Because of their different longitude.
Example of a computer using energy
Answer: Booting up the computer: When you turn on the computer, it requires a burst of energy to start up the various components and initialize the operating system.
Explanation:
Calculate the osmotic pressure of 5.0g of sucrose ssolution in 1L. Answer should be in Torr
Answer: The osmotic pressure of 5.0g of sucrose solution in 1 L is 271.32 torr.
Explanation:
Given: Mass = 5.0 g
Volume = 1 L
Molar mass of sucrose = 342.3 g/mol
Moles are the mass of a substance divided by its molar mass. So, moles of sucrose are calculated as follows.
\(Moles = \frac{mass}{molarmass}\\= \frac{5.0 g}{342.3 g/mol}\\= 0.0146 mol\)
Hence, concentration of sucrose is calculated as follows.
\(Concentration = \frac{moles}{Volume (in L)}\\= \frac{0.0146 mol}{1 L}\\= 0.0146 M\)
Formula used to calculate osmotic pressure is as follows.
\(\pi = CRT\)
where,
\(\pi\) = osmotic pressure
C = concentration
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into above formula as follows.
\(\pi = CRT\\= 0.0146 \times 0.0821 L atm/mol K \times 298 K\\= 0.357 atm (1 atm = 760 torr)\\= 271.32 torr\)
Thus, we can conclude that the osmotic pressure of 5.0g of sucrose solution in 1 L is 271.32 torr.
An ion has 38 protons, 36 electrons, and 40 neutrons, what us the elements symbol
The symbol of the element in which it's ion has 38 protons, 36 electrons, and 40 neutrons is ⁷⁸₃₈Sr
How do I determine the symbol of the element?To obtain the symbol of the element, we shall obtain the mass number of the element. This is shown below:
Proton = 38Neutron = 40Mass number = ?Mass number = Proton + Neutron
Mass number = 38 + 40
Mass number = 78
Finally, we shall determine the symbol of the element. Details below:
Proton = 38Atomic number (z) = Proton = 38Mass number (A) = 78Symol of element =?From the periodic table, the element with atomic number of 38 is Strontium.
Thus, the symbol of the element will be ⁷⁸₃₈Sr
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How many moles of aluminum oxide will be produced from 0.50 mol of oxygen?
4 Al + 3 O2→ 2 Al2O3
Answer:
\(\boxed {\boxed {\sf \frac {1}{3} \ mol \ Al_2O_3 \approx 0.34 \ mol \ Al_2O_3}}\)
Explanation:
We will use stoichiometry to solve this problem. The reaction given has a formula of
\(4Al+3O_2 \rightarrow 2Al_2O_3\)
The coefficients tell us the number of moles necessary for the reaction.
The reaction requires 3 moles of oxygen to produce 2 moles of aluminum oxide. We can make a ratio.
\(\frac {3 \ mol \ O_2}{ 2\ mol \ Al_2O_3}}\)
Since we are doing the reaction with 0.5 moles of oxygen, we multiply the ratio by that number.
\(0.5 \ mol \ O_2 *\frac {3 \ mol \ O_2}{ 2 \ mol \ Al_2O_3}}\)
Flip the ratio so the moles of oxygen cancel each other out.
\(0.5 \ mol \ O_2 *\frac {2 \ mol \ Al_2O_3}{ 3 \ mol \ O_2}}\)
\(0.5 *\frac {2 \ mol \ Al_2O_3}{ 3 }\)
\(\frac {1 \ mol \ Al_2O_3}{ 3 }\)
\(\frac {1}{3} \ mol \ Al_2O_3 = 0.33333 \ mol \ Al_2O_3 \approx 0.34 \ mol \ Al_2O_3\)
0.5 moles of oxygen produces 1/3 or approximately 0.34 moles of aluminum oxide.
Choose the answer that describes the hierarchy among these three body regions.
A. The oral region is part of the facial region, and the facial region is part of the cephalic region.
B. The cephalic region is part of the facial region, and the facial region is part of the oral region.
C. The cephalic region is part of the facial region, and the facial region is part of the manual region.
D. The oral region is part of the cephalic region, and the cephalic region is part of the facial region.
Answer:
letter: B
Explanation:
thats is the true answer.
pleas heart my heart my answer
Electron configuration worksheet
Answer:
bro please rotate it and send again please
Tellurium is a period 5 chalcogen. Selenium is a period 4 chalcogen. If the only factor affecting ionization energies was the nuclear charge, then electrons would be easier to remove (ionize) from Se than Te. Experimentally the opposite is true. It takes 941.0 kJ/mol of energy to ionize the outermost electron from Se while it only takes 869.3 kJ/mol to ionize from Te. A good model should account for this. Quantum mechanical calculations do predict this but require access to sophisticated software, large amounts of computing power and technical expertise. Slater suggested that some simple empirical rules that take into account electron electron repulsion (or shielding) could give a good estimate of the effective nuclear charge (Zeff). The Zeff for the outermost electron in Te is . The Zeff for the outermost electrons in Se is . According to Slater's calculation of effective nuclear charge (does or does not) predict the correct ordering of ionization energies for Se and Te. A better means of rationalizing ionization energies is to include the atomic as follows: [Z subscript e f f end subscript over r squared] . For Te, r = 136 pm and for Se r = 117 pm. This new model (does or does not) predict the correct ordering of first ionization energies for Se and Te.
Answer:
yes
Explanation: took quiz
The main assumptions of the Kinetic Molecular Theory of gases are:
1. Gases are made up of molecules which are relatively far apart.
2. The molecules are in motion at high speeds.
3. The molecules are perfectly elastic.
4. Increase in temperature increases the kinetic energy of the molecules.
The assumption that accounts for the great compressibility of gases compared to liquids and solids is:
1
2
3
4
none
The assumption that accounts for the great compressibility of gases compared to liquids and solids is assumption 1: Gases are made up of molecules which are relatively far apart. Option A)
The assumption that accounts for the great compressibility of gases compared to liquids and solids is assumption 1: Gases are made up of molecules which are relatively far apart.
In gases, the molecules are widely spaced and have significant gaps between them. This allows gases to be easily compressed under pressure. When external pressure is applied to a gas, the molecules can be brought closer together, reducing the volume occupied by the gas. The gaps between the molecules provide room for compression, allowing gases to occupy a smaller volume.
In contrast, liquids and solids have molecules or particles that are closely packed together. The intermolecular forces in liquids and solids are stronger, limiting their compressibility. The molecules or particles are already in close proximity, leaving little room for further compression.
Therefore, the assumption that gases consist of molecules that are relatively far apart accounts for their greater compressibility compared to liquids and solids. Hence Option A) is correct.
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Solve this whole experiment,
I'll be so glad . thanks
●do the above experiment
●give detailed answers
THANKS
One kilogram is the same as
Answer:
1000 grams
Explanation:
Kilo- is the SI prefix meaning 1000. So, 1 kilogram is the same as 1000 grams.
What amount of energy is required to change a spherical drop of water with a diameter of 1.20 mm to three smaller spherical drops of equal size? The surface tension, , of water at room temperature is 72.0 mJ/m2
.
7.0329 x10 mm] -4.43x104m√ = 2. * 6029 * Ten ^ - 4 * m I Water has a surface tension of 72.0 mJ/m2 at normal temperature.
What kind of energy is needed to transform a water drop with a 2.20 mm diameter into four smaller drops with the same size?
At room temperature, water has a surface tension of 72.0 mJ/m2.
I'll try it out even if it seems like a physics challenge rather than a chemical one.
Surface area of the sphere equals 4 r2.
Radius, diameter, and volume of sphere are equal to (4/3)r3 2.20 mils = 1.10 mils
The four new droplets' surface tension differences with the original droplet are?
The energy needed to complete the specified task would be 0.00173 mary jane - 0.00114 w / mk = 0.00059 mary jane = 5.9x10-4 mJ.
