helppp plzzzzzzzzzzz​

The 11-4 skills practice areas of regular polygons and composite figures involve finding the areas of different geometric shapes using specific formulas and methods.

To find the area of regular polygons, you can use the formula (1/2) x apothem x perimeter.

For composite figures, you can break the shape into smaller, more manageable shapes like rectangles, triangles, or circles, and then calculate the area of each component before adding them together.

Hence, The 11-4 skills practice areas of regular polygons and composite figures teach you to find areas using the appropriate formulas and methods, improving your geometry understanding and problem-solving abilities.

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The plan that would give Genesis the lowest monthly payment is D. The monthly credit card payment would be $540.78, which is lower than the monthly payment on the bank loan.

From the information, the home improvement project that totals $16,000, and Genesis is choosing between taking out a simple interest bank loan at 8% for 3 years.

The simple interest earned will be:

= Principal × Rate × Time / 100

= (16000 × 8 × 3)/100

= $551.11

The compound interest will be:

A = P(1 + r/n)^nt

A = accumulated amount

P = amount deposited

r = rate

n = times of compound per year

t = years

This will be:

A = 16000(1 + 0.15/12)^(12×7)

A = $540.78

Therefore the correct option is D.

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(i) Pairs of neighboring angles are supplementary and opposite angles have the same measure.

(ii) The two angles formed by a line coming out of another line are supplementary.

(i) When two straight lines pass through each other, then two pairs of opposite angles are constructed. A pair with angles of \((3\cdot x + 52)^{\circ}\) and another pair with angles of \((2\cdot x + 2)^{\circ}\), each pair of angles with different measures are supplementary.\(\blacksquare\)

(ii) When a straight line comes out of another straight line, from a point distinct to any endpoint of the former, then we construct two supplementary angles. The largest angle has a value of \((10\cdot x + 20)^{\circ}\), whereas the smaller one has a value of \((6\cdot x + 8)^{\circ}\). \(\blacksquare\)

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You must run approximately 3.04 miles per day for the remaining five days in order to complete the total distance of 20 miles.

Let's denote the number of miles you must run per day for the remaining five days as "m".

On the first two days, you ran a total of 4.8 miles. Therefore, the total distance left to cover in the remaining five days is 20 miles - 4.8 miles = 15.2 miles.

Since you will be running the same amount each day for the remaining five days, the total distance covered in those five days will be 5 * m miles.

To determine the value of "m," we can set up an equation:

5 * m = 15.2

Dividing both sides of the equation by 5:

m = 15.2 / 5

m ≈ 3.04

Therefore, you must run approximately 3.04 miles per day for the remaining five days in order to complete the total distance of 20 miles.

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Answer: red hot= $4

gummies=$9

Step-by-step explanation:

3r+1g=21

-(3r+3g=39)

3r+1g=21

-3r-3g=-39

-2g=-18

g=9

3r+1(9)=21

3r=12

r=4

Answer:

r=8, s=3

Step-by-step explanation:

(5+√2)/(4+√8)=

(5+√2)/(4+2√2)=

(5+√2)/2(2+√2)=

(5+√2)(2-√2)/2(2-√2)(2+√2)=

(10-5√2+2√2-2)/2(4-2)=

(8-3√2)/4  ⇔ (r-s√2)/4

r=8, s=3

Answer:

Question 1)

\(\text{ Distance from A to the house is approximately 78.34 meters}\\\text{The height of the house is approximately 50.77 meters}\)

Question 2)

\(\text{ Part A) \cos(x)=\frac{12}{13}} \\ \text{ Part B) \sin(90-x)=\frac{12}{13} }\)\(\text{ Part A) }\\\cos(x)=\frac{12}{13}\\\\\text{ Part B)}\\\sin(90-x)=\frac{12}{13}\)

Step-by-step explanation:

Question 1)

Please first reference below for the image.

Also recall the basic trigonometric functions with SohCahToa.

Part 1)

In order to find the distance, we will need to find the value of \(x\). However, to do so, we must find the value of \(c\) first.

First, we will need to find BM. We can use the smaller triangle. BM is opposite of the smaller triangle, and we already know that the hypotenuse is 20 meters. So, we can use sine:

\(\sin(A)=\frac{\text{opp}}{\text{hyp}}\)

Substitute 32° for A and 20 for the hypotenuse. Our BM is our opposite, so substitute BM for opposite. This yields:

\(\sin(32)=\frac{BM}{20}\)

Solve for BM. Multiply both sides by 20:

\(BM=20\sin(32)\)

Don't approximate just yet. In order to make our answer to most precise, we will approximate at the very end.

So, BM is 20sin(32) meters. BM of the smaller triangle is the same as BM of the larger triangle, so BM of the larger triangle is also 20sin(32). Now, we can find the value of \(c\). However, we will first need to find the value of \(\angle MBT\). To do so, notice that \(\angle ABM, \angle MBT, \text{ and } 40\textdegree\) form a straight angle. Therefore:

\(\angle ABM+\angle MBT+40^\circ=180\)

Simplify:

\(\angle ABM+\angle MBT=140\)

So, we will need to find \(\angle ABM\), which is \(\angle B\) of the smaller triangle. So, we can use the trig functions again. Since we now know BM, we can use cosine. So:

\(\cos(B)=\frac{\text{adj}}{\text{opp}}\)

Substitute 20sin(32) for the adjacent and 20 for the opposite. So:

\(\cos(B)=\frac{20\sin(32)}{20}\)

To solve for B, take the inverse cosine of both sides. Evaluate:

\(B=\cos^{-1}(\frac{20\sin(32)}{20})=58^\circ\)

Therefore, we can substitute 58 for \(\angle ABM\) and solve. This yields:

\(58+\angle MBT=140\\\Rightarrow\angle MBT=82^\circ\)

So, we can now find c. We know BM and that \(\angle B\) (of the larger triangle) is 82°. To find c, then, we will use cosine. So:

\(\cos(B)=\frac{\text{adj}}{\text{hyp}}\)

Substitute 82 for B, 20sin(32) for the adjacent BM, and c for the hypotenuse. So:

\(\cos(82)=\frac{20\sin(32)}{c}\)

Solve for c by cross-multiplying:

\(c=\frac{20\sin(32)}{\cos(82)}\)

Now, finally, we can solve for \(x\). We know \(c\) (the hypotenuse) and we want to find \(x\). We also have an angle of 40°. So, we can use cosine:

\(\cos(40)=\frac{x}{c}\)

Multiply both sides by \(c\):

\(x=c\cos(40)\)

Substitute \(c\):

\(x=\frac{20\sin(32)\cos(40)}{\cos(82)}\)

Approximate:

\(x\approx58.34\text{ meters}\)

However, this is only \(x\). The distance from the house is \(x+20\). Therefore, the distance from the house is:

\(d\approx58.34+20\approx78.34\text{ meters}\)

Part 2)

We want to find the height h. Since we already determined \(c\), we can use it to find \(h\). We will use the sine function this time:

\(\sin(40)=\frac{h}{c}\\\Rightarrow h=c\sin(40)\\\Rightarrow h=\frac{20\sin(32)\sin(40)}{\cos(82)}\\\Rightarrow h\approx48.95\)

However, we will still need to add the eye level of 182 centimeters or 1.82 meters. So:

\(h\approx48.95+1.82\approx50.77\text{ meters}\)

The height of the house is approximately 50.77 meters.

Question 2)

We know that: \(\tan(x)=\frac{5}{12}\)

Remember that tangent is the opposite side over the adjacent side. So, let's find the hypotenuse. We can us the Pythagorean Theorem:

\(a^2+b^2=c^2\)

Substitute 5 for a and 12 for b. Solve for c:

\(c^2=(5)^2+(12)^2\\\Rightarrow c^2=25+144\\\Rightarrow c=\sqrt{169}=13\)

So, our hypotenuse is 13, our adjacent is 12, and our opposite is 5. We can now solve for the others:

A)

\(\cos(x)=\frac{\text{adj}}{\text{hyp}}\\\Rightarrow\cos(x)=\frac{12}{13}\)

B)

\(\sin(90-x)=\cos(x)\\\text{Note: This is a cofunction identity}\\\Rightarrow\sin(90-x)=\frac{12}{13}\)

Note: The document I found said \(\sin^2(90-x)\). Anyways, it will just be: \(\sin^2(90-x)=\frac{144}{169}\)

Answer:

C. Corresponding angles

Step-by-step explanation:

Hope this helps!

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The infinite geometric series will converge if the common ratio of the next terms is 1/5. Each phrase in this series is created by multiplying the one before it by a fifth.

The series converges when the common ratio's absolute value (in this case, 1/5 of 1) is smaller than 1. We may use the formula for the sum of an infinite geometric series, which is provided by S = a / (1 - r), where 'a' is the first term and 'r' is the common ratio, to calculate the sum of the infinite series. In this instance, a = 1/5 and r = 1/5 are substituted into the formula to yield S = (1/5) / (1 - 1/5) = 1/4. As a result, the total of the infinite geometric series 1/5 is equal to 1/4.

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Answer: The fewest number of inches that can be the length of one of the remaining sides is 2 inches.

Step-by-step explanation:

Let's denote the lengths of the other two sides as x and y, where x is the side we are looking for.

According to the triangle inequality theorem, the sum of any two sides of a triangle must be greater than the third side. Therefore, we have:

x + 25 > y and x + y > 25

We also know that the perimeter of the triangle is 80, so:

x + y + 25 = 80

Combining the second and third equations, we get:

x + y > 55

Substituting the third equation into the first inequality, we get:

80 - y > y - 25

Solving for y, we get:

y > 52.5

Since y must be a whole number, the smallest possible value for y is 53. Substituting this value into the equation x + y + 25 = 80, we get:

x + 53 + 25 = 80

Simplifying this equation, we get:

x = 2

Therefore, the fewest number of inches that can be the length of one of the remaining sides is 2 inches.

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Answer:

\( \frac{m}{k} = x \\ \\ kx = m \\ \\ k = \frac{m}{x} \)

I hope I helped you^_^

Answer:

\( \frac{m}{k} = x \\ \\ \frac{1}{k} = \frac{x}{m} \\ \\ k = \frac{m}{x} \)

Hope it helps

Answer:

I'm not sure if its A or C but C sounds like it could be the right answer

Step-by-step explanation:

Answer: Planting vegations near riverbanks

Step-by-step explanation:

because everything else is harmful to the earth .-.

Hence, \(\frac{-1-3}{4-(-2)}\)  is the required fraction.

We know that the slope of a line is defined as the change in y coordinate with respect to the change in x coordinate of that line.

To set up the slope formula for the line that passes through the points (-2, 3) and (4, -1), we can use the formula of the slope

i.e. \(m=\frac{y_2-y_1}{x_2-x_1}\)

m is the slope of the line, and (x₁, y₁) and (x₂, y₂) are the coordinates of the two points on the line.

So, x₁ = -2

y₁ = 3

x₂ = 4

y₂ = -1

Substituting the values in the formula

\(m = \frac{-1-3}{4-(-2)}\)

Hence, \(\frac{-1-3}{4-(-2)}\)  is the required fraction.

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Therefore, 25.8 hours per employee each week is the mean number of hours worked.

The mean in mathematics is the average value among a group of numbers. It is calculated by adding up all of the set's numbers, then dividing the result by the total number of numbers in the set.

You may calculate the mean, for instance, if you have the set of numbers 2, 4, 6, and 8, by adding them all together and dividing by the total number of numbers:

(2 + 4 + 6 + 8) / 4 = 20 / 4 = 5

Consequently, 5 is the mean of these numbers.

