Answer:
Molar Mass: the mass of one mole of an element. CONVERSION FACTORS: 1 mole = 6.02 x 10. 23 atoms 1 mole = atomic mass
hope this helps ;)
Explanation:
Substances A and B react with each other such that A is 75% consumed in 16 minutes and A is 87.5% consumed in 24 minutes. Changing the concentration of B has no effect on the reaction rate. The reaction is:
a. Zero order in both A and B.
b. First order in both A and B.
c. Second order in A and zero order in B.
d. First order in A and zero order in B.
e. There is insufficient information to answer this question.
Option d. First order in A and zero order in B. The reaction rate can be determined by the rate of change of concentration of the reactant over time.
In this case, the reaction is first order in A, meaning the reaction rate is proportional to the concentration of A. This can be seen as the reaction rate is the same even when the concentration of B is changed, implying that B has no effect on the reaction rate. On the other hand, the reaction is zero order in B, meaning the reaction rate is independent of the concentration of B. This means that the reaction rate is proportional to the concentration of A and is independent of the concentration of B. This can be observed from the fact that the reaction rate remains the same when the concentration of B is changed, implying that B has no effect on the reaction rate. On the other hand, the reaction rate is directly proportional to the concentration of A, meaning that as the concentration of A increases, the reaction rate also increases. Therefore, the reaction is first order in A and zero order in B.
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An atom is found to have 44 Protons.
What would be necessary to balance out the charge, making it a neutral atom?
For any component: Proton count equals atomic number
Number of protons plus number of electrons equals the atomic number.
The number of neutrons is equal to the atomic number-mass number.
What does atomic number mean?The quantity of protons in an element's atom is known as the atomic number. The atomic number of krypton in our illustration is 36. This indicates that the nucleus of a ruthenium atom contains 36 protons.
Every atom of ruthenium has 44 protons, which is intriguing. A Ruthenium atom cannot exist if it does not have 44 protons. A distinct element is produced by changing the number of protons in an atom's nucleus. An atom of rhodium is produced, for instance, by taking one proton away from a krypton atom.
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Why are chromosomes important? They play a role in cell division. They pass molecules through the nucleus. They produce food for a plant cell. They provide energy to the cell.
Chromosomes important because they play a role in cell division.
What is cell division?Cell division is described as the process by which a parent cell divides into two daughter cells and usually occurs as part of a larger cell cycle in which the cell grows and replicates its chromosome before dividing.
Chromosomes has another function of ensuring that each new cell receives a complete set of genetic information which is required for proper cell function and development.
In conclusion, there are two types of cell division which are mitosis and meiosis.
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10. When dissolved in water, most Group 1 metal salts can be described as
strong electrolytes.
strong acids.
weak electrolytes.
A
B
C
D
non-electrolytes.
(1)
When dissolved in water, most Group 1 metal salts can be described as strong electrolytes.
When Group 1 metal salts are dissolved in water, they can be described as strong electrolytes. This is because Group 1 metals, such as lithium (Li), sodium (Na), potassium (K), and so on, readily lose their outermost valence electron to form positive ions (cations). These cations then dissociate completely in water, separating from the anions to which they were originally bonded.
The dissociation of Group 1 metal salts in water results in the formation of positively charged metal ions and negatively charged non-metal ions (anions). These ions are free to move and conduct electric current, making the solution a good conductor of electricity. The complete dissociation of Group 1 metal salts in water and the presence of freely moving ions make them strong electrolytes.
Strong electrolytes are substances that ionize completely or almost completely in solution, producing a high concentration of ions. This is in contrast to weak electrolytes, which only partially ionize and produce a lower concentration of ions.
In summary, when Group 1 metal salts are dissolved in water, they form strong electrolytes due to their ability to dissociate completely into ions, leading to a high concentration of freely moving ions in the solution, thus enabling efficient electrical conductivity.
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An automobile tire contains air at 320.×103 Pa at 20.0 ◦C. The stem valve is removed and the air is allowed to expand adiabatically against the constant external pressure of 100.×103 Pa until P = Pexternal. Assume the air is an ideal gas with C¯ V = 5/2 R (diatomic). Calculate the final temperature.
