Find the value of F (5)

A) 500

B) 54 minutes

C) 68cents and 60 cents

D)

E) $40.95

A proportion is a statement that says that two ratios are equal. They can be used in many everyday situations like comparing sizes, cooking, calculating percentages, and more.

Proportions can be written as equivalent fractions or as equal ratios.

A) 42% = 210

100% = (210 x 100)/42

= 500 people

B) 135 berries = 15 minutes

    486 berries = ??minutes

= (486 x 15)/135

= 54 minutes

C) unit price = $6.75/10 = 0.675cents or 68cents

    ii) unit price = $7.25/12 = 0.604cents or 60cents

D) Inconclusive question.

E) 40% of 65 = $26

65 - 26 = $39

Tax = 5% = $1.95

Total = $39 + 1.95

Final Price of jacket = $40.95

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a) To calculate the pressure at 12 hours of shut-in:

substitute the given values into the pressure buildup equation and solve for P(t=12).

b) Superposition in time is used in pressure buildup analysis by adding or summing the responses of multiple transient tests to analyze and interpret reservoir behavior and properties.

We have,

a) To calculate the pressure in the production well at 12 hours of a shut-in, we can use the equation for pressure transient analysis during shut-in periods, known as the pressure buildup equation:

P(t) = Pi + (Q / (4πKh)) * log((0.14ϕμCt(t + Δt)) / (Bo(ΔP + Δt)))

Where:

P(t) = Pressure at time t

Pi = Initial reservoir pressure

Q = Flow rate

K = Permeability

h = Reservoir thickness

ϕ = Porosity

μ = Viscosity

Ct = Total compressibility

t = Shut-in time (12 hours)

Δt = Time since the start of the flow period

Bo = Oil formation volume factor

ΔP = Pressure drop during the flow period

Given:

Pi = 3100 psi

Q = 200 STB/day

K = 45 md

h = 60 ft

ϕ = 15%

μ = 1.2 cp

Ct = 15x10^-6 psi^-1

Bo = 1.3 bbl/STB

t = 12 hours

Δt = 48 hours

ΔP = Pi - P(t=Δt) = Pi - (Q / (4πKh)) * log((0.14ϕμCt(Δt + Δt)) / (Bo(ΔP + Δt)))

Substituting the given values into the equation:

ΔP = 3100 - (200 / (4π * 45 * 60)) * log((0.14 * 0.15 * 1.2 * 15x\(10^{-6}\) * (48 + 48)) / (1.3 * (3100 - (200 / (4π * 45 * 60)) * log((0.14 * 0.15 * 1.2 * 15 x \(10^{-6}\) * (48 + 48)) / (1.3 * (0 + 48))))))

After evaluating the equation, we can find the pressure in the production well at 12 hours of shut-in.

b) Superposition in time is a principle used in pressure transient analysis to analyze and interpret pressure build-up tests.

It involves adding or superimposing the responses of multiple transient tests to simulate the pressure behavior of a reservoir.

The principle of superposition states that the response of a reservoir to a series of pressure changes is the sum of the individual responses to each change.

Superposition allows us to combine the information obtained from multiple tests and obtain a more comprehensive understanding of the reservoir's behavior and properties.

It is a powerful technique used in reservoir engineering to optimize production strategies and make informed decisions regarding reservoir management.

Thus,

a) To calculate the pressure at 12 hours of shut-in:

substitute the given values into the pressure buildup equation and solve for P(t=12).

b) Superposition in time is used in pressure buildup analysis by adding or summing the responses of multiple transient tests to analyze and interpret reservoir behavior and properties.

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The state-variable model for the given system is: dx1(t)/dt = x2(t) dx2(t)/dt = -8x1(t) - 3x2(t) + 10u(t) y(t) = x1(t)

To obtain the state-variable model of the given system, we first need to express the differential equation in the form of state equations. The state-variable model consists of two equations: the state equation and the output equation.

Let's denote the state variables as x1(t) and x2(t). The state equation is given by: dx1(t)/dt = x2(t) dx2(t)/dt = -8x1(t) - 3x2(t) + 10u(t)

Here, x1(t) represents the state variable for the derivative of y(t) (dx1(t)/dt), and x2(t) represents the state variable for the derivative of ÿ(t) (dx2(t)/dt).

To derive the output equation, we relate the output variable y(t) to the state variables. In this case, the output equation is: y(t) = x1(t)

Therefore, the state-variable model for the given system is: dx1(t)/dt = x2(t) dx2(t)/dt = -8x1(t) - 3x2(t) + 10u(t) y(t) = x1(t)

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A confounding variable must be associated with both the exposure and the outcome, and it should not be an intermediate step in the causal pathway between the exposure and outcome.

To determine if a variable confounds an association, follow these steps:

1. Identify the exposure, outcome, and potential confounding variable: Determine which variables are your exposure (independent variable), outcome (dependent variable), and the potential confounding variable.

2. Assess the relationship: Evaluate if the potential confounding variable is associated with both the exposure and the outcome. If it is, it could be a confounder.

3. Control for the confounding variable: Adjust your statistical analysis to account for the potential confounding variable, either by stratification or using multivariable regression techniques.

4. Compare the results: Analyze the strength and direction of the association between the exposure and outcome before and after controlling for the confounding variable. If the association changes significantly, it's likely that the variable is a confounder.

Remember that a confounding variable must be associated with both the exposure and the outcome, and it should not be an intermediate step in the causal pathway between the exposure and outcome.

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Answer:

No

Step-by-step explanation:

We can check with the Pythagorean Theorem.

a^2 + b^2 = c^2

  a and b are always the smaller sides, the legs

  c is the longer side, the hypotenuse

3^2 + 3^2 >  6^2

9 + 9 > 36

18 < 36

18 is not greater than 36, therefore this triangle can not have the side lengths 3, 3, and 6.

Step-by-step explanation:

1/16 is ur ans.

\(2 ^{ - 4} \)

\(1 \div 2 ^{4} \)

\(1 \div 16\)

1 / 16 or 0.0625

you exponet using a^-n

= 1/ a^n

1/2^4

evaluate the power

1/16

or u can write 0.0625 whatever you want

Answer:

2b^2+10b+12 = 2(b^2+5b+6) = 2(b+3)(b+2)

4x^2+4x-3 = 4(x^2+x-3/4) = 4(x+3/2)(x-1/2)

6m^2+7m-3 = 6(m^2+m-1/2) = 6(m+1/2)(m-1/2)

10x^2-9x+6 = 10(x^2-x+6/10) = 10(x-1/2)(x-3/2)

18h^2+15h-18 = 18(h^2+5/6h-1) = 18(h+3)(h-2)

Answer:

Step-by-step explanation:

Answer:

137.04

Step-by-step explanation:

I took the test

Answer:

3645

Step-by-step explanation:

65610/18=3645

The amount of interest earned on a deposit of $60.00 at a rate of 9% per annum for 2 years is $108.

As per the given problem:

Amount deposited = $60.00

Interest rate per year = 9%

The formula for calculating the interest is given by:

Interest = (Principal × Rate × Time)/100

Where Principal is the initial amount invested or deposited

Rate is the percentage of interest that you earn per annum

Time is the duration for which you want to calculate the interest

Putting the values in the above formula, we get:

Interest = (60 × 9 × 2)/100= (108 × 1)/1= $108

So, the amount of interest earned on a deposit of $60.00 at a rate of 9% per annum for 2 years is $108.

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The answer would very. Let's say the function is y + 4 = (x + 4)

Two points would be (-4,-4) and (4,0)

Answer:

x  ≥  21

Hope this helps!

Answer:

plz give the other person brain thingy :D

Step-by-step explanation:

Answer:

x = − 5 + 1/2 √ 21 or x = − 5 + − 1/2 √ 21

Step-by-step explanation:

Let's solve your equation step-by-step.

4(x+5)^2=21

Step 1: Simplify both sides of the equation.

4x^2+40x+100=21

Step 2: Subtract 21 from both sides.

4x^2+40x+100−21 =21−21 4x^2+40x+79=0

For this equation: a=4, b=40, c=79

4x^2+40x+79=0

Step 3: Use quadratic formula with a=4, b=40, c=79.

x= −b±√ b^2−4ac/2ax

= −(40)+√ (40)^2−4(4)(79)/2(4)

x = 40^2±√ 336/8

x= −5+1/2 √ 21 or x = −5+ − 1/2√ 21

Answer: x = − 5 + 1/2 √ 21 or x = − 5 + − 1/2 √ 21

( I hope this was helpful) >;D

To find τ∘σ∘τ⁻¹, we need to apply the permutations in the given order. First, let's find σ∘τ. σ=(1345)(278) means that 1 maps to 3, 3 maps to 4, 4 maps to 5, 5 maps to 1, 2 maps to 7, 7 maps to 8, and 8 maps to 2.

