Answer:
8
Step-by-step explanation:
3 + 3 + 2
Use the graph to determine the domain and range of the function.
Q
(-8,5)
20-
16-
-20-16-12-8-4
(-12,-11)
8-
st
-8-
-12-
-16-
-20
(1-1)
(-2,-4)
X
4 8 12 16 20
Q
5
hs
HEE
The domain is
(Type your answer in inte
The domain is {-8, -12, 1, -2} and the range is {5, -11, -1, -4}
How to determine the domain and the rangeFrom the question, we have the following parameters that can be used in our computation:
The graph
On the graph, we have
(-8,5) (-12,-11) (1-1) (-2,-4)
The domian is the set of the input values
Using the ordered pairs as a guide, we have
Domain = {-8, -12, 1, -2}
For the range, we have
The range is the set of the output values
So, we have
Range = {5, -11, -1, -4}
Hence, the range is {5, -11, -1, -4}
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3 Jack walk from Santa Clara to Polo Allo. Il took I hour 25 min to walk from Santa Clot to Los Altos. Than it took 25 minute of wal from los altos to Palo buto. He arrived in Palo alto at 2:45 P.M. of what time die Santa Clara ? he leave Santa clara
The time Jack left Santa Clara is 1 : 55 pm
What is word problem?A word problem in math is a math question written as one sentence or more. These statements are interpreted into mathematical equation or expression.
The time for Jack to walk to lose Altos is 25 min and he uses another 25mins to work to Palo alto.
Therefore, the total time he spent is
25mins + 25 mins = 50 mins
He arrived Palo at 2 :45 pm, therefore the time he left Santa Clare will be ;
2:45 pm = 14 :45
= 14:45 - 50mins
= 13:55
= 1 : 55pm
Therefore he left at 1:55 pm
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jenna has a piece of paper that is 84 square inches in area. it is 10 1/2 inches long. what is the width of the piece of paper in square inches
Answer: the paper is 8 inches
Step-by-step explanation: I'm sure the answer is 8.
Find the vertex, focus, and directrix of the parabola.(y + 3)^2 = 16(x - 3)
We will have the following:
We are given the parabola:
\((y+3)^2=16(x-3)\)And we can see that it follows:
\((y-k)^2=4p(x-h)\)Now, we will have that the vertex is given by:
\((h,k)\)From the equation we then have that the vertex is:
\((3,-3)\)Now, we can see that p = 4 since 16 / 4 = 4. Now, we remember that the focus is located p units to the right since it is positive, thus the focus is given by:
\((h+p,k)\)So, the focus is at:
\((3+4,-3)\to(7,-3)\)Finally we will have that the directrix of the parabola will be given by:
*First, we find the distance between the focus and the vertex, that is:
\(d=\sqrt[]{(7-3)^2+(-3-(-3))^2}\Rightarrow d=4\)Now, since the x coordinate of the vertex is 3, then the directrix will pass at 4 units to its left, that is the directrix is given by:
\(x=-1\)That can be seing in the graph:
*** Summary***
Vertex: (3, -3)
Focus: (7, -3)
Directrix: x = -1
HELP IM GIVING BRAINLIEST
Answer:
Step-by-step explanation:
Add
Keeping car tires inflated is essential to safe driving. For one type of car tire, the tire pressure in pounds per square inch (psi) is assumed to be approximately Normal, with a mean of 35 psi and a standard deviation of 2 psi. What percentage of tires are inflated to a pressure between 33.5 and 36 psi?
Find the z-table here.
22.55%
46.48%
53.52%
77.45%
Answer:
Step-by-step explanation:
The text is a statistics problem that asks to find the probability of a certain range of values in a normal distribution. A normal distribution is a bell-shaped curve that shows how data values are spread around the mean. The mean is the average of all the data values, and the standard deviation is a measure of how much the data values vary from the mean. To solve this problem, we can use the following steps:
Convert the given range of values to standard scores or z-scores. A z-score tells us how many standard deviations a value is away from the mean. To find the z-score, we use the formula: z=σx−μ
where x is the value, μ is the mean, and σ is the standard deviation. For example, to find the z-score for 33.5 psi, we plug in the values: z=233.5−35=−0.75
This means that 33.5 psi is 0.75 standard deviations below the mean. Similarly, to find the z-score for 36 psi, we plug in the values: z=236−35=0.5
This means that 36 psi is 0.5 standard deviations above the mean.
Use a z-table to find the area under the curve for each z-score. A z-table is a table that shows the probability of getting a z-score less than or equal to a given value. For example, to find the area under the curve for -0.75, we look up the row for -0.7 and the column for 0.05 in the z-table and get 0.2266. This means that there is a 22.66% chance of getting a z-score less than or equal to -0.75. Similarly, to find the area under the curve for 0.5, we look up the row for 0.5 and the column for 0 in the z-table and get 0.6915. This means that there is a 69.15% chance of getting a z-score less than or equal to 0.5.
