Answer:
1/81
Step-by-step explanation:
First, square 1/3 that gets you, 1/9, multiply by 3 again to get 1/27, again to get 1/81
During the 1990s, the forested area of Guatemala decreased at an average rate of 1.7%
If the forested area in Guatemala in 1990 was about 34,400 square kilometers, write an equation for the forested area for t years after 1990
The equation for the forested area for t years after 1990 is
y = 34400 \((0.983)^t\).
What is exponential decay?
The term "exponential decay" in mathematics refers to the process of a constant percentage rate reduction in an amount over time. It can be written as y=a(1-b)x, where x is the amount of time that has passed, an is the initial amount, b is the decay factor, and y is the final amount.
Here the initial forest area a = 34400 square kilometer.
Average rate = 1.7% = 1.7/100 = 0.017.
Now using exponential decay formula then,
=> y = a\((1-b)^t\)
Where t = number of years.
=> y = 34400(\(1-0.017)^t\)
=> y = 34400 \((0.983)^t\)
Hence the equation for the forested area for t years after 1990 is
y = 34400 \((0.983)^t\).
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Mr Cooper’ claroom had 5 table. There were 4 tudent at each table. Mr Garcia’ claroom had 3 more tudent than Mr Cooper’ claroom
Mr. Garcia's classroom had 23 students.
Let's denote the number of students in Mr. Cooper's classroom as C and the number of students in Mr. Garcia's classroom as G.
Given that Mr. Cooper's classroom had 5 tables with 4 students at each table, we can write:
C = 5 * 4 = 20
It is also given that Mr. Garcia's classroom had 3 more students than Mr. Cooper's classroom, so we can write:
G = C + 3
Substituting the value of C from the first equation into the second equation, we get:
G = 20 + 3 = 23
Therefore, Mr. Garcia's classroom had 23 students.
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In ΔBCD, the measure of ∠D=90°, DC = 12, BD = 35, and CB = 37. What is the value of the tangent of ∠B to the nearest hundredth?
Answer:
0.34
Step-by-step explanation:
Only the smartest person can help me with Algebra 2! Answer how many you can!
Part 3
Using the concepts of domain and range of functions, we have that:
10. The range is y ≥ 2.
11. The domain is all real numbers, the range is y ≤ 3, and it is a function.
12. The domain is (-4,3], and the range is (-5,5).
What are the domain and the range of a function?The domain of a function is the set that contains all the values of the input. In a graph, it is represented by the values of x.The range of a function is the set that contains all the values of the output. In a graph, it is represented by the values of y.Hence, for these problems:
10. The range is y ≥ 2.
11. The domain is all real numbers, the range is y ≤ 3, and it is a function.
12. The domain is (-4,3], and the range is (-5,5).
In item 11, we have that it is a function because it has no vertically aligned points, that is, each value of x is associated with only one value of y.
In item 12, the open intervals are due to the open circles at the extremes of the domain and the range on the graph.
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Given a normal distribution with mu equals 100 and sigma equals 10 comma complete parts (a) through (d). LOADING... Click here to view page 1 of the cumulative standardized normal distribution table. LOADING... Click here to view page 2 of the cumulative standardized normal distribution table. a. What is the probability that Upper X greater than 70? The probability that Upper X greater than 70 is .0016 nothing. (Round to four decimal places asneeded.) b. What is the probability that Upper X less than 80? The probability that Upper X less than 80 is nothing. (Round to four decimal places as needed.) c. What is the probability that Upper X less than 95 or Upper X greater than 125? The probability that Upper X less than 95 or Upper X greater than 125 is nothing.(Round to four decimal places as needed.) d. 99% of the values are between what two X-values (symmetrically distributed around the mean)? 99% of the values are greater than nothing and less than nothing.
a Probability that Upper X 0.0013 ,
b. Upper X less than 80 is 0.0228
c Upper X less than 95 or Upper X greater than 125 is 0.6853.
d 99% of the values are between 76.7 and 123.3 (symmetrically distributed around the mean).
Given a normal distribution with mu equals 100 and sigma equals 10, we can use the cumulative standardized normal distribution table to complete the following parts:
a. What is the probability that Upper X greater than 70?
