Help please this needs to be turned in tommorrow soo im trying to rush and when i rush i cant focus

Lucy has $7 less than Kristine and $5 more than Nina together, the three have $35. Lucy has $11.

Let's denote the amount of money that Kristine has as K, the amount of money that Lucy has as L, and the amount of money that Nina has as N.

According to the given information, we can form two equations:

Lucy has $7 less than Kristine: L = K - 7

Lucy has $5 more than Nina: L = N + 5

We also know that the three of them have a total of $35: K + L + N = 35

We can solve this system of equations to find the values of K, L, and N.

Substituting equation 1 into equation 3, we get:

K + (K - 7) + N = 35

2K - 7 + N = 35

Substituting equation 2 into the above equation, we get:

2K - 7 + (L - 5) = 35

2K + L - 12 = 35

Since Lucy has $7 less than Kristine (equation 1), we can substitute K - 7 for L in the above equation:

2K + (K - 7) - 12 = 35

3K - 19 = 35

Adding 19 to both sides:

3K = 54

Dividing both sides by 3:

K = 18

Now we can substitute the value of K into equation 1 to find L:

L = K - 7

L = 18 - 7

L = 11

Finally, we can find the value of N by substituting the values of K and L into equation 3:

K + L + N = 35

18 + 11 + N = 35

N = 35 - 18 - 11

N = 6

Therefore, Lucy has $11.

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The statement that best proves that <XWY ≅ <ZYW is that two parallel lines are cut by a transversal, then the alternate interior angles are congruent

To determine the correct statement, we need to know the properties of a parallelogram.

These properties includes;

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The p-value for study B is 0.98.

With the same set of data, two studies were conducted.

Study A was a two-sided test while study B was a one-sided test.

The p-value of the test in study A is 0.040.

If the test statistic from your sample has a negative value, the p-value for a two-sided test is equal to twice the p-value for the lower-tailed p-value. If the test statistic from your sample has a positive value, the p-value is two times that of the upper-tailed p-value.

So, in conclusion:

The one-tail p-value equals one minus half the two-tailed value.

The two-tail p-value is twice the one-tail p-value.

As study A is a two-sided test with p-value = 0.04.

The p-value of study B will be:

p = 1 - ( 1/2 ) × 0.04

p = 1 - 0.02

p = 0.98

The p-value for study B is 0.8.

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Answer:

None of the colors

Step-by-step explanation:

The given parameters can be represented as:

\(Silver = 3\)

\(Red = 3\)

\(Green = 3\)

\(Orange =1\)

\(Total = 10\)

Required

Which has a probability of 12%

To do this, we calculate the probability of each color.

This is calculated as:

\(P(Color) = \frac{Color}{Total}\)

So, we have:

\(P(Silver) = \frac{Silver}{Total}\)

\(P(Silver) = \frac{3}{10}\)

Express as percentage

\(P(Silver) = 30\%\)

\(P(Red) =\frac{Red}{Total}\)

\(P(Red) =\frac{3}{10}\)

Express as percentage

\(P(Red) =30\%\)

\(P(Green) = \frac{Green}{Total}\)

\(P(Green) = \frac{3}{10}\)

Express as percentage

\(P(Green) = 30\%\)

\(P(Orange) = \frac{1}{10}\)

\(P(Orange) = 0.1\)

Express as percentage

\(P(Orange) = 10\%\)

So, we have:

\(P(Silver) = 30\%\)

\(P(Red) =30\%\)

\(P(Green) = 30\%\)

\(P(Orange) = 10\%\)

From the above calculations, none of the colors have a probability of 12%.

The answer choice which could be the length of side BC is; BC < 12.

It follows from the task content that the possible length of the side BC is to be determined.

Since, the sides given AB and BC both have length sum equal to 12. It follows from the triangle inequalities that the length of the third side must be less than the sum of lengths of the other two sides.