In this instance, a store employed 5 workers for varying shifts. The list displays each individual's hours worked.

14 23 26 40 26

We add up all of these numbers and divide by the total number of numbers to determine the mean:

(14 + 23 + 26 + 40 + 26) / 5

= 129 / 5 mean of the numbers of hours worked by the employees = 25.8

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In line 17, "summons" most nearly means calls forth.

What happens when you get summoned?

Can summons be Cancelled?

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The corresponding uncertainty in the x-component of the net force on this system is approximately εFnetx, rounded to at least 3 significant figures.

To find the uncertainty in the x-component of the net force on a system, given uncertainties in the forces and angles, we need to propagate the uncertainties through the calculations. The uncertainties given are εF = 10 N for the forces and εθ = 0.5∘ for the angles. The task is to determine the corresponding uncertainty in the x-component of the net force, keeping at least 3 decimal places in the intermediate steps.

Given:

Uncertainty in force (εF) = 10 N

Uncertainty in angle (εθ) = 0.5∘

To find the uncertainty in the x-component of the net force, we need to consider the uncertainties in the individual forces and angles and how they contribute to the overall uncertainty.

First, we propagate the uncertainty for the x-component of each force. Let's denote the forces as F1 and F2, with uncertainties εF1 and εF2, and the corresponding x-components as F1x and F2x. The uncertainties in the x-components can be calculated as:

εF1x = εF1 * cos(θ1)

εF2x = εF2 * cos(θ2)

Next, we propagate through the subtraction of the x-components. Let's denote the net force as Fnet, with uncertainty εFnet. The uncertainty in the net force's x-component can be calculated as:

εFnetx = sqrt(εF1x^2 + εF2x^2)

Be careful with the sign you should use in the subtraction. The net force's x-component is calculated as:

Fnetx = F1x - F2x

Finally, we consider the uncertainty in the x-component of the net force:

εFnetx = |Fnetx| * (εFnetx / |Fnetx|)

Using the given uncertainties and performing the calculations, we can determine the uncertainty in the x-component of the net force, keeping at least 3 decimal places.

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Let's start graphing the first inequality y > 3x - 4. Since this is already in its slope-intercept form, we can see right away that the y-intercept of its boundary line is at (0, -4) and the slope is 3.

Aside from the y-intercept, let's find another point on the line using the slope. We will add 3 on the y-coordinate of the y-intercept and add 1 on the x-coordinate.

Hence, we have another point on the boundary line at (1, -1).

Let's plot these two points (0, -4) and (1, -1) and connect them using a dashed line since the inequality is "greater than". Also, the shade of the graph will be above the line.

The graph of the first inequality y > 3x - 4 is:

Moving on to the second inequality y ≤ x + 1, the y-intercept is at (0, 1) and the slope is 1.

Let's find another point on the line using the slope by adding 1 on the y-coordinate of the y-intercept and 1 on the x-coordinate.

Therefore, we have another point on the line at (1, 2).

Let's plot these points (0, 1) and (1, 2) on the graph. Connect them using a solid line because the inequality symbol has "or equal to". The shade of the graph will be below the line since the inequality symbol is "less than".

The graph of the second inequality y ≤ x + 1 is:

Combining the two graphs, we have:

The solution to the two inequalities would be the common shaded region, hence, in the diagram, it will be the darker shade.

Based on the given choices, this is shown by Option D.

This I believe would be in terms of long division, correct? If so, follow the steps below to guide you through the process.

___________________________________________________

First, you must multiply both the numerator and denominator by 100.

\(\frac{6.08}{0.16}\)

\(\frac{608}{16}\)

Next, convert the problem into long division format and solve.

   __38

16| 608

Hence, the solution for Long Division of 6.08/0.16 would be 38.

Hope this helps! Please lmk if it does. Good luck!

Area is a measure of the size of a two-dimensional surface or region. It is typically measured in square units, such as square meters or square feet. The area of a shape is found by multiplying the length and width of the shape in most cases, although the formula for finding the area may vary depending on the shape.

In the given question,

To find the unit rate in terms of the number of squirrels per square mile, we need to divide the total number of squirrels by the total area of the park.

Total number of squirrels = 20 + 32 + 128 = 180

Total area of the park = 5 + 8 + 32 = 45

Note: The last blank can be filled with 40, as shown above.

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Answer:

1. 4

2. 512

3. 81

Step-by-step explanation:

Answer:

18

Step-by-step explanation:

The midsegment is calculated as

\(\frac{sumofbases}{2}\) = \(\frac{12+24}{2}\) = \(\frac{36}{2}\) = 18

Answer:

Look below

Step-by-step explanation:

Well, earthquakes do really shake things up, don't they?

The Expected value of M is 65

The Standard error of M is 5

Given,

The sample score, n = 9

The Standard deviation, σ = 15

Population mean, μ = 65

Then,

The Expected value of M = μ

∴ The Expected value of M = 65

The Standard error of M = σ/\(\sqrt{n}\)

                                          \(=\frac{15}{\sqrt{9} } \\\\=\frac{15}{3} \\=5\)

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There are several ways to solve this puzzle and get as close to zero as possible while still meeting the constraints.

One possible way is:

6 / 2 = 3 + 5 - 9 x 1

This equation can be simplified as follows:

6 / 2 = 3 + 5 - 9 x 1

3 = 3 + 5 - 9

3 = -1

However, this solution violates the constraint of making a true statement. Therefore, we need to adjust the equation to make it true while still getting as close to zero as possible. One way to do this is:

6 / (2 + 1) = 3 + 4 - 5 x 9

This equation can be simplified as follows:

6 / (2 + 1) = 3 + 4 - 5 x 9

2 = -38

This solution meets the constraint of making a true statement and gets as close to zero as possible.

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Population: All American households.

Sample: The 1780 American households surveyed.

Individuals: The American households participating in the survey.

In the given scenario, we have a survey of 1780 American households that found 59% of the households own a computer. Let's identify the population, sample, and individuals in the study:

Population: The population refers to the entire group or larger set of individuals that we are interested in. In this case, the population would be all American households.

Sample: The sample is a subset of the population that is chosen to represent the population accurately. In this situation, the survey includes 1780 American households. Therefore, the sample is the 1780 households that were surveyed.

Individuals: The individuals in the study are the specific units or elements being surveyed or examined. In this case, the individuals are the American households that participated in the survey. Each household represents an individual within the study.

To summarize:

Population: All American households.

Sample: The 1780 American households surveyed.

Individuals: The American households participating in the survey.

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Answer:

\(x=0.00009028, x=-2.999909725\)

Step-by-step explanation:

Use the quadratic formula:

\(x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\)

when \(ax^2+bx+c=0\)

Therefore, for \(144000x^2+431974x-39=0\)

a = 144,000   b = 431,974  and c = -39

Substituting this data into the quadratic formula:

\(x=\dfrac{-431974 \pm \sqrt{431974^2-4(144000)(-39)} }{2(144000)}\)

\(x=0.00009028, x=-2.999909725\)

Answer:

D

Step-by-step explanation:

I think it's D. Because you have that free shots give you 1 point so it is 1x or x , then you have two pointers which give you 2 points so it is 2y and you have three pointers which give you 3 points so it is 3z

Answer:

i think B makes more sense

Step-by-step explanation:

The signal has a fundamental period of 6 and contains exclusively odd harmonics (n = 1, 3, 5,...).

A periodic signal is one that repeats the same pattern or sequence of values over a set period of time, referred to as the period or duration of one cycle.

The given signal is:

f(t) = 3sin(t) + 2sin(3t)

To determine whether this signal is periodic or aperiodic, we need to check whether it repeats itself after a certain time interval.

For a signal to be periodic, there must be a value T such that:

f(t) = f(t+T)   for all t

Let's first consider the first term of the signal: 3sin(t). This term is a sinusoidal function with a period of 2π. That is, it repeats itself every 2π units of t.

Now let's consider the second term of the signal: 2sin(3t). This term is also a sinusoidal function, but with a period of 2π/3. That is, it repeats itself every 2π/3 units of t.

To check whether the sum of these two terms is periodic, we need to find the smallest value of T for which the two terms will repeat themselves simultaneously. This is known as the fundamental period.

The fundamental period of a sum of two sinusoidal functions with different periods is given by the least common multiple (LCM) of the individual periods.

In this case, the individual periods are 2π and 2π/3. The LCM of these periods is:

LCM(2π, 2π/3) = 6π

Therefore, the fundamental period of the signal is 6π.

Since the signal is periodic, we can write it as a Fourier series:

f(t) = a0/2 + ∑(n=1 to infinity) [an*cos(nωt) + bn*sin(nωt)]

where:

ω = 2π/T = π/3   (fundamental angular frequency)

an = (2/T) ∫(0 to T) f(t)*cos(nωt) dt

bn = (2/T) ∫(0 to T) f(t)*sin(nωt) dt

Using the formulae for an and bn, we can calculate the coefficients of the Fourier series:

a0 = (1/T) ∫(0 to T) f(t) dt = 0   (since f(t) is odd)

an = (2/T) ∫(0 to T) f(t)*cos(nωt) dt = 0

bn = (2/T) ∫(0 to T) f(t)*sin(nωt) dt =

    (2/6π) ∫(0 to 6π) [3sin(t) + 2sin(3t)]*sin(nωt) dt

Evaluating this integral, we get:

bn = \((2/π) [(-1)^{n-1} + (1/3)(-1)^{n-1}]\)

Therefore, the Fourier series of the signal is:

f(t) = ∑(n=1 to infinity) [(2/π) [(-1)^n-1 + (1/3)(-1)^n-1]]*sin(nπt/3)

So, the signal is periodic with a fundamental period of 6π, and it contains only odd harmonics (n = 1, 3, 5, ...).

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A. The appropriate inference procedure to test if the M&M color distribution changed from 2008 to 2017 is a goodness-of-fit chi-squared test.

B. The appropriate hypotheses for the test are:

H0: The observed color distribution of the M&M sample collected in 2016-2017 is equal to the M&M color distribution reported by the company in 2008.

Ha: The observed color distribution of the M&M sample collected in 2016-2017 is different from the M&M color distribution reported by the company in 2008.

C. The intermediate components of the chi-squared goodness-of-fit test are:

Expected count: Calculate the expected count of each color based on the M&M color distribution reported by the company in 2008.

Observed count: Observe the actual count of each color in the sample collected in 2016-2017.

Deviation: Calculate the deviation between the observed and expected count for each color.

Chi-squared statistic: Calculate the chi-squared statistic as the sum of the squared deviations, divided by the expected count.

P-value: Find the p-value by comparing the calculated chi-squared statistic to a chi-squared distribution with degrees of freedom equal to the number of colors minus one.

D. The conclusion from the test is not reliable. A p-value of 0.05 is usually used as a threshold for significance, and if the p-value is more significant than 0.05, the conclusion is that there is not enough evidence to reject the null hypothesis. However, in this case, the sample size is too small (712 candies) to make a reliable conclusion about the population, and the conclusion should be treated with caution.

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The domain and the range of the function are (-∝, ∝) and (0, ∝), respectively

From the question, we have the following parameters that can be used in our computation:

The graph

The above graph is an exponential function

The rule of an function is that

The domain is the set of all real values

In this case, the domain is (-∝, ∝)

For the range, we have

Range = (0, ∝)

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We have the following:

solving for x:

The answer is: