x = -5 + 5√3
Step-by-step explanation:
A = ℓ × w
50 = (x + 10) × x
50 = x² + 10x
x² + 10x - 50 = 0
a = 1b = 10c = -50x = [-b ± √(b² - 4ac)] / 2a
x = [-10 ± √(10² - 4(1)(-50))] / 2(1)
x = [-10 ± √(100 - (-200))]/2
x = [-10 ± √300]/2
x = [-10 ± 10√3]/2
x = [-5 ± 5√3]
because x is a unit of length, it is positive
x = -5 + 5√3
a brother and sister sold magazine subscriptions for a school fundraiser. the sister sold 5 fewer than twice the number of subscriptions her brother sold. they sold a total of 52 subscriptions.
how many subscriptions did the brother and sister each sell?
= a fx The function f is defined by f (x) = 50-3^x. The function g is defined by g(x) = a · Here are graphs of f and g. y مه f Х 1. How does a compare to 50? Explain how you know. 2. How does b compare to 3? Explain how you know. Edit View Insert Format Tools Table 12pt Paragraph В I U A o Tv :
Answer:
Step-by-step explanation:
a, compares to 50 beacuse a means the staying point ; slope, so that’s why it starts at 50.
b, compares to 3 beacuse that is the y-intercept
round to ten-thousandth (cut off says quadrant 1, I couldnt fit it all in.)
sin(A)=2/5
trig identity:
* sin^2(A)+cos^2(A)=1
* tan(A)=sin(A)/cos(A)
find: tan(A)
\(\begin{gathered} \sin ^2(A)+\cos ^2(A)=1 \\ (\frac{2}{5})^2+\cos ^2(A)=1 \\ \cos ^2(A)=1-\frac{4}{25} \\ \cos ^2(A)=\frac{21}{25} \\ \cos (A)=\sqrt[]{\frac{21}{25}}=\frac{\sqrt[]{21}}{5} \end{gathered}\)\(\begin{gathered} \tan (A)=\frac{\sin (A)}{\cos (A)} \\ \tan (A)=\frac{\frac{2}{5}}{\frac{\sqrt[]{21}}{5}} \\ \tan (A)=\frac{2}{\sqrt[]{21}}\approx0.436 \end{gathered}\)Helppp will mark brainliestttt
The set of ordered pairs represents a function because every input has only one corresponding output.
How many pairs of parallel lines are in the flipped shape
Answer: 5
Step-by-step explanation:
What is the measure of angle D?
Answer:
52
Step-by-step explanation:
Since the sum of interior angles in a quadrilateral is 360°, you have to subrtact all those numbers from 360° in order to get angle D. What I mean is:
360 - (128+126+54)
360 - 308
52
Answer:
52°
Step-by-step explanation:
The trapezoid is a closed figure, meaning all the angles must equal 360°.
1. Set up the equation
128° + 126° + 54° + ∠D = 360°
2. Solve for ∠D
360 - 128- 126- 54 = 52
∠D = 52°
You can also solve this by knowing that in a trapezoid:
∠A + ∠D = 180° and ∠B + ∠C = 180°
1. Set up the equation
128 + ∠D = 180°
2. Solve
180 - 128 = 52
∠D = 52°
Show that the process X(t):=e t/2
cos(W(t)),0≤t≤T, is a martingale w.r.t. any filtration for Brownian motion and represent it as an Itô process on any time interval [0,T],T>0.
A stochastic process X(t) is called a martingale if the expected value of X(t) given all information available up to and including time s is equal to the value of X(s).
Thus, to show that the process X(t):=e^(t/2)cos(W(t)), 0 ≤ t ≤ T is a martingale w.r.t. any filtration for Brownian motion, we need to prove that E(X(t)|F_s) = X(s), where F_s is the sigma-algebra of all events up to time s.
As X(t) is of the form e^(t/2)cos(W(t)), we can use Itô's lemma to obtain the differential form:dX = e^(t/2)cos(W(t))dW - 1/2 e^(t/2)sin(W(t))dt
Taking the expectation on both sides of this equation gives:E(dX) = E(e^(t/2)cos(W(t))dW) - 1/2 E(e^(t/2)sin(W(t))dt)Now, as E(dW) = 0 and E(dW^2) = dt, the first term of the right-hand side vanishes.