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Answe

a is y=1.66667(3)^x

b is 405

c I don't know  sorry

Step-by-step explanation:

Answer:

$39.6

Step-by-step explanation:

5.5 times 7.20 = $39.6

Answer:

heyy

Step-by-step explanation: hey, im sorry i cant answer your question, i need points :(

Answer:

train B

Step-by-step explanation:

it is train B because the graph on train B the number is high

I think, did this help

The level of the liquid is dropping at a rate of 9/(4π) inches per second when the liquid is 1 inch deep.

We are given that the filter is in the shape of a vertex-down cone, with a height of 6 inches and a diameter of 4 inches at its open (upper) end. We are also given that the liquid drips out the bottom of the filter at a constant rate of 3 cubic inches per second.

Let's let h be the height of the liquid in the cone, and let V be the volume of the liquid in the cone.

The volume of a cone is given by the formula:

V = (1/3)πr²h,

where r is the radius of the cone. Since the diameter of the cone at its open end is 4 inches, the radius is 2 inches. Thus, we have:

V = (1/3)π(2²)h = (4/3)πh.

Now, we need to find dh/dt, the rate at which the height of the liquid is dropping, when the liquid is 1 inch deep. Since the liquid is dripping out of the filter at a constant rate of change 3 cubic inches per second, we have:

dV/dt = -3.

Taking the derivative of the equation for V with respect to t, we get:

dV/dt = (4/3)π dh/dt.

Substituting -3 for dV/dt, and substituting 1 for h, we get:

-3 = (4/3)π dh/dt.

Solving for dh/dt, we get:

dh/dt = (-3)/(4/3)π = -9/(4π) inches per second.

Therefore, the level of the liquid is dropping at a rate of 9/(4π) inches per second when the liquid is 1 inch deep.

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Answer: Choice A) 44

==============================================

Work Shown:

cos(angle) = adjacent/hypotenuse

cos(X) = 13/18

X = arccos(13/18)

X = 43.7617 approximately

X = 44

Side note: The arccosine function is the same as inverse cosine as notated by \(\cos^{-1}\). Make sure your calculator is in degree mode.

Answer:

To represent the area of a stained-glass mosaic that sits under a parabolic arch, we can use the equation for a parabolic arch, which is of the form

y = a(x - h)^2 + k

where (h,k) is the vertex of the parabola. The width of the parabolic arch at the base is 8 feet, so the vertex of the parabola is located at (4,0). Therefore, the equation for the parabolic arch is

y = a(x - 4)^2

The height of the parabolic arch is 10 feet, so we can represent the area of the stained-glass mosaic as the region where y is between 0 and 10. This can be expressed as the inequality

0 ≤ a(x - 4)^2 ≤ 10

Solving this inequality for x gives us the solution

-2 ≤ x - 4 ≤ 2

which simplifies to

2 ≤ x ≤ 6

Therefore, the quadratic inequality that represents the area of the stained-glass mosaic is

2 ≤ x ≤ 6

Step-by-step explanation:

Answer:

-------------------------------------------------------

According to given details we have:

The equation for the parabola is y = a(x - h)² + k, where (h, k) is vertex.

Substitute h = 4, k = 10:

We know y = 0 at x = 0, substitute to find the value of a:

So the parabola is:

We are looking for the area between the parabola and the x-axis, therefore we need two inequalities:

See attached for reference.

Answer:  see below

Step-by-step explanation:

Note that an open dot means NOT included and a closed dot means included.

11) 1 < x < 3

   (1, 3)

12) 2 ≤ x ≤ 7

    [2, 7]

13) -3 < x ≤ -1

    (-3, -1]

14) -3 < x ≤ 4

    (-3, 4]

Answer:

x = 7

Step-by-step explanation:

Given

3(x - 4) - 5 = x - 3 ← distribute parenthesis on left side and simplify

3x - 12 - 5 = x - 3

3x - 17 = x - 3 ( subtract x from both sides )

2x - 17 = - 3 ( add 17 to both sides )

2x = 14 ( divide both sides by 2 )

x = 7

Step-by-step explanation:

(Ryan+ castel)/2

(5+6)/2

11/2

5.5 hrs or 5½ hrs

A cylinder's curved section has a constant diameter if the circumference of each of its circular bases equals the height of the cylinder.

We have to given that;

the circumference of each circular base of a cylinder is equal to the height of the cylinder.

Now, We get;

A cylinder's curved section has a constant diameter if the circumference of each of its circular bases equals the height of the cylinder.

Hence, As a result, the cylinder's cross section, or the form you see when you cut it perpendicular to its height, will always be round and its diameter will remain constant over the course of the cylinder's height.

Thus, A cylinder's curved section has a constant diameter if the circumference of each of its circular bases equals the height of the cylinder.

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Answer:

N$12 576. 11

Step-by-step explanation:

Loss%=10%

S.P= N$11 480.50

C.P =?

Loss%=100(C.P - S.P)/C.P

10=100(C.P-11 480.50)/C.P

10C.P=100C.P - 1 148 050

1 148 050=100C.P - 10C.P

1 148 050=90C.P

C.P=N$12 576.11

Answer:

6

Step-by-step explanation:

Answer:

6 is answer

Step-by-step explanation:

Answer:

Step-by-step explanation:

For observers right at the north pole and the south pole, there are only two seasons – an almost six-month long winter night followed by an almost six-month long summer day!

Simplifying the calculation: Therefore, the answer is approximately 0.2745.

To calculate P(A|D), we can use Bayes' theorem:

P(A|D) = (P(D|A) * P(A)) / P(D)

We are given:

P(A) = 0.19

P(D|A) = 0.105

To calculate P(D), we can use the law of total probability:

P(D) = P(D|A) * P(A) + P(D|B) * P(B) + P(D|C) * P(C)

We are given:

P(D|B) = 0.035

P(B) = 0.43

P(D|C) = 0.099

P(C) = 0.38

Now we can substitute these values into the equation:

P(D) = (0.105 * 0.19) + (0.035 * 0.43) + (0.099 * 0.38)

Simplifying the calculation:

P(D) = 0.01995 + 0.01505 + 0.03762

P(D) = 0.07262

Now we can calculate P(A|D):

P(A|D) = (0.105 * 0.19) / 0.07262

Simplifying the calculation:

P(A|D) = 0.01995 / 0.07262

P(A|D) ≈ 0.2745

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Answer:

1. The value of x is 9.4.

2. The value of y is 17.7.

Step-by-step explanation:

The following data were obtained from the question:

Angle θ = 32°

Hypothenus = y

Opposite = x

Adjacent = 15

1. Determination of the value of x.

The value of x can be obtained as follow:

Angle θ = 32°

Opposite = x

Adjacent = 15

Tan θ = Opposite /Adjacent

Tan 32° = x/15

Cross multiply

x = 15 × Tan 32°

x = 9.4

Therefore, the value of x is 9.4

2. Determination of the value of y.

The value of y can be obtained as follow:

Angle θ = 32°

Hypothenus = y

Adjacent = 15

Cos θ = Adjacent /Hypothenus

Cos 32° = 15/y

Cross multiply

y × Cos 32° = 15

Divide both side by Cos 32°

y = 15/Cos 32°

y = 17.7

Therefore, the value of y is 17.7.

Answer: 6,500 feet MSL

Step-by-step explanation:

I don't think any options you provide have the correct answer! It should be 6,500 feet MSL

The system of equations are solved and x = -4 and y = -1

Given data ,

Let the system of equations be represented as A and B

where 3x + 8y = -20   be equation (1)

And , -5x + y = 19   be equation (2)

Multiply equation (2) by 8 , we get

-40x + 8y = 152   be equation (3)

Subtracting equation (1) from equation (3) , we get

-40x - 3x = 152 - ( -20 )

-43x = 172

Divide by -43 on both sides , we get

x = -4

Substituting the value of x in equation (2) , we get

-5 ( -4 ) + y = 19

20 + y = 19

Subtracting 20 on both sides , we get

y = -1

Hence , the equation is solved and x = -4 and y = -1

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5 more than a number is greater or equal to 27

The "number" can be represented as x.

\(\boxed{x+5\geq 27}\)

9514 1404 393

Answer:

  p is proportional to q, r, t, and inversely proportional to s

Step-by-step explanation:

Assuming k is a "constant of proportionality," the value of p is directly proportional to each of the numerator variables: q, r, t. P is inversely proportional to the denominator variable, s.

Answer

length = 11 in

width = 6in

2 in = 5m

length =

28m ÷ 5

= 5

remainder 3m

1 in = 2.5

if 2in = 5m

then 2 × 5 = 10

10 + 1 = 11in

width

2in = 5m

15m ÷ 5

= 3

3× 2

=6

Answer:

Since Q is a center of gravity, we can apply these formulas

1. Projection of b onto row space of A: (3/2, 1/2, 1/2, -1/2)

2. (a) Basis for Nul(A): {(1, -1, -1, 0), (-1, 0, 3, 1)}

(b) Basis for orthogonal complement of Nul(A): {(1, 0, 0, 0), (0, 1, 0, 0), (0, 0, 1, 0), (0, 0, 0, 1), (-1, 3, 1, 0)}

3. (a) Bases for orthogonal complements of V and W: V+ = span{(2,-1,0)}, Wt = span{(-2,4,1)}

(b) Projection of 6 onto V: p = (3/14)(2,-1,0)

4. y = (1/7)(-5,9,-8) + (3/7)(1,3,-2)

1. To find the projection, we first compute the orthogonal complement of the row space of A. Then, we find the projection of b onto the row space of A by projecting it onto the orthogonal complement of the row space of A and subtracting the result from b.

2. (a) To find a basis for the null space of A, we solve the equation Ax = 0 and express the solutions in parametric form, then choose two linearly independent vectors as a basis.

(b) To find a basis for the orthogonal complement of the null space of A, we find a basis for the row space of A and apply the Gram-Schmidt process to obtain a set of orthogonal vectors, then normalize them to obtain an orthonormal basis.

3. (a) To find a basis for the orthogonal complement of V, we find a basis for V and apply the Gram-Schmidt process to obtain a set of orthogonal vectors, then normalize them to obtain an orthonormal basis. Similarly, to find a basis for the orthogonal complement of W, we use the formula Wt = (V ∩ W)⊥.

(b) To find the projection of 6 onto V, we use the formula p = ((6·v)/(v·v))v, where v is any basis vector for V.

Error vector and orthogonal vector: ē = (11/14)(-1,2,5), orthogonal to v = (2,-1,0)

To find the error vector, we subtract the projection of 6 onto V from 6. To find the orthogonal vector to which the error vector is orthogonal, we take the cross product of the basis vectors for V.

4. To write y as a linear combination of a vector in V and a vector in V, we first find a basis for V and use the formula y = ((y·v₁)/(v₁·v₁))v₁ + ((y·v₂)/(v₂·v₂))v₂, where v₁ and v₂ are basis vectors for V.

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The scale factor of the dilation is equal to the similarity ratio of the original figure (ABCD) to the dilated figure (MNOP). They represent the proportional relationship between corresponding lengths.

When MNOP is a dilation of ABCD, the scale factor of the dilation is directly related to the similarity ratio of ABCD to MNOP. The similarity ratio is the ratio of corresponding lengths in the two figures.

In a dilation, the scale factor determines how much the original figure is enlarged or reduced to create the new figure. If the scale factor is greater than 1, the figure is enlarged, and if it is between 0 and 1, the figure is reduced.The similarity ratio compares corresponding lengths in the original figure (ABCD) to their corresponding lengths in the dilated figure (MNOP). Since a dilation is a proportional transformation, the similarity ratio will be equal to the scale factor of the dilation. This is because each length in ABCD is multiplied by the same factor to obtain the corresponding length in MNOP.

Therefore, the scale factor of the dilation is equal to the similarity ratio of ABCD to MNOP. They both represent the proportional relationship between corresponding lengths in the two figures.

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The irrational numbers between 1 and √2 are 1.247......, 1.367.... and  1.1509....

From the question, we have the following parameters that can be used in our computation:

1 and square root 2

Rewrite as

1 and √2

When evaluated, we have

1 and 1.41421356.....

The irrational numbers between the numbers are numbers that cannot be expressed as fractions

Some of these numbers are

1.247......

1.367....

1.1509....

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