Answer:
C
Explanation:
The concept of superheros
Answer: C.
Explanation:
cause that concept is oooooooooooooooooooooooooooooold
what file can you edit on a linux system to configure shared folders using samba?
/etc/samba/smb.conf is the file you can edit on a linux system to configure shared folders using samba.
What is a Linux system ?A Unix-like operating system (OS) for desktops, servers, mainframes, mobile devices, and embedded devices, Linux is open source and user-developed. One of the most broadly supported operating systems, it is supported on virtually all popular computing platforms, including x86, ARM, and SPARC.Windows OS is a for-profit operating system, whereas Linux is an open-source alternative. In contrast to Windows, which lacks access to the source code, Linux allows users to modify the code as needed.Applications, interfaces, programs, and software are all produced through Linux programming. Desktops, real-time apps, and embedded devices frequently employ Linux code.Programmers can learn about the Linux kernel for free online, enabling them to use, modify, and develop Linux without restriction.Learn more about linux system refer to :
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which of the following is another term for transmission media? a. information highway b. communications channel c. sending device d. data transmitter
The correct answer is b. Communications channel.is another term for transmission media.
Sending messages from one microwave station to another is what is meant by the term "fixed wireless" in the context of microwave transmission (shown in Figure 8-1 on page 296). When compared to a dial-up connection, microwaves may transport data up to 4,500 times quicker. medium for communication. The message is really sent across this linking or connecting channel. This media may be wireless or it may be a physical wire or cable. An order to transfer data, instructions, or information is started by a transmitting device. The transmitting device is linked to a communications channel by a communications device. Data, instructions, or information are transmitted across a communications channel, also known as a transmission medium.
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Question 17/20
The process for maturing an idea towards patentability is called:
Select the correct option(s) and click submit.
Freedom to Operate
MCD
Trademarking
CIM
Submit
The process for maturing an idea towards patentability is called: CIM.
An intellectual property can be defined as an intangible and innovative creation of the mind that is solely dependent on human intellect (intelligence).
Hence, an intellectual property is an intangible creation of the human mind, ideas, thoughts or intelligence.
Globally, there are three (3) main ways to protect an idea or intellectual property and these include:
Trademarks.Copyright.Patents.A patent can be defined as the exclusive (sole) right granted to an inventor by a sovereign authority such as a government, which enables him or her to manufacture, use, or sell an invention (idea) for a specific period of time.
Generally, patents are used on an idea or innovation for products that are manufactured through the application of various technologies.
CIM is an acronym for collaborative invention mining and it can be defined as the process for maturing an idea towards patentability, especially through collaborative interaction..
Thus, the objective of collaborative invention mining (CIM) is to collectively strengthen, mature and develop an idea to become a tangible product that proffers a solution to a problem, thereby, making it patentable.
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hris has received an email that was entirely written using capitalization. He needs to paste this text into another document but also ensure that the capitalization is removed.
What should Chris do?
Write pseudocode for a program which will ask a user to enter two numbers a and b.
it then asks what operation is to be performed: a*b, a/b, a//b or a%b, performs the appropriate calculation and prints out the result.
Pseudocode for the program:
1- Prompt the user to enter two numbers, a and b.
2- Prompt the user to enter the desired operation: a*b, a/b, a//b, or a%b.
3- Read the values of a, b, and the operation from the user.
4- Perform the appropriate calculation based on the chosen operation:
a. If the operation is a*b, multiply a by b.
b. If the operation is a/b, divide a by b.
c. If the operation is a//b, perform integer division of a by b.
d. If the operation is a%b, calculate the remainder when a is divided by b.
5- Print the result of the calculation.
The pseudocode outlines the steps to be followed by the program to perform the desired calculation based on the user's inputs. It prompts the user for the numbers and the operation, reads the inputs, and applies the appropriate calculation method based on the chosen operation. Finally, it prints out the result of the calculation.
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Wrong answers will be reported
True or false
This code print the letter “h”
planet = “Earth”
print(planet[5])
Answer:
False
Explanation:
string indexes start at 0 so planet[5] does not exist
9. can you envision circumstances in which an assembly language permits a label to be the same as an opcode (e.g., mov as a label)? discuss.
No, there are no circumstances in which an assembly language permits a label to be the same as an opcode. It is not possible to use opcode as a label in assembly language.
This is because opcodes are reserved keywords and commands that are already used to perform certain operations. If you try to use an opcode as a label, the assembler will fail to identify the intended instruction and raise an error.
For example, in the following code, `mov` is an opcode:``` mov ax, bx ```In this instruction, `mov` copies the contents of the `bx` register into the `ax` register. If we try to use `mov` as a label like this:``` mov: mov ax, bx ```
This code will fail because `mov` is already reserved as an opcode and cannot be used as a label. Therefore, it is not possible to use an opcode as a label in assembly language.
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List three ideas for checking in with your progress and recognizing completion on your actions.
One idea for checking in with your progress and recognizing completion on your action is to set specific milestones or targets along the way and regularly evaluate your progress towards them.
How can you effectively track your progress and acknowledge completion of your action?To effectively track your progress and acknowledge completion of your action, it is important to establish clear milestones or targets that can serve as checkpoints. Break down your overall goal into smaller, measurable objectives that can be achieved incrementally.
Regularly assess your progress by comparing your actual achievements against these milestones. This will provide you with a tangible way to track your advancement and ensure that you stay on track. Once you reach a milestone or successfully complete a specific objective, take the time to acknowledge and celebrate your achievement.
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Using a microphone to record a sound on your computer is an example of:
It is an example of an "Input device". A further explanation is provided below.
Audio input communication devices enable the user customer to transmit audio information to a technology to examine or evaluate, track record as well as execute controls.The microphones connect towards the computer's microphones connection mostly on rear of PC's. There may have been a microphones port at the very front of various PC's casings.
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Which of the following BEST describes the differences between sequential and event-driven programming?
Answer:
In sequential programming, commands run in the order they are written. In event-driven programming, some commands run in response to user interactions or other events.
Explanation:
Event-driven program : A program designed to run blocks of code or functions in response to specified events.
Sequential programming: The order that commands are executed by a computer, allows us to carry out tasks that have multiple steps. In programming, sequence is a basic algorithm: A set of logical steps carried out in order.
The missing options are;
A) In sequential programming commands run one at a time. In event-driven programming all commands run at the same time.
B) In sequential programming commands run faster than in event-driven programming.
C) In sequential programming each command is run many times in sequence. In event-driven programming all commands are run a single time as an event.
D) In sequential programming commands run in the order they are written. In event-driven programming some commands run in response to user interactions or other events.
This question is about sequential programming and event-driven programming.Option D is correct.
To answer this question, we need to first of all define what the two terminologies in computer programming are;Event-driven programming; This is a programming pattern whereby the program flow is determined by a sequence of events that arise from activities/interaction of the user or the system. Sequential programming: This is a programming pattern whereby the program flow is determined by the sequence in which it was written.Looking at the given options, the only one that fits perfectly into the description I have given above about sequential and event-driven programming is Option D.Read more at; brainly.com/question/17970226
A vector image applies a surface color and texture to a wireframe to make it look more like a real life object
Rendering a vector image applies a surface color and texture to a wireframe to make it look more like a real-life object. The correct option is C.
What is rendering?Rendering, also known as image synthesis, is the act of utilising a computer software to produce a photorealistic or non-photorealistic image from a 2D or 3D model.
The completed image is referred to as a render. Multiple models may be created in a scene file that contains objects using a data structure or language that is carefully defined.
The scene file contains information about the geometry, viewpoint, texture, lighting, and shading of the virtual scene.
The data in the scene file is then processed by a rendering application, and the results are exported as a digital image or raster graphics image file. The concept of "rendering" is similar to that of an artist's interpretation of a scene.
Thus, the correct option is C.
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Your question seems incomplete, the missing options are:
-Capturing
-Pixelating
-Rendering
-Blocking
Find the 66th term of the arithmetic sequence
25,10,−5
Answer:
the answer is 33825
Explanation:
Answer:
-950
Step-by-step explanation:
Arithmetic sequence=a+(n-1)d
a=first number
n=nth term
d=difference
a=25
n=66
d=-15
So let's solve
25+(66-1)(-15)
25+(65)(-15)
25-975
-950
So the 66th terms is -950
ind the total quantity purchased and total sales for each product. also include all of the product's information. sort them so that the best selling products are at the top of the results.
Code in SQL to store all of the product's information and sort them so that the best selling products are at the top of the results.
ORDER BY and the SELECT TOP clause can be used to show the top 5 selling products. Let's examine the SQL query for displaying the top five selling products with the ORDER BY and SELECT TOP clauses using the MSSQL server. A database is being created. Create a database called Brainly for this purpose using the command listed below. Make a table next. Use the following SQL query to create the four-column table sales details.the query used to add rows to the table. The following SQL query is being used to add rows to the sales details table. viewing the inserted data and sorting it according to the quantity of sold units. Run a search to discover the top 5 selling items.
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Describe how the process of sampling, RGB pixels, and binary sequences work together to display a digital color image. Plz I got an assignment due soon.
Answer:
Sampling, RBG pixels and binary sequences work together to display a digital color image by letting the computer know where the RBG pixel is going to be placed and what the opacity for that pixel is. The combination of these components is what gives you a digital color image.
Explanation:
I'm not sure if this is correct because I had trouble with it too but this is what I wrote for the answer.
Literally, sampling means the transformation of analog images to digital equivalents, where:
RGB pixels: These are the digital colors that are displayed on the screen after the analog images are sampled.Binary sequence: This is the process through which the analog images are sampled by binary representations of 0s and 1s.For sampling to be done, the binary sequencing of the analog images must first be done. When the binary sequence process is completed, the end result is transferred to the RGB pixels.
The RGB pixels get the output of binary sequence as its own input. Once the RGB pixels completes its transformation, the digital color images will then be displayed on the screen for the user to see.
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TRUE/FALSE. stemi is also known as q-wave or transmural myocardial infarction
False. STEMI is not synonymous with q-wave or transmural myocardial infarction,while STEMI involves ST-segment elevation, q-wave and transmural infarction can be seen in different types of myocardial infarctions.
How is STEMI related to q-wave or transmural myocardial infarction?ST-elevation myocardial infarction (STEMI) is a specific type of myocardial infarction (heart attack) characterized by ST-segment elevation on an electrocardiogram (ECG). It indicates a complete blockage of a coronary artery, resulting in the death of a portion of the heart muscle. STEMI is not synonymous with q-wave or transmural myocardial infarction.
Q-wave myocardial infarction refers to the presence of abnormal Q-waves on an ECG, indicating previous damage to the heart muscle. It can be seen in different types of myocardial infarctions, including STEMI, non-ST-elevation myocardial infarction (NSTEMI), or subendocardial myocardial infarction.
Transmural myocardial infarction refers to the involvement of the entire thickness (from endocardium to epicardium) of the heart muscle in the infarction. It can occur in both STEMI and non-STEMI cases, depending on the extent of the coronary artery blockage.
So, while STEMI can be associated with q-waves or transmural involvement, it is not synonymous with them.Therefore the given statement is false.
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Which statement describes what this command accomplishes when inside and outside interfaces are correctly identified for NAT? ip nat inside source static tcp 192.168.1.50 80 209.165.201.1 8080 extendable A. It allows host 192.168.1.50 to access external websites using TCP port 8080. B. It allows external clients coming from public IP 209.165.201.1 to connect to a web server at 192.168.1.50. C. It allows external clients to connect to a web server hosted on 192.168.1.50. D. It represents an incorrect NAT configuration because it uses standard TCP ports.
Answer:
The answer is "Option C".
Explanation:
The NAT accurately identifies the environment and internal interfaces, and main customers can link to a 192.168.1.50 Web server. When designed for, proxies examine input and output packages. IP nat "inside source" implies to encourage an outgoing parcel emanating from an "outside" application and behave accordingly.
Which of these is a challenge that developers face who write web applications?
a. not being able to access databases
b. not knowing how much memory the user's computer has
c. not knowing the user’s screen resolution\
d. not being able to use programming languages such as Ruby or Java
Answer:
c. not knowing the user’s screen resolution
Explanation:
taking text on edge2020
Answer:
c. not knowing the user’s screen resolution
Explanation:
Which of the following are true (select all that apply). Group of answer choices Tables should not include titles. Tables should not include abreviations. Tables should be able to be understood in isolation. Tables should be concise. Tables are identified in the text by the page on which they appear.
The following statements are true: Tables should be able to be understood in isolation. Tables should be concise.
Tables should be able to be understood in isolation: This means that tables should provide sufficient information and context within themselves so that readers can comprehend the data and relationships presented without needing to refer to the surrounding text. Tables should include clear headings, column labels, and appropriate units of measurement.
Tables should be concise: Tables should present data in a clear and concise manner, avoiding unnecessary details or excessive information. They should focus on the most relevant and important data to effectively convey the intended message.
When using tables in documents or publications, it is important to ensure that they can be understood independently and that they present information concisely. By following these guidelines, readers can interpret the tables accurately and efficiently.
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#include // printf
int main(int argc, char * argv[])
{
// make a string
const char foo[] = "Great googly moogly!";
// print the string
printf("%s\nfoo: ", foo);
// print the hex representation of each ASCII char in foo
for (int i = 0; i < strlen(foo); ++i) printf("%x", foo[i]);
printf("\n");
// TODO 1: use a cast to make bar point to the *exact same address* as foo
uint64_t * bar;
// TODO 2: print the hex representation of bar[0], bar[1], bar[2]
printf("bar: ??\n");
// TODO 3: print strlen(foo) and sizeof(foo) and sizeof(bar)
printf("baz: ?? =?= ?? =?= ??\n");
return 0;
}
Here's the modified code with the TODO tasks completed:
```cpp
#include <cstdio>
#include <cstdint>
#include <cstring>
int main(int argc, char * argv[]) {
// make a string
const char foo[] = "Great googly moogly!";
// print the string
printf("%s\nfoo: ", foo);
// print the hex representation of each ASCII char in foo
for (int i = 0; i < strlen(foo); ++i)
printf("%x", foo[i]);
printf("\n");
// TODO 1: use a cast to make bar point to the *exact same address* as foo
uint64_t* bar = reinterpret_cast<uint64_t*>(const_cast<char*>(foo));
// TODO 2: print the hex representation of bar[0], bar[1], bar[2]
printf("bar: %lx %lx %lx\n", bar[0], bar[1], bar[2]);
// TODO 3: print strlen(foo) and sizeof(foo) and sizeof(bar)
printf("baz: %zu =?= %zu =?= %zu\n", strlen(foo), sizeof(foo), sizeof(bar));
return 0;
}
```
Explanation:
1. `uint64_t* bar` is a pointer to a 64-bit unsigned integer. Using a cast, we make `bar` point to the same address as `foo` (the address of the first character in `foo`).
2. We print the hex representation of `bar[0]`, `bar[1]`, and `bar[2]`. Since `bar` points to the same address as `foo`, we interpret the memory content at that address as 64-bit unsigned integers.
3. We print `strlen(foo)`, which gives the length of the string `foo`, and `sizeof(foo)`, which gives the size of `foo` including the null terminator. We also print `sizeof(bar)`, which gives the size of a pointer (in this case, the size of `bar`).
Note: The behavior of reinterpret casting and accessing memory in this way can be undefined and may not be portable. This code is provided for illustrative purposes only.
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Below is the Hasse diagram for a partial order relation R on the set {a,b,c,d,e}. e be a Are the following statements true or false? True 4 1. (a, a) ER False A 2. (c, e) ER False 3. (b, c) ER True 4. (a,d) E R True 4 5. (e,a) ER True 6. (a,b) ER
1. (a, a) ER: False. 2. (c, e) ER: False. 3. (b, c) ER: True. 4. (a, d) ER: True. 5. (e, a) ER: True. 6. (a, b) ER: True.
The first statement is false, as it represents a reflexive relation, but (a, a) is not present in the Hasse diagram. The second statement is false, as (c, e) is not connected by an upward arrow. The third, fourth, fifth, and sixth statements are true, as the corresponding pairs are connected by upward arrows in the diagram. In a Hasse diagram, elements are represented as nodes, and a directed arrow from one node to another indicates the order relation. The absence of an arrow between two nodes implies the absence of an order relation between them. For the given statements, we can observe that (a, a) is not present in the diagram, indicating a lack of reflexivity. Similarly, (c, e) is not connected by an upward arrow, indicating a lack of an order relation. On the other hand, (b, c), (a, d), (e, a), and (a, b) are all connected by upward arrows, indicating an order relation between them.
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Which of the following is not a characteristic of a large database?
a) Optstore items in a filing cabinet.
b) Stores items in a computer such as music.
c) stores large amounts of items such as an online store.
d) can be used as a small recipe book.
The contrast ratio of green-45 text on a yellow-15 background is
to 1.
03
O 30
O 45
06
Answer:
30
Explanation:
in ratio
not connected
for (int j- 4; j > 0; j--)
for (int k 1; k < j; k+)
System.out.print (j +);
System.out . println() ;
What is output when the program runs?
a.
4444
b
4321
321
21
4444
333
22
1234
123
12
4321
432
43
Answer:
C is your awnser
Explanation:
Call your function from Example 1 three times with different kinds of arguments: a value, a variable, and an expression. Identify which kind of argument is which.
Answer:
Example 1:
def function(num):
print(num*2)
Example 2:
function(5)
num = 2
function(num)
function(3-1)
Explanation:
Given:
See attachment for complete question
To start with Example (1)
def function(num):
print(num*2)
Note that; the above code segment which doubles the parameter, num could have been any other code
In Example (1), the parameter is num
For example (2):
We can call the function using:
#1. A value:
function(5)
In #1, the argument is 5; a value
#2. A Variable
num = 2
function(num)
In #2, the argument is num; a variable
#3. An Expression
function(3-1)
In #3, the argument is 3-1; an expression
a(n) is a programmer who specializes in building knowledge bases, each consisting of a set of rules that the computer will try to prove or disprove by asking a battery of questions.
A Knowledge Engineer is a programmer who specializes in building knowledge bases for Expert Systems.
These knowledge bases consist of a set of rules that the computer utilizes to solve complex problems by proving or disproving them.
The system generates a series of questions, also known as a battery of questions, to gather information and infer conclusions based on the provided rules.
The Knowledge Engineer's role is vital in creating efficient and accurate Expert Systems, as they are responsible for designing, implementing, and maintaining the rules to ensure the system produces reliable results for users.
Their expertise helps streamline decision-making processes and enhances problem-solving capabilities in various industries.
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What will router R2 do with a packet destined for 192.168.10.129?
a. send the packet out interface FastEthernet0/0
b. send the packet out interface Serial0/0/1
c. drop the packet
d. send the packet out interface Serial0/0/0
Router R2 will send the packet out interface FastEthernet0/0.
In order to determine the correct outgoing interface for a packet, routers use routing tables that contain information about network destinations and associated interfaces. When a packet arrives at router R2 with a destination IP address of 192.168.10.129, R2 will consult its routing table to determine the appropriate next hop for forwarding the packet.
Based on the given options, the most likely choice is to send the packet out interface FastEthernet0/0. However, without additional information about the routing table entries and the network topology, it is not possible to provide an absolute certainty about the routing decision.
Routers typically examine the destination IP address of the packet and apply a longest prefix match to identify the appropriate next hop and outgoing interface. If there is a matching entry in the routing table for the destination IP address 192.168.10.129, specifying FastEthernet0/0 as the outgoing interface, then router R2 will forward the packet accordingly.
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What Tradeoffs Do Buffer Trees Pose As Compared To LSM Trees?
Buffer trees and Log-structured merge-tree are both data structures in computer science, and there are several tradeoffs between them.
As compared to LSM trees, buffer trees pose the following tradeoffs:
Buffer trees store data in a balanced binary tree, whereas LSM trees combine the best of both worlds: a memory component for fast operations and a disk component for durability.
Buffer trees are mainly used in-memory database management systems (DBMS), while LSM trees are used in several storage engines. Buffer trees are more efficient when dealing with small datasets, while LSM trees work best when handling large amounts of data.Buffer trees provide faster operations when the dataset fits into memory.
LSM trees are better suited to larger datasets, even those that do not fit into memory. However, buffer trees are less efficient when dealing with large datasets, and they can cause more I/O because they are not optimized for the disk layout
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which tab do you need to select to change your page orientation from portrait to landscape?
Answer:
That would be the layout tab.
The page layout tab is used to change your page orientation from portrait to landscape.
What is page layout?Page layout is used to create documents with a more usage design, like newsletters, books, or posters. A page layout document is like a canvas that you put in text boxes, images, and other objects to, then gather the objects on the page however you like.There are four basic layout types namely process, product, hybrid, and fixed position.A page layout is defined as a collection of map elements arranged on a virtual page designed for map printing.Use of portrait to landscape orientation, the following steps arepage layout->orientation->landscape.To learn more about page layout refers to:
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Assume that we want to transmit the 4-bit sequence 1010 to user A, and 1100 to user B. Assume that the system uses CDMA with code length of 4. The system assigns the PN code 1100 (PNA) to user A and the PN code 0000 (PNB) to user B. Please note that ZERO mark will be given to correct answers without showing all the steps for all the parts in this question!!!! (No steps, No marks!) a) [1] Are the two PN codes PNA and PNB orthogonal? b) [2] Show the encoded messages to user A and user B. (in (+1,-1)) 1 of 2 c) [1] If we use PNA to decode the encoded message to user A, what is the output? d) [1] Now, combine both encoded messages A and B as they would be transmitted together by the base station. What is the combined encoded signal? e) [1] If we use PNB to decode the combined signal in d), what is the output?
A message is 1010 and user B's message is 1100. Therefore, the encoded message to user A will be the product of the message sequence 1010 and the PN code 1100 in (+1,-1) notation as follows: User A: 1010 x 1100 = +1 -1 +1 -1,
The encoded message to user B will be the product of the message sequence 1100 and the PN code 0000 in (+1,-1) notation as follows: User B: 1100 x 0000 = 0 0 0 0c) Therefore, we have to check the correlation between PNA and PNB.corr (PNA, PNB) = [1 - 2(Nc/2)]corr (1100, 0000) = [1 - 2(4/2)] = [1 - 4] = -3So, the two PN codes PNA and PNB are orthogonal.b)
A message is 1010 and user B's message is 1100. Therefore, the encoded message to user A will be the product of the message sequence 1010 and the PN code 1100 in (+1,-1) notation as follows: User A: 1010 x 1100 = +1 -1 +1 -1The encoded message to user B will be the product of the message sequence 1100 and the PN code 0000 in (+1,-1) notation as follows: User B: 1100 x 0000 = 0 0 0 0c)
If we use PNA to decode the encoded message to user A we simply take the dot product of the encoded message and PNA as follows: User A: (+1 -1 +1 -1) . (1100) = +1 +1 -1 -1 = 0 if we use PNA to decode the encoded message to user A, the output will be 0. d) signal is as follows: (+1 -1 +1 -1) + (0 0 0 0) = +1 -1 +1 -1e) If we use PNB to decode the combined signal in d), we simply take the dot product of the combined signal and PNB as follows: Combined signal: (+1 -1 +1 -1) + (0 0 0 0) . (0000) = 0 Therefore, if we use PNB to decode the combined signal in d), the output will be 0.
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How to solve eror: array must be initialized with a brace-enclosed initializer
A comma-separated set of constant expressions encased in braces () serves as an array's initializer. An equal symbol (=) is placed in front of the initializer. Not every element in an array needs to be initialised.
The array will have random values at each memory place if it is not initialised at the moment of declaration or at any point thereafter. Because zero is the default value for omitted array elements, the compiler will set the first array element to the value you've specified (zero) and all remaining array elements will also be set to zero. 0 for char ZEROARRAY[1024]; The unwritten entries would be filled with zeros by the compiler. As an alternative, you might launch the programme with memset to initialise the array: ZEROARRAY, 0 0 1024;
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