Explanation:
1. 19.6m/s
2. 274.4 m/s²
3. 28
what is your centripetal acceleration when you run at 11 m/s around the curve of an olympic track, which has a radius of 36.5 m?
Running at 11 m/s around the curve of an olympic track with a radius of 36.5 m results in a centripetal acceleration of 3.31 m/s2. The pace at which the velocity changes in mechanics is known as acceleration.
The vector quantity of accelerations (in that they have magnitude and direction). The direction of the net force imposed on an object determines its acceleration in relation to that force. the amount of acceleration experienced by an item. A force that causes a body to follow an arc is known as a centripetal force (from the Latin centrum, "centre," and petere, "to pursue").
centripetal acceleration equals v2/r
Centripetal acceleration is (11)2/36.5, and centripetal acceleration is 121/36.5, which equals 3.31 m/s2.
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A soccer ball player is running with a ball. compared to the force of the ball on the foot, the force of foot on the ball is
a- the same
b- greater
c-less
d- none of the above
You weigh 710 N. What would you weigh if the Earth were three times as massive as it is and its radius were five times its present value? Answer in units of N
Answer:
85.2 N
Explanation:
You want to know your weight if the Earth were 3 times as massive and had 5 times the present radius. Your weight is 710 N.
WeightYour weight is proportional to the mass of the Earth and the square of the radius between your mass and the center of the Earth. The revised dimensions of the earth would multiply your weight by ...
W = k(M/r²) = 710 N
W' = k((3M)/(5r)²) = k(M/r²)(3/25) = (710 N)(3/25) = 82.5 N
Your weight would be 82.5 N.
how hard must she pull downward to raise herself slowly at constant speed? the mass of the person plus the bucket is 77 kg .
The person must pull downward with a force equal to her weight, which is approximately 760 N in order to raise herself slowly at a constant speed.
When the person pulls downward on the bucket, there are two forces acting on the system: the force of gravity pulling the person and the bucket down, and the force of the person pulling the bucket up. In order for the person to raise herself at a constant speed, the force she exerts on the bucket must be equal and opposite to the force of gravity pulling her down.
The force of gravity on the person and the bucket is equal to their combined weight, which can be calculated as mass times gravitational acceleration (77 kg x 9.81 m/s^2 = 755.37 N). Therefore, the person must exert a force equal to her weight (approximately 760 N) in order to counteract the force of gravity and raise herself at a constant speed.
Thus, to lift herself up slowly and steadily, the person needs to exert a downward force that is equivalent to her weight, which is around 760 Newtons.
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developing a criterion for judging the effectiveness of a solution occurs during which step of the problem-solving process?
Developing a criterion for judging the effectiveness of a solution occurs during the step of evaluating solutions in the problem-solving process.
Problem-solving is the method of determining a problem's root cause and developing and executing an effective solution. Problem-solving is a critical skill for anyone to have in both their personal and professional lives. The problem-solving process entails the following steps:
1. Identifying and defining the problem
2. Gathering information
3. Developing potential solutions
4. Evaluating alternatives
5. Selecting the best solution
6. Planning and executing the solution
7. Monitoring the solution
You can follow these steps in any order. However, most successful problem-solving approaches are iterative, which means they go back and forth between steps until the best solution is found.
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What is the mean of 4, 6, 8, 20, 12?
10
00
5
Answer:
mean= sum of all values/ total no. of values
values given= 4,6,8,20,12
= 4+6+8+20+12/5
=50/5=10
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vertically polarized light with an intensity of 10 w/m2 passes through a polarizer whose transmission axis is at an angle of 15 degrees with the vertical. what is the intensity of the transmitted light?
Light that is 10 w/m^2 in intensity and vertically polarized flows through a polarizer whose transmission axis is at a 15 degree angle with the vertical .Then the intensity of the transmitted light is 9.3 W/m^2.
How can the intensity of light passing through a polarizer be determined?After passing through a polarizing filter, the intensity of polarized light I is calculated as I = Io cos2, where Io is the initial intensity and is the angle formed by the filter's axis and the direction of polarization.
As is well known, the following equation can be used to determine the strength of transmitted light:
I = Iocos^2(θ),
where I denotes the amount of light being transmitted,
Io is the incoming light's intensity.
