find the quality of water at t=65 °c, v = 0.06 m3/kg. (provide your answer to 4 decimal places, e.g. 0.1234; do not include the units when you enter your answer on bblearn.)

One calcium ion \((Ca2^+)\)and two bromide ions\((Br^-)\)are produced when \(CaBr^2\) (calcium bromide) dissolves in water.

The ionic compound calcium bromide \((CaBr^2)\) is made up of calcium cations \((Ca2^+)\)and bromide anions \((Br^-)\)in a 1:2 ratio. It is a crystalline white substance that is very soluble in both alcohol and water.

Therefore, One \(Ca2^+\) ion and two Br- ions are produced by each formula unit of\(CaBr^2\) in solution. This is due to the fact that the ionic compound \(CaBr^2\) dissociates in water, causing the compound to separate into its individual ions, which are then solvated by water molecules.

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Answer: False

Explanation: Gaining an electron which has a negative charge results in an overall negative charge, thus making this an anion, and the answer, false.

Answer:false

Explanation:it becomes a anion

Answer:

Molarity = 1.12 mol/L

Explanation:

To make an aqueous solution of Na₂O, the concentration will be calculated by: concentration (c) (or molarity) = number of moles present (n) ÷ volume needed (V) (in litres)

since we don't have moles, we can calculate moles by:

number of moles (n) = mass present (m) (in grams) ÷ molar mass (M) (in grams per mole), which we can find using a standard IUPAC Periodic Table

∴ n(Na₂O) = m/M = 34.8/(22.99×2+16.00) = 0.56147 mol

Now we have the number of moles present, we can calculate concentration:

∴ c(Na₂O) = n/V = 0.56147/0.50L = 1.12 mol/L

IBM's Watson utilizes a massively parallel, text mining-focused, probabilistic evidence-based computational architecture called DeepQA.

IBM's Watson utilizes a massively parallel, text mining-focused, probabilistic evidence-based computational architecture called DeepQA.

                                    IBM's Watson utilizes a massively parallel, text mining-focused, probabilistic evidence-based computational architecture called DeepQA.

                            IBM's Watson utilizes a massively parallel, text mining-focused, probabilistic evidence-based computational architecture called DeepQA.

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The primary goal of the carburetor is to atomize and vaporize the fuel before mixing it with air in varying proportions, making it the device that is used for atomizing and vaporizing the fuel before mixing it with air in varying proportions.

The device that is used for atomizing and vaporizing the fuel before mixing it with air in varying proportions is Carburetor. A carburetor is a device that blends air and fuel for an internal combustion engine. It is often located on the top of an engine on a direct engine-to-carburetor link, and it controls how much air and fuel are mixed.The carburetor must also supply the engine with a spark plug to ignite the fuel/air mixture in each cylinder.

The carburetor must provide a fuel/air mixture that is consistent with the engine's changing demands, which vary with engine speed, load, and temperature. A carburetor is responsible for enriching the fuel/air mixture when the engine is cold and for leaning the mixture as the engine warms up. As well, it is also responsible for regulating the fuel/air mixture at part-throttle levels, where the engine spends most of its time when driving.

When an engine is running at full throttle, it is operating at wide-open throttle (WOT), and the carburetor provides the richest fuel/air mixture possible.The carburetor, like most engine systems, is a complex and sensitive device that must be correctly tuned to perform properly. The primary goal of the carburetor is to atomize and vaporize the fuel before mixing it with air in varying proportions, making it the device that is used for atomizing and vaporizing the fuel before mixing it with air in varying proportions.

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Explanation:

lactose is disaccharide

because it contains 1 monosaccharide galactose +

1 monosaccharide glucose

The correct answer to the question is: disaccharide

Monosaccharides are simple sugar which can not be hydrolysed into simpler or smaller molecules.

Disaccharides are sugars produced by the condensation of two monosaccharides with the elimination of a water molecule.

A Monomer is a small molecule which can combine with other similar molecules to form a large molecule called polymer. Thus, a monomer of starch is simply a small molecule that combines together to form a polysaccharide called starch. The monomer of starch is glucose.

Glucose and galactose combined to form lactose i.e

The above is simply a demonstration of how disaccharides are produced.

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Answer:

The aroma of the popcorn spreads throughout the room gradually due to the presence of air.

