HELP ME PLEASE-

For the equation b=2a+4, a and b are integers.

The following three assumptions can be made about a and b for the equation above.
Ifa>0,thenb>0.
Ifa=0,thenb≠0.
Ifa<0,thenb<□.
What number is missing from the expression b<□ in the third assumption?

First, you have to divide 8 by 5 (you always divide the bottom from the top) which equals 1.6

answer:1.6

hope that helped!

The rate of change of the function that has a graph that passes

through the points (-1, 3) and (-2,-4) is slope and is equal to 7.

We have given two points  (-1, 3) and (-2,-4) .

Rate of change of graph is given by slope

Using slope formula , we get

      m = -4 - 3 / -2 - (-1)

      m = -7 / -2 + 1

      m = -7 / -1

       m = 7

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Answer:

\(\left(a+4\right)\left(a-5\right)\)

Step-by-step explanation:

Break the expression into groups.

=(a^2+4a)+(−5a−20)

Factor out a from a2+4a:     a(a+4)

Factor out −5 from −5a−20:     −5(a+4)

=a(a+4)−5(a+4)

Fixed ratio reinforcement schedules are a type of continuous reinforcement schedules, whereas variable ratio reinforcement schedules are a type of intermittent reinforcement schedules.

This is a difference between fixed ratio reinforcement schedules and variable ratio reinforcement schedules.

However, the variable ratio reinforcement schedules and fixed ratio reinforcement schedules have some differences such as:Fixed ratio reinforcement schedules are based on the number of responses a subject makes while a variable ratio schedule is based on the subject's behavior after an average time.

Variable ratio schedules refer to when the reinforcement occurs after an average number of behaviors is exhibited.

Variable ratio schedules are more effective than fixed ratio schedules because the subject's behavior does not need to be repetitive to be rewarded.

The correct option is option B.

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Answer:

positive charge...............

Hello!

Answer:

\(\huge\boxed{x = 1/2, 9/2}\)

|2x - 5| = 4

Solve for the negative and positive expressions:

2x - 5 = 4

2x = 9

x = 9/2

------------

-(2x - 5) = 4

-2x + 5 = 4

-2x = -1

x = 1/2.

Therefore, the solutions are x = 1/2 and 9/2.

Answer:

(0, - 1). thats the answer

Answer:

x = 25

y = 6

Step-by-step explanation:

In a parallelogram, opposite angles are equal.

2x and 50 are opposite angles,

2x = 50

Divide 2 on both sides,

x = 50 / 2

x = 25

In a parallelogram opposite sides are equal.

y + 5 and 11 are opposite sides,

y + 5 = 11

y = 11 - 5

y = 6

Answer:

x=25

y=6

Step-by-step explanation:

from the diagram,

2x= 50(opposite angles of a parallelogram)

2x= 50

dividing bothsides by 2

2x/2=50/2

x= 25

then,

y+5=11(opposite sides of a parallelogram)

y= 11-5

y= 6

Answer:

115 lbs = 52.16 kilograms

Step-by-step explanation:

115 pounds is a little over 52kg

Answer:

wag po kayo mag bibigay ng points na marami

Kasi ma iiscam po kayo

Answer:

Step-by-step explanation:

We assume Q is between P and R.

According to segment addition postulate we have:

Substitute values and solve for x:

Find PQ:

Find QR:

Answer:

9.3. your ans. nabsbss

The angles in the triangle is as follows:

m∠ACB = 83°

m∠CBA =56°

m∠BAC = 41°

m∠1 = 139°

The sum of angles in a triangle is 180 degrees. Therefore, let's find the external angles and interior angles.

m∠ACB = 180 - 97(sum of angles on a straight line)

m∠ACB = 83 degrees

m∠CBA = 180 - 124(sum of angles on a straight line)

m∠CBA =56 degrees

m∠BAC = 180 - 56 - 83

m∠BAC = 41 degrees

m∠1 = 180 - 41(angles on a straight line)

m∠1 = 139 degrees

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Answer:

2 and 3

Step-by-step explanation:

To simplify this expression, you will need to use the distributive property.

Multiply -2/5 by 15 = - 6, -2/5 by -20d = 8d, and -2/5 by 5c = -2c.

you can switch these around to get -6 + 8d - 2c and -2c + 8d - 6.

Hope this helps :)

Answer:

$10

Step-by-step explanation:

200*0.05=10

Answer:

$10

Step-by-step explanation:

90% = 0.95

200×0.95= 190

200-190=10

Answer:

haha got ya you thought

Step-by-step explanation:

Answer:4

Step-by-step explanation:22-4=18-4=14-4=10-4=6=2

angle has a measure equal to the sum of the the question is ∠DQS.


According to the problem, we need to find an angle whose measure is equal to the sum of the measures of ∠SQR and ∠QRS. We can use the angle addition postulate which states that the measure of an angle formed by two adjacent angles is equal to the sum of their measures.

Let's consider angle ∠DQS. This angle is formed by adjacent angles ∠SQR and ∠QRS. Therefore, according to the angle addition postulate, the measure of angle ∠DQS is equal to the sum of the measures of ∠SQR and ∠QRS.



Thus, we can conclude that the angle ∠DQS has a measure equal to the sum of the measures of ∠SQR and ∠QRS.

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The percentage of the family's text messages did Mrs. Carson is 35 % and Ben is 65 %.

A part of a whole expressed in hundredths a high percentage of students attended. Also the result obtained by multiplying a number by a percent the percentage equals the rate times the base.

Given:

The Carson family sent 800 text messages last month.

Mrs. Carson sent 280 text messages

Ben sent 520 texts messages.

According to given question we have

Total text messages last month= 800

Mrs. Carson=

\(\frac{280}{800}*100\\ \\=35\)

Ben

=

\(\frac{520}{800}*100\\ \\=65\)

Therefore, the percentage of the family's text messages did Mrs. Carson is 35 % and Ben is 65 %.

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Answer:

9.5_<w<9.25

Step-by-step explanation:

Answer:

y = 4/3x

Step-by-step explanation:

Hope that helps you

Answer:

If there are 4 boys and they ate 3 pizzas, and each boy ate the same amount, then each boy ate 3/4 of a pizza. If you want to express this as a fraction, it would be 3/4 of a pizza per boy. If you want to express it as a decimal, it would be 0.75 pizzas per boy. If you want to express it as a percentage, it would be 75% of a pizza per boy.

Considering the equation f(x, y) = y⁴/x, the directional derivative of f in the direction of u at the point p(1,3) is -183/39.

At the point p(1,3), the equation is calculated to determine the directional derivative in the direction of the vector u = 1 3 2i + 5j. Therefore, the directional derivative is given by:`Duf(p) = ∇f(p) · u`

We first need to calculate the gradient of the function:`∇f(x, y) = <∂f/∂x, ∂f/∂y>`Differentiating f(x, y) partially with respect to x and y gives:```
∂f/∂x = -y⁴/x²
∂f/∂y = 4y³/x
```Therefore, the gradient of f is:`∇f(x, y) = <-y⁴/x², 4y³/x>`At the point p(1,3), the gradient of f is:`∇f(1,3) = <-81, 12>`

We need to normalize the vector u to get the unit vector in the direction of u.`||u|| = √(1² + 3² + 2² + 5²) = √39`

Therefore, the unit vector in the direction of u is:`u/||u|| = (1/√39) 3/√39 2i/√39 + 5/√39j`

Therefore, the directional derivative is:`Duf(p) = ∇f(p) · u = <-81, 12> · (1/√39) 3/√39 2i/√39 + 5/√39j`

Evaluating this expression gives:`Duf(p) = (-243 + 60)/39 = -183/39`

Therefore, the directional derivative of f in the direction of u at the point p(1,3) is -183/39.

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Answer:

Hey there!

p(x)=7x+25

7x+25=60

7x=35

x=5

Let me know if this helps :)

Volume of a Cylinder = pi * r^2 * h

V / (pi*r^2) = h

12157 / (pi * 9^2) = h = 47.774

So the total amount of Alex's paycheck this week is $50 and the equation that we use is: paycheck = saving account deposit / (percentage deposited into saving account / 100)

To find the total amount of Alex's paycheck this week, you can use the following equation:

paycheck = saving account deposit / (percentage deposited into saving account / 100)

Plugging in the known values, we get:

paycheck = $35 / (70% / 100)

Simplifying the fraction, we get:

paycheck = $35 / 0.7

Solving for the paycheck, we find that the total amount of Alex's paycheck this week is $50.

So the total amount of Alex's paycheck this week is $50.

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(a) The net force exerted on the test charge q by the two 2.00μC charges is 0 N.

(b) The electric field at the origin due to the two 2.00μC charges is 0 N/C.

(c) The electric potential at the origin due to the two 2.00μC charges is 0 V.

(a) To find the net force exerted on the test charge q, we need to calculate the individual forces between the charges and q using Coulomb's law. Coulomb's law states that the force between two charges is given by the equation:

\(\[F = \dfrac{k \cdot |q_1 \cdot q_2|}{r^2}\]\)

where F is the force, k is the electrostatic constant (k ≈ 9.0 × 10^9 N·m^2/C^2), \(q_1\) and \(q_2\) are the charges, and r is the distance between the charges.

Let's denote the charge at x = 0.8 m as \(q_1\) and the charge at x = -0.8 m as \(q_2\). The distances between the charges and the test charge q are 0.8 m and -0.8 m, respectively.

Calculating the forces:

\(\[F_1 = \dfrac{k \cdot |2.00\mu C \cdot 1.28\times10^{-18} C|}{(0.8m)^2}\]\)

\(\[F_2 = \dfrac{k \cdot |2.00\mu C \cdot 1.28\times10^{-18} C|}{(-0.8m)^2}\]\)

Substituting the values and evaluating the expressions:

\(\[F_1 = \dfrac{(9.0\times10^9 N \cdot m^2/C^2) \cdot (2.00\times10^{-6} C) \cdot (1.28\times10^{-18} C)}{(0.8 m)^2}\]\)

\(\[F_2 = \dfrac{(9.0\times10^9 N \cdot m^2/C^2) \cdot (2.00\times10^{-6} C) \cdot (1.28\times10^{-18} C)}{(-0.8 m)^2}\]\)

Simplifying the expressions:

\(\[F_1 = 2.304 N\]\)

\(\[F_2 = -2.304 N\]\)

The net force, \(F_{net}\), is the vector sum of these forces:

\(\[F_net = F_1 + F_2 = 2.304 N - 2.304 N = 0 N\]\)

Therefore, the net force exerted on the test charge q by the two 2.00μC charges is 0 N.

(b) The electric field at the origin due to the two 2.00μC charges can be calculated by dividing the net force by the magnitude of the test charge q. Using the formula:

\(\[E = \dfrac{F_net}{|q|}\]\)

Substituting the values:

\(\[E = \dfrac{0 N}{1.28\times10^{-18} C}\]\)

Simplifying the expression:

\(\[E = 0 N/C\]\)

Therefore, the electric field at the origin due to the two 2.00μC charges is 0 N/C.

(c) The electric potential at the origin due to the two 2.00μC charges can be found using the formula:

\(\[V = \dfrac{k \cdot (q_1/r_1 + q_2/r_2)}{|q|}\]\)

Substituting the values:

\(\[V = \dfrac{(9.0\times10^9 N \cdot m^2/C^2) \cdot [(2.00\mu C/0.8 m) + (2.00\mu C/-0.8 m)]}{1.28\times10^{-18} C}\]\)

Simplifying the expression:

\(\[V = 0 V\]\)

Therefore, the electric potential at the origin due to the two 2.00μC charges is 0 V.

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Answer: m = -2

Step-by-step explanation:

Slope formula: \(\frac{y2-y1}{x2-x1}\)

Plug in the numbers to the slope formula: \(\frac{2- -10}{-4 - 2} = \frac{2+10}{-4-2}\)

Reduce: \(\frac{12}{-6} = \frac{6}{-3} = -2\)

Answer:

cos2q

Step-by-step explanation:

sin2q x cos2q/sin2q

= cos2q