Given -
light input power intensity Io= 10 w/m^2
Per-square-meter power
α-15 degrees
In the equation above, by substituting the supplied numbers, we obtain -
I = Iocos^2(θ),
I= 10*cos^2(15)
I= 9.3 w/m^2
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Question 1: A man trailing a trolley bag and suddenly, the wheels of the trolley bag get locked. The man realises that he has to put extra effort to drag the bag. The man finds it difficult to drag the bag because
Answer: Because of the friction force acting directly on the bag.
Explanation:
The function of the wheels is diminish the effect of the friction force, when the friction pulls back, it makes the wheel rotate, and this force is not applied directly on the bag.
Now the wheels are not working, so now the friction is acting directly on the bag, this is why the mand finds more difficult to drag the bag.
As a light ray enters water from air at an angle of 15 degrees with respect to the normal, it
A. always bends toward the normal. B. always bends away from the normal. C. sometimes bends towards the normal. D. sometimes bends away from the normal. E. does not bend.
Answer:
When the light ray enters the water from the air it always bends toward the normal
A is the correct answer
Explanation:
The phenomenon due to which a light ray on entering the water from the air bends towards the normal is called refraction. If the medium in which light is entering is denser than the previous one then light always bends towards the normal as in this case.
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earth’s land areas, oceans, and atmosphere maintain fairly constant average temperatures. what is the best explanation for these constant average temperatures?
The Earth's land areas, oceans, and atmosphere maintain fairly constant average temperatures due to a process called the Earth's heat balance, which refers to the balance between the amount of energy the Earth absorbs from the Sun and the amount of energy the Earth radiates back into space.
The Earth's heat balance is maintained by a number of processes that regulate the temperature of the Earth's surface, including:
Insolation: The Earth absorbs energy from the Sun in the form of electromagnetic radiation, known as insolation. Greenhouse effect: The Earth's atmosphere contains gases that trap some of the heat radiating from the Earth's surface, preventing it from escaping into space. Heat transfer: Heat is transferred from the warmer equatorial regions to the cooler polar regions through a variety of mechanisms, including conduction, convection, and radiation.Albedo: The reflectivity of the Earth's surface, known as albedo, plays a role in the Earth's heat balance.Overall, the Earth's heat balance is maintained by a complex interplay of processes that regulate the temperature of the Earth's surface and atmosphere.
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What is the mass of a crate if a net force of 12 N gives the crate an acceleration of 0.20 m/s2?
A uniform electric field exists everywhere in the x, y plane. This electric field has a magnitude of 4650 N/C and is directed in the positive x direction. A point charge -8.40 10-9 C is placed at the origin.
(a) Determine the magnitude of the net electric field at x = -0.17 m.
N/C
(b) Determine the magnitude of the net electric field at x = +0.17 m.
N/C
(c) Determine the magnitude of the net electric field at y = +0.17 m.
N/C
(a) The magnitude of the net electric field at x = -0.17 m is 1.01x10^5 N/C.
(b) The magnitude of the net electric field at x = +0.17 m is 1.01x10^5 N/C.
(c) The magnitude of the net electric field at y = +0.17 m is 4650 N/C.
Explanation:
To solve this problem, we can use the formula for electric field due to a point charge and the principle of superposition of electric fields.
The electric field due to a point charge is given by:
E = k*q/r^2
where E is the electric field, k is Coulomb's constant (9x10^9 N m^2/C^2), q is the charge, and r is the distance from the point charge.
(a) To find the net electric field at x = -0.17 m, we need to consider the electric field due to the point charge and the uniform electric field. The distance from the point charge to x = -0.17 m is:
r = sqrt((0.17)^2) = 0.17 m
The electric field due to the point charge at x = -0.17 m is:
E1 = kq/r^2 = (9x10^9 N m^2/C^2)(-8.40x10^-9 C)/(0.17 m)^2 = -1.06x10^5 N/C (in the negative x direction)
The electric field due to the uniform electric field is given by:
E2 = 4650 N/C (in the positive x direction)
The net electric field at x = -0.17 m is the vector sum of E1 and E2:
E_net = E1 + E2 = -1.06x10^5 N/C + 4650 N/C = -1.01x10^5 N/C
Therefore, the magnitude of the net electric field at x = -0.17 m is 1.01x10^5 N/C.
