Eleanor has £50. Trevor takes £y. What’s an expression for how much Eleanor has got left?

Write down the answer, and don’t leave spaces, please.

Answers

Answer 1

Answer:

£50-£y or 50-y

Step-by-step explanation:

remaining = initial - taken

remaining = 50 - y


Related Questions

PLEASE HELP FAST I’M HAVING A LITTE TROUBLE PLEASE GIVE THE RIGHT ANSWER

PLEASE HELP FAST IM HAVING A LITTE TROUBLE PLEASE GIVE THE RIGHT ANSWER

Answers

Answer:

C)  1/2  and 8

Step-by-step explanation:

-2x + y = 7              Eq. 1

6x + y = 11               Eq. 2

From Eq. 1:

y = 7 + 2x               Eq. 3

From Eq. 2:

y = 11 - 6x              Eq. 4

Equalyzing Eq. 3 and Eq. 4:

7 + 2x = 11 - 6x

2x + 6x = 11 - 7

8x = 4

x = 4/8

x = 1/2

From Eq. 3:

y = 7 +2* 1/2

y = 7 + 1

y = 8

Check:

From Eq. 2

6x + y = 11

6*1/2 + 8 = 11

3 + 8 = 11

Riley is building a pool with a surrounding deck in their backyard. The pool has a fixed area, A m2, but the pool's dimensions can vary (For instance, a 4 m2 pool can have infinitely many length-width combinations, including 2×2, 4×1, 1×4, or π2×8π).The width of the pool deck extends beyond the pool on both sides, as does the length of the pool deck. Because the pool has a fixed area, the pool length depends on the pool width and vice versa.The width in the applet, W, varies between .5 meters and 12 meters. Find the minimum area for a pool and deck built as in the application such that the pool's area is 1800 square meters, the deck extends an extra 10 meters wide on both sides of the pool, and the deck extends an extra 5 meters long on the corresponding sides of the pool. Your solution should contain a justification for why your found area is indeed the minimizing area.

Answers

The minimal size for a pool and deck constructed as in the application, with the deck extending an additional 10 meters is 1400 meter square.

Given that,

We have to find the minimal size for a pool and deck constructed as in the application, with the deck extending an additional 10 meters on each side of the pool and a further 5 meters along the corresponding sides of the pool. The pool's area is 1800 square meters.

We know that,

Area of the Total space = (l+10)(b+20)

Here,

b=1800/l

l= 30

So,

b=60

Area of the total space is (30+10)(60+20) = 40×80 = 3200 m²

The minimum area of deck = 3200-1800 = 1400 m²

Therefore, The minimal size for a pool and deck constructed as in the application, with the deck extending an additional 10 meters is 1400 meter square.

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An ice cream cone has a height of 4 in and a radius of 1 in. If the cone is 0.1 in thick, what is the difference (in in3) between the volume of the cone, including the shell, and the volume of the ice cream you can fit inside the shell

Answers

Answer:

\(0.79 in^3\)

Step-by-step explanation:

Given data for the cone

height h= 4 in

radius r= 1 in

hence diameter d= 2 in

thickness of cone= 0.1 in

The volume of the cone including the shell can be expressed as

\(volume=\frac{1}{3} \pi r^2h\)

\(volume= \frac{1}{3}*3.142*1^2*4\\\volume= \frac{12.568}{3} \\\volume= 4.189 in^3\)

The volume of the ice cream can be expressed as

N/B: the diameter of the ice cream is

2-(0.1*2)= 2-0.2= 1.8 in

hence the radius is 0.9 in

\(volume= \frac{1}{3}*3.142*0.9^2*4\\\ volume= \frac{10.18}{3} \\\ volume= 3.39 in^3\)

The difference in volume is \(4.189-3.39= 0.79 in^3\)

Solve for n:
-5(n + 6) = 3(7 + 3n) + 3n ​

Answers

Answer:

n = -3

Step-by-step explanation:

-5n-30=21+9n+3n

-5n-30=21+12n

-17n=51

n=-3

PLEASE HELP!!!!!!!!!

PLEASE HELP!!!!!!!!!

Answers

According to the information we can infer that the scale drawing of the football field will have dimensions of 2.5cm by 4.5cm.

How to create the scale drawing?

To create the scale drawing, we need to convert the real-life dimensions of the football field into centimeters and then apply the scale of 1:2000.

Real-life dimensions:

Length: 50mWidth: 90m

Converting to centimeters:

Length: 50m * 100cm/m = 5000cmWidth: 90m * 100cm/m = 9000cm

Applying the scale of 1:2000:

Length on the drawing: 5000cm / 2000 = 2.5cmWidth on the drawing: 9000cm / 2000 = 4.5cm

According to the above, the scale drawing of the football field will have dimensions of 2.5cm by 4.5cm.

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PLEASE HELP!!!!!!!!!

PLEASE ANSWER ASAP FOR BRAINLEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

PLEASE ANSWER ASAP FOR BRAINLEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answers

Answer:

I think it is 1 in 12 ft.

Step-by-step explanation:

1in:12ft is the answer. Hopefully this helps

What are two pairs of opposite sides that are parallel and congruent?

Answers

Parallelogram have two pairs of opposite sides that are parallel and congruent.

In a parallelogram, two pairs of opposite sides are parallel and congruent. A parallelogram is a quadrilateral with opposite sides that are parallel and congruent. Therefore, any pair of opposite sides in a parallelogram satisfies the criteria of being both parallel and congruent.

For example, let's consider a parallelogram ABCD:

Side AB is parallel and congruent to side CD.Side AD is parallel and congruent to side BC.

These two pairs of opposite sides, AB and CD, and AD and BC, are parallel (they never intersect) and congruent (they have the same length).

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20 kilograms increased by 25%

Answers

Answer:

25 kilograms

Step-by-step explanation:

A number k multiplied by 4 is less than -3/2

Answers

Answer:

\(4k < -\frac{3}{2}\)

Step-by-step explanation:

"A number k multiplied by 4 is less than -3/2"

First, let's look at the first part:

"A number k..."
We know the number we are operating is called k.

Let's look at the second part.

"...multiplied by 4..."

Now, we are multiply k by 4. After doing so, we get:

\(4k\)

Finally, let's look at the last part.

"...is less than -3/2"

The quantity "a number k multiplied by 4" (or 4k) is less than -3/2.

We can rewrite this as:

\(4k < -\frac{3}{2}\)


Please help its due soon

Please help its due soon

Answers

Note that:

The frequency table value for "Grapes" is 28.The relative frequency table value for "Oranges" is 20/200 = 0.1 or 10%.The relative frequency table value for "Strawberries" is 30/200 = 0.15 or 15%.The relative frequency table value for "Other" is 102/200 = 0.51 or 51%.The relative frequency table value for the total is 1 or 100%.

What is Relative Frequency?

Relative frequency is a statistical term that refers to the proportion of times an event or value occurs in a dataset relative to the total number of observations or occurrences in the dataset.

It is calculated by dividing the frequency of a particular event or value by the total number of observations in the dataset. The resulting value is a decimal or a percentage that provides information about the relative importance or prevalence of the event or value in the dataset. R

elative frequency is useful in many areas of statistics, including data analysis, probability theory, and hypothesis testing.

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What is the y-intercept of the line?

What is the y-intercept of the line?

Answers

It crosses the y axis at 4... it is 4 :)

Answer:

a. (0, 4)

General Formulas and Concepts:

Algebra I

The y-intercept is the y value when x = 0. Another way to reword that is when the graph crosses the y-axis.

Step-by-step explanation:

According to the graph, the line crosses the y-axis at y = 4. Therefore, our y-intercept is 4. Writing it in coordinate point would be (0, 4), as definition of the y-int.

find the value of x

a) 2:5=8:x

Answers

Step-by-step explanation:

solution:

given,

or, 2:5 = 8:x

or, 2/5 = 8/x [ changing into fraction form ]

or, 2x = 40 [ doing cross-multiplication ]

or, x = 20 [ dividing both sides with 2]

Can someone please explain how to do this.

Can someone please explain how to do this.

Answers

Answer: 9/30

Step-by-step explanation:

Merone Company allocates materials handling cost to the company's two products using the below data:

Modular Homes Prefab Barns
Total expected units produced 5,900 8,900
Total expected material moves 590 190
Expected direct labor-hours per unit 790 290

The total materials handling cost for the year is expected to be $325,890.

If the materials handling cost is allocated on the basis of material moves, the total materials handling cost allocated to the modular homes is closest to: (Round your intermediate calculations to 2 decimal places.)

Multiple Choice

$246,507.90

$160,629.00

$213,514.00

$238,382.50
Merone Company allocates materials handling cost to the company's two products using the below data:

Modular Homes Prefab Barns
Total expected units produced 6,000 9,000
Total expected material moves 600 200
Expected direct labor-hours per unit 800 300

The total materials handling cost for the year is expected to be $300,000.

If the materials handling cost is allocated on the basis of direct labor-hours, the total materials handling cost allocated to the prefab barns is closest to: (Round your intermediate calculations to 2 decimal places.)

Multiple Choice

$105,000.00

200,000.00

$150,204.00

$108,000.00

Spates, Incorporated, manufactures and sells two products: Product H2 and Product E0. Data concerning the expected production of each product and the expected total direct labor-hours (DLHs) required to produce that output appear below:

Expected Production Direct Labor-Hours Per Unit Total Direct Labor-Hours
Product H2 190 6.9 1,311
Product E0 190 5.9 1,121
Total direct labor-hours 2,432

The company’s expected total manufacturing overhead is $270,968.

If the company allocates all of its overhead based on direct labor-hours, the overhead assigned to each unit of Product H2 would be closest to: (Round your intermediate calculations to 2 decimal places.)

Multiple Choice

$222.84 per unit

$126.48 per unit

$768.80 per unit

$96.36 per unit

Doles Corporation uses the following activity rates from its activity-based costing to assign overhead costs to products.

Activity Cost Pools Activity Rate
Setting up batches $ 70.72 per batch
Processing customer orders $ 27.78 per customer order
Assembling products $ 12.81 per assembly hour

Data concerning two products appear below:

Product K52W Product X94T
Number of batches 66 53
Number of customer orders 46 31
Number of assembly hours 419 162

Required:
How much overhead cost would be assigned to each of the two products using the company's activity-based costing system? (Round your intermediate calculations and final answers to 2 decimal places.)

Answers

The total materials handling cost allocated to the modular homes is $246,372.84.

The total materials handling cost allocated to the Prefab Barns is closest to $108,000.

What is the total materials handling cost allocated?

To allocate materials handling cost based on material moves, we must determine proportion of material moves for each product and then apply that proportion to the total materials handling cost.

Proportion of material moves for Modular Homes:

= (Total expected material moves for Modular Homes) / (Total expected material moves for both products)

= 590 / (590 + 190)

= 0.756

Total materials handling cost allocated to Modular Homes:

= Proportion of material moves for Modular Homes * Total materials handling cost

= 0.756 * $325,890

= 246 372.84

= $246,372.84.

To allocate the materials handling cost based on direct labor-hours, we need to determine proportion of direct labor-hours for each product.

For Modular Homes:

Total direct labor-hours for Modular Homes:

= 6,000 units * 800 hours/unit

= 4,800,000 hours

For Prefab Barns:

Total direct labor-hours for Prefab Barns:

= 9,000 units * 300 hours/unit

= 2,700,000 hours

Total direct labor-hours for both products:

= 4,800,000 hours + 2,700,000 hours

= 7,500,000 hours

Proportion of direct labor-hours for Prefab Barns:

= 2,700,000 hours / 7,500,000 hours

= 0.36

Allocated materials handling cost for Prefab Barns:

= Proportion of direct labor-hours for Prefab Barns * Total materials handling cost

= 0.36 * $300,000

= $108,000.

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50 Points! Multiple choice algebra question. Photo attached. Thank you!

50 Points! Multiple choice algebra question. Photo attached. Thank you!

Answers

The exact value of cos theta if the terminal side of theta in standard position contains the point (6,-8) is, 3 / 5

We have to given that;

the terminal side of theta in standard position contains the point (6,-8)

Hence, For given condition we get;

The exact value of cos theta if the terminal side of theta in standard position contains the point (6,-8) is,

Here, x = 6, y = - 8

Hence, We get;

r = √x² + y²

r  = √6² + 8²

r = √36 + 64

r = √100

r = 10

So, The exact value of cos theta if the terminal side of theta in standard position contains the point (6,-8) is,

cos θ = x / r

cos θ = 6 / 10

cos θ =  3 / 5

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Prove the identity note that each statement must be based

Prove the identity note that each statement must be based

Answers

Given the identity:

\((\csc ^2x-1)\sin x=\cos ^2x\csc x\)

We will prove the identity as follows

Starting from the left-hand side

First, use the rule of reciprocal

\((\csc ^2x-1)\sin x=(\frac{1}{\sin^2x}-1)\sin x\)

Second, use the rule of quotient

\(=(\frac{1-\sin^2x}{\sin^2x})\sin x\)

Third, use the Pythagorean theorem

\(=\frac{\cos^2x}{\sin^2x}\cdot\sin x\)

Fourth, Multiply using the rule algebra

\(=\frac{cos^2x}{\sin x}\)

Finally, use the rule of reciprocal

\(=\cos ^2x\csc x\)

Which will be matched with the right-hand side.

A small barrel can hold 2041.11 cubic centimeters sand. The radius of a barrel is 7 cm, what is the height of the barrel? Use 3.14 for pi. Round your answer to the nearest hundredth

Answers

Answer:

Step-by-step explanation:

I'm assuming that the barrel is in the shape of a cylinder..

Givens

r = 7

pi = 3.14

V = 2041.11

Formula

V = pi * r^2 * h

h = V / (pi * r^2)

Solution

h = 2041.11/(3.14 * 7^2)

H = 2014.11 / 153.86

H = 13.09

You have a map that is missing a scale. The distance from Point A to Point B is
five inches on the map, and after driving it, you know it is 250 miles in reality.

Answers

The scale of the map in the question is 1 inch = 50 miles.

What is the scale of the map?

A scale in a map is a relation that tells us how many units each unit in the map represents. In this case, we know that the distance between two points A and B on the map is 5 inches, while the actual distance between these two places is 250 miles.

Then we start with the relation:

5 inches = 250 miles.

But to get the scale of the map we need to see how many miles one inch represents in the map, then we can divide both sides of the equation by 5 to geT:

5 in = 250 mi

1 in = 250mi/5

1 in = 50 mi

The scale of the map is 1 inch to 50 miles.

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in what category does sugar, brown sugar, butter, eggs, vanilla, flour , unsweetened coca power , baking soda , salt & chocolate chips ? help please i’ll give extra points

in what category does sugar, brown sugar, butter, eggs, vanilla, flour , unsweetened coca power , baking

Answers

Eggs goes in dairy and everything else goes in other

dude what is this i dont understand

dude what is this i dont understand

Answers

Answer:

g(1) = 1

Step-by-step explanation:

the absolute value function always gives a positive result, that is

| - a | = | a | = a

to evaluate g(1) substitute x = 1 into g(x)

g(1) = - 3| 1 - 2| + 4

    = - 3| - 1| + 4

   = - 3(1) + 4

  = - 3 + 4

  = 1

 

check whether -2 and 2 are zeroes of the polynomial x+2

Answers

Answer:

-2 is a zero of the polynomial. 2 is not a zero of the polynomial.

Step-by-step explanation:

A value of x is a zero of a polynomial if when it is substituted for x in the polynomial, it makes the polynomial evaluate to zero.

The polynomial is x + 2

Let x = -2:

x + 2 = -2 + 2 = 0

-2 is a zero of the polynomial.

Let x = 2:

x + 2 = 2 + 2 = 4

2 is not a zero of the polynomial.

1
kg = kg to g. help
g​

Answers

Answer:

100 grams

Step-by-step explanation:

Formala: multiply the mass value by 100

Answer:

1,000g

Step-by-step explanation:

1kg is equal to 1,000 grams, so just convert it.

1 times 1,000 = 1,000

45. A 5-foot log leans against a wall and inclines at a 45° angle from the ground. What expression will
solve the distance between the base of the log to the base of the wall?
A. sin 45
B. cos 45
C. tan 45
D. csc 45
46. What trigonometric ratio can we use to solve for the height of a building given the distance between
the observer and the base of the building and its angle of elevation?
A. Sine
B. Cosine
C. Tangent
D. Secant
47. With the sun, a girl 1.4 m tall casts a 3.6 m shadow. Find the angle of elevation from the tip of
the shadow to the sun.
A. 18°
B. 19°
C. 20°
D. 21°
48. What formula is used to solve the problem: "Find zB in an oblique triangle ABC with the
following measures: A = 50°, a = 15 and b = 10."
A. Sine Law
B. Cosine Law
C. Tangent Law
D. Cosecant Law
49. In an oblique triangle XYZ, ZX = 63°, x = 139 and y = 140. Find A: 100°
B. 64°
C. 60°
D. 45°
50. What formula will solve: "Jackie and Peter skate apart with an angle of 15° between them.
Jackie skates for 5 meters and Peter skates for 7 meters. How far apart are the skaters?
A. d² = 52+72-2(5)(7) cos 15
C. 7² = 52+d²-2(5)(d) cos 15
B. 52= d²+72-2(d)(7) cos 15
D. 152=52+72-2(5)(7) cos

Answers

Answer: it was be cos4

Step-by-step explanation: 1/2 divided by 3/4 = cos4

The diameter of a bowl is 14 cm. What is the circumference? Give the exact
answer in terms of pi.
2
7п cm
147 cm
287 cm
43.967 cm

Answers

The answer is 43.967cm because circumference is equal to pi times the diameter, or two times pi times the radius.

Unions, intersections, and complements involving 2 sets
Sets B and C are subsets of the universal set U.
These sets are defined as follows.
U={f, k, m, s, x, y, z)
B={k, s, y}'
C={s,z}
(a) B'UC' = 1
(b) B'nc =

Answers

Intersection of B'∩C = {k, y}

To find the intersection of B' and C, we need to first find the complement of set B (B') and then find the intersection between B' and C.

1. Complement of set B (B'):

The complement of set B (B') consists of all elements in the universal set U that are not in set B. From the given information, set B is defined as {k, s, y}', which means it contains all elements in U except for k, s, and y. Therefore, the complement of set B is {f, m, x, z}.

2. Intersection between B' and C:

Now, we need to find the intersection between B' (complement of B) and set C. From the given information, set C is defined as {s, z}. To find the intersection, we need to identify the common elements between B' and C.

The elements present in both B' and C are k and y. Therefore, the intersection of B' and C is {k, y}.

So, the answer to (b) is B'∩C = {k, y}.

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Find the solution of the system for which

Find the solution of the system for which

Answers

Answer:

3,0,-6,0

Step-by-step explanation:

x1=3 because 3+0+0=3

since x2 and s2=0.

23 is the quotient of a number t and 61

Answers

Answer:

Mao ni ang answer

\(61 \div 23 = 1\)

Thx sa points

20. Sketch the level curve of the function f(x, y) that contains the point (5,0).

f(x, y) is shown in the picture attached.​

20. Sketch the level curve of the function f(x, y) that contains the point (5,0).f(x, y) is shown in

Answers

At the given point,

\(f(5,0) = \dfrac1{\sqrt{5^2 + 0^2 - 9}} = \dfrac1{\sqrt{16}} = \dfrac14\)

Then the level curve is

\(\dfrac1{\sqrt{x^2 + y^2 - 9}} = \dfrac14 \\\\ \implies \sqrt{x^2 + y^2 - 9} = 4 \\\\ \implies x^2 + y^2 - 9 = 4^2 \\\\ \implies x^2 + y^2 = 25 = 5^2\)

which is a circle centered at the origin with radius 5 - quite easy to sketch.

Find the leg of a right triangle with sides 5.2cm and 15cm

Answers

The length of the other leg is 14.06 cm.

Noted that Pythagoras theorem states that the square of the longest side must be equal to the sum of the square of the other two sides in a right-angle triangle.

|AC|^2 = |AB|^2 + |BC|^2    

Given that

Hypotenuse, AC = 15 cm  and shorter leg, AB = 5.2 cm.

We are to find the length of the other leg, BC.

From Pythagoras' theorem, we have

\(|AC|^2 = |AB|^2 + |BC|^2 \\\\|BC|^2 = |15 |^2 - |5.2 |^2 \\\\|BC|^2 = 225 - 27.04 \\\\|BC|^2 = 197.96\\\\\)cm.

BC = 14.06

Thus, the length of the other leg is 14.06 cm.

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Charlie buys 150 small packets of mints so that
Number of small packets: number of medium packets = 3:4
So how do you find like how much each one is for like 3:4
NEED HELP FAST

Answers

Answer:

3x=60

4x=80

Step-by-step explanation:

I think you've typed it wrong it must be 140 packets. All you need to do is assume 3:4 as 3x and 4x and add it

so 7x=140

x=20

3x=60

4x=80

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