Explanation:

The popcorn bag releases an aroma when opened. This aroma then travels through the air due to which the aroma spreads throughout the room.

Note:

If the room was closed, the aroma will remain inside the room. If the room was open, the aroma will also spread beyond the room due to the presence of air.

Answer:

PV=nRT

0.20×v = 0.070×8.00

0.20V= 0.56

0.20v÷0.20v = 0.56÷0.20v

= 2.8

The metabolic process that occurred in the apparatus of the experiment given in the question is photosynthesis. The graphed results of the experiment are related to the process of photosynthesis.

Photosynthesis is the process in which the green plants use the energy of sunlight to convert carbon dioxide and water into glucose and oxygen. In this process, chlorophyll pigment, present in the chloroplasts of the plant cells, captures the energy of sunlight. This captured light energy is used to convert water and carbon dioxide into oxygen and glucose.

In the experiment mentioned above, the metabolic process that occurred in the apparatus is photosynthesis. It is because spinach leaves were used in the experiment to observe the amount of oxygen (O2) and carbon dioxide (CO2) present in the leaves.

The graphed results of this experiment show that the amount of oxygen in the leaves increased over time while the amount of carbon dioxide decreased. This is because the leaves absorbed carbon dioxide from the air and converted it into glucose and oxygen through the process of photosynthesis. As a result, the amount of oxygen increased over time, and the amount of carbon dioxide decreased. Hence, it can be concluded that the graphed results of the experiment are related to the process of photosynthesis.

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The molarity of NaOH is \(0.24009 \mathrm{M}$\).

This is the formula for molarity:

\(\text { molarity of } \mathrm{NaOH}=\frac{\text { number of moles of } \mathrm{NaOH}}{\text { volume of } \mathrm{NaOH} \text { solution }(\mathrm{L})}$$\)

First, we need to find the number of moles of \($\mathrm{NaOH}$\) :

\($K H P$\) being "monoprotic" mean s that one mole of KHP is one equivalent. Basically, 1 molecule of KHP only donates \($1 H^{+}$\) ion.

We also know that\($\mathrm{NaOH}$\) is a monoprotic base, because there's only one \($\mathrm{OH}^{-}$\) ion in its chemical formula.

Therefore, 1 mole of KHP will correspond to 1 mole of \($\mathrm{NaOH}$\) in a neutralisation reaction.

In other words, 1 mole of \($\mathrm{NaOH}$\) will neutralise 1 mole of \($\mathrm{KHP}$\).

The number of moles of KHP that was neutralised was:

\($\frac{1.25}{39.098+1.008+8 \times 12.01+4 \times 1.008+4 \times 16}$\)

= 0.00612 moles

Because the mole ratio of K H P to N a O H is 1 : 1 , 0.00612moles of N a O H must have neutralised 0.00612 moles of K H P .

Then, we need to find the volume of the N a O H solution. This is pretty simple, actually, because it was given to us in the question: 28.05  mL , or 0.02549 L .

Finally, we just need to plug these values into the formula for molarity:

molarity of \($\mathrm{NaOH}=\frac{\text { number of moles of } \mathrm{NaOH}}{\text { volume of } \mathrm{NaOH} \text { solution }(\mathrm{L})}$\)

molarity of \($\mathrm{NaOH}=\frac{0.00612 \mathrm{~mol}}{0.02549 \mathrm{~L}}$\)

molarity of \($\mathrm{NaOH}=0.24009 \mathrm{M}$\)

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The number of units per volume, area, or length: as. a: a substance's mass per unit volume is 85.12 g.

Therefore,

The density of tin in g ml =  6.037 g/ml.

so  the mass of a piece of tin with a volume of 14.1 mL.

= 6.037 x 14.1 = 85.12 g.

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answer: 1.42%

Explanation:

Answer:

A decade is 10 years. Therefore you must first multiply ten by five to get 50. After you multiply the 12 months in a year by the 50 years. Your answer should be 600

Explanation:

Answer:its d

Explanation:just took it

Answer:

Explanation:

The density of a substance can be found by using the formula

\(density = \frac{mass}{volume} \\ \)

From the question we have

\(density = \frac{24}{1200} = \frac{1}{50} \\ \)

We have the final answer as

Hope this helps you

Answer:

3.93 mol

Explanation:

The balanced equation is given as;

2 Fe₂S₃+ 9 O₂ --> 2 Fe₂O₃ + 6 SO₂

From the reaction;

2 mol of Fe₂S₃ reacts with 9 mol of O₂ to form 6 mol of 6 SO₂

This means;

1 mol of Fe₂S₃  requires 9/2 mol of O₂

Also,

1 mol of O₂ requires 1/9 mol of Fe₂S₃

In the question, we have;

1.31 moles of Fe2S3 and 22.8 moles of O2

The limiting reactant which determine how much of the product formed is; Fe₂S₃ because O₂ is in excess.

The relationship between Fe₂S₃ and SO₂ is;

2 mol Fe₂S₃ produces 6 mol of SO₂

1.31 mol of Fe₂S₃ would produce x mol ?

2 = 6

1.31 = x

x = 6 * 1.31 / 2 = 3.93 mol

Answer:C097

Explanation:

Mass of \(Na_{2}S_{2}O_{3}\) needed = 0.115g. The given problem can be solved using the concepts of solubility product constant and formation constant.

Given that, Mass of AgBr = 4.7 g Volume of solution = 1.0 L

Ksp of AgBr = 3.3 × 10−13 \(3.3 * 10^{-13}\)

kf of \([Ag(S_{2}O_{3})_{2}]^{3-} = 4.7 * 10^{13}\)

We know that AgBr dissolves in \(Na_{2}S_{2}O_{3}\) by the following reaction:

\(AgBr + Na_{2}S_{2}O_{3} = NaBr + Ag(S_{2}O_{3})_{2}^{3-}\)

For the reaction to occur, the following equilibrium should be established:

\([Ag(S_{2}O_{3})_{2}]^{3-} + AgBr =  Ag_{2}(S_{2}O_{3})_{3} + Br^{-}\)

The Ksp of AgBr can be calculated as follows:

Ksp = [Ag+] [Br−] = (2s) (s)

= \(= 4s 3.3 * 10^{-13}\)

\(= 4s3s = \sqrt[3]{\frac{3.3 * 10^{-13}}{4} }\)

= \(3.4 * 10^{-5}\)M.

The molar concentration of AgBr is \(2s = 6.8 * 10^{-5}\)M.

The formation constant of [Ag(S2O3)2]3−\([Ag(S_{2}O_{3})_{2}]^{3-}\) is given by

\(kf =  \frac{[Ag(S_{2}O_{3})_{2} ^{3-}] }{[Ag^{+}]_{2} [S_{2}O_{3} ^{2-}]}\)

= \(\frac{[Ag(S_{2}O_{3})_{2}^{3-}]}{(s4)4.7 * 10^{13}}\)

= \(\frac{[Ag(S_{2}O_{3})_{2}^{3-}]}{ (6.8 * 10^{-5})4.7 * 10^{13} * 6.8 * 10{-5}}\)

=\([Ag(S_{2}O_{3})_{2}^{3-}][Ag(S_{2}O_{3})_{2}^{3-}]\)

=\(3.196 * 10^{9}\) M.

The molar concentration of \(Na_{2}S_{2}O_{3}\)  is equal to the molar concentration of \([Ag(S_{2}O_{3})_{2}]^{3-}\). Therefore, the molar mass of \(Na_{2}S_{2}O_{3}\)  can be calculated as follows: \(Na_{2}S_{2}O_{3}\)  = \([Ag(S_{2}O_{3})_{2}]^{3-}\). × molar mass / volume of solution \([Ag(S_{2}O_{3})_{2}]^{3-}\). = 3.196 × 10−3 M (1 L = 1000 mL)

\(Na_{2}S_{2}O_{3}\) = \([Ag(S_{2}O_{3})_{2}]^{3-}\).

= 3.196 × 10−3 MC = n / Vn = C × Vn

=  \(Na_{2}S_{2}O_{3}\) × Molar mass of  \(Na_{2}S_{2}O_{3}\) (g/mol) × Vn

= 3.196 × 10−3 M × 158.11 g/mol × 1000 mLn

= 0.508 g or 0.115 g (rounded off to three significant figures).

