In order to accommodate the increased wave speed, guitars have linear strings with variable linear mass densities, a linear density string and a higher density string under the same tension.
There is a formula for speed velocity. is determined by multiplying the mass of the strength by the square of the attention attention force. As a result, this demonstrates that the investment's velocity accelerated toward the square of the linear identity.
What then is becoming increasingly identity? No. They never fell short to cut. In order to answer the issue, the lesser density string will have a higher velocity if it is under the same strain as the advertising industry.
Lower your pace for the higher density strength and the wave speed.
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Please please help me :)
Answer:
Explanation:
2) From F=ma
Force =15×40=600N or kgm/s2
3)From the same equation making acceleration the subject of the formula will give
a=f÷m
=24÷4=6m/s2
4)m=f÷a
=45÷15=3kg
can someone please help me A wave’s velocity is 120 m/sec with a frequency of 6 Hz. What is its wavelength?
Answer:
by using formula,
wavelength= velocity/frequency
= 120/6
= 20 meter
Ans: 20 meter
Answer:
wavelength= velocity
= 120/6= 20 meter
Explanation:
The Earth's gravitational field strength, g = 9.81 N kg-1, is also sometimes given as the acceleration due to gravity, g = 9.81 m s-2. Show that these units are equivalent.
The units N kg-1 and ms^2 are equivalent.
What are dimensions?In physics, we often use the idea of dimension to establish the fact that a physical relationship is correct. It could also be used to obtain correct unit of a given physical quantity.
Now we have to obtain the dimensions of N kg-1 from the fact that;
N = Kgms^2 this implies that;
Kgms^2(kg-1) = ms^2
Hence, the units N kg-1 and ms^2 are equivalent.
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Answer:
Explanation:
dimensions of N kg-1 from the fact that;
N = Kgms^2 this implies that;
Kgms^2(kg-1) = ms^2
Hence, the units N kg-1 and ms^2 are equivalent.
what does this quote mean?
Answer:
Basically, it means that you never know until you try.
Explanation:
Scientists are studying a moving glacier. To monitor the flow of the glacier, they place a series of five markers, A, B, C, D, and E, in a straight line across the path of flow. A and E are closest to the edges of the glacier. C is in the center of the glacier. B and D are between A and C and C and E respectively. How would the scientists predict the motion of each of the markers relative to the edges of the valley down which the glacier flows? What pattern would they predict in the markers over time?
Answer: c a d b
Explanation:
Glaciologists use Glen–Nye Flow Law, to predict the movements of glaciers thus, The pattern they predict in the markers over time would be C D A B.
How would the scientists predict the moving glacier of the markers relative to the edges of the valley down which the glacier flows?In some parts of the world, glaciers are an important natural resource because the nature and behaviour of glaciers are an impact the hydrologic, geologic, and ecological systems of their immediate location.
Due to this, Glaciologists monitor and try to predict the movement and morphology of glaciers.
One of the techniques used by "Glaciologists" in the monitoring and prediction of glaciers in the use of markers.
The movement of markers is measured relative to the edges of the valley down which the glacier flows.
Thus, The movement of the markers are then predicted using the Glen–Nye Flow Law.
The pattern they predict in the markers over time would be C D A B.
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As you walk to science class, you start out at a speed of 2 m/s, for a time of 120 seconds (you’re really excited to get to class). Then you see your friend and slow down to a speed of 0.5m/s for 30 seconds. You stop at your locker for 40 seconds (a speed of 0 m/s). You realize that you are about to be late so you hurry to class at a speed of 1 m/s and get to class just as the bell rings (4 minutes after your trip started). How far did you travel total?
The total travelled distance is • Speed, time and distance is one of the most common and important topics in the Mathematics or Quant section.
What is Speed?Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. In other words, velocity is a vector, whereas speed is a scalar value.
For instance, 50 km/hr west denotes the velocity of a car whereas 50 km/hr (31 mph) denotes the speed at which it is moving down a route.
The average speed of an object is determined by dividing the distance traveled by the amount of time it takes the object to reach the distance.
Therefore, The total travelled distance is • Speed, time and distance is one of the most common and important topics in the Mathematics or Quant section.
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020 (part 1 of 3) 10.0 points
A tennis ball is dropped from 1.39 m above the
ground. It rebounds to a height of 0.968 m.
With what velocity does it hit the ground?
The acceleration of gravity is 9.8 m/s². (Let
down be negative.)
Answer in units of m/s.
021 (part 2 of 3) 10.0 points
With what velocity does it leave the ground?
Answer in units of m/s.
022 (part 3 of 3) 10.0 points
If the tennis ball were in contact with the
ground for 0.0125 s, find the acceleration
given to the tennis ball by the ground.
Answer in units of m/s².
Answer:
The tennis ball hit the ground at a speed of approximately \(5.22\; {\rm m\cdot s^{-1}}\).
The tennis ball bounced away from the ground at a speed of approximately \(4.36\; {\rm m\cdot s^{-1}}\).
The average acceleration of the tennis ball during the contact was approximately \(766\; {\rm m\cdot s^{-2}}\).
Explanation:
If an object of mass \(m\) is travelling at a speed of \(v\), the kinetic energy \(\text{KE}\) of that object will be \(\text{KE} = (1/2)\, m\, v^{2}\). At a height of \(h\) above the ground, the gravitational potential energy \(\text{GPE}\) of that object will be \(\text{GPE} = m\, g\, h\).
If the drag on the tennis ball is negligible, energy will be conserved:
\(\begin{aligned}& \text{GPE at initial height} \\ &= \text{KE right before hitting the ground}\end{aligned}\).
In particular, if the tennis ball was released from a height of \(h\), its speed \(v\) right before landing will ensure that \(m\, g\, h = (1/2)\, m\, v^{2}\). Rearrange to obtain \(v = \sqrt{2\, g\, h}\). Since the tennis ball was released from a height of \(h = 1.39\; {\rm m}\), the speed of the ball right before landing will be:
\(\begin{aligned}v &= \sqrt{2\, g\, h} \\ &= \sqrt{2\, (9.8\; {\rm m\cdot s^{-2}}) \, (1.39\; {\rm m})} \\ &\approx 5.22\; {\rm m\cdot s^{-1}}\end{aligned}\).
The same reasoning applies when the tennis ball bounces off the ground:
\(\begin{aligned}& \text{KE right after leaving the ground} \\ &= \text{GPE at max height after bouncing upward}\end{aligned}\).
If the tennis ball bounced off the ground at a speed of \(v\), the height \(h\) that this tennis ball will reach should also satisfy \(m\, g\, h = (1/2)\, m\, v^{2}\). Rearrange to obtain \(v = \sqrt{2\, g\, h}\). Since the tennis ball reached a height of \(0.968\; {\rm m}\), it would have bounced off the ground at a speed of:
\(\begin{aligned}v &= \sqrt{2\, g\, h} \\ &= \sqrt{2\, (9.8\; {\rm m\cdot s^{-2}}) \, (0.968\; {\rm m})} \\ &\approx 4.36\; {\rm m\cdot s^{-1}}\end{aligned}\).
Acceleration measures the rate of change in velocity. The velocity of this tennis ball was downward right before landing, at approximately \((-5.22\; {\rm m\cdot s^{-1}})\) (the negative sign indicates the direction of velocity.) The velocity of this ball points upward after bouncing back, at approximately \(4.36\; {\rm m\cdot s^{-1}}\).
Hence, the change in the velocity of this tennis ball will be:
\(\begin{aligned} \Delta v &= v_{1} - v_{0} \\ &\approx4.356\; {\rm m\cdot s^{-1}} - (-5.220\; {\rm m \cdot s^{-1}}) \\ &\approx 9.576\; {\rm m\cdot s^{-2}}\end{aligned}\).
Since this change in velocity required a duration of \(\Delta t = 0.0125\; {\rm s}\), the average acceleration of this tennis ball would have been:
\(\begin{aligned} a &= \frac{\Delta v}{\Delta t} \\ &\approx \frac{9.576\; {\rm m\cdot s^{-1}}}{0.0125\; {\rm s}} \\ &\approx 766\; {\rm m\cdot s^{-2}} \end{aligned}\).
Can anyone help me with this question please
I’ll mark as brainliest
No links.
the transverse Wave which is Answer:2
Answer:
1
Explanation:
amplitude is the maximum distance from the rest of the particles. amplitude is thus measured from the rest position to the peak of a crest or of a trough.
as seen below, graph 1 has an amplitude of 1 while both graph 2 and 3 has an amplitude of 2.
what animal that does not eat meat
Answer:
An animal that doesn’t eat meat is called a herbivore. An few examples would be cows, rabbits, horses, and goats.
:)
Question
3.2
Calculate the value of critical angle for light passing from glass to air (given that refractive index of
glass - 1.5)
Answer:
42°
Explanation:
From the question given above, the following data were obtained:
Refractive index (n) = 1.5
Critical angle (C) =?
The refractive index and the critical angle are related according to the following reaction:
n = 1 / Sine C
Thus, with the above formula, we can obtain the critical angle as follow:
Refractive index (n) = 1.5
Critical angle (C) =?
n = 1 / Sine C
1.5 = 1 / Sine C
Cross multiply
1.5 × Sine C = 1
Divide both side by 1.5
Sine C = 1 / 1.5
Sine C = 0.6667
Take the inverse of sine
C = Sine¯¹ (0.6667)
C = 41.8 ≈ 42°
Thus, the critical angle is approximately
42°.
major league baseball games last an average of 190.885 minutes (standard devaition =
Major League Baseball games last an average of 190.885 minutes with a standard deviation that was not specified in the question. The standard deviation is a measure of how much the data deviates from the mean or average.
It can be used to determine the spread of the data and how closely the individual values cluster around the mean. Without the standard deviation, it is difficult to make any further conclusions about the duration of MLB games.
It seems that your question is incomplete, and I cannot provide a proper answer without the necessary information.
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A graduate student is trying to follow the weather on Jupiter for her PhD thesis. To see the big weather patterns in the upper atmosphere of the planet, she needs to have excellent resolution. What type of telescope would be best for her to use? a. a refractor, with as small an aperture as possible b. a radio telescope c. a large reflector in an observatory located at sea level d. a large reflector located in orbit above the Earth's atmosphere e. you can't fool me, all these telescopes have the same resolution
Answer: large reflector located in orbit above the Earth's atmosphere
Explanation:
Since the student wants to see the big weather patterns in the upper atmosphere of the planet, and she will therefore need to have excellent resolution, the type of telescope that is ideal for her to use is a large reflector located in orbit above the Earth's atmosphere.
It should be noted that the refractor or a radio telescope isn't ideal in this situation as they will not capture the bug weather pattern and doesn't have an excellent resolution like the large reflector.
Which family in the periodic table has elements that are silvery and lustrous?
Alkali metals
Halogens
Noble gases
Nonmetals
Answer:
the answer is Transitional metals
Explanation:
they are hard and have a high density
The answer is;
(A) Akali Metals
Hope this helped.
The distance from one crest to the next is the ________.
Answer:
Wavelength.
Explanation:
1 period, or wavelength, is measured from one crest to another or from one trough to another.
What is physics and discuss its branches and their various uses in daily life
Physics is a natural science that studies the behavior and properties of matter and energy. Its various branches have a wide range of applications in our daily lives, from designing structures and machines to developing new technologies and understanding the universe.
Physics is a natural science that studies the behavior and properties of matter and energy, their interactions, and the laws that govern them. It is a fundamental science that aims to understand the universe from the smallest subatomic particles to the largest structures and phenomena.
The branches of physics include classical mechanics, thermodynamics, electromagnetism, optics, quantum mechanics, relativity, astrophysics, and nuclear physics. These branches have various applications in our daily lives. For example:
1. Classical mechanics is used in designing structures and machines, and in predicting the motion of objects such as cars, airplanes, and projectiles.
2. Thermodynamics is important for understanding the behavior of heat and energy transfer in engines, refrigerators, and other devices.
3. Electromagnetism is essential for the functioning of electronic devices, such as computers, televisions, and mobile phones.
4. Optics is used in designing lenses, cameras, and telescopes, as well as in medical imaging technologies such as X-rays and MRI scans.
5. Quantum mechanics has applications in the development of new materials, electronics, and computer technologies.
6. Relativity is important for understanding the behavior of objects traveling at high speeds or in strong gravitational fields, such as GPS satellites.
7. Astrophysics helps us understand the properties and behavior of celestial objects, such as stars, galaxies, and black holes.
8. Nuclear physics is important for energy production and the study of the fundamental building blocks of matter.
In conclusion, physics is a fundamental science that has a wide range of applications in our daily lives, from designing structures and machines to developing new technologies and understanding the universe. Its various branches help us understand the behavior of matter and energy and the laws that govern them, and they have a profound impact on many aspects of our lives.
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A vehicle is traveling at a velocity of 30 meters per second. Exactly 5 seconds later, its velocity has changed by a factor of 0.6. What was the vehicles average acceleration over that time period?
Answer:
-2.4 m/s²
Explanation:
avg accel = Δv/Δt
v-i = 30 m/s
v-f = (30 m/s)(0.60) = 18 m/s
Δt = 5.0 sec
avg accel = (18 m/s - 30 m/s) / 5.0 s = (- 12 m/s) / 5 s = -2.4 m/s²
negative sign means it's slowing down
Two heavy blocks are connected by a uniform rope that has a mass of 4.00 kg. An upward force of 200 N is applied to ↑F=200 N3 the upper block. 6.00 kg a. Draw three diagrams-one for each block and one for the rope-- showing 4.00 kg the forces acting on each. For each force identify what is exerting the force b. What is the acceleration of the entire system? c. What is the tension at the top of the rope? d. What is the tension at the middle of the rope? 5.00 kg
When two heavy blocks were connected by a uniform rope that has a mass of 4.00 kg, acceleration of the system was found to be 2.7 m/s²; the tension at the top of heavy rope was 136.5 N; the tension exerted at the midpoint of the rope was112.5N.
Tension is defined as the act of stretching or straining or the condition of a substance being stretched or strained.
a) Acceleration of the system can be calculated as
a=Fn/m
={200-(16x9.8)}/16
=2.7m/s²
so therefore the acceleration of the system was calculated and found to be=2.7m/s²
b) the tension of the heavy rope at the top can be calculated as
200-50-T1=5(2.7)
T1=136.5N
the tension at the top of heavy rope was 136.5 N
c)the tension at the middle point of the rope was
T2-9g = 9(a)
=9(g+a)
=9(9.8+2.7)
=112.5 N
so here the tension exerted at the midpoint of the rope was 112.5N.
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what is the frequency of a photon that has the same momentum as a neutron moving with a speed of 1300 m/s ?
To find the frequency of a photon that has the same momentum as a neutron moving with a speed of 1300 m/s, we can use the equation:
p_neutron = p_photon
where p is momentum, and set the momentum of the neutron equal to the momentum of the photon:
m_neutron * v_neutron = h * f_photon / c
where m_neutron is the mass of the neutron, v_neutron is its velocity, h is Planck's constant, f_photon is the frequency of the photon, and c is the speed of light.
Substituting the given values, we get:
(1.67493 x 10^-27 kg) * (1300 m/s) = h * f_photon / (3 x 10^8 m/s)
Solving for f_photon, we get:
f_photon = (m_neutron * v_neutron * c) / h
Plugging in the values for c, h, m_neutron, and v_neutron, we get:
f_photon = (1.67493 x 10^-27 kg * 1300 m/s * 3 x 10^8 m/s) / 6.62607 x 10^-34 J s
Therefore, the frequency of the photon is approximately 2.527 x 10^20 Hz.
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An object initially traveling at 20.0 m/s south decelerates uniformly at 6.00 m/s2 and is displaced 25.0 m. What is the final velocity of the object? (magnitude and direction)
Answer:
50.37 m/s and 40ms object
Help!
If alcohol or drugs are used in small quantities, and with little or no damaging consequences, it's not usually
considered drug abuse.
A. True
B. False
If alcohol or drugs are used in small quantities, and with little or no damaging consequences, it's not usually considered drug abuse.
The correct option is A.
What is driver license?A person who has completed his 18 years of age, wants to drive any vehicle whether car or bike, he must have a license called the driver's license.
Drug abuse is the aggressiveness developed in person after drinking alcohol.
In countries, when a person takes in alcohol with little or no damaging consequences, he is not to be considered as drug abuse.
The given statement is True.
Thus, the correct option is A.
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What separates the two sections of the solar system?.
Answer:
These two groups of planets are separated by the asteroid belt, a disk of small rocky bodies orbiting the sun between Mars and Jupiter.
Explanation:
Your welcome!
Select all situations in which the acceleration of the ball is - 9.8 m/s/s
a. A boy throws a ball up into the air.
b. As the ball travels upward.
c. When the ball is at the top of its path.
d. When the ball is falling down.
Answer:
All the options (a, b, c, and d) are correct situations for negative value of acceleration due to gravity.
Explanation:
Acceleration due to gravity is always acted towards the center of the earth. It's magnitude is \(9.8\rm{m/s^{2}}\).
As per the sign convention, downward direction is considered as negative.
Now, consider the cases:
1. When an object or ball is thrown upward: While moving upwards, gravity or gravitational acceleration opposes the motion of object. The object speed or displacement will be positive while gravity will be negative.
2. When an object is at the top or highest point of their path: When the object is at the top of its path, the gravity still acts downwards and the velocity becomes zero. So, gravity will be negative at this position.
3. When object is falling downward: While falling downwards, the acceleration and velocity will be negative as they both are directed downwards.
From the above points, the value of gravity will always be negative.
Therefore, in all the given options (a, b, c, and d), the acceleration will be \(-9.8\rm{m/s^{2}}\).
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During a tug-of-war, team A pulls on team B by applying a force of 1700 N to the rope between them. The rope remains parallel to the ground. How much work does team A do if they pull team B toward them a distance of 3.9 m
Team A does 6630 Joules of work during the tug-of-war. Work done is represented by the formula W= F * d Where W = work done F = force applied d = distance covered by the object Team A pulls on team B by applying a force of 1700 N to.
the rope between them. And the rope remains parallel to the ground .The force applied by team A = 1700 N Distance covered by team B = 3.9 m Using the formula, the work done by Team A is W = F * d W = 1700 N * 3.9 m W = 6630 Joules When two objects are involved in movement,
there is a transfer of energy between them. When one object moves in the direction of the force applied, work is done. Work done is defined as the product of the force applied and the distance covered by the object in the direction of the force.Work is a scalar quantity, and its SI unit is Joules (J). In the scenario described in the question, team A applies a force of 1700 N to move team B a distance of 3.9 m. By calculating the work done using the formula W = F * d, we can determine that team A does 6630 Joules of work during the tug-of-war.
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According to Newton’s second law, the mass of an object is 120kg and it is accelerating at a rate of 5m/s2 . The object’s force would be
Answer:
F = 600 N
Explanation:
The second law is F = m * a
The mass (m) is in kg = 120
The acceleration in in m/s^2 = 5
The force is in Newtons.
m and a do not require any conversions. They are in the correct units.
F = 120 * 5
F = 600 N
If
you weigh 140 pounds, what is your weight in kilograms
Electrical equipment should always be properly connected to an electrically neutral source. What is this source called
Answer:
Earth or ground
Explanation:
Earth is the reference point in an electrical circuit from which voltages are measured, it connects the house's electrical system physically to the ground. It functions in a house to ensures that exposed electrical parts do not have a dangerous voltage relative to the Earth, which could cause an electric shock if a grounded person touched them, and also to make sure that the failures of internal insulation triggers protective mechanisms such as fuses or circuit breakers in the circuit to remove power from the device.
Name:
date:
12. maria hiked up kennesaw mountain heading east. she hiked for a total of 2 hours, and
covered a total distance of 6 miles. what was her average velocity?
The Maria travels at an average speed of 3 miles per hour. the difference between the shift of position or displacement (x) and the time periods (t) during which the displacement takes place.
What is the purpose of average velocity?
An element's displacement over time is its average velocity. When calculating an object's actual speed, we divide the distance traveled by the time passed. We are aware that velocity is a vector quantity, and we can calculate the average velocity by dividing the displacement by the time.
How can I calculate the average velocity?
Actual velocity is determined by dividing the overall distance you went by the total duration, while average velocity is determined by dividing the total distance you traveled by the whole time.
Briefing:
the total distance covered by the maria = 6 miles
The time by Maria = 2 hours
The average velocity of Maria = 6/2 = 3 mph
Therefore, the average velocity of Maria is 3 mph.
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An FM radio station broadcasts radio waves with a frequency of 96,000,000 Hz. What is the speed of these radio waves if they have a wavelength of 3.1 m?
What type of wave is this ?
an astronaut on an eva has wandered dangerously far away from the shuttle. she has also exhausted all the fuel in her jet pack. how can she get back to the shuttle?
The conservation of the momentum allows to find the result of how the astronaut can return to the spacecraft is:
Throwing the thruster away from the ship.
The momentum is defined as the product of the mass and the velocity of the body, for isolated systems the momentum is conserved. If we define the system as consisting of the astronaut and the evo propellant, this system is isolated and the internal forces become zero. Let's find the moment in two moments.
Initial instant. Astronaut and thrust together.
p₀ = 0
Final moment. The astronaut now the thruster in the opposite direction of the ship.
\(m_f\) = m v + M v '
where m is propellant mass and M the astronaut mass.
As the moment is preserved.
0 = m v + M v ’
v ’= \(- \frac{m}{M} \ v\)
We can see that the astronaut's speed is in the opposite direction to the propeller, that is, in the direction of the ship.
The magnitude of the velocity is given by the relationship between the masses.
In conclusion, using the conservation of the momentun we can find the result of how the astronaut can return to the ship is:
Throwing the thruster away from the ship.
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