given the presence of dust throughout the disk of the milky way galaxy, what is the best technique for learning about more distant regions of our galaxy's disk?

Answer:

heat energy

Explanation:

Friction causes the molecules on rubbing surfaces to move faster, so they have more energy. This gives them a higher temperature, and they feel warmer.

A degausser device can be used to erase the contents of a hard drive using a magnetic field.

A degausser is a tool that generates a strong magnetic field that can erase the data stored on magnetic media such as hard drives, tapes, and floppy disks. This is done by exposing the media to a changing magnetic field that effectively randomizes the data, making it unrecoverable. Degaussers are often used by organizations that need to dispose of sensitive data securely, such as government agencies or financial institutions.

It is important to note that not all hard drives can be effectively erased using a degausser, and other methods such as physical destruction or software-based wiping may be necessary in some cases.

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Answer:

A foundation.

Explanation:

Balance can be considered a foundation for other physical skills because it is essential for performing many movements and activities effectively and efficiently. Having good balance helps individuals maintain stability and control over their body, which is important for actions like walking, running, jumping, and even standing still. Without good balance, individuals may struggle with coordination, experience falls or injuries, or have difficulty performing tasks that require precise movements. Therefore, developing and maintaining good balance can serve as a foundation for other physical skills and overall physical health.

The angular speed of the wheels is approximately 235.62 radians per minute, and the wheels make approximately 192.09 revolutions per minute.

To find the angular speed of the wheels in radians per minute, we first need to convert the linear speed from miles per hour to inches per minute. Since there are 5280 feet in a mile and 12 inches in a foot, we have:

15 miles/hour × 5280 feet/mile × 12 inches/foot × 1/60 hour/minute = 15840 inches/minute.

The linear speed of the wheels is the same as the distance traveled by a point on the circumference of the wheel in a given time. The formula for linear speed is given by:

v = rω,

where v is the linear speed, r is the radius of the wheel, and ω is the angular speed.

Given that the wheel has a diameter of 30 inches, the radius is half of the diameter, which is 15 inches. Plugging in the values, we can solve for ω:

15840 inches/minute = 15 inches × ω,

ω ≈ 1056 radians/minute.

Therefore, the angular speed of the wheels is approximately 1056 radians per minute.

To find the number of revolutions per minute, we divide the angular speed by 2π, as there are 2π radians in one revolution:

1056 radians/minute ÷ (2π radians/revolution) ≈ 168 revolutions/minute.

Rounding to two decimal places, the wheels make approximately 168 revolutions per minute.

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Answer:

neurons

Explanation:

i hope this works

(a) It will take 2 seconds for the ball to pass the man moving in the downward direction.

(b) The maximum height attained by the ball is 20 meters.

(c) The ball will take 2+2\sqrt{2} seconds to hit the ground.

(a) How long will it take the ball to pass the man moving in the downward direction?

We can use the equation of motion:

v = u + at,

where:

v = final velocity (0 m/s since the ball will momentarily stop when passing the man),

u = initial velocity (20 m/s upwards),

a = acceleration (due to gravity, -10 m/s²),

t = time.

Substituting the known values we get:

0 = 20 - 10t.

Simplifying the equation:

10t = 20,

t = 20/10,

t = 2 seconds.

Therefore, it will take 2 seconds for the ball to pass the man moving in the downward direction.

(b) What is the maximum height attained by the ball?

To find the maximum height attained by the ball, we can use the following equation:

v² = u² + 2as,

where:

v = final velocity (0 m/s at the maximum height),

u = initial velocity (20 m/s upwards),

a = acceleration (acceleration due to gravity, -10 m/s²),

s = displacement.

The maximum height will be achieved when v = 0. Rearranging the equation, we get:

0 = (20)² + 2(-10)s.

Simplifying the equation:

400 = -20s.

Dividing both sides by -20:

s = -400/-20,

s = 20 meters.

Therefore, the maximum height attained by the ball is 20 meters.

(c) How long will it take the ball to hit the ground?

To find the time it takes for the ball to hit the ground, we can use the following equation:

s = ut + (1/2)at²,

where:

s = displacement (60 meters downwards),

u = initial velocity (20 m/s upwards),

a = acceleration (acceleration due to gravity, -10 m/s²),

t = time.

Rearranging the equation, we get:

-60 = 20t + (1/2)(-10)t².

Simplifying the equation:

-60 = 20t - 5t².

Rearranging to form a quadratic equation:

5t² - 20t - 60 = 0.

Dividing both sides by 5:

t² - 4t - 12 = 0.

Solving the equation using the quadratic formula, we get:

t = (4 ± sqrt(16 + 4 x 12)) / 2

t = (4 ± 4sqrt(2)) / 2

t = 2 ± 2sqrt(2)

Since time cannot be in negative terms, we ignore the negative value of t.  Therefore, the time it takes for the ball to hit the ground is:

t = 2 + 2sqrt(2) seconds

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(a) How long will it take the ball to pass the man moving in the downwards direction ?

Using Equation of Motion:-

\( \large\bigstar \: \: \: { \underline { \overline{ \boxed{ \frak{v = u + at}}}}}\)

where:-

Plugging in Values:-

\( \large \sf \longrightarrow \: v = u + at\)

\( \large \sf \longrightarrow \: 0 = 20 + ( - 10)t \: \)

\( \large \sf \longrightarrow \: 0 - 20=( - 10)t \: \)

\( \large \sf \longrightarrow \: - 10t = - 20\: \)

\( \large \sf \longrightarrow \: t = \frac{ - 20}{ - 10} \\ \)

\( \large \sf \longrightarrow \: t = 2 \: secs \\ \)

Therefore, it will take 2 seconds for the ball to pass the man moving in the downward direction.

________________________________________

\( \\\)

(b) What is the maximum height attained by the ball ?

→ To solve the given problem, we can use the equations of motion

Using Equation of Motion:-

\( \large\bigstar \: \: \: { \underline { \overline{ \boxed{ \frak{ {v}^{2} = {u}^{2} + 2as}}}}}\)

where:

Plugging in Values:-

\( \large \sf \longrightarrow \: {v}^{2} = {u}^{2} + 2as\)

\( \large \sf \longrightarrow \: {(0)}^{2} = {(20)}^{2} + 2( - 10)s\)

\( \large \sf \longrightarrow \: 0 = 400 + 2( - 10)s\)

\( \large \sf \longrightarrow \: 400 + (- 20)s = 0\)

\( \large \sf \longrightarrow \: 400 - 20 \: s = 0\)

\( \large \sf \longrightarrow \: - 20 \: s = - 400\)

\( \large \sf \longrightarrow \: \: s = \frac{ - 400}{ - 20} \)

\( \large \sf \longrightarrow \: \: s = 20 \: metres\)

Therefore, the maximum height attained by the ball is 20 meters.

________________________________________

\( \\\)

(c) How long will it take the ball to hit the ground ?

Using Equation of Motion:-

\( \large\bigstar \: \: \: { \underline { \overline{ \boxed{ \frak{ s= ut + \frac{1}{2}a{t}^{2}}}}}}\)

where:

Plugging in Values:-

\( \large \sf \longrightarrow \: s= ut + \frac{1}{2}a{t}^{2}\)

\( \large \sf \longrightarrow \: -60= 20t + \frac{1}{2}(-10){t}^{2}\)

\( \large \sf \longrightarrow \: -60= 20t + \frac{-10}{2}\times{t}^{2}\)

\( \large \sf \longrightarrow \: -60= 20t + (-5)\times{t}^{2}\)

\( \large \sf \longrightarrow \: -60= 20t-5\times{t}^{2}\)

\( \large \sf \longrightarrow \: 20t-5{t}^{2}+60\)

\( \large \sf \longrightarrow \: {t}^{2}-4t-12\)

\( \large \sf \longrightarrow \: t=\frac{-b \pm\sqrt{{b}^{2}-4ac}}{2a} \)

\( \large \sf \longrightarrow \: t=\frac{-(-4) \pm\sqrt{{(-4)}^{2}-4(1)(-12)}}{2(1)} \)

\( \large \sf \longrightarrow \: t=\frac{4 \pm\sqrt{16-4(-12)}}{2} \)

\( \large \sf \longrightarrow \: t=\frac{4 \pm\sqrt{16-(-48)}}{2} \)

\( \large \sf \longrightarrow \: t=\frac{4 \pm\sqrt{16+48}}{2} \)

\( \large \sf \longrightarrow \: t=\frac{4 \pm\sqrt{64}}{2} \)

\( \large \sf \longrightarrow \: t=\frac{4 \pm 8}{2} \)

\( \large \sf \longrightarrow \: t=\frac{4 + 8}{2} \qquad or \qquad t=\frac{4 - 8}{2} \)

\( \large \sf \longrightarrow \: t=\frac{12}{2} \qquad or \qquad t=\frac{-4}{2} \)

\( \large \sf \longrightarrow \: t=6 \qquad or \qquad t= -2 \)

Since time cannot be negative , Therefore, it will take 6 secs to hit the ground!!

________________________________________

\( \\\)

✅

An objects potential energy is due to its state of rest.

Define potential energy

Potential energy is a form of accumulated energy that is dependent on the relationship between different system components. When a spring is compressed or expanded, its potential energy increases. The potential energy of a steel ball is greater when it is raised above the earth than when it is brought to Earth.

Energy that is conserved or kept in a substance or object is known as potential energy. The position, arrangement, or condition of the item or substance determines the amount of stored energy. It can be pictured as energy with the "potential" to perform labor. Mechanical energy, electrical energy, chemical energy, radiant energy, nuclear energy, and heat energy are the six categories of potential energy.

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According to the question ,On writing 0.51 in scientific notation , the value of a is 5.1 and value of k is -1 .

When a number outside 1 and 10 is scaled by a power of 10, the result is represented in scientific notation.

Simply put, scientific notation is a means to write numbers. Due to its lower length, increased efficiency, and straightforward magnitude indication, it is particularly helpful when expressing extremely big or extremely small quantities. A decimal portion multiplied by an integer number of ten can be used to represent any real number.

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The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)

The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.

To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).

The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).

In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).

Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.

If co > co_critical, the system is considered overdamped (Option E).

If co = co_critical, the system is considered critically damped (Option D).

If co < co_critical, the system is considered underdamped (Option C).

Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.

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The total mechanical energy of the bicyclist is 1400 J, obtained by adding her potential energy of 720 J and kinetic energy of 680 J. The correct answer is option B.

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Answer:

Hey there!

Elements only contain one type of atom, and a compound contains atoms of different elements chemically combined together. For example, gold is an element, because it only is made of gold atoms, where water or H2O is a compound.

Let me know if this helps :)

Answer:

A compound contains atoms of different elements chemically combined together in a fixed ratio. An element is a pure chemical substance made of same type of atom. Elements contain only one type of atom.

Example:

Explanation:

The average velocity should stay about the same as you decrease the displacement between the two photogates.

Distance is the length of any path connecting any two places. When measured along the shortest path between any two points, displacement is the direct distance between them.

The vector difference between an object's initial and finishing coordinates is known as displacement. The distance the thing has travelled may be substantially different from that. The pace at which displacement alters over time is known as velocity. It is also a vector.

False—distance is a vector quantity. It calculates the length and direction of a hypothetical motion in a straight line from the starting point to the destination of the point.

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Now

\(\\ \sf\longmapsto 20cm\)

\(\\ \sf\longmapsto 2\times 10^{-1}\)

\(\\ \sf\longmapsto 0.1m\)

Answer:

179.02N/m

Explanation:

spring constant = force/extension

(12.8)/(0.0715)= 179.02N/m

Answer:

c. Protons and electrons

Explanation:

electrons carry out negative charge

protons carry out positive charges

The graph that correctly gives the variation of the electric field as a function of r is the third graph.

The electric field inside a conducting shell is zero. This is because the charges on the shell distribute themselves so that the electric field is zero everywhere inside the shell.

The electric field outside a conducting shell is radial and directed away from the center of the shell. The magnitude of the electric field is inversely proportional to the square of the distance from the center of the shell.

Therefore, the graph of the electric field as a function of r is a horizontal line at zero for r < a, a vertical line at r = a, and a decreasing curve for r > a.

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Answer:

C A B D E

Explanation:

The newest rocks are always on top, and the oldest rocks are on the bottom.

C. 305 million

A. 200 million

B. 68 million

D. 3 million

E. 800 thousand

Answer:

The earth's axis of rotation is tilted 66.5 degrees with respect to its orbital plane around the sun and its axis of rotation is inclined 23.5 degrees from the perpendicular, with respect to this plane. The tilt of the earth affects the angle between the sun beam and the normal over a surface.

Earth orbits at an angle, so half the year, the Northern Hemisphere is tilted toward the Sun — this is summer in the Northern Hemisphere, and winter in the Southern Hemisphere. The other half of the year, the Northern Hemisphere is tilted away from the Sun, creating winter in the north and summer in the south.

When the Earth's axis is tilted toward the sun for the Northern Hemisphere, the people in the Northern Hemisphere experience summer, while at the same time, the Southern Hemisphere is tilted away from the sun and the people there experience winter.

The Northern Hemisphere receives the maximum intensity of the sun's rays, while the angle of sunlight decreases in the Southern Hemisphere.

When the sun's rays strike Earth's surface near the equator, the incoming solar radiation is more direct (nearly perpendicular or closer to a 90˚ angle). Therefore, the solar radiation is concentrated over a smaller surface area, causing warmer temperatures.

Answer:

xfxy naa

Explanation:

dhdhuciffbfjfufu

You don't need to calculate anything.

You said "0.05 Ampere".

"Ampere" means "coulomb per second".

Newton's equation for universal gravitation and Coulomb's law of electrical force are quite similar. The forms of the two equations are fairly comparable. The inverse square relationship between force and separation distance may be seen in both equations.

While Coulomb's law only applies to stationary charges, Gauss's law might be thought of as being more fundamental because it applies to both moving and stationary charges.

Therefore, Because of this, one of the four Maxwell equations is Gauss's law.

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The values of all sub-parts have been obtained.

(1).  The maximum factored load the beam can withstand is 45.2 kN/m.

(2).  The moment resistance of the cross-section is 291735.65 Nm.

(3).  The factored moment demand is 27939.6 Nm

1) To draw the governing shear and bending moment diagram for the factored load, we need to first calculate the maximum factored load that the beam can withstand.

The maximum factored load on the beam is given by:

Dead Load = 20 kN/m + 15 kN

                   = 35 kN/m.

Live Load = 2 kN/m + 1 kN

                = 3 kN/m.

Total Factored Load = 1.2 x Dead Load + 1.6 x Live Load

                                  = 1.2 x 35 kN/m + 1.6 x 3 kN/m

                                  = 45.2 kN/m.

The maximum factored load the beam can withstand is 45.2 kN/m.

The shear force and bending moment diagrams for the given factored load can be obtained as shown below:

Shear Force Diagram:

Bending Moment Diagram:

2) To calculate the moment resistance of the cross-section, we can use the formula:

MR = σst A'(d - a/2) + 0.85f'c A''(d - a/2)

Where, σst = yield stress of tension steel [σst = fy / γst],

γst = safety factor for tension steel [γst = 1.15A']

A' = area of tension steel, [A'' = b(d - a)].

Where,

b = width of the beam [b = 600 mm],  

d = total height of the beam [d= 1000 mm],

a = effective depth of tension steel [a = 920 mm]

f'c = compressive strength of concrete [f'c = 25 MPa],

MR = σst A'(d - a/2) + 0.85f'c A''(d - a/2)

MR = (400 / 1.15) x 10 x (1000 - 920/2) + 0.85 x 25 x 590 x (1000 - 920/2)

MR = 291735.65 Nm

The moment resistance of the cross-section is 291735.65 Nm.

3) To check if this cross-section is adequately designed to resist the factored bending moment (LRFD), we need to calculate the factored moment demand and compare it with the moment resistance.

The factored moment demand is given by:

MF = ϕ x Mu

Where,ϕ = resistance factor = 0.9, Mu = factored bending moment

Mu = 1.2 x Dead Load x L2 / 8 + 1.6 x Live Load x L2 / 8 + 1.2 x (Dead Load + Live Load) x L2 / 2

   = 1.2 x 35 x 152 / 8 + 1.6 x 3 x 152 / 8 + 1.2 x 38 x 152 / 2

   = 31044 Nm

MF = ϕ x Mu

     = 0.9 x 31044

    = 27939.6 Nm

The factored moment demand is 27939.6 Nm, which is less than the moment resistance of the cross-section, i.e., 291735.65 Nm.

Therefore, this cross-section is adequately designed to resist the factored bending moment.

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The angular velocity of the skater during the finale is 2.18 rad/s.

The conservation of angular momentum is a principle in physics that states that the total angular momentum of a system remains constant if no external torques act on the system. Mathematically, this can be expressed as L1 = L2, where L1 is the initial angular momentum of a system, L2 is the final angular momentum of the system, and the total torque acting on the system is zero. This principle is analogous to the conservation of linear momentum, which states that the total linear momentum of a system remains constant if no external forces act on the system. The conservation of angular momentum is an important principle in many areas of physics, including mechanics, electromagnetism, and quantum mechanics.

We can use the conservation of angular momentum to solve this problem. The initial angular momentum of the skater and the hand-arms is given by:

L1 = I1 * w1

where I1 is the moment of inertia of the skater's body, and w1 is the initial angular velocity. Since the hand-arms are extended, their moment of inertia can be neglected.

When the skater pulls their arms inward, the moment of inertia of the system decreases. The final moment of inertia is given by:

I2 = I1 + 2md^2

where m is the mass of each hand-arm, d is the distance of the hand-arm from the axis of rotation, and we multiply by 2 since there are two hand-arms.

The final angular velocity w2 can be found by equating the initial and final angular momentum:

L1 = I1 * w1 = I2 * w2

Substituting the expressions for I1, I2, and simplifying, we get:

w2 = w1 * I1 / (I1 + 2m(d2^2 - d1^2))

where d1 is the initial distance of the hand-arm from the axis of rotation (0.60 m), and d2 is the final distance of the hand-arm from the axis of rotation (0.20 m).

Substituting the given values, we get:

w2 = 0.50 m/s * 1.719 kgm^2 / (1.719 kgm^2 + 2 * 5.0 kg * (0.20 m^2 - 0.60 m^2))

w2 = 2.18 rad/s

Therefore, The skater's angular velocity during the grand finale is 2.18 rad/s.

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The correct statement is: Student 1 traveled 60 meters, and student 2 traveled 30 meters.

Calculate the speed of each student:

Student 1: 40 meters / 60 seconds = 0.67 meters per second

Student 2: 20 meters / 60 seconds = 0.33 meters per second

Use the speed to calculate the distance each student would travel in 90 seconds:

Student 1: 0.67 meters per second × 90 seconds = 60 meters

Student 2: 0.33 meters per second × 90 seconds = 30 meters

Therefore, the correct statement is: Student 1 traveled 60 meters, and student 2 traveled 30 meters.

What is speed?

Speed is a measure of how fast an object is moving. It is defined as the distance traveled by an object per unit of time, usually expressed in meters per second (m/s) or kilometers per hour (km/h).

The formula for calculating speed is:

Speed = Distance / Time

Where distance is the distance traveled by the object, and time is the duration of the travel.

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Based on the relationship between a star's mass and its luminosity, as described in Chapter 5 of your textbook, we can determine the relative luminosity and lifespan of stars with different masses compared to the Sun.

For a star that is 10 times more massive than the Sun:

According to the mass-luminosity relationship, more massive stars have higher luminosities. Since the star is 10 times more massive than the Sun, we can assume it will have a greater luminosity. However, without specific data on the exact relationship between mass and luminosity, we cannot determine the precise relative luminosity value. As for its lifespan, more massive stars tend to have shorter lifespans than lower-mass stars. Therefore, we can expect the star that is 10 times more massive than the Sun to have a shorter lifespan compared to the Sun's 10 billion years.

For a star that is 1/3 as massive as the Sun:

Similarly, using the mass-luminosity relationship, less massive stars have lower luminosities. If the star is 1/3 as massive as the Sun, we can expect it to have a lower luminosity compared to the Sun. Again, without specific data, we cannot determine the exact relative luminosity value. Regarding its lifespan, less massive stars typically have longer lifespans. Therefore, we can expect the star that is 1/3 as massive as the Sun to have a longer lifespan compared to the Sun's 10 billion years.

In summary, a star that is 10 times more massive than the Sun would likely have a greater luminosity and a shorter lifespan, while a star that is 1/3 as massive as the Sun would likely have a lower luminosity and a longer lifespan.

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Answer:

15009

Explanation:

PE = mgh

PE = 61.2(9.81)(10 * 2.50)

PE = 15009.3

Dielectrics are substances that prevent the flow of current.

They are most frequently used for energy storage in capacitors and to build radio frequency transmission lines because of their capacity to store charges. To enhance the performance of semiconductors, high-permittivity dielectric materials are frequently utilised.

They are most frequently used for energy storage in capacitors and to build radio frequency transmission lines because of their capacity to store charges.

To enhance the performance of semiconductors, high-permittivity dielectric materials are frequently utilised. a material that is dielectric, insulating, or an extremely bad conductor of electrical current. A substance that is an electrical insulator is known as a dielectric material.

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Using the opposite pole of the magnet would reverse the direction of the electric current generated through electromagnetic induction.

Whilst you opposite the path of the contemporary flowing within the cord, the north and south poles also are reversed. When you reverse the contemporary once more, the north and south poles reverse again. In fact, on every occasion the modern is reversed, the north and south poles will trade places.

A magnet and a coil of wire can be used to provide an electric-powered modern-day. A voltage is produced while a magnet moves into a coil of cord. This procedure is known as electromagnetic induction. The direction of the caused voltage is reversed while the magnet is moved out of the coil once more.

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Answer:

100% C

Explanation:

Nitrile Gloves  gloves are safe for working with electricity.

A synthetic rubber made from acrylonitrile and butadiene, nitrile rubber is also referred to as nitrile butadiene rubber, NBR, Buna-N, and acrylonitrile butadiene rubber. Trade names like Perbunan, Nipol, Krynac, and Europrene are also used. Being resistant to chemicals, fuel, and oil makes this rubber special.

These gloves are therefore the best option for anyone who must handle potentially dangerous and caustic chemicals. Being incredibly puncture-resistant and removing the possibility of latex allergic reactions, they are also ideal for the majority of medical settings.

The robust barrier of protection provided by nitrile gloves can help keep the wearer safe from chemicals, acids, and oils. Latex-free: Nitrile gloves are excellent for anyone with sensitive skin or a latex allergy because they are latex-free, unlike natural rubber gloves.

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The index of refraction of this liquid will be 1.28. It is found as the ratio of the sin of the angle of incidence and the angle of reflection.

The refractive index of a substance is a dimensionless quantity that specifies how quickly light passes through it in optics.

The given data in the problem is;

Angle of incidence (i)= 65°

Angle of refraction(r) = 42°

The formula for the index of refraction is;

\(\rm n = \frac{sin \ i }{sin \ r} \\\\ \rm n = \frac{sin 65 ^0}{sin 42^0} \\\\ n=1.28\)

Hence, the index of refraction of this liquid will be 1.28.

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Answer:

the average speed in annual work out is 46.5