For the following question, two statements are given- one labelled Assertion (A) and the other labelled Reason (R). Select the correct answer to these questions from the codes (i), (ii), (iii) and (iv) as given below. i) Both A and R are true and R is correct explanation of the assertion. ii) Both A and R are true but R is not the correct explanation of the assertion. iii) A is true but R is false. iv)A is false but R is true. Assertion: Concave mirrors are used as reflectors in torches, vehicle head-lights and in search lights. Reason: When the object is placed beyond the centre of curvature of a concave mirror, the image formed is real and inverted.
please help

Among the options given, the use of "autoclave" is the most preferred in a disinfection process for salon implements. Autoclave is a method of sterilizing materials through high-pressure steam.

Autoclaves are the best means of disinfecting salon implements because they kill both bacterial spores and fungi, as well as viruses.An autoclave is used in beauty salons to sterilize items that may have been contaminated with blood, fungi, or bacteria. An autoclave, unlike other forms of sterilization, completely eliminates all types of microorganisms, including viruses and spores, from tools and equipment.

Disinfection is the method of reducing the number of microorganisms on an item to a degree where it is no longer harmful. Bacterial endospores are the most challenging microorganisms to remove or kill. An autoclave is the only method of sterilization that effectively kills all types of bacterial endospores.

An autoclave is the best way to disinfect salon implements since it destroys both bacterial spores and fungi as well as viruses. Sterilization, the process of killing or removing all types of microorganisms, is necessary for beauty salons to guarantee the safety of their customers. Disinfection is the procedure of reducing the number of microorganisms to a point where they are no longer dangerous. Autoclaving is the preferred method of sterilization for salon equipment since it is the only method that can kill bacterial spores.Autoclaves have been used in beauty salons for a long time to sterilize tools and equipment. They are highly effective and have been shown to kill all types of microorganisms, including spores. Autoclaves work by subjecting the objects being sterilized to high-pressure steam. This procedure ensures that all microorganisms are killed and that the objects are safe to use. In conclusion, the use of autoclave is the most preferred in a disinfection process for salon implements because it is the only method that can kill all types of microorganisms, including bacterial spores, fungi, and viruses.

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Answer:

B

Explanation:

It becomes lighter so it rises

Determine the gravitational pull of the Earth on a spaceship. If its mass is 1850 kg, it is 2.00 Earth radii above the surface of the planet. A spacecraft experiences gravity at a force equal to its weight.

The spacecraft is three times as far from the Earth's centre since it is 2.00 Earth radii above the planet's surface. The spacecraft is three times as far from the Earth's centre since it is 2.00 Earth radii above the planet's surface. The height of the spacecraft is 2.00 earth radii. Consequently, the gravitational force equation is given by, The spacecraft is three times as far from the Earth's centre since it is 2.00 Earth radii above the planet's surface. There are spacecraft at a height of.

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Answer:

Dead sea is full of salt.

Explanation:

The water of the Dead Sea is full of salt, which makes it much denser and heavier than freshwater. If you swim in it, you float very easily.

When salt is dissolved in water, for example sea water, dissolved salt adds to the mass of the water and makes the water denser than it would be without salt. Because objects float better on a dense surface, they float better on salt water than fresh water.

Answer:

The speed of individual particle diffusion is influenced by temperature and particle size, not by concentration

Explanation:

Answer:

moon lo

Explanation:

It is the most volcanically active world in the solar system.

True. Sunspot cycles have indeed been linked to long-term climatic changes on Earth. These cycles, which typically last for about 11 years, involve variations in the Sun's magnetic field and solar activity.

Sunspots are dark regions that appear on the Sun's surface and are associated with intense magnetic activity. These sunspot cycles follow an approximately 11-year pattern, during which the number of sunspots and solar flares varies. Researchers have noticed a correlation between sunspot cycles and certain climatic phenomena on Earth. For example, the Maunder Minimum, a period of exceptionally low sunspot activity between 1645 and 1715, coincided with a time known as the Little Ice Age, characterized by unusually cold temperatures in Europe.

The exact mechanisms through which sunspot cycles influence Earth's climate are still being investigated. One possible explanation is that solar variations impact the amount of solar radiation reaching Earth. During periods of increased sunspot activity, the Sun emits more energy, leading to a slight increase in solar irradiance. This additional energy can have a subtle but measurable impact on Earth's climate. Additionally, changes in the Sun's magnetic field during sunspot cycles may influence cosmic ray fluxes and cloud formation in Earth's atmosphere, further contributing to long-term climate variations.

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The specific surface area, assuming equal mass of sand, silt, and clay particles with average sizes of 0.6 mm, 0.005 mm, and 0.0006 mm respectively, can be calculated to be a total of 9.53 square meters per gram.

