Help with this pls, I am giving brainliest :D

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Explanation:

There are 9 letters in "Metallica", so there would be 9! = 9*8*7*6*5*4*3*2*1 = 362880 different permutations; however, this is only the case if we could tell the letters L and A apart.

We have two copies of each of those repeated letters, so we have to divide by 2!*2! = (2*1)*(2*1) = 4 to account for these repeats.

Because we can't tell the repeated letters apart, we really have (9!)/(2!*2!) = (362880)/(4) = 90720 different permutations.

Answer:

Step-by-step explanation:

it is always greater than its opposite

1. Since triangle ABC and DEF are congruent, the value of x is -3

2. length AB = 24

length DE = 24

If the three angles and the three sides of a triangle are equal to the corresponding angles and the corresponding sides of another triangle, then both the triangles are said to be congruent.

Since triangle ABC is congruent to triangle DEF , then we can say that line AB is equal to line DE

therefore;

12- 4x = 15-3x

collect like terms

12 -15 = -3x +4x

x = -3

therefore the value of x is -3 and

AB = 12 - 4x

AB = 12 -4( -3)

AB = 12 +12 = 24

DE = 15-3x

= 15-3(-3)

= 15 + 9

= 24

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The total mass of the lamina is 32π units, the moment about the x-axis is (32/5), the moment about the y-axis is 0, the center of mass is (0, 1/(5π)), and the moment of inertia about the origin is (64/7)π.

To find the total mass, we need to integrate the density function over the given region

m = ∬ρ(x,y) dA

where ρ(x,y) = 2(x^2+y^2) and the region is x^2+y^2 ≤ 16 in the first quadrant. Using polar coordinates, we have

m = \(\int\limits^0_\(pi /2\) \(\int\limits^0_4\) 2r^2 r dr dθ

= 2 \(\int\limits^0_\(pi /2\) [r^4/2]₀^4 dθ

= 2 \(\int\limits^0_\(pi /2\) 32 dθ

= 32π

So the total mass is 32π.

To find the moment about the x-axis, we need to integrate the product of the density function and the distance from the x-axis

Mx = ∬ρ(x,y) y dA

Using polar coordinates, we have

Mx = \(\int\limits^0_\(pi /2\)\(\int\limits^0_4\)2r^4 sinθ dr dθ

= 2\(\int\limits^0_\(pi /2\) [r^5/5]₀^4 sinθ dθ

= (32/5) \(\int\limits^0_\(pi /2\) sinθ dθ

= (32/5)

So the moment about the x-axis is (32/5).

To find the moment about the y-axis, we need to integrate the product of the density function and the distance from the y-axis

My = ∬ρ(x,y) x dA

Using polar coordinates, we have

My =\(\int\limits^0_\(pi /2\) \(\int\limits^0_4\) 2r^4 cosθ dr dθ

= 2 \(\int\limits^0_\(pi /2\) [r^5/5]₀^4 cosθ dθ

= 0

Since the region is symmetric with respect to the y-axis, the moment about the y-axis is zero.

To find the center of mass (X, Y), we need to use the following formulas

X = (My)/m

Y = (Mx)/m

From part B, Mx = (32/5), and from part A, m = 32π. Therefore:

Y = (Mx)/m = (32/5)/(32π) = 1/(5π)

From part C, My = 0. Therefore, X = 0. So the center of mass is located at (0, 1/(5π)).

To find the moment of inertia about the origin, we need to integrate the product of the density function and the distance squared from the origin

I = ∬ρ(x,y) (x^2+y^2) dA

Using polar coordinates, we have

I = \(\int\limits^0_\(pi /2\) \(\int\limits^0_4\) 2r^4 r^2 dr dθ

= 2\(\int\limits^0_\(pi /2\) [r^7/7]₀^4 dθ

= (128/7) ∫₀^(π/2) dθ

= (64/7)π

So the moment of inertia about the origin is (64/7)π.

