How can you create an equivalent resistance of 8 ohms from only 10 ohms resistors and 3 ohm resistors?

Answer:

scalar d = 54000 m , v_average = 16,667 m / s

vector    d = -4000 m , moved 4000 to the west

                 v_average = 0                

Explanation:

his is a uniform motion exercise, but we must be careful with quantities that are scalars and vector quantities

The distance traveled is a scalar

       d = d₁ + d₂

       d = 25000 + 29000

       d = 54000 m

the speed is a scalar, in the exercise it is not specified if the speed of each trajectory or the average speed. Therefore we will calculate the two

       v₁ = d₁ / t₁

       v₁ = 25000/1500

       v₁ = 16,667 m / s

       v₂ = 29000/1740

        v₂ = 16,667 m / s

Since the two speeds are equal, the average speed is

       v = (v1 + v2) / 2

       v_average = 16,667 m / s

now let's calculate the displacement that is a vector, so it has direction in addition to modules

suppose the eastward direction is positive and the bold are vectors

      d = d₁ - d₂

       d = 25000 - 29000

        d = -4000 m

this means that it moved 4000 to the west

velocity is a vector, we assume positive eastward movement

        v₁ = 16,667 m / s

         v₂ = - 16,667 m / s

         v_average = (v1 -v2) / 2

         v_average = 0

13.The color with the longest wavelength is option A. Red.

14.The sky appears blue due to option D. Scattering of light.

Red light has a longer wavelength compared to yellow and blue light.The color that has the longest wavelength is red. The color of the sky appears blue due to scattering of light. The distance between one peak and the next in a series of waves, particularly electromagnetic waves traveling through space or along a wire is referred to as wavelength.

The wavelength of light, for example, determines its color. Red light has the longest wavelength, followed by orange, yellow, green, blue, and purple, with violet light having the shortest wavelength. When light is reflected off a surface or passes through a medium, it can be deflected in various directions, a phenomenon known as scattering of light.

The Earth's atmosphere scatters sunlight in all directions, but the shorter blue wavelengths are scattered more than the longer wavelengths. As a result, we perceive the sky as blue during the day.  The light becomes scattered when it interacts with particles in the atmosphere, causing the sky to appear blue during the day and red during sunset or sunrise. The scattering of light is the process that causes the sky to appear blue.

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The velocity of the sled after one minute is 10.6 m/s.

The velocity of the sled after one minute is calculated by applying Newton's second law of motion and formula instantaneous power as shown below.

P = Fv

where;

P = mav

P = m (v/t)v

P = mv²/t

Pt = mv²

v² = Pt / m

v = √ ( Pt / m )

where;

The velocity of the sled after one minute is calculated as;

v = √ ( 187.5 x 60 / 100 )

v = 10.6 m/s.

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The velocity of the arrow after two seconds on the moon is 51.68 m/s.

The given expression for height as a function of time t, H = 55t - 0.83t^(2). We need to find the velocity of the arrow after two seconds. To find velocity, we have to differentiate H with respect to time.

So, we have: dh/dt = 55 - 1.66t.

The velocity of the arrow after two seconds can be found by substituting t = 2 in the above expression. Therefore, we have:

dh/dt = 55 - 1.66

t= 55 - 1.66(2)

= 55 - 3.32

= 51.68.

Therefore, the velocity of the arrow after two seconds is 51.68 m/s.

Explanation: The given expression for height as a function of time t, H = 55t - 0.83t^(2). We need to find the velocity of the arrow after two seconds. To find velocity, we have to differentiate H with respect to time.

So, we have:

dh/dt = 55 - 1.66t.

The velocity of the arrow after two seconds can be found by substituting t = 2 in the above expression. Therefore, we have: dh/dt = 55 - 1.66t

= 55 - 1.66(2)

= 55 - 3.32

= 51.68.  

Hence, the velocity of the arrow after two seconds is 51.68 m/s.

Conclusion: The velocity of the arrow after two seconds on the moon is 51.68 m/s.

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(a) Time rate of increase of electric field = 0.8 V/s
(b) Magnetic field between the plates at 5.00 cm from the center = 1 x 10^{-9}T

(a) The time rate of increase of electric field between the plates can be found by dividing the current (I) by the capacitance (C) of the capacitor. First, find the capacitance using the formula C = ε₀A/d, where ε₀ is the vacuum permittivity (8.85 x 10^{-12} F/m), A is the area of the plates, and d is the plate separation. Calculate A as πr², where r is the radius of the plates. Then, divide the current by the capacitance to find the time rate of increase of the electric field.

(b) The magnetic field between the plates can be calculated using Ampere's Law. The formula is B = μ₀I/(2πr), where μ₀ is the permeability of free space (4π x 10^{-7} T·m/A), I is current, and r is the distance from the center. Plug in the given values to find the magnetic field at 5.00 cm from the center.

Calculation steps:
1. Calculate A: A = π(0.1 m)² = 0.0314 m²
2. Calculate C: C = (8.85 x 10^-12 F/m)(0.0314 m²)/(0.004 m) = 6.91 x 10^{-11} F
3. Calculate the time rate of increase of electric field: E = I/C = (0.2 A)/(6.91 x 10^{-11}F) = 0.8 V/s
4. Calculate magnetic field: B = (4π x 10^{-7}T·m/A)(0.2 A)/(2π(0.05 m)) = 1 x 10^{-9}T

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The lightning is occurring approximately 5.1  kilometers away if the flash to bang is 15 seconds. The speed of sound in dry air at a temperature of around 20 degrees Celsius is approximately 343 (m/s)

The flash to bang method is a way to estimate the distance of a lightning strike based on the time between seeing the flash of lightning and hearing the thunder. Sound travels at a speed of approximately 343 meters per second (m/s) in air. By multiplying this speed by the time interval between the flash and the bang, which is 15 seconds in this case, we can determine the distance.

To calculate the distance, we use the formula:

\(\begin{equation}\text{Distance} = \text{Speed} \times \text{Time}\)

Given that the time between the flash and the bang is 15 seconds, we can substitute the values into the formula:

\(\text{Distance} = 343\ \text{m/s} \times 15\ \text{s} = 5145\ \text{m} = 5.145\ \text{km}\)

Therefore, if the flash to bang is 15 seconds, the lightning strike is approximately 5.1  kilometers away.

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The time for a capacitor in an uncharged, series RC circuit to reach 90% of its final charge will remain unchanged when a second resistor is added in series with the original resistor. The correct answer is option c.

In a series RC circuit, the time it takes for the capacitor to charge to a certain percentage of its final charge (often referred to as the time constant) is determined by the product of the resistance (R) and the capacitance (C), denoted as RC. The time constant represents the time it takes for the capacitor to charge or discharge approximately 63.2% of the way towards its final value.

Option a, doubling the battery voltage, will change the time constant because it affects the charging rate of the capacitor. Option b states that all situations result in a change, which is incorrect. Option c, adding a second resistor in series, does not affect the RC time constant since the time constant is solely determined by the product of the resistance and capacitance.

However, option d, doubling the RC time constant, will indeed change the time it takes for the capacitor to reach 90% of its final charge. Therefore, the correct answer is option c.

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The properties of a thermal radiator include the fact that the power radiated is proportional to the temperature raised to the fourth power. This means that as the temperature of the thermal radiator increases, the amount of power radiated increases exponentially.

The hotter objects emit more light for a given area, which means that the brightness of the thermal radiator will increase as it gets hotter. However, as the temperature increases, the color of the radiation will also change. Specifically, hotter objects will look redder, while cooler objects will look bluer. Finally, it is important to note that the power radiated by a thermal radiator is directly proportional to its temperature, not inversely proportional. Here is an answer incorporating the requested terms The power radiated by a thermal radiator is proportional to the temperature raised to the fourth power, according to the Stefan-Boltzmann Law. This means that hotter objects emit more light for a given area. hotter objects look bluer, as the peak wavelength of their emitted radiation shifts towards the shorter blue end of the spectrum, while cooler objects look redder as their peak wavelength shifts towards the longer red end of the spectrum.

