Answer:
Volume equals to thrice the length. \([V] = [L]\times [L]\times [L]\)
Explanation:
Dimensionally speaking, volume equals to thrice the length. That is:
\([V] = [L]\times [L]\times [L]\)
PLEASE HELP
atoms are split at power plant to create electricity
A. radiant to mechanical
B. nuclear to electrical
C. chemical to radiant
D. mechanical to electrical
Answer:
C. nuclear to electrical
Answer:
c its c noob
Explanation:
23. As the frequency of a wave increases, the period of the wave
Answer: decreases
Explanation: As frequency increases the period of a wave decreases because they have an inverse relationship. The equation for wave period (T) is the inverse of the frequency (f). So, as frequency increases, the value for period will decrease accordingly.
What exerts pressure in all directions?
Answer: Gases
Explanation: Gases don't have a certain direction, so they go in all directions.
Explain how series circuits use current and voltage and Explain how parallel circuits use current and voltage
'''In a series circuit, the sum of the voltages consumed by each individual resistance is equal to the source voltage. Components connected in parallel are connected along multiple paths so that the current can split up; the same voltage is applied to each component.''
a type of reaction that produces an increase in temperature is called?
Answer: Exothermic
Explanation:
An exothermic reaction causes an increase in temperature. This is because the energy released when the bonds are broken among the reactants is greater than than the energy absorbed when new bonds are formed among the products. This leftover energy gets passed along to the surroundings, where it produces a measurable increase in heat.
the rate constant for this first-order reaction is 0.0422 s−1 at 300 °c. if the initial mass of a is 19.10 g, calculate the mass of a remaining after 0.816 min.
The mass of A remaining after 0.816 min is 9.42 g.
Convert the temperature to Kelvin: 300 °C + 273.15 = 573.15 K.
Use the following equation to calculate the rate constant (k) at the given temperature:
ln(k2/k1) = (Ea/R) x ((1/T1) - (1/T2))
where k1 is the rate constant at a reference temperature (usually 298 K), k2 is the rate constant at the given temperature, Ea is the activation energy of the reaction, R is the gas constant (8.314 J/mol.K), T1 is the reference temperature in Kelvin, and T2 is the given temperature in Kelvin.
Assuming the activation energy (Ea) to be 100 kJ/mol, we get:
ln(k/0.0422) = (100000/8.314) x ((1/298) - (1/573.15))
k = 0.159 s^-1
Use the first-order rate equation to calculate the amount of A remaining after 0.816 min:
ln(Nt/No) = -kt
where Nt is the amount of A remaining after time t, No is the initial amount of A, k is the rate constant, and t is the time elapsed.
Substituting the given values, we get:
ln(Nt/19.10) = -0.159 x (0.816 x 60)
Nt = 9.42 g
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1. A cannon launches a shell with mass 100 kg toward a target. When the shell is at a height of 12 m its
velocity is 45 m/s. What is total mechanical energy of the shell?
Potential energy plus kinetic energy are combined to form mechanical energy. According to the principle of mechanical energy conservation, mechanical energy is constant in an isolated system when only conservative forces are acting on it.
E mechanical = U + K
E mechanical = mechanical energy
U = potential energy
K = kinetic energy
Mechanical energy, also known as kinetic energy or potential energy, is the energy that an object possesses when it is in motion or the energy that an object stores due to its location.
Renewable energy is also fueled by mechanical energy. In order to efficiently produce electricity or convert energy, many sources of renewable energy depend on mechanical energy.
Applying,
Mechanical Energy (M.E.) = ((1/2)mv²) + (m × g × h)
= ((1/2)*100*45²)+(100*9.8*12)
= 101250+ 11760
= 113010 J
m is the object's mass, v is its speed, g is its gravitational acceleration, and h is its height above the ground.
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One object has a mass of 1 kg and another object has a mass of 3 kg. If the speeds are the same, which of the following is true about their kinetic energy?
Their masses are the same.
The object with a higher mass has three times the kinetic energy of the less massive object.
It is impossible to determine without the speeds.
The object with a smaller mass has a greater kinetic energy than the object with a higher mass.
Answer:
The object with a higher mass has three times the kinetic energy of the less massive object.
We know that K.E.= 1/2 mv²
mass of first object = 1kg
speed = v
So K.E. = 1/2mv²
= 1/2 × (1) × v²
=
\( \: \: \: \: \: \: \: \: \: = \frac{1}{2} {v}^{2} \\ \)
Now the mass of second body = 3kg
speed = v
So K.E. = 1(3)v²/2
=
\( \: \: \: \: \: \: \: \: \: = \: \: \frac{3}{2} {v}^{2} \\ \)
now
K.E of first / KE of 2nd
\( \frac{1}{2} {v}^{2} \div \frac{3}{2} {v}^{2} \\ \)
\(\frac{ \frac{ke \: of \: first \: }{ - - - - - - - - - - -} }{ \frac{ke \: of \: 2nd}{} } = \frac{ \frac{1}{ - -} }{ 3 } \\ \\ so \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ 3(ke \: of \: first \:) = ke \: of \: 2nd\)
how can we take advantage of waste materials
Answer:
we can incinerate waste materials and use the product as fuel rather than dumping them. It may produce carbon dioxide but we can create a machine that can convert carbon into energy.
Using the Skygazer's Almanac for 2022 at 40 degrees.
What day will Venus and Saturn be in opposite parts of the sky
this year?
According to the Skygazer's Almanac for 2022 at 40 degrees, Venus and Saturn will be in opposite parts of the sky on December 17, 2022.
The Skygazer's Almanac provides astronomical information for a specific location and year. In this case, at a latitude of 40 degrees, the almanac indicates that Venus and Saturn will be in opposite parts of the sky on December 17, 2022. This means that Venus and Saturn will appear at opposite sides of the celestial sphere as observed from Earth. However, it's important to note that the almanac's predictions are approximate and can be influenced by various factors, including atmospheric conditions and the observer's specific location. To obtain the most accurate and up-to-date information, it is recommended to consult more recent astronomical sources or use specialized software that can provide precise positions and dates for celestial events.
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What is leptin released by and how would you predict the levels of leptin to be in nicole when compared to a healthy, female adult of similar age and weight?.
Leptin is released by adipocytes, and I predict that the levels of leptin would be decreased in Nicole when compared to a healthy, female adult of similar age and weight.
The body regulates itself in two ways, neural signals and hormones. Hormones are chemical messengers released by endocrine glands into the blood stream that carry out a particular function in the body. The hormone that regulates appetite and body weight is leptin.
Leptin is released by fat storing cells in the body called adipocytes. The word 'leptin' comes from a Greek word 'leptos' meaning 'fat controller', perfectly fitting its function. Since leptin is stored in the fat tissues, a person's weight has a direct effect on the levels of leptin in a person. When we lose weight, the amount of leptin circulating in the body decreases, leading to more appetite and weight gain.
A lack of leptin in the body, arising from genetic diseases results in uncontrolled appetite and obesity. Generally, female adults also produce less leptin than male adults
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The photon energy range covers five orders of magnitude. Which has the highest energy?
The photon energy range covers a wide span, and the highest energy photons are found in the gamma-ray portion of the electromagnetic spectrum.
Gamma rays have the highest energy among all photons, and their energy range extends to the highest values within the electromagnetic spectrum.
Gamma rays have energies typically on the order of kiloelectron volts (keV) to megaelectron volts (MeV), or even higher in certain cases.
The energy range of photons spans from radio waves (with energies in the range of microelectron volts, or μeV) to gamma rays (with energies reaching into the giga-electron volts, or GeV).
Thus, the highest energy photons can be found within the gamma-ray portion, at the higher end of the electromagnetic spectrum.
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A piece of equipment belonging to an astronaut has a mass of 2 kg on the surface of the Moon. What is its weight on the Moon?
Answer:
brainliest plss
Explanation:
a car has a mass of 1200 kg. what would be its weight on earth?
Answer:
11772 N
Explanation:
\(\boxed{w = mg}\)
w= weight
m= mass
g= acceleration due to gravity
The acceleration due to gravity on earth is 9.81m/s².
Substitute m= 1200 and g= 9.81 into the formula:
w= 1200(9.81)
w= 11772 N
1.
Give the number of significant figures in the following:
5
A.
2.9910 x 10 m
C.
.0405 ml
B.
4500 km
D.
2.000 m
4
Answer:
It's B .0405 I just did this
Explanation:
ur welcome
how much time is there between when a star rises and when it sets?
The amount of time between when a star rises and when it sets depends on the star's declination and the observer's latitude. On average, a star takes around 12 hours to complete its journey across the sky.
The time between when a star rises and sets depends on the star's declination, which is its angular distance north or south of the celestial equator, and the observer's latitude. Stars with a declination close to the celestial equator will take the shortest amount of time to complete their journey across the sky, while stars with a declination closer to the celestial pole will take the longest. This is because stars closer to the pole have a smaller apparent motion across the sky.
On average, a star takes around 12 hours to complete its journey across the sky, from rising in the east to setting in the west. This means that for half of the day, a particular star will be visible in the sky, and for the other half of the day, it will be below the horizon. However, the exact amount of time between when a star rises and when it sets will vary depending on the star's declination and the observer's latitude. For example, at the equator, a star with a declination of 0 degrees will take about 12 hours to complete its journey across the sky, while at the North Pole, the same star will be visible for the entire 24-hour period.
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What is an effect of continental drift?
Answer: An effect of continental drift is causing tectonic plates resting upon the convecting mantle to move which results in natural disasters like earthquakes, volcanic eruptions, and more.
An eagle carrying a trout flies above a lake along a horizontal path. The eagle drops the trout from a height of 6.1 m. The fish travels 7.9 m horizontally before hitting the water.
What is the velocity of the eagle? Round at the end of the calculation to the nearest tenth
The velocity of the eagle is 12.4 m/s
What is velocity?Velocity is the rate of change of displacement.
The S.I unit of velocity is m/s.
To calculate the velocity of the eagle, we use the formula below.
Formula:
v² = u²+2gs.......... Equation 1Where:
v = Final velocityu = Initial velocityg = acceleration due to gravitys = DistanceFrom the question,
Given:
u = 0 m/sg = 9.8 m/s²s = 7.9 mSubstitute these values into equation 1
v² = 0²+2×9.8×7.9v² = 154.84v² = √(154.84)v = 12.4 m/sHence, the velocity of the eagle is 12.4 m/s.
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Which of the following statements is true?
1.Heat is transferred in solids by convection.
2.Both liquids and gases are fluids.
3.Temperature is the same as heat.
4.Objects moving through air don't experience friction.
Explain why a pencil falls to the floor instead of toward the person who dropped it.
Explanation:
The gravitational pull of the earth (VERY large mass) is greater than YOUR gravitational pull on the pencil
Force of gravity = G m1m2/ r^2
G = constant m1 = pencil mass m2 = earth (or you)
r = distance between the objects)
NEED HELP URGENT!!!
These 2
Answer:
Acceleration & 9.8 M/S/S
Explanation:
Pretty self explanatory for question 2, speeding up can easily be related to acceleration, and for question 3
"Its value is 9.8 m/s2 on Earth. That is to say, the acceleration of gravity on the surface of the earth at sea level is 9.8 m/s2. When discussing the acceleration of gravity, it was mentioned that the value of g is dependent upon location. There are slight variations in the value of g about earth's surface."
Hope it helped - rida
when electromagnetic radiation (e.g., light) is doppler-shifted by motion of the source away from the detector the
When electromagnetic radiation is Doppler-shifted by motion away from the detector, the observed wavelength increases.
What causes Doppler shift effect?When an object emitting electromagnetic radiation, such as light, is moving away from an observer (detector), the wavelengths of the observed radiation are stretched or increased.
This phenomenon is known as the Doppler shift. It occurs because the motion of the source affects the perceived frequency or wavelength of the radiation. When the source is moving away, the observed wavelength is longer compared to the emitted wavelength.
This effect can be observed in various contexts, such as the redshift observed in the light from distant galaxies, indicating their recession from us due to the expansion of the universe.
Additionally, it is relevant in understanding the behavior of stars, galaxies, and other astronomical objects. By analyzing the Doppler shift, scientists can infer important information about the motion and velocity of celestial objects.
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An object is taken to Mars. It’s mass is 15kg, it’s weight on Mars is 55.5N
What is the gravitational field strength on Mars?
Answer:
Approximately \(3.7\; {\rm N \cdot kg^{-1}}\) (or equivalently, \(3.7\; {\rm m\cdot s^{-2}}\).)
Explanation:
Gravitational field strength measures the force (weight) that the field exerts on object of unit mass (e.g., \(1\; {\rm kg}\).)
Divide the weight of the object by its mass to find the gravitational field strength at the position.
In this question, \(\text{weight} = 55.5\; {\rm N}\) while \(\text{mass} = 15\; {\rm kg}\). Therefore, the gravitational field strength will be:
\(\begin{aligned} & (\text{gravitational field strength}) \\ =\; & \frac{(\text{weight})}{(\text{mass})} \\ =\; & \frac{55.5\; {\rm N}}{15\; {\rm kg}} \\ =\; & 3.7\; {\rm N \cdot kg^{-1}} \end{aligned}\).
why does a person feel weightless during a free fall
Freud believes that defense mechanisms are reactions people have to protect themselves from uncomfortable feelings. the article ""high on anxiety"" suggests that some people want to feel __________ instead of calm because that’s the feeling they’re used to operating under. a. anxious b. happy c. excited d. angry please select the best answer from the choices provided a b c d
Answer:
A: Anxious
Explanation:
got a 100% of Edge
A ball is projected horizontally with a velocity of 1.5 m/s from a cliff as
shown. The ball hits the ground 1.22 s after it leaves the cliff. The effects of air resistance are negligible. Identify which row in the table shows the horizontal velocity, vertical velocity and the vertical displacement of the
ball just before it hits the ground.
The correct answer is C.
The ball is projected horizontally with a velocity of 1.5 m/s from a cliff and the ball hits the ground 1.22 s after it leaves the cliff.
We need to find out which row in the table shows the horizontal velocity, vertical velocity and the vertical displacement of the ball just before it hits the ground.
So, we know that,
u = 1.5 m/s (horizontal velocity) and
t = 1.22 s.
Now, horizontal distance covered by the ball,
S = ut=1.5×1.22=1.83 m.
So, we can conclude that at the time of hitting the ground, the horizontal displacement of the ball is 1.83m.
The vertical velocity at the time of hitting the ground can be calculated as:
v = u + gtw
here g = 9.8 m/s² (acceleration due to gravity)
v = 0 + 9.8(1.22)
v = 11.956 m/s
The ball is dropped from rest, so the initial vertical velocity is 0.
The time taken to hit the ground is t = 1.22 s.
The vertical displacement at the time of hitting the ground can be calculated as:
s = ut + 0.5gt²
s = 0 + 0.5(9.8)(1.22)²
s = 7.45 m
So, the row (c) in the table shows the horizontal velocity, vertical velocity and the vertical displacement of the ball just before it hits the ground.
Hence, the correct option is (c) (1.5 m/s, -11.96 m/s, 7.45 m).
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An 80.0 N force accelerates a 6.0 kg object from 4.0 m/s to 8.0 m/s. What is the
impulse?
0 24 N"s
0 3.33 Nºs
30 N's
0 -30 N's
0-24 N's
Answer:
24kgm/s
Explanation:
Given parameters:
Force = 80N
Mass of object = 6kg
Initial velocity = 4m/s
Final velocity = 8m/s
Solution:
Impulse = ?
Solution:
The impulse on a body is its change in momentum.
Impulse = m (v - u )
m is the mass
v is the final velocity
u is the initial velocity
Now insert the parameters and solve;
Impulse = 6 (8 - 4) = 24kgm/s
the faceplate of a diving mask can be ground into a corrective lens for a diver who does not have perfect vision. the proper design allows the person to see clearly both under water and in the air. normal eyeglasses have lenses with both the front and back surfaces curved. how should the lenses of a diving mask be curved? on the inner surface only on both surfaces on the outer surface only
The lenses of a diving mask are curved on the inner surface only
The primary goals of treated lenses are to either protect your eyes from surface glare or enhance colors underwater. As divers we learn that water absorbs light as we go deeper, these anti-reflective coatings further improve light transmittance into the mask, thus increasing brightness also The lenses of a diving mask are curved on the inner surface only.
This is great for divers who spend a lot of time on the surface or divers who like to appreciate enhanced colors underwater – photographers will also appreciate the glare reduction underwater. The tint of the treatment in some masks makes it hard for you to see the diver's eyes – so for instructors, tinted masks aren’t usually their go-to, as their students won’t be able to see their eyes.
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does increased atmospheric pressure increase or decrease the boiling point of water? why?
Answer:
Increased atmospheric pressure will increase the boiling point of water
Water vapor has liquid phase and a vapor phase
As pressure is increased vapor particles will return to the liquid phase
An oversimplified view is to consider the activity of individual molecules of water - when molecules of water are heated they are more active and more likely to escape from the liquid phase to the vapor phase
The Physics of Energy | 1st Edition Chapter 31, Problem 1P Compute the pressure at a depth Z below the surface in a reservoir behind a hydroelectric dam. Compute the work done by a volume of water as it passes from this pressure on one side of a turbine to essentially zero pressure on the other side. Show that this analysis yields the same formula (31.2)[P = e * dV/dt = rho * g * Z * e * Q] for the power output as the energy analysis presented in §31.1.1.
The analysis using pressure and work yields the same formula for power output as the energy analysis presented in §31.1.1.
To compute the pressure at a depth Z below the surface in a reservoir behind a hydroelectric dam, we can use the formula for hydrostatic pressure: P = rho * g * Z, where rho is the density of water, g is the acceleration due to gravity, and Z is the depth below the surface.To compute the work done by a volume of water as it passes from this pressure on one side of a turbine to essentially zero pressure on the other side, we can use the formula for work: W = P1 * V1 - P2 * V2, where P1 and P2 are the pressures on either side of the turbine, and V1 and V2 are the volumes of water on either side.We can substitute the expression for P1 in terms of Z and simplify the expression to obtain: W = rho * g * Z * e * Q, where e is the efficiency of the turbine and Q is the volume flow rate of water through the turbine.This expression for work is the same as the formula for power output presented in §31.1.1, which is P = e * dV/dt, where dV/dt is the rate of change of volume flow rate with time. By equating the two expressions for work and power output, we obtain the formula for power output in terms of pressure and volume flow rate: P = rho * g * Z * e * Q. Therefore, the analysis using pressure and work yields the same formula for power output as the energy analysis presented in §31.1.1.For more such question on power
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