How far is A(7,8) from B(13, 16)?

Answer:

what is the complete question?

In mathematics, "\(a^2\)" denotes the square of a number or variable "a." It is calculated by multiplying "a" by itself.

4For example, if "a" is 5, then a^2 would be 5*5, which equals 25. When "a" represents a positive number, its square is always positive.

If "a" is negative, its square is still positive since a negative multiplied by a negative results in a positive.

In geometrical terms, if "a" represents the length of the side of a square, then a^2 represents the area of that square. This notation is part of the general concept of exponentiation.

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The Question in English

What does a^2 mean in mathematics

Answer:

(12,0)

Step-by-step explanation:

So whenever you are asked for an "intercept" it is the point where a line crosses the axis. The x intercept is where the line crosses at the x axis (horizontal line on the graph) and the y intercept is where the y axis crosses (vertical axis).

So this question is really asking where is the point when y = 0

The x values in the chart are 5 apart-- 22 +5 = 27, 27+ 5 = 32

The y values are 18 apart --> 36 + 18 = 54, 54+ 18 = 72

Make a little chart where y = 0 (this is where the x crosses) and you can see

there is a point at (17, 18) and then (12, 0) and that point is the x intercept.

Answer:

(12, 0)

Step-by-step explanation:

the x-intercept is the point, where y=0.

so, the second coordinate is therefore 0, no matter what.

now, at what x is that ?

let's find the line function.

a line is

y = a×x + b

let's use the first point (22, 36)

36 = a×22 + b

a = (36 - b)/22

let's use the second point (27, 54)

54 = a×27 + b

now we use the first expression describing a in terms of b and insert that into the second expression.

54 = 27×(36 - b)/22 + b

54×22 = 27×(36 - b) + 22b = 972 - 27b + 22b

1188 = 972 - 5b

216 = -5b

b = -43.2

=>

a = (36 - -43.2)/22 = (36 + 43.2)/22 =79.2/22 = 3.6

our line is

y = 3.6x - 43.2

so, now back to the question, at what x is y=0 ?

0 = 3.6x - 43.2

3.6x = 43.2

x = 12

To find the value of x when (fog)(x) = -8, we first need to find the composition of f and g, which is given by (fog)(x) = f(g(x)). To do this, we substitute g(x) into the expression for f(x) and simplify:

f(g(x)) = f(1) when g(x) = 1

f(g(x)) = f(-2) when g(x) = -2

f(g(x)) = f(3) when g(x) = 3

f(g(x)) = f(-4) when g(x) = -4

f(g(x)) = f(4) when g(x) = 4

There is no value of x for which (fog)(x) = -8.

Using the table given in the question, we can find the values of f(g(x)) for each possible value of g(x):

f(g(x)) = f(1) = -2

f(g(x)) = f(-2) = 0

f(g(x)) = f(3) = 32

f(g(x)) = f(-4) = 8

f(g(x)) = f(4) = 4

Therefore, (fog)(x) = -8 is not possible. The closest value we can get to -8 is by setting g(x) = -4, which gives f(g(x)) = f(-4) = 8. Thus, there is no value of x for which (fog)(x) = -8.

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The dual linear program is as follows:

y1 + 4y2 - w1 = 1

2y1 + 3y2 + w2 = -2

-y1 + 4y2 + 2y3 >= 1

y1 - 2y3 <= 0

y2, y3 >= 0

The primal linear program is:

x1 + 2x2 - x3 + x4 >= 0

4x1 + 3x2 + 4x3 - 2x4 <= 3

-x1 - x2 + 2x3 + x4 = 1

x2, x3 >= 0

To find the dual, we introduce dual variables y1, y2, and y3 for the primal's three constraints, and w1 and w2 for the primal's two non-negativity constraints on x2 and x3, respectively.

The dual linear program is:

maximize 0y1 + 3y2 + y3

subject to:

y1 + 4y2 - w1 = 1

2y1 + 3y2 + w2 = -2

-y1 + 4y2 + 2y3 >= 1

y1 - 2y3 <= 0

y2, y3 >= 0

The objective function of the dual is the sum of the products of the primal's objective coefficients and the dual variables, which gives 0y1 + 3y2 + y3. The new objective is to maximize this expression subject to the dual constraints.

Note that the dual program is also written in standard form, with all inequality constraints replaced by equality constraints and non-negativity constraints.

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Answer:

1 / 121

Step-by-step explanation:

4^0 = 1

11^2 = 121

4^0 / 11^2 = 1 / 121

Answer:

a) 30 games

b) 66 points total

c) 2.2 points/ game

d) modal goals = 1

Step-by-step explanation:

a) 2 + 10 + 7 + 6 + 3 + 2 =  30 total games

b) (2*0) + (10*1) + (7*2) + (6*3) + (3*4) + (2*5)

0 + 10 + 14 + 18 + 12 + 10 = 66 total goals

c) 66 goals/ 30 games = 2.2 goals/ games

d) highest frequency of number of goals is 1 goal

Answer:

63/2

Step-by-step explanation:

area D1*D2/2= 9*7/2= 63/2

if my answer helps please mark as brainliest.

The independent variable in either a before/after t-test or a within-subjects ANOVA is always measured on a nominal or categorical scale.

This is because these statistical tests are used to compare means of two or more related groups, where the independent variable represents the different conditions or time points in which the dependent variable is measured.

For example, in a before/after t-test comparing the effectiveness of a medication, the independent variable would be the two time points (before and after), which are categorical in nature. Similarly, in a within-subjects ANOVA comparing three different treatment conditions, the independent variable would be the three treatment conditions, which are nominal in nature.

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Step-by-step explanation:

From pythagoras triple

11, 60, 61

the missing side is 11 in.

The margin error for the given poll having 95% confidence level with sample size of 410 is equal to 3.15%.

Sample size n = 410

Confidence level = 95%

Margin of error for this poll, use the formula,

ME = Z× (√(p₁(1-p₁) / n))

where Z is the z-score corresponding to the desired level of confidence.

p₁ is the sample proportion = 0.12

Using attached z-score table,

For a 95% confidence level, the corresponding z-score is 1.96.

Substituting the given values, we get,

ME = 1.96 × (√(0.12× (1-0.12) / 410))

Simplifying the expression inside the parentheses, we get,

⇒ME = 1.96 ×  0.0160

⇒ME = 0.0315

Margin of error for this poll at the 95% confidence level is approximately 0.0315.

Therefore,  95% confidence level represents that the true proportion of people who like dogs is within 3.15% of the observed proportion of 12%.

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The probability that none of 200 women using the pill will become pregnant is found to be 0.002.

Given: Assume a birth control pill has a 97% success rate in avoiding pregnancies.

Probability that none of 200 women using the pill will become pregnant is given as

= 0.97(200)

=0.0023

=0.002

Therefore, probability that none of 200 women using the pill will become pregnant is found to be 0.002.

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Answer:

This equation is in standard form, so to make graphing easier you need to put it in y=mx+b form or slope, intercept form.

Step-by-step explanation:

I have attached a photo of what the graph would look like.

However, in the future you should know how to turn this into a slope intercept equation.

-2x+7y=-21

+2x        +2x

7y=2x-21

divide the entire equation by 7

y= 2/7x-3

That is a full equation in slope intercept form.

Hopefully this helps!

The graph of the linear equation -2x + 7y = -21 is a line passing through the points (0, -3) and (10.5, 0) which is given below.

Given a linear equation:

-2x + 7y = -21

It is required to graph the linear equation.

In order to graph this, first, it is required to find the points through which it passes.

Substitute x = 0.

7y = -21

y = -3

So, the line passes through (0, -3), which is the point where the line touches the y-axis.

Substitute y = 0.

-2x = -21

x = 10.5

So, the line passes through (10.5, 0), which is the point where the line touches the x-axis.

Draw a line passing through these points. This is the graph.

Hence, the line passes through the points (0, -3) and (10.5, 0).

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Answer:

A 5% raise can be written as 1.05 so the new salary is 25100 * 1.05 = $26355.

Answer:

y= 1\6x -5

Step-by-step explanation:

lmk if that is correct.

also that should be in slope int. form

Answer:

y=1/6x-5

Step-by-step explanation:

x-6y=30

move the x

-6y=30-x

divide all by -6

-6/-6y=30/-6 -x/-6

y=-5+1/6x

rearrange

y=1/6x-5

your answer is the second one

Answer:

digit

Step-by-step explanation:

2 + 2 = 4 the 2 is the digit and 4 is the answer

Answer:

What is your question?

______________________________

Please rate my answer and say thanks!

(a) The probability of having two or fewer accidents during one week can be calculated using the Poisson distribution with a mean of 2.

(b) The probability of having two or fewer accidents in total during a period of 2 weeks can be calculated by considering the sum of two independent Poisson random variables with a mean of 2.

(c) The probability of having two or fewer accidents each week during a period of 2 weeks can be calculated by multiplying the probabilities of having two or fewer accidents in each week, which are obtained from the Poisson distribution.

(d) To calculate the probability of having more than 120 accidents in one year, we can approximate the Poisson distribution with a normal distribution using the Central Limit Theorem and calculate the cumulative probability.

(a) To calculate the probability of having two or fewer accidents during one week, we can use the Poisson distribution formula. P(X ≤ 2) = e^(-λ) * (λ^0/0!) + e^(-λ) * (λ^1/1!) + e^(-λ) * (λ^2/2!), where λ is the mean, which in this case is 2. Plugging in the values, we get P(X ≤ 2) ≈ 0.6767.

(b) To calculate the probability of having two or fewer accidents in total during a period of 2 weeks, we consider the sum of two independent Poisson random variables.

Let Y be the total number of accidents in 2 weeks. Since the mean of a Poisson distribution is additive, the mean of Y is 2 + 2 = 4. Using the Poisson distribution formula, P(Y ≤ 2) = e^(-λ) * (λ^0/0!) + e^(-λ) * (λ^1/1!) + e^(-λ) * (λ^2/2!). Plugging in λ = 4, we get P(Y ≤ 2) ≈ 0.2381.

(c) To calculate the probability of having two or fewer accidents each week during a period of 2 weeks, we multiply the probabilities of having two or fewer accidents in each week. Since the accidents occur independently, we can use the results from part (a) twice. P(X ≤ 2 each week) = P(X ≤ 2 in week 1) * P(X ≤ 2 in week 2) ≈ 0.6767 * 0.6767 ≈ 0.4577.

(d) To calculate the probability of having more than 120 accidents in one year, we can approximate the Poisson distribution with a normal distribution using the Central Limit Theorem. The mean of the Poisson distribution is 100, and the variance is also 100.

Approximating the Poisson distribution as a normal distribution with a mean of 100 and a standard deviation of √100 = 10, we can calculate the z-score for 120. The z-score is (120 - 100) / 10 = 2. Using a standard normal distribution table or a calculator, we find that the cumulative probability of having more than 120 accidents is approximately 0.0228.

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Answer: 267.402

Step-by-step explanation:

The answer is 267.402 because 217.4 times 1.23 = 267.402.

Answer:

267 mph

Step-by-step explanation:

Multiplication

i hope this helps have a great day :)

Answer:

option B

Step-by-step explanation:

the slope is -2, so the equation must have -2x in it.

This narrows it down to option C and B

the intercept is at -5, not +5 so the correct answer is y = -2x - 5

Hence, the distance between Hawkes Meadow and Brunswick Street is roughly 11.1 kilometres (km).

Distance is a unit used to express the distances between two objects or positions. This is a scalar value that is typically stated in length units like feet, metres, kilometres, or miles. Distance between two things is a physical concept that specifies their separation; it is frequently used to estimate how much space there is between them. The shortest distance, also referred to as "as the crow flies," can be calculated either along a horizontal path or a curved path. Displacement, or the shift in an object's position from its original location to its end position, is a notion in physics that is closely connected to distance.

given

Using the data from the timetable and the calculation, we can determine how many kilometres the bus travels between Hawkes Meadow and Brunswick Street:

Distance is determined by multiplying time and speed.

According to the timetable, the bus travels from Hawkes Meadow to Othello Avenue in 15 minutes (from 14:25 to 14:32), and from Othello Avenue to Brunswick Street in 8 more minutes (i.e., from 14:32 to 14:40). Hence, it takes 15 + 8 = 23 minutes to get from Hawkes Meadow to Brunswick Street.

Also, we are informed that the bus travels at an average speed of 29 km/h between Hawkes Meadow and Brunswick Street.

To utilise the calculation, we must first divide the time in minutes by 60 to convert it to hours:

23, divided by 60 hours, or 0.3833 hours (rounded to 4 decimal places)

Hence, we can compute the distance using the following formula:

11.12 kilometres is equal to 29 km/h times 0.3833 hours (rounded to 2 decimal places)

Hence, the distance between Hawkes Meadow and Brunswick Street is roughly 11.1 kilometres (km).

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Answer:

StGraph the line using the slope and y-intercept, or two points.

Slope: −47

y-intercept: (0,−4)

x     y

−7    0

0    −4

Step-by-step explanation:

The distance between the centers of the two wheels is approximately 11.86 feet.

The length of the conveyor belt is equal to the circumference of the circle formed by each wheel plus the distance between the centers of the two wheels.

Let's call the distance between the centers of the two wheels "d". The circumference of each wheel can be calculated using the formula

C = πd

Since each wheel has a diameter of 1 foot, its radius is 0.5 feet. Therefore, the circumference of each wheel is:

C = πd = π(0.5) = 1.57 feet (approx.)

The length of the conveyor belt is given as 15 feet. So we can write

2C + d = 15

Substituting the value of C, we get

2(1.57) + d = 15

3.14 + d = 15

d = 11.86 feet

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The probability that the sample mean would be less than 100.9 months is approximately 0.9600.

We can use the central limit theorem to approximate the sampling distribution of the sample mean as a normal distribution with a mean of 97 months (the population mean) and a standard deviation of σ/√n, where σ is the population standard deviation and n is the sample size.

The standard deviation of the sampling distribution can be calculated as follows

σ/√n = √(169)/√59 = 2.065

Therefore, the z-score corresponding to a sample mean of 100.9 months is

z = (100.9 - 97) / 2.065 = 1.75

Using a standard normal distribution table or calculator, we can find that the probability of obtaining a z-score less than 1.75 is approximately 0.9599.

Therefore, the probability that the sample mean would be less than 100.9 months is approximately 0.9599.

Rounding this to four decimal places, we get

P(x < 100.9) ≈ 0.9600

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Step-by-step explanation:

Priya's mix follows the mix ratio of 3/5 (scoops of powder to cups of water).

every mix that tastes exactly the same has to have the same ratio.

so, the possible number combinations are

3/5 × x/x, x = 1, 2, 3, 4, 5, 6, ...

3 scoops to 5 cups

6 scoops to 10 cups

9 scoops to 15 cups

12 scoops to 20 cups

15 scoops to 25 cups

...

By mathematical induction, we have shown that A^p is symmetric for any positive integer p.

To prove that A^p is symmetric for any positive integer p, we will use mathematical induction.

Base case: p = 1

Since A is symmetric, we have A = A^T. Therefore, A^1 = A is also symmetric.

Inductive step

Assume that A^k is symmetric for some positive integer k. That is, (A^k)^T = A^k.

We want to show that A^(k+1) is symmetric as well. That is, we want to show that (A^(k+1))^T = A^(k+1).

We have

(A^(k+1))^T = (A^k × A)^T (by definition of A^(k+1))

= A^T × (A^k)^T (by the transpose of a product rule)

= A^T × A^k (since we assumed (A^k)^T = A^k)

= (A^k × A)^T (since A is symmetric)

= A^(k+1)

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The given question is incomplete, the complete question is:

If A is a symmetric matrix, use mathematical induction to show that the matrix A^p is also symmetric for any positive integer p.

Answer:

A

Step-by-step explanation:

In 2 months, he got 70 stamps, meaning 35 stamps per month. On the first month, he has 55 stamps by the end of the first month, and since every month he gets 35 stamps, He was given 20 Stamps to start with. It is not D since he saves 35 stamps himself every month, meaning from the beggining of that month, he had 20, and by the end had 55, since the question specifies it shows the amont of stamps at the END of the month.

Answer:

maybe its 17 but I'm not expert