Answer:
6.15.3 k
Explanation:
From the question we can see that
q = 0, Δu = w
Then,
\(T_f = \frac{C_{V,m}+RP_{ext}P_i}{C_{V,m}+RP_{ext}P_f} T_i\)
putting values wet
=\(\frac{2.5\times 8.314+8.314\left(10^5\right)\left(3.20\times 10^5\right)}{2.5\times 8.314+\left(8.314\right)\left(10^5\right)\left(10^5\right)}\times \:293\)
T_f = 615.3 K
Please Help! 100 points!!!!!
In Parts I and II of the lab, what happened to the electrons of each element to produce the different colors of light? Explain your answers using important terms from the lesson and information provided in the laboratory.
Answer:
In Parts I and II of the lab, what happened to the electrons of each element to produce the different colors of light? ... When heat was added to the elements, the electrons absorbs the energy and moves to its excited state. Once the electron starts to fall back to a lower orbit, it emits energy in the form of light.
Happy to help ☀️Keep on shining☀️
Explanation:
7.0 x 10 -3 mol of I2 in 100.00ml of solution
2. What is the volume of 2.89 g of CH4 (methane gas) at STP?
use n = m / M to find the moles
once you have the moles you will be able to find the Volume wirh the formula n × Vm
Vm is always 22,4 dm³/mol
hope this helped!!
Does the octet rule state that all elements except Hydrogen and Helium want eight (8) valence electrons?
Answer:
yes
Explanation:
Identify the substance that has formula mass of 133.5amu.
(a) MgCI
b)SCI
c)BCI
D) AICI
The calculated formula masses to 133.5 amu, we find that the substance with a formula mass closest to 133.5 amu is (d) AlCl3. Therefore, the answer is option D.
To identify the substance with a formula mass of 133.5 amu, we need to calculate the formula mass of each given substance and compare it to 133.5 amu.
(a) MgCl2:
The formula mass of MgCl2 can be calculated by adding the atomic masses of magnesium (Mg) and chlorine (Cl).
Mg: atomic mass = 24.31 amu
Cl: atomic mass = 35.45 amu
Formula mass of MgCl2 = (24.31 amu) + 2(35.45 amu) = 95.21 amu
(b) SCl:
The formula mass of SCl can be calculated by adding the atomic masses of sulfur (S) and chlorine (Cl).
S: atomic mass = 32.07 amu
Cl: atomic mass = 35.45 amu
Formula mass of SCl = 32.07 amu + 35.45 amu = 67.52 amu
(c) BCl:
The formula mass of BCl can be calculated by adding the atomic mass of boron (B) and chlorine (Cl).
B: atomic mass = 10.81 amu
Cl: atomic mass = 35.45 amu
Formula mass of BCl = 10.81 amu + 35.45 amu = 46.26 amu
(d) AlCl3:
The formula mass of AlCl3 can be calculated by adding the atomic mass of aluminum (Al) and 3 times the atomic mass of chlorine (Cl).
Al: atomic mass = 26.98 amu
Cl: atomic mass = 35.45 amu
Formula mass of AlCl3 = 26.98 amu + 3(35.45 amu) = 133.78 amu. Option D
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pOH of the 0.001M NaOH solution is
The pOH of the 0.001 M NaOH solution is approximately 3.
To determine the pOH of a solution, we need to know the concentration of hydroxide ions (OH-) in the solution.
In the case of a 0.001 M NaOH solution, we can assume that all of the NaOH dissociates completely in water to form Na+ and OH- ions. Therefore, the concentration of hydroxide ions in the solution is also 0.001 M.
The pOH is calculated using the equation:
pOH = -log[OH-]
Substituting the concentration of hydroxide ions, we have:
pOH = -log(0.001)
Using a calculator, we can evaluate the logarithm:
pOH ≈ 3
Therefore, the pOH of the 0.001 M NaOH solution is approximately 3.
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How does the chemical structure of a substance affect its interaction with other substances?
This is due to the fact that a substance's chemical qualities, such as its molecular form, polarity, and functional groups, govern how it behaves and interacts with other substances.
How does their chemical makeup impact their chemical characteristics?By illustrating the spatial arrangement of atoms and chemical bonds within the molecule, chemical structure establishes the molecular geometry of a compound. In doing so, chemists are given a crucial visual depiction of a chemical formula.
In what ways do drugs interact with one another?In a chemical reaction, reactants come into contact with one another, atoms in the reactants break their connections with one another, and then the atoms reorganise and form new bonds to create the products.
