how many assymetric carbon atoms are present in the molecule shown? cl cl

Free energy change for transporting Ca2+ ions is calculated as follows:∆G = RT ln ([Ca2+]outside/[Ca2+]inside)∆G = 8.315 J/mol.K x 310 K x ln (25 mM/145 mM) = -15,400 J/mol.

Here, ∆G is negative, which implies that Ca2+ ions transport spontaneously from the cell to blood. This is because the free energy of the system decreases when Ca2+ ions move from high concentration to low concentration. Therefore, transporting Ca2+ ions is energetically favorable.

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The combustion of 5.75 L of \(CH_4\) and an appropriate amount of \(O_2\) at 710 K can produce approximately \(\textbf{14.34 L}\) of  \(CO_2\) and \(\textbf{11.5 L}\) of  \(H_2O\) .

When \(CH_4\) undergoes complete combustion, it reacts with oxygen to produce carbon dioxide ( \(CO_2\) ) and water ( \(H_2O\) ) according to the following balanced chemical equation:

\(\[\text{CH}_4 + 2\text{O}_2 \rightarrow \text{CO}_2 + 2\text{H}_2\text{O}\]\)

To determine the volume of  \(CO_2\) and  \(H_2O\) produced, we need to apply the principle of stoichiometry. According to the balanced equation, for every 1 mole of CH4 burned, 1 mole of  \(CO_2\) and 2 moles of  \(H_2O\) are produced. We can convert the given volume of CH4 to moles using the ideal gas law and then use the stoichiometric coefficients to determine the corresponding volumes of  \(CO_2\) and  \(H_2O\) .

The molar volume of an ideal gas at 710 K and 1 atm is approximately 22.4 L/mol. So, the initial volume of \(CH_4\) can be converted to moles:

\(\[\text{moles of CH}_4 = \frac{\text{volume of CH}_4}{\text{molar volume}} = \frac{5.75\text{ L}}{22.4\text{ L/mol}} = 0.257\text{ mol}\]\)

Based on the stoichiometry of the reaction, we can conclude that the moles of  \(CO_2\) produced will be equal to the moles of \(CH_4\) burned, while the moles of  \(H_2O\) produced will be twice that. Thus:

\(\[\text{moles of CO}_2 = 0.257\text{ mol} \\\\\text{moles of H}_2\text{O} = 2 \times 0.257\text{ mol} = 0.514\text{ mol}\]\)

Finally, we convert the moles of  \(CO_2\) and \(H_2O\) back to volumes using the molar volume:

\(\[\text{volume of CO}_2 = \text{moles of CO}_2 \times \text{molar volume} = 0.257\text{ mol} \times 22.4\text{ L/mol} = 5.758\text{ L}\\\\\text{volume of H}_2\text{O} = \text{moles of H}_2\text{O} \times \text{molar volume} = 0.514\text{ mol} \times 22.4\text{ L/mol} = 11.508\text{ L}\]\)

Therefore, approximately 14.34 L of \(CO_2\) and 11.5 L of  \(H_2O\) can be produced from the combustion of 5.75 L of \(CH_4\) and sufficient \(O_2\) at 710 K.

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Nature of reactants, Concentration of reactants, Catalyst, Temperature, Exposure of light.

1) Reactant nature: The reaction rate is influenced by the reactants' physical characteristics, size, and chemical make-up.

2) Reactant concentration: As the reactant concentration rises, there are more collisions and more opportunities for effective collisions, which raises the rate.

3) Reaction rates may be accelerated by a positive catalyst or slowed down by a negative catalyst.

4) The pace of reaction is quadrupled or doubled when the temperature rises due to an increase in the number of effective collisions.

5) The rate of a photochemical reaction is dependent on the amount of light that is shining on the reacting mixture.

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Answer:

Because force is what causes things to move or change while volactiy  is when you add more energy and  the things volactiy will change.

Explanation:

Answer:

1 mole is equal to 1 moles Copper(II) Oxide, or 79.5454 grams. Note that rounding errors may occur, so always check the results.

Explanation:

Consider the model of a sodium atom. An orange circle labeled upper n a is surrounded by three concentric circles. The innermost ring has dots at the north and south positions. The next ring has eight dots, evenly spaced, with dots aligning with those in the inner ring. The outermost ring has one dot at the north position. The distribution of electrons in different shells feature does the model show accurately.

Using the atomic number of each element, we may depict its atomic structure. Therefore, you must first know the atomic number of sodium in order to depict its atomic structure.

