Fructose is an example of a ketohexose. The -hexose part of the name indicates that fructose is a Choose... that contains Choose... carbons. The keto- part of the name indicates that fructose contains Choose... functional group. Fructose can combine with glucose to form sucrose. Therefore, sucrose is a Choose... .

Answer:

1.Race

4.cobra

3.nobody

The current passing through the electrolytic cell is approximately 2.02 x 10^4 Amperes.

To calculate the current in amperes, we need to use Faraday's laws of electrolysis and the stoichiometry of the reaction.

Faraday's laws state that the amount of substance produced or consumed during electrolysis is directly proportional to the quantity of electricity passed through the cell. The relationship is given by:

Q = nF

Where Q is the electric charge in coulombs (C), n is the number of moles of substance involved in the reaction, and F is Faraday's constant, which is equal to 96,485 C/mol.

In this case, the substance being produced is Cl2, and we know the mass of Cl2 produced, which is 4.8 x 10^5 g.

First, we need to calculate the number of moles of Cl2 produced:

Molar mass of Cl2 = 35.45 g/mol

Moles of Cl2 = mass / molar mass = (4.8 x 10^5 g) / (35.45 g/mol) ≈ 1.354 x 10^4 mol

Now we can calculate the quantity of electricity passed through the cell using Faraday's laws:

Q = nF

Q = (\(1.354 x 10^4\)mol) * (96,485 C/mol)

Q ≈ 1.308 x 10^9 C

The quantity of electricity is given in coulombs. To find the current, we need to divide this value by the time in seconds.

Given that the time is 18 hours, we convert it to seconds:

Time = 18 hours * 60 minutes/hour * 60 seconds/minute

Time = 6.48 x 10^4 seconds

Finally, we can calculate the current:

Current (I) = Q / Time

I = (1.308 x 10^9 C) / (6.48 x 10^4 s)

I ≈ 2.02 x 10^4 Amperes

Therefore, the current passing through the electrolytic cell is approximately 2.02 x 10^4 Amperes.

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Two key criteria that engineers must prioritize are efficiency and safety. By emphasizing efficiency and safety during process development, engineers can create robust and reliable processes that not only maximize productivity but also prioritize the well-being of personnel and the environment.

When developing a process, engineers need to consider several important criteria. Two key criteria that engineers must prioritize are efficiency and safety.

Efficiency is crucial in process development to ensure optimal use of resources, time, and energy. Engineers strive to design processes that maximize productivity, minimize waste, and reduce costs. This involves optimizing reaction conditions, streamlining workflow, and implementing automation where possible. Efficiency considerations also extend to energy consumption, raw material utilization, and overall process sustainability.

Safety is another critical aspect that engineers must prioritize. They need to identify and mitigate potential hazards associated with the process, ensuring the safety of both personnel and the environment. This involves conducting thorough risk assessments, implementing safety protocols, and designing equipment and systems with safety features. Engineers must also consider the safe handling and storage of materials, as well as potential risks during transportation and disposal.

By emphasizing efficiency and safety during process development, engineers can create robust and reliable processes that not only maximize productivity but also prioritize the well-being of personnel and the environment.

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Answer:

answer = -0.95

Explanation:

Answer:

Explanation:

From the given information:

We are to calculate the heat (q), work done (w), Internal Energy (U), Enthalpy (H) for both cases.

Latent heat of vaporization is the heat (q) change when one mole of liquid is vaporized

Given that:

Pressure (constant) = 1 bar  = 100 kPa

The latent heat of vaporization\(\Delta H^0_{vap}\) = 2260 kJ/kg

number of moles = 1 mole  of liquid water

mass of the water = 18 g = 0.018 kg

∴

Heat (q) required  = m\(\Delta H^0_{vap}\)

q = (0.018 kg) × 2260 kJ/Kg

q = 40.68 kJ/mol

The work done required is calculated by using the equation :

w = PdV

w = 1 bar (\(V_2-V_1\) )

where;

1 bar = 10⁵ Pa

\(V_2\) = specific volume of steam = 0.0305 m³/mol

\(V_1\) = specific volume of water = 0.00001837 m³/mol

∴

w = 10⁵ Pa (  0.0305 - 0.00001837 ) m³/mol

w = 10⁵ Pa (0.03048163) m³/mol

w = 3048.163 J

w \(\simeq\) 3.05 kJ

The enthalpy of reaction (H)  is the energy measured in the system = 40.68 kJ/mol

The internal energy U = \(\Delta H - w\)

The internal energy U =  40.68 - 3.05

The internal energy U = 37.63 kJ/mol

B.

here;

the volume is constant which is given as 0

Pressure = 1 atm

Therefore;

w =PdV

w  = P(0)

w = 0

we know that:

q = U+w

q = U+0

q = U

q = U =  37.58 kJ/mol

The enthalpy change \(\Delta H = U+ w\)

ΔH = 37.58 kJ/mol + 0

ΔH = 37.58 kJ/mol

The average speeds of gas molecules in cylinders A, B, C, and D are 0.03 m/s, 0.009 m/s, 0.1 m/s, and 1.5 m/s respectively. Cylinder A contains gas that is closest to absolute zero.

Absolute zero, often known as 0 kelvin, is the lowest point on the thermodynamic temperature scale, when the enthalpy as well as entropy of a cooled ideal gas reach their lowest values.

According to international treaty, absolute zero is defined as 273.15 degrees Celsius, which really is equivalent to 459.67 degrees Fahrenheit. The average speeds of gas molecules in cylinders A, B, C, and D are 0.03 m/s, 0.009 m/s, 0.1 m/s, and 1.5 m/s respectively. Cylinder A contains gas that is closest to absolute zero.

Therefore, Cylinder A contains gas that is closest to absolute zero.

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• If somebody threw a curveball this would be a kinetic energy. because ou transfer energy to it and it move.

• we also call this energy of motion .

The red line showing the IR spectrum emitted from the earth's surface does not match the blue line showing the expected IR spectrum from a 300˚C object because:

IR spectroscopy studies Infrared (IR) light in the electromagnetic spectrum.

Sensors are used by thermal detection systems, also known as infrared detection systems, to detect radiation in the infrared region of the electromagnetic spectrum.

In order to create an electronic signal, an infrared camera must first detect the thermal energy or heat, that the scene being seen emits. After processing this signal, an image is created.

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Answer:

The energy in cabbage leaves comes from the light from the sun.

Explanation:

The plant keeps the light (in the leaves) as energy to help make it grow.

When 7.524 is rounded to 3 significant figures, it will be 7.52.

The process of changing a number to a nearby number with fewer significant digits is known as rounding.

Rounding can be done to the nearest integer, the nearest tenth, the nearest hundredth, and so on.

Here are some pointers on rounding numbers to a certain number of significant digits:If the digit following the last significant digit is less than 5, simply drop it and all following digits.

(round down)For example, 2.832 rounded to two significant digits is 2.8 since the 3 is followed by a 2 which is less than 5.

If the digit following the last significant digit is greater than 5, add 1 to the last significant digit, then drop all of the digits that follow it.

(round up)For example, 4.673 rounded to two significant digits is 4.7 since the 3 is followed by a 7 which is greater than 5.

If the digit following the last significant digit is exactly 5, the preceding digit is odd, and no other digits follow, increase the last significant digit by 1.

If the digit following the last significant digit is exactly 5, the preceding digit is even, and no other digits follow, simply leave the last significant digit alone.

For example, 2.875 rounded to two significant digits is 2.9 since the 5 is followed by an odd number, which means that the 8 should be rounded up, while 2.765 rounded to two significant digits is 2.8 since the 5 is followed by an even number, which means that the 6 should be left alone.

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Answer:

MRCORRECT has answered the question

Explanation:

Film photography is another example ofchemical reaction by light. In this example, the chemical compounds coated on the film go through a chemical reaction. ... These plates (usually made of aluminum) are coated with a photosensitive compound consisting of a polymer and a photosensitivechemical system.

The concentration of NaOH in molarity is calculated to be equal to 2.186 M.

Concentration of chemical substance expresses the amount of substance present in any mixture.

In a neutralization reaction between NaOH and HCl, the number of moles of HCl will be equal to the number of moles of NaOH.

n(NaOH) = n(HCl)

n is the number of moles.

n(HCl) = M(HCl) x V(HCl)

M is the molarity and V is the volume in liters.

n(HCl) = 0.65 M x 0.037 L = 0.02405 moles HCl

Since the number of moles of NaOH is the same as the number of moles of HCl, we can use the following formula to find the concentration of NaOH:

M(NaOH) = n(NaOH) / V(NaOH)

V(NaOH) = 11.0 mL / 1000 mL/L = 0.011 L

M(NaOH) = n(NaOH) / V(NaOH) = n(HCl) / V(NaOH)

M(NaOH) = 0.02405 moles / 0.011 L = 2.186 M

Therefore, the concentration of NaOH in molarity is 2.186 M.

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Answer:

D

Explanation:

Grinding to a powder increases the surface area of the charcoal .

The reaction of charcoal (carbon) and oxygen is sped up by grinding the charcoal into a fine powder. This is an example of increasing surface area to increase reaction rate. Option D is the answer.

Grinding charcoal into a fine powder enhances its reactivity by increasing surface area. This finer texture promotes more frequent collisions between charcoal particles and oxygen molecules, facilitating faster chemical reactions.

The heightened contact points enable efficient utilization of reactants, optimizing resource consumption. Shorter diffusion paths within smaller particles expedite reactant diffusion, aiding quicker reaction rates.

Additionally, the augmented surface area promotes efficient heat transfer, crucial in reactions involving temperature changes.

Grinding charcoal amplifies the reaction rate by maximizing interaction opportunities, accelerating the conversion of charcoal and oxygen into products.

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The classification for the following half-reactions is:

An oxidation-reduction reaction is any chemical reaction in which the oxidation number of a molecule, atom, or ion changes by gaining or losing electrons.

There are 2 kinds of half-reactions.

Let's classify the following half-reactions.

Electrons are not exchanged and Cl, the element present on both sides, has the same oxidation number, -1. This is neither oxidation nor reduction.

Mg loses 2 electrons and its oxidation number increases from 0 to +2. This is an oxidation half-reaction.

H gains 2 electrons and its oxidation number decreases from +1 to 0. This is a reduction half-reaction.

The classification for the following half-reactions is:

The question is incomplete. I believe the complete question is as follows.

Use this oxidation-reduction reaction to answer questions about half-reactions:

Mg + 2 HCl → MgCl₂ + H₂

Classify these half-reactions by typing in "O" for "oxidation half-reaction," "R" for "reduction half-reaction," and "N" for "neither."

HCI → MgCl₂

Mg → MgCl₂ + 2 e⁻

2 HCI + 2 e⁻ → H₂

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Answer:

For those who need it, the answers are N, O, R

Explanation:

After the reaction is complete, no nitrogen and no hydrogen molecules remain, and 8.00 x 1014 molecules of NH3 are produced.

In the equation, nitrogen and hydrogen react at a high temperature, in the presence of a catalyst, to produce ammonia, according to the balanced chemical equation:N2(g)+3H2(g)⟶2NH3(g)The coefficients of each molecule suggest that one molecule of nitrogen reacts with three molecules of hydrogen to create two molecules of ammonia.

So, to determine how many molecules of ammonia are produced when four nitrogen and nine hydrogen molecules are present, we must first determine which of the two reactants is the limiting reactant.

To find the limiting reactant, the number of moles of each reactant present in the equation must be determined.

Calculations:
Nitrogen (N2) molecules = 4Hence, the number of moles of N2 = 4/6.02 x 1023 mol-1 = 6.64 x 10-24 mol
Hydrogen (H2) molecules = 9Hence, the number of moles of H2 = 9/6.02 x 1023 mol-1 = 1.50 x 10-23 mol

Now we have to calculate the number of moles of NH3 produced when the number of moles of nitrogen and hydrogen are known, i.e., mole ratio of N2 and H2 is 1:3.

The mole ratio of N2 to NH3 is 1:2; thus, for every 1 mole of N2 consumed, 2 moles of NH3 are produced.
The mole ratio of H2 to NH3 is 3:2; thus, for every 3 moles of H2 consumed, 2 moles of NH3 are produced.
From these mole ratios, it can be observed that the limiting reactant is nitrogen.

Calculation for NH3 production:
Nitrogen (N2) moles = 6.64 x 10-24 moles
The mole ratio of N2 to NH3 is 1:2; therefore, moles of NH3 produced is 2 × 6.64 × 10−24 = 1.33 × 10−23 moles.

Now, to determine how many molecules of NH3 are produced, we need to convert moles to molecules.
1 mole = 6.02 x 1023 molecules
Thus, 1.33 x 10-23 moles of NH3 = 8.00 x 1014 molecules of NH3 produced.

To find the amount of each reactant remaining after the reaction is complete, we must first determine how many moles of nitrogen are consumed, then how many moles of hydrogen are consumed, and then subtract these from the initial number of moles of each reactant.

The moles of nitrogen consumed = 4 moles × 1 mole/1 mole N2 × 2 mole NH3/1 mole N2 = 8 moles NH3
The moles of hydrogen consumed = 9 moles × 2 mole NH3/3 mole H2 × 2 mole NH3/1 mole N2 = 4 moles NH3
Thus, the moles of nitrogen remaining = 6.64 × 10−24 mol – 8 × 2/3 × 6.02 × 10^23 mol-1 = 5.06 × 10−24 mol
The moles of hydrogen remaining = 1.50 × 10−23 mol – 4 × 2/3 × 6.02 × 10^23 mol-1 = 8.77 × 10−24 mol

Finally, the number of molecules of each reactant remaining can be calculated as follows:
Number of N2 molecules remaining = 5.06 × 10−24 mol × 6.02 × 10^23 molecules/mol = 3.05 × 10−1 molecules ≈ 0 molecules
Number of H2 molecules remaining = 8.77 × 10−24 mol × 6.02 × 10^23 molecules/mol = 5.28 × 10−1 molecules ≈ 0 molecules.

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In the case of a real gas when you're using Van Der Waals equation, the volume of a real gas is considered as (Vm - b), where b can be considered as the volume occupied by per mole.

Therefore, when the ideal gas law gets substituted with V = Vm  - b, it is given as : P(Vm  - b) = nRT

The presence of intermolecular attraction P was modified as follows.

\(\frac{P+a}{V^{2} } (Vm- b) = RT\\\frac{P+an^{2} }{V^{2} } (V - nb) = nRT\)

Where, Vm: molar volume of the gas

R: universal gas constant

T: temperature

P: pressure

V: volume

Thus, it is possible to reduce Van Der Waals equation to the ideal gas law as PVm = RT.

What is the significance of the Ideal gas Law?

The ideal gas law only functions as an approximation approach when high accuracy is not necessary because it describes the behaviour of ideal gasses, which there aren't any of. It is a solid introduction to the fundamental behaviour of gases and works well as a teaching tool, which is why it is taught to the majority of university students as part of any introduction to physics. In essence, the ideal gas law enables students to comprehend ideas such as the process of thermodynamic cycles, such as an engine, the reason an airbag expands, what transpires to a balloon at high altitude, and other related ideas.

Hence, Van Der Waals equation to the ideal gas law as PVm = RT.

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The sample with the largest number of oxygen atoms will be calcium perchlorate.

Since we are not looking at the number of moles, the mass of the compounds has no bearing on the number of atoms of oxygen.

Therefore, the compound with the largest number of oxygen atoms is calcium perchlorate.

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Answer:

Science is the pursuit and application of knowledge and understanding of the natural and social world following a systematic methodology based on evidence. Experiment and/or observation as benchmarks for testing hypotheses

Explanation:

Answer:

Chemical symbols are abbreviations that are used in chemistry to shorten names of chemical elements and chemical compounds.

Answer: For number 8. I think only one if not i'm so sorry also you would need 143. 0914

Explanation:

Answer:

Hello! :p

I hope this helps! Thank you so much! :)

Answer:

something that can be maintained over a period of time

Answer:

a balance between meeting today's needs.......

Explanation:

Answer:

i think it would be A

Explanation:

When you step on the scale, you might see a reading of 160 lbs, but in actuality, you might weigh 160.11111 pounds, that would be challenging to determine with a standard bathroom scale.

Describe scale.

 A fish's external body covering, specifically, consists of a tiny, flattened, stiff, and unmistakably delimited plate. B: A tiny, thin plate with mica scales that resemble the scales of a moth's wing.

A little weighing scale – what is it?

It is a compact weighing scale with an easy-to-read digital screen that is portable. It is a compact weighing scale with an easy-to-read computer indicator that is portable. It is a versatile scale that works well for weighing big goods in various locations.

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Answer:

131836.43 pounds

Explanation:

one kilogram is 2.20462 pounds. multiply 2.20462 by 59800

Answer: 131836.43

Formula: Multiply the mass value by 2.205

59800×2.205=131836.43

Answer:

The common sources of outdoor air pollution are emissions caused by combustion processes from motor vehicles, solid fuel burning and industry. Other pollution sources include smoke from bushfires, windblown dust, and biogenic emissions from vegetation (pollen and mold spores).

smog is produced when sunlight reacts with nitrogen oxides in the atmosphere. Nitrogen oxides come from car exhaust, coal power plants, and factory emissions. When sunlight hits these chemicals, they form airborne particles and ground-level ozone—or smog.

The helium sample will occupy a volume of 11.12 L if the pressure is reduced to 5.15 atm while maintaining the temperature at 20 °C.

The ability of monoprotic acids to donate one hydrogen atom or proton to their aqueous solution as opposed to diprotic acids to provide two hydrogen atoms or protons is the primary distinction between the two types of acids.

The pressure and volume of a gas are related by the following equation, known as Boyle's law:

P1V1 = P2V2

where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume, respectively.

Using this equation, we can solve for V2:

P1V1 = P2V2

V2 = (P1V1) / P2

Plugging in the values given in the problem, we get:

V2 = (5.79 atm x 9.89 L) / 5.15 atm

V2 = 11.12 L

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Approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M.

To determine the mass of glucose (C6H12O6) required to prepare a 0.215 M solution in 5000 mL, we need to use the formula:

Molarity (M) = moles of solute / volume of solution (in liters)

First, let's convert the volume of the solution from milliliters (mL) to liters (L):

5000 mL = 5000/1000 = 5 L

Now, we can rearrange the formula to solve for moles of solute:

moles of solute = Molarity (M) x volume of solution (L)

moles of solute = 0.215 M x 5 Lmoles of solute = 1.075 mol

Since glucose (C6H12O6) has a molar mass of approximately 180.16 g/mol, we can calculate the mass of glucose using the equation:

mass of solute = moles of solute x molar mass of solute

mass of glucose = 1.075 mol x 180.16 g/mol

mass of glucose = 194.0 g (rounded to three significant figures)

Therefore, approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M. It's important to note that the molar mass of glucose used in this calculation may vary slightly depending on the level of precision required.

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Taking into account the reaction stoichiometry and limiting reagent, 26.72 grams of Na₂SO₄ are formed when 22 grams of NaOH reacts with 21 grams of H₂SO₄.

In first place, the balanced reaction is:

2 NaCl + H₂SO₄ → Na₂SO₄ + 2 HCI

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

NaCl: 2 moles ×58.45 g/mole= 116.9 grams

H₂SO₄: 1 mole ×98 g/mole= 98 grams

Na₂SO₄: 1 mole ×142 g/mole= 142 grams

HCI: 2 moles ×36.45 g/mole= 72.9 grams

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 116.2 grams of NaCl reacts with 98 grams of H₂SO₄, 22 grams of NaCl reacts with how much moles of H₂SO₄?

\(mass of H_{2} SO_{4} =\frac{22 grams of NaClx98 grams of H_{2} SO_{4} }{116.2 grams of NaCl}\)

mass of H₂SO₄= 18.55 grams

But 18.55 grams of H₂SO₄ are not available, 21 grams are available. Since you have less moles than you need to react with 22 grams of NaCl, H₂SO₄ will be the limiting reagent.

The following rules of three can be applied, considering the limiting reagent: if by reaction stoichiometry 116.9 grams of NaCl form 142 grams of Na₂SO₄, 22 grams of NaCl form how much mass of Na₂SO₄?

\(mass of Na_{2}S O_{4} =\frac{22 grams of NaClx142 grams of Na_{2}S O_{4}}{116.9 grams of NaCl}\)

mass of Na₂SO₄= 26.72 grams

Then, 26.72 grams of Na₂SO₄ are formed when 22 grams of NaOH reacts with 21 grams of H₂SO₄. The correct answer is first option.

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