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Answer:

La fuerza ejercida sobre el piso del elevador hacia abajo es aproximadamente 1,004.075 N

Explanation:

Fuerza = Masa × Aceleración

El peso de la caja = 800 N

La velocidad hacia abajo = 5.0 m / s

Tomando la aceleración debida a la gravedad, g = 9,8 m / s²

La masa del cuerpo, m = 800 N / g = 800 N / (9,8 m / s²) ≈ 81,63 kg

La fuerza ejercida sobre el piso del ascensor durante la aceleración hacia arriba, 'N', se da como sigue;

N = m · g + m · a

a = 2,5 m / s²

∴ N = 81,63 kg × 9,8 m / s² + 81,63 × 2,5 m / s² = 800 N + 81,63 × 2,5 m / s² ≈ 1,004,075 N

La fuerza ejercida sobre el piso del ascensor hacia abajo ≈ 1,004.075 N

When a beam of light, which is traveling in glass, strikes an air boundary, there is a reflection.

The phenomenon of reflection occurs when light waves bounce off the boundary of a medium. When the light waves come into contact with the boundary between two materials, the wave is split into a reflected wave and a refracted wave, with each wave traveling in a different direction. The reflected wave bounces off the boundary and returns to the medium from which it came. The refracted wave, on the other hand, bends as it enters the second medium, making an angle with the incident wave.

The angle of incidence and the angle of reflection are equal in magnitude and opposite in direction. This is known as the law of reflection. When a beam of light travels from a medium with a higher refractive index (such as glass) to one with a lower refractive index (such as air), it refracts away from the normal. Hence, the beam of light is reflected back towards the glass as it strikes the air boundary.

When a beam of light travels from a medium with a higher refractive index to one with a lower refractive index, it refracts away from the normal. When the beam of light, which is traveling in glass, strikes an air boundary, it reflects back towards the glass as a reflection. The angle of incidence and the angle of reflection are equal in magnitude and opposite in direction, which is known as the law of reflection.

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To drag the box from point A to B on a horizontal surface using a horizontal force of 10 N, a work of 60 joules (J) must be done over a distance of 6 meters (m).

On a horizontal surface, if a box is dragged from point A to B by a horizontal force of 10 N, the work done can be calculated using the formula:

Work = Force x Distance

In this case, the force applied is 10 N and the distance between points A and B is 6 m.

Plugging these values into the formula, we get:

Work = 10 N x 6 m = 60 Nm

The unit for work is joules (J), so the work done in this scenario is 60 J.

When a force is applied to move an object, work is done.

The work done is calculated by multiplying the force applied by the distance over which the force is exerted.

In this case, the force applied is 10 N and the distance is 6 m.

Multiplying these values gives us the work done, which is 60 J.

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Answer:

Explanation:

1.wrap bar magnet in a plastic baggie and remove the iron filings from the mixture by using a bar magnet. Place a small piece of scrap paper on the scale and “tare” the scale. Then place filings on the scrap paper and record (e) the mass of the iron filings. Don't throw out the iron–save it to be recollected.

2.When sand is added to water it either hangs in the water or forms a layer at the bottom of the container. Sand therefore does not dissolve in water and is insoluble. It is easy to separate sand and water by filtering the mixture. Salt can be separated from a solution through evaporation.

3.Sand (mostly silicon dioxide) is not.

Pour the salt and sand mixture into a pan.

Add water. ...

Heat the water until the salt dissolves. ...

Remove the pan from heat and allow it to cool until it's safe to handle.

Pour the salt water into a separate container.

Now collect the sand.

Pour the salt water back into the empty pan.

Heat the salt water until the water boils. Continue boiling it until the water is gone and you're left with the salt.

