how is it possible to get a 2000-v emf from a 12-volt battery?

Answers

Answer 1

Get a 12-volt battery to produce a 2000-v emf. A 2Amp current is currently flowing through the battery while it charges.

Provided are the battery's EMF at 12 volts, internal resistance at 0.5 ohms, and terminal voltage at 13 volts.

When the terminal voltage exceeds the battery's EMF, the battery is charging and currents can flow in the opposite direction.

ΔV = E - Ir

The formula is: ΔV - E = -Ir

13 - 12 = -0.5I 1 = -0.5I I = 1 / -0.5 I = -2 A.

The negative symbol denotes a stream flowing in the opposite direction.

As a result, the battery is charging and a 2Amp current is flowing through it. utilizing an induced EMF and a step-up transformer operation volt battery. A magnetic field is produced in the coil's core by current flowing through the 12 volt coil.

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Related Questions

A box of books weighing 315 N is shoved across the floor by a force of 477 N exerted downward at an angle of 35° below the horizontal. If the coefficient of kinetic friction between the box and the floor is 0.58, how long does it take to move the box 4.20 m starting from rest?

Answers

Answer:

It takes 1.14 s to move the box 4.20 m.

Explanation:

Using Newton's second law we have:

\(Fcos(35)-F_{f}=ma\)

\(Fcos(35)-\mu mg=ma\)

F is the force exerted and m the mass of the books

\(Fcos(35)-\mu mg=ma\)

\(477cos(35)-(0.58*315)=\frac{315}{9.81}a\)

So, the books accelerate at:

\(a=6.48\: m/s^{2}\)

We know that the initial velocity is zero, so using the kinematic position equation, we have:

\(x=\frac{1}{2}at^{2}\)

So, we just need to solve the equation for t.

\(4.2=\frac{1}{2}6.48t^{2}\)

\(t=\sqrt{\frac{2*4.2}{6.48}}\)

Taking the positive value of t:

\(t=1.14\: s\)

Therefore, it takes 1.14 s to move the box 4.20 m.

I hope it helps you!

A block of wood is kept on table top. The mass of wooden block is 5 kg and its dimensions are 40cmx20cmx10cm. 1. Calculate the area of the wooden block in cm2 and in2. 2. Calculate the volume of the wooden block in cm3 and in3. 3. Compute the density of the wooden block in g/cm3 and lb/in3. 4. Compute the pressure. 5. Compute the pressure on top surface of the wooden block. 6. Compute the pressure on the bottom surface of the wooden block. 7. Compute the force on top surface of the wooden block. 8. Compute the force on the bottom surface of the wooden block. 9. What is the difference between the force on the bottom and the force on top?

Answers

Let's calculate the values based on the given information:

The area of the wooden block can be calculated by multiplying the length and width of one of its faces:

Area = Length * Width

Area = 40 cm * 20 cm

Area = 800 cm²

To convert to square inches, we can use the conversion factor 1 inch = 2.54 cm:

Area in square inches = Area in square centimeters / (2.54 cm/inch)²

Area in square inches = 800 cm² / (2.54 cm/inch)²

Area in square inches ≈ 124.03 in²

The volume of the wooden block can be calculated by multiplying its length, width, and height:

Volume = Length * Width * Height

Volume = 40 cm * 20 cm * 10 cm

Volume = 8000 cm³

To convert to cubic inches, we can use the conversion factor 1 inch = 2.54 cm:

Volume in cubic inches = Volume in cubic centimeters / (2.54 cm/inch)³

Volume in cubic inches = 8000 cm³ / (2.54 cm/inch)³

Volume in cubic inches ≈ 488.19 in³

The density of the wooden block can be calculated by dividing its mass by its volume:

Density = Mass / Volume

Density = 5 kg / 8000 cm³

To convert to grams per cubic centimeter (g/cm³), we can use the conversion factor 1 kg = 1000 g:

Density in g/cm³ = Density in kg/cm³ * 1000 g/kg

Density in g/cm³ = (5 kg / 8000 cm³) * 1000 g/kg

Density in g/cm³ ≈ 0.625 g/cm³

To convert to pounds per cubic inch (lb/in³), we can use the conversion factor 1 kg = 2.20462 lb and 1 inch = 2.54 cm:

Density in lb/in³ = Density in kg/cm³ * (2.20462 lb/kg) / (2.54 cm/inch)³

Density in lb/in³ = (5 kg / 8000 cm³) * (2.20462 lb/kg) / (2.54 cm/inch)³

Density in lb/in³ ≈ 0.036 lb/in³

Pressure is defined as force divided by area. In this case, we need more information to calculate the pressure. If the block is subjected to a specific force, we can divide that force by the appropriate surface area to find the pressure.

The pressure on the top surface of the wooden block depends on the force applied to it. Without information about the applied force, we cannot calculate the pressure.

Similarly, the pressure on the bottom surface of the wooden block depends on the force applied to it. Without information about the applied force, we cannot calculate the pressure.

The force on the top surface of the wooden block depends on the pressure applied and the surface area. Without information about the pressure or force applied, we cannot calculate the force.

The force on the bottom surface of the wooden block depends on the pressure applied and the surface area. Without information about the pressure or force applied, we cannot calculate the force.

Without the values for forces on the top and bottom surfaces, we cannot determine the difference between them.

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The area of the wooden block is 2800 cm² and 434.96 in².The volume of the wooden block is 8000 cm³ and 487.61 in³.The density of the wooden block is 0.625 g/cm³ and 0.0226 lb/in³.The pressure on the wooden block is 0.06125 N/cm² and 0.0089 psi.The pressure on the top surface of the wooden block is 0.06125 N/cm² or 0.0089 psi.The pressure on the bottom surface of the wooden block is 0.06125 N/cm² or 0.0089 psi.The force acting on the top surface of the wooden block is 49 N.The force acting on the bottom surface of the wooden block is 49 N.The force on the bottom surface is equal in magnitude to the force on the top surface.

1. The area of the wooden block can be calculated using the formula for the surface area of a rectangular prism: SA = 2(lw + lh + wh), where l, w, and h are the length, width, and height of the block, respectively. Using the given dimensions, we can find the surface area in cm²:

SA = 2(40 × 20 + 40 × 10 + 20 × 10)

SA = 2(800 + 400 + 200)

SA = 2(1400)

SA = 2800 cm²

To convert cm² to in², we can use the conversion factor 1 in² = 6.45 cm². So, the area in in² is:

2800 ÷ 6.45 = 434.96 in² (rounded to two decimal places)

2. The volume of the wooden block can be calculated using the formula for the volume of a rectangular prism: V = lwh. Using the given dimensions, we can find the volume in cm³:

V = 40 × 20 × 10

V = 8000 cm³

To convert cm³ to in³, we can use the conversion factor 1 in³ = 16.39 cm³. So, the volume in in³ is:

8000 ÷ 16.39 = 487.61 in³ (rounded to two decimal places)

3. The density of the wooden block can be calculated using the formula: density = mass/volume. The mass of the block is given as 5 kg. To convert this to grams, we can use the conversion factor 1 kg = 1000 g. So, the mass in grams is:

5 kg × 1000 g/kg = 5000 g

Using the volume calculated in part 2, we can find the density in g/cm³:

density = 5000 g/8000 cm³

density = 0.625 g/cm³

To convert g/cm³ to lb/in³, we can use the conversion factor 1 g/cm³ = 0.0361 lb/in³. So, the density in lb/in³ is:

0.625 g/cm³ × 0.0361 lb/in³/g/cm³ = 0.0226 lb/in³

4. The pressure on the wooden block is given by the formula: pressure = force/area. To find the pressure, we need to know the force acting on the block. Since the block is simply resting on the tabletop, the force acting on it is due to its weight. Using the formula for weight: w = mg, where w is weight, m is mass, and g is the acceleration due to gravity (9.8 m/s²).