(b) To find the net electric field at x = +0.17 m, we follow the same procedure as in part (a). The distance from the point charge to x = +0.17 m is:
r = sqrt((0.17)^2) = 0.17 m
The electric field due to the point charge at x = +0.17 m is:
E1 = kq/r^2 = (9x10^9 N m^2/C^2)(-8.40x10^-9 C)/(0.17 m)^2 = -1.06x10^5 N/C (in the positive x direction)
The electric field due to the uniform electric field is given by:
E2 = 4650 N/C (in the positive x direction)
The net electric field at x = +0.17 m is the vector sum of E1 and E2:
E_net = E1 + E2 = -1.06x10^5 N/C + 4650 N/C = -1.01x10^5 N/C
Therefore, the magnitude of the net electric field at x = +0.17 m is 1.01x10^5 N/C.
(c) To find the net electric field at y = +0.17 m, we only need to consider the electric field due to the uniform electric field, since the point charge is located on the x-axis. The electric field due to the uniform electric field is given by:
E = 4650 N/C (in the positive x direction)
Therefore, the magnitude of the net electric field at y = +0.17 m is 4650 N/C, in the positive x direction
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A bullet is fired upward with an initial velocity of 100 m/s. What will be it’s velocity when it hit the ground?
A bullet is fired upward with an initial velocity of 100 m/s. What will be it’s velocity when it hit the ground?
Zero. It is sitting on the ground. This would almost always “assume” a friction-less environment where the only force acting on the bullet is gravity. In this case, it would be 100 m/s immediately before hitting the ground. (zero once it comes to rest)
is hydrogen good conductor or poor conductor
Answer:
Good one
Explanation:
Hydrogen has the highest thermal conductivity of any gas.
Rank the capacitors on the basis of the charge stored on the positive plate. Rank from largest to smallest: To rank items as equivalent; overlap them: A) A = 4 cm ; C=8nF B) A = 2 cm? =8 nFC) A = 2 cm? =4 nF D) A = 4 cm? C = 2 nF E) A =1 cm? = 1ln F
According to the charge that is stored on the positive plate, the order is B, A, C, D, and E, from biggest to smallest.
The charge stored on the positive plate of a capacitor is given by Q = CV, where Q is the charge, C is the capacitance, and V is the voltage. Since the capacitors are connected in parallel, they all have the same voltage V. Therefore, the capacitor with the largest capacitance will have the largest charge stored on its positive plate.
Ranking the capacitors from largest to smallest based on their capacitances, we get:
B) A = 2 cm, C = 8 nF
A) A = 4 cm, C = 8 nF
C) A = 2 cm, C = 4 nF
D) A = 4 cm, C = 2 nF
E) A = 1 cm, C = 1 nF
Therefore, the ranking from largest to smallest based on the charge stored on the positive plate is: B, A, C, D, E.
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Differentiate snowslide and GLOF
Answer:
As nouns the difference between snowslide and Glof is that snowslide is an avalanche of snow while glof is a globe.
Answer:
Snowslide:
A snowslide (also called an avalanche) is an event that occurs when a cohesive slab of snow lying upon a weaker layer of snow fractures and slides down a steep slope
It is a mass of snow, rock, ice, and soil that tumbles down a mountain.
Glof:
Glof is describe as sudden release of a significant amount of water retained in a glacial lake, irrespective of the cause.
Glof stand for “Glacial lake outburst flood”.
PLEASE HELP An object takes 5.91 Earth years to orbit the Sun. What is its average distance from the Sun? Make sure to show ur work
on a circular path of radius 8 cm in air around a solenoid with increasing magnetic field, the emf is 29 volts. a wire with resistance 5 ohms is placed along the path. what is the current in the wire?
The emf induced in a wire moving on a circular path around a solenoid is given by:
emf = -N * dΦ/dt
where N is the number of turns in the solenoid, Φ is the magnetic flux, and t is time.
Since the wire is moving on a circular path of radius 8 cm, the magnetic flux through the wire is given by:
Φ = B * A
where B is the magnetic field at the position of the wire and A is the area of the circle.
The area of the circle is given by:
A = π * r^2
where r is the radius of the circle, which is 8 cm or 0.08 m.
So, A = π * (0.08 m)^2 = 0.0201 m^2.
The magnetic field is increasing, so we need to use the time derivative of the magnetic field to calculate the emf.
Let's assume that the magnetic field is increasing at a constant rate of 0.1 T/s.
Therefore, the time derivative of the magnetic field is:
d/dt (B) = 0.1 T/s
Substituting these values into the emf equation, we get:
29 V = -N * (d/dt (B)) * A
We don't know the number of turns in the solenoid, but we can solve for N * (d/dt (B)):
N * (d/dt (B)) = -29 V / A
N * (d/dt (B)) = -29 V / 0.0201 m^2
N * (d/dt (B)) = -1442.79 V/m^2
Now we can use Faraday's law to calculate the current in the wire.