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Answer:

5.20² x 15

C. 405.6 pi

Answer:

c

Step-by-step explanation:

Answer:

a₄ = 320

Step-by-step explanation:

To obtain a term in a geometric sequence , multiply the previous term by the common ratio r

r = \(\frac{a_{2} }{a_{1} }\) = \(\frac{20}{5}\) = 4 , then

a₄ = 4 × a₃ = 4 × 80 = 320

Answer:

12 pounds of Kenyan French Roast coffee

8 pounds of Sumatran coffee

Step-by-step explanation:

if you use x pounds of Kenyan French Roast coffee and y pounds of Sumatran coffee then you know that

11x + 10y = 10.6 * 20

x+y=20

10x+10y=200

11x+10y=212

x=12

y = 20-x = 20-12 = 8

so you want to use

12 pounds of Kenyan French Roast coffee

8 pounds of Sumatran coffee

Answer:

A

Step-by-step explanation:

Answer: A

Step-by-step explanation:

ight so basically you got (4,-1) and a slope of 6. you need this formula: y-y1=m(x-x1) so your y1 in this equation would be -1 and your x1 would be 4. now you gotta fill in the blanks which is y+1=6(x-4) (if you confused why the 1 turned to a positive, originally you’re supposed to subtract the y1 but since it was already negative, negative x negative = positive.) so now you got y+1=6(x-4) and boom

answer: y+1=6(x-4)

The mean of the variable given in the question is Option A. 41.6.

To find the mean of the variable, we need to multiply each range of weekly hours worked by its corresponding probability, then sum all of the results.

The calculations are as follows:

(23 * 0.08) + (36 * 0.10) + (43 * 0.74) + (54 * 0.08) = 41.6

Therefore, the mean of the variable is Option A. 41.6.

In this case, the probabilities for each range of weekly hours worked to represent the likelihood of an employee working within that range. For example, the probability of an employee working between 41-50 hours is 0.74, which is quite high compared to the other ranges. As a result, this range has a larger impact on the overall mean of the variable.

It is important to calculate the mean of a variable as it helps in understanding the central tendency of a distribution. In this case, the mean helps us to understand the average number of weekly hours worked by employees, which can be useful in making decisions related to employee scheduling, workload management, and compensation.

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Yes, you can show significant differences using superscripts in an ANOVA (Analysis of Variance) single-factor test.

In an ANOVA test, superscripts are commonly used to indicate significant differences between the means of different groups or treatments.

Typically, letters or symbols are assigned as superscripts to denote which groups have significantly different means. These superscripts are usually presented adjacent to the mean values in tables or figures.

The specific superscripts assigned to the means depend on the statistical analysis software or convention being used. Each group or treatment with a different superscript is considered significantly different from groups with different superscripts. On the other hand, groups with the same superscript are not significantly different from each other.

By including superscripts, you can visually highlight and communicate the significant differences between groups or treatments in an ANOVA single-factor test, making it easier to interpret the results and identify which groups have statistically distinct means.

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The sum of the angle measures of the polygon is 540°, the value of x is 5.

The sum of the angle measures of the polygon is 540°.

We know that the sum of the interior angles of a polygon of n sides = (n – 2) × 180°. = 3× 180°= 540°

If a polygon has x sides, then the sum of its angle measures can be found using the formula:

Therefore, for a polygon with x sides, the equation becomes:

⇒(x-2) * 180° = 540°

Solving for x, we get:

⇒x = (540° + 360°) / 180° + 2

⇒x = 3 + 2

⇒x = 5

So, the polygon has 5 sides.

Therefore, the value of  x is 5.

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Answer:

Step-by-step explanation:

Siny= 4xy +x²

dy/dx(cos y) =4y+ 4x(dy/dx)+2x

making dy/dx the subject

dy/dx(cos y)-4x(dy/dx)=4y+2x

dy/dx(cos y -4x)=4y+2x

dy/dx=(4y+2x)/(cos y -4x)

The percentage of his budget allotted to the variable expenses is 46%.

Winston has $2,003 to budget each month. He budgets $1,081 for fixed expenses and the remainder of his budget is set aside for variable expenses.