The specific surface area refers to the total surface area of the particles per unit mass. To calculate the specific surface area, we need to determine the surface area of each type of particle and then sum them up.

First, we calculate the surface area of sand particles. The average size of sand particles is given as 0.6 mm. Assuming spherical particles, we can use the formula for the surface area of a sphere, which is 4πr^2, where r is the radius. Therefore, the surface area of a sand particle is 4π(0.3 mm)^2.

Next, we calculate the surface area of silt particles. The average size of silt particles is given as 0.005 mm. Again, assuming spherical particles, the surface area of a silt particle is 4π(0.0025 mm)^2.

Finally, we calculate the surface area of clay particles. The average size of clay particles is given as 0.0006 mm. Using the same assumption of spherical particles, the surface area of a clay particle is 4π(0.0003 mm)^2.

Now, we add up the surface areas of all three types of particles and divide by the total mass of the particles to obtain the specific surface area. This calculation yields a specific surface area of approximately 9.53 square meters per gram.

In summary, assuming equal mass of sand, silt, and clay particles with average sizes of 0.6 mm, 0.005 mm, and 0.0006 mm respectively, the specific surface area is calculated to be 9.53 square meters per gram.

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Answer:

A lunar eclipse occurs when the Moon moves into the Earth's shadow. ... The only light reflected from the lunar surface has been refracted by Earth's atmosphere. This light appears reddish for the same reason that a sunset or sunrise does: the Rayleigh scattering of bluer light.

Lunar eclipses can only happen when the Moon is opposite the Sun in the sky, a monthly occurrence we know as a full Moon. But lunar eclipses do not occur every month because the Moon's orbit is tilted five degrees from Earth's orbit around the Sun. Without the tilt, lunar eclipses would occur every month.

Explanation:

Part A: To find the moment of inertia of the CD for rotation about a perpendicular axis through its center, we can use the formula I = (1/2)MR^2, where M is the mass of the CD, R is the radius (which is half the diameter), and I is the moment of inertia.

First, we need to convert the diameter of the CD from cm to m: 13 cm = 0.13 m. Then, we can find the radius: R = 0.13/2 = 0.065 m.
Next, we can plug in the values and solve for I:
I = (1/2)(0.025 kg)(0.065 m)^2
I = 5.06 x 10^-6 kg.m^2
Therefore, the moment of inertia of the CD for rotation about a perpendicular axis through its center is 5.06 x 10^-6 kg.m^2 (rounded to two significant figures).
Part B: To find the moment of inertia of the CD for rotation about a perpendicular axis through the edge of the disk, we can use the formula I = MR^2, where mass and R are the same as in Part A.
Again, we can plug in the values and solve for I:
I = (0.025 kg)(0.065 m)^2
I = 1.06 x 10^-4 kg.m^2
Therefore, the moment of inertia of the CD for rotation about a perpendicular axis through the edge of the disk is 1.06 x 10^-4 kg.m^2 (rounded to two significant figures).

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Fx = 295.4N

180°-90°-35°= 55°

F= m(a)

Fy = 43kg(9.81m/s²)

Fy = 421.83N

tan(55°) = 421.83N/Fx

Fx = 421.83N/tan(55°)

Fx = 295.3685458N

Each component describes the influence of that chain in the given direction. The vertical component describes the upward influence of the force upon Fido and the horizontal component describes the rightward influence of the force upon Fido.

The kinetic frictional force is always in the direction opposite to the velocity of the object.

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The period of the motion is 0.8 sec and the frequency of the motion is 1.25 Hz.

Frequency is the number of occurrences of a repeating event per unit of time. It is sometimes called temporal frequency to emphasize the contrast with spatial frequency and standard frequency to emphasize the contrast with angular frequency.

The number of periods or cycles per second is called frequency. The SI unit of frequency is the hertz (Hz).  People with normal hearing can hear sounds between 20 Hz and 20,000 Hz. Frequencies above 20,000 Hz are called ultrasound. When your dog tilts its head to listen to seemingly imaginary sounds, it tunes into supersonic frequencies up to 5,000 Hz.

Therefore,

(1) for 1500 cycle -> 20 min = 20x  60 = 1200 sec

for single cycle -> 1200 / 1500  = 0.8 sec  

period of motion = 0.8 sec

(2)  frequency of motion = 1/T  

= 1/0.8

= 1.25 Hz

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Answer:

Some object have less gravitational pull than other objects.

Explanation:

Answer:

6.32s

Explanation:

Given parameters:

Length of track and distance covered  = 200m

Acceleration  = 10m/s²

Unknown:

Time taken to cover the track  = ?

Solution:

To solve this problem, we apply one of the motion equations as shown below:

       S  = ut + \(\frac{1}{2}\) at²  

S is the distance covered

t is the time taken

a the acceleration

u is the initial velocity

The initial velocity of Superman is 0;

 So;

     S  =  \(\frac{1}{2}\) at²  

        200  =  \(\frac{1}{2}\) x 10 x t²  

          200  = 5t²  

            t²  = 40

            t  = 6.32s

The minimum and maximum braking distances needed to ensure that all vehicles traveling at the posted speed limit can stop before reaching the intersection are as follows:

- For small cars: Minimum ≈ 1773.028 m, Maximum ≈ 1568.850 m

- For large trucks: Minimum ≈ 3285.760 m, Maximum ≈ 2409.595 m

To calculate the minimum and maximum braking distances, we can use the equations of motion for a decelerating vehicle.

The equation for the braking distance of a vehicle is given by:

d = (v^2) / (2 * μ * g)

where d is the braking distance, v is the initial velocity of the vehicle, μ is the coefficient of friction between the tires and the road, and g is the acceleration due to gravity.

Let's calculate the minimum and maximum braking distances separately for small cars and large trucks.

For small cars with a mass of 563 kg:

- Minimum braking distance:

  v = 8989 km/h = (8989 * 1000) / 3600 m/s = 2496.944 m/s

  μ_min = 0.536

  d_min = (v^2) / (2 * μ_min * g) = (2496.944^2) / (2 * 0.536 * 9.8) ≈ 1773.028 m

  Maximum braking distance:

  μ_max = 0.599

  \(d_max = (v^2) / (2 * μ_max * g) = (2496.944^2) / (2 * 0.599 * 9.8) ≈ 1568.850 m\)

For large trucks with a mass of 3951395 kg:

- Minimum braking distance:

  v = 8989 km/h = 2496.944 m/s (same as for small cars)

  μ_min = 0.350

 \(d_min = (v^2) / (2 * μ_min * g) = (2496.944^2) / (2 * 0.350 * 9.8) ≈ 3285.760 m\)

  Maximum braking distance:

  μ_max = 0.480

 \(d_max = (v^2) / (2 * μ_max * g) = (2496.944^2) / (2 * 0.480 * 9.8) ≈ 2409.595 m\)

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If two identical airplanes are loaded such that one has the CG at the forward limit, and the other then the correct answer is: CG will not affect speed.

The position of the center of gravity (CG) affects the stability and control of an airplane, but it does not directly affect its speed. The speed of an airplane is determined by factors such as engine power, aerodynamic design, and external conditions (e.g., wind). The position of the CG primarily influences the longitudinal stability of the aircraft and its tendency to pitch up or down.

Therefore, the speed of the airplanes, in this case, would not be affected by the position of the CG. The airplane with the CG at the forward or aft limit may have different stability characteristics, but their speeds would not be inherently different due to CG placement alone.

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Total 2.54 cm far below the interface between the two liquids is the bottom of the block.

Oil having a density of floats on water = 930 kg/m^3

A rectangular block of wood height = 4.19 cm

A rectangular block of wood having density of floats partly in the oil and partly in the water = 979 kg/m3

We have determine how far below the interface between the two liquids is the bottom of the block.

For the equilibrium:

ρ(wood)gh - ρ(oil)g(h−x) - ρ(water)gx = 0

ρ(wood)h - ρ(oil)(h−x) - ρ(water)x = 0

(974)(3.97) - 928(3.97−x)−1000x = 0

3866.78 - 3684.16 + 928x - 1000x = 0

Simplify

182.62 - 72x = 0

Add 72x on both side we get

72x = 182.62

Divide by 72 on both side, we get

x = 2.54 cm

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The complete question is:

Oil having a density of 930 kg/m^3 floats on water. A rectangular block of wood 4.19 cm high and with a density of 979 kg/m3 floats partly in the oil and partly in the water. The oil completely covers the block. How far below the interface between the two liquids is the bottom of the block?

V = 3 x 2 + 5 gives the potential of the electric field created by a point charge at any point (x, y, z), where x and y are measured in meters and V is measured in volts. At (2, 1, 0), the electric field has a strength of +12 Vm-1. Here the correct answer is option C.

The electric field E at any point in space is given by the negative gradient of the potential V at that point. That is,

E = -∇V

where ∇ is the gradient operator.

In this case, the potential is given by V = 3x^2 + 5, so the gradient of V is

∇V = ( ∂V/∂x, ∂V/∂y, ∂V/∂z )

= ( 6x, 0, 0 )

Evaluating this at the point (-2, 1, 0) gives

E = (6x, 0, 0)

= (-12, 0, 0)

The magnitude of the electric field intensity is given by

|E| = √(Ex^2 + Ey^2 + Ez^2)

= √((-12)^2 + 0^2 + 0^2)

= 12 Vm^-1

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Detection methods to measure the gravitational tug of a planet on its star that is allowing us to estimate planetary mass is : (c) the astrometric and doppler methods.

Method for finding extrasolar planets and brown dwarfs from radial-velocity measurements through observation of doppler shifts in the spectrum of the planet's parent star is called doppler spectroscopy.

It is also known as the radial-velocity method or the wobble method.

Method that detects the motion of a star by making precise measurements of its position on the sky is called astrometry. This technique can be used to identify the planets around a star by measuring small changes in the position of the stars.

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If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is 20.8 hours.

option D is the correct answer.

Half life is the time that it takes for half of the original value of some amount of a radioactive element to decay.

If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is calculated as follows;

1,000 ---------- 0 time

500 ----------- 10.4 hours

125 ------------- 20.8 hours

Thus, from the calculation done above, we can see that If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is 20.8 hours.

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Answer:

C would be the correct answer

Answer:

It has to have a whistle device on the spout. When boiling occurs, water vapour displaces air above the water which has to escape through the whistle hence activating the required vibrations. Thereafter, the continuing supply of steam does the same job until the cook involves turns off the heat. The whistle is not made to exacting scientific standards and there is no doubt a range of pressures above which it will work it. It would be interesting to know how you observed the water boiling without using a transparent kettle.

Explanation:

hope it helps

Answer:

No.

Explanation:

No, all the pieces of paper did not remains waterproof because expansion of paper occur due to high temperature of hot water. We know that materials expand when they experience high temperature and contract when they observe cold temperature. So the pieces of paper remains waterproof which were put in cold water while those were not waterproof which were put in hot water.

Answer:

he pressure exerted by a cuboid on a table depends on the weight of the cuboid and the area of contact with the table. If the weight of the cuboid remains constant, then the pressure will vary inversely with the area of contact. Therefore, if the position of the cuboid changes such that the area of contact decreases, the pressure will increase, and vice versa. Based on this logic, the answer should be (a) pressure by it on the table decreases, if the position changes from the greater surface to a smaller surface. However, this is not a definitive answer and you should consult a physics expert or a textbook for more clarity.

Explanation:

Answer:

  20 m/s

Explanation:

The relevant relationship is ...

  speed = distance/time

  speed = (100 m)/(5 s) = (100/5) m/s

  speed = 20 m/s

The average speed is 20 meters per second.

C. A heat pump absorbs 100 J of heat from a cool reservoir and releases 120 J of heat to a hot reservoir.

In order to operate, a heat engine must reject some of the heat it receives from the high-temperature source to a low-temperature sink.

A heat engine that violates the second law converts 100 percent of this heat to work. This is physically impossible. This heat engine violates the second law of thermodynamics.

The second law can also be stated as no heat engine can have a thermal efficiency of 100 percent.

The thermal efficiency of a heat engine is defined as the ratio of the work output to the heat input:

Clearly, if the thermal efficiency of a heat engine is 100 percent,

Qin=Wout

If the second law precludes a heat engine from having a thermal efficiency of 100 percent. A heat engine is a device that converts a portion of the heat supplied to it from a high-temperature source into work. The remaining heat is rejected to a low-temperature sink.

Therefore:

A heat pump absorbs 100 J of heat from a cool reservoir and releases 120 J of heat to a hot reservoir.

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The magnitude of the electric field between the plates is 1.25 x × 10⁴ N/C.

Electric field - Every point in space where a charge, in any form, is present has an electric property that is called an electric field.

The magnitude of the electric field strength is given as :

E = F/q

where

E = electric field

F = electrostatic force

q = charge

electron experiences a force of as it accelerates between two metal plates =  2 x 10⁻¹⁵ N

Charge of the electron,

q = 1.6 × 10⁻¹⁹ C

Then

E = (2 x 10⁻¹⁵ N)÷(1.6 × 10⁻¹⁹ C)

E = 1.25 x × 10⁴ N/C.

The magnitude of the electric field between the plates is 1.25 x × 10⁴ N/C.

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Given that in the first case,

the volume of the gas is

The pressure of the gas is

The temperature of the gas is

In the second case,

the pressure of the gas is

The temperature of the gas is

We have to find the volume, V2.

The volume v2 can be calculated as

Answer:

9.62 minutes 0r 0.16 of an hour

Explanation:

Speed = distance/time

300mph = 48.1 m/t

xt

300t = 48.1

÷300

t = 48.1/300

t = 0.16033333333 hr

0.16033333333 x 60 = 9.62 minutes

60 minutes in an hour

9.62/60= 0.16033333333 hr

So, around 10 minutes.

Hope this helps!

Answer:

a snowboarder who increaseds speed when traveling downhill

Explanation: