How can the inner core be solid if it is hotter than the surface of the sun

1. The time taken for the car to stop is 5 s

2. The distance travelled during the reaction time is 50 m

3. The distance travelled during the stopping time is 62.5 m

1. How do I determine the time taken for the car to stop?

The time taken for the car to stop can be obtained as follow:

a = (v - u) / t

-5 = (0 - 25) / t

-5 = -25 / t

Cross multiply

-5 × t = -25

Divide both sides by -5

t = -25 / -5

t = 5 s

Thus, the time taken to stop is 5 s

2. How do I determine the distance travelled during the reaction time?

The distance travelled during the reaction time can be obtained as follow:

Distance travelled = velocity × reaction time

Distance travelled = 25 × 2

Distance travelled = 50 m

3. How do I determine the distance travelled during the stopping time?

s = ut + ½at²

s = (25 × 5) + (½ × -5 × 5²)

s = 125 - 62.5

s = 62.5 m

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Distance travelled by a body in unit time is called speed. it is a scalar quantity because it can be specified only by magnitude.

From the diagram, the angular speed will increase clockwise, the sign of the angular acceleration will be negative and the direction of rotation will be clockwise direction and the sign of the angular acceleration is negative. The correct answer is option B

Given that two objects of masses m1 and m2 are attached to a seesaw. The seesaw is made of a bar that has length l and is pivoted so that it is free to rotate in the vertical plane without friction. Counterclockwise is considered the positive rotational direction.

If m1 is 24 kilograms, m2 is 12 kilograms, and mbar is 10 kilograms, The moment of object m1 will be equal to the moment of object m2 without the Mbar

Let assume that the length L of the seesaw is 9 cm.

Anticlockwise moment = 24 x 9/3 = 72Nm

Clockwise moment = 12 x 2(9/3) = 72 Nm

With the consideration of mass of the bar Mbar, this will add to clockwise moment of the seesaw.

Therefore, the direction of rotation will be clockwise direction.

Angular acceleration is positive when object is speeding up and negative when slowing down. Also, angular acceleration is positive when speed increases in an anticlockwise direction and negative when speed increases in the clockwise direction.

From the diagram, since the angular speed increase clockwise, the sign of the angular acceleration will be negative.

We can conclude that the direction of rotation will be clockwise direction and the sign of the angular acceleration is negative.

The correct answer is option B

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Science reevaluates a theory when new evidence is found that contradicts it and lots of evidence to support its claims, while hypothesis and theory need evidence to support them.

A scientific theory is a well-sustained body of evidence that is supported by many predictive outcomes.

Conversely, a hypothesis is a plausible explanation that needs to be tested by using the scientific method.

In conclusion, science reevaluates a theory when new evidence is found that contradicts it (question 1) and lots of evidence to support its claims (question 2), hypothesis and theory need evidence to support them (question 3).

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Answer:

To sum up the confusion its

1) D) Science Reevaluates the validity of the theory
2) D) Theories are well established with lots of evidence to support their claims.
3) A) Both a hypothesis and a theory need evidence to support them.

Explanation:

I took the test and it's what the last guy tried to say even if it was all jumbled up...

Answer:

blanket= texture, thermal conductivity,and mass

glass= the rest

Explanation:

im not good at explaining

Answer:

Explanation:

Let the weight of the truck be W . reaction force R = W

Maximum frictional force = μ R

= .8 x W

So for movement of truck

Pulling force = frictional force

10560 = .8W

W = 13200 N

weight of heaviest truck required = 13200 N .

The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.

To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.

The force between two charged particles can be calculated using Coulomb's law:

F = k * |q₁ * q₂| / r²

Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.

First, let's calculate the force exerted on q₂ by q₁:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²

F₁₂ ≈ 252000 N

The force is positive because q₁ and q₂ have opposite charges.

Next, let's calculate the force exerted on q₂ by q₃:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²

F₂₃ ≈ -63000 N

The force is negative because q₂ and q₃ have the same charge.

Finally, we can find the net force on q₂ by summing the individual forces:

Net force = F₁₂ + F₂₃

Net force = 252000 N + (-63000 N)

Net force ≈ 189000 N

The net force on particle q₂ is approximately 189000 N.

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The best way of presenting the information on density graphically would be to use a D, bar graph.

A bar graph is a type of chart that uses rectangular bars to represent data. The bars are typically arranged in columns, with the independent variable (in this case, the type of wood) on the x-axis and the dependent variable (in this case, the density) on the y-axis.

A bar graph is the best choice for this data because it allows for easy comparison of density of different types of wood. We can see at a glance which type of wood is the densest and which type of wood is the least dense.

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The volume of the parallelepiped is 83 cubic units.

The volume of a parallelepiped with sides give as a = ( 7,2 ,4 ) , b = ( 4,7 ,6 ) and c = ( 3,4 ,7 ).

The volume of a parallelepiped with adjacent sides a, b, and c is given by the scalar triple product (a × b) · c.

First, need to calculate the cross product of vectors a and b

a × b =

\(\left[\begin{array}{ccc}i &j&k\\7&2&4\\4&7&6\end{array}\right]\)

= (2 × 6 - 4 × 7) i - (7 × 6 - 4 × 4) j + (7 × 7 - 2 × 4) k

= -8 i - 26 j + 45 k

Now, calculate the scalar triple product

(a × b) · c = (-8)(3) + (-26)(4) + (45)(7) = 83

Therefore, the volume of the parallelepiped is 83 cubic units.

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Answer:

The sphere becomes positively charged.

First compute the resultant force F:

\(\mathbf F_1=(5.90\,\mathbf i-5.60\,\mathbf j)\,\mathrm N\)

\(\mathbf F_2=(4.65\,\mathbf i-5.55\,\mathbf j)\,\mathrm N\)

\(\implies\mathbf F=\mathbf F_1+\mathbf F_2=(10.55\,\mathbf i-11.15\,\mathbf j)\,\mathrm N\)

Then use Newton's second law to determine the acceleration vector \(\mathbf a\) for the particle:

\(\mathbf F=m\mathbf a\)

\((10.55\,\mathbf i-11.15\,\mathbf j)\,\mathrm N=(2.10\,\mathrm{kg})\mathbf a\)

\(\mathbf a\approx(5.02\,\mathbf i-5.31\,\mathbf j)\dfrac{\rm m}{\mathrm s^2}\)

Let \(\mathbf x(t)\) and \(\mathbf v(t)\) denote the particle's position and velocity vectors, respectively.

(a) Use the fundamental theorem of calculus. The particle starts at rest, so \(\mathbf v(0)=0\). Then the particle's velocity vector at t = 10.4 s is

\(\mathbf v(10.4\,\mathrm s)=\mathbf v(0)+\displaystyle\int_0^{10}\mathbf a(u)\,\mathrm du\)

\(\mathbf v(10.4\,\mathrm s)=\left((5.02\,\mathbf i-5.31\,\mathbf j)u\,\dfrac{\rm m}{\mathrm s^2}\right)\bigg|_{u=0}^{u=10.4}\)

\(\mathbf v(10.4\,\mathrm s)\approx(52.2\,\mathbf i-55.2\,\mathbf j)\dfrac{\rm m}{\rm s}\)

If you don't know calculus, then just use the formula,

\(v_f=v_i+at\)

So, for instance, the velocity vector at t = 10.4 s has x-component

\(v_{f,x}=0+\left(5.02\dfrac{\rm m}{\mathrm s^2}\right)(10.4\,\mathrm s)=52.2\dfrac{\rm m}{\mathrm s^2}\)

(b) Compute the angle \(\theta\) for \(\mathbf v(10.4\,\mathrm s)\):

\(\tan\theta=\dfrac{-55.2}{52.2}\implies\theta\approx-46.6^\circ\)

so that the particle is moving at an angle of about 313º counterclockwise from the positive x axis.

(c) We can find the velocity at any time t by generalizing the integral in part (a):

\(\mathbf v(t)=\mathbf v(0)+\displaystyle\int_0^t\mathbf a\,\mathrm du\)

\(\implies\mathbf v(t)=\left(5.02\dfrac{\rm m}{\mathrm s^2}\right)t\,\mathbf i+\left(-5.31\dfrac{\rm m}{\mathrm s^2}\right)t\,\mathbf j\)

Then using the fundamental theorem of calculus again, we have

\(\mathbf x(10.4\,\mathrm s)=\mathbf x(0)+\displaystyle\int_0^{10.4}\mathbf v(u)\,\mathrm du\)

where \(\mathbf x(0)=(-1.75\,\mathbf i+4.15\,\mathbf j)\,\mathrm m\) is the particle's initial position. So we get

\(\mathbf x(10.4\,\mathrm s)=(-1.75\,\mathbf i+4.15\,\mathbf j)\,\mathrm m+\displaystyle\int_0^{10.4}\left(\left(5.02\dfrac{\rm m}{\mathrm s^2}\right)u\,\mathbf i+\left(-5.31\dfrac{\rm m}{\mathrm s^2}\right)u\,\mathbf j\right)\,\mathrm du\)

\(\mathbf x(10.4\,\mathrm s)=(-1.75\,\mathbf i+4.15\,\mathbf j)\,\mathrm m+\dfrac12\left(\left(5.02\dfrac{\rm m}{\mathrm s^2}\right)u^2\,\mathbf i+\left(-5.31\dfrac{\rm m}{\mathrm s^2}\right)u^2\,\mathbf j\right)\bigg|_{u=0}^{u=10.4}\)

\(\mathbf x(10.4\,\mathrm s)\approx(542\,\mathbf i-570\,\mathbf j)\,\mathrm m\)

So over the first 10.4 s, the particle is displaced by the vector

\(\mathbf x(10.4\,\mathrm s)-\mathbf x(0)\approx(270\,\mathbf i-283\,\mathbf j)\,\mathrm m-(-1.75\,\mathbf i+4.15\,\mathbf j)\,\mathrm m\approx(272\,\mathbf i-287\,\mathbf j)\,\mathrm m\)

or a net distance of about 395 m away from its starting position, in the same direction as found in part (b).

(d) See part (c).

Answer:

Explanation:

The iron ring to be put on the rim of a cart wheel is always of slightly smaller diameter than that of the wheel. When the iron ring is heated to become red hot, it expands and slips on to the wheel easily. When it is cooled, it contracts and grips the wheel firmly.

Explanation:

Iron rims are made slightly smaller than the wheels. They are heated red hot before fixing them on the cart wheels to expand them so that they can be easily fixed on the wheels and water is poured on them to cool them. As the rims cool they contract and take the shape of the wheel and get firmly fixed on the wheels.

So iron-rims are heated before putting them on the wheels of Bullock-carts

Hope it will help :)

Answer:

we need the image to do so.

Explanation:

sorry

The number of moles of the air will be 1.6.

The equation of state for a fictitious ideal gas is known as the ideal gas law, also known as the general gas equation. Although it has some restrictions, it is a good approximation of the behaviour of many gases under various circumstances.

Given that an automobile tire has a volume of 0.0185 m ³. At a temperature of 294 K, the pressure in the tire is 212 kPa.

Calculate the volume at pressure P₂,

P₁V₁ = P₂V₂

V₂ = ( P₁V₁ ) / P₂

V₂ = ( 212 x 0.0185 ) / 252

V₂ = 0.0155 m³

The number of the moles will be calculated as:-

PV = nRT

n = ( P₂V₂ / RT)

n = ( 252 x 0.0155 x 1000 ) / ( 8.3145 x 294 )

n = 1.6 moles

Therefore, there will be 1.6 moles in the air.

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1. The time taken for the object to reach the ground is 2.47 s

2. The speed with which the object will reach the ground is 26.206 m/s

1. How do I determine the time taken?

We can obtain the time taken for the object to reach the ground as      follow:

h = ½gt²

30 = ½ × 9.8 × t²

30 = 4.9 × t²

Divide both side by 4.905

t² = 30 / 4.9

Take the square root of both side

t = √(30 / 4.9)

t = 2.47 s

Thus, the time taken to reach the ground is 2.47 s

2. How do i determine the speed?

The speed the object will use to reach the ground can be obtained as follow:

v = u + gt

v = 2 + (9.8 × 2.47)

v = 2 + 24.206

v = 26.206 m/s

Thus, the speed is 26.206 m/s

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The coefficient of static friction places a limit of approximately 3.42 seconds on the minimum time required for the car to accelerate from rest to 60.0 mph (26.8 m/s).

To find the limit that the coefficient of static friction places on the minimum time required for a car to accelerate from rest to 60.0 mph (26.8 m/s), we need to consider the maximum acceleration the car can achieve due to the friction between the rear tires and the pavement.

The maximum acceleration can be determined using the formula:

a_max = μs * g

where μs is the coefficient of static friction and g is the acceleration due to gravity (approximately 9.8 m/s²).

In this case, since the car's engine only turns the two rear wheels, the maximum acceleration is limited by the friction force between the rear tires and the pavement.

Now, to calculate the minimum time required to accelerate to 60.0 mph (26.8 m/s), we can use the following kinematic equation:

v = u + a * t

where v is the final velocity (26.8 m/s), u is the initial velocity (0 m/s), a is the acceleration, and t is the time.

Rearranging the equation, we have:

t = (v - u) / a

Plugging in the values, we get:

t = (26.8 m/s - 0 m/s) / a_max

t = 26.8 m/s / (μs * g)

Substituting the given value for the coefficient of static friction (μs ≈ 0.800) and the acceleration due to gravity (g ≈ 9.8 m/s²), we can solve for the minimum time required:

t = 26.8 m/s / (0.800 * 9.8 m/s²)

t ≈ 3.42 seconds

Therefore, the coefficient of static friction places a limit of approximately 3.42 seconds on the minimum time required for the car to accelerate from rest to 60.0 mph (26.8 m/s).

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Answer:

I think Albert Einstein invented physics.

Explanation:

Iam soory if Iam wrong.

-0.5m/s^2 is the  acceleration of the car

Because we have the Initial velocity (20 m/s), the final velocity (0 m/s), and the distance traveled x=400m. we can use the kinematic equation

Vf^2= Vo^2 + 2ax,

vf will be zero.

0= Vo^2+ 2ax

Vo^2= -2ax

20^2= -2a(400)

1= -2a

a= -1/2= -0.5m/s^2

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When a 1200 kilogram safe is 2.1 m above a heavy-duty spring and the rope holding the safe breaks, the spring constant is 199,136 N/m (roughly 200 kN/m). The safe collides with the spring, compressing it by 56 cm.

In physics, an object's kinetic energy is the energy it has as a result of its motion. It is defined as the amount of work required to accelerate a body of a given mass from rest to a certain velocity. The body retains its kinetic energy after gaining it during acceleration until its speed changes. Kinetic energy is the energy that an item has as a result of its movement. If we wish to accelerate an item, we must apply force to it. Using force demands us to put in effort. After work is completed, energy is transferred to the item, and the thing moves at a new constant speed.

Here,

The spring constant is 200kN/m.

The work done on the spring by the the free falling safe is equal to the kinetic energy of the spring:

W1 =1/2kx²

The work done on the safe by gravity is the potential energy of the spring:

W2 = (mass of safe) x g x (height)

    = 1000kg x 9.8 m/s^2 x (2 + 0.54)m

    =1000kg x 9.8 m/s^2 x (2.54)m

    = 24,892 N-m

W2 = W1 =24892 N-m

W=1/2kx²

Therefore, k = 199136 kN/m.

The spring constant is 199,136 N/m approximately 200 kN/m when a 1200 kg safe is 2.1 m above a heavy-duty spring when the rope holding the safe breaks. the safe hits the spring and compresses it 56 cm.

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A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.

To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.

Given:

Resistance of the coil, R1 = 4 ohm

Resistance of the other resistor, R2 = 8 ohm

Current passing through the 8-ohm resistor, I = 2A

First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.

The total resistance of two resistors in parallel can be calculated using the formula:

1/Rp = 1/R1 + 1/R2

Substituting the given values, we have:

1/Rp = 1/4 + 1/8

1/Rp = 2/8 + 1/8

1/Rp = 3/8

Rp = 8/3 ohm

Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).

R_total = R_internal + Rp

R_total = 0.5 + 8/3

R_total = 1.833 ohm

Now, we can find the emf of the cell using Ohm's Law:

emf = I * R_total

emf = 2 * 1.833

emf ≈ 3.667 volts

Therefore, the emf of the cell is approximately 3.667 volts.

However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.

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Answer:

A. the inertia of shelly

Explanation:

Answer:

A.  the inertia of Shelly

Explanation:

newtons first law states that an object at rest stays at rest unless on opposite force act against it, so when the buss started to move it acted on shelly forcing her to move back. Shelly's inertia was at a halt and was forced back by the motion of the bus.

The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.

To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.

Given:

R1 = 4 Ω

R2 = 30 Ω

R3 = 10 Ω

R4 = 5 Ω

Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:

RT1-2 = R1 + R2

RT1-2 = 4 Ω + 30 Ω

RT1-2 = 34 Ω

Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:

1/RTotal = 1/RT1-2 + 1/R3

1/RTotal = 1/34 Ω + 1/10 Ω

1/RTotal = (10 + 34) / (34 * 10) Ω

1/RTotal = 44 / 340 Ω

1/RTotal ≈ 0.1294 Ω

RTotal ≈ 1 / 0.1294 Ω

RTotal ≈ 7.74 Ω

Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:

RTotalCircuit = RTotal + R4

RTotalCircuit = 7.74 Ω + 5 Ω

RTotalCircuit ≈ 12.74 Ω

Therefore, the total resistance of the circuit is approximately 12.74 Ω.

To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:

I = V / RTotalCircuit

I = 56 V / 12.74 Ω

I ≈ 4.39 A

Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).

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Answer:

3. Only accelerated motion can be sensed

Explanation:

Without windows on such a train, you'd have no frame of reference for your speed. By that I mean, without being able to see how fast you are moving past other things, it's almost as if you aren't moving at all... almost.

At rest you obviously aren't moving and in uniform motion, with a constant speed, it would feel as though you aren't moving. But during periods of acceleration you'll feel the force on your body (F=ma) and would be able to tell if you were moving in a particular direction.

You've probably felt this before. Maybe not on a windowless train but perhaps in a car or on a roller coaster. Speeding up makes you go back into your seat a bit and slowing down makes you lean forward a bit. Both speeding up and slowing down are examples of acceleration (just in different directions) and how fast you accelerate will affect how much force you experience.

So the answer would be option 3.

Side note: If the train wasn't smooth riding then there would be some amount of friction going on and you could probably tell if you were in motion by the products of that friction (like sound and vibrations) even at a constant speed.

The distance of the balance point of the ruler from zero when the body is moved to the 25cm mark is (14d + 280)/9 cm.

Let X be the mass of the body in grams, and let d be the distance from the pivot to the balance point of the ruler in centimeters when the body is at the 15cm mark.

Total clockwise moment about the pivot = Total anticlockwise moment about the pivot

Clockwise moment due to the ruler = (mass of the ruler) x (distance from the pivot to the ruler's center of gravity)

= (36 g) x (55 cm)

= 1980 g cm

Clockwise moment due to the body = (mass of the body) x (distance from the pivot to the body)

= X g x (15 cm)

= 15X g cm

Anticlockwise moment due to the ruler = (mass of the ruler) x (distance from the pivot to the balance point of the ruler)

= (36 g) x (d - 30 cm)

= 36 (d - 30) g cm

Anticlockwise moment due to the body = (mass of the body) x (distance from the pivot to the balance point of the ruler)

= X g x (30 - d) cm

= 30X g cm - Xd g cm

Equating the clockwise and anticlockwise moments, we have:

1980 g cm + 15X g cm = 36 (d - 30) g cm + 30X g cm - Xd g cm

Simplifying and rearranging, we get:

45X g = 6 (d - 30) g + 1980 g

45X g = 6d g - 180 g + 1980 g

45X g = 6d g + 1800 g

X = (6d + 1800)/45 g

X = (2d + 600)/15 g

Therefore, the mass of the body is (2d + 600)/15 grams.

1980 g cm + 25X g cm = 36 (e - 30) g cm + 30X g cm - Xe g cm

45X g = 6 (e - 30) g + 1980 g - 25X g

45X g = 6e g - 180 g + 1980 g - 25X g

45X g + 25X g = 6e g + 1980 g - 180 g

70X g = 6e g + 1800 g

e = (70X + 1800)/6 g

e = (35X + 900)/3 g

Substituting X = (2d + 600)/15 g, we get:

e = (35/3)((2d + 600)/15) + 900/3 g

e = (14d + 280)/9 g

Therefore, the distance of the balance point of the ruler from zero when the body is moved to the 25cm mark is (14d + 280)/9 cm.

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Answer:

The magnitude of displacement vector 2D-E is approximately 14.49 units. The calculation is done using the Pythagorean theorem after finding 2D-E by multiplying vector D by 2 and subtracting vector E.

Explanation:

The value of 2D-E must first be calculated in order to ascertain the displacement 2D-E's magnitude. Vector D may be multiplied by two to accomplish this, and the result can be obtained by deducting vector E:

2D-E = 2(6i + 3j - k) 4i + 5j + 3k = 8i + 11j - 5k - (4i - 5j + 3k) = 12i + 6j - 2k

We can use the Pythagorean theorem to determine the magnitude of the displacement vector now that we know it:

|2D-E| = √(8² + 11² + (-5)²) = √(64 + 121 + 25) = √210 ≈ 14.49

The displacement 2D-E magnitude is therefore 14.49 units or such. From the object's beginning location to its ultimate position, the displacement's entire length is shown by this. Being a scalar variable, the displacement's magnitude does not reveal the displacement's direction.

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Explanation: make brainalist and keep smiling

First, recall the definition of work. The work done by a constant force is equal to the force multiplied by a displacement

s:W=F⋅s

If the work done was 55,000 Joules, and the displacement traversed was 25 meters, then all you need to do is substitute into the equation:

55,000J

=25m⋅F

Divide both sides by 25 meters to solve for

F

:

55,000

J25m=F

Since the Joule is defined as Newtons multiplied by meters, the meters will cancel off, and our answer will be:

F=2,200N

The distance CE is called the altitude of the triangle ABD.

In mathematics, the distance CE is called the altitude of the triangle ABD.

An altitude is a line segment drawn from the vertex of a triangle to the opposite side, and it is perpendicular to that side.The altitude CE divides the triangle into two smaller right triangles, ACE and BCE.

The length of the altitude can be found using the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

To find the length of the altitude CE, you would use the Pythagorean theorem on either of the right triangles.

For example, using the right triangle ACE, you would have:

AC² + CE² = AE²

Where AC is the length of one of the legs of the triangle, CE is the length of the altitude, and AE is the length of the hypotenuse.

By rearranging this equation, you can solve for CE:

CE² = AE² - AC²CE = √(AE² - AC²)

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The subject depicted in the attached image is Astronomy and Astrophysics.

Astronomy is the scientific study of celestial objects such as stars, planets, galaxies, and other phenomena that exist outside of Earth's atmosphere.

Astronomers use a variety of methods to observe and study these objects, including telescopes, spacecraft, and computer simulations.

Astronomy is a broad field that includes many different sub-disciplines, such as astrophysics, planetary science, and cosmology.

Astronomers study the physical properties and behavior of celestial objects, such as their composition, temperature, motion, and evolution.

They also seek to understand the structure and history of the universe as a whole.

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In our lives or possibly in countless lifetimes, non-renewable energy sources will deplete or cease to exist. Coal, petroleum, & natural gas make up the majority of non-renewable energy sources.

By most standards, biofuels, oil, and natural gas—cause significantly more damage than renewable energy sources, including air pollution, ill effects on human health, habitat loss for species, water use, land use, the global warming emissions.

Coal, nat gas, oil, & nuclear energy are examples of nonrenewable energy sources. Since we now depend on these resources for the majority of our energy, once they are depleted, they could be replaced, which poses a serious issue for humanity.

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