Gases other than compressed air are normally supplied in pressurized cylinders at?

A liquid at 50 degrees Celsius would have a melting point of 50 degrees Celsius and a boiling point of approximately 173.15 degrees Celsius.

What is the liquid?

iquid is a state of matter that has a definite volume, but does not have a fixed shape. It is one of the four fundamental states of matter, along with solid, gas, and plasma. Liquids tend to have a greater volume than solids, but geneLrally take the shape of their container. Examples of liquids include water, milk, blood, gasoline, and oil. Liquids are composed of molecules that tend to have greater mobility and can easily flow past each other. Depending on the temperature, pressure, and composition of the liquid, it can undergo changes in the state of matter.

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The bromination of an alkane, compared to the radical formation for chlorination takes place at a slower rate.

Alkanes are organic group of compounds that contains an aldehyde in their first carbon atom. Bromination and chlorination are the replacement of hydrogen group with a halogen group, such as bromine or chlorine.

       As we know that halogenation involves the formation of a carbon-halogen bond. The halogenation will surely depend on the carbon-halogen strength. The more powerful the bond is the slower it will take place.

       Bond formation energy of C−Cl is higher than that of C−Br bond. So, the ease of bromination is lower than the ease of chlorination. As chlorine is a more electro negative ion it gets dissociates easily.

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The dependent variable is the heart rate of daphnia, a small crustacean.

WHAT IS INDEPENDENT AND DEPENDENT VARIABLES?

In an experiment, two variables are important. These two variables are the independent variable and dependent variable.

Therefore, the dependent variable is the heart rate of daphnia, a small crustacean.

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Answer:

4.2 × 10¹⁷ atoms of Se

Explanation:

Step 1: Convert the mass to grams

We will use the conversion factor 1 g = 10⁶ μg.

55 μg × 1 g/10⁶ μg = 5.5 × 10⁻⁵ g

Step 2: Calculate the moles corresponding to 5.5 × 10⁻⁵ g of Se

The molar mass of Se is 78.96 g/mol.

5.5 × 10⁻⁵ g × 1 mol/78.96 g = 7.0 × 10⁻⁷ mol

Step 3: Calculate the atoms in 7.0 × 10⁻⁷ moles of Se

We will use Avogadro's number: there are 6.02 × 10²³ atoms of Se in 1 mole of Se.

7.0 × 10⁻⁷ mol × 6.02 × 10²³ atom/1 mol = 4.2 × 10¹⁷ atom

Answer:

19.79%

Explanation:

mass % = (mass solute / total mass) * 100

total mass = 129.54 + 525 = 654.54

solute = C6H12O6

(129.54/654.54) = .1979

.1979 * 100 = 19.79%

Formamide has the structure HC(O)NH2 and atoms in formamide that have a trigonal planar geometry are (c) both C and N.

Formamide is the simplest monocarboxylic acid amide which is obtained by formal condensation of formic acid with ammonia. It is the parent of the class of formaldehydes and has a role as a solvent. It is monocarboxylic acid amide, one-carbon compound and member of formamides.

Formamide is used as a feedstock in the manufacture of formate esters, as  ionizing solvent, as RNA stabilizer in gel electrophoresis, and also in tissue preservation. Health effects may occur immediately after exposure to formamide such as eye irritation and burns.

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Answer:A measure of performance of fuel for internal combustion engines. Stated simply, a higher octane rating corresponds to more engine power and less knocking or other pre-ignition problems.

Explanation:

I'm also in chemistry.

Answer:

Explanation:

figure indicating the antiknock properties of a fuel, based on a comparison with a mixture of isooctane and heptane.

Answer:

4.  0.5 kilometers (1st option)

5.  0.1 00 liters (last option)

Explanation:

500 meters to kilometers

4.

1 kilometer = 1000 meters

We use the formula SBD (SMALL TO BIG DIVIDE) i hope this helps you

500 ÷ 1000

= 0.5 kilometers

5.

100 milliliter to liter

SBD

100 ÷ 1000

= 0.1 00 liters

Denise ought to keep detailed record of the experiment to allow someone to do the same investigation and check the accuracy of results. Option D

The term experiment has to do with cause and effect relationships. We know that the cause is what leads to the effect if the process can be tested in a laboratory. The experiment that as performed by Denise was targeted at finding what time of the day is warmest.

From the results of the experiment, we can conclude that Denise ought to keep detailed record of the experiment to allow someone to do the same investigation and check the accuracy of results.

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Answer:

pOH = 8

Explanation:

There are many formulaes to go from pH to pOH. One of my favorites is this one:

pH+pOH=14  (Now this just becomes an algebra problem because you already know pH value)

6 + pOH = 14 (subtract 6 from both sides)

pOH= 8

As for the two different types of chemical bonding illustrated by Figure A and Figure B, they are the Ionic bond and Polar covalent bond. The properties and descriptions that best illustrate each figure are listed below:Figure AIonic BondThe ionic bond involves the transfer of valence electrons from the nonmetal to the metal ion. There is no sharing of electrons in ionic bonding, and the valence electrons in the anion are transferred to the metal cation, creating an ion-pair. This leads to an electrostatic attraction between the anion and cation, which is the ionic bond's fundamental concept.The Na-Cl bond is a prime example of an ionic bond since sodium is a metal, while chlorine is a nonmetal, and the bond between them is ionic.Polar Covalent BondThe polar covalent bond involves unequal sharing of electrons, as opposed to the ionic bond. Electronegativity differences lead to unequal sharing, and if one atom is more electronegative than the other, it attracts electrons closer to it, creating partial negative and positive charges.The N-H bond is a perfect example of a polar covalent bond because the hydrogen atom has a partial positive charge, while the nitrogen atom has a partial negative charge.Figure BNon-polar Covalent BondA non-polar covalent bond occurs when two atoms share electrons equally between them. Both atoms have the same electronegativity; thus, electrons are evenly shared between them.The C-Cl bond is a prime example of a non-polar covalent bond since both atoms have a relatively similar electronegativity, and there is an equal sharing of electrons.Transder of CloctromThere is no such thing as a transder of cloctrom bond. The correct term is transfer of electrons.CI-CI BondCI-CI bond is a covalent bond between two identical chlorine atoms, representing a diatomic molecule. Since the atoms are identical, there is no difference in electronegativity, and electrons are evenly distributed.Polar Covalent BondThe polar covalent bond involves unequal sharing of electrons, as opposed to the ionic bond. Electronegativity differences lead to unequal sharing, and if one atom is more electronegative than the other, it attracts electrons closer to it, creating partial negative and positive charges.The unequal sharing of electrons is best illustrated by the unequal sharing of electrons in the carbon-oxygen bond.

The mass of \(N_2\) that dissolves in 1.0 L of water at 25°C and 0.75 atm of \(N_2\) is approximately \(1.3 \times 10^{(-2)\) g. Here option D is the correct answer.

To solve this problem, we'll use Henry's law, which states that the concentration of a gas in a liquid is directly proportional to the partial pressure of the gas above the liquid. The mathematical equation for Henry's law is:

C = k * P

Where:

C is the concentration of the gas in the liquid (in mol/L or M),

k is Henry's law constant (in M/atm),

P is the partial pressure of the gas (in atm).

We are given:

Henry's law constant (k) = \(6.4 \times 10^{(-4)\) M/atm

Partial pressure of \(N_2\) (P) = 0.75 atm

The volume of water (V) = 1.0 L

We need to find the mass of \(N_2\) that dissolves in 1.0 L of water. Let's follow the steps to solve the problem:

Step 1: Calculate the concentration of \(N_2\) in the water using Henry's law equation.

C = k * P

C = (\(6.4 \times 10^{(-4)\) M/atm) * (0.75 atm)

C = \(4.8 \times 10^{(-4)\) M

Step 2: Convert the concentration from molar (M) to grams (g).

To convert from molar concentration to mass, we need to multiply by the molar mass of \(N_2\). The molar mass of \(N_2\) is approximately 28 g/mol.

Mass of \(N_2\) = Concentration * Molar mass

Mass of \(N_2\) = (\(4.8 \times 10^{(-4)\) M) * (28 g/mol)

Mass of \(N_2\) = \(1.344 \times 10^{(-2)\) g

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Answer:The atoms in gases are far apart from each other, so they are much more disordered than either liquids or solids.

Explanation:

In an activity involving the use of bromothymol blue solution and Cabomba (an aquatic plant), the purpose of having two tubes containing bromothymol blue solution without the Cabomba is to serve as control tubes.

The control tubes allow us to compare the changes in color and pH of the solution in the experimental tubes (i.e., the tubes with Cabomba) to the changes in the solution without Cabomba.

The bromothymol blue solution changes color in response to changes in pH, so if the solution in the experimental tube turns yellow (indicating a decrease in pH) while the solution in the control tube remains blue, we can conclude that the decrease in pH is due to the activity of the Cabomba. On the other hand, if both the experimental and control tubes turn yellow, we cannot attribute the change in pH solely to the activity of the Cabomba, as there may be other factors affecting the pH of the solution.

By having control tubes, we can ensure that any observed changes in the experimental tubes are due to the activity of the Cabomba and not due to some other factor. This helps to ensure the accuracy and reliability of the experimental results.

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In the context of atomic orbital (AO) wavefunctions, the terms "radial node" and "nodal plane" refer to different aspects of the wavefunction's behavior.

A radial node is a region in the AO wavefunction where the probability of finding an electron is zero along the radial direction. In other words, it represents a spherical shell where the electron is unlikely to be found. The number of radial nodes is determined by the principal quantum number (n) of the orbital. For example, the 2s orbital has one radial node, while the 2p orbital has no radial nodes.

On the other hand, a nodal plane is a flat plane within the AO wavefunction where the probability of finding an electron is zero along a particular direction. It represents a surface that divides the orbital into two regions of opposite phases. The number of nodal planes is determined by the angular quantum numbers (l and m) of the orbital. For example, the 2s orbital has no nodal planes, while the 2p orbital has one nodal plane (the xz or yz plane).

Radial nodes arise from the radial part of the wavefunction because they depend on the distance from the nucleus. The radial part determines the distribution of the electron density as a function of distance, and the nodes correspond to regions where the density drops to zero.

On the other hand, nodal planes arise from the angular part of the wavefunction because they depend on the orientation and shape of the orbital. The angular part describes the angular distribution of the electron density around the nucleus, and the nodal planes correspond to regions where the phase of the wavefunction changes sign.

In summary, radial nodes are related to the distance from the nucleus and arise from the radial part of the wavefunction, while nodal planes are related to the orientation and shape of the orbital and arise from the angular part of the wavefunction. The 2s orbital has one radial node and no nodal planes, while the 2p orbital has no radial nodes and one nodal plane.

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ANSWER

B po yung ans:)

Answer:

The correct options are;

1. 1,600

2. 100 Watts

A 23-30 watt CFL provides 1,600 lumens and is equivalent to a 100 Watts incandescent bulb

Explanation:

Brightness is measured in lumens and watts measure energy usage therefore with the use of an energy saving light bulb, the same lumination can be obtained at a lower energy usage.

According to a comparison chart for LED Lights vs. Incandescent Light Bulbs vs. Compact Fluorescents (CFLs) from USAI lightening website 23-30 watts CFL has a light output of 1,600 and is therefore produces enough light as a 100 Watts Incandescent Light Bulb

Also according to energy.gov website, CFLs save up to 75% energy such that a 23-30 watt CFL can produce the same illumination as a 100 watt incandescent bulb

Therefore we have, a 23-30 watt CFL provides 1,600 lumens and is equivalent to a 100 Watts incandescent bulb.

Answer:

1600 lumens, 100 watt incandescent

Explanation:

100% on edge (:

Explanation:

Assume if its asking about molecule particle:

1 mol of AgNO3 = 6.022 x 10^23 molecules

0.75 mol of AgNO3 = 0.75 x 6.022 x 10^23

= 4.5165 x 10^23 molecules

Assume if its asking about atom particle:

AgNO3 has 5 elements

0.75 mol of AgNO3 = 0.75( 5 x 6.022 x 10^23)

= 2.2583 x 10^24 atoms

The answers would be for 2nd and 3rd composites are X3Z4 and X4Z3.

The given questions is incorrect, the question is that the first emulsion has the formula X2Z3. also what is the chemical formula for alternate and also the third emulsion?

According to the question,

Mass of X in first emulsion = 1.0 g

Mass of Z in first emulsion = 0.472 g

The chemical formula of first emulsion = X2Z3

This means1.0 g of X is over to 2 intelligencers of X

= > One operative of X = 0.5 g of X.

g of Z is similar to 3 intelligencers of Z< = > one operative of Z = 0.15733 g of X.

Now for the Alternate emulsion,

Mass of X = 1.0 g

intelligencers of X = 1.0/0.5 = 2

Mass of Z = 0.420 grams

Number of intelligencers of Z = 0.420/0.15733 = 2.6695 intelligencers

rate of intelligencers of X to Z = 22.6695 = 3 4

Empirical formula of alternate emulsion = X3Z4

Now for the third emulsion,

Mass of X = 1.0 g

Intelligencers of X = 1/0.5 = 2 intelligencers

Mass of Z = 0.236 grams

Number of intelligencers of Z = 0.236/0.15733 = 1.5 intelligencers

Rate of intelligencers of X to Z = 21.5 = 4 3

Empirical formula of third emulsion = X4Z3

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The acid in the given reaction is HBr (Option B). In a chemical reaction, acid is a substance that donates or gives away hydrogen ions (H+) while the base is a substance that accepts hydrogen ions.

When the base accepts the hydrogen ion, it becomes positively charged.What is the reaction given?Consider this reaction :KOH + HBr ➝ KBr + H₂OKOH is a base while HBr is an acid. When KOH and HBr react, they form KBr and H₂O (water). HBr loses a hydrogen ion to KOH which accepts it. Thus HBr donates a proton (H+) to KOH which accepts the proton. Therefore, HBr acts as an acid while KOH acts as a base. So, the correct answer is option B, HBr.Further HBr stands for hydrogen bromide, which is a highly acidic compound. It gives off H+ ions when dissolved in water and donates H+ ions to a base to produce water.

The given reaction is an example of a neutralization reaction, as a base KOH (potassium hydroxide) reacts with an acid, HBr (hydrogen bromide), to produce a salt, KBr (potassium bromide), and water.

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A 250 ml sample of saturated a g o h solution was titrated with h c l , and the endpoint was reached after 2. 60 ml of 0. 0136 m h c l was dispensed. Based on this titration, what is the k s p of a g o h . Ksp=1.9×10⁻⁸

Titration is a typical laboratory technique for quantitative chemical analysis used to calculate the concentration of a specified analyte. It is also referred to as titrimetry and volumetric analysis (a substance to be analyzed). A standard solution with a known concentration and volume is prepared as the reagent, also known as the titrant or titrator. To ascertain the concentration of the analyte, the titrant reacts with an analyte solution (also known as the titrand). The titration volume is the amount of titrant that interacted with the analyte.

A typical titration starts with a beaker or Erlenmeyer flask being placed below a calibrated burette or chemical pipetting syringe that contains the titrant and a little amount of the indicator (such as phenolphthalein).

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Answer:  neutralization reaction

Explanation:

An acid-base reaction is a type of chemical reaction that involves the exchange of one or more hydrogen ions, H+, between species that may be neutral (molecules, such as water, H2O) or electrically charged (ions, such as ammonium, NH4+; hydroxide, OH−; or carbonate, CO32−).

The correct answer is

True for the statements, and

(B) 1

For alcohol dehydrogenase,

Two of the statements are true:

1. Ethanol is the reducing agent, which means it loses electrons and is oxidized during the reaction.

This is because it donates two hydrogen atoms to NAD+ to form NADH, while itself losing two hydrogen atoms to become acetaldehyde.

2. NAD+ is being oxidized, which means it loses electrons and is reduced during the reaction. This is because it accepts two hydrogen atoms from ethanol to form NADH.

3. There is a transfer of electrons during the reaction.

This is because ethanol donates two hydrogen atoms (and their associated electrons) to NAD+ to form NADH, while itself losing two hydrogen atoms (and their associated electrons) to become acetaldehyde.

Therefore, statement 3 is false.

4. Ethanol is not reduced during the reaction. Instead, it is being oxidized (as mentioned in statement 1) to form acetaldehyde.

Therefore, statement 4 is false.

In summary, the correct answer is (B) 1.

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The balanced chemical equation for the combustion reaction of the gaseous hydrocarbon fuel (CxH2x+2) with air can be written as CxH2x+2 + (2x + 1)O2 + 3.76N2 -> xCO2 + (x + 1)H2O + 3.76(2x + 1)N2. The fuel is determined to be methane (CH4).

The balanced chemical equation for the combustion reaction of the gaseous hydrocarbon fuel (CxH2x+2) with air can be written as:

CxH2x+2 + (2x + 1)O2 + 3.76N2 -> xCO2 + (x + 1)H2O + 3.76(2x + 1)N2.

Given the volumetric analysis of the products of combustion, we can determine the value of x in the hydrocarbon fuel. The percentage of carbon dioxide (CO2) corresponds to the carbon atoms in the fuel, so 9.45% CO2 implies x = 1. The fuel is therefore methane (CH4).

To calculate the air-fuel ratio, we compare the moles of air to the moles of fuel in the balanced equation. From the equation, we have (2x + 1) moles of oxygen (O2) and 3.76(2x + 1) moles of nitrogen (N2) for every 1 mole of fuel. Substituting x = 1, we find that the air-fuel ratio is 17.2 kg of air per kg of fuel.

To determine the heat transfer rate and combustion efficiency on a lower heating value (LHV) basis, we need to calculate the molar enthalpies of the reactants and products. Using standard molar enthalpies of formation, we can calculate the change in molar enthalpy for the combustion reaction. The heat transfer rate can be obtained by multiplying the change in molar enthalpy by the mass flow rate of the fuel. The combustion efficiency on an LHV basis can be calculated by dividing the actual heat transfer rate by the ideal heat transfer rate.

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Answer:

In simple terms, the endothermic reactions absorb energy from the surrounding that is in the form of heat. On the other hand, an exothermic reaction releases energy into the surrounding of the system. A popular example of an endothermic chemical reaction is photosynthesis.

(i searched in g o o gle)

Answer:

draws in pollution.

Explanation:

While they circulate ocean waters, they're also drawing in the pollution that we release in coastal areas, known as marine debris.

Explanation:

The ultraviolet light is responsible for the glow. It activate the calcite and causes it to temporarily emit visible light of various colors. This light emission is known as "fluorescence."

Calcite has the ability to temporarily absorb a small amount of light and an instant later release a small amount of light of a different wavelength. This change in wavelength causes a temporary color change of the mineral in the eye of a human observer.

This process of flourescence occurs when a specimen is illuminated with specific wavelengths of light. Ultraviolet (UV) light, x-rays, and cathode rays are several examples of light that can cause this process. The light from the desk is not enough to cause thsi flourescence.

Answer: athe answer is a

Explanation:

The statement "Isotopes with an even number of both protons and neutrons are generally stable" is TRUE.

Isotopes with an even number of protons and neutrons are known as isotopes. A single element can have a different number of neutrons; such elements are known as isotopes. A nucleus containing a different number of neutrons will have a different mass number than the element's standard atomic number since the mass number is equal to the number of neutrons plus the number of protons in the nucleus.

There are 275 isotopes recognized for 81 stable elements, while there are 50 isotopes for elements that are radioactive and occur naturally.

Isotopes with an even number of both protons and neutrons tend to be more stable, as the strong nuclear force and the electromagnetic force in a nucleus cancel out, causing a more stable nucleus. The vast majority of stable elements have a nearly equal number of neutrons and protons, though there are some exceptions, such as beryllium-8 and helium-3.

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