Hats numbered 1 through 10 are distributed, uniformly at random, to people numbered 1 through 10. All distributions of hats are equally likely to occur. What is the probability that neither person 7 nor person 3 get their hat

Answer:

Step-by-step explanation:

why what happen?

but same though my teacher keeps giving me a 3/5

Answer:

Step-by-step explanation:

it will always be true as long as it is adittion the r is the unknown number just add 15 plus what equals 25

So, the last three digits of m*n is 001.

Let p be the probability that Alfred wins given that he goes first. Then, the probability that Bonnie wins given that she goes first is 1-p. Therefore, the probability that Alfred wins the second game given that Bonnie went first in the first game is 1-p. Similarly, the probability that Alfred wins the third game given that he went first in the second game is p, and so on.

Therefore, the probability that Alfred wins the sixth game given that he went first in the first game is:

p(1-p)(1-p)(p)(p)(p) = p^4 (1-p)^2

Since m and n are relatively prime, the last three digits of m*n are the last three digits of p^4 * (1-p)^2, which is the last three digits of p^4 and the last three digits of (1-p)^2. Since p is the probability of winning given that you go first, it is a number between 0 and 1. Therefore, the last three digits of p^4 and (1-p)^2 are 001, resulting in the last three digits of the final answer being 001.

Therefore, the last three digits of m*n is 001.

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Answer:

8 inches

Step-by-step explanation:

A = (1/2)(B + b)h

100 = (1/2)(12 + 13)h

200 = 25h

h = 200/25

h = 8

Answer: 8 inches

Phil's ball did not reach a higher maximum height than John's ball.

It should be noted that to determine whose tennis ball hit the court first, we need to find when each ball hits the ground. The equation for John's ball is given by:

f(t) = (-16t-2) (t-2)

Setting f(t) = 0, we can solve for t:

0 = (-16t-2) (t-2)

0 = 16t^2 - 30t + 4

0 = 8t^2 - 15t + 2

Using the quadratic formula, we get t as 1.04 seconds

So John's ball hits the ground at around 0.29 seconds and then again at around 1.04 seconds.

For Phil's ball, the equation is given by:

f(t) = (-16t-2) (t-2)

Setting f(t) = 0, we can solve for t:

0 = (-16t-2) (t-2)

0 = 16t^2 - 30t + 4

0 = 8t^2 - 15t + 2

Using the quadratic formula, we get t = 0.29 seconds or t ≈ 1.04 seconds

So Phil's ball hits the ground at around 0.29 seconds and then again at around 1.04 seconds.

Part 2: To determine the maximum height of Phil's ball, we need to find the vertex of the parabolic equation. The vertex of the parabolic equation f(t) = (-16t-2) (t-2) is at:

t = -b / (2a) = 15 / (2*16) ≈ 0.47 seconds

Substituting t = 0.47 seconds into the equation, we get:

f(0.47) ≈ 12.56 feet

So the maximum height of Phil's ball is approximately 12.56 feet.

To determine whether Phil's ball reached a higher maximum height than John's ball, we need to find the maximum height of John's ball. We can do this by completing the square:

f(t) = -16t^2 + 32t + 4

= -16(t^2 - 2t) + 4

= -16(t^2 - 2t + 1) + 20

= -16(t-1)^2 + 20

So the maximum height of John's ball is 20 feet.

Since 12.56 feet is less than 20 feet, Phil's ball did not reach a higher maximum height than John's ball.

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The Michelson-Morley experiment was conducted in 1887 to detect the existence of the luminiferous ether, which was thought to be the medium through which light traveled.

Here is the procedure for the Michelson-Morley experiment:

1. Set up a light source, a half-silvered mirror, two mirrors, and two detectors in a square configuration.

2. Split the light beam using the half-silvered mirror so that one beam goes to one mirror and the other beam goes to the other mirror.

3. Reflect the beams back to the half-silvered mirror and combine them to produce an interference pattern.

4. Rotate the entire apparatus by 90 degrees and repeat the measurement.

5. Compare the interference patterns from the two orientations.

If there is a luminiferous ether, the speed of light should be faster in the direction of the ether flow and slower in the perpendicular direction. This should produce a difference in the interference patterns.

However, the Michelson-Morley experiment showed that there was no difference in the interference patterns, indicating that the luminiferous ether did not exist.

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The conclusion "(x)(A(x) ∨ B(x))" is false since there exist elements (e.g., 1) that satisfy B(x) but not A(x).

To show that the argument is invalid using the model universe method, we need to find a counterexample where the premises are true, but the conclusion is false.

Let's consider the following interpretation:

Domain of discourse: {1, 2}

A(x): x is even

B(x): x is odd

Under this interpretation, the premises "(x)(A(x) ∧ B(x))" and "(∃x)A(x)" are true because all elements in the domain satisfy A(x) ∧ B(x), and there exists at least one element (e.g., 2) that satisfies A(x).

However, the conclusion "(x)(A(x) ∨ B(x))" is false since there exist elements (e.g., 1) that satisfy B(x) but not A(x).

In this counterexample, the premises are true, but the conclusion is false, demonstrating that the argument is invalid using the model universe method.

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Answer:

1. 1/4

2. 2/4

3. 2/4

4. 4/1

Step-by-step explanation:

The area of the associated sector is: 120π

A sector is the portion of the area of a circle surrounded by an arc and two radii.

Analysis:

Area of a sector = ∅/360 x π\(r^{2}\)

∅ = 75°

r = 24 units

Area of sector = 75/360 x π\((24)^{2}\) = 120\(\pi\) square units

In conclusion, the area of the associated sector is 120π square units

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Answer:

A

Step-by-step explanation:

I Just Took the Test.

Answer:

She should buy the coat and pay for shipping

Step-by-step explanation:

Set up a proportion to express the the 80 pounds to yen.

\(\frac{2}{292.82}\) = \(\frac{80}{x}\)

2 x 40 = 80

292.82 x 40 = 11,712.80

230.50 + 25.30 = 255.8

255.80 < 11,712.80

Helping in the name of Jesus.

Answer:

  3/2

Step-by-step explanation:

Finding the slope of a line on a graph is easier if you can identify places where the line crosses grid intersections. We see two of those to be ...

  (4, 1) and (6, 4)

The second of these points is 4-1 = 3 grid squares higher than the first point. It is also 6 -4 = 2 grid squares to the right. The slope is the ratio of these values:

  slope = "rise"/"run" = 3/2

The slope of the graphed line is 3/2.

Answer:

i. 2040  ii.1632

Step-by-step explanation:

I think i did this right..

The probability distribution for the random variables X (number of pages with moderate graphics) and Y (number of pages with high graphics) can be represented as follows:

P(X = x, Y = y) = (30Cx * 10Cy) / (100C4)

In this scenario, we have a hypergeometric distribution because we are sampling without replacement from a finite population (100 pages).

The probability of selecting x pages with moderate graphics (out of 30) and y pages with high graphics (out of 10) from the sample can be calculated using the hypergeometric probability formula. The numerator represents the number of favorable outcomes (combinations of selecting x moderate pages and y high pages) and the denominator represents the total number of possible outcomes (combinations of selecting any 4 pages).

Using the combination formula, 30Cx represents the number of ways to choose x out of 30 moderate pages, and 10Cy represents the number of ways to choose y out of 10 high pages. The denominator, 100C4, represents the total number of ways to choose any 4 pages out of 100.

The probability distribution can be used to calculate the probabilities of different combinations of moderate and high graphics pages occurring in a sample of four pages selected from the small-business website. This information can be helpful in understanding the likelihood of certain graphics content being present in the sample and can aid in decision-making or analysis related to the website's content.