τ=(164)(2583) means that 1 maps to 6, 6 maps to 4, 4 maps to 1, 2 maps to 5, 5 maps to 8, 8 maps to 3, and 3 maps to 2. Now, let's apply σ∘τ:

1 maps to 6 (σ∘τ),
6 maps to 4 (σ∘τ),
4 maps to 5 (σ∘τ),
5 maps to 1 (σ∘τ),
2 maps to 7 (σ∘τ),
7 maps to 8 (σ∘τ),
8 maps to 3 (σ∘τ),
3 maps to 2 (σ∘τ).

So, σ∘τ=(65418232).

Finally, to find τ∘σ∘τ⁻¹, we need to apply τ⁻¹ to σ∘τ. τ⁻¹=(164)(2583)⁻¹=(416)(5238) means that 1 maps to 4, 4 maps to 1, 2 maps to 5, 5 maps to 2, 3 maps to 8, and 8 maps to 3. Applying τ⁻¹ to σ∘τ, we get:

6 maps to 1 (τ⁻¹∘σ∘τ),
5 maps to 4 (τ⁻¹∘σ∘τ),
4 maps to 2 (τ⁻¹∘σ∘τ),
1 maps to 5 (τ⁻¹∘σ∘τ),
2 maps to 8 (τ⁻¹∘σ∘τ),
8 maps to 3 (τ⁻¹∘σ∘τ),
3 maps to 2 (τ⁻¹∘σ∘τ).
Therefore, τ∘σ∘τ⁻¹=(15452832).

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Answer:

S = 3770.25 in^2

Step-by-step explanation:

20/15 = 4/3

5027/ 4/3 = 3770.25

Answer:

Step-by-step explanation:

For equation-x²4x+11

x=-b+_√b²-4ac/2a

 = -4+-√16-44/2

 =-2+-√-7

 =-2+-√7i

hence correct option is

The friend's thinking is incorrect, and the probability of the next flip being tails is still 50%.

There is no law of averages for the short run.

The first five flips do not affect the sixth flip. C

Each flip of a coin is an independent event, meaning the outcome of one flip does not affect the outcome of the next flip.

The fact that the friend has flipped five heads in a row does not increase or decrease the probability of the next flip being heads or tails.

The probability of getting heads or tails on any given flip is always 50%, regardless of the outcomes of previous flips.

This is known as the "law of large numbers," which states that the long-run frequency of an event will approach its theoretical probability as the number of trials increases.

The short run, anything can happen, and streaks or patterns can occur by chance.

The outcome of one coin flip does not influence the outcome of the subsequent flips since each coin flip is a separate event.

The likelihood that the following flip will result in heads or tails is unaffected by the friend flipping five consecutive heads.

Regardless of the results of prior flips, there is always a 50% chance of receiving heads or tails on every current flip.

This is known as the "l

aw of large numbers," which holds that as the number of trials rises, the long-run frequency of an occurrence will approach its theoretical probability.

In the near term, anything is possible, and streaks or patterns might arise by accident.

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Answer:

Step-by-step explanation:

(0.061)(0.43) =0.02623

Answer:

Step-by-step explanation:

A

Answer:

96

Step-by-step explanation:

:)

Answer:

d. x les-than-or-equal-to 3 Graph B

Graph B expressed as follows; The graph on the coordinate plane, a line goes through (0, 3) and (4, 5). Another line goes through (1, 0.5), and (4, 6.5). The lines intersect at (3, 4.5)

Step-by-step explanation:

The given inequality is expressed as follows;

0.5·x + 3 ≥ 2·x - 1.5

Let y₁ = 0.5·x + 3, and y₂ = 2·x - 1.5, we get;

For x = -1, 0, 1, 2, 3, 4, 5, 6

y₁ = 2.5, 3, 3.5, 4, 4.5, 5, 5.5, 6

y₂ = -3.5, -1.5, 0.5, 2.5, 4.5, 6.5, 8.5, 10.5

From the given data, the lines intersect at (3, 4.5)

The graph on the coordinate plane, a line goes through (0, 3) and (4, 5). Another line goes through (1, 0.5), and (4, 6.5). The lines intersect at (3, 4.5)

Please find attached the required inequality created with MS Excel

Therefore, we have;

3 + 1.5 ≥ 2·x - 0.5·x

4.5 ≥ 1.5·x

∴ 3 ≥ x

x ≤ 3

Therefore, with (typographical) correction, the best option is x les-than-or-equal-to 3 Graph B

Answer:

D

Step-by-step explanation:just took the test

Answer: The average growth rate of customers in the queue is 30 per hour

Step-by-step explanation:

Given that:

Step1:

number of customers arrived per hour = 100

The capacity of the coffee shop = 80

Step2:

let us assume at the beginning, the coffee shop is empty. Only 80 of the 100 customers that arrive in the first hour may be attended to. There are 20 consumers in line, so they must wait for the next hour.