Therefore, the mass of \(Na_{2}S_{2}O_{3}\)  needed to dissolve 4.7 g of AgBr in a solution volume of 1.0 L is 0.115 g (rounded off to three significant figures).

The mass of Na2S2O3 needed to dissolve 4.7 g of AgBr in a solution volume of 1.0 L is 0.115 g (rounded off to three significant figures).

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Answer:

There are three main types of rocks: sedimentary, igneous, and metamorphic. Each of these rocks are formed by physical changes—such as melting, cooling, eroding, compacting, or deforming—that are part of the rock cycle. Sedimentary Rocks Sedimentary rocks are formed from pieces of other existing rock or organic material. There are three different types of sedimentary rocks: clastic, organic (biological), and chemical. Clastic sedimentary rocks, like sandstone, form from clasts, or pieces of other rock. Organic sedimentary rocks, like coal, form from hard, biological materials like plants, shells, and bones that are compressed into rock. The formation of clastic and organic rocks begins with the weathering, or breaking down, of the exposed rock into small fragments. Through the process of erosion, these fragments are removed from their source and transported by wind, water, ice, or biological activity to a new location. Once the sediment settles somewhere, and enough of it collects, the lowest layers become compacted so tightly that they form solid rock. Chemical sedimentary rocks, like limestone, halite, and flint, form from chemical precipitation. A chemical precipitate is a chemical compound—for instance, calcium carbonate, salt, and silica—that forms when the solution it is dissolved in, usually water, evaporates and leaves the compound behind. This occurs as water travels through Earth’s crust, weathering the rock and dissolving some of its minerals, transporting it elsewhere. These dissolved minerals are precipitated when the water evaporates. Metamorphic Rocks Metamorphic rocks are rocks that have been changed from their original form by immense heat or pressure. Metamorphic rocks have two classes: foliated and nonfoliated. When a rock with flat or elongated minerals is put under immense pressure, the minerals line up in layers, creating foliation. Foliation is the aligning of elongated or platy minerals, like hornblende or mica, perpendicular to the direction of pressure that is applied. An example of this transformation can be seen with granite, an igneous rock. Granite contains long and platy minerals that are not initially aligned, but when enough pressure is added, those minerals shift to all point in the same direction while getting squeezed into flat sheets. When granite undergoes this process, like at a tectonic plate boundary, it turns into gneiss (pronounced “nice”). Nonfoliated rocks are formed the same way, but they do not contain the minerals that tend to line up under pressure and thus do not have the layered appearance of foliated rocks. Sedimentary rocks like bituminous coal, limestone, and sandstone, given enough heat and pressure, can turn into nonfoliated metamorphic rocks like anthracite coal, marble, and quartzite. Nonfoliated rocks can also form by metamorphism, which happens when magma comes in contact with the surrounding rock. Igneous Rocks Igneous rocks (derived from the Latin word for fire) are formed when molten hot material cools and solidifies. Igneous rocks can also be made a couple of different ways. When they are formed inside of the earth, they are called intrusive, or plutonic, igneous rocks. If they are formed outside or on top of Earth’s crust, they are called extrusive, or volcanic, igneous rocks. Granite and diorite are examples of common intrusive rocks. They have a coarse texture with large mineral grains, indicating that they spent thousands or millions of years cooling down inside the earth, a time course that allowed large mineral crystals to grow.

Alternatively, rocks like basalt and obsidian have very small grains and a relatively fine texture. This happens because when magma erupts into lava, it cools more quickly than it would if it stayed inside the earth, giving crystals less time to form. Obsidian cools into volcanic glass so quickly when ejected that the grains are impossible to see with the naked eye. Extrusive igneous rocks can also have a vesicular, or “holey” texture. This happens when the ejected magma still has gases inside of it so when it cools, the gas bubbles are trapped and end up giving the rock a bubbly texture. An example of this would be pumice.

Explanation:

oh and also nice profile pic :P

The best type of spoon for stirring hot liquid to prevent burns to a person's hand is a wooden spoon.

Wooden spoons are less conductive to heat than metal spoons, so they won't heat up as much as a metal spoon.

Wooden spoons are also less reactive to acidic liquids than metal spoons, so they won't affect the taste of the candy.

Furthermore, wood is non-reactive, which means it won't add any aftertaste or smell to your food when you use it to stir or mix anything.

Wooden spoons are a great choice because they are not as heavy as metal spoons, which can be uncomfortable to hold for a long time while stirring hot liquid.

Wooden spoons are also better for nonstick pans because they won't scratch the surface like metal spoons do.

Lastly, wooden spoons are very versatile and can be used for everything from stirring soups and stews to mixing cakes and batters, making them a must-have kitchen utensil.

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The complete question id-

A recipe for candy requires that the liquid ingredients be stirred constantly until the liquid reaches a temperature of 140°C. What type of spoon, either wood or metal, would be more suitable to prevent burns to a person's hand while stirring the hot liquid? Please explain your choice, taking into consideration the properties of wood and metal.

Explanation

NH4Cl(s) = NH4+(aq) + Cl-(aq) AH = +3.5 kcal/mole

We have some changes that shift the equilibrium to the right, according to Le Châtelier's principle.

I will write some of them:

By Adding amount of NH4Cl or by increasing the temperature because according to the heat of the reaction this is an endothermic reaction.

Answer: Increasing the temperature of the system.

Answer:

The specific heat of the sample unknown metal is approximately 0.45 J/g °C.

General Formulas and Concepts:
Thermodynamics

Specific Heat Formula: \(\displaystyle q = mc \triangle T\)

Explanation:

Step 1: Define

Identify variables.

m = 112 g

ΔT = 20.0 °C

q = 1004 J

Step 2: Solve for c

∴ specific heat capacity c is equal to around 0.45 J/g °C.

---

Topic: AP Chemistry

Unit: Thermodynamics

Answer:

deforestation decreases biodiversity of the forest ecosystem

Explanation:

Deforestation has to do with the process of felling trees. This process destroys forest ecosystems. Deforestation is normally carried out for the purpose of development.

An ecosystem is a self supporting unit in which living and non living things interact. The different species of plants and animals found in an ecosystem is called biodiversity.

Since organisms in an ecosystem interact among each other and with their non-living environment, destruction of the trees in the forest ecosystem leads to the loss of certain species present in the ecosystem.

For instance, climbers and animals found on tree tops are normal components of a forest ecosystem. When trees are felled and the forest ecosystem is destroyed across the world, these organisms are threatened. This leads to loss of species or loss of biodiversity.

Answer:

Here’s one possible answer:

Deforestation will likely decrease the biodiversity of the forest ecosystem. It reduces the living space and food sources for some of the organisms. Scarcity of space and food may be a threat to the population of those organisms. Over time, some species may die off, leaving fewer species in the forest.

Explanation:

To calculate the numerical change in vapor pressure with a change in temperature using the Clausius-Clapeyron equation, you need the heat of vaporization and the gas constant, R.

The Clausius-Clapeyron equation is a useful tool for estimating the change in vapor pressure with temperature. It requires the following quantities: the heat of vaporization (ΔHvap), which represents the energy needed to convert a substance from liquid to vapor at a constant temperature, and the gas constant (R), which is a fundamental constant with a value of 8.314 J/mol·K. Assuming both the initial and final temperatures are known, the equation allows you to calculate the numerical change in vapor pressure. Therefore, the two quantities needed to calculate the change in vapor pressure with temperature using the Clausius-Clapeyron equation are the heat of vaporization and the gas constant, R.

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Answer:

CHCl₃

Explanation:

We have the following data:

C = 5.03 g

H = 0.42 g

Cl= 44.5 g

First, we divide each mass by the molar mass (MM) of the chemical element to calculate the moles:

MM(C) = 12 g/mol

moles of C = mass/MM(C) = 5.03 g/(12 g/mol) = 0.42 mol C

MM(H) = 1 g/mol

moles of H = mass/MM(H) = 0.42 g/(1 g/mol) = 0.42 mol H

MM(Cl) = 35.4 g/mol

moles of Cl = mass/MM(Cl) = 44.5 g/(35.4 g/mol) = 1.26 mol Cl

Now, we divide the moles by the smallest number of moles (0.42):

0.42 mol C/0.42 = 1 C

0.42 mol H/0.42 = 1 H

1.26 mol Cl/0.42 = 3 Cl

Thus, the C:H:Cl ratio is 1:1:3.

Therefore, the empirical formula is CHCl₃

Answer:

CHCl₃

Explanation:

Answer:

i think c

Explanation:

Answer:

Average atomic mass  = 32 amu

Explanation:

Given data:

Abundance of X-30.00 amu = 30%

Abundance of X-32.00 amu = 50%

Abundance of X-35.00 amu = 20%

Average atomic mass = ?

Solution:

Average atomic mass  = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  +(abundance of 3rd isotope × its atomic mass)  / 100

Average atomic mass  = (30×30)+(50×32)+(20×35) /100

Average atomic mass =  900 + 1600 +700 / 100

Average atomic mass = 3200 / 100

Average atomic mass  = 32 amu.

A hydrocarbon that contains four carbon atoms with single bonds is a butane. In this case, its name has to end with -one because it contains a ketone functional group. Therefore, its name is butanone.

The structural form of the butanone is

Given that the compound is formed by Carbon, Oxygen, and Hydrogen molecular compounds because they are formed by nonmetals.

The cell potential (Ecell) of the zinc-air battery at 25.0 degrees Celsius and a partial pressure of oxygen of 0.15 atm is 1.65 V.

To calculate the cell potential (Ecell) of the zinc-air battery at 25.0 degrees Celsius, we can use the Nernst equation, which relates the cell potential to the standard cell potential and the concentrations or pressures of the reactants:

\(E_{\text{cell}} = E^{\circ}_{\text{cell}} - \left(\frac{RT}{nF}\right) \ln(Q)\)

Where:

E°cell is the standard cell potential (given as 1.65 V)

R is the ideal gas constant (8.314 J/(mol·K))

T is the temperature in Kelvin (25.0 + 273.15 = 298.15 K)

n is the number of electrons transferred in the balanced cell reaction (2 in this case)

F is Faraday's constant (96485 C/mol)

Q is the reaction quotient

In this case, since we are given the partial pressure of oxygen (O2) in the air diffusing through the cathode (0.15 atm), we can use the partial pressure as a substitute for concentration.

The reaction quotient (Q) can be calculated using the partial pressures of the reactants and products (ZnO):

\(Q = \frac{{(P(\text{ZnO}))^2}}{{P(\text{O}_2)}}\)

Plugging in the values into the Nernst equation, we have:

Ecell = 1.65 V -\(\frac{{8.314 \, \text{J/(mol}\cdot\text{K)}} \times 298.15 \, \text{K}}}{{2 \times 96485 \, \text{C/mol}}} \right) \ln \left( \frac{{(P(\text{ZnO}))^2}}{{P(\text{O}_2)}} \right)\)

Let's calculate the cell potential (Ecell) using the given values:

Ecell = 1.65 V -\({{8.314 \, \text{J/(mol}\cdot\text{K)}} \times 298.15 \, \text{K}}}{{2 \times 96485 \, \text{C/mol}}} \right) \ln \left( \frac{{(0.15 \, \text{atm})^2}}{{0.15 \, \text{atm}}} \right)\)

Simplifying the equation further:

\(E_{\text{cell}} = 1.65 \, \text{V} - (0.0257 \, \text{V}) \ln \left( \frac{{0.15^2}}{{0.15}} \right)\)

Calculating the natural logarithm:

\(E_{\text{cell}} = 1.65 \, \text{V} - (0.0257 \, \text{V}) \ln(1)\)

Since ln(1) is equal to 0:

Ecell = 1.65 V - (0.0257 V) * 0

Ecell = 1.65 V

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Answer:

The new volume of the gas is 29.57 Liters

Explanation:

Given;

initial pressure of gas, P₁ =  12 atm

initial volume of gas, V₁ = 23 Liters

initial temperature of gas, T₁ = 200 K

final pressure of gas, P₂ =  14 atm

final temperature of gas, T₂ = 300 K

final volume of gas, V₂ = ?

To determine the final volume of the gas, we apply general gas law;

\(\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}\\\\V_2 = \frac{P_1V_1T_2}{T_1P_2}\\\\V_2 = \frac{12*23*300}{200*14}\\\\V_2 = 29.57 \ Liters\)

Therefore, the new volume of the gas is 29.57 Liters

Explanation:

I think pebbles because the pebbles can be different sizes and have bigger gaps in between them so the water will go through quicker.

hope this helps srry if wrong