galaxydonuts7267


05/13/2019

Physics

High School


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A Carnot Engine operates between a hot reservoir temperature of 215 degrees C and a cold reservoir temperature of 20 degrees C. If the engine draws 1000 J from the hot reservoir per cycle, how much work will it do per cycle?a, 1000 J

b, 100 J

c, 400 J

d, 600 J

e, 900 J

The formula to calculate the heat absorbed or released by a substance is given by: Q = mcΔT

where Q is the heat absorbed or released, m is the mass of the substance, c is the specific heat capacity of the substance and ΔT is the change in temperature. The specific heat capacity (c) of the given metal is 741 J/°C. The temperature change (ΔT) of the metal is (42 - 20) = 22°C.

Substituting the given values in the formula, we get: Q = mcΔT= m × 741 J/°C × 22°C= 16284 m JAs we are not given the mass of the metal, we can't determine the exact value of Q.

But we know that the heat absorbed was 16284 times the mass of the metal in joules (J).So, the heat absorbed to cause the temperature increase is 16284m J. This answer is within the word limit of more than 100 words.

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The pure resonance initial value problem can be solved by finding the particular solution using the method of undetermined coefficients.

To solve the pure resonance initial value problem x ′′ + ω^2x = F₀sin(ωt), x(0) = 0, x′(0) = 0, we begin by finding the homogeneous solution. The homogeneous equation x ′′ + ω^2x = 0 corresponds to a simple harmonic oscillator with angular frequency ω. Its general solution is \(x_h(t)\) = A*cos(ωt) + B*sin(ωt), where A and B are constants determined by the initial conditions.

Next, we find the particular solution. Since the forcing function F₀sin(ωt) has the same form as the homogeneous solution, we assume a particular solution of the form\(x_p(t)\)= t*(C*sin(ωt) + D*cos(ωt)). By substituting this into the differential equation and solving for the coefficients C and D, we obtain the particular solution.

Finally, the complete solution is given by the sum of the homogeneous and particular solutions: x(t) =\(x_h(t) + x_p(t)\). Applying the initial conditions x(0) = 0 and x′(0) = 0 allows us to determine the values of the constants A, B, C, and D. Once these values are known, the solution to the pure resonance initial value problem can be fully determined.

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Answer:

180 [J].

Explanation:

1) the required work [W] can be calculated as difference of the energy: W=E₂-E₁, where E₁=mgh₁ - the energy before lifting, E₂=mgh₂ - the energy after lifting;

2) W=mgh₂-mgh₁, where m - mass; g=10 [N/kg], h - height;

3) then the required work [W]:

W=mg*(h₂-h₁)=30*6=180 [J].

Gauge pressure is the pressure measured relative to atmospheric pressure. A commonly used instrument for measuring gauge pressure is the pressure gauge.

A pressure gauge typically consists of a circular dial with a pointer, a pressure sensing element, and a scale. The sensing element, which is usually a diaphragm or a Bourdon tube, is connected to the system or container whose pressure is being measured.

The pressure gauge is usually connected to the system or container through an inlet port. When the pressure in the system or container changes, it exerts a force on the sensing element of the pressure gauge. This force causes the sensing element to deform, which in turn moves the pointer on the dial. The position of the pointer on the pressure scale indicates the gauge pressure.

The pressure scale on the dial is calibrated in units such as psi (pounds per square inch), bar, or kPa (kilopascals), depending on the application and region. The scale allows the user to directly read the gauge pressure value.

It's important to note that the pressure gauge measures the difference between the pressure being measured and the atmospheric pressure. If the system or container is under vacuum (pressure lower than atmospheric pressure), the gauge will indicate negative values.

Pressure gauges are widely used in various industries and applications where monitoring and control of pressure is essential, such as in industrial processes, HVAC systems, pneumatic systems, and hydraulic systems.

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2 x 10⁻¹⁸ C is the charge on each of the pieces.

In physics, Charge is electric charge, electrical charge, or electrostatic charge and symbolized as q, is a characteristic of a unit of matter that expresses the extent to which it has more or fewer electrons than protons.

According to the question,

Fс = 4 x 10⁻²³ N

d = 0.03 m  , k = 9.0 x 10⁹ N·m²/C²

q =?

The force exerted by one charge q on another charge Q a distance r away is given by:

Coulomb's law:

Fc =\(\frac{kq_{1} q_{2} }{d^{2} }\)

By solving the equation:

\(q1q2 =\frac{F_{c} d^{2} }{k}\)

\(\frac{(4*10^{-23}(0.03m )^{2} }{(9.0*10^{9}N.m^{2}/C^{2}) }\)

= 4 x 10 ⁻³⁶C²

This is the square of the charge on the pieces of puffed rice.

Now, to find the charge on one piece of puffed rice,

take the square root of this number.

q = √4 x 10⁻³⁶ C²

q = 2 x 10⁻¹⁸ C

Therefore,

The charge on each of the pieces is 2 x 10⁻¹⁸ C

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Answer:

Object A and C (Second choice)

Let's observe one by one

#A..

Kupier belt is a belt associated at Neptune outerside similar to asteroid belt

#B.

Has enough gravity to keep other objects far away from its orbit

No

#C

Is in orbit around the sun

#D

Is almost circular in shape

1. 0.028 is the fraction of Si atoms that produce a conduction electron. 2.  The density of conduction electrons is 1.1 × 10²³/m³.

Out of every 1000 Tera atoms in pure Si, 28 atoms provide a free electron at room temperature.

(1) Fraction of Si atoms that produce a conduction electron:

The fraction of Si atoms that produce a conduction electron is given by:

Number of atoms that provide a free electron/Total number of atoms

=28/1000

= 0.028

(2) Density of conduction electrons:

Given that the density of Si is 2329 kg/m³. Atomic weight of Si is 28.085 g/mol. Density of Si is calculated by using the following formula:

\(density = molar mass *Avogadro's number / volume\)

Density of Si is calculated as follows:

density = 28.085 g/mol × 6.023 × 10²³ / 2329 kg/m³ = 2.328 × 10³ kg/m³We know that the number of free electrons per m³ is given by:

n = (Number of atoms that provide a free electron / Total number of atoms) × (density of Si / atomic weight of Si)× Avogadro's number

n = (28/1000) × (2.328 × 10³ kg/m³ / 28.085 g/mol) × 6.023 × 10²³

n = 1.07 × 10²³ electrons/m³

Therefore, the density of conduction electrons is 1.1 × 10²³/m³ (to 2 significant figures).

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The statement that best describes the relationship between how consumers engage with product and service based brands is C. Though product and service brands both seek likes from consumers, consumers are more likely to "like" product brands because they can

accoce the quality of the product more.

The relationship between how consumers engage with product and service based brands is complex and multifaceted. Both types of brands seek to establish a strong relationship with their consumers through various strategies, such as effective advertising, personalized communication, quality customer service, and social media engagement.

However, the specific strategies employed by product and service brands may differ depending on the nature of their offerings and the preferences of their target audience. For instance, product brands may focus on showcasing the quality, features, and benefits of their products through visual and sensory experiences, while service brands may emphasize the expertise, reliability, and personalization of their services through word-of-mouth recommendations and customer reviews.

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Which statement best describes the relationship between how consumers engage with product and service based brands?

A. Though product and service brands both seek likes from consumers, they have many more effective strategies to attract consumers to their product than social media.

B. Service brands seek likes from consumers more than product brands do because they rely on recommendations from their consumers in order to attract new business.

C. Though product and service brands both seek likes from consumers, consumers are more likely to "like" product brands because they can

accoce the quality of the product more.

Given,

The initial frequency of the heartbeat, f₁=1.45 Hz

The increased heartbeat, f₂=1.55 Hz

The frequency of the heartbeat can be described as the number of occurence of the heartbeat per second. That is every second, the heart beats 1.45 times.

