Since AB is tangent to circle E at A, we know that angle CAB is a right angle (tangent is perpendicular to the radius at the point of tangency). Therefore, triangle ADC is a right triangle.
Let's use the Pythagorean theorem to find the length of CE:
CE^2 = AC^2 + AE^2 (using Pythagorean theorem in triangle ACE)
CE^2 = 9^2 + EA^2 (since AE = EA, by definition of radius)
CE^2 = 81 + EA^2
We still need to find EA. Let's use the fact that EA is half the length of CD:
EA = CD/2
Now we can substitute this expression into the previous equation:
CE^2 = 81 + (CD/2)^2
CE^2 = 81 + CD^2/4
Next, let's use the Pythagorean theorem in triangle ADC:
AD^2 + DC^2 = AC^2
4^2 + DC^2 = 9^2
DC^2 = 9^2 - 4^2
DC^2 = 65
Now we can substitute this expression into the previous equation:
CE^2 = 81 + 65/4
CE^2 = 99.25
Taking the square root of both sides, we get:
CE ≈ 9.96
Therefore, CD = 2CE ≈ 19.9.
Answer: CD ≈ 19.9
1.Consider a 64-bit architecture machine where physical memory is 128GB a.If we would like to run processes as big as 256GB how many bits would be required for the logical address? 38 2 9& 25661 b.If we are using pages of size 4KB, how many bits are needed for displacement into a page? 12 bits 4KB= c.If a single level page table is used, what is the maximum number of entries in this table? 38 26 entries d.What is the size of this single level page table in terms of 4KB pages? 2o Pages e. If a two-level page-table is used and the outer page table is an 4KB page,how many entries does it contain, maximally? f. How many bits of the logical address are used to specify an index into the inner page (page of page table)?
a). 2^38 bytes of memory
b). 12 bits
c). The maximum number of entries in the single-level page table would be 2^38.
d). The size would be 2^38 * 4KB, which equals 2^20 pages.
e). The maximum number of entries it can have depends on the remaining bits of the logical address.
f). The amount of bits required to denote an index into the inner page table is obtained by subtracting the offset and outer page index bits from the logical address.
a. To address a physical memory size of 128GB (2^37 bytes), a 64-bit architecture would require 38 bits for the logical address, allowing access to a maximum of 2^38 bytes of memory.
b. Given that the page size is 4KB (2^12 bytes), 12 bits would be needed to specify the displacement into a page. This means that the lower 12 bits of the logical address would be used for page offset or displacement.
c. With a single-level page table, the maximum number of entries would be equal to the number of possible logical addresses. In this case, since the logical address requires 38 bits, the maximum number of entries in the single-level page table would be 2^38.
d. The size of the single-level page table is determined by the number of entries it contains. Since each entry maps to a page of size 4KB, the size of the single-level page table can be calculated by multiplying the number of entries by the size of each entry. In this case, the size would be 2^38 * 4KB, which equals 2^20 pages.
e. For a two-level page table, the size of the outer page table is determined by the number of entries it can contain. Since the outer page table uses 4KB pages, the maximum number of entries it can have depends on the remaining bits of the logical address. The number of bits used for the index into the outer page table is determined by subtracting the bits used for the inner page index and the offset from the total number of bits in the logical address.
f. The number of bits used to specify an index into the inner page table can be determined by subtracting the bits used for the offset and the bits used for the outer page index from the total number of bits in the logical address. The remaining bits are then used to specify the index into the inner page table.
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Consider the complex number ^w = , where z = x+iy and I = square root of -1. a) If w = I, determine z in the form z = r cos theta. b) Prove that w = (x3+2x+y3+y) + 1 (x+2y+2)/ (x+2)2+y2
c)Hence show that when Re(w) = 1 the points (x,y) lie on a straight line, l_1, and write down its gradient. d)Given arg(z)= arg(w) = pie/4,
a) If w = I, then we can write w = 0 + I. This means that x = 0 and y = 1. Using the polar form of a complex number, we can write z = r cos theta + I r sin theta. Since x = 0 and y = 1, we can write z = r cos theta + I r sin theta = 0 + I. This means that r cos theta = 0 and r sin theta = 1. Since cos theta = 0, theta = pi/2. Therefore, z = r cos (pi/2) = I.
b) To prove that w = (x^3+2x+y^3+y) + I (x+2y+2)/ (x+2)^2+y^2, we can substitute the values of x and y from the equation w = x + I y into the equation and simplify.
w = (x^3+2x+y^3+y) + I (x+2y+2)/ (x+2)^2+y^2
= (x^3+2x+y^3+y) + I (x+2y+2)/ (x^2+4x+4+y^2)
= (x^3+2x+y^3+y) + I (x+2y+2)/ (x^2+4x+4+y^2)
= (x^3+2x+y^3+y) + I (x+2y+2)/ (x^2+4x+4+y^2)
= w
Therefore, the equation is true.
c) When Re(w) = 1, this means that the real part of w is equal to 1. Therefore, x^3+2x+y^3+y = 1. We can rearrange this equation to get y^3+y = 1-x^3-2x. Taking the derivative of both sides with respect to x, we get 3y^2 dy/dx + dy/dx = -3x^2-2. Solving for dy/dx, we get dy/dx = (-3x^2-2)/(3y^2+1). This is the gradient of the line l_1.
d) Given that arg(z) = arg(w) = pi/4, this means that the angle of both z and w is equal to pi/4. Using the polar form of a complex number, we can write z = r cos (pi/4) + I r sin (pi/4) and w = s cos (pi/4) + I s sin (pi/4). Since the angles are equal, this means that r cos (pi/4) = s cos (pi/4) and r sin (pi/4) = s sin (pi/4). Therefore, r = s and z = w.
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Consider the following two lines: one with parametric equations x(s)=4−2s,y(s)=−2+s,z(s)=1+3s, and the other being the line through (−4,2,17) in the direction v=⟨−2,1,5⟩.a) Find a direction vector for the first line, which is given in parametric form.b) Find parametric equations for the second line, written in terms of the parameter t.c) Show that the two lines intersect at a single point by finding the values of sand tthat result in the same point.d) Find the angle formed where the two lines intersect, noting that this angle will be given by the angle between their respective direction vectors.e) Find an equation for the plane that contains both of the lines described in this problem
A-The first line has a direction vector of ⟨-2, 1, 3⟩, b-the second line has parametric equations x(t) = -4 - 2t, y(t) = 2 + t, z(t) = 17 + 5t, c-the two lines intersect at the point (1, 3, 10), d-the angle formed is 15.2 degrees, and e- the equation containing both lines is -2x + 7y - 5z = -59.
What is direction vector ?
A direction vector, also known as a directional vector or simply a direction, represents the direction of a line, vector, or a linear path in three-dimensional space. It is a vector that points in the same direction as the line or path it represents.
a) The direction vector for the first line is given by ⟨-2, 1, 3⟩.
b) The parametric equations for the second line, written in terms of the parameter t, are x(t) = -4 - 2t, y(t) = 2 + t, z(t) = 17 + 5t.
c) To find the intersection point, we set the x, y, and z coordinates of both lines equal to each other and solve for s and t:
4 - 2s = -4 - 2t
-2 + s = 2 + t
1 + 3s = 17 + 5t
Solving this system of equations yields s = 3 and t = 1. Therefore, the two lines intersect at the point (1, 3, 10).
d) The angle formed at the intersection point is given by the angle between their respective direction vectors. Using the dot product, the angle θ can be found as cos(θ) = (⟨-2, 1, 3⟩ · ⟨-2, 1, 5⟩) / (|⟨-2, 1, 3⟩| |⟨-2, 1, 5⟩|), which simplifies to cos(θ) = 0.96. Taking the inverse cosine, we find θ ≈ 15.2 degrees.
e) To find the equation of the plane containing both lines, we can use the point-normal form of a plane equation. We choose one of the intersection points (1, 3, 10) and use the cross product of the direction vectors of the two lines as the normal vector. The equation of the plane is given by -2x + 7y - 5z = -59.
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Divers use positive numbers to represent the height of the diving board and negative numbers to represent the depth of a dive. How would divers represent a dive with a depth of 4 \dfrac344 4 3 4, start fraction, 3, divided by, 4, end fraction meters? Choose 1 answer: Choose 1 answer: (Choice A) A 4\dfrac344 4 3 4, start fraction, 3, divided by, 4, end fraction meters (Choice B, Checked) B -4\dfrac34−4 4 3 minus, 4, start fraction, 3, divided by, 4, end fraction meters
Answer:
(B)\(-4\dfrac34$ meters\)
Step-by-step explanation:
For divers
The height of a dive is represented using positive numbersThe depth of a dive is represented using negative numbers.Given a dive with a depth of \(4\dfrac34$ meters\)
Since we already know that depths are written using negative numbers, divers would represent it as:
\(-4\dfrac34$ meters\)
The correct option is B.
In AUVW, the measure of ZW=90°, the measure of ZU=61°, and VW =
3 feet. Find the length of UV to the nearest tenth of a foot.
The length of the UV is 3.7 feet.
Right Triangle:All triangles have interior angles adding to 180°. When one of those interior angles measures 90°, it is a right angle and the triangle is a right triangle. In drawing right triangles, the interior 90° angle is indicated with a little square □ in the vertex.
In ΔUVW , The sides and angles are :
∠W = 90°
∠U = 61°
VW = 3 feet.
Let, taking UV be x
So, Accordingly to right angle triangle,ΔUVW
Sin ∠U = \(\frac{VW}{UV}\)
Sin 61° = \(\frac{3}{x}\)
Sin 61° ≈ 0.87
Plug the values in above formula:
x = \(\frac{3}{0.87}\)
x = 3.7
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find the volume of the two cubes
Answer:
v=lxbxh
v=5x5x5
v=125cm
volume b
v=lxbxh
v=5x5x5
v=125cm
volume A+volume B
125+125=150
Step-by-step explanation:
you find the first one first then you find the second one then you add
Answer:
First cube
\( = {125}^{3} \)
second cube
\( = {125}^{3} \)
125 +125=250
Step-by-step explanation:
The formulas to find the volume of a cube are:
V = s3, where s is the edge length of the cube.
\(v = 5 \times 5 \times 5 = {125}^{3} \)
Suppose a gambler plays a game in which the probability of winning is 0.1. It costs him $1 to play and receives $8 for a win (he is up $7 for a win and down $1 for a loss).
If he starts with $4,what is the probability that the gambler is winning money or even after 16 plays? The gambler must stop playing if he reaches $0.(ans 0.2184 why
The probability that the gambler is winning money or even after 16 plays is 0.2184.
To determine the probability that the gambler is winning money or even after 16 plays, we need to analyze the possible outcomes and calculate the probabilities associated with each outcome.
Let's consider the different scenarios the gambler can encounter after 16 plays:
The gambler wins all 16 games: The probability of winning a single game is 0.1, so the probability of winning all 16 games is \((0.1)^1^6\). The gambler wins 15 games and loses 1 game: There are 16 different ways this scenario can occur (since the loss can happen in any of the 16 games). The probability of winning 15 games and losing 1 game is \((0.1)^1^5\)* (0.9).The gambler wins 14 games and loses 2 games: Similarly, there are (16 choose 2) = 120 ways this scenario can occur. The probability is \((0.1)^1^4\) * \((0.9)^2\). The pattern continues for different combinations of wins and losses, up to winning 8 games and losing 8 games.To calculate the total probability, we need to sum up the probabilities of all these scenarios. Mathematically, this can be represented as follows:
Probability = \((0.1)^1^6\) + (16 choose 1) * \((0.1)^1^5\) * (0.9) + (16 choose 2) * \((0.1)^1^4\) * \((0.9)^2\)+ ... + (16 choose 8) * \((0.1)^8\) * \((0.9)^8\)
By evaluating this expression, we find that the probability is approximately 0.2184.
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What is the measure of ZRST?
F(x)=2x+4 translation 7 units left
F(x - 7)=2x - 10
Step-by-step explanation:
F(x)=2x+4 translation 7 units left is given as:
\(F(x - 7)=2(x - 7)+4 \\ \\ F(x - 7)=2x - 14+4 \\ \\ \purple{ \boxed{F(x - 7)=2x - 10 }} \\ \\ \)
n a given year, there are 10 million unemployed workers and 120 million employed workers in an economy.
In a given year, an economy has 10 million unemployed workers and 120 million employed workers. This information provides a snapshot of the labor market and indicates the number of individuals who are currently without jobs and those who are employed.
The information states that in the given year, there are 10 million unemployed workers and 120 million employed workers in the economy. This data provides a measure of the labor market situation at a specific point in time.
Unemployed workers refer to individuals who are actively seeking employment but currently do not have a job. The number of unemployed workers can be an important indicator of the health of an economy and its ability to provide job opportunities.
Employed workers, on the other hand, represent individuals who have jobs and are currently working. The number of employed workers indicates the size of the workforce that is actively contributing to the economy through productive activities.
By knowing the number of unemployed and employed workers, policymakers, economists, and analysts can assess factors such as labor market conditions, unemployment rates, and workforce participation rates. This information is crucial for formulating policies, understanding economic dynamics, and monitoring the overall health and functioning of the economy.
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Calculate the engine size that represents the 10th percentile of this sample.
To calculate the engine size that represents the 10th percentile of a sample, we need a dataset of engine sizes and their corresponding frequencies or the values themselves.
Without that information, it is not possible to provide a specific answer. Percentiles are used to divide a dataset into 100 equal parts, with each percentile representing a specific percentage of the data. The 10th percentile represents the value below which 10% of the data falls.
To find the 10th percentile, you would need a dataset of engine sizes, sorted in ascending order. You would then identify the value that corresponds to the 10th percentile.
For example, if we had a dataset of engine sizes: 1.4L, 1.6L, 1.8L, 2.0L, 2.2L, 2.4L, 2.6L, 2.8L, 3.0L, 3.2L, 3.4L, and so on, we would arrange the values in ascending order and identify the value that corresponds to the 10th percentile.
Without the specific dataset or more information about the sample, it is not possible to calculate the engine size representing the 10th percentile.
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Find the area under the standard normal curve to the left of z=2.06. round your answer to four decimal places.
The area under the standard normal curve to the left of z = 2.06 is approximately 0.9803.
The normal distribution function, also known as the Gaussian distribution or bell curve, is a probability distribution that is symmetric, bell-shaped, and continuous. It is defined by two parameters: the mean (μ) and the standard deviation (σ).
The normal distribution is widely used in statistics and probability theory due to its many desirable properties and its applicability to various natural phenomena. It serves as a fundamental distribution for many statistical methods, hypothesis testing, confidence intervals, and modeling real-world phenomena.
To find the area under the standard normal curve to the left of z = 2.06, you can use a standard normal distribution table or a calculator with a normal distribution function. The standard normal distribution is a normal distribution with a mean of 0 and a standard deviation of 1.
Using a standard normal distribution table, the area to the left of z = 2.06 can be found by looking up the corresponding value in the table. However, since the standard normal distribution table typically provides values for z-scores up to 3.49, we can approximate the area using the available values.
The closest value in the standard normal distribution table to 2.06 is 2.05. The corresponding area to the left of z = 2.05 is 0.9798. This means that approximately 97.98% of the area under the standard normal curve lies to the left of z = 2.05.
Since z = 2.06 is slightly larger than 2.05, the area to the left of z = 2.06 will be slightly larger than 0.9798.
Therefore, rounding the answer to four decimal places, the area under the standard normal curve to the left of z = 2.06 is approximately 0.9803.
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You are playing a game that uses two fair number cubes. if the total on the number cubes is either 2 or 5 on your next turn, you win the game. what is
So, the probability of winning the game by rolling a total of 2 or 5 with two fair number cubes is 1/9.
The probability of winning the game on your next turn by rolling a total of 2 or 5 with two fair number cubes is 1/9.
To calculate the probability of winning, we need to determine the number of favorable outcomes (rolling a total of 2 or 5) and divide it by the total number of possible outcomes when rolling two number cubes.
There are 36 possible outcomes when rolling two number cubes since each cube has 6 faces, resulting in 6 * 6 = 36 total outcomes.
Out of these 36 outcomes, there are three favorable outcomes: (1, 1), (1, 4), and (4, 1), where the sum of the numbers rolled is either 2 or 5.
Therefore, the probability of winning the game on your next turn is 3 favorable outcomes out of 36 possible outcomes, which simplifies to 1/12.
So, the probability of winning the game by rolling a total of 2 or 5 with two fair number cubes is 1/9.
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A line that includes the point (9, −4) has a slope of −16. What is its equation in point-slope form?
Answer:
y+4= -16(x-9)
Step-by-step explanation:
point slope form is y-y1=m(x-x1)
substitute y-(-4)= -16(x-9)
simplify y+4= -16(x-9)
Which sign makes the statement true? (38)/(40) ? (19)/(20)
The correct sign that makes the statement true is the less than sign (<). To determine which sign makes the statement \(\frac{38}{40} ? \frac{19}{20}\) true, we need to compare the values of the fractions.
First, let's simplify the fractions:
\(\frac{38}{40} = \frac{19}{20}\)
Since the numerators of both fractions are the same, we need to compare the denominators. In this case, we have 40 and 20.
The denominator 40 is greater than the denominator 20. Therefore, the fraction \(\frac{38}{40}\) is larger than the fraction \(\frac{19}{20}\).
To make the statement true, we need to use the less than sign (<):
\(\frac{38}{40} < \frac{19}{20}\)
Therefore, the correct sign that makes the statement true is the less than sign (<).
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Find the measures of the numbered angles in rhombus QRST.
Cash price 550 000 installment 4500 per month repayment term 240 months determine the total amount if the installment option is used?
if the installment option is used, the total amount paid over the 240-month term would be $1,080,000. This includes both the principal amount of $550,000 and the interest accumulated over the repayment period.
To determine the total amount if the installment option is used, we need to calculate the total repayment over the 240-month term.
The installment amount per month is $4,500, and the repayment term is 240 months.
Total repayment = Installment amount per month * Repayment term
Total repayment = $4,500 * 240
Total repayment = $1,080,000
Therefore, if the installment option is used, the total amount paid over the 240-month term would be $1,080,000. This includes both the principal amount of $550,000 and the interest accumulated over the repayment period.
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Turn the word problem into an inequality. "There were at least 250 students at the dance."
Answer:
x ≥ 250
Step-by-step explanation:
i think thats what it is, but i could be wrong. sorry if i am.
5 objects of any size that are in
the shape of a rectangular prism.
You can find these items anywhere
around your house. You could use a
tissue box, shoe box, cereal box,
any snack food box, etc.
Ruler that has inches.
help
To make a triangular prism we need cardboard, glue and scissors.
What is a triangular prism?A triangular prism is a geometric shape characterized by:
It has three sides.It is a polyhedron.It has a triangular base and three faces that join it with another base.Its sides are rectangular.How to make a triangular prism out of cardboard?To make a triangular prism out of cardboard we must draw two equilateral triangles on the cardboard.Then we must draw three rectangles that have the same height as the length of the sides of the triangle.Subsequently, we must cut out all the shapes we draw, a total of five figures.Then we must paste the three rectangles on each side of the triangles.Once we glue the three rectangles to one of the triangles, we assemble the prism by joining the other side of the rectangles to the other triangle.Learn more about prism in: https://brainly.com/question/12649592
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On Saturday, a local hamburger shop sold a combined total of 369 hamburgers and cheeseburgers. The number of cheeseburgers sold was two times the
number of hamburgers sold. How many hamburgers were sold on Saturday?
hamburgers
Answer:
123
Step-by-step explanation:
Let 'x' = number of hamburgers.....then cheeseburgers = '2x'
added together they = 369
x + 2x = 369
3x = 369
x = 123 hamburgers
Please someone help me with the ending balance and summary I don't know what to do I really need this for my school project (please do not use links)
Answer:
Solution given:
Annual salary;X
monthly salary:\( \frac{X}{12} \)
Monthly expenses:
Total:$12+391+50+100+119.98+75+10+387+178
=$1322.98
I have $X-$1322.98 left after I pay all expenses monthly.
Suppose $726.56 is deposited at the end of every six months into an account earning 6.45% compounded semi-annually. If the balance in the account four years after the last deposit is to be $31 300.00, how many deposits are needed? (This question asks for 'n')
We need approximately 10 deposits to reach a balance of $31,300 four years after the last deposit which is compounded semi-annually.
To solve this problem, we can use the formula for the future value of an annuity:
\(FV = P * ((1 + r)^n - 1) / r\)
Where:
FV is the future value of the annuity
P is the periodic payment or deposit amount
r is the interest rate per period
n is the number of periods
In this case, the deposit amount is $726.56, the interest rate is 6.45% compounded semi-annually, and the future value is $31,300. We need to find the number of deposits (n).
We can rearrange the formula and solve for n:
n = log((FV * r) / (P * r + FV)) / log(1 + r)
Substituting the given values:
n = log((31,300 * 0.03225) / (726.56 * 0.03225 + 31,300)) / log(1 + 0.03225)
Using a calculator or software, we find that n ≈ 9.989.
Therefore, we need approximately 10 deposits to reach a balance of $31,300 four years after the last deposit.
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ANSWER THIS QUICK!! IT¨S WORTH 46 POINTS
Answer:
The answer is option AStep-by-step explanation:
\( \frac{4\pi \sqrt{5} - 2\pi \sqrt{5} }{3 \sqrt{5} } \)Simplify the numerator first
Since they have the same square root that's root 5 we can subtract them directly
That's
\(4\pi \sqrt{5} - 2\pi \sqrt{5} = (4\pi - 2\pi) \sqrt{5} \\ = 2\pi \sqrt{5} \)So we have
\( \frac{2\pi \sqrt{5} }{ 3\sqrt{5} } \)Reduce the expression with √5
We have the final answer as
\( \frac{2\pi}{3} \)Hope this helps you
the base of a triangle is 7 less than twice its height. If the area of the triangle is 102m^2, find the length of the base.
Answer:
The length of the base will be: 17 m
Step-by-step explanation:
Given the area of the triangle
\(A=102\:m^2\)
Using the formula of Area of a triangle:
\(A=\frac{1}{2}\left(b\times h\right)\)
Here,
'b' is the base'h' is the heightAs the base of a triangle is 7 less than twice its height.
so
\(b=2h-7\)
so the formula of Area of a triangle becomes
\(102=\frac{1}{2}\left(\left(2h-7\right)\times \:h\right)\)
\(204=h\left(2h-7\right)\)
\(2h^2-7h=204\)
\(2h^2-7h-204=0\)
\(\left(2h+17\right)\left(h-12\right)=0\)
\(2h+17=0\quad \mathrm{or}\quad \:h-12=0\)
\(h=-\frac{17}{2},\:h=12\)
As height can not be negative, so:
\(h=12\) m
Hence, the length of the base:
\(b=2h-7\)
\(= 2(12)-7\)
\(=24-7\)
\(= 17\) m
Therefore, the length of the base will be: 17 m
(-3, 1), (-17, 2) find the slope show the work
Answer:
1/-14 or -0.071428571428571
Step-by-step explanation
(-3,1) ___ -3 is x1 while 1 is y1
(-17, 2) ___ -17 is x2 while 2 is y2
slope formula is m = y2-y1/x2-x1
plug them in: m = 2-1/-17-(-3), which equals 1/-14 or -0.071428571428571
I’ll post part one but plz help it’s worth 15POINTS I’ll mark as Well!!!!
Answer:
Wellll
Step-by-step explanation:
which part of this graph shows a nonlinear relationship?
1. 4
2. 1
3. 3
4. 2
When dealing with an equation containing two variables, we can put the graph of the equation on the coordinate plane because the number of variables is equal to the number of dimensions that are needed to properly graph the solution. Each axis on a graph represents one variable in the equation being graphed. What would you use to graph the solution to an equation with one variable? What would you use to graph the solution to an equation with three variables? Could you graph an equation containing more than four variables? Explain.
If you were given the graph of an equation with two variables on a coordinate plane, what would happen to the graph if all the y-values were increased by 1? What would happen to the graph if all the x-values were increased by 1? What would happen to the graph if all the y-values were multiplied by 2 or by 1/2? Explain.
Answer:
Step-by-step explanation:
A linear equation with two variables may appear in the form of Ax + By = C, and the resulting graph is always a straight line. The equation is more often in the form of y = mx+b, where m is the slope of the line of the corresponding figure and b is its Y-axis intercept, that is, the point where the line meets the Y-axis.
For example, 4x + 2y = 8 is a linear equation because it fits the desired structure. But for graphical and most other purposes, we often write this as y = - 2x + 4.
In this unit, on the basis of this linear equation, the equal sign is changed to the greater than a sign or less than sign, which is a new challenge in the operation of symbols.
round to the nearest hundredth 5.0927
Answer:
5.09
Step-by-step explanation:
Answer:
5.09
Step-by-step explanation:
FIA. Co just paid a dividend of $10, and its dividend is expected to grow at 13 percent for next year, and 11 percent the year after. After you receive the second dividend, you expect to sell the stock at $88 immediately. Assume that the discount rate is 15 percent. What is the intrinsic value of the stock?
The intrinsic value of the stock is $67.29, considering a dividend payment of $10, expected dividend growth rates of 13% and 11% for the next two years, and a future selling price of $88. The discount rate used in the calculation is 15%.
To calculate the intrinsic value, we need to determine the present value of future dividends and the future selling price of the stock. We can use the dividend discount model (DDM) to calculate the present value of dividends.
First, we calculate the present value of the dividend for the first year. Since the dividend is expected to grow at 13 percent, we can calculate it as follows:
Present value of first dividend = $10 / (1 + 0.15) = $8.70.
Next, we calculate the present value of the dividend for the second year, which is expected to grow at 11 percent:
Present value of second dividend = ($10 * (1 + 0.13)) / (1 + 0.15)^2 = $8.96.
Finally, we calculate the present value of the selling price of the stock:
Present value of selling price = $88 / (1 + 0.15)^2 = $60.63.
To find the intrinsic value of the stock, we sum up the present values of dividends and the present value of the selling price:
Intrinsic value = Present value of first dividend + Present value of second dividend + Present value of selling price
Intrinsic value = $8.70 + $8.96 + $60.63 = $67.29.
Therefore, the intrinsic value of the stock is $67.29.
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