Therefore, the percentage allotted for variable expenses can be calculated as follows:

Hence,

percent for allotted for variable expenses = 2003 - 1081 / 2003 × 100

percent for allotted for variable expenses = 922 / 2003 × 100

percent for allotted for variable expenses = 92200 / 2003

percent for allotted for variable expenses = 46.0309535696

percent for allotted for variable expenses = 46%

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Answer:

14

Step-by-step explanation:

8x-1 = 7x+13

type it into desmos next time

The final value is 4 (mod5)

Hence, 17^342 ≡ 2^342 ≡ 4 (mod5).

To find 5^903 (mod60), we can use Euler's totient function. Since 60 = 2^2 × 3 × 5, we have φ(60) = 2^1 × 3^1 × 4 = 24. Therefore, we can use Euler's theorem to write:

5^24 ≡ 1 (mod60)

Raising both sides to the power of 37, we get:

5^(24*37) ≡ 1^37 ≡ 1 (mod60)

So 5^888 ≡ 1 (mod60).

Now, we can write:

5^903 = 5^888 * 5^15

Since 5^888 ≡ 1 (mod60), we just need to find 5^15 (mod60).

To do this, we can use the repeated squaring method. Writing 15 in binary form, we have:

15 = 1111 (in binary)

So we can compute:

5^1 ≡ 5 (mod60)

5^2 ≡ 25 (mod60)

5^4 ≡ 25^2 ≡ 25 (mod60)

5^8 ≡ 25^2 ≡ 25 (mod60)

Therefore:

5^15 ≡ 5^8 * 5^4 * 5^2 * 5^1 ≡ 25 * 25 * 25 * 5 ≡ 25 (mod60)

Hence, 5^903 ≡ 5^15 ≡ 25 (mod60).

To find 17^342 (mod5), we can use the fact that 17 ≡ 2 (mod5). Therefore:

17^342 ≡ 2^342 (mod5)

Using the repeated squaring method again, we can compute:

2^1 ≡ 2 (mod5)

2^2 ≡ 4 (mod5)

2^4 ≡ 1 (mod5)

Therefore:

2^342 ≡ 2^2 * (2^4)^85 ≡ 4 * 1^85 ≡ 4 (mod5)

Hence, 17^342 ≡ 2^342 ≡ 4 (mod5).

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The product or multiplication of the polynomials is given as

x² +11x + 24.

A result or product is produced by multiplication or a statement that lists the factors to be multiplied.

Given (x+8) (x+3)

let us find the product :

= x² + 8x + 3x + 24

= x² +11x + 24

Let us now test the equivalency .

(x+8) (x+3) = (1+8)(1+3) = (9)(4) = 36

x² +11x + 24 = (1)² + 11(1) + 24 = 36

Hence we can see that the product is same in both the cases.

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Answer:

X=13

Step-by-step explanation:

So if ΔABC ≅ ΔDEC, then that means that ∠B is ≅ ∠E. Therefore you would write the equation 3x=6x-39 and solve for X to get 13.

The answer is the lower bound theorem identifies -2 as a lower bound for the real zeros of f(x). The upper bound theorem does not specify any upper bound for the real zeros of (x)

The Lower bound theorem states that "If the terms of a polynomial are arranged in descending order of their degrees, then the absolute value of the quotient of the constant term and the coefficient of the term of the highest degree gives a lower bound for the absolute value of its zeros." Let's examine whether the lower bound theorem identifies -2 as a lower bound for the real zeros of f(x) and whether 3 is an upper bound for the real zeros of (x).

As f(x) = 56 = x + 17x² + 11x + 23Since f(x) is not arranged in descending order of their degrees, we have to rearrange it as follows. 17x² + 11x + x + 23 + 56 = 17x² + 12x + 79 on rearranging the equation we have: 17x² + 12x + 79 = 0Hence the constant term is 79 and the coefficient of the term of the highest degree is 17. Thus, using the lower bound theorem, we can evaluate that a lower bound for the absolute value of the zeros of the polynomial is 79/17 ≈ 4.65 Since -2 is less than the calculated lower bound of 4.65, it is indeed a lower bound for the real zeros of f(x). Now, for (x), the constant term is 0, and the coefficient of the term of the highest degree is 1. Thus, using the upper bound theorem, we can evaluate that an upper bound for the absolute value of the zeros of the polynomial is 1/0, which is equal to infinity. Since infinity is not a number, 3 cannot be an upper bound for the real zeros of (x).

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( A )-  We use the inclusion-exclusion principle to find the total number of integers in the set that are divisible by at least one of 2, 3, 5, or 7. The result is 104.

( B-) There are 48 primes in the set of integers that are divisible by at least one of 2, 3, 5, or 7.

(C-) n must be greater than 120, which means that all composite numbers in the set 1, 2,..., 120 that were not counted in part (a) must be divisible by at least one of 2, 3, 5, or 7.

(a) The number of integers in the set 1, 2,..., 120 that are divisible by at least one of 2, 3, 5, and 7 can be found using the principle of inclusion-exclusion. We first find the number of integers that are divisible by each individual prime factor:

Number of integers divisible by 2: 60

Number of integers divisible by 3: 40

Number of integers divisible by 5: 24

Number of integers divisible by 7: 17

Next, we find the number of integers that are divisible by each pair of prime factors:

Number of integers divisible by 2 and 3: 20

Number of integers divisible by 2 and 5: 12

Number of integers divisible by 2 and 7: 8

Number of integers divisible by 3 and 5: 8

Number of integers divisible by 3 and 7: 5

Number of integers divisible by 5 and 7: 3

We continue in this way to find the number of integers that are divisible by three prime factors, four prime factors, and so on. Finally, we use the inclusion-exclusion principle to find the total number of integers in the set that are divisible by at least one of 2, 3, 5, or 7. The result is 104.

(b) To find the number of primes in the set of integers that are divisible by at least one of 2, 3, 5, or 7, we need to exclude all composite numbers. We can do this by subtracting the number of integers that are divisible by two or more of 2, 3, 5, and 7 from the total number of integers found in part (a):

Number of integers divisible by 2 and 3: 20

Number of integers divisible by 2 and 5: 12

Number of integers divisible by 2 and 7: 8

Number of integers divisible by 3 and 5: 8

Number of integers divisible by 3 and 7: 5

Number of integers divisible by 5 and 7: 3

Number of integers divisible by 2, 3, and 5: 4

Number of integers divisible by 2, 3, and 7: 2

Number of integers divisible by 2, 5, and 7: 2

Number of integers divisible by 3, 5, and 7: 1

Therefore, there are 48 primes in the set of integers that are divisible by at least one of 2, 3, 5, or 7.

(c) Of the integers in 1, 2,..., 120 that were not counted in part (a), the only one that is not prime is 1. To see why all of the others are primes, consider any composite number n that is not divisible by 2, 3, 5, or 7. By the fundamental theorem of arithmetic, n can be written as a product of primes, none of which are 2, 3, 5, or 7. But since n is composite, it must have at least one prime factor other than 2, 3, 5, or 7. Therefore, n must be greater than 120, which means that all composite numbers in the set 1, 2,..., 120 that were not counted in part (a) must be divisible by at least one of 2, 3, 5, or 7.

(d) Using the results from parts (b) and (c), we can find the total number

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Answer:

A regular polygon is a sided polygon in which the sides are all the same length and are symmetrically placed about a common center

Step-by-step explanation:

Your website was partially correct, but wasn't completely reliable. Hope this helped!

The lengths of lines KO and LN is; 24cm and 18m respectively.

Since the face of the building is an equilateral triangle and the sections of reinforcement are parallel to side JP;

On this note, since, MK = 18m +6m = 24m.

Similarly, since, ML = 18m

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Therefore , the solution of the given problem of triangle comes out to be 15 √3 is the length of the triangle's .

If a polygon includes two or more additional components, it is a hexagon. It has a straightforward rectangle shape. The only edges of something like a configuration that can distinguish it from a standard triangle are A and B. The limits continue to be precisely collinear, but Euclidean geometry only yields one section as opposed to a whole cube. A triangle has three sides and three angles.

Here,

opposite/hypotenuse of sin(60 degrees)

which implies:

=>  hypotenuse * sin(60 degrees) = opposite

Likewise, given the angle in the lower right corner is 30 degrees, we can infer the following:

opposite/adjacent = tan(30 degrees)

which implies:nearby + tan(30 degrees) * opposite

. Let's employ the first equation:

=> Hypotenuse = x/sin(60 degrees)

The Pythagorean theorem can be used to determine its length.

=> Hypotenuse 2 equals x 2 plus 15.

If we simplify, we get:

=> √(x2 + 225), hypotenuse

When we enter this expression into the initial equation, we obtain:

=> √(x² + 225) = x/sin(60 degrees).

=> x = √(x2 + 225) * sin(60 degrees)

=> x = (√(3)/2) * √(x² + 225)

=> x² = (3/4) * (x² + 225)

=> 4x² = 3x² + 675

=> x² = 675

=> x = √ (675)

=> x = 15 √3

Hence,  15 √3 is the length of the triangle's .

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Answer:

Y=2(x-5)(x+1)

Y=2x-10+2x+2

=4x-8

Y =4x-8

Answer:

answer = 19.2

Step-by-step explanation:

48 = 24 + 1.25x

48 - 24 = 1.25x

24 = 1.25x

24/1.25 = x

19.2 = x

Answer:

lol

Step-by-step explanation:

What is the equation for three times a number is 27?

3 times a number (9) equals 27. 3 times 9 equals 27. This is correct and we have found and checked our answer!

Answer:

normal force decreases

Step-by-step explanation:

N=mgcosθ, and cosine decreases as theta increases

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Answer:

A) decreases

Step-by-step explanation:

As the angle of the incline increases, the normal force decreases, which decreases the frictional force. The incline can be raised until the object just begins to slide.

Answer:604

Step-by-step explanation: its easy

677-73

As per the given data and on the basis of currency-conversion,

A)a smallest number of coins which are worth exactly the price of the toy, so there is no change=29

B)the smallest number of coins which are worth at least the price of a toy, expecting possible change=30

C)the largest number of coins which are worth exactly the price of the toy with no change=86

What is currency-conversion?

Any medium of exchange that is used to pay for commodities, services, or products, as well as to estimate their value, is referred to as currency or money. Money in circulation in a nation, such as coins, notes, and bills, is referred to as currency. 100 cents to the dollar We multiply (here by 100) a larger unit (a dollar) to get a smaller unit (a cent), and we divide (here by 100) a smaller unit (a cent) to get a larger unit (a dollar).

We know that :

1 penny= 1 cent

1 nickel = 5 cents

1 dime = 10 cents

1 quarter = 25 cents

1 dollar = 100 cents

Ishan has:

43 pennies = 43 cents

31 nickels = 31 x 5 cents

               = 155 cents

21 dimes= 21 x 10

             =210 cents

10 quarters=10 x25

                 =250 cents

total money in cents=43+155+210+250

    Ishan has             =658 cents

Ishan wants to buy a toy car:

price of toy car=3 dollars 99 cents

                        = 3x100 cents+99cents

                        =399 cents

A)To make exactly 399 cents using larger value coins so that number of coins is smallest and no change:

399 cents = 250  cents+ 140  cents+ 5  cents + 4 cents

                 =10 quarters+ 14 dimes + 1 nickel + 4 pennies

Total coins = 10+14+1+4

                   =29 coins

29 coins which are worth exactly the price of the toy, so there is no change.

B)To make 399 cents using larger value coins so that number of coins is smallest possible change:

400 cents = 250  cents + 140  cents + 5  cents + 5 cents

                 =10 quarters+ 14 dimes + 2 nickels

Change=400-399=1 cent

Total coins = 10+14+2

                   =30 coins

30 coins which are worth at least the price of a toy, expecting possible change

C)To make 399 cents with least value coins so that we get the largest number of coins which are worth exactly the price of the toy with no change:

399 cents=34 cents + 155 cents + 210 cents

                =34 pennies + 31 nickels + 21 dimes

Total coins= 34+ 31+21

                 = 86 coins

86 coins which are worth exactly the price of the toy with no change

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