How do I find the reading of the final weight of the block?

The current (in amperes) the frying pan draws from the 500 volt circuit, given that it has a resistance of 25 ohms is 60 amperes

From the question given above, the following data were obtained:

The current drawn by the frying pan can be obtained as follow:

Voltage (V) = Current (I) × resistance (R)

Inputting the given parameters, we have:

1500 = Current × 25

Divide both sides by 25

Current = 1500 / 25

Current = 60 amperes

Thus, from the above calculation we can conclude that the current drawn by the frying pan is 60 amperes

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Answer:

2.0 m/s

Explanation:

Remember that F = maF=maF, equals, m, a, where FFF is the net force, mmm is the mass of the object, and aaa is its acceleration. To solve this problem, we will need to first find the net force acting on the piano and then use F = maF=maF, equals, m, a to find the piano’s acceleration.

Hint #22 / 4

The net force is the sum of all of the forces on the piano. In this circumstance, Elvis's and Noah's forces are in the same direction, and the friction force is in the opposite direction. So, our net force equation would be:

​

=400 N+150 N−100 N

=450 N

Now, we can use F = maF=maF, equals, m, a and solve for the acceleration:

225 kg

450 N

=2.0

The acceleration of the piano is 2.0 m/s

The acceleration of the piano is 2m/s².

We know the formula for force is

F =ma

where f is force, m is mass and a is acceleration.

We need to calculate the total force used in moving the piano

F= Total force- Frictional force

F= 400N+150N-100N= 450N.

We have F=450N and m= 225kg

F=ma

450N= 225ˣ a

a= 450/225

a= 2m/s²

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Answer:

Gravitional pull or gravity

Explanation:

Its that simple

Answer:

a= 18.4m

b= 26.2m

Explanation:

Please see the attached picture for full solution.

Your resultant velocity will be along the + y - direction or north direction and has magnitude of 2 m/s.

The quantities that have both magnitude and direction are called vector quantities. Example - velocity, acceleration, force etc.

Given in the question is a plane flying at a rate of 8m/s north and the  wind is blowing 6m/s south.

In order to find the resultant, refer to the diagram attached. The north direction is represented by +y axis and south direction is represented by -y axis.

The velocity vector representing you will be [v1] = 8 j

The velocity vector representing the wind will be [v2]  = - 6 j

Resultant vector [v] = v1 - v2 [Opposite and unequal vectors]

v = 8 j - 6 j

v = 2 j

Therefore, you resultant velocity will be along the + y - direction or north direction and has magnitude of 2 m/s.

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Answer:

706 J

Explanation:

Use the gravitational potential energu equation

Eg = mgh

and sub in the values

Eg = (4kg)(9.8)(18)

Eg = 705.6

When reading the simile "Bolt runs as fast as lightning," the most appropriate visual interpretation would be that "Bolt runs very fast."

This simile compares Bolt's speed to that of lightning, which is known for its incredible swiftness. The intention is to emphasize Bolt's exceptional speed by equating it to the rapid movement of lightning.

While the simile highlights Bolt's remarkable speed, it does not specify the manner in which he runs or the impact of each step. Therefore, the options suggesting Bolt runs in a straight line, in a wavy manner, or that each step produces thunder are not directly implied by the simile itself. These additional details go beyond the comparison of speed and introduce elements that are not explicitly mentioned.

Hence, the most accurate interpretation based solely on the simile is that Bolt runs very fast, comparable to the speed of lightning.

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The aim of this study is to develop a Sun-Earth-Moon model that will serve to describe "the real and apparent movements of the Sun-Earth-Moon system and the results of these movements".

A fundamental topic in astronomy, that is difficult To properly understand the why requires three-dimensional thinking and imagination. In this context;

• Students have difficulty understanding basic concepts of astronomy; H.

such as creating seasons, phases of the moon, lunar and solar eclipses that require three-dimensional thinking must be properly understood. So to teach difficult abstract concepts,

• To solve the problem of the lack of materials and tools related to matter.

• To enhance learning retention by engaging students' multiple senses,

• Capturing concepts visually and verbally increases skills. Remember the image of this concept when you meet its verbal equivalent, or reversed. Therefore, to help students remember what they are learning,

• Have students see tools, objects, and events that they cannot see perceive with their five senses,

• Show students tools, objects, and events that they cannot reach

or bring to class,

• Attract attention and arouse interest in a topic, needed a model to grow.

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Answer:

C) If an ice cube is placed into a boiling water, then it will melt in less than 2 minutes.

Explanation:

Answer:  54.12 m

Explanation:

Answer: I like your profile picture

Explanation:

The common characteristics  of planets do Saturn and Earth share is they both have moon. Saturn have 13 moons and earth have only one moon.

Moons of planets are spatial objects which revolves around a planet and experiences gravitational pull from the planet. Both saturn and earth are planets of solar system.

The earth that is the only planet planet with living things have only one moon which is called moon itself. Earth is entirely different from the composition and nature of all other planets.

Saturn have 13 moons namely, enceladus, janus, mimas etc. Saturn have some rings made of dust and gases which are not found for any other planet. The composition and gaseous matter in saturn is different from that of earth.

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Explanation: ΔL = τ(average) * Δt
Change in angular momentum = average torque * change in time

solve for average torque for each objects
τ(average) = ΔL / Δt

Object y average torque
τy = ΔLy / Δt = 20 / 5 = 4
τy = 4

Object x average torque
τx = ΔLx / Δt = 10 / 5 = 2
τx = 2

Relates τy and τx
2τx = τy

Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey.

The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. The precise relation between torquey and torquex is torquey = 2 * torquex.

To relate torquey to torquex, we are able to use the concept of angular momentum and torque. Angular momentum is described because the manufactured from the moment of inertia and angular velocity:

L = I * ω

Differentiating this equation with an appreciation of time, we get:

dL/dt = d(I * ω)/dt

Using the product rule of differentiation, we've got:

dL/dt = I * dω/dt + ω * dI/dt

Now, we realize that torque (τ) is described because of the charge of the exchange of angular momentum:

τ = dL/dt

Substituting the expression for dL/dt in terms of angular velocity and second of inertia:

τ = I * dω/dt + ω * dI/dt

Let's denote the common price of torque for item X as torquex. Since object X has a moment of inertia I0, we can write:

torquex = I0 * dω/dt + ω * dI0/dt

Now, let's consider item Y. It has a moment of inertia 2I0. Using the identical expression, we will write:

torquey = (2I0) * dω/dt + ω * d(2I0)/dt

torquey = 2I0 * dω/dt + ω * (2 * dI0/dt)

torquey = 2I0 * dω/dt + 2ω * dI0/dt

Comparing the expressions for torquex and torquey, we will see that:

torquey = 2 * torquex

Therefore, the precise relation between torquey and torquex is;

torquey = 2 * torquex.

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The correct question is;

"Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey. The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. Which of the following expressions correctly relates torquey to torquex?"

Answer:

bc it was a universal explosion and It started the future

Explanation:

FACTS

Answer:

i wouldn't believe so.

Explanation:

because there was no room or air for the sound to move through. this is because of immense heat and the amount of hyperactive neutrons, electrons and protons clouding everywhere. This would mean that even if there was sound it would a. not travel far or b. go in a completely different direction than expected.

The magnetic field in the region is into the paper and has a magnitude of 60 mT and the tension in either wire is 0.096 N.

To find the tension in either wire, we can apply the equation for the force experienced by a current-carrying wire in a magnetic field.

The force experienced by a current-carrying wire in a magnetic field is given by the equation F = B * I * L * sin(θ), where B is the magnetic field strength, I is the current, L is the length of the wire, and θ is the angle between the wire and the magnetic field.

In this case, the wire is suspended horizontally by two vertical wires, and the magnetic field is into the paper. Since the wire is horizontal, the angle between the wire and the magnetic field is 90 degrees, so sin(θ) = 1.

The force experienced by the wire due to the magnetic field is F = B * I * L.

Given:

Current (I) = 8.0 A

Magnetic field (B) = 60 mT = 60 * 10^(-3) T

Length of the wire (L) = 40 cm = 40 * 10^(-2) m

Substituting the given values into the equation, we get:

F = (60 * 10^(-3) T) * (8.0 A) * (40 * 10^(-2) m)

Simplifying the expression, we find:

F = 0.192 N

Since the wire is suspended by two vertical wires, the tension in each wire will be half of the total force. Therefore, the tension in either wire is 0.192 N / 2 = 0.096 N.

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The radiation that is least damaging to humans is non-ionizing radiation.

Non-ionizing radiation refers to the type of radiation that does not have enough energy to remove tightly bound electrons from atoms or molecules, thus not causing significant damage to biological tissues.

Examples of non ionizing radiation include radio waves, microwaves, visible light  and low energy ultraviolet (UV) radiation. while excessive exposure to any form of radiation can have adverse effects, non-ionizing radiation is generally considered to be less harmful compared to ionizing radiation, which includes X-rays and gamma rays.

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The tax rate you will pay is displayed in tax brackets for each category of taxable income.

Thus, For instance, in 2022, the first $10,275 of your taxable income is subject to the lowest tax rate of 10% if you are single.

Up until the maximum amount of your taxable income, the following portion of your income is taxed at a rate of 12%.

As taxable income rises, the tax rate rises under the progressive tax system. Overall, this has the result that taxpayers with higher incomes often pay a greater rate of income tax than taxpayers with lower incomes.

Thus, The tax rate you will pay is displayed in tax brackets for each category of taxable income.

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Answer:

- They need oxygen to burn fuel

- Aerodynamics

- Extreme temperatures

- Radiation

- Pressure issues

Explanation:

A airplane is a heavier-than-air aircraft kept aloft by the upward thrust exerted by the passing air on its fixed wings and driven by propellers, jet propulsion, etc.

Aeroplanes cannot travel in space for several reasons:

They need oxygen to burn fuel - Aeroplane engines rely on the oxygen in the atmosphere to burn fuel and generate thrust. In space, there is no atmosphere so there is no oxygen for the engines to work.

Aerodynamics - Aeroplane wings generate lift by interacting with the air. In space, there is no air so wings would be unable to generate any lift. Aeroplanes rely on aerodynamics to fly which does not work in space.

Extreme temperatures - In space, temperatures can range from -150 degrees Celsius to 150 degrees Celsius. Aeroplanes are designed to operate within a much narrower temperature range. The extreme cold and heat of space could damage aeroplane components.

Radiation - In space, there are high levels of radiation from the Sun and cosmic rays. Aeroplane bodies are not designed to shield against this type of radiation and it could damage electronics and affect aeroplane systems.

Pressure issues - Aeroplanes are designed to withstand air pressures at altitudes up to around 12 kilometers. In low-Earth orbit and beyond, the air pressure is essentially zero. This extreme change in pressure could cause structural damage to the aeroplane.

In summary, while aeroplanes are designed to fly through the Earth's atmosphere, they lack the key features needed to operate in the extreme environment of outer space like spaceships. Aeroplanes require things like oxygen, aerodynamics and being able to withstand changes in pressure - all of which do not exist or work the same way in space.

Explanation:

The wing is pushed up by the air under it. Large planes can only fly as high as about 7.5 miles. The air is too thin above that height. It would not hold the plane up.

Answer:

the femur, or thigh bone

Answer:

The femur bone is the longest and strongest bone in the body.

Explanation:

We have that the  the strength of the force between the Sun and the moon  is mathematically given as

F2=0.12140F1N

Question Parameters:

Distance between the Earth and the Sun were increased by a factor of 2.87,

Generally the equation for the  Gravitational Force   is mathematically given as

\(F=\frac{Gm1m2}{d^2}\\\\Where\\\\f1/f2=d1^2/d2^2\\\\Therefore\\\\F2=\frac{F1*d1}{3.23^2}\\\\F2=\frac{F1*1}{2.87^2}\\\\\)

F2=0.12140F1N

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Weight of a body is defined as the force with which it is attached to the earth.

mass is the total quantity of matter present.

the weight of something is given as mass * acceleration

weight of an object is directly proportional to the mass of the object.  so, if mass doubles, weight will also double.

hope this helps :)

- jeron

Answer:

v = - 1,715 m / s ,   x = 0.0156 m

Explanation:

This is an oscillatory movement exercise, which is described by the expression

          x = A cos (wt + Ф)

we can assume that the block is released from its maximum elongation, so the phase constant (Ф) is zero

As we are told that the stone does not affect the movement of the spring mass system, the amplitude and angular velocity do not change, in the upward movement the stone is attached to the mass, but in the downward movement the mass has an acceleration greater than g leave the stone behind, let's look for time, for this we use the definition of speed and acceleration

         v = dx / dt

         v = - A w sin wt

          a = - Aw² cos wt

         a = -g

         -g = - Aw² cos wt

          wt = cos⁻¹ (g / Aw²)

          t = 1 / w cos⁻¹ (g / Aw²)

angular velocity and frequency are related

        w = 2π f

        w = 2π 4

         w = 8π   rad / s

remember that the angles are in radians

          t = 1 / 8π cos⁻¹ (9.8 / (0.07 64π²))

          t = 0.039789 1.3473

          t = 0.0536 s

let's find the speed for this time

          v = - A w sin wt

          v = - 0.07 8π sin (8π 0.0536)

          v = - 1,715 m / s

the distance is

           x = A cos wt

           x = 0.07 cos (8π 0.0536)

           x = 0.0156 m

Explanation:

You want  N/m

 N = 66 * 9.81

 m = 2.3 x 10^-2 m

66* 9.81 / 2.3 x 10^-2  = 28150 =  28 000 N/m    to two S D

Answer:

300,000,000 and the second question is the same.