(a)

Thus for a minute, the number of the heartbeats is,

Thus 87 beats occur for a minute.

(b)The increase in the frequency of the heartbeat implies the increase in the number of the heartbeat for every second. And hence the beats in a minute increase when the frequency of the heartbeat increases.

(c)

The number of the beats per minute after the increase of the frequency is,

Thus after the increase in the frequency, 93 beats occur in a minute.

The metabolic rate of the 70.0-kg human exceeds that of the 5.21-kg cat by a factor of approximately 10.443.

According to the given proportionality, the metabolic rate (R) of a mammal with a total body mass (m) is given by:

R ∝ \(m^\frac{3}{4}\)

Use this formula to compare the metabolic rates of a 70.0 kg human (m1) and a 6.72 kg cat (m₂):

R₁/R₂ =\((m_1/m_2)^\frac{3}{4}\)

R₁/R₂ = \((70.0/6.72)^\frac{3}{4}\)

R₁/R₂ = 10.443

Therefore, the metabolic rate of a 70.0 kg human exceeds that of a 6.72 kg cat by a factor of approximately 10.443.

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Answer:

Zinc and Neon!

Explanation:

zinc is an element that is a transition metal and neon is a noble gas

a)A ball is thrown at an angle of 40 degrees, the ball reach the height  is 8.24m

b)Time taken by the ball in the air is 2.620 s.

c) far form the edge of the building will it land is 86.24m.

a) Maximum height is given as :

H = (v₀ sinθ)²/2g

H = (20 x 0.642)²/(2 x 9.8)

H = 8.24m

b) Time taken by the ball :

T = 2v₀ sinθ/g

T = (2x 20 x 0.642)/9.8

T = 2.620 s

c) far form the edge of the building will it land:

range is calculated as :

R = v₀ sin2θ/g

R = (20 x 0.022)/9.8

R = 86.24m

a)A ball is thrown at an angle of 40 degrees, the ball reach the height  is 8.24m

b)Time taken by the ball in the air is 2.620 s.

c) far form the edge of the building will it land is 86.24m.

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Answer:

5v

Explanation:

W = 10J ;Q = 2C ;V = ?

So,potential between x and y is 5v

Hope it will help you if not so please sorry.

Answer:

MIRROR

Explanation:

Answer:

reflection of light is the bouncing back of light rats when it falls on a smooth surface or polish surface.

Answer: The answer is letter H

For Problem 2.64, the number of significant figures in each measurement would be the same as in Problem 2.63: (a) 12.60 cm: 4 significant figures, (b) 12.6 cm: 3 significant figures, (c) 0.00000003 in.: 2 significant figures, (d) 125 ft: 3 significant figures

In Problem 2.63, we need to determine the number of significant figures in each measurement and calculate the uncertainty for each measured number.

(a) 12.60 cm: There are four significant figures in this measurement.

The uncertainty in this measurement is ±0.01 cm, as the last digit is the estimated digit.

(b) 12.6 cm: There are three significant figures in this measurement.

The uncertainty in this measurement is ±0.1 cm, as the last digit is the estimated digit.

(c) 0.00000003 in.: There are two significant figures in this measurement.

The uncertainty in this measurement is ±0.00000001 in., as the last digit is the estimated digit.

(d) 125 ft: There are three significant figures in this measurement.

The uncertainty in this measurement depends on the precision of the instrument used for measurement and is not provided in the problem statement.

For Problem 2.64, the number of significant figures in each measurement would be the same as in Problem 2.63:

(a) 12.60 cm: 4 significant figures

(b) 12.6 cm: 3 significant figures

(c) 0.00000003 in.: 2 significant figures

(d) 125 ft: 3 significant figures

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Answer:

1.656 × 10^(-21) J

Explanation:

Formula for the average translational kinetic energy per atom is;

K.E = (3/2)kΔt

Where;

k is boltzmann constant = 1.38 × 10^(-23) J/K

ΔT is change in temperature = 373 - 293 = 80 K

Thus;

K.E = (3/2) × 1.38 × 10^(-23) × 80

K.E = 1.656 × 10^(-21) J

Answer:

The weight supported by the wire is 123.15 N

Explanation:

Given;

tensile stress in the wire, τ = 2 x 10⁷ Nm⁻²

diameter of the wire, d = 2.8 mm

radius of the wire, r = 1.4 mm = 1.4 x 10⁻³ m

The area of the wire is calculated as;

\(A = \pi r^2\\\\A = \pi (1.4 \times 10^{-3})^2\\\\A = 6.158 \times 10^{-6} \ m^2\)

The weight supported by the wire is calculated as;

W = F = τ x A

W = (2 x 10⁷ Nm⁻²) X (6.158 x 10⁻⁶ m²)

W = 123.15 N

Therefore, the weight supported by the wire is 123.15 N

Cuando se sumerge una piedra en un recipiente con agua, la piedra experimenta dos fuerzas: su peso hacia abajo y una fuerza de empuje hacia arriba que equivale al peso del agua desalojada por la piedra.

Esto se debe al principio de Arquímedes, que establece que un cuerpo sumergido en un fluido experimenta una fuerza de empuje igual al peso del fluido desplazado.

Cuando se sumerge la piedra en el agua, la fuerza de empuje actúa en sentido contrario a la fuerza de gravedad, lo que hace que la piedra parezca "más liviana" en el agua. La magnitud de la fuerza de empuje es igual al peso del agua desplazada por la piedra, según el principio de Arquímedes.

El principio de Arquímedes establece que un cuerpo sumergido en un fluido experimenta una fuerza de empuje dirigida hacia arriba y de magnitud igual al peso del fluido desplazado por el cuerpo. Esto ocurre porque el cuerpo desplaza una cantidad de fluido equivalente a su propio volumen.

En el caso de la piedra sumergida en agua, el volumen del agua desplazada por la piedra es igual al volumen de la piedra. La fuerza de empuje actúa hacia arriba y contrarresta parcialmente la fuerza de gravedad, lo que hace que la piedra parezca "más liviana" en el agua.

Es importante tener en cuenta que la fuerza de empuje depende del volumen del cuerpo y de la densidad del fluido en el que se sumerge. En este caso, al conocer la densidad del agua, podemos determinar la magnitud de la fuerza de empuje como igual al peso del agua desplazada por la piedra.

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Según el principio de Arquímedes, una piedra u otro objeto sumergido en agua experimentará una fuerza de empuje hacia arriba igual al peso del agua que desplaza. Esto hace que el objeto parezca más ligero en el agua que en el aire.

En física, el fenómeno que describes se llama el principio de Arquímedes. Este principio establece que un objeto sumergido en un fluido experimenta una fuerza de empuje hacia arriba que es igual al peso del fluido que desplaza. En este caso, la piedra sumergida en el agua experimentará una disminución en su peso debido a esta fuerza de empuje. Supongamos que la piedra tiene una densidad mucho mayor que el agua, por lo que se hundirá. Sin embargo, sentirá menos peso que en el aire porque el agua empuja hacia arriba contra ella con una fuerza igual al peso del agua que ha desplazado. Este efecto es por el cual los objetos parecen más ligeros cuando están en el agua.

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Without specific details about the forces and conditions involved, we cannot determine the exact change in the sum of kinetic and potential energy.

The behavior of energy will depend on the specific circumstances of the ball's motion.

To accurately determine what happened to the sum of the kinetic and potential energy of a ball moving from point A to point C, we need more information about the specific conditions and forces acting on the ball.

However, in general terms, the sum of kinetic energy and potential energy of an object can change during its motion. The law of conservation of energy states that energy cannot be created or destroyed, but it can be transformed from one form to another.

If we assume no external forces such as friction or air resistance, we can consider the following scenarios:

If the ball moves in a conservative system (such as a frictionless track), where only gravitational potential energy is involved, the sum of kinetic and potential energy will remain constant throughout the motion. As the ball moves from point A to point C, its potential energy decreases while its kinetic energy increases by an equal amount.

If external forces like friction or air resistance are present, then energy transformations can occur. In such cases, the sum of kinetic and potential energy may not remain constant.

For example, if frictional forces act against the ball's motion, some of its initial kinetic energy may be converted into other forms of energy like heat or sound, resulting in a decrease in the sum of kinetic and potential energy.

In summary, without specific details about the forces and conditions involved, we cannot determine the exact change in the sum of kinetic and potential energy. The behavior of energy will depend on the specific circumstances of the ball's motion.

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Answer:

C is your answer fam.

Explanation:

Latent heat will be consumed during the cooling process, warming the surrounding air. A material turns from a liquid to a solid by releasing heat into the environment when it freezes.

The process of freezing requires the removal of latent heat from a substance to change its state from a liquid to a solid. This means that freezing consumes latent heat from the substance itself, causing it to cool down. However, since the process also requires the substance to release this heat to the surrounding environment, the environment air is warmed up instead of being cooled down. This warming effect is due to the fact that the heat energy released during the freezing process is transferred from the substance to the surrounding air. Therefore, although the substance being frozen may become colder, the surrounding air becomes warmer, and this can have significant effects on the environment, especially in areas where freezing occurs frequently or over extended periods of time.

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Answer:

naturally occurring

Explanation:

it has to come from the earth and not be man made

Answer:

$-27

Explanation:

madison's checking account had a balance of -$12. then she wrote a check for $15 which represents madison ´s account balance now?

a check is a withdrawal from the account so subtract:

-12 - 15 = -$27

Madison's account is over drafted by $27.

Answer:

W = 96.875 N

Explanation:

For this exercise let's use the law of universal gravitation

          F = \(G \frac{m M }{r^2}\)

we substitute this force in Newton's second law

          F = m a

          G \frac{m M }{r^2} = m a

          a = \(G \frac{M}{r^2}\)

This sidewalk we will call it gravity acceleration

           g₀ = a

the weight of a body is

         W₀ = m g₀

if we change the cario of r ’= 4r

          a’=  \(G \frac{M}{r'^2 }\)

          a ’= G \frac{M}{(4r)^2 }

           a' = \(G \frac{M}{r^2} \ \frac{1}{16}\)

          a ’=  \(\frac{g_o}{16}\)

therefore the weight of the body must be

           W = m g = \(m \ \frac{g_o}{16}\)

           W = W₀ / 16

            W = 1550/16

            W = 96.875 N

The place of a north equatorial current is taken by the Monsoon Current. There is, however, an South Equatorial Current.

The South Equatorial Currents are ocean currents in the Pacific, and Atlantic, loose westerly with the trades north of latitude 22° S, it divides to form the East Africa Coastal Current, operating northward, and a south-flowing stream. correctly, equatorial-current systems comprise two westward-flowing currents approximately 600 miles

The North Equatorial Current (NEC) is a westward wind-driven current mostly detected near the equator, but the location varies from dissimilar oceans. Trade winds drive both North and South Equatorial Currents westward, thus conveying warm ocean-surface waters in that direction.

So we can conclude that The South Equatorial Current is a broad, westward flowy current that extends from the surface.

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Answer:

b

Explanation:

Answer:

16 m

Explanation:

Given:

v₀ = 4 m/s

a = 4 m/s²

t = 2 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (4 m/s) (2 s) + ½ (4 m/s²) (2 s)²

Δx = 16 m

The acceleration of the ball is 1.27 X 10⁵ m/s²

The Newtons second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object.

Given,

Mass = 145 kg

Force = 18,400 N

We need to calculate the acceleration

Using formula of acceleration(a)

a = F/m  where F= force and m= mass

Put the values in the formula,

 a = 18,400/(145 X 10⁻³) = 1.27 X 10⁵ m/s²

Therefor, the acceleration of the ball is 1.27 X 10⁵ m/s².

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Answer:

c

Explanaticon: