hi please help which one is it

don't do this "just for points" i need the correct answer

Answer:

36 did not get an A on the test

Step-by-step explanation:

48/4*3=36

Answer:

i have made it in above picture

hope it helps

The velocity of a particle = i + 2t j

The acceleration of a particle = 2 j

The speed of a particle = \(\sqrt{1 + 4t^{2} }\)

Here,

The position function is, \(r (t ) = ti + t^{2} j +2k\)

We have to find, the velocity, acceleration, and speed of a particle with the given position function.

What is Velocity of a particle with the given position function?

The instantaneous velocity v(t) of a particle is the derivative of the position with respect to time. That is, v(t)=dx/dt.

Now,

The position function is, \(r (t ) = ti + t^{2} j +2k\)

The velocity of a particle = \(\frac{d r(t)}{dt}\)

\(r (t ) = ti + t^{2} j +2k\)

\(\frac{d r(t)}{dt} = i + 2t j\)

The acceleration of a particle = \(\frac{d^{2} r(t)}{dt^{2} }\)

\(r (t ) = ti + t^{2} j +2k\)

\(\frac{d r(t)}{dt} = i + 2t j\)

\(\frac{d^{2} r(t)}{dt^{2} }= 2j\)

The speed of a particle = \(| \frac{d r(t)}{dt}| = |v(t)|\)

\(\frac{d r(t)}{dt} = i + 2t j\)

\(|v(t)|=\sqrt{1 + 4t^{2} }\)

Hence, The velocity of a particle = \(i + 2t j\)

The acceleration of a particle = \(2 j\)

The speed of a particle = \(\sqrt{1 + 4t^{2} }\)

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The Holding Period Return (HPR) for Alphabet Inc. (GOOG) from January 1st, 2021 to December 31st, 2021 is X%. The capital gain yield is Y% and the dividend gain yield is Z%.

The HPR calculation involves determining the overall return on an investment over a specific period.

To calculate the HPR for Alphabet Inc. (GOOG) during the given period, we need the closing prices at the beginning and end of the period.

Using the closing price of GOOG on January 1st, 2021, and December 31st, 2021, we can calculate the capital gain yield and dividend gain yield. The formula for HPR is:

HPR = (Ending Value - Beginning Value + Dividends) / Beginning Value

To calculate the capital gain yield, we use the formula:

Capital Gain Yield = (Ending Value - Beginning Value) / Beginning Value

And for the dividend gain yield, we use the formula:

Dividend Gain Yield = Dividends / Beginning Value

By plugging in the appropriate values from the stock prices and dividends, we can calculate the HPR, capital gain yield, and dividend gain yield.

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Weighted least squares (WLS) method cannot be used to check if the estimated model is free of heteroscedastic errors.

Heteroscedasticity in a model implies that there is a variance in errors that is not consistent across the sample. To determine if the estimated model free of heteroscedastic errors using Weighted least squares (WLS), it is first important to understand what the term WLS means. WLS is an alternative to ordinary least squares (OLS) that is used to adjust the data for homoscedasticity.

Instead of minimizing the sum of squared residuals, as is the case with OLS, it minimizes the sum of squared weighted residuals. To check for heteroscedasticity, the most straightforward approach is to plot the residuals against the predicted values. If heteroscedasticity is present, the plot will demonstrate a pattern.

On the other hand, if heteroscedasticity is absent, the plot will show a random pattern. When plotting residuals against fitted values, it is critical to examine the plot and make sure the pattern appears to be random. It can be concluded that the estimated model is free of heteroscedastic errors using weighted least squares (WLS) if there is no pattern in the residuals plot.

Checking for heteroscedasticity using variance inflation factor (VIF) is another way to verify if a model is free of heteroscedastic errors. However, this approach is only effective if the model is a multiple regression model. A variance inflation factor (VIF) of one indicates that the variables are not correlated, while a variance inflation factor (VIF) greater than one indicates that the variables are highly correlated.

A VIF value of less than 5 indicates that there is no multicollinearity issue in the model. Hence, this approach cannot be used to check if the estimated model is free of heteroscedastic errors.

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The ΔH values associated with the dissolution of lithium chloride that are exothermic involve the release of heat energy. When a substance dissolves in a solvent, it can either release heat (exothermic) or absorb heat (endothermic).

Here are the steps to determine if the dissolution of lithium chloride is exothermic:

1. Look for the chemical equation that represents the dissolution of lithium chloride. In this case, it would be:

LiCl(s) → Li+(aq) + Cl-(aq)

2. Examine the enthalpy change (ΔH) associated with this chemical equation. If the ΔH value is negative, it indicates an exothermic process, meaning that heat is released during the dissolution. If the ΔH value is positive, it indicates an endothermic process, meaning that heat is absorbed during the dissolution.

So, to identify the exothermic ΔH values associated with the dissolution of lithium chloride, you need to find experiments or reliable sources that provide the enthalpy change values for this reaction.

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The coefficient of x⁵y⁶ in (xy)¹¹ is 462.

The coefficient of x⁵y⁶ in (xy)¹¹ is:

Identify the powers of x and y in the term x⁵y⁶.

The powers are 5 and 6, respectively.

Since (xy)¹¹ is raised to the 11th power, we need to find the binomial coefficient using the formula:

C(n, k) = n! / (k!(n-k)!),

where n is the power (11 in this case) and k is the power of x (5 in this case).

Calculate the binomial coefficient:

C(11, 5) = 11! / (5!(11-5)!) = 11! / (5!6!) = 462.

Therefore, the coefficient of x⁵y⁶ in (xy)¹¹ is 462.

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LCL and UCL values of both scenarios are (158.61,161.39),(69.65,70.35) respectively.

To calculate the lower confidence limit (LCL) and upper confidence limit (UCL) for each given scenario, you'll need to use the following formula:

LCL = X - (z * (sigma / √n))
UCL = X+ (z * (sigma / √n))

where X is the sample mean, n is the sample size, sigma is the population standard deviation, and z is the z-score corresponding to the desired confidence level (1 - alpha).

First Scenario:
X = 160, n = 436, sigma = 30, alpha = 0.01

1. Find the z-score for the given alpha (0.01).
For a two-tailed test, look up the z-score for 1 - (alpha / 2) = 1 - 0.005 = 0.995.
The corresponding z-score is 2.576.

2. Calculate LCL and UCL.
LCL = 160 - (2.576 * (30 / √436)) ≈ 158.61
UCL = 160 + (2.576 * (30 / √436)) ≈ 161.39

First Scenario Result:
LCL = 158.61
UCL = 161.39

Second Scenario:
X= 70, n = 323, sigma = 4, alpha = 0.05

1. Find the z-score for the given alpha (0.05).
For a two-tailed test, look up the z-score for 1 - (alpha / 2) = 1 - 0.025 = 0.975.
The corresponding z-score is 1.96.

2. Calculate LCL and UCL.
LCL = 70 - (1.96 * (4 / √323)) ≈ 69.65
UCL = 70 + (1.96 * (4 / √323)) ≈ 70.35

Second Scenario Result:
LCL = 69.65
UCL = 70.35

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The top right graph could show the arrow's height above the ground over time.

The initial and the final height are both at eye level, which is the reference height, that is, a height of zero.

This means that the beginning and at the end of the graph, it is touching the x-axis, hence either the top right or bottom left graphs are correct.

The trajectory of the arrow is in the format of a concave down parabola, hitting it's maximum height and then coming back down to eye leve.

Hence the top right graph could show the arrow's height above the ground over time.

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Answer:

\(\displaystyle -\frac{1}{3} < x < 2\)

Step-by-step explanation:

We want to solve the quadratic inequality:

\(9x^2-15x<6\)

In order to solve a quadratic inequality, find its zeros. That is, let the inequality sign be an equal sign and solve for x. We do this because it denotes when the graph crosses the x-axis: that is, when it is positive and/or negative. This yields:

\(9x^2-15x=6\)

Solve for x:

\(\displaystyle \begin{aligned} 9x^2-15x-6 &= 0\\ 3x^2 - 15 -6 &= 0 \\ (3x+1)(x-2) &= 0\end{aligned}\)

By the Zero Product Property:

\(\displaystyle 3x + 1 = 0 \text{ or } x - 2 = 0\)

Hence:

\(\displaystyle x = -\frac{1}{3}\text{ or } x = 2\)

Now, we can test intervals. The three intervals are: all values less than -1/3, values between -1/3 and 2, and all values greater than 2.

To test the first interval, let x = -1. Substitute this into our original inequality:

\(\displaystyle \begin{aligned}9(-1)^2 -15(-1) \, &?\, 6 \\ 9+15 \, &? \, 6 \\ 24&> 6 \xmark \end{aligned}\)

The resulting symbol is "greater than," which is not our desired symbol.

To test the interval between -1/3 and 2, we can let x = 0:

\(\displaystyle \begin{aligned} 9(0)^2 - 15(0) \, &? \, 6 \\ (0) - (0) \, &? \, 6 \\ 0 &< 6\, \checkmark\end{aligned}\)

The resulting symbol is indeed less than. So, the interval (-1/3, 2) is a part of our solution.

Finally, to test the third interval, let x = 3. Then:

\(\displaystyle \begin{aligned} 9(3)^2 - 15(3) \, &? \, 6 \\ (81) - (45) \, &? \, 6 \\ 36 &> 6\end{aligned}\)

Again, this is not our desired symbol.

In conclusion, our only solution is the interval:

\(\displaystyle \left(-\frac{1}{3}, 2\right)\)

Or as an inequality:

\(\displaystyle -\frac{1}{3} < x < 2\)

it is seen that if the number of people in the group is n = 23, the probability that at least two people will have the same birthday is at least 1/2.

Let P(A) be the probability that in a randomly selected group of n people, at least two people have the same birthday.

If we assume that the year has 365 days, then the number of ways to select n people with different birthdays is n x (n-1) x (n-2) x ... x (n-364).

the probability of selecting n people with different birthdays is P(A') = n(n - 1)(n - 2)...(n - 364)/365nThen, the probability that at least two people in a group of n have the same birthday is given by P(A) = 1 - P(A').

We need to find the smallest value of n such that P(A) ≥ 1/2.Let's solve for this.Let us find n such that P(A) ≥ 1/2.

By using the complement rule, 1-P(A') = P(A).Then:1 - n(n - 1)(n - 2)...(n - 364)/365n ≥ 1/2n(n - 1)(n - 2)...(n - 364)/365n ≤ 1/2(2)n(n - 1)(n - 2)...(n - 364) ≤ 365n/2Now, take the natural logarithm of both sides and simplify as follows:ln[n(n - 1)(n - 2)...(n - 364)] ≤ ln[365n/2]nln(n) - ln[(n - 1)!] - ln[(n - 2)!] - ... - ln[2!] - ln[1!] ≤ ln[365n/2]

Therefore, we need at least 23 people in the group for the probability of two or more people having the same birthday to be at least 1/2.

This is because n = 23 is the smallest number for which the inequality holds, and therefore, it is the smallest number of people required to ensure that the probability of two or more people having the same birthday is at least 1/2.

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The space would cost at, $833.34 per month.

:: Total area = 1000 square feet

:: Cost per feet per year = $10

Therefore,

Total cost per year would be, equal to the product of total area and cost per unit area per year.

That is,

Total cost per year = 1000 x $10

That is, $10,000.

Now, we know, there are 12 months in an year.

So, cost per month is, ( total cost per year / 12 )

That is, therefore,

Cost per month = ($10,000 / 12)

Which equals to, $833.34 per month. (rounded off)

So,

The space cost at, $833.34 per month.

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The space cost you $833.33. per MONTH

To calculate the monthly cost, we first need to determine the annual cost of the space.

Given that the cost is $10 per square foot per year, we know, there are 12 months in an year and the space is 1,000 square feet, the annual cost of the space would be:

Annual cost = the space  * cost

Annual cost = 1,000 square feet * $10/square foot = $10,000

To convert this to monthly cost, we divide the annual cost by 12 (the number of months in a year):

Monthly cost = $10,000 / 12 = $833.33

Therefore, the monthly cost of the 1,000 square feet of space in the new building would be $833.33.

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Answer:

Step-by-step explanation:

Find the distance between the given points: (-7, 5) and (-8, 4)

Find the distance between the given points: (-7, 5) and (-8, 4)

On solving the provided question, by properties of parallel lines we got to know that -  1 - A  2 - C  3 - B  4 - D

When two or more lines cross the intersection line, alternate exterior angles result. These angles are created on a number of sides outside the transverse lines. Any two parallel lines that cross one another create two angles with the horizontal line. In the area between the parallel lines, interior angles are formed, while alternate exterior angles are formed in the area outside the parallel lines.

Matches are -

1 - A

2 - C

3 - B

4 - D

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Answer:

Horizontal line: y=-5

Vertical line: x = 4

Step-by-step explanation:

As we have to determine the equations for the horizontal and vertical lines passing through the point (4, -5).

Therefore, the equation of the horizontal line passing through the point (4, -5) will be: y=-5

Therefore, the equation of the vertical line passing through the point (4, -5) will be: x=4

Hence:

Horizontal line: y=-5

Vertical line: x = 4

Answer:

2 + 8x + y^2 +2y = 8

Step-by-step explanation:

(x-h)^2/a^2 - (y-k)^2/b^2 = 1 Step 1: Complete the so to determine the form x^2 + 8x + y^2 +2y = 8 (x^2 + 8x+color(red)(16)) + (y^2 + ...

إجابة (١)

·

Shape: Circle (x+4)2+(y+1)2=9 Explanation: Remember: Some of the formula for conic are: Circle: (x−h)2+(y−k)2=r2 Ellipse: (x−h)2a2+(y−k)2b2=1

i dont know but i do know that OOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOO

Answer:

y = 2/3x + 2/3

Step-by-step explanation:

just substitute every known value into the parent function on a linear function

y = mx +b

-4 = 2/3(-7) +b

now solve for b (the y-intercept)

-4 = -14/3 + b

-12/3 = -14/3 + b ( made it to same denominator)

2/3 = b

Answer:

25v-5y+30

Step-by-step explanation:

-5 times -5 is +25, then you just add on the v so boom 25v

-5 times y, pretend there is an invisible 1 infront of the y, 1y times -5 is -5y

-5 times -6, two negative equal a positive and 5 times 6 is 30, so -5 times -6 is also 30

When the second derivative of a function equals zero, it indicates a possible point of inflection or a critical point where the concavity of the function changes. It is a significant point in the analysis of the function's behavior.

The second derivative of a function measures the rate at which the slope of the function is changing. When the second derivative equals zero at a particular point, it suggests that the function's curvature may change at that point. This means that the function may transition from being concave upward to concave downward, or vice versa.

Mathematically, if the second derivative is zero at a specific point, it is an indication that the function has a possible point of inflection or a critical point. At this point, the function may exhibit a change in concavity or the slope of the tangent line.

Studying the second derivative helps in understanding the overall shape and behavior of a function. It provides insights into the concavity, inflection points, and critical points, which are crucial in calculus and optimization problems.

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When the second derivative of a function equals zero, it indicates a critical point in the function, which can be a maximum, minimum, or an inflection point.

The second derivative of a function measures the rate at which the slope of the function is changing. When the second derivative equals zero, it indicates a critical point in the function. A critical point is a point where the function may have a maximum, minimum, or an inflection point.

To determine the nature of the critical point, further analysis is required. One method is to use the first derivative test. The first derivative test involves examining the sign of the first derivative on either side of the critical point. If the first derivative changes from positive to negative, the critical point is a local maximum. If the first derivative changes from negative to positive, the critical point is a local minimum.

Another method is to use the second derivative test. The second derivative test involves evaluating the sign of the second derivative at the critical point. If the second derivative is positive, the critical point is a local minimum. If the second derivative is negative, the critical point is a local maximum. If the second derivative is zero or undefined, the test is inconclusive.

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1+b²+b⁴ ​can be resolved into factors (1+b²+b),(1+b²- b).

We will evaluate  1+b²+b⁴​ with the help of algebraic identities,

We can write 1+b²+b⁴ as,

1+b²+b⁴ = 1+(b)²+(b²)²

             = 1+(b)²+(b)²+(b²)²-b² (Adding and subtracting b²)

             = 1+2(b²)+(b²)²-(b)²

             = (1)²+2(b²)(1)+(b²)²- (b)²

Now using the identity (a + b)²= a²+b²+2ab, we have,

1+b²+b⁴ = (1+b²)²- (b)²

             = (1+b²+b)(1+b²- b)  [By using identity a²-b²= (a+b)(a-b)]

Therefore, the correct answer is  1+b²+b⁴​= (1+b²+b)(1+b²- b).

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The linear trendline used to forecast sales for a given time period takes the form y = b0 + b1t, where y represents the estimated sales, b0 is the constant term, b1 is the coefficient of the time period variable (t), and t is the time period.

In this equation, the coefficient b1 determines the relationship between the time period and the estimated sales. If b1 increases, it means that for each additional time period, the estimated sales will also increase. On the other hand, if b1 is constant, it implies that the estimated sales do not change with each additional time period.

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The probability that the product of two randomly selected numbers is even is 3/4 or 75%.

To find the probability that the product of two randomly selected numbers is even, we can consider the possible scenarios in which the product is even.

1. If at least one of the selected numbers is even: In this case, the product will be even regardless of the second number.

2. If both selected numbers are odd: In this case, the product will be odd.

Therefore, the only scenario where the product is not even is when both selected numbers are odd.

Let's assume the set of numbers we are selecting from is the set of positive integers.

The probability of selecting an odd number is 1/2, and since we are selecting two numbers independently, the probability of selecting two odd numbers (and therefore the product being odd) is (1/2) * (1/2) = 1/4.

Therefore, the probability that the product of two randomly selected numbers is even is:

1 - 1/4 = 3/4.

Hence, the probability that the product is even is 3/4 or 75%.

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Answer:

The circumference of a semi-circle can be calculated using the formula:

Circumference of a semi-circle = (π × diameter)/2We have a diameter of 26.5 in, and we need to find the circumference of the semi-circle. Therefore, the circumference of the semi-circle is:

Circumference of a semi-circle = (π × 26.5)/2= (3.14 × 26.5)/2= 41.6075 in (rounded to 42 to the nearest hundred)

Therefore, the circumference of the semi-circle with a diameter of 26.5 in is approximately 42 in (rounded to the nearest hundred).

Step-by-step explanation:

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Answer:

Hose A fills at a rate of 10 gal per min

Hose B fills at a rate of 8 gal per min

Hose B fills at a faster rate

Step-by-step explanation:

Answer:

Hose A=10 gal per min

Hose B=8 gal per min

Hose A is faster

Step-by-step explanation:

A) 160 gallon/16 minutes=10 gallons per minute

B) 240 gallon/30 minutes=8 gallons per minute

K' ( -2, 2) , L' (1,2) , M' (1,-1) , N' (-2,-1)

Firstly, we needt to identify the coordinates of the vertices of the quadilateral

Afterwards, we then perform the translation

The translation simply means we add 2 to the x-value and add 4 to the y-value

So if we had coordinates of a vertex as (x,y); upon translation, we will have (x + 2, y+ 4)

Let us identify the vertices;

K'

K (-4,-2)

L (-1,-2)

M (-1,-5)

N (-4,-5)

After translation, we have;

K' ( -2, 2) , L' (1,2) , M' (1,-1) , N' (-2,-1)

Answer:

true

Step-by-step explanation:

Answer:

true

Step-by-step explanation:

2/8

÷2

1/4

1/4=0.25

1/8=0.25

Answer:

x= 17

HJ= 27

JK= 153

HK= 180

Step-by-step explanation:

If HJ=x+10

JK=9x

KH=14x−58

a) The diagram of sketch of the segments described above is attached to this answer.

b) KH = HJ + JK

14x - 58 = (x + 10) + 9x

14x - 58 = x + 10 + 9x

c)

14x - 58 = x + 10 + 9x

14x - 58 = 10x + 10

Collect like terms

14x - 10x = 10 + 58

4x = 68

Divide both sides by 4

4x/4 = 68/4

x = 17

d)

x= 17

HJ= x + 10

= 17 + 10

= 27

Hence, HJ = 27

JK= 9x

= 9 × 17

= 153

Hence, JK = 153

HK=14x −58

HK = 14 × 17 - 58

= 238 - 58

= 180

Hence, HK = 180

In the given public good provision game, player 1's expected payoff for contributing and not contributing depends on player 2's cutoff point (C*₂). When player 1 contributes, their payoff is v - C₁ if C₁ < C*₂, and 0 if C₁ ≥ C*₂. When player 1 does not contribute, their payoff is always 0.

In this public good provision game, player 1's decision to contribute or not contribute depends on their private cost, C₁, and player 2's cutoff point, C*₂. If player 1 contributes, they incur a cost of C₁ but gain access to the public good valued at v dollars. However, if C₁ is greater than or equal to C*₂, player 1's expected payoff for contributing would be 0 since player 2 would not contribute.

On the other hand, if player 1 does not contribute, their expected payoff is always 0, as they neither incur any cost nor receive any benefit from the public good. Therefore, player 1's expected payoff for not contributing is constant, irrespective of the cutoff point.

To determine player 1's expected payoff for contributing, we consider the case when C₁ is less than C*₂. In this scenario, player 2 contributes to the public good, allowing both players to consume it. Player 1's payoff would then be v - C₁, which represents the value of the public good minus their cost of contribution. However, if C₁ is greater than or equal to C*₂, player 1's contribution would be futile, as player 2 would not contribute. In this case, player 1's expected payoff for contributing would be 0, as they would not gain access to the public good.

In summary, player 1's expected payoff for contributing is v - C₁ if C₁ < C*₂, and 0 if C₁ ≥ C*₂. On the other hand, player 1's expected payoff for not contributing is always 0. Therefore, when C₁ is low, player 1 would prefer to contribute, as long as the cost of contribution is less than player 2's cutoff point.

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Step-by-step explanation:

Hey ..but there is nothing from which question can be equated ..

like if they are equal to zero..

or

(4x+45)=(5x-18)

i am giving answer for both scenarios

(4x+45)=0

4x=-45

x=-45/4

x=(-11.25)

(5x-18)=0

5x=18

x=18/5

x=3.6

Incase if they both are equal to each other...

(4x+45)=(5x-18)

(45+18)=(5x-4x)

63=x

x=63

Hope it helps you

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