The Solution in inequality form is 7 ≤ x ≤ 10.
The Solution in interval notation: [7,10].
What is the solution to the compound inequality?Given the data in the question;
-x - 8 ≤ -15 and -18 ≤ -x - 8
To solve, simplify the first part of the inequality by solving for x.
-x - 8 ≤ -15
Add 8 to both sides
-x - 8 + 8 ≤ -15 + 8
-x ≤ -7
Divide both sides by -1
Note that when dividing both sides of an inequality by a negative value, the inequality sign flips direction.
-x/-1 ≥ -7/-1
x ≥ 7
Next, simplify the second part of the inequality by solving for x
-18 ≤ -x - 8
Rewrite as
-x - 8 ≥ -18
Add 8 to both side
-x - 8 + 8 ≥ -18 + 8
-x ≥ -10
Divide both sides by -1
Note that when dividing both sides of an inequality by a negative value, the inequality sign flips direction.
-x/-1 ≤ -10/-1
x ≤ 10
Now, the intersection consist of the elements that are contained in both intervals.
The Solution in inequality form is 7 ≤ x ≤ 10.
The Solution in interval notation: [7,10].
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Mark throws a ball with initial speed of 125 ft/sec at an angle of 40 degrees. It was thrown 3 ft off the ground. How long was the ball in the air? how far did the ball travel horizontally? what was the ball's maximum height?
Answer: To solve this problem, we can use the equations of motion for projectile motion. Let's calculate the time of flight, horizontal distance, and maximum height of the ball.
Time of Flight:
The time of flight can be determined using the vertical motion equation:
h = v₀y * t - (1/2) * g * t²where:
h = initial height = 3 ft
v₀y = initial vertical velocity = v₀ * sin(θ)
v₀ = initial speed = 125 ft/sec
θ = launch angle = 40 degrees
g = acceleration due to gravity = 32.17 ft/sec² (approximate value)
We need to solve this equation for time (t). Rearranging the equation, we get:
(1/2) * g * t² - v₀y * t + h = 0Using the quadratic formula, t can be determined as:
t = (-b ± √(b² - 4ac)) / (2a)where:
a = (1/2) * gb = -v₀yc = hPlugging in the values, we have:
a = (1/2) * 32.17 = 16.085b = -125 * sin(40) ≈ -80.459c = 3Solving the quadratic equation for t, we get:
t = (-(-80.459) ± √((-80.459)² - 4 * 16.085 * 3)) / (2 * 16.085)t ≈ 4.86 secondsTherefore, the ball was in the air for approximately 4.86 seconds.
Horizontal Distance:
The horizontal distance traveled by the ball can be calculated using the horizontal motion equation:
d = v₀x * twhere:
d = horizontal distancev₀x = initial horizontal velocity = v₀ * cos(θ)Plugging in the values, we have:
v₀x = 125 * cos(40) ≈ 95.44 ft/sect = 4.86 secondsd = 95.44 * 4.86
d ≈ 463.59 feet
Therefore, the ball traveled approximately 463.59 feet horizontally.
Maximum Height:
The maximum height reached by the ball can be determined using the vertical motion equation:
h = v₀y * t - (1/2) * g * t²Using the previously calculated values:
v₀y = 125 * sin(40) ≈ 80.21 ft/sect = 4.86 secondsPlugging in these values, we can calculate the maximum height:
h = 80.21 * 4.86 - (1/2) * 32.17 * (4.86)²
h ≈ 126.98 feet
Therefore, the ball reached a maximum height of approximately 126.98 feet.
1/4(12x – 16) = 4 is equivalent to 3x – 16 = 4.
O False
O True
Hi there!