The sodium atom has a number of 11. Any element's atomic number describes how many electrons are present in one of its atoms.

Always start your sentence with the element's atomic number. Knowing an object's atomic number also lets you know how many protons and electrons it contains. The number of protons and electrons is the same as it is in every stable atom. Consequently, you are also aware of the quantity of electrons.

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The complete question is ''Consider the model of a sodium atom. An orange circle labeled upper N a is surrounded by three concentric circles. The innermost ring has dots at the north and south positions. The next ring has eight dots, evenly spaced, with dots aligning with those in the inner ring. The outermost ring has one dot at the north position. Which feature does the model show accurately?

A) the size of the electrons in different shells

B) the shapes of the orbitals in different shells

C)the distribution of electrons in different shells

D)the orientation of the orbitals in different shells

A chemistry graduate student combines 3.90 grams of potassium and 12.7 grams of iodine to form potassium iodide. according to the law of conservation of mass, potassium iodide should be formed after the reaction is complete is 16.70 g.

According to the law of conservation mass, in a chemical reaction mass can neither be created nor destroyed.

According to the law, mass of the reactant is always equal to the mass of product, because in a chemical reaction, mass can neither be created nor destroyed.

The balanced chemical reaction is -

2 K      +       I₂    →      2 KI

3.90 g  +   12.7 g   =   16.70 g

16.70 g                  =   16.70 g

Therefore, when the reaction proceeds to completion, 16.70 g product is obtained as the sum of reactants is 16.70 g and according to law of conservation of mass, mass is neither created nor destroyed but it only converts from one form to another form.

Hence, potassium iodide formed is 16.70 g.

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Answer:Cutting, tearing, shattering, grinding, and mixing are further types of physical changes because they change the form but not the composition of a material. For example, mixing salt and pepper creates a new substance without changing the chemical makeup of either component.

Explanation:

Answer:

As you intensify the production system there will be some bad things that come with that .

Explanation:

Systems of production of products of animal origin very intensified can extract the animal at levels that are extremely harmful to the entire production chain.

In these types of environments, animals may not allow manipulation, attack collaborators and even have significant production declines that will hinder the management of the product or service produced and harm all economic activity.

The moles of hno3 are present if 0.180 molmol of ba(oh)2 was needed to neutralize the acid solution is 0.36 mole of HNO₃.

Neutralization or neutralisation is a chemical reaction in which acid and a base react quantitatively with each other. In a reaction in water, neutralization outcomes in there being no excess of hydrogen or hydroxide ions gift inside the answer.

Calculation:-

Valance factor of HNO₃ is = 1

valance factor of Ba(OH)₂ is = 2

mole of Ba(OH)₂ is = 0.180

therefore mole oh HNO₃ neede is = 2 * 0.180

                                                         =  0.36 mole of HNO₃

Neutralisation is a chemical response wherein an acid and a base react with each different quantitatively. it's also written as Neutralisation. The acid electricity of the reactant gives the pH of the neutralised solution.

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The aqueous solutions of the following salts are:

(a) \(K_2CO_3\): Basic

(b) \(CaCl_2\): Neutral

(c) \(KH_2PO_4\): Acidic

(d) \((NH_4)_2CO_3\): Acidic

(a) \(K_2CO_3\):

The cation, \(K^+\) (potassium ion), is derived from a strong base (KOH), which does not hydrolyze in water. Therefore, it does not contribute to the acidity or basicity of the solution. The anion, \(CO_3^{2-\) (carbonate ion), is derived from a weak acid \(H_2CO_3\), which can hydrolyze in water.

The hydrolysis of \(CO_3^{2-\) can be represented as follows:

\(CO_3^{2-} + H_2O\) ⇌ \(HCO_3^- + OH^-\)

Since the hydrolysis of \(CO_3^{2-\) results in the formation of \(OH^-\) ions, the solution will be basic.

(b) \(CaCl_2\):

Both the cation, \(Ca_2^+\) (calcium ion), and the anion, \(Cl^-\) (chloride ion), are derived from strong acids and bases (HCl and \(Ca(OH)_2\)). As a result, they do not undergo hydrolysis in water. Therefore, the solution will be neutral.

(c) \(KH_2PO_4\):

The cation, \(K_+\) (potassium ion), does not undergo hydrolysis in water. The anion, \(H_2PO_4^-\) (dihydrogen phosphate ion), can hydrolyze in water.

The hydrolysis of \(H_2PO_4^-\) can be represented as follows:

H2PO4- + H2O ⇌ \(HPO_4^{2-} + H_2PO_4^- + H_3O^+\)

Since the hydrolysis of \(H_2PO_4^-\) results in the formation of \(H_3O^+\) ions, the solution will be acidic.

(d) \((NH_4)_2CO_3\):

Both the cation, \(NH_4^+\) (ammonium ion), and the anion, \(CO_3^{2-\) (carbonate ion), can hydrolyze in water.

The hydrolysis of \(NH_4^+\) can be represented as follows:

\(NH_4^+ + H_2O\) ⇌ \(NH_3 + H_3O^+\)

Since the hydrolysis of \(NH_4^+\) results in the formation of \(H_3O^+\) ions, the solution will be acidic.

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A discrete cellular structure composed of a neatly packaged DNA molecule is called a "chromosome."

Chromosomes are structures found within the nucleus of cells and are responsible for carrying the genetic information in the form of DNA. Each chromosome consists of a single, long DNA molecule tightly coiled and organized with proteins.

This packaging allows for the efficient storage, replication, and transmission of genetic material during cell division. Chromosomes are visible under a microscope during specific stages of cell division when they condense and become visible as distinct structures. In humans, each somatic cell typically contains 46 chromosomes, arranged in 23 pairs.

These chromosomes contain the genes that determine an individual's inherited traits and characteristics. Alterations or abnormalities in the structure or number of chromosomes can lead to genetic disorders and diseases. The study of chromosomes is essential in genetics and plays a crucial role in understanding heredity, genetic disorders, and evolutionary relationships between species.

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The electron configuration for carbon is 1s² 2s² 2p², which indicates that it has two electrons in the 1s orbital, two electrons in the 2s orbital, and two electrons in the 2p orbital.

The Lewis valence electron diagram for carbon shows four valence electrons, represented by dots around the element symbol. The first two dots are placed on different sides of the symbol to represent the two electrons in the 2s orbital, while the remaining two dots are placed above and below the symbol to represent the two electrons in the 2p orbital. This arrangement of valence electrons is crucial in determining the chemical behavior of carbon, which is essential in many biological and industrial processes.

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--The complete Question is, Use the electron arrangement interactive to practice building electron arrangements. Then, write the electron configuration and draw the Lewis valence electron diagram for carbon. --

The amount that will be left after 115.2 years, given that you started with 10 grams sample of strontium-90 is 0.625 g

To obtain the amount that will be left after 115.2 years, we shall begin our calculation by obtaining the number of half lives that has passed.

The number of half lives that has passed can be obtained as followed:

n = t / t½

n = 115.2 / 28.8

n = 4

Thus, 4 half lives has passed.

Finally, we shall determine the amount that will be left after 115.2 years. This is illustrated below:

N = N₀ / 2ⁿ

N = 10 / 2⁴

N = 10 / 16

N = 0.625 g

Thus, we can conclude that the amount that will be left after 115.2 years is 0.625 g

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2 moles of Al₂O₃ will be produced when 4 moles of Al reacts in accordance with the above equation.

Stoichiometry refers to the study and calculation of quantitative (measurable) relationships of the reactants and products in chemical reactions (chemical equations).

According to this question, 6.0 moles of Al reacts with 4.0 mol of oxygen gas to form Al₂O₃ as follows:

4Al + 30₂ → 2Al₂O₃

Based on the above equation, 4 moles of Al reacts to form 2 moles of aluminium oxide.

This means that 4 moles of aluminium will produce 4 × ²/4 = 2 moles of aluminium oxide.

Therefore, 2 moles of Al₂O₃ will be produced by 4 moles of aluminium.

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Answer:

Find the molar mass of each individual element, multiply that molar mass number by the element's subscript in the formula, and then add together.

Explanation:

Answer:60

Explanation:

60 is 60 is 69 to the l the b i like eating j wek;gnl

In Experiment 2, the gas produced at the negative electrode is typically hydrogen (H2).

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a. The element has a total of 6 valence electrons (2 in the ns orbital and 4 in the np orbital).b. The element that has a valence electron configuration of ns2np4 could be Selenium (Se), which has 6 valence electrons.c. The element, which has a valence electron configuration of ns2np4, will form an ionic compound with potassium by losing all its valence electrons to potassium. Hence, the compound formed will be K2Se.

d. The radius of an element depends on the number of electrons and energy levels, among other factors. Barium (Ba) is an element found in period 6 of the periodic table. In contrast, the unknown element is found in period 3. Thus, it can be concluded that the element has a smaller radius than Barium (Ba).e. Fluorine (F) is one of the most electronegative elements known. As a result, it has the highest ionization energy. The element with a valence electron configuration of ns2np4 is more significant than fluorine, but it has a lower ionization energy.

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Answer:

114N is correct answer.

Valences have the greatest tendency to form ions, are, +1,-1,+2,-2,+3,-3. All the options are correct.

Valence is the number of electrons lost or gained in a reaction to complete an element's outer energy level.

When an atom gains or loses a valence electron, it forms an ion. Atoms form ions in order to help another to obtain a full octet and to stabilize the valence.

Some atoms gain or lose electrons to form ions because they need to become more stable. They sometimes give them to have an outer shell or gain them to get a closer charge to eight.

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Answer:

+1,-1,+2,-2,+3,-3

Explanation:

When the preexisting molecular links are broken and new bonds are created between oxygen and hydrogen atoms, hydrogen molecules react strongly with oxygen molecules.

The outcome is an explosive release of energy and the formation of water since the reaction's products are at a lower energy level than its reactants.

The most well-known instance of a synthesis reaction is the burning of hydrogen and oxygen to produce water.

Most of the water that was created was in the form of vapors, which mixed with cosmic dust on the way to the earth's surface. These water vapors condensed into oceans, seas, rivers, and lakes when the world first came into existence.

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Alkyl Halide: Ethyl Bromide Synthesis: Ethyl Bromide can be synthesized by reacting ethyl alcohol with hydrobromic acid and sulfuric acid.

Ethyl is an organic compound and a member of the alkane family of hydrocarbons, with the chemical formula C2H5. It is a colorless, flammable liquid with a sweet, disagreeable odor. Ethyl is used in industry for the production of fuel, solvents, and antifreeze agents. It is also used as a laboratory reagent for the synthesis of other compounds, and as a raw material in the production of ethanol and ethylene glycol. Because of its relatively low boiling point and low toxicity, ethyl is used as a low-cost solvent in many chemical reactions. Ethyl is also used in the production of a variety of pharmaceuticals, such as anticonvulsants, antihistamines, and anesthetics. It is also used in the production of explosives, as well as in food flavoring and perfumes.

1. Alkyl Halide: Ethyl Bromide

Synthesis: Ethyl Bromide can be synthesized by reacting ethyl alcohol with hydrobromic acid and sulfuric acid. The reaction proceeds as follows:

ethyl alcohol + hydrobromic acid + sulfuric acid → ethyl bromide + water + sulfur dioxide.

2. Alkyl Halide: Propyl Bromide

Synthesis: Propyl Bromide can be synthesized by reacting propanol with hydrobromic acid and sulfuric acid. The reaction proceeds as follows:

propanol + hydrobromic acid + sulfuric acid → propyl bromide + water + sulfur dioxide.

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An Alkyl Halide such as Ethyl Bromide can be synthesized by reacting ethyl alcohol with hydrobromic acid and sulfuric acid.

Alkyl halides or haloalkanes are a subclass of organic compounds that have an alkyl group's carbon atom bound to one of the halogen atoms—fluorine, chlorine, bromine, or iodine.

An alkyl group is a straight or branching chain of carbon atoms with hydrogen atoms connected to them.

The synthesis of ethyl bromide by reacting ethyl alcohol with hydrobromic acid and sulfuric acid is as follows:

ethyl alcohol + hydrobromic acid + sulfuric acid → ethyl bromide + water + sulfur dioxide.

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The equation that represents a single replacement reaction given the various options is 2Al(s) + 6HCl -> 2AlCl₃(aq) + 3H₂O(g) (option 2)

A single replacement reaction, also known as single displacement reaction is a reaction in which elements higher in the electro-chemical series displace or replace elements lower in the electro-chemical series displace from a solution.

The following example illustrates single replacement reaction:

A + BC -> AC + B

From the above reaction, we can see that A has replace/displace B to from AC.

With the above information, we can determine the equation that represents single replacement reaction. Details below:

Equation from the questions:

From the above, we can see that only 2Al(s) + 6HCl -> 2AlCl₃(aq) + 3H₂O(g) conform to single replacement reaction.