Using the cumulative standardized normal distribution table, we find the z-score for 70 as (70-100)/10 = -3. We then look up the probability for a z-score of -3, which is 0.0013. Therefore, the probability that Upper X greater than 70 is 0.0013. (Round to four decimal places as needed.)
b. What is the probability that Upper X less than 80?
Using the cumulative standardized normal distribution table, we find the z-score for 80 as (80-100)/10 = -2. We then look up the probability for a z-score of -2, which is 0.0228. Therefore, the probability that Upper X less than 80 is 0.0228. (Round to four decimal places as needed.)
c. What is the probability that Upper X less than 95 or Upper X greater than 125?
Using the cumulative standardized normal distribution table, we find the z-score for 95 as (95-100)/10 = -0.5 and the z-score for 125 as (125-100)/10 = 2.5. We then find the probabilities for each of these z-scores, which are 0.3085 and 0.0062, respectively. To find the probability that Upper X is either less than 95 or greater than 125, we add these two probabilities and subtract from 1 (to account for the overlap): 1 - (0.3085 + 0.0062) = 0.6853. Therefore, the probability that Upper X less than 95 or Upper X greater than 125 is 0.6853. (Round to four decimal places as needed.)
d. 99% of the values are between what two X-values (symmetrically distributed around the mean)?
To find the z-score corresponding to the 99th percentile, we look up the probability of 0.99 in the cumulative standardized normal distribution table, which is 2.33 (rounded to two decimal places). Using this z-score, we can find the corresponding X-values using the formula z = (X - mu)/sigma. Solving for X, we get: X = z*sigma + mu = (2.33)(10) + 100 = 123.3 and X = (-2.33)(10) + 100 = 76.7. Therefore, 99% of the values are between 76.7 and 123.3 (symmetrically distributed around the mean).
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Let f(n)=10log 10
(100n) and g(n)=log 2
n. Which holds: f(n)=O(g(n))
g(n)=O(f(n))
f(n)=O(g(n)) and g(n)=O(f(n))
After comparing the growth rates of f(n) and g(n) and observing the logarithmic function, we can say that f(n) = O(g(n)).
To determine which holds among the given options, let's compare the growth rates of f(n) and g(n).
First, let's analyze f(n):
f(n) = 10log10(100n)
= 10log10(10^2 * n)
= 10 * 2log10(n)
= 20log10(n)
Now, let's analyze g(n):
g(n) = log2(n)
Comparing the growth rates, we observe that g(n) is a logarithmic function, while f(n) is a with a coefficient of 20. Logarithmic functions grow at a slower rate compared to functions with larger coefficients.
Therefore, we can conclude that f(n) = O(g(n)), which means that option (a) holds: f(n) = O(g(n)).
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What are the solutions of the equation x 3 2 +2 x 3 )- 8 0?
The value of x from the given expression is 1 and -5.
Hence we get the solution as 1 and -5.
What is factorization?A number or other mathematical object is factorised (also called factorised in some varieties of British English) or factored by a number of factors, typically smaller or simpler things of the same kind.
Given the quadratic expression
(x - 3)^2 + 2(x - 3) - 8 = 0
Expand the expression
(x - 3)^2 + 2(x - 3) - 8 = 0
x^2 - 6x + 9 + 2x - 6 - 8 = 0
x^2 - 6x + 2x + 9 - 6 - 8 = 0
x^2 - 4x - 5 = 0
Factorize the result
x^2 - 4x - 5 = 0
x^2 + 5x - x - 5 = 0
x(x + 5) - 1(x + 5) = 0
x - 1 = 0 & x + 5 = 0
x = 1 & x = -5
Hence the value of x is 1 and -5
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Jerome solved the equation below by graphing. log subscript 2 baseline x log subscript 2 baseline (x minus 2) = 3
x = 4 would be the solution of the given problem.
