how much force in newtons is required to accelerate a 5 kg bowling ball at 2 m/s2?(1 point) responses 2.5 n 2.5 n 7 n 7 n 10 n 10 n 3 n

Answers

Answer 1

To accelerate a 5 kilogram bowling ball at 2 m/s2, 10N of force is needed.

How do you determine force?

Newton's second principle of motion provides the definition of the force formula: An object's force is equal to its mass times its acceleration. F = m ⨉ a. To use this method, you must use SI units for force (newtons), mass (kilograms), and acceleration (meters per second squared).

What two categories of forces exist?

Contact forces and function at a distance forces are the two different types of forces. Your daily use of force is evident. Basically, push and pull are forces. You exert force on an item when you push against it or pull against it.

Briefing:

To calculate F = ma,

multiply 5 kg by 2 m/s2.

which gives you 10N.

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Related Questions

Explain how to identify a starting position
on a line.

Answers

Answer:

We can easily find out the beginning point of the line by using dot representation. When it comes to position vector, it expresses the exact position of certain object from the starting point of the coordinate system. The vector is a straight line that has a certain end which is fixed to its body

Answer:

Displacement is defined as the distance, in any direction, of an object relative to the position of another object. Physicists use the concept of a position vector as a graphical tool to visualize displacements. A position vector expresses the position of an object from the origin of a coordinate system

Explanation:

G 13% part (g) using the numbers from the previous step, give a numeric answer for the time in seconds that elapse when the package, initially at rest, travels a distance of 2. 25 m down the ramp

Answers

The time required for the container to move 2.25 metres down the ramp is roughly 0.104 seconds.

From part (f), we have determined the final velocity of the package to be 1.38 m/s. Using this value along with the distance traveled (Δx = 2.25 m), we can calculate the time elapsed using the kinematic equation:

Δx = (vf² - vi²) / 2a

Substituting the values, we get:

2.25 = (1.38² - 0) / (2 * 0.087)

Solving for time (t), we get:

t = 2.25 * 0.087 / 1.897

t ≈ 0.104 seconds

Therefore, the time elapsed when the package travels a distance of 2.25 m down the ramp is approximately 0.104 seconds.

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A satellite's speed is 3,684 m/s. After 3 minute(s), it is 9,567 m/s. What is the satellite's
acceleration in m/s2?
Round your answer tot he nearest tenth.

Answers

Explanation:

acceleration=change in velocity /time in seconds

=(9567-3684)/(3 × 60)

= 5883/180

= 32.7m/s^2

Help!! I will mark brainliest!! Worth 50 pts!

If 50.0 calories of heat energy are added to 120 grams of copper currently at room temperature (20°C), what will the change in temperature be?

24.6°C
30 °C
4.6°C
20°C

Answers

The change in temperature of the copper is 4.6 ⁰C.

What is heat capacity?

The heat capacity of an object is the total quantity of heat needed to raise the entire mass of a substance by 1 kelvin.

Mathematically, heat capacity is given as;

Q = mcΔθ

where;

Q is the quantity of heat in the material = 50 calories c is the specific heat capacity of copper = 0.09 cal/gcΔθis change in temperature

Δθ = Q/mc

Δθ = (50) / (120 x 0.09)

Δθ = 4.6 ⁰C

Thus, the change in temperature of the copper at the room temperature is determined from the heat capacity of copper.

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Why are there only two elements in the first period of the periodic table?(1 point)

because the first two elements both start with H and are grouped together

because the next elements have other things in common and they need to be arranged together

because only two electrons can fit in the first orbit around the nucleus, and each period on the table is organized by number of orbits

because each row increases in atomic mass by a specific number, so anything over five is in the second row

Answers

Answer:

because each row increases in atomic mass by a specific number, so anything over five is in the second row.

HELP ASPP PLEASE Thank you

HELP ASPP PLEASE Thank you

Answers

The 6.3 g/cm³ is the density of the iron.

What is density ?
volumetric
unit of mass of a substance. M represents for mass, and V for volume, and density is defined as d = M/V. Grams per cubic centimeter is the most widely used unit of density.

What is mass ?

Measurement of the attribute of substance often known as inertia. Fundamentally, a body of matter is defined by the resistance it provides to a force-induced change in its speed or location.

Therefore, 6.3 g/cm³ is the density of the iron.

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you don't have to work anything out PLEASE JUST READ IT​

you don't have to work anything out PLEASE JUST READ IT

Answers

Answer:

I think it's D

Explanation:

I don't know I just think

A very long, straight wire carries a current of 26 A in the direction. An electron 1.3 cm from the center of the wire in the direction is moving with a speed of 4.77 x 10 m/s. Find the force on the electron when it moves in the following directions. directly away from the wire Nie 2) NJ 3) NA * parallel to the wire in the direction of the current Ni 5) Nj Nk perpendicular to the wire and tangent to a circle around the wire in the +] direction

Answers

The force is acting in the +K direction since it is perpendicular to both the velocity and the magnetic field. Force on electron = 3.08 x 10⁻¹⁷ N

Current I = 26 A

Electron velocity V = 4.77 x 10 m/s

Distance r = 1.3 cm

= 1.3 x 10⁻² m 1.

Find the magnetic field:

Formula used to calculate magnetic field is:

B= μ0×I2πr

Where, μ0 = 4π×10⁻⁷B

= μ0×I2πrB

= 4π×10⁻⁷×26 2π×1.3×10⁻²B

= 2.02 × 10^-5 T2.

Find the force acting on the electron, when it moves in the direction directly away from the wire:

Formula to calculate force on electron is:

F= qVBsinθ

Where,F = Force acting on electron

V = Velocity of electron

B = Magnetic field

q = charge of an electron

θ = Angle between the direction of motion of an electron and direction of the magnetic field that, the electron is moving in a direction directly away from the wire, so it is moving perpendicular to the wire.

Therefore, θ = 90 degrees.

So the force can be calculated as:

F= qVB sin 90

F= qVB

Therefore,F = 1.6×10⁻¹⁹×4.77×10×2.02 × 10⁻⁵

F = 3.08 x 10⁻¹⁷ N3.

Find the force acting on the electron, when it moves in the direction parallel to the wire in the direction of the current:

the electron is moving parallel to the wire, so the angle between the direction of motion of the electron and direction of the magnetic field is 0 degrees.

So the force can be calculated as:

F= qVBsinθ

F = 0N₄.

Find the force acting on the electron, when it moves in the direction perpendicular to the wire and tangent to a circle around the wire in the +J direction:

Here, the angle between the direction of motion of the electron and direction of the magnetic field is 90 degrees.

So,θ = 90 degrees

Therefore, the force on the electron can be calculated as:

F= qVB sin 90

F= qVB

Therefore,F = 1.6×10⁻¹⁹ ×4.77×10×2.02 × 10⁻⁵ F

= 3.08 x 10⁻¹⁷ N

The force is acting in the +K direction since it is perpendicular to both the velocity and the magnetic field.

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Explain the sign conventions for heat and work, and why expansion is a positive work and compression a negative work.

Answers

In thermodynamics, heat and work are two ways in which energy can be transferred into or out of a system. The sign convention for heat and work is crucial in thermodynamics calculations.

When supplied to the system, heat is represented by the letter Q, which has a positive sign, and when released, a negative sign.

W stands for work, and it has a positive sign when the system performs work on the environment, and a negative sign when the environment performs work on the system.

Expansion work is the effort put forth by a system when it expands under a continuous external pressure.

A system's work when it grows is beneficial because energy is transmitted from the system to the surrounds and the system is working on its surroundings.

Contrarily, when the system is compressed, the environment works on it and energy is transferred from the environment to the system.

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A ray of sunlight forms a 24°-angle with the ground. what is the length of the shadow cast by a person 1.82 m tall?

Answers

The length of the shadow cast by a person who is 1.82 m tall when a ray of sunlight forms a 24° angle with the ground is approximately 4.09 meters.

To solve this problem, we'll use trigonometry with the given angle and the height of the person to find the length of the shadow. We know that the angle between the sunlight and the ground is 24°, and the person is 1.82 m tall.

We can model this situation using a right triangle, where the person's height represents the opposite side, the length of the shadow represents the adjacent side, and the angle of elevation is 24°. To find the length of the shadow, we can use the tangent function, which is defined as the ratio of the opposite side to the adjacent side in a right triangle.

So, we have:

tan(24°) = opposite side (height of the person) / adjacent side (length of the shadow)

Now, we can plug in the height of the person:

tan(24°) = 1.82 m / length of the shadow

To find the length of the shadow, we can rearrange the equation and solve for it:

Length of the shadow = 1.82 m / tan(24°)

Using a calculator, we find that:

Length of the shadow ≈ 1.82 m / 0.4452 ≈ 4.09 m

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What is missing from this graph?

(A) A title.
(B) Axis labels.
(C) A trendline.

What is missing from this graph?(A) A title.(B) Axis labels.(C) A trendline.

Answers

We have that what  missing from this graph is

Axis labels.

Correct option is B

Generally

It is important to note that a graph is incomplete with out labeling its  axis to show clarification

The Graph above  has

a title as"Number of sunspots each year"

and obvious trend lines

Therefore

Axis labels.

Correct option is B

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Answer:

It's axis labels

Explanation:

I took the test :D

A horizontal net force is exerted on a 2.0 kg object at rest. The object starts at x=0 m and travels 8.0 m along a horizontal frictionless surface.
What is the velocity of the object
Round answer to 2 significant digits
____ m/s

A horizontal net force is exerted on a 2.0 kg object at rest. The object starts at x=0 m and travels

Answers

There's a constant force of 35 N exerted on the object of mass 2.0 kg, so it undergoes an acceleration a of

35 N = (2.0 kg) a   →   a = 17.5 m/s²

The object travels 8.0 m, so that it attains a velocity v of

v ² = 2 (17.5 m/s²) (8.0 m)   →   v ≈ 16.73 m/s ≈ 17 m/s

The velocity of the 2 Kg object which travels 8 m along the horizontal frictionless surface is 17 m/s

How to determine the acceleration Force (F) = 35 NMass (m) = 2 KgAcceleration (a) =?

a = F / m

a = 35 / 2

a = 17.5 m/s²

How to determine the velocity Initial velocity (u) = 0 m/sDistance (s) = 8 mAcceleration (a) = 17.5 m/s²Final velocity (v) =?

v² = u² + 2as

v² = 0² + (2 × 17.5 × 8)

v² = 280

Take the square root of both side

v = √280

v = 17 m/s

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A basketball, a pool cue ball, and a golf ball all fall down in the absence
of air resistance. Which of the following is true about their
acceleration?

Answers

The acceleration of all objects increases when there is no air resistance because air resistance slow down the speed of an object.

What is acceleration?

The rate of change in velocity over time is known as acceleration. Velocity is the speed of an object in a specific direction. Acceleration occurs when change occurs in velocity.

So we can conclude that the acceleration of all objects increases when there is no air resistance because air resistance slow down the speed of an object.

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I have no idea what the answer is for this but can someone help?

I have no idea what the answer is for this but can someone help?

Answers

Answer:

Soft serve ice cream

Explanation:

1g fat = 9 calories

take the fat numbers for each option and multiple by 9 and see who gives you 101

vanilla ice cream = 11.2 x 9 = 100.8 rounded to 101

frozen yogurt = 4 x 9 = 36

French fries = 24.7 x 9 = 222.3

pretzels = 1 x 9 = 9

60x / 125 Oiltis 20 / 01 / EN285 An Olympus objective lens is given below. Assume GFP is used in the sample and its spectra are the same as in the graph. 1) Calculate the resolution of the microscope. 2) Assume a microtubule filament of 50nm (width) x 1000nm (length) is imaged by the objective lens. What is the size of the image? If the camera pixel size is 10um, what is the size of the image in unit of pixel #s? 1.0 or 0.8 Fluorophore Excitation and Emission Spectra Steep Peak Spectral Excitation Tails Spectrum Maximum Wavelength Emission Spectrum Symmetrical Spectral Profiles FWHM Sloped Excitation Sloped Tail Emission Tail 0.6 Normalized Excitation and Emission 0.4 0.2 150 nm Spectral Width 0.0 400 450 500 550 Wavelength (Nanometers) 600 650 Figure 2 JAPAN UplanFLN

Answers

The size of the image in terms of pixel numbers which is about 27.4 pixels (1000nm / 36.5nm per pixel).

To calculate the resolution of the microscope, we need to use the formula: Resolution = 0.61 x λ / NA, where λ is the wavelength of light and NA is the numerical aperture of the objective lens. Looking at the given information, we see that the microscope objective is an Olympus UplanFLN with a numerical aperture of 1.0 and we are using GFP, which has a wavelength of around 488nm. Plugging these values into the formula, we get a resolution of about 274nm.

Now, to find the size of the image of the microtubule filament, we can use the formula: Size of image = Actual size x Magnification. The magnification of the microscope is not given, so we cannot solve this directly. However, we are given the pixel size of the camera which is 10um. We can assume that each pixel corresponds to a certain magnification factor, which we can calculate by dividing the pixel size by the resolution we just found. This gives us a magnification factor of about 36.5x. Using this factor, we can calculate the size of the image in terms of pixel numbers which is about 27.4 pixels (1000nm / 36.5nm per pixel).

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How do you identify conjunctive adverbs in a sentence?.

Answers

Subjunctive adverbs can be followed by a semicolon or period usually followed by a comma.

Adverb Conjunctions also called conjunctive adverbs to join two complete thoughts together like conjunctions. Use the second sentence to modify the first sentence like an adverb. Subjunctive adverbs can be followed by a semicolon or period, usually followed by a comma.

Conjunctive adverbs are a special type of adverb used to connect independent clauses together. While most adverbs are used to modify verbs adjectives or other adverbs subjunctive adverbs are used as conjunctions to connect one sentence to another. Indicates a connection between two separate statements within a sentence. Organize your ideas into two or more sentences. Show the relationships between ideas in stand-alone sentences.

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If you changed the surface of the incline the car is rolling down, how might that impact the distance and speed the car travels? Explain your answer using Newton's Laws.

Answers

Explanation: As the angle is increased the acceleration of the object is increased as the angle increases the component of the force parallel to the incline increases and the component of forced perpendicular to the inclined decreases it is the parallel component of the weight vector that causes the acceleration.

A piano string having a mass per unit length equal to 4.50 10-3 kg/m is under a tension of 1 300 N. Find the speed with which a wave travels on this string.

Answers

The speed with which a wave travels on this piano string is approximately 537.3 m/s.

To find the speed with which a wave travels on the piano string, we can use the equation:

v = √(T/μ)

where v is the speed of the wave, T is the tension in the string, and μ is the mass per unit length of the string.

Plugging in the values given, we get:

v = √(1300 N / 4.50 10-3 kg/m)

Simplifying this expression, we get:

$v = \sqrt{2.89 \times 10^5 \text{ m}^2/\text{s}^2}$

Evaluating this expression, we get:

v = 537.3 m/s

Therefore, the speed with which a wave travels on this piano string is approximately 537.3 m/s.


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If a person ran 400 meters at average speed of 10 meters per second, what would his / her time be?

Answers

Like the rate? Of how fast she can go?

8. You are heating a substance in a test tube. Always point the open end of the ne
a. Toward yourself
b. Toward your lab partner
C. Toward another classmate
d. Away from all people

Answers

Answer:

b ok bye thansks

bye.

Always point the open end of a test tube being heated d. Away from all people.

When heating a substance in a lab, there is a chance that the substance could react to the heat and evaporate into a gaseous state.

This could be very dangerous if the gas is:

corrosivea pollutant biological breathing hazard

You should therefore be careful to point the tube away from others and yourself so that the gas does not affect either them or you.

In conclusion therefore, always point the open end of the tube away from all people.

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8. You are heating a substance in a test tube. Always point the open end of the nea. Toward yourselfb.

what is the two example of velocity​

Answers

A train moves at a high velocity. Velocity is the rate of motion, speed or action. An example of velocity is a car driving at 75 miles per hour. "Velocity."

What is the function of the endoplasmic reticulum?

Answers

Answer:

packages proteins

Explanation:

Answer:

The endoplasmic reticulum ( ER) plays a key role in the modification of proteins and the synthesis of lipids. It consists of a network of membranous tubules and flattened sacs. The discs and tubules of the ER are hollow, and the space inside is called the lumen....

A student stands in a school hallway. A wall separates a classroom from
the student. The student in the hallway cannot see inside the classroom
but hears noises from within the classroom. Which of these best explains
why the student hears the noises but cannot see into the classroom?

Answers

Answer: sound waves are transmitted through the wall and visible light waves are reflected by the wall.

Please help me with the blanks

Please help me with the blanks

Answers

... all forms of electromagnetic radiation
Also:
... particles, including alpha particles and neutrinos.

What is the energy of a radio photon from an AM radio station that broadcasts at 1297.7 kilohertz? Hint: Review Mathematical Insight 5.1. Answer: Choose... Check What is the wavelength of a radio wave from an AM radio station that broadcasts at 1297.7 kilohertz?

Answers

The wavelength of a radio wave from an AM radio station that broadcasts at 1297.7 kilohertz is approximately 230.7 meters.

The energy of a single photon of this radio wave can be calculated using the formula E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength. Therefore, the energy of a photon from this radio wave is approximately 8.55 x 10^-31 joules.

Radio waves are a type of electromagnetic radiation, which can be characterized by their wavelength and frequency. In this case, the frequency of the radio wave is given as 1297.7 kilohertz.

To calculate the wavelength, we can use the formula λ = c/f, where c is the speed of light and f is the frequency. Plugging in the values, we get λ ≈ 230.7 meters.

The energy of a single photon of this radio wave can be calculated using the formula E = hc/λ, where h is Planck's constant (6.626 x 10^-34 joule-seconds), c is the speed of light (3 x 10^8 meters per second), and λ is the wavelength.

Plugging in the values, we get E ≈ 8.55 x 10^-31 joules. This is an extremely small amount of energy, but it is enough to create a detectable signal in a radio receiver.

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These are the reactant in a chemical equation: 6 CO2 + 6 H2O --> C6H12O6 + 6 O2

Answers

Answer:

Carbon Dioxide and Water.

Explanation:

This is the chemical formula for photosynthesis!

Will mark brainiest!!!

1. A __ is caused by a sudden shift in the ocean crust which displaces the water. *

2. A tsunamis is possible, but unlikely at a __ plate boundary where two plates are moving sideways past each other. *

3. A Shallow __ is a good indicator of tsunamis, but sends data very slowly and cannot detect earthquakes. *

4. Tsunamis are common at __ plate boundaries, since large earthquakes release the built up pressure, resulting in a quick vertical movement of the plate. *

5. The Indonesian Earthquake of 2004 had a 9.1__, which was the third largest ever recorded in human history. *

All possible answers:
A. Earthquake
B. Tsunami
C. Magnitude
D. Sensor
E. Transform
F. Convergent
G. Divergent

Answers

Answer:

1. Tsunami

2.Divergent

3.Sensor

4.Convergent

5.Magnitude

Explanation:

imagine you are outside enjoying the warm sunshine with friends. as you briefly glance up at the sun, the part of the sun that you can see directly is called its:

Answers

photosphere

bc it is





The angular resolution of a radio wave telescope decreases with
decrease disc size. true or false

Answers

The angular resolution of a radio wave telescope decreases with decreased disc size which is false.

The angular resolution of a radio wave telescope actually increases with a decrease in dish size. Angular resolution refers to the ability of a telescope to distinguish between two closely spaced objects in the sky. It is determined by the size of the telescope's aperture or dish.

In general, the larger the aperture or dish size of a telescope, the better its angular resolution. A larger dish collects more incoming radio waves, allowing for finer details to be resolved. Smaller dishes, on the other hand, have limited collecting area and, therefore, lower angular resolution. This is why larger radio telescopes are often preferred for high-resolution observations.

So, to achieve better angular resolution, one would typically need a larger dish size for a radio wave telescope.

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a 3 m long ladder leans against a frictionless wall at an angle of 60 degrees what is the minimum value of the coefficinet of static friction twith the ground that prevents the ladder from slipping

Answers

For a 3 m long ladder leaning against a frictionless wall, the minimum value of the coefficient of static friction is mathematically given as

mu=0.2886

What is the minimum value of the coefficient of static friction with the ground that prevents the ladder from slipping?

Generally, the equation for the Force  is mathematically given as\(-\mu N_{1}+N_{2}=0\)

Therefore

\(\mu=\frac{1}{2}tan\theta\)

\(\mu=\frac{1}{2}tan30^{0}\)

mu=0.2886

In conclusion, the minimum value of the coefficient of static friction

mu=0.2886

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