How do I do this can someone help me plss

Answer:

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

2 ÷ 1/3

= 2 x 3

= 6

Therefore, 2 divided by 1/3 equals 6.

Hoped this helped.

Answer:

6

Step-by-step explanation:

2          1

-      /    -

1          3

then you can use keep switch flip to make it

2/1 x 3/1

3x2 = 6

Answer:

A. Covering the entire box is the surface area, which is 664 in.

Step-by-step explanation:

I did the test myself. Have a great day/night! Good luck with the rest of your test! <3

a. \(123.1(1.069)^3 \approx 150.4\)

b. \(123.1(1.069)^{20} \approx 467.5\)

Step-by-step explanation:

x-1-(x-1)²+ax-a

Factorize the expression ?

Given expression is x-1-(x-1)²+ax-a

It can be written as

(x-1)-(x-1)²+(ax-a)

=> (x-1)-(x-1)(x-1)+a(x-1)

=> (x-1)[1-(x-1)+a]

=> (x-1)(1-x+1+a)

=> (x-1)(2-x+a)

x-1-(x-1)²+ax-a = (x-1)(2-x+a)

Hope this helps!!

We have an absolute value function that opens upwards. The interval where it is decreasing only is:

(-∞, 2)

All absolute value equations of the form:

y = |x - a| + b

have graphs that open upwards, and a vertex in the point (a, b).

While ones of the form:

y = -|x - a| + b

have graphs that open downwards, and again, a vertex in the point (a, b).

In this case we have one that open upwards:

h(x)=|x-2|+6

With a vertex at (2, 6)

The function will be decreasing on the left side of the vertex, so the interval where the function is only decreasing is:

(-∞, 2)

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Answer

5

Step-by-step explanation:

there are already 2 units in height therefore 2 plus 3 is 5

37.5% of the students collected between 49 and 98 kilograms of newspapers for the recycling project. Percentage method can be used here.

To answer this question, we need to determine the number of students who collected between 49 and 98 kilograms of newspapers and then calculate what percentage of the total number of students that represents.

First, we need to gather the data and sort it into categories. We can create a frequency table with intervals of 10 kilograms:
Mass Range | Number of Students
   0-9 kg               3
   10-19 kg            5
  20-29 kg           7
  30-39 kg           4
  40-49 kg           6
  50-59 kg           8
  60-69 kg           5
  70-79 kg           2
  80-89 kg           1
  90-99 kg           2

To find the number of students who collected between 49 and 98 kilograms of newspapers, we need to add up the frequencies for the 50-59, 60-69, and 70-79 kg categories. That gives us a total of 15 students.
To calculate the percentage of students who collected between 49 and 98 kilograms of newspapers, we need to divide the number of students in that range by the total number of students and then multiply by 100. In this case, we have 15 students in the range and a total of 40 students overall, so:
15/40 * 100 = 37.5%.

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Explanation

We are given a right-angled triangle with the following:

We are required to determine the missing side (i.e. the value of x).

We can achieve this by using the Pythagorean theorem as follows:

Hence, the answer is:

Answer:

D. y+1=3(x+1)

Answer:

The point (1 | 6) is on the graph.

Step-by-step explanation:

Answer:

it is 1/6

Step-by-step explanation:

Step-by-step explanation:

\(\frac{1-\sin ^2\left(x\right)}{1+\sin \left(x\right)}=1-\frac{1}{\csc \left(x\right)}\)

\(\frac{1-\sin ^2\left(x\right)}{1+\sin \left(x\right)}\)

\(=1-\sin \left(x\right)\)

⇒ \(\sin \left(x\right)=\frac{1}{\csc \left(x\right)}\)

\(=1-\frac{1}{\csc \left(x\right)}\)

The distance between the sailboat and the dock is approximately 21.006 km

To find the distance between the sailboat and the dock, we can use trigonometry.

Given:

Distance between the lighthouse and dock (north-south direction) = 30 km

Viewing angle between the lighthouse and dock = 35 degrees

We can consider the right triangle formed by the sailboat, the lighthouse, and the dock.

The distance between the sailboat and the dock is the adjacent side of the triangle, while the distance between the lighthouse and the dock is the opposite side.

Using the trigonometric function tangent (tan), we have:

tan(angle) = opposite / adjacent

tan(35 degrees) = opposite / 30 km

Solving for the opposite side (distance between sailboat and dock):

opposite = tan(35 degrees) * 30 km

opposite ≈ 0.7002 * 30 km

opposite ≈ 21.006 km

Therefore, the sailboat is approximately 21.006 km away from the dock.