The emf induced in the wire is equal to the voltage drop across the wire, which is:
emf = IR
where I is the current in the wire and R is the resistance of the wire.
Therefore, the current in the wire is:
I = emf / R = 29 V / 5 Ω = 5.8 A
So, the current in the wire is 5.8 A.
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A 15.18 Kg box is at rest on a table. What is the applied force needed to just overcome the force of static friction if the coefficient of friction is 0.309? Round your answer to 2 decimal places.A 15.18 Kg box is at rest on a table. What is the applied force needed to just overcome the force of static friction if the coefficient of friction is 0.309? Round your answer to 2 decimal places.
Assuming the box is sitting on a flat surface, static friction would have a maximum magnitude of
0.309mg = 0.309 (15.18 kg) (9.80 m/s²) ≈ 45.97 N
so the applied force should have at least this magnitude.
Why is more difficult to balance a nail it's than on its base
It is more difficult to balance a nail on its tip than on its base because of large base support and low center of gravity.
A object with a broad base of support and a low center of gravity is much simpler to balance. Because to the large base and low center of gravity, the object won't tumble over from even a slight center of gravity wobble. Therefore, it would be easier to balance a nail on its base rather than its tip.
Any object is drawn towards the Earth's centre by gravity, as if its weight were concentrated there. The center of gravity refers to that location. When an object's center of gravity is not supported, it will tip over. The center of gravity is located precisely in the middle of symmetrical objects like a ball or a meter stick. For things that are not symmetrical, like a baseball bat, the center of gravity is closer to the heavier end.
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Complete question is:
Explain why it is more difficult to balance a nail on its tip than on its base.
Note: please don't answer according to pressure concepts, answer according to equilibrium concepts.
what is the force of gravity (in newtons) acting between the earth and a 125-kg person standing on the surface of the earth?
The force of gravity acting between the earth and a 125-kg person standing on the surface of the earth is 1226.7N.
This is calculated using Newton's law of universal gravitation, which states that the gravitational force between two objects is equal to the product of their masses, divided by the square of the distance between them, multiplied by the gravitational constant. In this case, the masses of the Earth and the person are both known, and the distance between them is assumed to be the radius of the Earth.
Therefore, the gravitational force between the Earth and the person can be calculated as:
F = (G x ME x Mperson) / (rEarth)²
Where:
Plugging in the values, the gravitational force between the Earth and the person comes out to be 1226.7N.
.
Therefore, the force of gravity between the earth and a 125-kg person standing on the surface of the earth comes out to be 1226.7N.
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from the well we take out a bucket of water with volume V=5 litres where aproximately the work done is A=450J.
How deep is the surface of the well's water?
For velocity take g=10m/s2
Answer:
9m
Explanation:
Given parameters:
Volume of the water = 5liters;
Since density = 1g/cm³
1L = 1000cm³
5L = 5000cm³
So;
mass = density x volume = 1 x 5000 = 5000g ; 5kg
Work done = 450J
Acceleration due to gravity = 10m/s²
Unknown:
Depth of the well = ?
Solution:
To solve this problem;
Work done = mass x gravity x depth
450 = 5 x 10 x depth
depth = 9m
Two identical resistors have an equivalent resistance of 322Ohms when connected in series. What is the equivalent resistance when that are connected in parallel? A resistor with a resistance of 232Ohms is connected to a power supply of 35 Volts. What is the current through the resistor?
Let's find out the equivalent resistance when the two identical resistors are connected in parallel, given that they have an equivalent resistance of 322 Ω when connected in series.
Step 1: Find the resistance of one resistorThe equivalent resistance of two identical resistors connected in series is twice the resistance of one resistor.R = (equivalent resistance)/2 = 322/2 = 161 Ω
Step 2: Find the equivalent resistance when the resistors are connected in parallelRecall that the equivalent resistance of two resistors connected in parallel is given by the following equation:R_eq = (R1 * R2)/(R1 + R2)Since the resistors are identical, R1 = R2 = R_eq/2So,R_eq = (R_eq/2 * R_eq/2)/(R_eq/2 + R_eq/2) = (R_eq^2/4)/R_eq = R_eq/4
Therefore, R_eq = 4 * R_eq/2 = 4 * 161 = 644 Ω
Therefore, the equivalent resistance when the two identical resistors are connected in parallel is 644 Ω. A resistor with a resistance of 232 Ω is connected to a power supply of 35 V. The current through the resistor can be found using Ohm's law, which states that the current (I) through a conductor between two points is directly proportional to the voltage (V) across the two points and inversely proportional to the resistance (R) between them.So, I = V/R = 35/232 = 0.1517 A
Therefore, the current through the resistor is 0.1517 A.
Resistors : A two-terminal passive electrical component used to limit or regulate the flow of electric current in electrical circuits. The principal reason for resistor is to lessen the ongoing stream and to bring down the voltage in a specific piece of the circuit.
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If two runners cover the same distance in different amounts of time, how do there speeds compare
b) When the wave passes over the glass it refracts. State what will happen to each
of the following properties of the wave when it refracts: (3)
Velocity -
Wavelength -
Frequency -
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Explanation:
An object accelerates 1.5m/s2 when a force of 7.0 newtons is applied to it. What is the mass of the object?
The mass of an object that accelerates 1.5m/s² when a force of 7.0 newtons is applied to it is 4.67kg.
How to calculate mass?The mass of an object can be calculated by dividing the force applied to the object by its acceleration. That is;
Mass = Force ÷ acceleration
According to this question, an object accelerates 1.5m/s² when a force of 7.0 newtons is applied to it. The mass of the object can be calculated as follows:
Mass = 7N ÷ 1.5m/s²
Mass = 4.67kg
Therefore, the mass of an object that accelerates 1.5m/s² when a force of 7.0 newtons is applied to it is 4.67kg.
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It is diffraction that limits the ________ of a telescope of a given objective diameter.A) apertureB) light graspC) resolutionD) magnificationE) interference
It is diffraction that limits the resolution of a telescope of a given objective diameter
Diffraction can be defined as spreading of waves in the presence of obstacles
The resolving power of a telescope can be calculated by the formula,
resolving power = 11.25 seconds of arc/ d,
When we use a telescope the very close objects such as stars or galaxies very small angles on the telescope. To determine the resolution of them on the telescope we need telescopes which have large aperture and therefore we can use resolving power here.
Thus, higher the diameter between objects, the better is the resolution of telescope.
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what must a uranium-235 nucleus absorb before fission will happen
Answer:
The arrangement of particles within uranium-235 is somewhat unstable and the nucleus can disintegrate if it is excited by an outside source. When a U-235 nucleus absorbs an extra neutron, it quickly breaks into two parts. This process is known as fission
Answer:
a nuetron
Explanation:
In a nuclear reactor , a neutron is absorbed into a nucleus (typically uranium-235). ... The fast moving neutrons carry most of the energy from the reaction with them (99%) but before the neutrons can collide with fresh uranium nuclei, they need to be slowed down
Air (n1 = 1.0) surrounds a solid glass cube (n2 = 1.5) with edge length a = 7.0 cm. An incoming ray of light strikes the cube at the midpoint of face #1 (the front face). The refracted ray strikes the midpoint of the edge that is shared by face #2 (the top face) and face #6 (the back face). What angle of incidence θ1 did the ray of light make with face #1? For the limits check, investigate what happens to θ1 if the glass cube’s index of refraction approaches that of air (n2 →n1).
The angle of incidence θ₁ at which the ray of light strikes face #1 of the glass cube is approximately 32.0°.
Find the angle of incidence?To determine this angle, we can use Snell's law, which states that the ratio of the sines of the angles of incidence and refraction is equal to the ratio of the indices of refraction of the two mediums involved.
Mathematically, it can be written as:
n₁ * sin(θ₁) = n₂ * sin(θ₂)
Given that n₁ (refractive index of air) is 1.0, n₂ (refractive index of glass) is 1.5, and the angle of incidence θ₁ is unknown, we can solve for θ₁.
The critical point to note is that the refracted ray strikes the midpoint of the edge shared by face #2 and face #6. This implies that the refracted ray will be perpendicular to that edge. By drawing a diagram and using geometric reasoning, we can determine that θ₁ is approximately 32.0°.
For the limits check, if the refractive index of the glass cube approaches that of air (n₂ → n₁), then θ₁ will approach 0°. This means that the incident ray will be almost parallel to face #1 of the glass cube.
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Use the periodic table to determine which of the following could be an isotope of indium (In). Check all that apply.
Z=49 A=113
N=64 Z=49
N=61 A:113
A=110 N=49
Please Help!!!
Answer:
1 & 2
Explanation:
Answer:
Z=49,A=113
N=64,Z=49
Explanation: