Heeeelllllllpppp I need this right now

Which type of friction acts on an object that is not moving?
O static fluid
O fluid friction
O sliding friction
O rolling friction

Answer:

10 kg.m/s

Explanation:

momentum: p=mv

Answer:

Explanation:

For every action (or force), there is an equal and opposite action (or force).

Answer:

FALSE

Explanation:

You breath in oxygen and your blood takes it through your body then you breath it out as carbon dioxide

A) To calculate the speed of the plane, we can use the formula for centripetal acceleration:

a = v^2 / r

where a is the centripetal acceleration, v is the speed of the plane, and r is the radius of the circular path.

We are given that the centripetal acceleration is 1g, which is equal to 9.8 m/s^2. We are also given the radius of the circular path as 200 m.

Substituting these values into the formula, we get:

9.8 m/s^2 = v^2 / 200 m

Solving for v, we get:

v = √(9.8 m/s^2 * 200 m) ≈ 44.2 m/s

Therefore, the speed of the plane is approximately 44.2 m/s.

B) To calculate the time required to make the turn, we can use the formula for the period of a uniform circular motion:

T = 2πr / v

where T is the period, r is the radius, and v is the speed of the object in uniform circular motion.

Substituting the given values, we get:

T = 2π(200 m) / (44.2 m/s) ≈ 28.6 s

Therefore, the time required to make the turn is approximately 28.6 seconds.

Answer:

ok

Explanation:

Acceleration is defined as the rate of change of velocity.

Acceleration = (Change in velocity) / time taken

Acceleration = (Final velocity - initial velocity) / time

As the object velocity changes by the same amount in each second, it means the acceleration is constant.

The maximum acceleration of the truck when it carries load of 1000 kg is 0.67 m/s².

Given data :

Force moving the truck = empty truck mass x max. acceleration

= 2,000 kg x 1 m/s²

= 2,000 N

The force will remain the same even with a load of 1,000 kg because that is the maximum force the truck is capable of producing.

Therefore,

2,000 N = mass with load x acceleration

2,000 N = (2,000 kg + 1,000 kg) * acceleration

2,000 N = 3,000 kg × acceleration

=> acceleration = 2,000 N / 3,000 kg

=> acceleration = 0.67 m/s²

Its maximum acceleration will be 0.67 m/s².

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The magnitude of the charge on the balloon and the wool glove is approximately 1.2 x 10^-8 coulombs.

According to Coulomb's law, the force between two charged objects is given by:

F = k * (|q1| * |q2|) / r^2

where F is the force, k is the Coulomb's constant, q1 and q2 are the magnitudes of the charges on the objects, and r is the distance between them.

Force (F) = 1.2 N

Distance (r) = 1 cm

= 0.01 m

The Coulomb's constant, k, is approximately 9 x 10^9 N·m²/C².

Rearranging the equation, we can solve for the magnitude of the charge (|q1| = |q2|):

|q1| * |q2| = (F * r^2) / k

Substituting the given values:

|q1| * |q2| = (1.2 N * (0.01 m)^2) / (9 x 10^9 N·m²/C²)

|q1| * |q2| ≈ 1.33333333333 x 10^-12 C

Since the charges on the balloon and the wool glove are equal but opposite in sign, we can consider them as |q1| = |q2|. Thus:

|q1| ≈ |q2|

≈ 1.33333333333 x 10^-12 C / 2

|q1| ≈ |q2|

≈ 6.66666666667 x 10^-13 C

Therefore, the magnitude of the charge on the balloon and the wool glove is approximately 6.66666666667 x 10^-13 coulombs or, in a more concise form, 1.2 x 10^-8 coulombs.

The magnitude of the charge on the balloon and the wool glove is approximately 1.2 x 10^-8 coulombs.

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Answer:

Explanation:

I assume you meant to type t = √2h/g and you're referring to an object in free fall:  If so, here's my answer:

x = x₀ + v₀t + 1/2at²

for an object in free fall x - x₀ = h    (height the object falls)

v₀ = 0   (if the object starts at rest)

a = g

Therefore,

h = 1/2gt²

t² = 2h/g

t = √2h/g

Answer:

46,080N

Explanation:

Fc=mv^2/r

Fc=30kg*(48m/s)^2/1.5m

Fc=69,120kg*m^2/s^2/1.5m

Fc=46,080kg*m/s or 46,080N

Answer:

5v

Explanation:

W = 10J ;Q = 2C ;V = ?

So,potential between x and y is 5v

Hope it will help you if not so please sorry.

To react completely with 0.500 L of volume of 0.500 M Na2CO3, you would need 0.250 L of 2.00 M HCl.

Write down the balanced chemical equation for the reaction between HCl and Na2CO3:

2 HCl + Na2CO3 → 2 NaCl + H2O + CO2

Determine the stoichiometry of the reaction:

From the balanced equation, we can see that 2 moles of HCl react with 1 mole of Na2CO3.

Calculate the number of moles of Na2CO3:

Given that the volume of Na2CO3 solution is 0.500 L and the concentration is 0.500 M, we can use the formula:

Moles = Concentration × Volume

Moles of Na2CO3 = 0.500 M × 0.500 L = 0.250 moles

Use the stoichiometry to determine the number of moles of HCl needed:

According to the stoichiometry of the balanced equation, 1 mole of Na2CO3 reacts with 2 moles of HCl.

Therefore, to react with 0.250 moles of Na2CO3, we would need 2 × 0.250 = 0.500 moles of HCl.

Convert moles of HCl to volume:

Given that the concentration of HCl is 2.00 M, we can use the formula:

Volume = Moles / Concentration

Volume of HCl = 0.500 moles / 2.00 M = 0.250 L

Convert the volume to liters:

The final answer is 0.250 liters of 2.00 M HCl are needed to react completely with 0.500 L of 0.500 M Na2CO3.

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The can be obtained by using the balanced chemical equation: Na2CO3 + 2 HCl → 2 NaCl + H2O + CO2  Write the balanced chemical equation for the reaction.

Na2CO3 + 2 HCl → 2 NaCl + H2O + CO2

Calculate the number of moles of Na2CO3. Using the formula n = c × V, where n is the number of moles, c is the concentration, and V is the volume, we get:

n = c × V

= 0.500 M × 0.500 L

= 0.250 mol

Calculate the number of moles of HCl required.The balanced chemical equation shows that 2 moles of HCl react with 1 mole of Na2CO3. Hence, the number of moles of HCl required can be calculated as follows

:n(HCl) = 2 × n(Na2CO3)

= 2 × 0.250 mol

= 0.500 mol

Calculate the volume of 2.00 M HCl required.The number of moles of HCl required is 0.500 mol. Using the formula V = n/c, where V is the volume, n is the number of moles, and c is the concentration, we get:

V = n/c

= 0.500 mol ÷ 2.00 M

= 0.250 L

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Answer:

12km per hour

Explanation:

The formula is distance/time.

24km/2 hours = 12km/1 hour

Explanation:

average speed = distance / time

= 24km/ 2 hr

= 12 km/ hr

Hope this will be helpful to you .

Answer:

Steps to determine the specific heat capacity.

1. Place a beaker on a balance and press zero.

2. Now add the oil to the beaker and record the mass of the oil.

3. Read the starting temperature of the oil.

4. Connect a joulemeter to the immersion heater.

5. Time for thirty minutes.

6. Read the number of joules of energy that passed into the immersion heater.

7. Read the final temperature of the oil.

8. Use the following formula to calculate the specific heat capacity.

Explanation:

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The pH-dependent protonation and deprotonation of PNP modulate the molecule's absorption spectra, resulting in a shift in the wavelength of maximum absorption, which can be observed as a change in color.

The effect of pH on p-nitrophenol (PNP) and its absorption spectra is primarily attributed to the protonation and deprotonation of the molecule. PNP is a weak acid with a phenolic hydroxyl group that can donate a proton. In acidic conditions (low pH), the phenolic group of PNP remains protonated. As the pH increases, the phenolic group starts deprotonating, resulting in the formation of the PNP anion.The absorption spectra of PNP are significantly influenced by the protonation state. In its protonated form, PNP exhibits absorption maxima at shorter wavelengths (lower energy), typically around 300-320 nm.

This absorption is due to the conjugation of the aromatic ring and the nitro group, which leads to a bathochromic shift (redshift) in the absorption spectrum.As the pH increases and PNP deprotonates, the absorption spectra shift towards longer wavelengths (higher energy). The deprotonated PNP anion shows absorption maxima around 400-420 nm. This shift occurs because deprotonation disrupts the conjugation, altering the electron delocalization in the molecule and causing a hypsochromic shift (blueshift) in the absorption spectrum.

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Average number of team members who reached their goal per day = 4.2

Number of team members that reached their goals on Monday = 5

Number of team members that reached their goals on Tuesday = 4

Number of team members that reached their goals on Wednesday = 2

Number of team members that reached their goals on Thursday = 7

Number of team members that reached their goals on Friday = 3

Total number of team members that reached their goals = 5 + 4 + 2 + 7 + 3

Total number of team members that reached their goals = 21

Average number of team members who reached their goal per day = 21/5

Average number of team members who reached their goal per day = 4.2

Answer:

The object will likely start moving with a nonzero acceleration.

Answer:

A) but be sure and read the answer.

Explanation:

If the object does not move at all, (that's an important restriction) the net force = 0. That being so, the acceleration must be 0 as well. But there is no law saying that there cannot be a constant motion and that's why the restriction is important.

The net force on particle q₁ is 6.76 x 10⁻³ N.

The net electric force acting on a charged particle due to other charged particles is given by Coulomb's law:

F = k × (|q₁|×|q₂|)/r²

where F is the force, k is Coulomb's constant, q₁ and q₂ are the charges on the particles, and r is the distance between them.

The direction of the force is along the line connecting the two charges, and is attractive for opposite charges and repulsive for like charges. In this case, the net force on q₁ due to q₂ and q₃ is the vector sum of the individual forces. So we need to calculate the force on q₁ due to q₂ and the force on q1 due to q₃ separately, and then add them as vectors.

F1 = k × (|q₁||q₂|)/r₁², where r1 = 0.220 m

F1 = (8.99 x 10⁹ Nm²/C²) x (8.99 uC) x (5.16 uC) / (0.220 m)²

F1 = 1.04 x 10⁻³N (attractive force)

F2 = k × (|q₁||q₃|)/r₂², where r₂ = 0.330 m

F2 = (8.99 x 10⁹ Nm²/C²) x (8.99 uC) x (89.9 uC) / (0.330 m)²

F2 = 7.80 x 10⁻³ N (repulsive force)

The net force on q₁ is the vector sum of F₁ and F₂, taking into account their directions:

F_net = F₁ - F₂ = 1.04 x 10⁻³ N - 7.80 x 10⁻³ N

F_net = -6.76 x 10⁻³ N (attractive force)

So the net force on q₁ is 6.76 x 10⁻³ N, in the direction towards q₂.

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a) The isocost curve equation is G = (20000 - 100C)/500. b) The isocost curve equation is G = (30000 - 100c)/500. c) The isocost curve equation is G = (20000 - 100C)/375. d)  The isocost curve equation is G = (20000 - 120C)/500.

To draw the isocost curve showing the different combinations of gas and coal, we need to use the cost per unit values for coal and gas, as well as the given expenditure (TC) and the changes in expenditure or prices.

Let's denote the quantity of coal as C and the quantity of gas as G. The cost per unit of coal is 100, and the cost per unit of gas is 500.

(a) Initial expenditure (TC) of 20000:

To find the combinations of gas and coal that can be purchased with an initial expenditure of 20000, we can use the following isocost equation

TC = 100C + 500G

We can rearrange the equation to solve for G in terms of C

G = (TC - 100C) / 500

Now we can plot the isocost curve with TC = 20000 using the equation above.

(b) Expenditure (TC) increases by 50%

If the expenditure increases by 50%, the new expenditure (TC_new) becomes 1.5 × TC = 1.5 × 20000 = 30000.

We can use the same isocost equation as before, but with the new expenditure value:

TC_new = 100C + 500G

Rearranging the equation to solve for G

G = (TC_new - 100C) / 500

Now we can plot the isocost curve with TC_new = 30000.

(c) Gas price reduced by 25%:

If the gas price is reduced by 25%, the new cost per unit of gas (Gas_new) becomes 0.75 × 500 = 375.

We can use the original isocost equation, but with the new cost per unit value:

TC = 100C + 375G

Rearranging the equation to solve for G

G = (TC - 100C) / 375

Now we can plot the isocost curve with the reduced gas price.

(d) Coal price rises by 20%

If the coal price rises by 20%, the new cost per unit of coal (Coal_new) becomes 1.2 × 100 = 120.

We can use the original isocost equation, but with the new cost per unit value:

TC = 120C + 500G

Rearranging the equation to solve for G:

G = (TC - 120C) / 500

Now we can plot the isocost curve with the increased coal price.

By plotting these isocost curves on a graph with G on the y-axis and C on the x-axis, we can visualize the different combinations of gas and coal that can be purchased at the given expenditures or price changes.

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Physics is the area of science that compares and describes quantities and movements of matter and energy. The correct option is option 2.

Physics is the study of matter and energy in space and time, as well as their interactions. The interactions of particles and physical objects are governed by energy and the fundamental forces of nature. Science's study of matter, its motion through space and time, as well as related ideas like energy and force, is known as physics.

Therefore, the branch of science known as physics compares and describes the amounts and motions of matter and energy. The right choice is number two.

The complete question is given below:-

What area of science compares and describes quantities and movements of matter and energy?

1. earth science

2. physics

3. chemistry

4. biology

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Answer:

iron (Fe), cobalt

(Co), and nickel (Ni) .

Answer:

You can use the formula: X= Vinitial.t + \(\frac{1}{2}\) g\(t^{2}\)

where: X: distance, which the question wants.

V initial = Zero

t= 1,2,3,10 sec.

g: is the acceleration due to gravity = 9.8 m/\(s^{2}\)

The object distance if the image height equals the object height is 216 mm.

For the height of the object and image to be the same the distance of the object must be 2F.

Given, F =  54 mm

So, 2F = 2× 54 = 108 mm

The distance of the image from the lens is 108 mm so the object and image must be 216 mm.

The object distance is the distance from where the object is placed to the incidence point of the image. The image distance is the distance from the focal point of the image to the center of the lens. Focal length refers to the focal length of the image. It is half of the mirror radius of the curvature.

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The correct statements concerning spectral classes of stars are B, C, D, F.

A) This statement is incorrect because K-stars are cooler stars and are not hot enough to be dominated by ionized helium lines.

B) This statement is correct. When the temperature of a star is around 10,000 K, most of the hydrogen atoms are in the second energy level (n=2), which leads to the formation of strong neutral hydrogen lines.

C) This statement is correct. The original spectral sequence (OBAFGKM) has been expanded to include additional classes such as L, T, and Y, which are used to classify cooler and less massive stars.

D) This statement is correct. The spectral types of stars are primarily based on temperature, which influences the ionization state and the strength of spectral lines in the star's spectrum.

E) This statement is a mnemonic used to remember the spectral sequence but is not a statement concerning spectral classes of stars.

F) This statement is correct. Type O-stars are the hottest and most massive stars, and their surface temperature is high enough to ionize most of the hydrogen atoms, which results in the weakness of hydrogen lines in their spectra.

Hence, B,C,D,F statements are correct which concerning spectral classes of stars .

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Answer:

Option D. 9.47 V

Explanation:

We'll begin by calculating the equivalent resistance of the circuit. This can be obtained as follow:

Resistor 1 (R₁) = 20 Ω

Resistor 2 (R₂) = 30 Ω

Resistor 3 (R₃) = 45 Ω

Equivalent Resistance (R) =?

R = R₁ + R₂ + R₃ (series connections)

R = 20 + 30 + 45

R = 95 Ω

Next, we shall determine the current in the circuit. This can be obtained as follow:

Voltage (V) = 45 V

Equivalent Resistance (R) = 95 Ω

Current (I) =?

V = IR

45 = I × 95

Divide both side by 95

I = 45 / 95

I = 0.4737 A

Finally, we shall determine, the voltage across R₁. This can be obtained as follow:

NOTE: Since the resistors are in series connection, the same current will pass through them.

Current (I) = 0.4737 A

Resistor 1 (R₁) = 20 Ω

Voltage 1 (V₁) =?

V₁ = IR₁

V₁ = 0.4737 × 20

V₁ = 9.47 V

Therefore, the voltage across R₁ is 9.47 V.

Answer:

9.47

Explanation:

Just Took the Test

Explanation:

Because they evolved rapidly, and moulted like other arthropods,trilobites serve as excellent index fossils, enabling geologists to date the age of the rock in which they are found

Answer:

1 kilogram [kg] = 89875517.8780129 gigajoule [GJ]

Explanation:

Hopes it helps.