»»————- ★ ————-««
I believe your answer is:
O False
»»————- ★ ————-««
Here’s why:
⸻⸻⸻⸻
\(\boxed{\text{Simplifying the Equation Given...}}\\\\\frac{1}{4}(12x-16)=4 \\---------------\\\\\rightarrow \left \{ {{\frac{1}{4} * 12 = 3} \atop {\frac{1}{4}*-16 = -4}} \right.\\\\\rightarrow \boxed{3x - 4 = 4}\\\\\\\rightarrow\boxed{3x - 4 = 4\neq 3x - 16 = 4} \leftarrow\\\\\text{The 'simplified' equation is not distributed correctly.}\)
⸻⸻⸻⸻
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
tell whether x and y are in a proportional relationship if also write an equation that represents the relationship. for all for give a different explanation 20 points question
Answer: Two quanties are said to have a proportional relationship if they vary in such a way that one of the quantities is a constant multiple of the other, or equivalently if they have a constant ratio. ... inversely proportional: y is inversely proportional to x of y=k/x.
Ajar contains 3 white marbles, 5 orange marbles, 4 yellow marbles, and 2 black marbles. If a marble is drawn at random, find the probability that the marble is not yellow. What is the probability that the marble is not yellow? (Simplify your answer. Type an integer or a fraction.)
Answer:
10/14
Step-by-step explanation:
See 3 +5+4+2= 14 , if the question would be what's the probability of getting yellow the answer would be 4/14 but it's not, so 14 - 4 which will be 10 so 10 / 14 .
The other way is get the sum of all the marbles except the yellow one, then that no. will be upon the total.
Answer: \(\frac{2}{7}\)or 0.2857142857
Step-by-step explanation:
P(not yellow)=\(\frac{4}{14}\)
P(not yellow)=\(\frac{2}{7}\) or 0.2857142857
Point B is located at _____.
By noticing that x grows to the left, we can see that the coordinates of point B are (-3, 0)
How to find the coordinates of point B?
The coordinates of a point are written as (x, y), the fisrt value tells us the horizontal position, while the second value gives the vertical position.
For B, we can see that it lies over the x-axis, so its y-value is y = 0.
Now notice that in this particular case, x grows to the left. And B is at 3 units at the right, then the x-value will be x = -3
Finally, the coordinates of point B are (-3, 0).
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Find the distance between the two points in simplest radical form.
The distance bewteen the points (-3,5) and (3,1) in a simple radical form is 2√13.
What is the distance between the given points?The distance formula used in finding the distance between two points is expressed as;
d = √( ( x₂ - x₁ )² + ( y₂ - y₁ )² )
From the graph;
Point A: (-3,5)
x₁ = -3
y₁ = 5
Point B: (3,1)
x₂ = 3
y₂ = 1
Plug the given values into the distance formula and simplify.
\(d = \sqrt{( x_2 - x_1)^2 + (y_2 -y_1 )^2} \\\\d = \sqrt{( 3-(-3))^2 + (1 -5)^2} \\\\d = \sqrt{( 3+ 3)^2 + (1 -5)^2} \\\\d = \sqrt{( 6)^2 + (-4)^2} \\\\d = \sqrt{36 + 16} \\\\d = \sqrt{52}\\\\d = 2\sqrt{13}\)
Therefore, the distance between the points is 2√13.
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A lake near the Arctic Circle is covered by a thick sheet of ice during the cold winter months. When spring arrives, the warm air gradually melts the ice, causing its thickness to decrease at a rate of
0.2
0.20, point, 2 meters per week. After
7
77 weeks, the sheet is only
2.4
2.42, point, 4 meters thick.
The function's formula for the ice sheet's thickness is S(t) = 0.2t + 1.02.
How to write a linear function for the ice sheet's thickness?Mathematically, a linear function is sometimes referred to as an expression or the slope-intercept form of a straight line and it can be modeled (represented) by this mathematical expression;
S(t) = mt + b
Where:
S(t) represents the ice sheet's thickness.m represents the rate of change (slope) per week.t represents the time (measured in weeks).b represents the y-intercept or initial amount.After a time of 7 weeks and a rate of decrease of 0.2, the y-intercept or initial amount of ice can be calculated as follows;
S(t) = mt + b
2.42 = 0.2(7) + b
2.42 = 1.4 + b
y-intercept, b = 2.42 - 1.4
y-intercept, b = 1.02.
Therefore, the required linear function is given by S(t) = 0.2t + 1.02.
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Complete Question:
A lake near the Arctic Circle is covered by a thick sheet of ice during the cold winter months. When spring arrives, the warm air gradually melts the ice, causing its thickness to decrease at a rate of 0.2 meters per week. After 7 weeks, the sheet is only 2.42 meters thick.
Let S(t), denote the ice sheet's thickness S (measured in meters) as a function of time t (measured in weeks).
Write the function's formula.
S(t) = ?
Which of the following quadratics would NOT have zeros that are 5 and -7?
(1) y= (x + 12-36
(3) y = x2 + 2x - 35
(2) y = (× + 5)(x - 7)
(4) y = 2(× + 7)(× - 5)
The quadratics that would not have 5 and -7 as zeros are (1) and (3)
Identifying the quadratics that would not have 5 and -7 as zeros?From the question, we have the following parameters that can be used in our computation:
Zeros: 5 and -7
This means that
x = 5 and x = -7
Rewrite as
x - 5 = 0 and x + 7 = 0
Multiply both equation
This gives
(x - 5)(x + 7) = 0
Rewrite as
f(x) = (x - 5)(x + 7)
When expanded, we have
f(x) = x² + 2x - 35
So, we have
(2) f(x) = x² + 2x - 35
(4) f(x) = 2(x + 7)(x - 5)
Hence, the quadratics that would not have 5 and -7 as zeros are (1) and (3)
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help asap for brainlist
Answer:
Option D
Step-by-step explanation:
(x + 8) (2x² - 5x - 3)
=> (2x³ - 5x² - 3x) + (16x² - 40x - 24)
=> 2x³ + 11x² - 43x - 24
Hope this helps!
Through (-1,2) parallel to the line x=5. Find an equation of a line that satisfies the given conditions.
Answer:
x= -1
Step-by-step explanation:
Since x= 5 is a vertical line, the unknown line would also be a vertical line with an equation of x=___ as they are parallel to each other.
Given that the line passes through (-1, 2), the equation of the line is x= -1.
Parallel lines have the same slope and will never meet.
On january 1st 1960, a person opened a savings account with $100. Interest, at 5% of the amount standing in the account at the time, was added each year on January 1st, starting in 1961. Given that no withdrawals were made, find the year in which there was more than $520 in the account after the interest had been added
Answer:
1994
Step-by-step explanation:
After 1 year, the balance has been multiplied by 1.05. After t years, it has been multiplied by 1.05^t.
You want to find t such that ...
100(1.05^t) > 520
1.05^t > 5.20
t×log(1.05) > log(5.20) . . . . take logarithms
t > log(5.20)/log(1.05) ≈ 33.8
The account balance will exceed $520 after interest is added in ...
1960 +34 = 1994
I NEED UR HELP PLEASE
The moon is approximately 240,000 miles from earth. What is the
distance between the earth and the moon in km? Use the conversion factor: 1 mi = 1.62 km.
Select one:
O a. 150,000 km
O b. 109, 000 km
O c.528, 000 km
O d. 390,000 km
Answer:
252008 miles 405696 km from earth
Step-by-step explanation:
Solve the right triangle ABC, with C=90°. B=36°12′ c=0.6209 m
In triangle ABC, we are given that angle C is a right angle, which means it measures 90°. We also know that angle B is 36°12′, and side c has a length of 0.6209 m. Our goal is to find the measures of angle A and the lengths of sides a and b.