(NOTE: I just saw Brian L's "comment," and this solution is in fact rather similar to his response of 6.4x10-4 mJ.)
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7.0329 x10 mm] -4.43x104m√ = 2. * 6029 * Ten ^ - 4 * m I Water has a surface tension of 72.0 mJ/m2 at normal temperature.
What kind of energy is needed to transform a water drop with a 2.20 mm diameter into four smaller drops with the same size?At room temperature, water has a surface tension of 72.0 mJ/m2.
I'll try it out even if it seems like a physics challenge rather than a chemical one.
Surface area of the sphere equals 4 r2.
Radius, diameter, and volume of sphere are equal to (4/3)r3 2.20 mils = 1.10 mils
The four new droplets' surface tension differences with the original droplet are?
The energy needed to complete the specified task would be 0.00173 mary jane - 0.00114 w / mk = 0.00059 mary jane = 5.9x10-4 mJ.
(NOTE: I just saw Brian L's "comment," and this solution is in fact rather similar to his response of 6.4x10-4 mJ.)
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Which of the following is TRUE if ΔEsys = -100 J?
The statement that is true if the ΔEsys = -100 J is that the system looses 100J of energy which is gained by the surroundings.
What is the energy of the system?Note that the study of energy is what we call thermodynamics. We should note that according to the laws of thermodynamics, energy can not be created nor destroyed but can be converted from one form to another.
This implies that the energy that is lost by the system must be gained by the surroundings since there can never be energy that goes to waste in the system.
Recall that the universe is composed of the system and the surroundings and the energy that is lost by the system must be gained by the surroundings and vice versa. This would now be our guide in deciding which statement is right above from what we have in the question here.
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Give the coefficient of y in the following expression. 2xz² - 7xy + 4.
Answer:
the coefficient of y is -7
A 0.15M solution of methylamine CH3NH2 contains an unknown concentration of methylamine chloride CH3NH3Cl. If the solution has a pH of 10.20,what is the concentration of methylamine chloride in the solution? Kb for methylamine=4.6*10^-4
Answer:
0.43 M
Explanation:
The equation that should be used in this case would be:
pOH = pKb + log([A+]/[Base])
pKb = -log (4.6*10^-4) = 3.34
pOH = 14-10.2 = 3.8
[Base] = 0.15
3.8 = 3.34 + log x/0.15
0.46=log x/0.15
10^(0.46) = x/.15
x = 10^(0.46) * 0.15 = 0.43 M
Which of these statements correctly describes the electronic charge distribution in a molecule? I. The charge density around each atom is the same as it is in the free atom. II. The electronic charge is distributed equally around each atom in the molecule. III. Electrons are attracted preferentially to atoms with high electronegativity. IV. Electronic charge density is enhanced in the space between atoms to form a bond. V. Electrons are always shared between atoms and never transferred from one atom to another. a. I only b. II and III only c. III and IV only d. II only e. V only
statement correctly describes the electronic charge distribution in a molecule-Option 2 The electronic charge is distributed equally around each atom in the molecule.
When charged matter is positioned in an electromagnetic field, it encounters a force due to its physical property of electrical charges. A positive or negative electric charge can exist (commonly carried by protons and electrons respectively). Like charges repel each other and, while unlike goods become more expensive one another. Coulomb, unit of electrical charges in the m long system, which serves as the foundation for the SI physical unit. C is the abbreviation. The coulomb is defined as the amount of electricity transferred in one second by a one-ampere current. Charge (exhibited by protons) and negative charge are indeed the two types of charge (exhibited by electrons.
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1 points
A bottle contains a mixture of two gases: Oxygen and Hellum. The partial pressure of O2 is 1.0 atm and the partial pressure of He is 100.0 mmHg. What is the total pressure in the tank? (Volume and temperature are
constant)
101 alm
011 atm
O 101 mmHg
O 1.1 mmHg
101 mmHg is the total pressure in the tank.
Thus, Dalton's Law of Partial Pressures states that while the volume and temperature of a gaseous mixture are held constant, the total pressure of the mixture is equal to the sum of the partial pressures of its gaseous components.
Nitrogen, oxygen, argon, carbon dioxide, water vapor, and a trace amount of other gases are all present in atmospheric air and pressure.
The increased oxygen content in the chamber can displace the CO bound to hemoglobin faster than air oxygen, hence the hyperbaric chambers are also used to treat carbon monoxide (CO) poisoning. The treatment of scuba divers with the bends is another application for hyperbaric chambers.
Thus, 101 mmHg is the total pressure in the tank.
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select the most appropriate condition(s) to turn a carboxylic acid into an alcohol. note: assume all reagents are in excess. one or more answers may be correct. group of answer choices lialh4 hcl, h2o k2cr2o7, h2so4 dibal-h hcl, h2o nabh4, meoh ch3mgbr hcl, h2o
The most appropriate condition to turn a carboxylic acid into an alcohol is: LiAlH₄ (lithium aluminum hydride), and NaBH₄ (sodium borohydride). Option A, and D are correct.
LiAlH₄ (lithium aluminum hydride) is a powerful reducing agent commonly used in organic chemistry for the reduction of a variety of functional groups, including aldehydes, ketones, esters, carboxylic acids, and others. LiAlH₄ is a strong reducing agent that can reduce carboxylic acids to alcohols.
The reaction proceeds via a four-electron reduction pathway and results in the formation of the corresponding alcohol. The mechanism involves the initial formation of an alkoxyalane intermediate, which undergoes a second reduction step to yield the alcohol product.
NaBH₄ (sodium borohydride) is a mild reducing agent commonly used in organic chemistry to reduce a variety of functional groups, including aldehydes, ketones, esters, and carboxylic acids. In the case of carboxylic acids, NaBH₄ reduces the carbonyl group (-COOH) to an alcohol group (-OH) by a two-electron reduction pathway, similar to LiAlH₄.
The reaction is usually carried out in aqueous or alcoholic solvents and requires the addition of a proton source (such as HCl or H₂SO₄) to activate the carboxylic acid before reduction.
Hence, A. D. is the correct option.
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--The given question is incorrect, the correct question is
"Select the most appropriate condition(s) to turn a carboxylic acid into an alcohol. note: assume all reagents are in excess. one or more answers may be correct. group of answer choices A) LiAlH₄ , B) K₂Cr₂O₇, C) DIBAL-H, D) NaBH₄, E) MeOH F) CH₃MgBr."--
In Natural selection, individuals whose unique characteristics are well-suited for an environment tend to survive and produce more offspring. true or false?
Answer: True
Explanation:
An error during which cellular process would create a gene mutation?
An error during DNA replication would create a gene mutation.
During DNA replication, the genetic information in a cell is copied to make new DNA molecules. However, mistakes can occur during this process, leading to changes in the DNA sequence, which can result in a mutation. Mutations can also be caused by exposure to environmental factors, such as radiation or chemicals, which can damage the DNA molecule directly or affect the cellular processes involved in DNA replication.
Mutations can have a variety of effects on the organism, ranging from no effect to causing serious health problems or even death. Gene mutations can also be inherited from a parent, which can result in genetic disorders or predisposition to certain diseases. Therefore, it is important to understand the mechanisms of gene mutations and their potential impacts on organisms.
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Why do scientific investigations lead to more questions?
O A. Scientists cannot answer questions.
B. Scientists never agree about experiments.
C. Investigations are usually wrong.
O D. They uncover new information.
Answer: C. investigations are usually wrong
Explanation: Because investigation are usually wrong and then that leads to more and more questions
How do I go about solving a Nuclear Equation?
Answer:
How do amoeba respire.
How do plants respire.
What physical property describes the ability of a substance to dissolve?
Answer:
solubility
Explanation:
2,4-Dimethylpent-2-ene undergoes an electrophilic addition reaction in the presence of HBr to form 2-bromo-2,4-dimethylpentane. Complete the mechanism of this addition and draw the intermediates formed as the reaction proceeds.
Answer:
See figure 1
Explanation:
In this case, we have to start with the ionization reaction of HBr to produce the hydronium ion (\(H^+\)) and the bromide ion (\(Br^-\)). Then the double bond in the alkene can attack the hydronium ion to produce a carbocation. The most stable carbocation would be the tertiary one, therefore we have to put the positive charge in the tertiary carbon. Then, the bromide attacks the carbocation to produce the final halide.
See figure 1
I hope it helps!
Is each ion stable? Explain.
Answer:
By satisfying the duet rule or the octet rule, ions are more stable.
Explanation:
Ionic bonds are formed through the exchange of valence electrons between atoms, typically a metal and a nonmetal. The loss or gain of valence electrons allows ions to obey the octet rule and become more stable.
The octet rule states that an atom is most stable when there are eight electrons in its valence shell. Atoms with less than eight electrons tend to satisfy the duet rule, having two electrons in their valence shell. By satisfying the duet rule or the octet rule, ions are more stable.
I HOPE THIS HELPS!!!!
Which of the following 0.250 m solutions has the greatest freezing-point depression?
CH2O
CaCl2
KCl
Answer:
CaCl2
Explanation:
Cacl2 would have greatest freezing point depression because in this case the vant Hoff factor is 2
More will be the value of vant Hoff factor more will be the depression in freezing point when concentration of all electrolyte is same
C(s) + O2(g) → CO2(g) ΔHº = -94.6 kJ
H2(g) + \scriptsize \frac{1}{2}O2(g) → H2O(l) ΔHº = -286.0 kJ
2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O (l) ΔHº = -2598.8 kJ
calculate the value of ΔHº for the final reaction:
2C(s) + H2(g) → C2H2(g) ΔHº = kJ
The value of enthalpy(ΔHº) for the final reaction (2C(s) + H₂(g) → C₂H₂(g) ) is -1932.8KJ.
Enthalpy change: what is it?A system's enthalpy is its heat capacity. A reaction's enthalpy change is roughly equivalent to how much energy is lost or gained throughout the reaction. If the enthalpy of the system decreases over the reaction, the reaction is preferred.
C(s) + O₂(g) → CO₂(g) ΔHº = -94.6 kJ --- (1)
H₂(g) + O₂(g) → H₂O(l) ΔHº = -286.0 kJ ---(2)
2C₂H₂(g) + 5O₂(g) → 4CO₂(g) + 2H₂O (l) ΔHº = -2598.8 kJ ---(3)
The value of ΔHº for the final reaction,
2C(s) + H₂(g) → C₂H₂(g)
ΔH₄° = 2× ΔH₂º + ΔH₃º - ΔH₁º
ΔH₄° = 2× -286.0 + ( -2598.8) - (- 94.6)
ΔH₄° = 2× -286.0 -2598.8 + 94.6
ΔH₄° = 666 - 2598.8
ΔH₄° = -1932.8KJ.
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How much heat is needed to convert 40.0 grams of CH₃OH(s) at -97.53˚C to CH₃OH(l) at -43˚C?
The heat needed to convert 40.0 grams of CH₃OH (s) at -97.53˚C to CH₃OH (l) at -43˚C is equal to 5278.5 J.
What is the specific heat capacity?The specific heat capacity can be defined as the heat required to raise the temperature of one unit of mass by one degree Celsius. The specific heat capacity depends upon the type of material.
The mathematical form is used to calculate the specific heat is equal to:
Q = mCΔT
Given, the mass of the methanol, m = 40 g
The final temperature of the methanol, T₂ = -43°C
The change in temperature of methanol, ΔT = -43 + 97.53 = 54.53°C
The specific heat capacity of methanol, C = 2.5 J/g·°C
The heat required to change methanol temperature:
Q = 40 × 2.42 × 54.53
Q = 5278.5 J
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What are phytoplankton and what percentage of oxygen do they produce? (ASAP)
Answer:
They are plants also known as plankton and they produce about 80-85% of the world's oxygen.
Explanation:
A galvanic (voltaic) cell consists of an electrode composed of magnesium in a 1.0 M magnesium ion solution and another electrode composed of silver in a 1.0 M silver ion solution, connected by a salt bridge. Calculate the standard potential for this cell at 25 °C.
Answer:
3.17 V
Explanation:
The cell is operating under standard conditions. These standard conditions include; that the reaction takes place at 298 Kelvin (room temperature), the pressure of the system is 1 atmosphere (standard pressure), and the solutions have a Molarity of 1.0 M for both the anode and cathode solutions. All these conditions are satisfied in the cell under review in the question.
Hence;
E°anode (magnesium)= -2.37 V
E°cathode (silver) = 0.80 V
E°cell= E°cathode -E°anode
E°cell= 0.80-(-2.37)
E°cell= 0.80 + 2.37
E°cell= 3.17 V
Hence the standard cell potential of this cell at 25°C is 3.17 V
Answer:
The standard potential at 25ºC is 3.17 V.
Explanation:
The anode in a galvanic cell is the electrode at which oxidation occurs and the cathode is the electrode at which reduction occurs.
The overall cell reaction will be the sum of two half-cell reactions. The standard reduction potentials are:
Mg²⁺ (1.0 M) + 2e⁻ → Mg (s) Eº = -2.37
Ag⁺ (1.0 M) + e⁻ → Ag (s) Eº= +0.80
Since the reactants are in their standard states (1.0 M) and at 25ºC we can write the half-cell reactions as follows:
Anode (oxidation): Mg (s) → Mg²⁺ (1.0 M) + 2e⁻
Cathode (reduction): 2Ag⁺ (1.0 M) + 2e⁻ → 2Ag (s)
Overall: Mg (s) +2 Ag⁺ (1.0 M) + 2e⁻ → 2Ag (s) + Mg²⁺ (1.0 M) + 2e⁻
In order to balance the overall equation we multiply the reduction of Ag⁺ by 2. We can do so because, as an intensive property, E° is not affected by this procedure.
The standard emf of the cell, E°cell , which is composed of a contribution from the anode and a contribution from the cathode, is given by:
\( Eº cell = Eº cathode - Eº anode \)
\( Eº cell = EºAg⁺/Ag - Eº Mg²⁺/Mg \)
\( Eº cell =0.80 V - (-2.37 V) \)
Eº cell = 3.17 V
phytoplankton are well known for being the bottom of the food chain in the ocean, but they have a widespread impact on earth during blooms. nasa researchers and scientists who are part of north atlantic aerosols and marine ecosystems study, or naames are investigating all of the following except:
1.These seasonal plankton generally blooms which helps the world's great fisheries that takes massive amounts of oxygen in the ocean.
Phytoplankton are considered as microscopic plant organisms that thrives in the ocean they live in bottom of the marine food chain. They are considered for the production of oxygen and also helps in about half of the photosynthesis on Earth. Phytoplankton also blooms, with the rapid increase of the population of these organisms, they also have significant impacts on the environment.
North Atlantic Aerosols and Marine Ecosystems Study (NAAMES) is a research project which targets in the investigation of the complex and interactions between phytoplankton, aerosols, and the atmosphere .
The above question is incomplete
phytoplankton are well known for being the bottom of the food chain in the ocean, but they have a widespread impact on earth during blooms. nasa researchers and scientists who are part of north Atlantis aerosols and marine ecosystems study, or naames are investigating all of the following except:
1.These seasonal plankton generally blooms which helps the world's great fisheries that takes massive amounts of oxygen in the ocean.
2. Phytoplankton also release toxins which can cause harm to fish and other marine animals, and the decomposition of the dead phytoplankton can lead to oxygen .
3.The impacts of phytoplankton also blooms on the ocean's carbon cycle and the environmental composition.
Hence, 1 is the correct option
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