 1.25 : 3.75 : 7.5 is 5 : 15 : 30.
To calculate the equivalent ratio of 1.25 : 3.75 : 7.5, we need to find a common multiplier that can be applied to all the numbers in the ratio to make them whole numbers. In this case, the common multiplier is 4 because it can be multiplied to each number to eliminate the decimals.
By multiplying each number in the ratio by 4, we get:
1.25 * 4 = 5
3.75 * 4 = 15
7.5 * 4 = 30
So the equivalent ratio of 1.25 : 3.75 : 7.5 is 5 : 15 : 30.
This means that the relative sizes or quantities represented by the original ratio are maintained in the equivalent ratio. For example, if we had 1.25 units of something, it would be equivalent to 5 units in the new ratio, and if we had 7.5 units, it would be equivalent to 30 units in the new ratio.
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What is the GCF of 18 and 130?
2,
3,
5,
8,
13,
Answers
Answer:2 will be your Answer :)
Step-by-step explanation:
As you can see when you list out the factors of each number, 2 is the greatest number that 18 and 130 divides into.
The greatest common factor of 18 and 130 is 2, because 2 is the largest number that is divisible by both numbers