how much energy must a 12 v car battery expend in moving 8.93 x 1020 electrons from its positive terminal to its negative terminal?

Answers

Answer 1

14.30 J of energy required  in moving 8.93 x 1020 electrons from its positive terminal to its negative terminal

The electric potential difference between points A and B, VB − VA is defined to be the change in potential energy of a charge q moved from A to B, divided by the charge. Units of potential difference are joules per coulomb, given the name volt (V) after Alessandro Volta.

Calculating the work directly is generally difficult, since W=Fdcosθ and the direction and magnitude of F can be complex for multiple charges, for odd-shaped objects, and along arbitrary paths. But we do know that, since F=qE, the work, and hence ΔPE, is proportional to the test charge q To have a physical quantity that is independent of test charge, we define electric potential V (or simply potential, since electric is understood) to be the potential energy per unit charge:

8.93 *1020 electrons has a charge of (8.93× 1020×1.6020×10⁻¹⁹) coulombs

The change in potential energy is ΔU=qΔV

=( 8.93× 1020×1.6020×10⁻¹⁹C)(12 V)

=    14.30 j

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Related Questions

Population growth is limited by density-dependent factor such as____

Answers

Answer:

predation, water supply, parasitism, migration, diseases, waste accumulation, food availability, and competition.

Explanation:

A population can be defined as the total number of living organisms living together in a particular place and sharing certain characteristics in common.

Population regulation can be defined as a biological process that balances limiting factors affecting the growth of a population based on density.

Basically, the factors that regulate the growth of a population are divided into two (2) main categories and these includes;

I. Density-independent factors.

II. Density-dependent factors.

Density-dependent are regulating factors such as predation, diseases, and competition that affect the size of the population of living organisms through decreasing or increasing mortality and birth rate.

This ultimately implies that, population growth is limited by density-dependent factors such as predation, parasitism, migration, diseases, waste accumulation, food availability, water supply, and competition within the population.

A) Is it possible for an object that, object with zero acceleration have velocity? If yes give an example if not give its proof.

Answers

Answer:

Yes, in case of uniform velocity

Explanation:

This is the case of uniform velocity. If a body covers equal displacement in equal intervals of time, then the velocity of a body is said to be ‘Uniform Velocity’. It meas that the velocity of a body remains constant during the motion and it does not change.

Since, acceleration is defined as the rate of change of velocity.

Therefore, if there is no change in velocity or in other words the change in velocity is zero, then the acceleration is also zero.

a = ΔV/t = 0/t

a = 0 m/s²

So, the acceleration of the body is 0 m/s², but it has a uniform velocity

Hence, it is possible for an object that, object with zero acceleration have velocity, which is the case case of uniform velocity.

Hi I need help with this question (see image ). ​

Hi I need help with this question (see image ).

Answers

Explanation:

a) Fixed points are the temperatures at which a thermometer is calibrated. They can refer either to the actual temperatures used for calibration, or the thermometer readings at those temperatures.

__

b) Fundamental interval is the difference between the fixed points. As with fixed points, it can refer either to the difference in actual temperature, or the difference in the corresponding thermometer readings.

Describe an object's velocity when an acceleration-time graph is zero?

Answers

Anything times zero is zero

A box at rest is in a state of equilibrium half way up on a ramp. The ramp has an incline of 42°. What is the force of static friction acting on the box if box has a gravitational force of 112. 1 N ? 70 N 80 N 75 N 85 N.

Answers

The magnitude of the force of static friction acting on the box is 75 N. Option D is correct.

What is static friction?

It is the frictional force between the two solid objects that are attached to each other.

It can be given by

\(F_s = mg \rm \ sin \theta\)

Where,

\(F_s\) - static friction

\(mg\) - gravitational force =  112. 1 N

\(\theta\) - inclined angle  = 42°

Put the values in the formula,

Fs = 112.1   x   sin42°

Fs = 75 N

Therefore, the magnitude of the force of static friction acting on the box is 75 N.