To find the weight in newtons (N), we can use the conversion factor 1 kg = 9.8 N. So, the weight of the block is:

5 kg × 9.8 N/kg = 49 N

Using the area of the block's base (40 cm × 20 cm = 800 cm²), we can find the pressure in N/cm²:

pressure = 49 N/800 cm²

pressure = 0.06125 N/cm²

To convert N/cm² to psi, we can use the conversion factor 1 psi = 6894.76 N/m². So, the pressure in psi is:

0.06125 N/cm² × (1 m²/10,000 cm²) × (1 psi/6894.76 N/m²) = 0.0089 psi (rounded to four decimal places)

5. The pressure on the top surface of the wooden block is the same as the pressure calculated in part 4: 0.06125 N/cm² or 0.0089 psi.

6. To find the pressure on the bottom surface of the block, we can use the formula: pressure = force/area. Since the bottom surface has the same area as the top surface, the pressure will also be the same: 0.06125 N/cm² or 0.0089 psi.

7. The force acting on the top surface of the wooden block is simply its weight, which we calculated to be 49 N in part 4.

8. The force acting on the bottom surface of the wooden block is also its weight, which we calculated to be 49 N in part 4.

9. The force on the bottom surface is equal in magnitude to the force on the top surface.

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if the hair feels rough when performing a porosity test, it means the cuticle is:

Answers

If the hair feels rough when performing a porosity test, it means the cuticle is raised or damaged. The porosity test involves running your fingers along a strand of hair from the ends to the roots to determine how easily it absorbs water.

If the hair feels rough, it indicates that the cuticle layer is not smooth and intact, which can lead to moisture loss, breakage, and damage. This could be due to various factors, including chemical treatments, excessive heat styling, environmental stressors, or lack of proper hair care. It is important to address the underlying causes of rough cuticles to improve the overall health and appearance of the hair.


If the hair feels rough when performing a porosity test, it means the cuticle is raised. Raised cuticles indicate high porosity, which means that the hair can easily absorb and lose moisture. High porosity hair is often the result of chemical treatments, heat damage, or environmental factors. To manage high porosity hair, it is important to use deep conditioning treatments and protein treatments regularly. Additionally, using leave-in conditioners and sealing the hair with oils can help lock in moisture and protect the cuticles. It is also recommended to avoid harsh chemicals and excessive heat styling to prevent further damage.

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when placing all fingers and the palm in contact with the object being lifted, you are using which of the following? question 1 options: a) vise grip b) lock grip c) power lift d) power grip

Answers

I use a power lift when all of my fingers and my palm are in contact with the object I'm lifting.

What posture should your hand be in during a power lift?

Put your hand on the side of the object that is farthest away from you. It should be on the same side of your body as your forward foot. The most popular technique for good lifting is this lift. When there is sufficient space to adopt a wide stance and the object is small enough to be straddled, utilise the basic lift. 7.

How are your palms positioned when employing the power grip?

Each hand should be inserted under the handle with the palm facing up and the thumb pointing upward for a power grip. Never attempt to lift a stretcher or palm facing down over the handle of the backboard.

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The Ptolemaic model of the Solar System has each planet moving along a circular epicycle whose center, in turn, moves around the Earth

Answers

The Ptolemaic model was a geocentric model of the Solar System developed by the ancient Greek astronomer, mathematician, and geographer Claudius Ptolemy.

What is Ptolemaic model?

According to this model, the Earth was at the center of the universe, and all the other celestial bodies revolved around it. Each planet in the Ptolemaic model was believed to move along a circular path called an "epicycle," which was centered on a point called the "deferent." The deferent, in turn, moved along a circular path around the Earth, called the "eccentric." The epicycle's center moved along the deferent at a constant rate, which gave the appearance of retrograde motion of the planet relative to the Earth. The Ptolemaic model was a complex and intricate system that required numerous epicycles, deferents, and eccentrics to explain the observed motions of the planets. While it was able to account for some of the observed planetary motions with reasonable accuracy, it had limitations and inaccuracies that became apparent as observations became more precise over time.

Here,

Eventually, the Ptolemaic model was replaced by the heliocentric model developed by Nicolaus Copernicus, which placed the Sun at the center of the Solar System and explained the observed motions of the planets more accurately.