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The mass of salt in the tank at time t.

dS/dt = 10 - S/400

S(0) = 100 grams

The solution is S(t) = 4000 - 3900\(e^{\frac{-t}{400}}\)

A tank holds water V(0) = 4000 liters in which salt S(0) = 100 grams.

So dS/dt = S(in) - S(out)

S(in) = 1 × 10 = 10 gram/liters

S(out) = S/V × 10 = 10S/V gram/liters

V = V(0) + q(in) - q(out)

V = 4000 + 10t - 10t

V = 4000 liters

dS/dt = 10 - 10S/V

dS/dt = 10 - 10S/4000

dS/dt = 10 - S/400

Now given; S(0) = 100.

Here, p(t) = 1/400, q(t) = 10

\(\int p(t)dt = \int\frac{1}{400}dt\)\(\int p(t)dt = \frac{1}{400}t\)

\(\mu=e^{\int p(t)dt}\)

\(\mu=e^{\frac{t}{400}}\)

So, S(t) = \(\frac{\int\mu q(t)dt+C}{\mu}\)

S(t) = \(\frac{\int e^{\frac{t}{400}} \cdot10dt+C}{e^{\frac{t}{400}}}\)

S(t) = \(e^{\frac{-t}{400}} \left({\int e^{\frac{t}{400}} \cdot10dt+C}\right)\)

S(t) = \(e^{\frac{-t}{400}} \left({10\times\frac{e^{\frac{t}{400}}}{1/400} +C}\right)\)

S(t) = \(e^{\frac{-t}{400}} \left({4000\times{e^{\frac{t}{400}} +C}\right)\)

Now solving the bracket

S(t) = 4000 + \(e^{\frac{-t}{400}}\)C.....(1)

At S(0) = 100

100 = 4000 + \(e^{\frac{-0}{400}}\) C

100 = 4000 + \(e^{0}\) C

100 = 4000 + C

Subtract 4000 on both side, we get

C = -3900

Now S(t) = 4000 - 3900\(e^{\frac{-t}{400}}\)

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The complete question is:

A tank holds 4000 liters of water in which 100 grams of salt have been dissolved. Saltwater with a concentration of 1 grams/liter is pumped in at 10 liters/minute and the well mixed saltwater solution is pumped out at the same rate. Write initial the value problem for:

The mass of salt in the tank at time t.

dS/dt =

S(0) =

The solution is S(t) =

To find out how much more total rainfall one city had compared to the other, we can use the equation:Total rainfall for City A - Total rainfall for City B = Difference in rainfallLet x be the total rainfall for City A and y be the total rainfall for City B.

Then the equation can be written as:x - y = Difference in rainfallWe can solve for the difference in rainfall by substituting the given values for x and y and solving for the variable. For example, if City A had 50 inches of rainfall and City B had 30 inches, we can plug those values into the equation:x - y = Difference in rainfall50 - 30 = Difference in rainfall20 = Difference in rainfall

Therefore, City A had 20 more inches of total rainfall than City B. The variables x and y represent the total rainfall for City A and City B, respectively. The variable "Difference in rainfall" represents the difference in total rainfall between the two cities.

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Answer:

2.25

Step-by-step explanation:

Answer:

Step-by-step explanation:

So first I divided 240 by 2 to get the hourly rate, which is 120. Then i multiplied 120 times 36 and got 4,320 quarts in 36 hours. The daily rate is 2,880, I got that by multiplying 120 by 24 because there are 24 hours in a day.

Answer:

<o=180-132=48

so,<s=24(The angle at the circumference is half of its corresponding angle at center)

Answer:

Poem:

Function is binary relation of two sets

have a single output but

not Function is having no function

have multiple output.

Range is a function refer to two closely concepts

but

Domain is a set of possible input values with concepts.

All the function are relation but

not all relation are function.

Relation is a collection of ordered pair but

imaginary is a collection of complex number written in imaginary unit.

Vertical line is parallel to y-axis but

horizontal line is parallel to x-axis.

Therefore, the missing point on the number line, which represents the value of –(–2) or 2, can be labeled as point "E" or any other appropriate designation.

The point representing the value of –(–2) on the number line can be determined by simplifying the expression –(–2), which is equivalent to 2.

Looking at the number line description provided, we can identify that point B represents the value of –3, point 0 represents zero, and point C represents 3. Therefore, we need to locate the point that corresponds to the value of 2.

Based on the pattern of the number line, we can infer that the point representing 2 would be between point 0 and point C. Specifically, it would be one unit to the left of point C.

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Vacation price after discount = Vacation price before reduction x (100% - 20%). a. To compute the price of the alternative vacation in Greece after deducting the 20% incentive.

In this scenario, the trip would have cost £1800 without the rebate. We add this sum to the formula to determine the total cost after the discount:

£1800 x (100% - 20%) = £1800 x 80% = £1440

A 20% discount is applied to the trip's price, which drops to £1440.

b. We deduct £100 from the vacation's cost after the 20% incentive has been applied in order to estimate the final total price after the £100 discount coupon has been used:

£1440 - £100 = £1340

The total cost of the trip is therefore £1340.

c. To calculate how much more each consumer will need to pay for this holiday, we divide the final total holiday price by 2, assuming that each client is paying an equal portion.

£1340/2 = £670

Therefore, each person's additional expense for this vacation will be £670.

The pair spent a total of £1200 on their first trip to Portugal, and they are currently spending an additional £1340 on a second trip to Greece. Therefore, the couple will pay an extra £140 for this holiday, and each person will pay an extra £670.

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Answer:

35

Step-by-step explanation:

4+3= 7

12-7=5

7x5=35

Both the buyer and supplier must work together to mitigate these risks through clear communication, regular monitoring and inspection, and a robust quality control system.

1. Responsibility for quality defects: The responsibility for quality defects lies with the supplier of the product, and the supplier must rectify the issue or provide a refund or exchange if necessary.

2. Responsibility for warranty: The responsibility for warranty depends on the terms of the contract between the buyer and supplier, but generally the supplier is responsible for honoring the warranty and providing repairs or replacements as needed.

3. Responsibility for recalls: The responsibility for recalls falls on both the buyer and supplier, but the supplier should take prompt action to identify and address any potential safety issues and work with the buyer to implement an effective recall strategy.

4. Outsourcing: Outsourcing can increase the risk of quality defects, warranty issues, and recalls due to the potential for miscommunication and lack of oversight.

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Answer:

false its 2 hours a 55 minutes I think hope this helps :)

Step-by-step explanation:

Answer:

noooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo

Step-by-step explanation:

Answer:

A C D

Step-by-step explanation:

first convert into 'like decimals' i.e. with equal number of decimal places.

such as question A:

                                 7.340 > 7.304       = TRUE

          QUESTION B;

                                    1.628 > 1.630   = FALSE

I HOPE IT HEPLED YOU

Answer:

621 times 29 is equal to 18009

Step-by-step explanation:

\( \\ 621 \times 29\)

\( \\ = 18009\)

By solving an inequality, we will see that option a is cheaper for more than 60 miles.

We know that option A charges $25 per day plus $0.15 per mile, so the cost for x miles is given by the linear equation:

A(x) = $25 + $0.15*x

While for option B the fixed cost is $10 and the cost per mile is $0.40, so the cost equation is:

B(x) = $10 + $0.40*x

The cost of option a will be smaller when:

$25 + $0.15*x < $10 + $0.40*x

$25 - $10 < $0.40*x - $0.15*x

$15 < $0.25*x

$15/$0.25 < x

60 < x

So for 60 miles the cost is the same, for x > 60 miles the cost of option a will be smaller (because the slope is smaller).

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Answer:

D:y=5x-8

steps- by- step explanation