Explanation:

Edge

Answer:

What is the speed of the light relative to the boys?

✔ 300,000,000

What is the speed of light relative to a stationary observer on the side of the road?

✔ 300,000,000

Explanation: MARK ME BRAINLIEST CUHZZZZZ DA*N (cant say dam or they gone banned me again)

Answer:

b

Explanation:

Because they used cutting-edge tools and technology to strengthen the signal and increase the range, the Swedish Space Agency was able to transmit a wifi signal over such a long area.

With a 2.4GHz frequency, Wi-Fi transmissions typically have a range of over 45 metres, or roughly 150 feet. You will have a reach of approximately 15 metres or 50 feet when using a 5Ghz frequency.

802.11g - Indoor effective ranges of 100–150 feet at 54 Mbps wireless throughput using a 2.4GHz transmission frequency. 802.11g and 802.11b can communicate at 11 Mbps.

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The constant acceleration of the train is 50/9 m/s².

The two balls will collide at a height of approximately 10.204 meters above the ground.

Using the kinematic equations of motion, we have:

distance = initial velocity * time + 1/2 * acceleration * time^2

For the first phase of acceleration, the initial velocity is zero, the time is 5 minutes = 300 seconds, and the distance traveled is unknown. So we have:

d1 = 0 + 1/2 * a * (300)^2

For the second phase of constant speed, the initial velocity is v, the time is 5 minutes = 300 seconds, and the distance traveled is also unknown. So we have:

d2 = v * 300

For the third phase of deceleration, the initial velocity is v, the time is also 5 minutes = 300 seconds, and the distance traveled is again unknown. So we have:

d3 = v * 300 + 1/2 * (-a) * (300)^2

The total distance traveled is the sum of these three distances:

distance = d1 + d2 + d3 = 1/2 * a * (300)^2 + v * 600 - 1/2 * a * (300)^2 = v * 600

Since the total distance traveled is given as 10 km = 10000 m, we have:

v * 600 = 10000

Solving for v, we get:

v = 10000/600 = 50/3 m/s

Now we can use the second equation above to find a:

d2 = v * 300 = (50/3) * 300 = 5000 m

Therefore, the constant acceleration of the train is:

a = 2 * (5000 - 1/2 * a * (300)^2) / (300)^2 = 50/9 m/s^2

The constant acceleration of the train is 50/9 m/s^2.

Problem 2: The height of the first ball dropped is given as 10m. Let's assume the height of the collision point is h meters above the ground.

Using the kinematic equation for free fall, we have:

h = 10 + 1/2 * g * t^2

where g is the acceleration due to gravity, which is approximately 9.81 m/s^2, and t is the time it takes for the second ball to reach the collision point after being thrown upwards.

The initial upward velocity of the second ball is 10 m/s, and we know that at the collision point, its velocity will be zero, since it will have reached its maximum height and will be momentarily at rest before falling back down.

Using the kinematic equation for motion with constant acceleration, we have:

0 = 10 + (-g) * t

Solving for t, we get:

t = 10/g = 10/9.81 seconds

Substituting this value of t into the first equation, we get:

h = 10 + 1/2 * 9.81 * (10/9.81)^2

Simplifying, we get:

h = 10.204 m

The two balls will collide at a height of approximately 10.204 meters above the ground.

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Answer:

Approximately \(-15.37m/s^2\)

Explanation:

The acceleration can be found using the formula:

\(x_{f} = x_{i} + v_{i} (t)+\frac{1}{2} (a)(t^{2} )\)

The work is as shown:

\(45m = 0 + 39 m/s (3.3s)+\frac{1}{2} a(3.3s)^2\)

\(45m=128.7m + 5.445s^2 a\)

\(-83.7m=5.445s^2a\)

\(a = -15.37190083m/s^2\)

a is about -15.37\(m/s^2\)

The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).

The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.

In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²

(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:

Electric flux = Electric field strength × Area

Electric flux = 18 N C⁻¹ × 0.450 m²

Electric flux = 8.1 N m² C⁻¹

In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.

The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).

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