Another 100 clients show up during the second hour, but there are already 20 people in line from the first hour. As a result, although the coffee shop needs to serve 120 customers, it can only do so at a rate of 80 each hour. Forty (40) consumers must wait in line for the next hour.

Therefore for two hours, The coffee shop's customer line is extending with an average growth rate of:

(20 customers per hour + 40 customers per hour) / 2 hours = 30 customers per hour

Therefore, the queue of customers grows at a rate of 30 customers per hour during the morning rush.

Answer:

1)Yes

2)No

Step-by-step explanation:

1) 3x^2 = -27

3 (-3)^2 = -27

Once you substitute your value in for x, you can follow the rule PEMDAS to solve the equation.

3 (-9) = -27

-27 =-27

2) 10 - 5x = y

In an ordered pair, the first number is x and the second number is y.

10 - 5 (-4) = 10

10 - 20 = 10

-10 = 10

-10 ≠ 10

PEMDAS: A rule that states solving an equation by the order of operations:

Parentheses

Exponents

Multiplication

Division

Addition

Subtraction

\(2x+40=60\\2x=20\\x=10\)

Answer:

X = 1.09

Step-by-step explanation:

6 to the 1.09th power is 7.04993094301076 so when it is rounded it is 7.

Answer:

the answer is 7

Step-by-step explanation:

log10(6x)=log10(7)

x•log10(6)=log10(7)

x = log10(7)/log10(6)

this works because of

logb(x y) = y ∙ logb(x)

I figured this out from the internet!!

source:TigerAlegbra

Answer:

Step-by-step explanation:

The answer is D. The graph to the left of x = 1 has an open hole at the x value of 1, and the graph does not continue on past the x value of 1. Therefore, the domain of that function is all values of x that are to the left of x = 1. The hole is open because the inequality statement doesn't have a line under the inequality symbol that says we have to include it. It is, however, included at the x value of 1 on the line.

Answer:

i am not surte

Step-by-step explanation:

Answer:

a). Center of the circle = (-2, 5)

b). Equation of the line ⇒ y = \(-\frac{4}{5}x+\frac{58}{5}\)

Step-by-step explanation:

Equation of the circle is,

x² + 4x + y²- 10y + 20 = 30

a). [x² + 2(2)x + 4 - 4] + [y²- 2(5)y + 25] - 25 + 20 = 30

   [x² + 2(2)x + 4] - 4 + [y² - 2(5)y + 25] - 25 + 20 = 30

   (x + 2)² + (y - 5)²- 29 + 20 = 30

   (x + 2)² + (y - 5)²- 9 = 30

   (x + 2)² + (y - 5)² = 39

By comparing this equation with the standard equation of a circle,

    Center of the circle is (-2, 5).

b). A point (2, 10) lies on this circle.

    Slope of the line joining this point to the center (-2, 5),

    \(m_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\)

          = \(\frac{10-5}{2+2}\)

          = \(\frac{5}{4}\)

    Let the slope of the tangent which is perpendicular to this line is '\(m_{2}\)'

    Then by the property of perpendicular lines,

          \(m_{1}\times m_{2}=-1\)

          \(\frac{5}{4}\times m_{2}=-1\)

                 \(m_{2}=-\frac{4}{5}\)

   Now the equation of the line passing though (2, 10) having slope \(m_{2}=-\frac{4}{5}\)

           y - y' = \(m_{2}(x-x')\)

           y - 10 = \(-\frac{4}{5}(x-2)\)

           y - 10 = \(-\frac{4}{5}x+\frac{8}{5}\)

                  y = \(-\frac{4}{5}x+\frac{8}{5}+10\)

                  y = \(-\frac{4}{5}x+\frac{58}{5}\)

Therefore, equation of the line will be, y = \(-\frac{4}{5}x+\frac{58}{5}\)

Answer:

5<4

Step-by-step explanation:

This inequality is not correct though.

5-7+7<-3+7

5<4