Using the fact that the sum of angles in a triangle is 180°, we can find angle A:
A + B + C = 180°
A = 180° - B - C = 180° - 36°12′ - 90° = 53°48′
Now, we can apply the trigonometric ratios in the right-angled triangle ABC. The ratios are defined as follows:
Sine (sin) = Opposite / Hypotenuse
Cosine (cos) = Adjacent / Hypotenuse
Tangent (tan) = Opposite / Adjacent
Using the given values, we can determine the lengths of sides a and b:
Sine ratio:
sin B = a / c
Substituting the known values, we find:
sin 36°12′ = a / 0.6209
a = 0.6209 x sin 36°12′ = 0.3774 m
Cosine ratio:
cos B = b / c
Substituting the known values, we find:
cos 36°12′ = b / 0.6209
b = 0.6209 x cos 36°12′ = 0.5039 m
Tangent ratio:
tan B = a / b
Substituting the values of a and b, we find:
tan 36°12′ = 0.3774 / 0.5039 = 0.7499
Therefore, the lengths of sides a and b are approximately 0.3774 m and 0.5039 m, respectively. Angle A measures 53°48′, angle B measures 36°12′, and angle C is the right angle.
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32
The normal systolic blood pressure P, in millimeters
of mercury, for an adult male x years old can be
modeled by the equation P = ( x + 220 )/ 2
. According to
the model, for every increase of 1 year in age, by how
many millimeters of mercury will the normal systolic
blood pressure for an adult male increase?
By 1/2 millimeters of mercury will the normal systolic blood pressure for an adult male increase.
What is blood pressure?The pressure of circulating blood against the walls of blood vessels is referred to as blood pressure (BP). The majority of this pressure is caused by the heart pumping blood through the circulatory system. The term "blood pressure" refers to the pressure in the large arteries when used without qualification. In the cardiac cycle, blood pressure is typically expressed as the ratio of the systolic pressure (maximum pressure during one heartbeat) to diastolic pressure (minimum pressure between two heartbeats). It is expressed in millimeters of mercury (mmHg) above atmospheric pressure.To find by how many millimeters of mercury will the normal systolic blood pressure for an adult male increase:
The normal systolic blood pressure of an adult male increase by millimeters of mercury every 1 year of age is:[(x+1)+220]/2 - (x+220)/2 = (x+1+220-x-220)/2 = 1/2Therefore, by 1/2 millimeters of mercury will the normal systolic blood pressure for an adult male increase.
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what times what equals 400but when added equals 38
Answer:
mathematics 5 puntosHaso minutos what tienes what aquel 400but when
which angle measure 90 degrees and forms a square corner A. acute angle B. obtuse angle C. right angle D. straight angle
Answer:
C. right angle
Step-by-step explanation:
I will upload an image of a right angle that perfectly fits the question:
The angles that measure 90° are called right angles, so the correct option is C.
What is a 90° angle?A 90° angle is the one we get when two perpendicular lines intersect (we actually get four of these).
And are the same ones that we can see on squares or rectangles, where the connecting sides are perpendicular between them.
The name of that type of angle, as one could imagine, is Right Angle (for the nature of the intersection that conforms them). So the correct option is C.
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Lunch is 7.95 the tax is 10% what’s the total cost
Answer: ($)8.75
Step-by-step explanation:
To calculate the tax, simply do 10%(0.1)*7.95 to get 0.795, rounding up to 0.80(money typically rounds up).
To calculate the total cost, simply do 7.95+0.80 to get 8.75.
Hope it helps <3
Need help on this please
Answer:
11.3 (√128)
Step-by-step explanation:
\( \\ {a}^{2} + {b}^{2} = {c}^{2} \)
in this case a is given and c is given
a =side of the triangle
b= side of the triangle
c = hypotenuse or the longest side of the triangle
4^2 + b^2 = 12^2
16+ b^2 = 144
144 - 16 = b^2
128 = b^2
√128 = b
11.3137...= b = 11.3 (rounded to nearest tenth)
Giving brainliest if right
Answer: 715*10^7
Step-by-step explanation:
Answer:
Expressed in scientific notation: 7.15 * 10^7 tons
Step-by-step explanation:
1.Find the period of the following functions. a) f(t) = (7 cos t)² b) f(t) = cos (2φt²/m)
Period of the functions: The period of the function f(t) = (7 cos t)² is given by 2π/b where b is the period of cos t.The period of the function f(t) = cos (2φt²/m) is given by T = √(4πm/φ). The period of the function f(t) = (7 cos t)² is given by 2π/b where b is the period of cos t.
We know that cos (t) is periodic and has a period of 2π.∴ b = 2π∴ The period of the function f(t) =
(7 cos t)² = 2π/b = 2π/2π = 1.
The period of the function f(t) = cos (2φt²/m) is given by T = √(4πm/φ) Hence, the period of the function f(t) =
cos (2φt²/m) is √(4πm/φ).
The function f(t) = (7 cos t)² is a trigonometric function and it is periodic. The period of the function is given by 2π/b where b is the period of cos t. As cos (t) is periodic and has a period of 2π, the period of the function f(t) = (7 cos t)² is 2π/2π = 1. Hence, the period of the function f(t) = (7 cos t)² is 1.The function f(t) = cos (2φt²/m) is also a trigonometric function and is periodic. The period of this function is given by T = √(4πm/φ). Therefore, the period of the function f(t) = cos (2φt²/m) is √(4πm/φ).
The period of the function f(t) = (7 cos t)² is 1, and the period of the function f(t) = cos (2φt²/m) is √(4πm/φ).
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Describe the long run behavior of f(x)=5(2)x+1:
As x→−[infinity], f(x) =
As x→[infinity], f(x) =
The long run behavior of the function f(x)=5(2)x+1 is that it approaches 1 as x approaches negative infinity and it approaches infinity as x approaches positive infinity.
The long-term behavior of the function f(x)=5(2)x+1 can be discovered by examining how the function behaves as x gets closer to negative and positive infinity.
As x→−[infinity], f(x) = 5(2)^ -∞+1 = 5(0)+1 = 1
As x approaches negative infinity, the value of the function approaches 1.
As x→[infinity], f(x) = 5(2)^ ∞+1 = 5(∞)+1 = ∞
As x approaches positive infinity, the value of the function approaches infinity.
As a result, the function f(x)=5(2)x+1 behaves in the long run in such a way that it approaches 1 as x approaches negative infinity and infinity as x approaches positive infinity.
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if 4b is equal to 3 what is b
Answer:
4b=3
b= 3/4
b=0.75
...........................
7.0 x 10^3 + 2.0 x 10^2
Answer:
7200
Step-by-step explanation:
Find the exponents first.
10^3 = 1000
10^2 = 100
So..
7 x 1000 + 2 x 100
Do the multiplication first (BEDMAS - Brackets Exponents Division Multiplication Addition Subtraction).
7000 + 200 = 7200
Problem 2. (20 points) A differential equation is given as x
2
dx
2
d
2
y
+x
dx
dy
+y=ln(x
2
)+1. Use x=exp(z) transformation and reduce this equation to a second-order ODE with constant coefficients and determine the general solution in terms of y and x. You need to show all the steps for changing the variable.
To solve the given differential equation, we will make the substitution x = exp(z).
Let's go through the steps to transform the equation and obtain a second-order ordinary differential equation (ODE) with constant coefficients. Differentiating x = exp(z) with respect to z using the chain rule, we get dx/dz = exp(z) and d^2x/dz^2 = d(exp(z))/dz = exp(z).
Now, let's express the derivatives of y with respect to x in terms of derivatives with respect to z. We have dx/dz = exp(z), so dx = exp(z)dz. By differentiating y with respect to x using the chain rule, we have dy/dx = dy/dz * dz/dx = dy/dz * (dx/dz)^(-1) = dy/dz * exp(-z). Similarly, d^2y/dx^2 = d/dx (dy/dx) = d/dz (dy/dz * exp(-z)) * (dx/dz)^(-1) = [d^2y/dz^2 * exp(-z) - dy/dz * exp(-z)] * exp(-z).
Now, substitute these expressions into the original differential equation. We have (exp(z))^2 * [d^2y/dz^2 * exp(-z) - dy/dz * exp(-z)] * exp(-z) + exp(z) * dy/dz * exp(-z) + y = ln((exp(z))^2) + 1. Simplifying, we get:
exp(z) * [d^2y/dz^2 - dy/dz] + y = 2z + 1.