I can't speak to the first part of this question, as I don't totally have context for what they're asking, but we can solve for x using one of the laws of logarithms, namely:
log.m + log.n = log.mn
Using this law, we can combine and rewrite our initial equation as
log(x^2- x) = 3
Remember that logarithms are simply another way of writing exponents. The logarithm is just another way of writing the fact . Keeping that in mind, we can express our logarithm in terms of exponents as
log(x^2- x) = 3 --> x^2- 2x = 8
2³ = 8, so we can replace the left side of our equation with 8 to get
x^2 - 2x - 8 =0
(x-4)(x+2) = 0
Hence x = 4 0r -2. As x cannot be negative so it would be 4.
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Select all the situations that can be modeled with an equation.
please help!!
The situations that can be modeled with an equation include the following:
A. The sale price of a television is $125 off of the original price.
C. Marco spent twice as much as Owen.
E. Ben paid a total of $75 for a shirt and a pair of shoes.
What is an equation?In Mathematics and Geometry, an equation can be defined as a mathematical expression which shows that two (2) or more thing are equal. This ultimately implies that, an equation is composed of two (2) expressions that are connected by an equal sign.
Assuming the variable x represent the independent variable and y represents the dependent variable, we have the following equations;
"The sale price of a television is $125 off of the original price."
y = x - 125
"Marco spent twice as much as Owen."
y = 2x
"Ben paid a total of $75 for a shirt and a pair of shoes."
x + y = 75
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Complete Question:
Select all the situations that can be modeled with an equation.
The sale price of a television is $125 off of the original price.
Anna gave away 5 hats.
Marco spent twice as much as Owen.
Susan earns $25 per day for d days.
Ben paid a total of $75 for a shirt and a pair of shoes.
Write the name of each decimal place indicated( pls help I’m failing and don’t troll I’ll give Brianliest)
Answer:
3. A. ten thousandths
4. C. tenths
5. D. hundredths
6. C. ten thousandths
hope you have a blessed day
Step-by-step explanation:
Answer:Question 3 answer is A.
Question 4 answer is C
Question 5 answer is D
Question 6 answer is C
YOUR WELCOME
(2x + 3)(5x2 - 2x - 1) = Ax3 + Bx2 + Cx + D. What are the values of B and C?
Answer:
B = 11; C = -8
Step-by-step explanation:
When simplified I get 10x^3 + 11x^2 - 8x - 3
Both Galapagos islands and the Island of Nauru are on the equator, but the Galapagos islands are at 90°W where the Island of Nauru is at 166.50°E. How far is it from the Galapagos islands to Nauru traveling over the Pacific ocean along the equator, correct to the nearest km?
Answer:
11565 km
Step-by-step explanation:
The computation is shown below:
But before reaching the final solution first we need to do the following calculations
The angle lies between the Galapagos and Nauru is
= 90° + 166.50°
= 256.5°
Since the sum of angle is 360 degrees
So the major arc and the minor arc is
= 360° - 256.5°
= 103.50°
Now the angles lies between galapagos islands is
= 180° - 90°
= 90°
And, between the naura island is
= 180° - 166.50°
= 13.5°
Now the total of this two island is
= 90° + 13.5°
= 103.5°
The length is
\(= \frac{\pi r }{180^{\circ}} \times \theta\\\\ = \frac{6,400\pi}{180^{\circ}} \times 103.5^{\circ}\)
= 11565 km
drew and hunter are playing basketball. drew passes the ball to hunter when he is 26 feet from the net and 24 feet from hunter. how far is hunter from the net if the angle from the net to drew to hunter is 34 degrees. round your answer to the nearest tenth.
Answer:
hunter is 5ft waay thx
Step-by-step explanation:
An easement enabling its holder to prevent the possessor of the land subject to the easement from doing certain acts or exercising certain rights of ownership he/she would otherwise have a legal right to is known as a
An easement enabling its holder to prevent the possessor of the land subject to the easement from doing certain acts or exercising certain rights of ownership is known as a negative easement.
A negative easement grants the holder the right to restrict or prohibit specific activities on the land, even though the possessor of the land would otherwise have the legal right to engage in those activities. It imposes limitations on the use or enjoyment of the land by the possessor.
For example, a negative easement may prohibit the landowner from building any structures that would obstruct the view of the neighboring property or from engaging in any activities that would cause excessive noise or pollution. The holder of the negative easement, such as a neighboring property owner or a conservation organization, can enforce these restrictions to protect their interests or preserve certain conditions.
Negative easements are typically established through legal agreements or by court decisions. They serve to balance the rights of the landowner with the interests of the easement holder, allowing for the protection of specific rights or conditions associated with the land.
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find the value of x in the triangle at the right
Answer: X = 72
Step-by-step explanation:
All triangles are 180 degrees, subtracting 36 from it
144 = 2x
divide 144 by 2
x = 72
In order to prove triangle similarity by AAA what does X have to equal?
Answer:
x has to be equal to 12
Step-by-step explanation:
In other to prove that the triangles are similar, the values of the angles at certain points must be equal
for example, the angle at the top vertices should be equal
So, we have it that;
6x = 3x + 36
6x-3x = 36
3x = 36
x = 36/3
x = 12
In triangle r s t, angle r = 63 degrees, angle t = 90 degrees, side r s = 23 and side s t = 10.4. which ratios are correct?
The correct ratios are: cos 27=23/RT, sec 27= 23/10.4 and cot 63 = RT/10.4
What is trigonometry ratio in tringle?
Trigonometric ratios are the ratios of the length of sides of a triangle. These ratios in trigonometry relate the ratio of sides of a right triangle to the respective angle. The basic trigonometric ratios are sin, cos, and tan, namely sine, cosine, and tangent ratios.In triangle RST, angle T= 90° and angle R= 63°
As the total of all angle in any triangle is 180°, so the measure of the angle S = 180°- (90°+63°)
S= 180°- 153°
S= 27°
According to the rule of trigonometric ratios,
cos(θ) = \(\frac{hypotenuse}{opposite}\)
sec(θ) = \(\frac{hypotenuse}{adjacent}\)
cot(θ) = \(\frac{adjacent}{opposite}\)
In respect of angle R (63°), side RS(23) is hypotenuse , ST(10.4) is opposite and RT is adjacent.
cos(63°) = \(\frac{23}{10.4}\)
sec(63°) = \(\frac{23}{RT}\)
cot(63°) = \(\frac{RT}{10.4}\)
Now, in respect of angle S(27°), hypotenuse is RS(23), adjacent is ST(10.4) and opposite is RT.
So, cos(27°) = \(\frac{23}{RT}\)
sec(27°) = \(\frac{23}{10.4}\)
cot(27°) = \(\frac{10.4}{RT}\)
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If a penceil has 25 grams and a apple has 75 grams more then the penceil how many grams is the apple
Answer:
The answer is 100
Step-by-step explanation:
It's 100 because it's saying that the apples is 75 more grams than the pencil. So we do 25 grams plus 75 grams which gets us 100. If your wondering where I got the 25 from it's from the amount of the pencil.
If / (x) = x? -1, g(x) = 2x - 3, and h(x) = 1 - 4x, find the following new functions, as well as any values (f-g)(3)
The new functions are:
(f + g)(x) = 3x - 4
(g - h)(x) = 6x - 4
(f o g)(x) = 2x - 4
(g o h)(x) = -8x - 1
And the value of (f-g)(3) = -2.
To find new functions, we can combine the given functions using arithmetic operations.
(f + g)(x) = f(x) + g(x) = (x - 1) + (2x - 3) = 3x - 4
(g - h)(x) = g(x) - h(x) = (2x - 3) - (1 - 4x) = 6x - 4
(f o g)(x) = f(g(x)) = f(2x - 3) = (2x - 3) - 1 = 2x - 4
(g o h)(x) = g(h(x)) = g(1 - 4x) = 2(1 - 4x) - 3 = -8x - 1
To find (f-g)(3), we need to evaluate the function (f - g) at x = 3:
(f - g)(3) = f(3) - g(3) = (3 - 1) - (2(3) - 3) = 1 - 3 = -2
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The given question is incomplete, the complete question is
If f(x) = x -1, g(x) = 2x - 3, and h(x) = 1 - 4x, find the following new functions, as well as any values (f-g)(3)
(f + g)(x)
(g - h)(x)
(f o g)(x)
(g o h)(x)
What is the value of x?
Answer:
x=12
Step-by-step explanation:
Intersecting Chords Formula:
(segment piece) x (segment piece) = (segment piece) x (segment piece)
10 * x = ( 3+x) *8
10x = 24+8x
Subtract 8x
10x-8x = 24+8x-8x
2x= 24
Divide by 2
2x/2 =24/2
x = 12
A class is putting ornaments on a Christmas tree.
One box of 30 ornaments cost $6.99. How
much does one ornament cost? (round to the
nearest cent)
Answer:
each ornament was about 5 cents
Step-by-step explanation:
Hope this helps
May I get Braineist pls
suppose that a researcher is interested in estimating the mean systolic blood pressure, , of executives of major corporations. he plans to use the blood pressures of a random sample of executives of major corporations to estimate . assuming that the standard deviation of the population of systolic blood pressures of executives of major corporations is mm hg, what is the minimum sample size needed for the researcher to be confident that his estimate is within mm hg of ?carry your intermediate computations to at least three decimal places. write your answer as a whole number (and make sure that it is the minimum whole number that satisfies the requirements).
To determine the minimum sample size needed for the researcher to be confident that his estimate is within "mm" hg of the true mean systolic blood pressure, we will use the following formula:
n = (Z * σ / E)²
where:
n = minimum sample size
Z = Z-score corresponding to the desired confidence level
σ = population standard deviation (in this case, "mm" hg)
E = margin of error (in this case, "mm" hg)
1. Determine the Z-score corresponding to the desired confidence level. Common confidence levels include 90%, 95%, and 99%, which correspond to Z-scores of 1.645, 1.960, and 2.576, respectively. Choose the appropriate Z-score based on the desired confidence level.
2. Substitute the given values of σ and E (both in "mm" hg) and the chosen Z-score into the formula: n = (Z * σ / E)²
3. Carry out the calculations, rounding the result up to the nearest whole number. This will ensure that the sample size is the minimum whole number that satisfies the requirements.
4. The result is the minimum sample size needed for the researcher to be confident that his estimate is within "mm" hg of the true mean systolic blood pressure.
Note: Since this question haven't provided specific values for standard deviation, margin of error, and desired confidence level . follow the steps with the specific values you have to find the minimum sample size.
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WILL GIVE BRAINLIEST
Answer:
3
Step-by-step explanation:
These are similar triangle
We can use ratios to solve
12 12+4
------ = ----------
9 9+DC
Using cross products
12( 9+DC) = 9*(12+4)
12 (9+DC) = 9*16
Divide each side by 12
12/12 (9+DC) = 9*16/12
9+DC = 12
Subtract 9 from each side
9+DC-9 =12-9
DC =3
Answer:
3 units
Step-by-step explanation:
We can see that triangle ADE is similar to triangle ACB.
Therefore the ratios of the lengths of their sides must be equal.
We can write AD/AC = AE/AB
we are given AD = 9, AE = 12 and AB = 12 + 4 = 16
Substituting the above values into the equation:
AD/AC = AE/AB
9 / AC = 12/16 (rearranging)
(AC)(12) = (9)(16)
AC = (9)(16)/12
AC = 12
We can also see that
DC = AC - AD
DC = 12 - 9
DC = 3 units
What does it mean to be "in the black"
Answer:
to be unaware
Step-by-step explanation:
Simplify (-8)2. please help
Answer:
-16
Step-by-step explanation:
This equation is showing -8 multiplied by 2, and when they are multiplied, the sum of those two numbers is -16.
Answer:
=-16
Step-by-step explanation:
(-8)2
= 2×-8
= -16
What is the perimeter of this quadrilateral?
(5,5)
(2, 4)
(4, 1)
(6, 1)
\(~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{5}~,~\stackrel{y_1}{5})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{4}) ~\hfill AB=\sqrt{[ 2- 5]^2 + [ 4- 5]^2} \\\\\\ AB=\sqrt{(-3)^2+(-1)^2}\implies \boxed{AB=\sqrt{10}} \\\\[-0.35em] ~\dotfill\\\\ B(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{4}~,~\stackrel{y_2}{1}) ~\hfill BC=\sqrt{[ 4- 2]^2 + [ 1- 4]^2}\)
\(BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad D(\stackrel{x_2}{6}~,~\stackrel{y_2}{1}) ~\hfill CD=\sqrt{[ 6- 4]^2 + [ 1- 1]^2} \\\\\\ CD=\sqrt{2^2+0^2}\implies \boxed{CD=2} \\\\[-0.35em] ~\dotfill\\\\ D(\stackrel{x_1}{6}~,~\stackrel{y_1}{1})\qquad A(\stackrel{x_2}{5}~,~\stackrel{y_2}{5}) ~\hfill DA=\sqrt{[ 5- 6]^2 + [ 5- 1]^2}\)
\(DA=\sqrt{(-1)^2+4^2}\implies \boxed{DA=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Perimeter}}{\sqrt{10}~~ + ~~\sqrt{13}~~ + ~~2~~ + ~~\sqrt{17}}~~ \approx ~~ 12.89\)
if you have to pay 4125 per semester how much do you have to pay to attend a four-year College
1 semester $4125
In a year we have 2 semesters
In 4 years we 2(4)=8 semesters
So we need to multiplicate $4125 by 8
4125 * 8 =33000
You need to pay $33000 to attend a four- year college
Answer: 3 años
Step-by-step explanation:
por que si
The city of Irvine reported that approximately 75% of residents are over the age of 60. Let X be the number of Irvine residents over the age of 60.From a random sample of 500 Irvine residents, 350 were over the age of 60.What is the sampling distribution of the sample proportion for the sample size of 500?Using the distribution of X from above, what is the probability that at most 350 of the 500 Irvine residents selected will be over the age of 60?What is the probability that at least 350 of the 500 residents in the sample were over the age of 60?What is the probability that between 400 and 475 of the residents were over the age of 60?
The probability that at most 350 of the 500 Irvine residents selected will be over the age of 60 is 0.9292. The probability that at least 350 of the 500 residents in the sample were over the age of 60 is 0.0708. The probability that between 400 and 475 of the residents were over the age of 60 is 5.88.
The probability that at most 350 of the 500 Irvine residents selected will be over the age of 60 can be found by calculating the z-score for 350 and finding the corresponding probability from a normal distribution table. The z-score for 350 is (350-375)/17 = -1.47. The corresponding probability from a normal distribution table is 0.0708.
The sampling distribution of the sample proportion for the sample size of 500 is a normal distribution with a mean of 0.75 and a standard deviation of \(√[(0.75)(0.25)/500] = 0.017.\)
The probability that at least 350 of the 500 residents in the sample were over the age of 60 can be found by calculating the z-score for 350 and finding the corresponding probability from a normal distribution table. The z-score for 350 is (350-375)/17 = -1.47. The corresponding probability from a normal distribution table is 1 - 0.0708 = 0.9292.
The probability that between 400 and 475 of the residents were over the age of 60 can be found by calculating the z-scores for 400 and 475 and finding the corresponding probabilities from a normal distribution table. The z-score for 400 is (400-375)/17 = 1.47 and the z-score for 475 is (475-375)/17 = 5.88.
The corresponding probabilities from a normal distribution table are 0.9292 and 1.0000, respectively. The probability that between 400 and 475 of the residents were over the age of 60 is 1.0000 - 0.9292 = 0.0708.
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how to find the scale factor of 10 cm=5m
The scale factor of 10cm to 5m is 50.
What is scale factor?The scale factor is a measure for similar figures, who look the same but have different scales or measures.
For example ,if a length of 5cm is doubled and it gives a length 10cm, the scale factor is 10/5 = 2. This means that we can express scale factor with a formula;
scale factor = new dimension / old dimension
Here, the old dimension is 10cm and the new dimension is 5m. We need to convert the 5m into cm
therefore 5m = 5× 100 = 500cm
therefore scale factor = 500/10 = 50
This means the scale factor of 10cm = 5m is 50
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Use the distributive property to rewrite the algebraic expression below
9 (r+12)
Answer:
9r+108
Step-by-step explanation:
9 times r, 9 times 12.
9r+ 12 times 9 equals 9r+108