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Answer:

\(x=3c\sqrt{a} -b^2\)

Step-by-step explanation:

\(\sqrt{a} =\dfrac{x+b^2}{3c}\)

Multiply both sides by 3c:

\(\implies \sqrt{a} \cdot 3c=\dfrac{(x+b^2) \cdot 3c}{3c}\)

\(\implies 3c\sqrt{a} =x+b^2\)

Subtract \(b^2\) from both sides:

\(\implies 3c\sqrt{a} -b^2=x+b^2-b^2\)

\(\implies 3c\sqrt{a}-b^2=x\)

Switch sides:

\(\implies x=3c\sqrt{a} -b^2\)

By using the concept of testing of hypothesis, it can be calculated that

The required test statistic is t = 0.918

What is testing of hypothesis?

Suppose, there is a hypothesis and there is a data at hand. Testing of hypothesis is a method of inferencing which is used to decide whether the given hypothesis is true or not based on the statistical data given

From the table attached here, it can be calculated that

\(\bar{x}_{2012}=365.4667\\s^{2}_{2012}=27133.66364\\\bar{x}_{2013}=331.775\\s^{2}_{2013}=29750.53782\\n_{2012}=45\\n_{2013}=40\\\)

So the test statistic t is

\(\large t=\frac{\bar{x}_{2012}-\bar{x}_{2013}}{\sqrt{\frac{s^{2}_{2012}}{n_{2012}}+\frac{s^{2}_{2013}}{n_{2013}}}}\)

\(t=\frac{365.4667-331.775}{\sqrt{\frac{27133.66364}{45}+\frac{29750.53782}{40}}}\)

\(t \large =\frac{33.6917}{36.6978711}\)

t = 0.918

The value of the test statistic is 0.918

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Etta needs to add the source of the information to better arrange these notes.

A note is a place where information about a specific item is recorded for later reference. The main goals of taking notes are to promote active learning and create study materials for tests. You should be able to organise material into an understandable format that will aid in your learning process by developing note-taking skills.

As a result, it is clear from the question that Etta is making notes for the purpose of creating a webpage about healthy eating. Once her notes have been organised with the relevant facts and information, Etta will need to cite her sources.

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For an independent-measures t statistic, the estimated standard error measures how much difference is reasonable to expect between the sample means for two samples selected from the same population.

True

The reliability of a measure is determined by the standard error of measurement. It is frequently mentioned in standardized testing and it describes how variable a test's measurement error is. A confidence interval for the true score of an element or an individual can be generated using the standard error of measurement.

To ascertain whether there is statistical support that the linked population means are statistically substantially different, the Independent Samples t Test compares the means of two independent groups. An example of a parametric test is the Independent Samples t Test. Additionally called the Independent t Test.

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Using the z table, the critical value \(z_{a/2}\) needed to construct a confidence interval with level 82% is 1.34.

In the given question,

We have to find the critical value \(z_{a/2}\) needed to construct a confidence interval with level 82%.

The confidence interval is 82%.

We can write 82% as 82/100 and 0.82.

Now the value of

\(\alpha\)=1−0.82

\(\alpha\)=0.18

Now finding the value of \(\alpha\)/2

\(\alpha\)/2=0.18/2

\(\alpha\)/2=0.09

Now finding the value of \(z_{a/2}\).

\(z_{0.82}\) = 1.34

Hence, the critical value \(z_{a/2}\) needed to construct a confidence interval with level 82% is 1.34.

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Answer: x = 29; RZ = 60, SW = 120

Step-by-step explanation:

If you look at the lines, RZ is half the value of SW. Knowing this, we can set up an equation like this:

2(RZ) = SW

2(2x+2) = 5x-25

By plugging in the values for RZ and SW, we can set them equal to each other and find x.

2(2x+2) = 5x-25

4x+4 = 5x-25

4 = x-25

x = 29

I think you only needed the variable, but I can provide the measures of the line, just in case:

RZ = 2x+2 ; 2(29)+2 = 60

SW = 5x-25 ; 5(29)-25 = 120

Since RZ is half of SW, we can tell we correctly determined x. Hope this helps!

MN+NO=MO

Where N is the midpoint of MO

Therefore:

MN = NO

MN = 8

NO = 8

8 + 8 = MO

MO = 16

Now:

MO + OQ = MQ

If O is the midpoint of MQ:

MO = OQ

OQ = 16

Therefore:

MQ = 16 + 16 = 32

Answer:

b is your answer hope it helps

Step-by-step explanation:

Answer: √144, 5, 13

Step-by-step explanation:

√144 = 12 and 5, 12, 13 is a pythagorean triplet.

It is not possible to determine the level of water in the tank using only the given information. To determine the level of water in the tank, we need to know either the height of the water column or the total pressure at the bottom of the tank, which includes the pressure due to the water column and the pressure due to the atmosphere.

Therefore, we can't fill the blank with any value since the problem does not provide any information regarding it. In order to find the level of water in the tank, we need to know either the height of the water column or the total pressure at the bottom of the tank, which includes the pressure due to the water column and the pressure due to the atmosphere.

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Answer:

To find the exterior angle of any polygon, just construct a line following one of the sides, and measure the angle.

Step-by-step explanation:

PLS GIVE BRAINLIEST

No question given. Repost.

The lateral area of the cylinder is 64π cm², and the surface area of the cylinder is 192π cm².

The circumference of a cylinder is equal to 2πr, where 'r' represents the radius. In this case, the given circumference of 16π cm can be equated to 2πr. Solving for 'r', we find that the radius is 8 cm.

Since the height of the cylinder is half the radius, the height can be calculated as 8/2 = 4 cm.

To calculate the lateral area of the cylinder, we use the formula: Lateral Area = 2πrh, where 'r' is the radius and 'h' is the height. Substituting the values, we have: Lateral Area = 2π(8)(4) = 64π cm².

The surface area of the cylinder comprises the lateral area and the two circular bases. The formula for the surface area of a cylinder is: Surface Area = 2πrh + 2πr². Substituting the values, we have: Surface Area = 2π(8)(4) + 2π(8)² = 64π + 128π = 192π cm².

Therefore, the lateral area of the cylinder is 64π cm², and the surface area of the cylinder is 192π cm² ≈603.2 \(cm^{2}\)

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Question: A right cylinder has a circumference of 16π cm. Its height is half the radius. what's the lateral area and the surface area of the cylinder rounded to the nearest tenth?

Answer:

I just did this lesson and the answer is ...

L ≈ 201.1 cm2 ; S ≈ 603.2 cm2

Hope this helps! Have a good day. :)

Answer:

A) She should buy the

Step-by-step explanation:

Part A:

For question A, we find the areas of both plots and see which one is greater.

For the first one, we do 3/8 * 2/3

\(\frac{3}{8} * \frac{2}{3} = \frac{6}{24} = \frac{1}{4}\)

The area of the first plot is 1/4 square miles

For the second one, we do 2/5 * 2/5

\(\frac{2}{5} *\frac{2}{5} = \frac{4}{25}\)

The area of the second plot is 4/25 square miles

We have 1/4 and 4/25.

To see which one is bigger, we make them have the same denominator, also known as the LCM (Least Common Multiple).

LCM(4,25) = 100

Now we make 1/4 have a denominator of 100

4 times what is 100?

25, so the numerator is 25 and the denominator is 100.

We get: 25/100

Now we make 4/25 have a denominator of 100

25 times what is 100?

4, so the numerator is 4 * 4 = 16 and the denominator is 100.

We get: 16/100

Now we can see which is bigger:

25/100 or 16/100

25/100 is bigger

Therefore, Miguel's mother should buy the plot with dimensions 3/8 and 2/3.

Part B

For part B, I'm not sure which plot of land she is going to pay for, so I will answer both.

We answered this in Part A already.

The 3/8 and 2/3 plot was 1/4 square miles and the 2/5 by 2/5 plot was 4/25 square miles.

Plot 1:

1/4 square miles

It said that it costs $750,000 for a square mile

This plot is 1/4 square miles, so we do

\($750,000 * \frac{1}{4} = \frac{750,000}{4} = 187,500\)

The cost for plot 1 is $187,500

Plot 2:

4/25 square miles

It said that it costs $750,000 for a square mile

This plot is 4/25 square miles, so we do

\(750,000*\frac{4}{25} = \frac{3,000,000}{25} = 120,000\)

The cost for plot 1 is $120,000

So for the 3/8 by 2/3 plot, it cost $187,500 and for the 2/5 by 2/5 plot costs $120,000

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