For the second term, we can use the fact that sin(W(t)) is independent of F_s and therefore can be taken outside the conditional expectation:
E(dX) = - 1/2 E(e^(t/2)sin(W(t)))dt = 0Since dX is zero-mean, it follows that X(t) is a martingale w.r.t. any filtration for Brownian motion.
Now, let's represent X(t) as an Itô process on the interval [0,T]. Applying Itô's lemma to X(t) gives:
dX = e^(t/2)cos(W(t))dW - 1/2 e^(t/2)sin(W(t))dt= dM + 1/2 e^(t/2)sin(W(t))dt
where M is a martingale with M(0) = 0.
Thus, X(t) can be represented as an Itô process on [0,T] of the form:
X(t) = M(t) + ∫₀ᵗ 1/2 e^(s/2)sin(W(s))ds
Hence, we have shown that X(t) is a martingale w.r.t. any filtration for Brownian motion and represented it as an Itô process on any time interval [0,T], T > 0.
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What is the name of the green segment in the hyperbola below
The Length of the conjugate axis is equal to 2b. The transverse axis is an essential feature of a hyperbola, as it determines the overall shape of the hyperbola.
In a hyperbola, the name of the green segment is called the transverse axis. The transverse axis is the longest distance between any two points on the hyperbola, and it passes through the center of the hyperbola. It divides the hyperbola into two separate parts called branches.
The transverse axis of a hyperbola lies along the major axis, which is perpendicular to the minor axis. Therefore, it is also sometimes called the major axis.
The other axis of a hyperbola is called the conjugate axis or minor axis. It is perpendicular to the transverse axis and passes through the center of the hyperbola. The length of the conjugate axis is usually shorter than the transverse axis.In the hyperbola above, the green segment is the transverse axis, and it is represented by the letters "2a". Therefore, the length of the transverse axis is equal to 2a.
The blue segment is the conjugate axis, and it is represented by the letters "2b".
Therefore, the length of the conjugate axis is equal to 2b.The transverse axis is an essential feature of a hyperbola, as it determines the overall shape of the hyperbola. In particular, the distance between the two branches of the hyperbola is determined by the length of the transverse axis.
If the transverse axis is longer, then the branches of the hyperbola will be further apart, and the hyperbola will look more stretched out. Conversely, if the transverse axis is shorter, then the branches of the hyperbola will be closer together, and the hyperbola will look more compressed.
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22 The five-number summary for scores on a statistics exam is: 35, 68, 77, 83 and 97. In all, 196 students took this exam About how many students had scores between 68 and 83? a. 98 b. 39 c. 6
d. 148 e.49
The approximate number of students with Scores between 68 and 83 is 98.Answer: a. 98
The five-number summary for scores on a statistics exam is: 35, 68, 77, 83 and 97. In all, 196 students took this exam About how many students had scores between 68 and 83?
The five-number summary consists of the minimum value, the first quartile, the median, the third quartile, and the maximum value.
The interquartile range is the difference between the third and first quartiles. Interquartile range (IQR) = Q3 – Q1, where Q3 is the third quartile and Q1 is the first quartile. The 5-number summary for scores on a statistics exam is given below:
Minimum value = 35
First quartile Q1 = 68
Median = 77
Third quartile Q3 = 83
Maximum value = 97
The interval 68–83 is the range between Q1 and Q3.
Thus, it is the interquartile range.
The interquartile range is calculated as follows:IQR = Q3 – Q1 = 83 – 68 = 15
The interquartile range of the scores between 68 and 83 is 15. Therefore, the number of students with scores between 68 and 83 is roughly half of the total number of students. 196/2 = 98.
Thus, the approximate number of students with scores between 68 and 83 is 98.Answer: a. 98
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Su Li wants to place a protective covering over a rectangular flower bed that measures 3.2 meters by 4.3 meters. How many square meters of covering will she need
The formula A = l w is used to calculate the area of a rectangle, which is 13.76 square meters. Su Li needs 13.76 square meters of covering for the rectangular flower bed.
The formula to calculate the area of a rectangle is given by:A = l × w Where, A = Area of rectangle l = length of rectangle w = width of rectangle Given that the rectangular flower bed measures 3.2 meters by 4.3 meters. So,Length of rectangular flower bed, l = 3.2 meters Width of rectangular flower bed, w = 4.3 meters Using the above formula, we can find the area of the rectangular flower bed. A = l × w= 3.2 meters × 4.3 meters= 13.76 square meters Therefore, Su Li will need 13.76 square meters of covering for the rectangular flower bed. Hence, the answer is 13.76 square meters of covering.
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The following frequency distribution analyzes the scores on a math test. Find the class boundaries of scores interval 40-59Scores| Number of Students40-59| 260-75| 476-82| 683-94| 1595-99| 5A. 39.5, 59.5B. 39.5, 58.5C. 40.5, 58.5D. 40.5, 59.5
The class boundaries for the scores interval 40-59 are 39.5 and 59.5.b The correct answer is A.
The numbers used to demarcate classes are called class boundaries. The difference between a class's upper class limit and its lower class limit indicates the extent of the gap between classes.
The class boundaries are found by adding/subtracting 0.5 to the lower and upper limits of each interval.
For the interval 40-59, the lower limit is 40 and the upper limit is 59. Adding/subtracting 0.5, we get:
Lower class boundary = 40 - 0.5 = 39.5
Upper class boundary = 59 + 0.5 = 59.5
Therefore, the class boundaries of the scores interval 40-59 are 39.5 and 59.5.
The answer is (A) 39.5, 59.5.
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the statistic x¯ is used as an estimator for which of the following?
As a point estimator for, we utilise x-bar (sample mean) (mu, population mean)
What is mean or average?The average value in mathematics is the middle number, which is calculated by dividing the total number of numbers by the sum of all the numbers. A set of data's average is calculated by adding up all the values and dividing the result by the total number of values.
We use the x-bar (sample mean) as a point estimator for (mu, population mean). As long as the sample is random, this estimator's impartial long-run distribution is centred at (mu).
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Complete question -
(16+3)-10÷5×3^2? with explanation step by step
Here, we want to simplify the given expression
We shall use the order of simplification for this
The order is PEDMAS
We shall start with the terms in parentheses before we move to the exponents
We have;
\(\begin{gathered} (16+3)-10\div5\times3^2 \\ =\text{ 19-10}\div5\times3^2 \end{gathered}\)Next is the exponent
\(=\text{ 19-10}\div5\times9\)The next thing to do is to divide
\(=\text{ 19-}2\times9\)The next thing to do is to multiply
\(=\text{ 19-18}\)We then proceed to subtract;
\(=\text{ 19-18 = 1}\)Can anyone plz help me plz:
What is the measure of 40 angle A’B’C’?
Answer:
angle ABC is a straight angle or, 180°
At the grocery store, I bought $4$ different items. I brought $3$ identical bags, and handed them to the cashier. How many ways are there for the cashier to put the items I bought in the $3$ identical bags, assuming he might leave some of the bags empty
There are 18 different ways in which the cashier can put the items in the bags.
In how many ways can 4 items be distributed in 3 bags?
There are some cases to consider.
1) The 4 items go in the same bag, there are 3 permutations for this case.
2) 3 items on one bag, and 1 item on other bag (there are 6 permutations for this case).
3) 2 items on one bag, 2 items on other bag (6 permutations).
4) 2 items on one bag, 1 item on each of the other two bags (3 permutations for this case).
We just need to count the total number of permutations, which is:
3 + 6 + 6 + 3 = 18
There are 18 different ways in which the cashier can put the items in the bags.
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Let S be the surface of the solid sphere x2+y2+z2≤36 and the vector field is given by, F=⟨z,y,x⟩. (a) Find divergence of F. (b) Use Divergence Theorem to evaluate ∬SF⋅dS Also, sketch the region of integration.
The divergence of the vector field F = ⟨z, y, x⟩ can be found by taking the partial derivatives of each component with respect to its corresponding variable and summing them up.
Let's denote the partial derivative with respect to x as ∂/∂x, y as ∂/∂y, and z as ∂/∂z. Then the divergence (div(F)) is given by:
\(\[\text{div}(F) = \frac{\partial}{\partial x}(x) + \frac{\partial}{\partial y}(y) + \frac{\partial}{\partial z}(z).\]\)
Taking the partial derivatives, we get:
\(\[\text{div}(F) = 1 + 1 + 1 = 3.\]\)
(b) The Divergence Theorem states that for a vector field F and a closed surface S bounding a region in space, the flux of F through S is equal to the triple integral of the divergence of F over the enclosed region. In this case, the surface S is the solid sphere defined by \(x^2 + y^2 + z^2\) ≤ 36.
To evaluate the flux of F through S, we need to compute the triple integral of the divergence of F over the region enclosed by S. Since the divergence of F is constant and equal to 3, the triple integral simplifies to:
\(\[\iiint\limits_V \text{div}(F) \, dV = \iiint\limits_V 3 \, dV,\]\)
where V represents the region enclosed by S.
To sketch the region of integration, visualize a solid sphere centered at the origin with a radius of 6 (since \(x^2 + y^2 + z^2\) ≤ 36). The region of integration encompasses the volume inside this sphere.
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8. timmy has collected plain and colored marbles. he has a total of 180 marbles, and there are 32 more plain marbles than colored marbles. knowing that x represents the number of plain marbles and y represents the number of colored marbles, which of the following systems of equations represents the number of marbles timmy has? a. x y
The given problem can be solved using algebraic equations as shown below. The number of plain marbles can be represented by "x" while the number of colored marbles can be represented by "y". If there are 32 more plain marbles than colored marbles, then the number of plain marbles will be y + 32.
So, the equation representing the number of plain marbles will be x = y + 32.There are a total of 180 marbles, so x + y = 180.Substituting the value of x in this equation, we get (y + 32) + y = 180. Simplifying, we get:2y + 32 = 1802y = 180 - 32 = 148y = 148/2 = 74. Substituting the value of y in x = y + 32, we get: x = 74 + 32 = 106.So, Timmy has 106 plain marbles and 74 colored marbles.
The system of equations representing the number of marbles Timmy has is: x + y = 180x = y + 32. Substituting the value of y in the equation x = y + 32, we get x = 74 + 32 = 106, which means that Timmy has 106 plain marbles. The number of colored marbles is y = 74. Therefore, the system of equations representing the number of marbles Timmy has is: x + y = 180x = y + 32.
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Please help me, really need help
The pair of 1st line is vertical opposite angle and 2nd one is adjacent angles.
What is vertical opposite angle ?
When 2 lines meet one another, then the other angles, shaped thanks to intersection ar known as vertical angles or vertically opposite angles. A try of vertically opposite angles ar continuously adequate to one another. Also, a angle and its adjacent angle are supplementary angles, i.e., they add up to a hundred and eighty degrees.
Main body:
1st pair of line intersect each other , so ∠1 = ∠2 by using vertical opposite angle.
2nd pair of line also intersect each other , so ∠3 ,∠4 are adjacent angles.
Hence ,pair of 1st line is vertical opposite angle and 2nd one is adjacent angles.
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What is the range of the function shown in the graph?
Answer:
D. -∞ < y < 5
Step-by-step explanation:
The range are all the possible values for y that the function can take. In the graph we can see that the highest value for y is 5 and there isn't a lowest value for y. It means that the range are values between -∞ and 5.
So the range is:
-∞ < y < 5
Let g be the function given by g(x)=x2ekx, where k is a constant. For what value of k does g have a critical point at x=2/3?
A. -3
B. -3/2
C. -1/3
D. 0
E. There is no such k
The answer is (B) -3/2. When k = -3/2, g(x) has a critical point at x = 2/3.
To learn
To find the value of k that makes g(x) have a critical point at x = 2/3, we need to find the derivative of g(x) and set it equal to zero, and then solve for k.
First, we use the product rule to find g'(x):
g'(x) = (2xekx) + (x2ekx)(kekx) = xekx(2+kx)
Next, we set g'(2/3) = 0 and solve for k:
g'(2/3) = (2/3)ek(2/3)(2+k(2/3)) = 0
Simplifying this equation, we get:
(2/3)ek(2/3)(2+k(2/3)) = 0
2 + k(2/3) = 0
k = -3/2
Therefore, the answer is (B) -3/2. When k = -3/2, g(x) has a critical point at x = 2/3.
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A shelf is supported with brackets as pictured in the diagram below. What is the
width of the shelf?
A 14 in.
B 16 in.
C 12 in.
D 10 in.
The width of the shelf is 10 inches. The correct option is D.
Describe Right Angled Triangle?A right-angled triangle is a triangle that has one angle measuring 90 degrees, which is known as the right angle. The sides adjacent to the right angle are known as the legs of the triangle, while the side opposite the right angle is known as the hypotenuse.
The Pythagorean theorem, which states that in a right-angled triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the legs, is one of the fundamental theorems of mathematics and is used extensively in various fields.
Let's call the width of the shelf "x". According to the given diagram, we have a right triangle where the base is x, the perpendicular is 10 inches, and the angle between the hypotenuse and the perpendicular is 45 degrees.
Using trigonometric ratios, we know that:
tan(45) = perpendicular/hypotenuse
tan(45) = 10/x
Since tan(45) is equal to 1, we can simplify the equation to:
1 = 10/x
Solving for x, we get:
x = 10
Therefore, the width of the shelf is 10 inches.
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What is a segment bisector of a triangle?
A line, segment, or ray that divides a triangle's side into two equal segments is known as a segment bisector in geometry. A line or segment that crosses the midpoint of a triangle's side is known as a segment bisector.
A line, segment, or ray that divides a triangle's side into two equal segments is known as a segment bisector in geometry. A line or segment that crosses the midpoint of a triangle's side is known as a segment bisector.
Let's think about an ABC triangle to help us better understand this idea. Drawn from vertex A to side BC, a segment bisector will meet BC at its halfway, cutting BC into two equal segments. The same holds true for segment bisectors that are drawn from vertices B and C to the triangle's obverse sides.
Segment bisectors have a few significant characteristics. First of all, they intersect in a single location known as the incenter because all three segment bisectors of a triangle are contemporaneous. The triangle's inscribed circle's incenter is located in the triangle's center.
Furthermore, a side's segment bisector is perpendicular to it. Because it is on the perpendicular bisectors of the sides, the incenter of a triangle is equally spaced from its three sides.
Segment bisectors are important in geometry, especially in the creation of circles, the properties of the incenter, and triangle congruence.
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Student Council sells soft drinks at basketball games and makes $ 1.50 from each. If they pay $ 75 to rent the concession stand, how many soft drinks would they have to sell to make $ 250 profit?
F. 116
G. 117
H. 167
J. 217
Answer: 166 Soft Drinks
Step-by-step explanation:
250 ÷ 1.50 = 166
A rectangular birthday present, 3 in. by 7 in. by 8 in., is covered by wrapping paper. How much wrapping paper is required?
a.
146 sq. in.
b.
101 sq. in.
c.
202 sq. in.
d.
168 sq. in.
The amount of wrapping paper that is required is; c. 202 sq. in.
What is the surface area of the rectangular cuboid?The formula for the surface area of a rectangular cuboid is given as:
SA = 2(lw + lh + hw)
where;
l = length
h = height
w = width
We are given;
Length; l = 3 in.
Width; w = 7 in.
Height; h = 8 in.
Thus, surface area is;
SA = 2((3*7) + (3*8) + (8*7))
SA = 2(21 + 24 + 56)
SA = 2(101)
SA = 202 sq. in
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in a factorial anova, compared to a design with only one independent variable, a major modification of using anova to analyze variability is that the sources of
A t-test cannot cover more than one group. This has to do with the underlying method used to calculate the test value.
Explain about t-test?
The t-test is designed to compare the means of two populations based on the means of the two samples. (any sample from either population).
The most important observation is that the t-test computes the difference between two sample means.
If you have trouble understanding 'variance', you can use the word standard deviation from the previous text to get your points.
In other words, there is more than one difference between the groups, but we want one measure of Total Difference Between Groups. The t-test cannot do that.
So the procedure for groups of three or more is: Run ANOVA first. As a second step, if you have reason to believe that differences exist (based on this test), you can use the t-test to determine where those differences lie.
A t-test cannot cover more than one group. This has to do with the underlying method used to calculate the test value.
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Can some please help me ASAP
I will give brainiest
Answer:
Step-by-step explanation:
Plz help ASAP I got 10 mins !!!!!
Answer:
x=5
Step-by-step explanation:
Since the triangles are similar we can use ratios to solve
4.5 7.5
---- = ------
3 x
Using cross products
4.5x = 3 * 7.5
4.5x = 22.5
Divide each side by 4.5
x = 22.5/4.5
x=5
Graph A (-3.-2), B (-5,-4), and C (-3,-4)
Pls solve the problems
Graph attached
5,032 divided by 52
Pls show your work so i know how you did it tnx ❤️
Answer:
96.76
Step-by-step explanation: