Step-by-step explanation:
when a line intersects parallel lines, then the intersecting angles must be the same for each of the parallel lines.
so,
y = 139
and the angles y and x are supplementary (or a linear pair). that means together they have 180°.
that is simply because the sum of all angles around a single point on one side of a line must be 180° (because the line is like the diameter of a circle with the "rotation point" being the center, and one side of the line represents the half-circle).
therefore,
y + x = 180
139 + x = 180
x = 41
.................................................
12 mygs will cost 27, and 5 flasks will cost 30
How 1 U.S tablespoons to Fluid ounce?
1 U.S. tablespoon is equivalent to 0.5 U.S. fluid ounces. A U.S. tablespoon is a unit of volume commonly used in cooking and baking, and it is equivalent to 3 teaspoons or 0.5 fluid ounces.
A fluid ounce is also a unit of volume, but it is typically used to measure liquids, such as water or milk. One U.S. fluid ounce is equal to 2 tablespoons, so 1 U.S. tablespoon is half of a U.S. fluid ounce. It is important to use the correct unit of measurement when following a recipe or measuring ingredients to ensure that the final result turns out as expected.
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what is h (kj mol-1) for the reaction if5(g) if3(g) f2(g) given the reactions if(g) f2(g) if3(g) h = -390 kj if(g) 2f2(g) if5(g) h = -745 kj
To find the enthalpy change (ΔH) for the reaction, we can use the concept of Hess's Law, which states that the enthalpy change of a reaction is independent of the pathway taken and depends only on the initial and final states.
Given the reactions:
1) I2(g) + F2(g) -> 2IF(g) ΔH = -390 kJ/mol
2) I2(g) + 3F2(g) -> 2IF5(g) ΔH = -745 kJ/mol
We can see that the reaction we want to determine the enthalpy change for (5IF3(g) -> 5IF(g) + F2(g)) can be obtained by combining these two reactions. By manipulating the reactions, we can cancel out the common species (I2(g)) to get the desired reaction.
If we double reaction 1 and subtract reaction 2 from it, we obtain:
2(I2(g) + F2(g)) - (I2(g) + 3F2(g)) -> 2IF(g) + F2(g)
This simplifies to:
I2(g) - F2(g) -> IF(g) + F2(g)
Now we have the desired reaction with the enthalpy change equal to the difference between the enthalpy changes of the reactions involved:
ΔH = ΔH(reaction 1) - ΔH(reaction 2)
ΔH = (-390 kJ/mol) - (-745 kJ/mol)
ΔH = 355 kJ/mol
Therefore, the enthalpy change for the reaction 5IF3(g) -> 5IF(g) + F2(g) is 355 kJ/mol.
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Perform the operation. (-7x^2 - 10x - 6) + (-3x^2 + x)
Answer:
-9x^2-9x-6
Step-by-step explanation:
You add like terms together only
-10x2(squared) - 9x - 6
Remove parentheses
Calculate the work done during the reversible isothermal compression of 0.05 mol of an ideal gas at an initial pressure and volume of 2.5 atm and 12 L respectively. Calculate the workdone for this process if there was a pressure change of 15 atm
The work done during the reversible isothermal compression of the gas is approximately -119.63 Joules. The negative sign indicates that work is done on the system during compression.
To calculate the work done during the reversible isothermal compression of an ideal gas, we can use the formula:
Work = -nRT ln(Vf/Vi)
Where:
- n is the number of moles of the gas
- R is the ideal gas constant (8.314 J/(mol·K))
- T is the temperature in Kelvin
- Vi is the initial volume
- Vf is the final volume
Given:
n = 0.05 mol
R = 8.314 J/(mol·K)
Vi = 12 L
To calculate the work done for the given pressure change, we need to find the final volume (Vf). We can use the ideal gas law to relate pressure, volume, and moles:
PV = nRT
Initial pressure (Pi) = 2.5 atm
Final pressure (Pf) = Pi + pressure change = 2.5 atm + 15 atm = 17.5 atm
Using the ideal gas law, we can solve for Vf:
Vf = (nRT) / Pf
Vf = (0.05 mol * 8.314 J/(mol·K) * T) / (17.5 atm)
Since the process is isothermal, the temperature remains constant. Let's assume it is 298 K:
Vf = (0.05 mol * 8.314 J/(mol·K) * 298 K) / (17.5 atm)
Vf ≈ 8.483 L
Now we can calculate the work done using the equation:
Work = -nRT ln(Vf/Vi)
Work = -(0.05 mol * 8.314 J/(mol·K) * 298 K) * ln(8.483 L / 12 L)
Work = -(0.05 mol * 8.314 J/(mol·K) * 298 K) * ln(8.483 L / 12 L)
Calculating the expression:
Work = -(0.05 mol * 8.314 J/(mol·K) * 298 K) * ln(0.7069)
Using a scientific calculator or math software to evaluate the natural logarithm:
Work ≈ -119.63 J
Therefore, the work done during the reversible isothermal compression of the gas is approximately -119.63 Joules. The negative sign indicates that work is done on the system during compression.
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Sara spends $x on pens which cost $2.50 each.
She also spends $(x - 14.50) on pencils which cost $0.50 each.
The total of the number of pens and the number of pencils is 19.
Write down and solve an equation in x.
in each of problems 4 through 9, find the general solution of the given differential equation. in problems 9, g is an arbitrary continuous function.
The general solution of the associated homogeneous differential equation \(y'' + 2y' + 2y = 0\) is given by
\(y_h = c₁ e^(-x) cos(x) + c₂ e^(-x) sin(x)\)
We can use the method of undetermined coefficients or variation of parameters to find y_p, depending on the form of g(x).
For each of problems 4 through 9, we need to find the general solution of the given differential equation.
Problem:
\(4y'' + 4y' + 13y = 0\)
By solving the auxiliary equation \(r² + 4r + 13 = 0,\)
we get
\(r = -2 + 3i, -2 - 3i.\)
Hence, the general solution is
\(y = c₁ e^(-2x) cos(3x) + c₂ e^(-2x) sin(3x)\)
Problem: \(5y'' + 4y' + 3y = 0\)
By solving the auxiliary equation \(r² + 4r + 3 = 0,\)
we get
\(r = -2 + √1, -2 - √1.\)
Hence, the general solution is
\(y = c₁ e^(-x) + c₂ e^(-3x)\)
Problem \(6y'' + y = 0\)
By solving the auxiliary equation \(r² + 1 = 0\),
we get
r = -i, i.
Hence, the general solution is
\(y = c₁ cos(x) + c₂ sin(x)\)
Problem\(7y'' - 3y' - 4y = 0\)
By solving the auxiliary equation \(r² - 3r - 4 = 0\),
we get
r = 4, -1.
Hence, the general solution is
\(y = c₁ e^(4x) + c₂ e^(-x)\)
Problem \(8y'' + 3y' + 2y = 0\)
By solving the auxiliary equation \(r² + 3r + 2 = 0,\)
we get
r = -1, -2.
Hence, the general solution is
\(y = c₁ e^(-x) + c₂ e^(-2x)\)
Problem:
\(9y'' + 2y' + 2y = g(x)\)
This is a non-homogeneous differential equation.
The general solution of the associated homogeneous differential equation \(y'' + 2y' + 2y = 0\) is given by
\(y_h = c₁ e^(-x) cos(x) + c₂ e^(-x) sin(x)\)
For the non-homogeneous equation, the general solution is given by
\(y = y_h + y_p\)
Where y_p is any particular solution of the non-homogeneous differential equation.
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Let W= the width of the rectangle, in inches. Write the length of the rectangle, L, in tes of W.
The length of the rectangle, L, is equal to W multiplied by a certain factor or ratio, representing the relationship between the length and width.
To express the length of the rectangle, L, in terms of the width, W, we can establish a relationship between the two dimensions.
Let's assume the length is twice the width. Therefore, we can write:
L = 2W
This equation states that the length (L) is equal to two times the width (W). The length is directly proportional to the width in this scenario.
Alternatively, if we assume the length is three times the width, we can write:
L = 3W
In this case, the length (L) is equal to three times the width (W).
The relationship between the length and width can vary depending on the specific conditions or requirements of the rectangle. However, by establishing an equation that relates the length and width, we can express the length in terms of the width.
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Sasha recorded the height and weight of all of the girls in her physical education course.
Weight Height
99 61
104 61
110 62
133 64
130 65
142 68
146 66
153 67
184 69
185 70
What is the correlation coefficient for the data
Answer:
0.9156
Step-by-step explanation:
In the picture attached, the data is plotted (I made it using MS Excel, you can use similar programmes or a calculator).
The line that best correlates the data has the following equation:
y = 0.1037x + 50.922
and its correlation coefficient is:
R² = 0.9156
Answer:
Correlation coefficient, r = 0.957
Step-by-step explanation:
Let y represent the weight
Let x represent the height
y x x² y² xy
99 61 3721 9801 6039
104 61 3721 10816 6344
110 62 3844 12100 6820
133 64 4096 17689 8512
130 65 4225 16900 8550
142 68 4629 20169 9656
146 66 4356 21316 9636
153 67 4489 23409 10251
184 69 4761 33856 12696
185 70 4900 34225 12950
\(\sum y = 1386\), \(\sum x = 653\), \(\sum x^2 = 42737\), \(\sum y^2 = 200276\), \(\sum xy = 91454\)
Correlation coefficient formula,
\(r = \frac{n \sum xy - \sum x \sum y}{\sqrt{(n \sum x^2 - (\sum x)^2) (n \sum y^2 - (\sum y)^2)} } \\r = \frac{10* 91454 - 653*1386}{\sqrt{(10* 42737 - (653)^2) (10* 200276 - (1386)^2)} }\)
Correlation coefficient, r = 0.957
Divide Rs 8100 for three persons in the proportion of 2:3:4
Step-by-step explanation:
Money = Rs 1800
Ratio = 2:3:4
1st Person = 2x
2nd Person = 3x
3rd Person = 4x
X = ?
2x + 3x + 4x = 1800
9x = 1800
X = 200
1st Person = 2x = 2×200 = Rs 400
2nd Person = 3x = 3×200 = Rs 600
3rd Person = 4x = 4×200 = Rs 800
Fill in the blank with the correct form of the verb. Be careful to watch for time cues in the sentence to be able to determine the correct form to use.
Yo quiero que ella _____ (hablar) español.
habla
hablará
hable
hablaba
Enter the ratio as a fraction in lowest terms (no decimals). 1.0 cm to 1.5 cm
Let's write the ration as a fraction:
1 cm to 1.5 cm
Ratio : 1/1.5 but we need to write it without decimals,
1/1.5 = 2/3 (multiplying by 2 numerator and denominator)
K, the correct answer is 2/3
help again <3 ty i will very much appreciate it
Answer:
5√3 is the simplified radical expression.
The function f(x) is graphed below. Determine whether the degree of the
function is even or odd and whether the function itself is even or odd.
Answers
A. f(x) has an even degree, but not an even function
B. f(x) has an even degree and is an even function
C. f(x) has an odd degree, but not an odd function
D. f(x) has an odd degree and is an odd function
D. f(x) has an odd degree and is an odd function
How to determine the type and the degree of the functionFrom the question, we have the following parameters that can be used in our computation:
The graph
A function is said to be odd if the function is symmetrical about the origin
Using the above as a guide, we have the following:
The graph is an odd function
This is because it is symmetrical about the origin
Also, the function has an odd degree
This is because the multiplicity of the zero is 3
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Find a set of parametric equations for the rectangular equation that satisfies the given condition. (Enter your answers as a comma-separated list.) y = 3x - 4, t = 0 at the point (4, 8)
To find the set of parametric equations for the rectangular equation y = 3x - 4, we need to express x and y in terms of a parameter, say t. Let us assume that t = 0 at the point (4, 8).
First, we can write x in terms of t as x = 4 + at, where a is some constant. To find the value of a, we can use the fact that y = 3x - 4. Substituting x = 4 + at in this equation, we get y = 3(4 + at) - 4 = 12 + 3at. So, the set of parametric equations for y and x are:
x = 4 + at
y = 12 + 3at
Note that these parametric equations are not unique. We could have chosen a different parameterization, say t = 1 at the point (4,8), and obtained a different set of parametric equations. However, the given condition specifies the starting point and therefore determines the parameterization.
In summary, we can find a set of parametric equations for a rectangular equation by expressing x and y in terms of a parameter, using the given condition to determine the starting point, and choosing a suitable parameterization.
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The plant runs 80 hours a week. A day has 24 hours. How many days does the plant run each week? ( hint: include the reminder.)
Answer:
Step-by-step explanation:
7?
Answer:
3 days and 8 hours
Step-by-step explanation:
80 ÷ 24 = 3.3333333333 (you get what i mean)
3 days and .3333333333 more of a day
24 ÷ 3 = 8
8 hours
3 days and eight hours
HOPE THIS HELPS
PLZZ MARK BRAINLIEST
Rectangle ABCD has a perimeter of 22 units. The coordinates of the rectangle's vertices are A(-4,5), B(3,x), and D(-4,x). Which could be the value of x
Through the given information in the question, the value of x could be 12.
What is the perimeter of a rectangle?The perimeter of a rectangle is the total distance around the outside of the rectangle. It is calculated by adding together the length of all four sides of the rectangle. If the length of the rectangle is denoted by 'l' and the width is denoted by 'w', then the formula for the perimeter (P) of the rectangle is:
P = 2l + 2w
Alternatively, the formula can also be written as:
P = 2(l + w)
The perimeter of a rectangle is given by the sum of the lengths of all four sides. Therefore, we can write:
AB + BC + CD + DA = 22
We know that AB = CD = 9 since they are opposite sides of the rectangle. We also know that DA = BC = x - 5, since they are the other two sides of the rectangle.
Substituting these values into the perimeter equation, we get:
9 + x - 5 + 9 + x - 5 = 22
Simplifying the equation, we get:
2x - 2 = 22
2x = 24
x = 12
Therefore, the value of x could be 12.
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Suppose that the position of one particle at time t isgiven by the equations x1 andy1. Meanwhile, the position of a secondparticle is given by the equations x2 andy2.
x1 = 3sin(t)
y1 = 2cos(t)
0 ≤ t ≤ 2π
x2 = -3 +cos(t)
y2 = 1 + sin(t)
0 ≤ t ≤ 2π
(a) Graph the paths of both particles. (Do this on paper. Yourinstructor may ask you to turn in this work.) How many points ofintersection are there?
1_____
(b) Find the collision point, where the particles are atthe same place at the same time.
( 2_____, 3____)
(c) If the x-coordinate of the second particle is given byx2 = 3 +cos(t) instead, is there still a collision? OYes ONo
The paths of two particles are described by parametric equations. The first particle follows a circular path, while the second particle follows a path with both circular and linear components.
We need to graph the paths and determine the number of points of intersection.
Additionally, we need to find the collision point where the particles occupy the same position at the same time.
Lastly, we need to determine if there is a collision when the x-coordinate of the second particle is modified.
(a) To graph the paths of both particles, we plot the parametric equations x1 = 3sin(t), y1 = 2cos(t) and x2 = -3 + cos(t), y2 = 1 + sin(t) on a coordinate plane for 0 ≤ t ≤ 2π. The paths of the particles will be represented by curves. By analyzing the graph, we can count the number of points of intersection.
(b) To find the collision point, we need to find the values of t where x1 = x2 and y1 = y2 simultaneously. By setting 3sin(t) = -3 + cos(t) and 2cos(t) = 1 + sin(t), we can solve for t. The obtained value(s) of t will give us the collision point (x, y) where the particles occupy the same position at the same time.
(c) If the x-coordinate of the second particle is modified to x2 = 3 + cos(t), we need to repeat the process of finding the collision point. By setting 3sin(t) = 3 + cos(t) and 2cos(t) = 1 + sin(t), we solve for t. Depending on the solution(s) of t, we can determine if there is still a collision or not.
Please note that since this question involves graphing and solving equations, it is best to draw the graphs and solve the equations visually or using numerical methods to obtain specific values.
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For a given event, what is the result of dividing the number of successful
outcomes by the number of possible outcomes?
A. Outcomes
ОО
B. Probability
h
c. Sample space
D. Empirical data
Answer: B. Probability
For example, let's say you want to know the probability of flipping tails.
There's 1 way to get tails out of 2 sides total. So 1/2 = 0.5 is the probability of flipping tails.
We define "success" as "getting tails".
Find the work done by a force of 3 pounds acting in the direction 2i + j in moving an object 2 feet from (0,0) to (0.2).
I need a step by step solution. Can someone please break this problem into simple steps leading to the answer (6•sqrt{5})/5 foot-pounds?
The work done by the force of 3 pounds acting in the direction 2i+j in moving an object 2 feet from (0,0) to (0.2) is (6•√5)/5 foot-pounds.
To find the work done by the given force, we need to first calculate the displacement and then use the formula for work done.
Calculate displacement:
The object moves from (0,0) to (0.2), so the displacement is:
Δr = (0.2 - 0)i + 0j = 0.2i
Calculate the magnitude of displacement:
|Δr| = √(0.2²) = √0.04 = 0.2
Calculate the unit vector in the direction of displacement:
uΔr = Δr/|Δr| = (0.2i)/0.2 = i
Calculate the angle between the force and the displacement:
θ = cos⁻¹[(2i+j)•i/(|2i+j||i|)] = cos⁻¹(2/√5)
Calculate the work done:
W = F•d•cosθ
= (3 pounds)•(0.2 feet)•cos(cos⁻¹(2/√5))
= (3•0.2•2/√5) foot-pounds
= (6/√5) foot-pounds
= (6•√5)/5 foot-pounds
Therefore, the work done by the force of 3 pounds acting in the direction 2i+j in moving an object 2 feet from (0,0) to (0.2) is (6•√5)/5 foot-pounds.
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A bee flies at 10 feet per second directly to a flowerbed from its hive. the bee stays at the flowerbed 12 minutes,and the flies directly back to the the hive 6 feet per second.it is away from the hive for a total of 16 minutes
The equation for distance of the flowerbed from the hive.
(d/10)+(d/6) = 240
The distance of the flowerbed from the hive = 900ft
How do you find speed and distance?To calculate speed, divide the journey's distance by the time it took to travel, so speed = distance divided by time. Divide the distance by the speed to get the time. Multiply speed by time to find the distance. These equations can be simplified to s=d/t, where s represents speed, d is distance, and t is time.
According to the given information:Let the distance of flower bed from hive to be = d
Time the bee stays at the flower bed = 11
Time the bee is away from the hive = 15
Time the bed was flying to the flower bed and back to the hive will be;
15 -11=4 minutes--------------changes to seconds by multiplying by 60
=4*60
=240 seconds
Formular for time is Distance/speed
Time of fright=240 seconds
Form expression for time of flying;
Time for flying from hive to flowerbed= d/10ft/s
Time for flying from flower bed to Hive= d/6ft/s
Solving these two equation we get:
A. (d/10)+(d/6) = 240
B. distance of the flowerbed from the hive:
(8d/30) = 240
8d = 7200
d = 7200/8
d = 900
The distance of the flowerbed from the hive = 900ft
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I understand that the question you are looking for is:
A bee flies at 10 feet per second directly to a flowerbed from its hive. The bee stays at the flowerbed for 11 minutes, and then flies directly back to the hive at 6 feet per second. It is away from the hive for a total of 15 minutes. a. What equation can you use to find the distance of the flowerbed from the hive?
a. Write the equation. Let d be the distance of the flowerbed from the hive.
b. How far is the flowerbed from the hive?
A bag contains 15 marbles: 10 red, and 5 white. Furthermore, every marble is labelled: each number in the set {1,2,..., 15} appears exactly once. Suppose four marbles are to be selected from the bag. (i) How many different selections of size 4 are possible? (ii) How many selections consist only of red marbles? (iii) How many selections of size 4 consist of 2 red and 2 white marbles?
Question 1:
In order to solve this question, we use the combination formula. We can select 4 marbles from 15 marbles and hence the solution is given by:
\($${{15}\choose{4}} = \frac{15!}{4!11!} = 1365$$\)
Question 2:
In order to solve this question, we can select 4 red marbles from 10 marbles of red color. Hence the solution is given by:
\($${{10}\choose{4}} = \frac{10!}{4!6!} = 210$$\)
Question 3:
In order to solve this question, we can select 2 red marbles from 10 red marbles and 2 white marbles from 5 white marbles. Hence the solution is given by:
\($${{10}\choose{2}} \times {{5}\choose{2}}= \frac{10!}{2!8!} \times \frac{5!}{2!3!}= 45 \times 10 = 450$$\)
Hence the answers are as follows: (i) 1365 (ii) 210 (iii) 450
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customers arrive at the wendy's drive-thru at random, at an average rate of 17 per hour. during a given hour, what is the probability that 10 or fewer customers will arrive at the drive-thru?
To solve this problem, we can use the Poisson distribution formula.
The formula is P(X ≤ 10) = e^(-λ) ∑(k=0 to 10) (λ^k / k!) where λ is the average rate of customers per hour, which is 17.
Substituting the values,
we get P(X ≤ 10) = e^(-17) ∑(k=0 to 10) (17^k / k!)
Using a calculator, we get P(X ≤ 10) = 0.2588 or 25.88%. This means that during a given hour, the probability that 10 or fewer customers will arrive at the drive-thru is 25.88%.
It is important to note that the Poisson distribution assumes that the arrival rate is random and constant. In reality, there may be factors that affect the arrival rate, such as time of day, day of the week, and weather conditions. However, the Poisson distribution can still be a useful tool in predicting customer arrivals and managing staffing levels.
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I need help please it’s one more question and I’m done with it please help me
Answer:
C
Step-by-step explanation:
If the ratio of people per tower is ~20.83, then multiply that by 624, which equals 13,000.
Complete the proportions in the answer choices to find which one would give you 13,000.
Choose the number sentence whose product is 5.85.
A. 1.7 x 3.5
B. 26 x 2.25
C. 4.5 x 2.3
D. 1.3 x 4.5
Answer:
D
1.3 times 4.5 is 5.85
Answer:
D
Step-by-step explanation:
BRAINLYEST please
help please: at the beginning of spring aaliyah planted a small sunflower in her backyard when it was first planted the sunflower was 10 inches tall the sunflower then began to grow at the rate of 0.5 inches per week how tall would the sunflower be after 7 weeks how tall would the sunflower be after W weeks
need help with this question
Answer:
I think it's c sorry if im wrong
Find the radius of Circle G Below. Round your answer to the nearest hundredth.
Answer:.
Step-by-step explanation
first thing is you are going to have to add
joe then nuts, then boom. You have your answer
A retailer is selling a wallet at a profit of 65% on the cost price. During a sale, the supplier decides to give the retailer a discount of 20%. As a result, the retailer reduces the normal selling price by 15%. Find the profit from selling 10 wallets as a percentage of the discounted cost price the retailer paid for the wallets?
The profit from selling 10 wallets is approximately 6.06% of the discounted cost price the retailer paid for the wallets.
To find the profit from selling 10 wallets as a percentage of the discounted cost price, we'll follow these steps:
Let's assume the cost price of one wallet is 'x' dollars.
The retailer sells the wallet at a profit of 65% on the cost price. Therefore, the selling price of one wallet is (cost price + 65% of cost price):
Selling Price = x + 0.65x = 1.65x
The supplier gives the retailer a discount of 20%. So, the retailer pays 80% of the selling price to the supplier. The discounted cost price per wallet is:
Discounted Cost Price = 80% of Selling Price = 0.8 × 1.65x = 1.32x
The retailer further reduces the normal selling price by 15%. The discounted selling price per wallet is:
Discounted Selling Price = Selling Price - 15% of Selling Price = 1.65x - 0.15 × 1.65x = 1.4x
To calculate the profit, we subtract the discounted cost price from the discounted selling price:
Profit per Wallet = Discounted Selling Price - Discounted Cost Price = 1.4x - 1.32x = 0.08x
Now, to find the profit from selling 10 wallets, we multiply the profit per wallet by the number of wallets:
Total Profit = Profit per Wallet × Number of Wallets = 0.08x × 10 = 0.8x
Finally, we calculate the profit as a percentage of the discounted cost price:
Profit Percentage = (Total Profit / (Discounted Cost Price × Number of Wallets)) × 100
Profit Percentage = (0.8x / (1.32x × 10)) × 100 = (0.8 / 13.2) × 100 ≈ 6.06%
Therefore, the profit from selling 10 wallets is approximately 6.06% of the discounted cost price the retailer paid for the wallets.
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Which statement is true when comparing how a student would complete the solution for the linear equation -2x + 3 = 6 to how the student would complete the solution for the linear inequality -2x + 3 < 6?
Completing the solution for the equation is the same as completing the solution for the inequality. The student would divide both sides by -2 in either case.
Completing the solution for the equation is the same as completing the solution for the inequality. The student would divide both sides by -2 in either case.
Completing the solution for the equation is the same as completing the solution for the inequality. The student would multiply both sides by -2 in either case.
Completing the solution for the equation is the same as completing the solution for the inequality. The student would multiply both sides by -2 in either case.
Completing the solution for the equation is not the same as completing the solution for the inequality. The student would divide by -2 to complete the solution for the equation and would divide by -2 and change the less than sign for the inequality to greater than.
Completing the solution for the equation is not the same as completing the solution for the inequality. The student would divide by -2 to complete the solution for the equation and would divide by -2 and change the less than sign for the inequality to greater than.
Completing the solution for the equation is not the same as completing the solution for the inequality. The student would multiply by -2 to complete the solution for the equation and would multiply by -2 and change the less than sign for the inequality to greater than.
Answer:
i just know
Step-by-step explanation:
-2x+3=6:
x= -3/2
-2x + 3 < 6:
x > −3/2