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The weight of a body kept at a distance of 6400 km from the centre of the
earth is 10N. What will be the weight of another object kept at a distance of 12,800km ?​

Answers

Answer:

2.5N

Explanation:

since force is inversely proportional to square of the distance apart. that means the ratio of distance apart. so u have 12800×12800÷(6400××6400)=4/1

so the weight will be reduced to 1/4 of 10N

How do data collected from tree rings provide evidence for climate
change?
Why isn’t this a answer when you search it

Answers

Answer:

Climate scientists compare the tree growth records to local weather records. For locations where a good statistical match exists between tree growth and temperature or precipitation during the period of overlap, the ring widths can be used to estimate past temperature or precipitation over the lifetime of the tree.

If a fossil contains 60% of its original carbon, how old is the fossil

Answers

if im not mistaken its 5600years old

determine the moments of inertia of the rectangular area about the x- and y-axes and find the polar moment of inertia about point o.

Answers

The definition of moment of inertia allows for the following results for the moment of inertia with respect to each axis:

1-Iₓ = m r²

2-Iy=9m r²

3-Iz=10m r².

What exactly is moment interia?

The expression yields the moment of interia as a scalar quantity.

Sol-

I =∫ r² dm

Where I is the moment of inertia, m is the body's mass, and r is the distance from the axis of rotation.

In the case of point particles, the expression is as follows:

I = m r²

In this case, we calculate along each coordinate axis.

a) The distance is x = r with respect to the x axis, and the moment of inertia is

Iₓ = m r²

indicate the distance in relation to the y-axis

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when a certain liquid freezes, it expands about 11.0%. what would be the pressure increase inside an engine block if the liquid in it froze? (the bulk modulus of the liquid when it solidifies is 1.70 109 n/m2.)

Answers

When a certain liquid freezes and expands by about 11.0%, the pressure increase inside an engine block is

To determine the pressure, you would follow these steps:

1. Calculate the fractional volume change: Since the liquid expands by 11.0%, the fractional volume change (∆V/V) is 0.11.

2. Apply the bulk modulus formula: The bulk modulus (K) is a property of the material that describes how its volume changes under pressure.

The formula relating pressure change (∆P), fractional volume change (∆V/V), and bulk modulus (K) is:
∆P = -K (∆V/V)

3. The bulk modulus of the liquid when it solidifies is 1.70 x 10^9 N/m^2, and the fractional volume change is 0.11. Using the formula from step 2:
∆P = - (1.70 x 10^9 N/m^2) (-0.11)

4. Calculate the pressure increase: Multiply the bulk modulus by the fractional volume change:
∆P = (1.70 x 10^9 N/m^2) (0.11) = 1.87 x 10^8 N/m^2

So, the pressure increase inside the engine block when the liquid in it freezes and expands by about 11.0% is 1.87 x 10^8 N/m^2.

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what is transfered when work is done

Answers

Answer:

energy

Explanation:

work is the involves energy transfer when an object is moved over a distance

Answer:

Energy

Explanation: When a force causes a body to move, work is done on the object by the force. Work is the measure of the energy transfer when a force ‘F’ moves an object through a distance ‘d’. So we say that energy is transferred from one energy store to another when work is done, and therefore, energy transferred = work done.

rank the automobiles based on the magnitude of the force needed to stop them, from largest to smallest. rank from largest to smallest. to rank items as equivalent, overlap them. if the ranking cannot be determined, check the box below.

Answers

The ranking of the cars from the largest to smallest based on the linear momentum, size of impulse and force needed to stop them is,

Light blue car = Purple car > Red car = Yellow car =  Blue car > Green car

The linear momentum of each car can be  calculated by;

P = mu

where;

m is the mass of the automobile

u is linear speed of the automobile

The linear momentum of the Red car is given as;

P = 1000 x 10 = 10, 000 kg.m/s

The linear momentum of the Yellow car is given  as;

P = 2,000 x 5 = 10,000 kg.m/s

The linear momentum of the Blue car is given as;

P = 500 x 20 = 10,000 kg.m/s

The linear momentum of the Light blue car is given as;

P = 1,000 x 20 = 20,000 kgm/s

The linear momentum of the Green car is given  as;

P = 500 x 10 = 5,000 kg.m/s

The linear momentum of the Purple car is given  as;

P = 4,000 x 5 = 20,000 kg.m/s

we can defined Impulse as the change in linear momentum;

J = ΔP

J = m(u - v)

J = mu = P

The force needed to stop each car is directly proportional to the impulse needed to stop the car.

Force x t = J

where;

t is the time of motion

Thus, we can conclude that the linear momentum of each car is directly proportional to the impulse and force needed to stop it.

P ∝ J ∝ Force

Ranking the cars from the largest to smallest based on the linear momentum, size of impulse and force needed to stop them;

Light blue car = Purple car > Red car = Yellow car =  Blue car > Green car

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Complete question:

Six automobiles are initially traveling at the indicated velocities. The automobiles have different masses and velocities. The drivers step on the brakes and all automobiles are brought to rest. Red Car: 1000kg, 10m/s Yellow Car: 2,000kg, 5m/s Blue Car: 500kg, 20m/s Light Blue Car: 1,000kg, 20m/s Green Car: 500kg, 10m/s Purple Car: 4,000kg, 5m/s Part A Rank these automobiles based on the magnitude of their momentum before the brakes are applied, from largest to smallest. Rank from largest to smallest. To rank items as equivalent, overlap them. Part B Rank these automobiles based on the magnitude of the impulse needed to stop them, from largest to smallest. Rank from largest to smallest. To rank items as equivalent, overlap them. Part C Rank the automobiles based on the magnitude of the force needed to stop them, from largest to smallest. Rank from largest to smallest. To rank items as equivalent, overlap them. if the ranking cannot be determined, check the box below.

Which scientific activities will Juno conduct on its trip to Jupiter? Check all that apply.
a. measuring the amount of water in Jupiter’s atmosphere
b. landing on the planet surface to collect rock samples
c. taking images of the planet using infrared cameras
d. taking chemical “fingerprints” of Jupiter’s gases
e. mapping Jupiter’s gravitational and magnetic field
f. transporting astronauts to the planet

Answers

Explanation:

Hope this helps,

Juno entered a polar orbit of Jupiter on July 5th 2016 UTC, to begin a scientific investigation of the planet. After completing its mission, Juno will be intentionally deorbited into Jupiters atmosphere. Junos mission is to measure Jupiters composition, gravitational field, magnetic field, and polar magnetosphere.

Answer:

1

3

4

5

or

a

c

d

e

Explanation:

Stars are held together by the force ___, ___ and the composition determine the amount of ___.

Answers

A star is a large ball of gas that generates its own energy by fusing hydrogen atoms to make helium. It is held together by its own gravity. ... Stars come in a variety of sizes and compositions, which determine their amount of energy and gravity.

A line with a negative slope on a distance-time graph means the object is?​

Answers

Answer:negative slope or gradient I think

Explanation:

a line with any negative slope on a distance time graph means that the object is moving at a constant speed (if the line is straight) but in the reverse discretion.

A free-body diagram represents forces acting on a system.
Question 20 options:
True
False

Answers

Answer:

False because free-body diagram is a sketch of only the object in question and the forces acting upon it, to scale.

It would be false !!!!!!!!!!

Cart A has mass M and is released from rest at a height 2H on a ramp making an angle 2 with the horizontal, as shown above. Cart B has mass 2M and is released from rest at a height H on a ramp making an angle with the horizontal. The carts roll toward each other, have a head- on collision on the horizontal portion of the ramp, and stick together. The masses of the carts’ wheels are negligible, as are any frictional or drag forces.

a.) Derive an expression to determine the velocity of Cart A in terms of the variables given in the prompt.

b.) Derive an expression to determine the velocity of Cart B in terms of the variables given in the prompt.

c.) Determine the final velocity of the carts after the collision.

d.) Is the collision elastic or inelastic? Justify your answer.

*Answers should not include numbers, only variables.

Cart A has mass M and is released from rest at a height 2H on a ramp making an angle 2 with the horizontal,

Answers

a) The expression to determine the velocity of cart A is \(v_{A} = 2\cdot \sqrt{g\cdot H}\).

b) The expression to determine the velocity of cart B is

\(v_{B} =\sqrt{2\cdot g\cdot H }\).

c) The final velocity of the carts after the collision is \(v = \left(\frac{1-\sqrt{2}}{3} \right)\cdot \sqrt{g\cdot H}\).

d) The collision is inelastic since a part of the energy of the entire system is lost when they stick together.

Study of an inelastic collision

In this question we shall apply principle of energy conservation and principle of linear momentum conservation to model an inelastic collision between two carts.

a) The combination of cart and ramp can be considered a conservative system as there are no non-conservative forces (i.e. friction), the final velocity of cart A (\(v_{A}\)) is related to the change in gravitational potential energy:

\(\frac{1}{2}\cdot M\cdot v_{A}^{2} = M\cdot g \cdot 2\cdot H\) (1)

Now we clear \(v_{A}\) and simplify the resulting expression:

\(v_{A} = 2\cdot \sqrt{g\cdot H}\)

The expression to determine the velocity of cart A is \(v_{A} = 2\cdot \sqrt{g\cdot H}\). \(\blacksquare\)

b) We apply the same approach used in part b) to find the final velocity:

\(\frac{1}{2}\cdot (2\cdot M) \cdot v_{B}^{2} = (2\cdot M)\cdot g \cdot H\) (2)

Now we clear \(v_{B}\) and simplify the resulting expression:

\(v_{B} =\sqrt{2\cdot g\cdot H }\)

The expression to determine the velocity of cart B is

\(v_{B} =\sqrt{2\cdot g\cdot H }\). \(\blacksquare\)

c) The final velocity (\(v\)system is determined by principle of linear momentum conservation:

\(3\cdot M\cdot v = M\cdot 2\cdot \sqrt{g\cdot H}-2\cdot M\cdot \sqrt{2\cdot g\cdot H}\)

\(3\cdot v = 2\cdot (1-\sqrt{2})\cdot \sqrt{g\cdot H}\)

\(v = \left(\frac{1-\sqrt{2}}{3} \right)\cdot \sqrt{g\cdot H}\)

The final velocity of the carts after the collision is \(v = \left(\frac{1-\sqrt{2}}{3} \right)\cdot \sqrt{g\cdot H}\). \(\blacksquare\)

d) The collision is inelastic since a part of the energy of the entire system is lost when they stick together. \(\blacksquare\)

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PLS HURRY
The photo shows a roller coaster. Assume the system is closed. Which roller-coaster car has the least potential energy due to gravity?
A. Car A
B. Car B
C. Car C
D. Car D

PLS HURRY The photo shows a roller coaster. Assume the system is closed. Which roller-coaster car has

Answers

Answer: it's rather A or B

Explanation: those are the moments it stops but most likely it is answer A.

An inductor is connected to a 20 kHz oscillator that produces an rms voltage of 9.0 V. The peak current is 60 mA. What is the value of the inductance L? Final answer in mH. Please explain step by step.

Answers

The value of the inductance L is approximately 1193.25 mH.

To solve for the value of the inductance L, we can use the formula:

Vrms = Ipeak * (2 * pi * f * L)

where:

Vrms = 9.0 V

Ipeak = 60 mA = 0.06 A

f = 20 kHz

Substituting the values into the formula:

9.0 V = 0.06 A * (2 * pi * 20,000 Hz * L

Simplifying:

L = 9.0 V / (0.06 A * 2 * pi * 20,000 Hz)

L = 9.0 / (0.007536)

L = 1193.25 mH (rounded to two decimal places)

Therefore, the value of the inductance L is approximately 1193.25 mH.

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An inductor is connected to a 20 kHz oscillator that produces an RMS voltage of 9.0 V. The peak current is 60 mA. The value of the inductance L is  1.692 mH.

Let's start by using the given information and then we'll solve for the value of the inductance L step by step:
1. Frequency of the oscillator (f) = 20 kHz = 20,000 Hz
2. RMS voltage (Vrms) = 9.0 V
3. Peak current (I_peak) = 60 mA = 0.06 A
Now, let's find the peak voltage (V_peak) using the relationship between RMS voltage and peak voltage:
Vrms = V_peak / √2
V_peak = Vrms * √2
V_peak = 9.0 V * √2 ≈ 12.73 V
Next, we'll calculate the impedance (Z) of the inductor using Ohm's law, which relates peak voltage and peak current:
Z = V_peak / I_peak
Z ≈ 12.73 V / 0.06 A ≈ 212.17 Ω
Now, we'll use the formula for the impedance of an inductor:
Z = 2 * π * f * L
Let's solve for the inductance L:
L = Z / (2 * π * f)
L ≈ 212.17 Ω / (2 * π * 20,000 Hz)
L ≈ 1.692 × 10^-3 H
Finally, convert the inductance L to millihenries (mH):
L ≈ 1.692 mH
So, the value of the inductance L is approximately 1.692 mH.

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It takes serina 0.25 hours to drive to school. Her route is 16km long . What is serina’s average speed on her drive to school

Answers

Explanation:

distance=16km=16000m

time=0.25hours=1/4hr=15min=900sec

speed=dist./time

=16000/900=160/9=17.777m/s

speed=17.78m/s (rounded)

Answer:

64

Explanation:

Avg. speed = total distance/total time

Avg. speed= 16km/0.25h

Avg. speed= 64km/h

Please help me↓
This topographical map has contour lines 5 ft of elevation (height above sea level) apart; the numbers on the thicker lines are elevation in feet. What is the difference in elevation between the two points marked?
Point II is 45 ft lower.
Point II is 10 ft lower.
Point II is 10 ft higher.
Point II is 45 ft higher.

Please help meThis topographical map has contour lines 5 ft of elevation (height above sea level) apart;

Answers

Answer:

unmmm u can say that it is going mt 15s

Answer: Did you get the answer?

Explanation:

(PLEASE HELP ILL GIVE OUT BRAINLIEST) Mr. Hicks stands on top of the roof and drops water ball oons at passing students. He misses with one and the balloon bursts on the pavement below, 1.84 seconds later. What
was the velocity of the balloon just before it hits the pavement? How far did the balloon drop?

Answers

Answer:

18.032m/s, 16.59m

Explanation:

Used to find the distance traveled

y=1/2gt^2, where y= vertical distance, g=acceleration due to gravity, and t=time

y=1/2*9.8*1.84^2

y=16.59m distance

Used to solve the final velocity before hitting the ground

vf=vo+at where vf=final velocity, vo=initial velocity, a=acceleeration, t=time

vf=0+9.8*1.84

vf=18.032m/s

What is the sign of the charge in this figure? a)positive b)You cannot tell from the information given. c) negative d) neutral​

What is the sign of the charge in this figure? a)positive b)You cannot tell from the information given.

Answers

Answer:

Explanation:

C

In charging by induction, a charged object is brought near an object without touching it. The presence of the charge object induces electron movement and a polarization of the object. Then conducting pathway to ground is established and electron movement occurs between the object and the ground. During the process, the charged object is never touched to the object being charged.

.The separation of white light into its component colors is called _____
A. diffraction.
B. reflection.
C. dispersion.
D. refraction.
E. polarization.

Answers

C.Dispersion hope it helps

What is the mass of an object that experiences a gravitational force of 685 n near earth's surface where g = 9.80 m/s2?

Answers

The mass of an object that experiences a gravitational force of 685 N near earth's surface where g = 9.80 m/s² is 98.89 kg.

What is gravitational force?

Any two mass-containing objects are attracted to one another by the gravitational force. Because it consistently attempts to pull masses together rather than pushing them apart, the gravitational force is known as attractive.

In reality, everything in the cosmos is tugging on everything else, including you!

According to the question,

The gravitational force of 685 N near earth's surface.

The acceleration due to gravity is  g = 9.80 m/s².

The formula for force acting of the body under the influence of gravitation is ;

Force = mass×acceleration

Substitute the given values;

685 = m×9.8

m = 685/9.8

m = 69.89 kg.

Therefore, mass of an object is 69.89 kg.

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Newton's 3rd Law of Motion
For every__________ (or force), there is an ____________ and __________ action (or force).

Answers

Answer:

Explanation:

For every action (or force), there is an equal and opposite action (or force).

Is gravitational energy a form of kinetic energy or potential energy? Why do you think that?

Please help due today!!​

Answers

Answer:

When something is lifted, work is done on the object against the pull of gravity. This work is converted to a form of potential energy called gravitational potential energy. When the item falls towards Earth like an apple from a tree, gravitational potential energy is converted into kinetic energy.

This armed
rover weighs 1900 N
and has a mass of
340 kg. What is the
acceleration due to gravity
on its current planet?
Please help

Answers

Answer:

5.59 m/s2

Explanation:

F = 1900 N

m = 340 kg

F = ma

Therefore, a = 1900/340 = 5.59

A lathe, initially at rest, accelerates at for, then runs at a constant angular velocity for, and finally decelerates uniformly for to come to a complete stop. What is its average angular velocity

Answers

The average angular velocity of the lathe is 3.75 rad/s.

First, we can find the final angular velocity of the lathe at the end of the constant velocity phase by using the kinematic equation:

ωf = ωi + αt

where ωi is the initial angular velocity (which is zero in this case), α is the angular acceleration (\(0.60 rad/s^2)\), and t is the time it takes to reach the constant velocity (10 s):

ωf = 0 + 0.60 rad/s^2 * 10 s = 6.0 rad/s

Next, we can use the constant velocity phase to find the total angle turned by the lathe during this period, which is given by:

θ2 = ω * t2

where ω is the constant angular velocity during this period (which is also 6.0 rad/s) and t2 is the time period (20 s):

θ2 = 6.0 rad/s * 20 s = 120 rad

Finally, we can use the deceleration phase to find the total angle turned by the lathe during this period, which is given by:

θ3 = ωf * t3 + (1/2) * (-α) * t3^2

where ωf is the final angular velocity (6.0 rad/s), α is the angular deceleration (-0.60 rad/s^2), and t3 is the time period (10 s):

θ3 = 6.0 rad/s * 10 s + (1/2) * (-0.60 rad/s^2) * (10 s)^2 = 30 rad

The total angle turned by the lathe is therefore:

Δθ = θ1 + θ2 + θ3 = 0 + 120 rad + 30 rad = 150 rad

The total time taken by the lathe is:

Δt = t1 + t2 + t3 = 10 s + 20 s + 10 s = 40 s

Therefore, the average angular velocity of the lathe is:

ω_avg = Δθ / Δt = 150 rad / 40 s = 3.75 rad/s

So the average angular velocity of the lathe is 3.75 rad/s.

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Full  Question: A lathe, initially at rest, accelerates at 0.60 rad/s^2 for 10 s, then runs at a constant angular velocity for 20 s, and finally decelerates uniformly for 10 s to come to a complete stop. What is its average angular velocity?

can someone help me asap please​

can someone help me asap please

Answers

Answer:

Resultant force is 20 N

Explanation:

Resolving vertically:

\({ \sf{F_{y} = (8 \cos 30 \degree) + (12 \cos 30 \degree) }} \\ { \sf{ \sum F_{y} = 17.3 \: newtons }}\)

Resolving horizontally:

\({ \sf{F_{x} = (8 \sin 30 \degree) + (12 \sin 30 \degree) }} \\ { \sf{ \sum F _{x} = 10 \: newtons}}\)

Resultant force:

\({ \boxed{ \bf{F = \sqrt{ {F _{x} }^{2} + {F _{y} }^{2} } }}} \\ { \sf{F = \sqrt{ {17.3}^{2} + {10}^{2} } }} \\ { \sf{F = \sqrt{399.29} }} \\ F = 19.98 \approx20 \: newtons\)

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