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Balance C3H8 + O2 + CO2 + H2O
Assuming the second plus sign is a typo and was meant to be a reaction arrow, this would be the balanced equation:
C3H8 + 5O2 —> 3CO2 + 4H2O
1. When 0.629 grams of Na3PO4.12H2O and 0.527 g BaCl2.2H2O are mixed with water , how many grams of Ba3(PO4)2 are produced?
The number of grams of Ba₃(PO₄)₂ that is produced is : 0.4328 gram
Given data
mass of Na₃PO₄.12H₂O = 0.629 grams
mass of BaCl₂.2H₂O = 0.527 grams
molar mass of Na₃PO₄.12H₂O = 380.12 g/mol
molar mass of BaCl₂.2H₂O = 244.26 g/mol
Determine the number of grams of Ba₃(PO₄)₂ produced
mole of Na₃PO₄.12H₂O = mass / molar mass
= 0.629 / 380.12 = 0.001654 mol
molar mass of BaCl₂.2H₂O = 0.527 / 244.26 = 0.002157 mol
After mixture : Determine the limiting reactant by lower mole ratio
mole ratio of BaCl₂.2H₂O = 0.002157 / 3
= 0.0007191
mole ratio of Na₃PO₄.12H₂O = 0.001654 / 2
= 0.000827
therefore the limiting reactant is : BaCl₂.2H₂O
Final step : Determine the mass of BaCl₂.2H₂O
molar mass of BaCl₂.2H₂O = 601.93 g/mol
Therefore :
mass of BaCl₂.2H₂O = moles * molar mass
= 0.0007191 * 601.93
= 0.4328 gram
Hence we can conclude that The number of grams of Ba₃(PO₄)₂ that is produced is : 0.4328 gram
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Which two phrases describe the movement of thermal energy due to
convection currents in the water on Earth?
O A. From the bottom of the ocean to the surface
B. From the surface of the ocean to the bottom
C. From cooler parts of Earth to the equator
D. From the equator to cooler parts of Earth
Answer:
D. From the equator to cooler parts of Earth
Explanation:
Thermal energy is always transferred from an area with a higher temperature to an area with a lower temperature. Moving particles transfer thermal energy through a fluid by forming convection currents.
Answer:
B. From the surface of the ocean to the bottom
D. From the equator to cooler parts of Earth
Explanation:
Test approved
hello, can you help me identify the name of these 4 molecules as well as the structural formula and the skeletal formula? thank you
Answer:1. metyletevinyl
4. (Z)-3-hydroxypropenal
Explanation:
20 points! Please help with Homework
Atomic mass is the sum of
protons and electrons
metalloids and metals
neutrons and protons
protons and neutrons
Answer:
Neutrons and protons
Explanation:
The average atomic mass of an element is the sum of the masses of its isotopes, each multiplied by its natural abundance (the decimal associated with percent of atoms of that element that are of a given isotope).
Wich stament describes to organ systems working together to get rid of waste played by cells
Answer:
C. Kidneys filter wastes from the bloodstream and produce urine
Explanation:
The atomic number of an atom is
A. The mass of the atom.
B. The number of protons added to the number of neutrons in the nucleus.
C. The number of protons in the nucleus.
D. Negatively charged.
Answer:
B. the number of protons added to the number of neutrons in the nucleus.
Explanation:
Sana makatulong
Two examples of potential energy are ________________________ and ______________________. Examples can include _________________________ and __________________________________.
Two examples of potential energy are gravitational potential energy and elastic potential energy.
What is Gravitational Potential Energy ?Gravitational potential energy is the energy stored in an object due to its position in a gravitational field. For example, a book placed on a shelf has gravitational potential energy because it has the potential to fall to the ground due to the force of gravity.
What is Elastic Potential Energy ?Elastic potential energy is the energy stored in an object when it is deformed, such as when a spring is compressed or stretched. For example, a compressed spring has elastic potential energy because it has the potential to return to its original shape and release the stored energy when it is released.
Other examples of potential energy include chemical potential energy, which is the energy stored in the bonds between atoms in a molecule, and nuclear potential energy, which is the energy stored in the nucleus of an atom.
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The dry solute has a mass of 0.086 g. 0.113 g of water evaporated while heating. What is the concentration in G solute / mL solvent at 30.1 C? Remember: 1 g = 1 ml for water
A. 0.88
B. 0.0860
C. 0.113
D. 0.761
The dry solute has a mass of 0.086 g. 0.113 g of water evaporated while heating, the concentration in G solute / mL solvent at 30.1 C is 0.88.
To find the concentration in g solute / mL solvent, we first need to find the mass of the solvent left after evaporation:
Mass of water before evaporation = 0.113 g
Mass of water after evaporation = 0.113 g - 0.086 g = 0.027 g
Since 1 g of water has a volume of 1 mL, the volume of water after evaporation is also 0.027 mL.
Next, we need to convert the temperature to Kelvin:
T = 30.1 + 273.15 = 303.25 K
We can now use the formula:
concentration = (mass of solute / mass of solvent) / (1 - (mass of water evaporated / mass of solvent))
Plugging in the values we get:
concentration = (0.086 g / (0.027 g)) / (1 - (0.113 g / (0.086 g + 0.027 g)))
concentration = 0.88 g/mL
Therefore, the answer is A. 0.88.
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Answer:
A
Explanation:
worked for me on acellus
How many mL of C8H18 are needed to react with 0.0500 mol O2? 2 C8H18 (l) + 25 O2 (g) - 16 CO2(g) + 18 H20 (g) molar masses: C8H18 = 114.22g/mole H2O = 18.02 g/mole CO2 = 44.01 g/mole O2 = 32.00 g/mole and make sure the answer has significant figures
Answer:
0.45688mL
Explanation:
1) First you should look on the coefficients.
\(2C_8H_{18(l)}\ + 25O_2_{(g)}=\ 16CO_{2(g)}+ 18H_2O_{(g)}\)
2) Do the ratio between C8H18 and O2:
\(C_8H_{18}\ \ \ \ \ \ \ \ \ O_2\\2 : \ \ \ \ \ \ \ \ \ \ \ \ \ 25\\X: \ \ \ \ \ \ \ \ \ \ \ 0.0500moles\\2X0.0500/25= 0.004\\X=0.004 \moles\ of\ C_8H_{18}\)
3) grams= moles X molecular mass
\(0.004*114.22= 0.45688g\)
[1g=1mL] => 0.45688mL
I have a balloon that has a volume of 0.5 L at a pressure of 0.5 atm. What is the new volume at a pressure of 1 atm?
I have a container at a volume of 2 L and at a temperature of 125 C. What is the new temperature of the container at a volume of 2 L?
A sample of helium gas in a balloon is compressed from 4.0 L to 2.5 L at a constant temperature. If the initial pressure was 3.0 atm at 4.0 L, what is the new pressure at 2.5 L?
A container has 50 mL of nitrogen at 25 C. What will be the volume if the new temperature if 60 C?
1)The new volume at a pressure of 1 atm is 0.25 L.
2)The new temperature of the container at a volume of 2 L is approximately 398°C.
3)The new pressure at 2.5 L is approximately 4.8 atm.
4)The new volume at a temperature of 60°C is approximately 55.8
1)To solve these gas law problems, we can use the ideal gas law equation, which states:
PV = nRT,
where P is pressure, V is volume, n is the number of moles of gas, R is the ideal gas constant, and T is temperature in Kelvin.
Balloon volume at a pressure of 0.5 atm:\(V_1\) = 0.5 L, \(P_1\)= 0.5 atm.
New volume at a pressure of 1 atm:\(P_2\) = 1 atm.
We can use the relationship\(P_1V_1 = P_2V_2\) to find the new volume (\(V_2\)).
(0.5 atm)(0.5 L) = (1 atm)(\(V_2\))
\(V_2\) = 0.25 L.
Therefore, the new volume at a pressure of 1 atm is 0.25 L.
2)Container volume: \(V_1\) = 2 L, \(T_1\)= 125°C.
New temperature at the same volume: \(V_2\) = 2 L.
We can use the relationship\(V_1\)/\(T_1\) = \(V_2\)/\(T_2\) to find the new temperature (\(T_2\)).
(2 L)/(125 + 273) K = (2 L)/(\(T_2\) + 273) K
Solving for\(T_2\), we get \(T_2\) ≈ 398°C.
Therefore, the new temperature of the container at a volume of 2 L is approximately 398°C.
3)Initial volume: \(V_1\)= 4.0 L, \(P_1\) = 3.0 atm.
Final volume: \(V_2\) = 2.5 L.
Since the temperature (T) is constant, we can use the relationship \(P_1\)\(V_1\) = \(P_2V_2\) to find the new pressure (\(P_2\)).
(3.0 atm)(4.0 L) = (\(P_2\))(2.5 L)
\(P_2\) ≈ 4.8 atm.
Therefore, the new pressure at 2.5 L is approximately 4.8 atm.
4)Initial volume: \(V_1\)= 50 mL, \(T_1\) = 25°C.
New temperature: \(T_2\) = 60°C.
We need to convert the temperatures to Kelvin.
\(T_1\)= 25 + 273 = 298 K, \(T_2\) = 60 + 273 = 333 K.
We can use the relationship \(V_1/T_1 = V_2/T_2\) to find the new volume (\(V_2\)).
(50 mL)/(298 K) = (\(V_2\))/(333 K)
\(V_2\) ≈ 55.8 mL.
Therefore, the new volume at a temperature of 60°C is approximately 55.8
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Where does the oil in cars come from?
Select 2 that apply
-Phytoplankton convert the sugar created through photosynthesis into oil.
-Coral Reefs clean the water by removing any carbon waste, they then convert this into oil.
-Every time there is an earthquake, oil is being produced and new oil deposits are created.
-The phytoplankton that is dead become liquefied over time due to pressure, and oil deposits
are formed.
-Fish produce oil as a waste product that eventually forms oil deposits.
- The phytoplankton that is dead become liquefied over time due to pressure, and oil deposits are formed.
- Fish produce oil as a waste product that eventually forms oil deposits.
Compare and contrast the thermal capacity and transfer of solids, liquids, and gases
Answer:
किसी पदार्थ की ऊष्मीय चालकता को प्रति इकाई तापमान अंतर के प्रति इकाई क्षेत्र की सामग्री की एक इकाई मोटाई के माध्यम से गर्मी हस्तांतरण की दर के रूप में परिभाषित किया गया है। किसी पदार्थ की ऊष्मीय चालकता इस बात का माप है कि उस पदार्थ में कितनी तीव्र ऊष्मा प्रवाहित होगी। थर्मल चालकता के लिए एक बड़ा मूल्य इंगित करता है कि सामग्री एक अच्छा गर्मी कंडक्टर है, और एक कम मूल्य इंगित करता है कि सामग्री एक खराब गर्मी कंडक्टर या इन्सुलेटर है। कमरे के तापमान पर शुद्ध तांबे की तापीय चालकता 401 W / m है। K, जो इंगित करता है कि एक 1m मोटी तांबे की दीवार 401 W / m 2 की दर से गर्मी का संचालन करेगीप्रति दीवार के क्षेत्र का अंतर दीवार के पार तापमान अंतर। चित्रा 2.3 सामान्य तापमान और दबाव में पदार्थ के विभिन्न राज्यों के लिए तापीय चालकता की सीमा को दर्शाता है। एक ठोस की ऊष्मीय चालकता, गैस की तुलना में चार गुना अधिक परिमाण की हो सकती है। यह प्रवृत्ति काफी हद तक दोनों राज्यों के बीच अंतर-संबंधी अंतर के कारण है।
ठोस राज्य
सामग्रियों के आधुनिक दृष्टिकोण में, एक ठोस में मुक्त इलेक्ट्रॉनों और एक आवधिक व्यवस्था में बाध्य परमाणुओं का समावेश हो सकता है जिसे जाली कहा जाता है। तदनुसार, थर्मल ऊर्जा का परिवहन दो प्रभावों के कारण होता है: मुक्त इलेक्ट्रॉनों का पलायन और जाली कंपन तरंगें। ये प्रभाव योगात्मक हैं, जैसे कि तापीय चालकता k , इलेक्ट्रॉनिक घटक k e और समरूप घटक k l का योग है
k = k e + k l
(2.7)
सामान्य तापमान और दबाव में विभिन्न राज्यों के लिए थर्मल चालकता की 2.3 रेंज चित्रा
k e विद्युत प्रतिरोधकता के व्युत्क्रमानुपाती होता है । शुद्ध धातुओं के लिए, जो कम के हैं , k e , k l की तुलना में बहुत बड़ा है । इसके विपरीत, मिश्र धातुओं के लिए, जो कि काफी बड़े होते हैं , k l से k का योगदान अब नगण्य नहीं है। गैर-धात्विक ठोस के लिए, k को मुख्य रूप से k l द्वारा निर्धारित किया जाता है , जो कि जाली के परमाणुओं के बीच परस्पर क्रिया की आवृत्ति पर निर्भर करता है। जाली व्यवस्था की नियमितता का k l पर महत्वपूर्ण प्रभाव पड़ता है , क्रिस्टलीय (सुव्यवस्थित) सामग्री की तरह, क्वार्ट्ज जैसी सामग्री में कांच जैसी अनाकार सामग्री की तुलना में अधिक ऊष्मीय चालकता होती है। वास्तव में, क्रिस्टलीय के लिए, गैर-धात्विक ठोस जैसे कि हीरा और बेरिलियम ऑक्साइड, k l काफी बड़े हो सकते हैं, जो कि अच्छे कंडक्टरों से जुड़े k के मूल्यों से अधिक होते हैं , जैसे कि एल्यूमीनियम।
इन्सुलेशन सिस्टम
थर्मल इंसुलेशन में कम तापीय चालकता वाली सामग्री शामिल होती है, जो एक कम प्रणाली वाली तापीय चालकता को प्राप्त करने के लिए संयुक्त होती है। फाइबर-, पाउडर-, फ्लेक-टाइप इंसुलेशन में, ठोस पदार्थ को पूरी तरह से एक एयर स्पेस में फैलाया जाता है। ऐसी प्रणालियों को एक प्रभावी तापीय चालकता की विशेषता होती है , जो ठोस पदार्थ की तापीय चालकता और सतह विकिरणकारी गुणों पर निर्भर करती है, साथ ही साथ हवा या शून्य स्थान की प्रकृति और मात्रात्मक अंश। प्रणाली का एक विशेष पैरामीटर इसकी थोक घनत्व (ठोस द्रव्यमान / कुल मात्रा) है, जो उस तरीके पर दृढ़ता से निर्भर करता है जिसमें ठोस सामग्री परस्पर जुड़ी हुई है।
द्रवित अवस्था
चूंकि इंटरमॉलिक्युलर स्पेसिंग बहुत बड़ी होती है और अणु की गति ठोस अवस्था की तुलना में द्रव अवस्था के लिए अधिक यादृच्छिक होती है, इसलिए थर्मल एनर्जी ट्रांसपोर्ट कम प्रभावी होता है। इसलिए गैसों और तरल पदार्थों की तापीय चालकता ठोस पदार्थों की तुलना में छोटी होती है।
ऊष्मीय विसरणशीलता
गर्मी हस्तांतरण समस्याओं के हमारे विश्लेषण में, पदार्थ के कई गुणों का उपयोग करना आवश्यक होगा। इन गुणों को आम तौर पर थर्मोफिजिकल गुणों के रूप में संदर्भित किया जाता है और इसमें दो अलग-अलग श्रेणियां, परिवहन और थर्मोडायनामिक गुण शामिल होते हैं। परिवहन गुणों में प्रसार दर गुणांक जैसे कि के, थर्मल चालकता (गर्मी हस्तांतरण के लिए), और , गतिज चिपचिपापन (गति हस्तांतरण के लिए) शामिल हैं। दूसरी ओर, थर्मोडायनामिक गुण, एक प्रणाली के संतुलन की स्थिति से संबंधित हैं। घनत्व ( ) और विशिष्ट ऊष्मा ( C p ) दो ऐसे गुण हैं जिनका उपयोग थर्मोडायनामिक विश्लेषण में बड़े पैमाने पर किया जाता है। उत्पाद सी पीआम तौर पर वॉल्यूमेट्रिक ताप क्षमता को कहा जाता है , जो थर्मल ऊर्जा को स्टोर करने के लिए एक सामग्री की क्षमता को मापता है। क्योंकि बड़े घनत्व के पदार्थों को आमतौर पर छोटे विशिष्ट हीट्स, कई ठोस और तरल पदार्थों की विशेषता होती है, जो कि बहुत अच्छा ऊर्जा भंडारण मीडिया है, इसमें तुलनीय ताप क्षमता होती है। हालांकि उनकी बहुत छोटी घनत्व के कारण, गैसें थर्मल ऊर्जा भंडारण के लिए खराब अनुकूल हैं।
ऊष्मा अंतरण विश्लेषण में, ऊष्मा चालकता के लिए तापीय चालकता का अनुपात एक महत्वपूर्ण गुण है जिसे तापीय विवर्तनशीलता कहा जाता है , जिसमें m 2 / s की इकाइयाँ होती हैं ।
(2.8)
यह तापीय ऊर्जा को संग्रहीत करने की क्षमता के सापेक्ष तापीय ऊर्जा का संचालन करने के लिए एक सामग्री की क्षमता को मापता है। बड़ी की सामग्री उनके थर्मल वातावरण में बदलाव के लिए जल्दी से प्रतिक्रिया देगी, जबकि छोटे की सामग्री अधिक सुस्त प्रतिक्रिया देगी, एक नई संतुलन स्थिति तक पहुंचने में अधिक समय लेगी।
Why do we study chemistry?
Answer:
The study of chemistry provides global work opportunities.
Explanation:
Answer:
2 answers.
Explanation:
1. The study of chemistry provides global work opportunities. Chemistry underpins understanding and progress in almost every science, technology, and industry sphere. It also makes a vital contribution to the economy, commerce and industry.
2. Because teachers want us to be bored and make time feel like it's stuck in honey.
In one of your classes, you were asked to start a program that would help the government in environmental conservation,
which would not fit that program?
A) Encourage your parents to buy Energy Star products.
B) Start a group project to campaign for the protection of an endangered species.
C) Promote the use of phone cases made from crocodile skin.
D) Make flyers about how to recycle trash from homes.
how many atoms are in 0.5 mole of aluminum
According to the Avogadro's number, there are 3.011×10²³ atoms in 0.5 mole of aluminium.
What is Avogadro's number?Avogadro's number is defined as a proportionality factor which relates number of constituent particles with the amount of substance which is present in the sample.
It has a SI unit of reciprocal mole whose numeric value is expressed in reciprocal mole which is a dimensionless number and is called as Avogadro's constant.It relates the volume of a substance with it's average volume occupied by one of it's particles .
According to the definitions, Avogadro's number depend on determined value of mass of one atom of those elements.It bridges the gap between macroscopic and microscopic world by relating amount of substance with number of particles.
Number of atoms can be calculated using Avogadro's number as follows: mass/molar mass×Avogadro's number, on substituting values in formula, 0.5×6.023×10²³=3.011×10²³ atoms.
Thus, there are 3.011×10²³ atoms in 0.5 mole of aluminium.
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A 19.66 g sample of chromium is heated in the presence of excess bromine. A metal bromide is formed with a mass of 110.3 g. Determine the empirical formula of the metal bromide.
To determine the empirical formula of the metal bromide formed, we need to first calculate the amount of chromium reacted and the amount of bromine reacted. The amount of chromium reacted can be calculated using its molar mass, which is 52 g/mol: 19.66 g chromium x (1 mol chromium / 52 g chromium) = 0.378 mol chromium.
Since there is excess bromine, all of the chromium would react with bromine to form the metal bromide. Therefore, the amount of bromine reacted can be calculated using the mass of the metal bromide formed:
110.3 g metal bromide x (1 mol metal bromide / molar mass of metal bromide) = amount of bromine reacted
We don't know the molar mass of the metal bromide yet, but we can use the law of conservation of mass to determine it. The mass of the metal bromide formed must equal the sum of the masses of the chromium and bromine that reacted.
110.3 g metal bromide = 19.66 g chromium + mass of bromine reacted mass of bromine reacted = 90.64 g
Now we can calculate the amount of bromine reacted:
90.64 g bromine x (1 mol bromine / 79.904 g bromine) = 1.133 mol bromine
To determine the empirical formula, we need to find the ratio of the moles of each element in the metal bromide.
Chromium: 0.378 mol
Bromine: 1.133 mol
To get a whole number ratio, we can divide both of these values by the smaller value (0.378 mol):
Chromium: 0.378 mol ÷ 0.378 mol = 1
Bromine: 1.133 mol ÷ 0.378 mol = 3
Therefore, the empirical formula of the metal bromide is CrBr3.
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