Another way you can separate the salt water and sand is to stir up the sand/salt water and pour it through a coffee filter to capture the sand.

Answer:

1. Separating iron from mixture

2. Separating sand from mixture

3. Separating Salt mixture

Sound intensity more than 70 dB (noise) for a long period of time may start to damage your hearing.

A loud noise with sound intensity more than 120 dB can cause immediate harm to your ears.

A) The resistance (R) in the LR circuit is approximately 0.156 ohms. B) the inductance (L) in the LR circuit is approximately 2.1 mH.

a) To find the resistance (R) in an LR circuit where the current falls to 50% of its initial value in 0.09 seconds, we can use the formula for the time constant (τ) of an LR circuit: τ = L / R

Given: L = 14 mH (convert to H: 14 × 10⁻³ H)

Δt = 0.09 s

The time constant (τ) is the time it takes for the current to reach approximately 63.2% of its initial or final value. In this case, the current falls to 50% of its initial value, so we can assume it is approximately one time constant (τ).

Since τ = L / R, we can rearrange the equation to solve for R: R = L / τ

R = (14 × 10⁻³)) / 0.09

R = 0.156 ohms

Therefore, the resistance (R) in the LR circuit is approximately 0.156 ohms.

b) To find the inductance (L) in an LR circuit where the current rises to 40% of its final value in 0.07 seconds, we can use the formula for the time constant (τ) of an LR circuit: τ = L / R

Given:

R = 30 ohms

Δt = 0.07 s

The time constant (τ) is the time it takes for the current to reach approximately 63.2% of its initial or final value. In this case, the current rises to 40% of its final value, so we can assume it is approximately one time constant (τ).

Since τ = L / R, we can rearrange the equation to solve for L: L = R × τ

L = 30 × 0.07

L = 2.1 H (convert to mH: 2.1 × 10³ mH)

Therefore, the inductance (L) in the LR circuit is approximately 2.1 mH.

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0.88m/s is the the acceleration when the girl is pulling the wagon at an angle of 36.9 degrees. She is pulling with a force of 50N and the boy is pushing with a force of 30N. The mass of the wagon and books together is 90kg.

A force is an influence that has the power to alter an object's motion. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

The given data :

Pushing force by boy =30N

pulling force by Girl=50N

Mass of wagon and books together= 90kg

angle of pulling =36.9 degree

so the acceleration will be=F/m

hence net force =30+50N=80N

a=80/90

a=0.88m/s

Hence, 0.88m/s is the the acceleration when the girl is pulling the wagon at an angle of 36.9 degrees. She is pulling with a force of 50N and the boy is pushing with a force of 30N. The mass of the wagon and books together is 90kg.

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Answer:

This may refer to a situation like:

"one person pushes a box, if there is equal and opposite reaction why the box moves and the person does not?"

Remember the second Newton's law:

F = m*a

suppose that the mass of the person is 3 times the mass of the box.

So, if the box has a mass M, the person will have a mass 3*M

Then the Newton's equation for the box when the person pushes with a force F is:

F = M*a

solving for the acceleration, we get:

F/M = a

While the person is also pushed by the box with a force with the same magnitude, then the equation for the person is:

F = (3*M)*a'

Solving for the acceleration, we get:

F/(3M) = a'

Now we can compare the acceleration of the box (F/M) with the acceleration of the person (F/3M).

Is easy to see that the acceleration of the box is 3 times the acceleration of the person.

So regardless of the fact that both the box and the person experience a force with the same magnitude, the box will move more due to this force.

This is why in situations like this, the forces do not seem balanced.

1. Five major external forces that affect organizations are economic, social, cultural, demographic, and technological. Economic factors such as inflation and interest rates can impact a company's profitability and purchasing power. Social factors like changing consumer preferences and lifestyles can influence demand for products and services.

Cultural factors like values and beliefs can shape consumer behavior and market trends. Demographic factors such as population size and age distribution can affect target markets.

Technological factors like advancements in automation or digitalization can disrupt industries and create new opportunities. These external forces shape the business environment and organizations must monitor and adapt to them to stay competitive.

2. Gathering competitive intelligence is crucial for businesses because it provides valuable insights about their competitors' strategies, strengths, weaknesses, and market position.

By understanding the competitive landscape, businesses can identify opportunities and threats, make informed decisions, and develop effective strategies.

Competitive intelligence helps businesses stay ahead of their competitors, anticipate market trends, identify emerging technologies, and improve their own products or services. It allows businesses to benchmark their performance, evaluate their competitive advantage, and identify areas for improvement.

Ultimately, gathering competitive intelligence empowers businesses to make proactive and strategic decisions that can lead to sustainable growth and competitive advantage.

3. In business, various economic variables need to be monitored as they have significant impacts on strategy applications. Some important economic variables include GDP (Gross Domestic Product), inflation rate, exchange rates, interest rates, consumer spending, unemployment rate, and industry-specific factors like raw material prices or energy costs.

Monitoring these variables helps businesses understand the overall economic conditions, identify market opportunities, and assess potential risks. For example, a high inflation rate may impact pricing strategies, while a favorable exchange rate can benefit export-oriented businesses.

By monitoring economic variables, businesses can adapt their strategies accordingly and make informed decisions to navigate the dynamic business environment.

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Answer:

\(\vec v_0=30.99 \ m/s\)

Explanation:

Refer to the attached image.

Here is a link to another projectile problem that gives some useful information, https://brainly.com/question/32300395. Although, this problem was a special case where we could use the range formula. So, here’s a bit of information about when it’s applicable to use the range formula.

You can use the range formula only if these two things apply:

1. The projectile lands at the same height originally fired from

2. The projectile isn't fired horizontally, (i.e. θ≠0° )

Answer:

4.1 Introduction. Our modern society depends heavily on thermal energy sources derived mostly from coal, petroleum, and natural gas combustion.

Answer:

Approximately \(1.5\; {\rm s}\).

(Assumptions: \(g = 9.81\; {\rm m\cdot s^{-2}}\); air resistance on the volleyball is negligible.)

Explanation:

Under the assumptions, acceleration of the volleyball would be \(a = (-g) = (-9.81)\; {\rm m\cdot s^{-2}}\) during the entire flight. (This value is negative since the ball is accelerating downwards- toward the ground.)

By the time the volleyball hits the ground, the volleyball would be at a position \(2.0\; {\rm m}\) below where it was launched. In other words, the (vertical) displacement of the volleyball during the entire flight would be \(x = (-2.0)\; {\rm m}\). (Negative since the ball is below where it was launched.)

Apply the SUVAT equation \((v^{2} - u^{2}) = 2\, a\, x\) to find the velocity of the volleyball right before hitting the ground. In this equation:

Rearrange this equation and solve for the velocity right before landing, \(v\). Note that because \(v\!\) is raised to the power of \(2\) in \((v^{2} - u^{2}) = 2\, a\, x\), both \(v = \sqrt{u^{2} + 2\, a\, x}\) and \(v = -\sqrt{u^{2} + 2\, a\, x}\) could satisfy this equation. However, \(v\!\!\) needs to be negative since the volleyball would be travelling downwards before reaching the ground.

Therefore, right before reaching the ground, velocity of the volleyball would be:

\(\begin{aligned} v &= -\sqrt{u^{2} + 2\, a\, x \\ &= -\sqrt{(6.0)^{2} + 2\, (-9.81)\, (-2.0)} \; {\rm m\cdot s^{-1}} \\ &\approx (-8.67)\; {\rm m\cdot s^{-1}}\end{aligned}\).

In other words, velocity of this volleyball has changed from \(u = 6.0\; {\rm m\cdot s^{-1}}\) (upwards) to \(v \approx (-8.67)\; {\rm m\cdot s^{-1}}\) (downwards) during this flight. Divide the change in the velocity \((v - u)\) by the rate of change in velocity \(a = (-9.81)\; {\rm m \cdot s^{-2}}\) to find the duration of this flight:

\(\begin{aligned}t &= \frac{v - u}{a} \\ &\approx \frac{(-8.67) - 6.0}{(-9.81)}\; {\rm s} \\ &\approx 1.5\; {\rm s}\end{aligned}\).

Answer:

Before starting the simulation and having the waves encounter the barrier, the wavelength is manipulated. This is the independent variable. The pattern of diffraction will vary as a result of the change in wavelength. The diffraction angle is therefore the dependent variable. A “constant” is a parameter that stays the same regardless of the variables. The parameter of the barrier that is held constant is the size.

Given :

Velocity of bullet, \(v_b=300\ m/s\).

Mass of bullet, m = 0.005 kg.

Mass of rifle, M = 5 kg.

To Find :

The recoil velocity of the rifle.

Solution :

Since, their is no external force is acting.

So, momentum of the system will be conserved :

Initial momentum = Final momentum

m(0) + M(0) = m(300) + Mv

\(v=-\dfrac{300m}{M}\\\\v=-\dfrac{300\times 0.005}{5}\\\\v=-0.3 \ m/s\)

Therefore, recoil velocity of the rifle is 0.3 m/s.

Hence, this is the required solution.

1. The time taken for the car to reach a velocity of 60 m/s is 8.57 s

2. The distance travelled during the time is 257.14 m

The acceleration of an object is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

1. How to determine the time

a = (v – u) / t

Thus,

t = (v – u) / a

t = (60 – 0) / 7

t = 8.57 s

2. How to determine the distance

v² = u² + 2as

60² = 0² + (2 × 7 × s)

3600 = 0 + 14s

3600 = 14s

Divide both sides by 14

s = 3600 / 14

s = 257.14 m

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If a particle moves along a straight line, if the velocity of the particle v = 2t², then the acceleration versus time graph will be a straight line, therefore the correct answer is option C,

The rate of change of the velocity with respect to time is known as the acceleration of the object. Generally, the unit of acceleration is considered as meter/seconds².

As we know the rate of change of velocity is known as acceleration

acceleration =change in velocity/change in time

As given in the problem If a particle moves along a straight line, if the velocity of the particle v = 2t²,

acceleration = dv/dt

                     =d ( 2t²)/dt

                     =4t

Thus, the acceleration versus time graph would be a straight line.

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Answer:

Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

Explanation:

Area × thickness = volume

density × volume = mass

mass × gravity = weight

Try to use this and it will work. Don't forget to convert units.

The mass of the bouquet can be calculated using the equation m = F/a. Which is equal to 0.9kg.

Since van Gennip’s speed dropped from 10.8 m/s to 10.01 m/s after she took the bouquet, this indicates that a force was applied to her causing her to slow down.

The applied force can be determined by taking the difference between her final and initial momentum, which is p = mv.

Thus, the applied force can be calculated by F = Δp/Δt.

Plugging in the given values, the mass of the bouquet can be calculated as

m = F/a = (63.0 kg × (10.8 m/s - 10.01 m/s))/10.01 m/s² = 0.9 kg.

Therefore, the mass of the bouquet is 0.9 kg.

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The low-point station has an elevation of 110.32 feet in the given vertical curve with a g1 grade of -2% and a g2 grade of +3%.

To find the elevation of the low-point station in the given vertical curve, we start with the provided data. The g1 grade is -2%, indicating a downward slope, while the g2 grade is +3%, indicating an upward slope. The BVC Station is located at 16+50, with an elevation of 112.00 feet. The length of the curve is given as 400.00 feet. To calculate the elevation at the low-point station, we consider the change in grade from g1 to g2 along the curve. The low-point station represents the transition point where the slope changes from descending to ascending. Using vertical curve calculations, we determine the elevation at the low-point station to be 110.32 feet. This means that the road reaches its lowest point at this station before it starts to ascend again.

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