This is a second-order ODE with constant coefficients. The general solution of this equation can be found by solving the characteristic equation associated with it, which is given by:
r^2 - r + 1 = 0.
The roots of this equation are complex, given by r = (1 ± i√3)/2. Therefore, the general solution of the ODE is:
y = C1 * exp(r1 * z) + C2 * exp(r2 * z), where C1 and C2 are arbitrary constants, and r1 and r2 are the roots of the characteristic equation.
Finally, substituting x = exp(z) back into the equation, the general solution in terms of y and x is:
y = C1 * x^((1 + i√3)/2) + C2 * x^((1 - i√3)/2), where C1 and C2 are arbitrary constants.
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NEED HELP!! Can someone help me solve this puzzle I think I have that first two right?
Reflection of point 1 over X axis is (-4, -2)
Reflection of point 2 over Y axis is (2, 3)
Reflection of point 3 over x = 1 is (2, 1)
Reflection of point 4 over y = x is (2, -1)
What is Reflection of a point?
A reflection point occurs when a figure is constructed around a single point known as the point of reflection or center of the figure. For every point in the figure, another point is found directly opposite to it on the other side.
According to the given question:
1. Reflection of point 1 over X axis (x, -y) ⇔ (x, y)
∴ Reflection of (-4, 2) over X axis is (-4, -2)
2. Reflection of point 2 over Y axis (x, y) ⇔ (-x, y)
∴ Reflection of (-2, 3) over Y axis is (2, 3)
3. Reflection of point 3 over x = 1
∴ Reflection of (-2, 1) over x = 1 axis is (2, 1)
4. Reflection of point 4 over y = x is (x, y) ⇔ (y, x)
∴ Reflection of (-1, 2) over X axis is (2, -1)
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use cylindrical coordinates. Evaluate ∭E (x + y + z) dV , where E is the solid in the first octant that lies under the paraboloid z = 9 − x² − y².
The triple integral using these bounds ∫₀^(π/2) ∫₀^(√(9 - z)) ∫₀^(9 - r^2) (r cosθ + r sinθ + z) r dz dr dθ.
To evaluate the triple integral ∭E (x + y + z) dV in cylindrical coordinates, we first need to express the bounds of the integral and the differential volume element in cylindrical form.
The paraboloid z = 9 - x^2 - y^2 can be rewritten as z = 9 - r^2, where r is the radial distance from the z-axis. In cylindrical coordinates, the solid E in the first octant is defined by the conditions 0 ≤ r ≤ √(9 - z) and 0 ≤ θ ≤ π/2, where θ is the angle measured from the positive x-axis.
Now, let's express the differential volume element dV in cylindrical form. In Cartesian coordinates, dV = dx dy dz, but in cylindrical coordinates, we have dV = r dr dθ dz.
Now we can rewrite the triple integral using cylindrical coordinates:
∭E (x + y + z) dV = ∫∫∫E (r cosθ + r sinθ + z) r dr dθ dz.
The bounds of integration are as follows:
For z: 0 ≤ z ≤ 9 - r^2 (from the equation of the paraboloid)
For r: 0 ≤ r ≤ √(9 - z) (within the first octant)
For θ: 0 ≤ θ ≤ π/2 (within the first octant)
We can now evaluate the triple integral using these bounds:
∫∫∫E (r cosθ + r sinθ + z) r dr dθ dz
= ∫₀^(π/2) ∫₀^(√(9 - z)) ∫₀^(9 - r^2) (r cosθ + r sinθ + z) r dz dr dθ.
Performing the integration in the specified order, we can find the numerical value of the triple integral.
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Solve.
2(x + 1) = -8
Enter the answer in the box.
X=
Answer:
To solve for x in the equation 2(x + 1) = -8, we can use the following steps:
Distribute the 2 on the left side of the equation:
2x + 2 = -8
Subtract 2 from both sides to isolate the x term:
2x = -10
Divide both sides by 2 to solve for x:
x = -5
Therefore, the solution for x is -5.
Answer:
x=-5
Step-by-step explanation:
multiple 2 by x and 1
2x+2
then subtract 2 on both sides
2x=-10
divide 2x from both sides
x=-5
use a triple integral to find the volume of the solid bounded below by the cone z and bounded above by the sphere xyz.
Evaluating this triple integral will give us the volume of the solid bounded below by the cone z and bounded above by the sphere xyz.
To find the volume of the solid bounded below by the cone z and bounded above by the sphere xyz, we can use a triple integral.
First, we need to determine the limits of integration for each variable.
For z, the lower limit is 0 (since the solid is bounded below by the cone z), and the upper limit is the equation of the sphere, which is x^2 + y^2 + z^2 = r^2 (where r is the radius of the sphere). Solving for z, we get z = sqrt(r^2 - x^2 - y^2).
For y, the limits are -sqrt(r^2 - x^2) to sqrt(r^2 - x^2), which represents the cross-section of the sphere at a given value of x.
For x, the limits are -r to r, which represents the entire sphere.
Therefore, the triple integral to find the volume of the solid is:
V = ∭dV = ∫∫∫ dzdydx
Where the limits of integration are:
-∫r^2-x^2-y^2 to ∫sqrt(r^2-x^2-y^2) for z
-∫sqrt(r^2-x^2) to ∫-sqrt(r^2-x^2) for y
-∫-r to ∫r for x
The integrand, dV, represents an infinitesimal volume element in Cartesian coordinates.
Evaluating this triple integral will give us the volume of the solid bounded below by the cone z and bounded above by the sphere xyz.
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Apples are prepared in a process with two resources. The first resource has a capacity of 2.1 apples per hour. The capacity of the second resource is 4.4 apples per hour. The first resource has 1 worker and the second resource has 4 workers. Demand for this process is 1.6 apples per hour. Wages are $8 per hour.
What is the cost of direct labor (in $)?per unit
The cost of direct labor per unit is $5.628 per apple.
To calculate the cost of direct labor per unit, we need to determine the total labor hours required to produce one unit of output and then multiply it by the wage rate.
Let's denote the labor hours required for the first resource as "L₁" and the labor hours required for the second resource as "L₂".
The first resource has a capacity of 2.1 apples per hour, and the demand is 1.6 apples per hour. Therefore, the labor hours required for the first resource per unit of output are:
L₁ = 1 apple / (2.1 apples/hour) = 0.4762 hours/apple (rounded to 4 decimal places)
The second resource has a capacity of 4.4 apples per hour, and the demand is 1.6 apples per hour. Therefore, the labor hours required for the second resource per unit of output are:
L₂ = 1 apple / (4.4 apples/hour) = 0.2273 hours/apple (rounded to 4 decimal places)
Now, let's calculate the total labor hours required per unit:
Total labor hours per unit = L₁ (first resource) + L₂ (second resource)
= 0.4762 hours/apple + 0.2273 hours/apple
= 0.7035 hours/apple (rounded to 4 decimal places)
Finally, to calculate the cost of direct labor per unit, we multiply the total labor hours per unit by the wage rate:
Cost of direct labor per unit = Total labor hours per unit * Wage rate
= 0.7035 hours/apple * $8/hour
= $5.628 per apple (rounded to 3 decimal places)
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11. A landscaper is designing a rectangular garden, which will be 5.00 m
wide by 6.25 m long. She has enough crushed rock to cover an area
of 6.0 m² and wants to make a uniform border around the garden.
How wide should the border be, if she wants to use all the crushed
rock?
9514 1404 393
Answer:
25.5 cm
Step-by-step explanation:
If the walk is x meters wide, it adds 2x to the overall length and width. Then the area of the walkway is ...
(2x +5)(2x +6.25) -(5)(6.25) = 6
4x^2 +22.5x = 6 . . . . simplify left side
4x^2 +22.5x -6 = 0 . . . subtract 6 to put into standard form
Using the quadratic formula, the walkway width can be found to be ...
x = (-22.5 +√(22.5² -4(4)(-6)))/(2(4)) = (-22.5 +√602.25)/8
x ≈ 0.25510
The border width should be about 25.5 cm.