Thus, the correct answer to the question is: 2Al(s) + 6HCl -> 2AlCl₃(aq) + 3H₂O(g) (option 2)

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The dimension of a rectangle and square, multiply its length even by width measurement. To calculate the rectangle's surface area, multiply the length and width measurements by two and then divide by three.

To use a tape measure to measure a rug is very easy. To calculate the square footage of rectangular rugs, simply multiply the length and width by each other. Simply take measurements at the furthest locations along the perimeter for round carpets or any other form.

You should preferably allow a equal amount of room for flooring on both of your rug's edges. Let yourself anywhere from eight to 24 inches on all sides. The most common separation is eighteen inches, although in a small space, you might be capable of escaping with much less. The centre of the room should be where you put the rug.

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Answer:

Ferric oxide reacts with aluminium to produce aluminium oxide and iron. The balanced chemical equation for the given reaction is : Fe2O3 + 2Al → Al2O3 + 2Fe.

The land accounts of the subsidiary be reported on consolidated financial statements will be book value for parent and Fair value for Subsidiary.

Option A is correct.

A business transaction known as an acquisition occurs when one company acquires control of another. These exchanges are a centerpiece of consolidations and acquisitions (M&A), a profession way in corporate regulation or money that spotlights on the purchasing, selling, and combination of organizations.

An obtaining is characterized as a corporate exchange where one organization buys a part or another organization's all's portions or resources. Acquisitions are regularly made to assume command over, and expand on, the objective organization's assets and catch collaborations.

Incomplete question :

In an acquisition where 100% control is acquired, how would the land accounts of the parent and the land accounts of the subsidiary be reported on consolidated financial statements on the date of acquisition?

A. Book value for both parent and subsidiary

B. Book value for parent, fair value for subsidiary

C. Fair value for subsidiary, book value for parent

D. Fair value for both parent and subsidiary

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Answer:

They are stronger than hydrogen bonding forces

Answer:

They occur between polar molecules.

Explanation:

I was answering the test and searched through my notes. This is the correct one.

Proof:

Check the attached picture.

GIVEN :

• Volume ,(V1)= 100ml

• Concentration ,(C1) = 2.50 M

• Concentration ,(C2) = 0.75 M

• Volume ,(V2) = ?

The relationship between Volume and Concentration can be represented by formula :

Replacing the given parameters into the formula above , Final Volume (V2) will be :

None of the above.

The energy difference between two energy levels in the hydrogen atom is given by the equation:

ΔE = E₂ - E₁ = -R_H(1/n₂² - 1/n₁²)

where ΔE is the energy difference, E₂ and E₁ are the energy levels, R_H is the Rydberg constant, and n₂ and n₁ are the principal quantum numbers.

In this case, the photon with a wavelength of 122 nm can excite the electron from n=1 to n=2. To determine if other photons can also excite the electron to the same level, we can use the equation:

λ = c / ν

where λ is the wavelength, c is the speed of light, and ν is the frequency of the photon.

Using the given wavelength values, we can calculate the corresponding frequencies and then determine if the energy difference matches the required energy to excite the electron from n=1 to n=2.

Calculating the frequencies and energy differences for the given wavelengths, we find:

For 244 nm:

ν = c / λ = (3.00 x 10^8 m/s) / (244 x 10^(-9) m) ≈ 1.23 x 10^15 Hz

ΔE = E₂ - E₁ = -R_H(1/n₂² - 1/n₁²) = -R_H(1/2² - 1/1²) = -R_H(1/4 - 1) = 3/4 R_H

For 61 nm:

ν = c / λ = (3.00 x 10^8 m/s) / (61 x 10^(-9) m) ≈ 4.92 x 10^15 Hz

ΔE = E₂ - E₁ = -R_H(1/n₂² - 1/n₁²) = -R_H(1/2² - 1/1²) = -R_H(1/4 - 1) = 3/4 R_H

For 94 nm:

ν = c / λ = (3.00 x 10^8 m/s) / (94 x 10^(-9) m) ≈ 3.19 x 10^15 Hz

ΔE = E₂ - E₁ = -R_H(1/n₂² - 1/n₁²) = -R_H(1/2² - 1/1²) = -R_H(1/4 - 1) = 3/4 R_H

Conclusion:

None of the calculated energy differences match the required energy difference to excite the electron from n=1 to n=2, which is 3/4 R_H. Therefore, none of the given wavelengths can be used to excite the electron from n=1 to n=2.

None of the above statements are true. The given wavelengths cannot be used to excite the electron from n=1 to n=2 in hydrogen.

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