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mechanism of flow of current in a conductor

Answers

Your mom is the answer because I said that your mom is the answer. Now give me my points

Answer:

The mass of earth 6*10^24kg and radius is 400kg Now find the value of acceleration due to gravity when a object is 3600km from the earth surface

An object has Ep of 220 J after being lifted to a height of 8 m. What is the object's mass?
3.73 kg
5.23 kg
1.67 kg
2.81 kg​

Answers

3.73 is the answer I believe so

calculate the magnitude of the magnetic field at a point 53.5 cm from a long, thin conductor carrying a current of 4.95 a. t

Answers

To calculate the magnitude of the magnetic field at a point 53.5 cm from a long, thin conductor carrying a current of 4.95 A, we can use the formula:

B = (μ₀ * I) / (2π * r)

To calculate the magnitude of the magnetic field at a point 53.5 cm from a long, thin conductor carrying a current of 4.95 A, you can use the Biot-Savart Law formula:

B = (μ₀ * I) / (2 * π * r)

Where:
- B is the magnitude of the magnetic field
- μ₀ is the permeability of free space (4π x 10^-7 T·m/A)
- I is the current in the conductor (4.95 A)
- r is the distance from the conductor (0.535 m, since you need to convert from cm to meters)

Now, let's substitute the values into the formula:

B = (4π x 10^-7 T·m/A * 4.95 A) / (2 * π * 0.535 m)

B = (6.28 x 10^-6 T·m * 4.95 A) / (1.07 m)

B = (3.1086 x 10^-5 T·m) / (1.07 m)

B = 2.905 T·m / m

B ≈ 2.9 x 10^-5 T

So, the magnitude of the magnetic field at a point 53.5 cm from the conductor is approximately 2.9 x 10^-5 T (teslas).

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in the phoenix area, electricity rates rabge from 8 cents per kilowatt-hour (winter) to 11.5 cents per kwh (summer). how much does the energy cost each month to run the refridgerator

Answers

The monthly energy cost to run the refrigerator is approximately $7.02.

To determine the monthly energy cost to run a refrigerator, we need to know the power consumption of the refrigerator and the number of hours it operates per month.

The power consumption of the refrigerator is usually stated in watts (W). If you know the power consumption in watts, you can convert it to kilowatts (kW) by dividing by 1000.

Let's assume the power consumption of the refrigerator is 100 watts (0.1 kW), and it operates for an average of 24 hours per day. In a month, there are typically 30 days.

To calculate the energy consumption in kilowatt-hours (kWh) per month, multiply the power consumption in kilowatts by the number of hours of operation per month:

Energy consumption = Power consumption (kW) x Operating hours per month

Energy consumption = 0.1 kW x 24 hours/day x 30 days

Energy consumption = 72 kWh

Now, we can calculate the cost of energy for running the refrigerator. Since electricity rates range from 8 cents/kWh (winter) to 11.5 cents/kWh (summer), we'll use an average rate of 9.75 cents/kWh for this calculation.

Monthly cost = Energy consumption (kWh) x Electricity rate (cents/kWh)

Monthly cost = 72 kWh x 9.75 cents/kWh

Monthly cost ≈ $7.02

Therefore, the monthly energy cost to run the refrigerator is approximately $7.02.

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when a star exhausts its core fusion fuel so that the core begins to contract, which of the following can stop the contraction?

Answers

The correct answer is degeneration pressure.

The final cycle of a main-sequence star depends greatly on its mass and that produces energy when the hydrogen ran out.

For this case, let's take our sun for example. In billion of years, after the hydrogen is depleted, gravity will take over and start compressing the star, increasing the temperature to levels where the core can now fuse helium into carbon, this process will heat the star again, and the outer layers of hydrogen that remained during the main sequence, will be hot enough to reignite the fusion due to the energy.

The sun will produce several times more energy than when it was in the main-sequence, and it will continue to expand, it will shallow mercury, Venus, the earth itself and perhaps mars until it finally burns the remaining hydrogen. When there is no more fuel to power up the star, it will start to collapse itself, and shrink until it becomes a white dwarf, the last phase of the star.

Therefore, the degeneration pressure is used to suppress the energy of the star and when a star exhausts its core fusion fuel so that the core begins to contract, it helps to stop the contraction.

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find ways you can change the total energy

Answers

Either make the hill taller to increase it or make the kill lower to decrease the total energy

Answer:

The ways to change the total energy are to either make the hill taller to increase it or make the hill lower to decrease the total energy.

Explanation:

The total mechanical energy of a system is the sum of the total kinetic energy and total potential energy.

Sakurai - Advanced Quantum Mechanics
3-11. Discuss how the numbers of nodes of the radial functions G(r) and F(r) of the hydrogen atom are related to the quantum numbers n, j, and I.

Answers

In quantum mechanics, the numbers of nodes of the radial functions G(r) and F(r) of the hydrogen atom are related to the quantum numbers n, j, and l.

The number of nodes for a function is defined as the number of points at which the function equals zero.There are a few different radial functions in hydrogen that we need to consider.

These include G(r), the radial part of the wave function for the 1s state, and F(r), the radial part of the wave function for the 2s or 2p states. Here's how the nodes of these functions are related to the quantum numbers:n: The principal quantum number, which specifies the energy level of the electron.

It determines the number of nodes in both G(r) and F(r). Specifically, G(r) has n-1 nodes and F(r) has n-2 nodes. This is because the energy level of the electron determines the size of the wave function, and nodes occur where the wave function crosses zero.j: The total angular momentum quantum number, which determines the shape of the wave function. It does not affect the number of nodes in either G(r) or F(r).

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What units would you use to measure a virus (nanometers micrometers millimeters)

Answers

nanometers

to measure a virus you use nanometers

In basin and range topography, the lowest areas are frequently occupied by a(n) ________.

Answers

In basin and range topography, the lowest areas are frequently occupied by a(n)  basin.

Basin and range topography is a geological feature characterized by alternating mountain ranges and elongated valleys or basins. The formation of this topography is attributed to the stretching and faulting of the Earth's crust, which leads to the uplift of mountains and the subsidence of adjacent basins.

The lowest areas in this type of topography are often occupied by basins, which are elongated depressions or low-lying regions. These basins typically collect sediment and water, forming flat or gently sloping landscapes. They can range in size from small valleys to extensive lowland areas.

The basins are important features of the basin and range topography and contribute to the unique landscape and hydrological characteristics of the region.

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How do you solve for ΜK?How do you solve for ΜK?

μ k = f k N = f k w cos 25 ° = f k m g cos 25 °. Substituting known values on the right-hand side of the equation, μ k = 45. 0 N ( 62 kg ) ( 9. 80 m/s 2 ) ( 0. 906 ) = 0. 82

Answers

the solution is μk = 0.82.

Given that:μk = f_k /N = f_k w cos25° = f_k m g cos25°

μk can be solved using the formula above;

Substituting known values on the right-hand side of the equation,

μk = 45.0 N (62 kg) (9.80 m/s²) (0.906)

μk = 0.82

Therefore, the solution is μk = 0.82.

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10. A balloon is filled with helium (density =0.178 kg/m3) to a volume that has a radius of 1.50 m and is then connected to a string as shown in the figure. If the mass of the skin of the balloon is 2.00 kg, determine the tension in the string when the balloon is at equilibrium. The density of air is 1.28 kg/m 4
.

Answers

A balloon is filled with helium (density =0.178 kg/m3) to a volume that has a radius of 1.50 m and is then connected to a string as shown in the figure. the weight of the balloon is (m_balloon - m_skin) * 9.8 N.

To determine the tension in the string when the balloon is at equilibrium, we need to consider the forces acting on the balloon.

1. Weight of the balloon: The weight of the balloon is given by the product of its mass and the acceleration due to gravity (9.8 m/s^2). The mass of the balloon can be calculated by subtracting the mass of the skin from the total mass of the balloon. So, the weight of the balloon is (m_balloon - m_skin) * 9.8 N.

2. Buoyant force: The buoyant force acting on the balloon is equal to the weight of the displaced air. The volume of the balloon can be calculated using the formula V = (4/3) * π * r^3, where r is the radius. The weight of the displaced air is given by the product of the density of air, the volume of the balloon, and the acceleration due to gravity. So, the buoyant force is ρ_air * V * g.

At equilibrium, the tension in the string is equal to the sum of the weight of the balloon and the buoyant force: Tension = (m_balloon - m_skin) * g + ρ_air * V * g.

Substituting the given values, we have Tension = (m_balloon - m_skin) * 9.8 + 1.28 * V * 9.8.

Now, let's calculate the volume of the balloon using the given radius. V = (4/3) * π * (1.50)^3 = 14.14 m^3.

Substituting the known values into the equation, we get Tension = (m_balloon - m_skin) * 9.8 + 1.28 * 14.14 * 9.8.

Given that the mass of the skin is 2.00 kg and the density of the balloon is 0.178 kg/m^3, we can calculate the mass of the balloon as follows: m_balloon = V * density = 14.14 * 0.178 = 2.52 kg.

Substituting this value, we have Tension = (2.52 - 2.00) * 9.8 + 1.28 * 14.14 * 9.8.

After evaluating this expression, the tension in the string when the balloon is at equilibrium is determined.

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Michael Jordan's vertical leap is reported to be 48 inches (1.22m). What is his take off speed?

Answers

Jordan's take-off speed is 4.9 ms.

Key Accomplishments Too many to list. See the link below. Bottom line Jordan's incredible 4-foot vertical jump puts the top of his head 6 inches above the edge and the soles of his feet higher than any of his other NBA cleats. rice field. I also ran 4.3 Forty. Don't let anyone tell you that someone was a better athlete than you are. MJ was not only a great goalscorer back then, but he was also a high-flying dunker.

He has only one player in NBA history called his Airness and that is Michael He Jordan. He currently owns his NBA vertical jump of 48 inches, the highest in the entire tournament. That number comes with a hang time on the edge of 0.92 seconds. The 30th-40th percentile is 15-16 inches. Above-average vertical jump, values ​​are in the 60th and 70th percentiles and range from 18 to 19 inches. A good rating is 20-21 inches, which corresponds to the 80-90th percentile.

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How do you find the average speed of three speeds?

Answers

Answer:

Assess what information you are given. Use this method if you know:

the total distance covered by one person or vehicle; and

the total time it took that person or vehicle to cover the distance.

Explanation:

Hope this helps! I might be wrong, so tell me if I am

Answer:

Average speed can be calculated by dividing the total distance the object travels by the total amount of time it takes to travel that distance.

Explanation:

This is as much as I can help you, i don't know much else on how to do that ;w; sorry

why is the wave nature of matter not important for a baseball?

Answers

The mass of a baseball is too large to exhibit wave-like behavior, making the wave nature of matter insignificant.

The wave nature of matter is not important for a baseball because the mass of a baseball is too large to exhibit wave-like behavior.

According to the de Broglie equation, the wavelength of an object is inversely proportional to its mass. Since a baseball has a large mass, its wavelength is incredibly small and insignificant.

Additionally, wave-like behavior is only observable on the atomic and subatomic level, where particles have incredibly small masses.

Therefore, for macroscopic objects like a baseball, classical mechanics is a more appropriate way to describe its motion, and the wave nature of matter can be ignored.

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A simple machine where an inclined plane is wrapped in a spiral is called a centripetal ramp.

T.
True
F.
False

Answers

Answer: False

Explanation:

determine the rms current, the average power dissipated by the resistor, and the maximu voltage of the capacitor

Answers

The RMS current , Power and Maximum voltage have values 0 to 1 , V1/2 to 0 and infinity to zero.

The triangle's vertical side will be significantly longer than its horizontal side if reactance dominates a circuit, and will be close to 90° as a result. This is in line with what is understood about purely reactive circuits, which produce a 90° phase difference between voltage and current.The horizontal side will be much longer than the vertical side if resistance dominates the circuit. In light of this, the value of will be very small, just as there is very little phase shift between voltage and current in a nearly entirely resistive circuit.As cosx varies from 1 to zero (corresponding to that varies from 0° to 90° or -90°), average power varies from (VI)/2 to zero.Therefore, it should come as no surprise that the cosine of —whether you choose to refer to as the impedance angle, the angle between active power and complex power, or the phase difference between voltage and current—is referred to as the power factor. To calculate the average power lost by a circuit, multiply the power factor by (VI)/2. A power factor that is closer to zero indicates that reactive power makes up a larger portion of the circuit's total power.

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Please help!! This is the last question and i’m unsure! I will mark brainliest! Please try to provide a explanation you don’t have to but atleast a short one

Please help!! This is the last question and im unsure! I will mark brainliest! Please try to provide

Answers

Answer:

True

Explanation:

As of Newton's law, yes. Because when I land my feet on the ground, I apply a force. As per Newton's third law, the ground must apply the same force on me.

If its correct, may I hv brainliest?

A 3-ton Toyota land cruiser travelled at a speed of 45m/s, collides with a 2- ton comfort taxi which was parked in front of the traffic lights intersection. After the collision, both cars lock together and move off in one direction. Determine the speed of cars after collision.

Answers

Answer:

v = 27 m/s

Explanation:

To find the speed of cars after the collision  you take into account the momentum conservation law. Total momentum of both cars before the collision must be equal to the total momentum of both cars after the collision.

After the collision both cars traveled together, then you have:

\(m_1v_1+m_2v_2=(m_1+m_2)v\)   (1)

m1: mass of the Toyota = 3-ton = 3000 kg

m2: mass of the taxi = 2-ton = 2000kg

v1: speed of the Toyota before the collision = 45m/s

v2: speed of the car before the collision = 0 m/s (it is  at rest)

v: speed of both cars after the collision = ?

You solve the equation (1) for v:

\(v=\frac{m_1v_1+m_2v_2}{m_1+m_2}\)

Next, you replace the values of the rest of the variables:

\(v=\frac{(3000kg)(45m/s)+0kgm/s}{3000kg+2000kg}=27\frac{m}{s}\)

hence, just after the collision both cars have a speed of 27m/s

4. A hockey puck with a momentum of -17 kg x m/s when it
collides with a hockey stick moving at 54 kg x m/s on ice.
Once the objects collide, the hockey puck has a momentum
of 35 kg x m/s, what must the momentum of the hockey
stick be?

Answers

Answer:

-2 kg x m/s

Explanation:

-17 + 54 = 35 + x

x = -2

The goal of this experiment was to answer the question, "How does diffraction occur?" Suppose you formulated this alternate hypothesis: If the gap width is increased while keeping wavelength constant, then the observed diffraction will decrease because the less the ratio between wavelength and gap width is, the smaller the observed diffraction angle will be. To test this hypothesis, you would change the and observe the in the system. Therefore, the independent variable would be the and the dependent variable would be the.

Answers

Answer:

gap width

diffraction angle

gap width

diffraction angle

Explanation:

i just did it

Answer:

To test this hypothesis, you would change the Gap Width and observe the Diffraction Angle in the system.

Therefore, the independent variable would be the Gap Width and the dependent variable would be the Diffraction Angle.

Explanation:

Edge 2021-2022 :)

If a football player hits the ball with a force of 50 N, determine the reaction force.

Answers

Answer: 60

Explanation: if u hit it it will have impact and the impact added 10n

A 2kg crate ret on the floor. How much work i required to move it at contant peed 3m a frictionle air table,

Answers

When mass and velocity are given the work done is the change in kinetic energy . Here the work done to move the crate will be will be 9 J.

Here a crate of 2 kg is resting on the floor. Work should be done to move the object at a constant speed. When mass and velocity are given, because here the object is attaining kinetic energy, the work done will be the change in kinetic energy.

As the object was at rest, the initial kinetic energy will be 0.

Work done, W = \(\frac{1}{2} mv_{2} ^{2} -\frac{1}{2}mv_{1} ^{2}\)

v₁ = 0 , so the second term becomes 0.

W = \(\frac{1}{2}mv_{2}^{2}\)

     = 1/2 ×2×3² = 9 J.

Since crate is moving on a frictionless surface, we can ignore the frictional force.

So the work done to move a 2 Kg crate over a frictionless surface at a speed of 3m/s is 9 J.

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PLEASE ITS PORTOFOLIO WORK
A car has a mass of 900 kg. he moves from rest with acceleration 1.2 m / s.
Calculate the force required to give the car that acceleration.​

Answers

Answer:

I'm pretty sure its 1080

Explanation:

force is = to mass multiplied by acceleration.

So 900 kg multiplied by 1.2m/s is = to 1080

I'm no expert so please tell me if I'm wrong so that I can improve.

Have fun buddy .

A car of mass m rests at the top of a hill of height h before

rolling without friction into a crash barrier located at the

bottom of the hill. The crash barrier contains a spring with

a spring constant k, which is designed to bring the car to

rest with minimum damage.

it

Determine, in terms of m, h, k, and g, the maximum

distance (x) the spring will be compressed when the car

hits it. (Hint: Conservation of energy]

Answers

The equation to determine the maximum distance the spring will be compressed when the car hits it is x = \(\sqrt{(2mgh)/k}\).

When the car rolls down the hill, it gains kinetic energy equal to its potential energy at the top of the hill: mgh. This kinetic energy will be transferred to the spring upon impact with the crash barrier. The spring will compress until all the kinetic energy is stored as potential energy in the spring.

Using the conservation of energy principle, we can equate the initial potential energy of the car with the potential energy stored in the compressed spring:
mgh = (1/2)kx²

where x is the maximum distance the spring will be compressed. Solving for x, we get:
x = \(\sqrt{(2mgh)/k}\)

So, the maximum distance the spring will be compressed is dependent on the mass of the car (m), the height of the hill (h), the spring constant (k), and the acceleration due to gravity (g).

In summary, the equation to determine the maximum distance the spring will be compressed when the car hits it is x = \(\sqrt{(2mgh)/k}\).

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why does somthing fall faster if it is heavier

Answers

why does something fall faster if it is heavier?

First of all I would like to inform you that this statement is not true. The acceleration does not depend on the mass of the object. Heavier things have a greater gravitational force AND heavier things have a lower acceleration. It turns out that these two effects exactly cancel to make falling objects have the same acceleration regardless of mass.

Lets see

According to Newton's second law

\(\\ \rm\rightarrowtail F=ma\)

F denotes to forcem denotes to massa denotes to acceleration

\(\\ \rm\rightarrowtail F\propto m\)

If mass is more force of gravity is more.

\(\\ \rm\rightarrowtail m\propto \dfrac{1}{a}\)

If mass is more acceleration is less or air resistance is less .

So heavier objects fall faster than lighter ones .

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