Subtract the smaller area from the larger area to find the area between the two z-scores. This area represents the probability of getting a value between 33.5 and 36 psi in the normal distribution. For example, to find the area between -0.75 and 0.5, we subtract: 0.6915−0.2266=0.4649
This means that there is a 46.49% chance of getting a value between 33.5 and 36 psi in the normal distribution.
Multiply the area by 100 to convert it to a percentage and write it with the appropriate units: The percentage of tires that are inflated to a pressure between 33.5 and 36 psi is 0.4649×100=46.49%
stop for X Y and Z show all work you must also write sentences to help explain your steps
1) Given this pentagon, let's find each measure of the angle x, y, and z we can notice that there are several supplementary angles.
2) Since we have a linear pair (∠80º and ∠y), then we can write:
m∠y = 180º -80º
m∠y = 100º
m∠x Another linear pair with ∠95º:
m∠x= 180º -95º
m∠x =85º
Let's visualize all the angles within that Pentagon:
Since there is a pentagon, then we can find the Sum of its interior angles by
S = 180(n-2)
S = 180( 5-2)
S =180(3)
S= 540º
And we can find the angle z by subtracting from 540º the sum of the other angles:
Hence m∠z = 540º -(95+127+100+118)
m∠z = 540º -(95+127+100+118)
m∠z = 100º
3) So the measures of angles x, y, and z are:
m∠x =85º, m∠y = 100º and m∠z = 100º
Solve the triangle. Round to the nearest tenth.
Find c aswell
Answer:
Set your calculator to Degree mode.
a² = 17² + 20² - 2(20)(17)cos(89°)
a² = 677.13236
a = 26.0 in.
sin(89°)/26.02177 = (sin B)/17
sin B = 17sin(89°)/26.02177
B = 40.8°
C = 50.2°
Nora is 4 years older than Hina . If the sum of their ages is at most 45 years ,find the maximum possible age of Hina. *
b) 25 years
a) 20 years
c) 15 years
choose the correct answer
Answer:
a) 20 years
Step-by-step explanation:
Hina: x
Nora: x + 4
x + x + 4 ≤ 45
2x + 4 ≤ 45
2x ≤ 41
x ≤ 20.5
20 years old and 15 years old would be ≤ 20.5 but the question asked for maximum possible age so 20 years old it is.
PLS HELP! weights (in pounds) of catfish caught in the river: 4.8 3 2.7 4.4 4.8 9.9 What is the outlier? A) 3 lbs B) 4.8 lbs C) 9.9 lbs D) none
The correct answer is C) 9.9 lbs as it is above the upper boundary 6.4865, it is the outlier in this dataset.
What is an outlier?An outlier is an observation that is much higher or lower than the other observations in a dataset.
In this case, the weights of the catfish range from 2.7 to 4.8 lbs, with one observation that is much higher at 9.9 lbs.
Therefore, 9.9 lbs is the outlier in this dataset.
To find the outlier in this dataset, we can calculate the interquartile range (IQR).
This is done by first calculating the first quartile (Q1) and third quartile (Q3).
The Q1 for this dataset =3.75
and the Q3= 4.675.
IQR= Q3 - Q1
= 0.925.
We then calculate the lower boundary as Q1 - (1.5 x IQR) = 2.3625.
The upper boundary is Q3 + (1.5 x IQR)= 6.4865.
Since 9.9 lbs is above this upper boundary, it is the outlier in this dataset.
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The GCF of 35 and 50 is
Answer: The greatest common factor of the two is 5.
Step-by-step explanation:
The greatest common factor is something that can be seen between the two as relation.
Which of the following is an advantage of using systematic random sampling?
Systematic random sampling reduces sampling variability.
Systematic random sampling does not require a finite population size.
Systematic random sampling could inadvertently miss patterns in the population.
Systematic random sampling uses clusters, which are close in proximity, making data collection easier.
This is a question that asks about the advantages of a systematic random sampling. Thus, we first take a look at the types of sampling, and then we see the advantage of systematic random sampling.
Samples may be classified as:
Convenient: Sample drawn from a conveniently available pool.
Random: Basically, put all the options into a hat and drawn some of them.
Systematic: Every kth element is taken. For example, you want to survey something on the street, you interview every 5th person, for example.
Cluster: Divides population into groups, called clusters, and each element in the cluster is surveyed.
Stratified: Also divides the population into groups. However, then only some elements of the group are surveyed.
Systematic:
One of the bigger advantages is that the systematic sampling eliminate clusters, which means that the last option is wrong.
Inadvertently missing patterns is a problem in systematic sampling, and not an advantage, thus the third option is also wrong.
It also does not reduce sampling variability, thus the first option is wrong.
From this, it can be concluded that the correct option is:
Systematic random sampling does not require a finite population size.
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A simple random sample of 100 observations was taken from a large population the sample mean and the standard deviation were determined to be 80 and 12 respectively. The standard error of the mean is 0.12
A. True
B. False
Answer:
A. True.
Step-by-step explanation:
To get the standard error of the mean, you need to do the sample standard deviation over the square root of the number of samples, n.
In this case, n = 100. The standard deviation is 12. To get the SAMPLE standard deviation, you do the population standard deviation over the square root of n. That is 12 / sqrt(100) = 12 / 10 = 1.2.
So, to get the standard error: 1.2 / sqrt(100) = 1.2 / 10 = 0.12.
The standard error of the mean is, indeed, 0.12, so the statement is A. True.
Hope this helps!
The data set below represents the different costs of a refrigerator at a local home improvement store.
$777, $498, $619, $379, $895, $1,256, $1,052
a. What is the median of the first half of the data? (first quartile)
The price of the refrigerators that is the median for the first half of the data is $498.
What is the median of the first half of the data?Median can be described as the number that occurs in the middle of a set of numbers that are arranged either in ascending or descending order
The prices arranged in ascending order is: $379, $498, $619, $777, $895, $1052, $1256
The first half of the prices are $379, $498, $619,
Median = $498
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A cheetah was racing a gazelle and a lion. For every 52 of a
mile the cheetah ran, the gazelle ran 16 of a mile and the lion
ran 34 of a mile. If the cheetah ran 20 miles miles, how many
miles did the gazelle and lion run?
Answer:
Step-by-step explanation:
Use the information in the figure. Find m
Answer:
Its 32
Step-by-step explanation:
you need to get 180 degrees altogether
If lines l and m are parallel in the figure above, and 2a − 3b = 95, then what is the value of b? Select one:
A. 39
B. 45
C. 53
D. 61
Answer: This question has no answer. The closest i could get was b= -95/3 + 2/3 a
Step-by-step explanation:
A dress that normally sells for $50 is on sale for $10. What is the percent decrease in the price?
Answer:
80%
Step-by-step explanation:
So the dress originally sold for $50, and it went down by $40 to reach $10. So, because it went down by $40, the way we figure out the percentage we need to figure out the fraction. The fraction is 40/50. So if a percentage is a fraction out of 100, then 40/50 is 80/100. The dress dropped by 80%.
If a turtle can crawl 1/2 foot in 40 minutes, how many feet can he crawl in an hour and a half?
Answer:
120 minutes or 2 hours
Step-by-step explanation:
1/2 x 3 = 1 1/2
40 x 3 = 120 or 2 hours
A bag contains 10 green,8 blue, and 2 white balls. Naomi seclets 2 balls from the bag at random, one at a time, without replacing them. What is the probability that she selects all two white balls?
E.) 2/95
F.) 1/95
G.) 1/190
H.) 1/380
To find the probability that Naomi selects both white balls, we need to consider the total number of possible outcomes and the number of favorable outcomes.
Total number of outcomes:
Naomi selects 2 balls without replacement, so the total number of outcomes is the number of ways she can choose 2 balls out of the total number of balls in the bag. This can be calculated using combinations:
Total outcomes = C(20, 2) = (20!)/(2!(20-2)!) = (20 * 19)/(2 * 1) = 190
Number of favorable outcomes:
Naomi needs to select 2 white balls. There are 2 white balls in the bag, so the number of favorable outcomes is the number of ways she can choose 2 white balls out of the 2 white balls in the bag:
Favorable outcomes = C(2, 2) = 1
Probability = Favorable outcomes / Total outcomes = 1/190
Therefore, the correct answer is (G) 1/190.
A coffee place is selling coffees for $2.50 each and cappuccinos for $3.75 each.
Today the coffee place sold a total of 70 drinks (coffees and cappuccinos) for a total of $222.50.
a) Write an equation that represents the information.
b) Solve the equation in (a) to find how many coffees and how many cappuccinos the coffee place sold today.
Answer:
Step-by-step explanation:
a) Let's denote the number of coffees sold as 'x' and the number of cappuccinos sold as 'y'.
The equation that represents the given information is:
2.50x + 3.75y = 222.50
b) To solve the equation, we need to find the values of 'x' and 'y' that satisfy the equation.
Since we have two variables and only one equation, we cannot determine the exact values of 'x' and 'y' independently. However, we can find possible combinations that satisfy the equation.
Let's proceed by assuming values for one of the variables and solving for the other. For example, let's assume 'x' is 40 (number of coffees):
2.50(40) + 3.75y = 222.50
100 + 3.75y = 222.50
3.75y = 222.50 - 100
3.75y = 122.50
y = 122.50 / 3.75
y ≈ 32.67
In this case, assuming 40 coffees were sold, we get approximately 32.67 cappuccinos.
We can also assume different values for 'x' and solve for 'y' to find other possible combinations. However, keep in mind that the number of drinks sold should be a whole number since it cannot be fractional.
Therefore, one possible combination could be around 40 coffees and 33 cappuccinos sold.
guess a solution of the form , plug it into as usual. then guess what and should be in terms of the eigenvalues and eigenvectors of . you should collect 4 different linearly independent solutions. for this notice that a square root of a positive number has two answers, a positive and a negative. then find the solution of the initial value problem where
The eigenvalue of T are 0,1,2,3,4 and the corresponding eigenvectors are of the form c, cx, cx2, cx3, cx4, where c ∈ R and c≠ 0.
A typical element p of P4(R) is given by expression p(x)= a0 +a1x+a2x2 +a3x3 +a4x4,
where a0, .... , a4 ∈ R.
With that expression, the eigenvalue-eigenvector equation Tp = λp, which in
this case is xp′(x) = λp(x), becomes
a1x+2a2x2 +3a3x3 +4a4x4 = λ(a0 +a1x+a2x2 +a3x3 +a4x4)
Comparing coefficients in the equation above, we see that the eigenvalue-eigenvector equation is equivalent to the system of equations
0 = λa0 a1 = λa1 2a2 = λa2 3a3 = λa3
4a4 = λa4.
From the equations above, we can see that if j ∈ {0, 1, 2, 3, 4} and aj≠ 0, then we have λ = j and ak = 0 for any k≠ j. Thus the eigenvalue of T are 0,1,2,3,4 and the corresponding eigenvectors are of the form c, cx, cx2, cx3, cx4, where c ∈ R and c≠ 0.
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a quadrilateral has diagonals that are perpendicular but not congruent. This quadrilateral could be
Answer:
Rhombus
Step-by-step explanation:
This could be a rhombus since in a square, the lines are congruent and perpendicular, so we move on to a broader shape, rectangles. the diagonals are congruent but not perpendicular, so we go to rhombus, and in a rhombus the diagonals are not congruent but they are perpendicular.
hey there ms or mr could you graph this but with numbers? yes this is my tutors response to the question but could you please graph this with numbers on the x-axis, y-axis, and points?
Answer
The triangle described by the coordinates given is attached below
A' (-2, -2)
B' (-1, 3)
C' (4, 0)
A (-2, 2)
B (-1, -3)
C (4, 0)
The image of the original triagle is attached below
Hope this Helps!!!
Which equivalent to (11-9)^3x2
Answer:
11-9=2 then, 2^3=8 , finally 8X2=16
Step-by-step explanation:
remember order of operations
integral of 1÷(1+sin x) dx
Answer:
\( \tan \: x - \sec \: x + c\)
Step-by-step explanation:
\( \int1 \div (1 + \sin \: x) \: dx \\ \\ = \int \frac{1}{1 + \sin \: x} dx \\ \\ = \int \frac{1}{(1 + \sin \: x)} \times \frac{(1 - \sin \: x)}{(1 - \sin \: x)} dx \\ \\ = \int \frac{1 - \sin \: x}{1 - \sin^{2} \: x} dx \\ \\ = \int \frac{1 - \sin \: x}{ \cos^{2} \: x} dx \\ \\ = \int \bigg( \frac{1}{ \cos^{2} \: x} - \frac{\sin \: x}{ \cos^{2} \: x} \bigg) dx \\ \\ = \int( { \sec}^{2} x - \sec \: x. \tan \: x)dx \\ \\ \purple{ \bold{ = \tan \: x - \sec \: x + c}}\)
anyoneeee know???????
Answer:
60
Step-by-step explanation:
6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
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question is in the image below
The perimeter of Sam's string is 178 inches.
Given information:
Sam has a rectangular shaped window.
Length = 65 inches.
Width = 24 inches.
To find the perimeter:
you can use the formula:
Perimeter = 2 x (Length + Width)
Substituting the values into the formula, we have:
Perimeter = 2 x (65 + 24)
Perimeter = 2 x 89
Perimeter = 178 inches
Therefore, the perimeter of the rectangular window is 178 inches.
So, the perimeter of the rectangular window is 178 inches. This means that if you were to walk along the outline of the window, you would cover a total distance of 178 inches. It's important to note that the perimeter represents the total length of all the sides combined, and it is measured in the same unit (in this case, inches) as the length and width of the window.
To learn more about the rectangular perimeter;
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Ray’s weight increased by 11% in the last two years. If he gained 16.5 pounds, what was his weight two years ago?
Answer:
Ray weighed 150 pounds two years ago.
Step-by-step explanation:
11/100 = 16.5/x
11x = 16.5(100)
11x = 1,650
(11x)/11 = (1,650)/11
x = 150
About time that he should start going to the gym!